WILL GIVE BRAINILY 5 STARS AND THANKS FOR CORRECT ANSWER ITS PRETTY EASY If it is 3:00 p.m. and you move the minute hand of the clock 270 degrees clockwise, what time will it be?

Answer:

The test statistic for testing if the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard is 3.234.

Step-by-step explanation:

We are given that in a random sample of 380 cars driven at low altitudes, 42 of them exceeded a standard of 10 grams of particulate pollution per gallon of fuel consumed.

In an independent random sample of 90 cars driven at high altitudes, 24 of them exceeded the standard.

Let [tex]p_1[/tex] = population proportion of cars driven at high altitudes who exceeded a standard of 10 grams.

[tex]p_2[/tex] = population proportion of cars driven at low altitudes who exceeded a standard of 10 grams.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]p_1\leq p_2[/tex]      {means that the proportion of high-altitude vehicles exceeding the standard is smaller than or equal to the proportion of low-altitude vehicles exceeding the standard}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]p_1>p_2[/tex]      {means that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard}

The test statistics that will be used here is Two-sample z-test statistics for proportions;

                             T.S.  =  [tex]\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }[/tex]  ~  N(0,1)

where, [tex]\hat p_1[/tex] = sample proportion of cars driven at high altitudes who exceeded a standard of 10 grams = [tex]\frac{24}{90}[/tex] = 0.27

[tex]\hat p_2[/tex] = sample proportion of cars driven at low altitudes who exceeded a standard of 10 grams = [tex]\frac{42}{380}[/tex] = 0.11

[tex]n_1[/tex] = sample of cars driven at high altitudes = 90

[tex]n_2[/tex] = sample of cars driven at low altitudes = 380

So, the test statistics =  [tex]\frac{(0.27-0.11)-(0)}{\sqrt{\frac{0.27(1-0.27)}{90}+\frac{0.11(1-0.11)}{380} } }[/tex]      

                                   =  3.234

The value of z-test statistics is 3.234.

Answer:

 $900

Step-by-step explanation:

To begin with let us estimate the total cash value of the prices

$1000 x 1= 1000

$500 x 1=  500

$50 x 2= 100

Total = $1600

Now let us calculate the total cost of tickets sold at $2.50 per tickets for 1000 tickets

2.5*1000= $2,500

Assuming worse case that the lottery had winners in all three categories and i.e the total prices given out is $1600

Then the expected profit is = $2,500-$1600= $900

Answer:

9/3 = 3x/3

3 = x

The spring stretches 9 inches with 3 kilograms of weight attached to it

Step-by-step explanation:

Substitute y = 9 into the equation y = 3x, or locate the answer on the graph:

y = 3x

9 = 3x.

Divide both sides of the equation by 3

Answer:The spring stretches 9 inches with 3 kilograms of weight attached to it.

Step-by-step explanation:

Substitute y = 9 into the equation y = 3x, or locate the answer on the graph:

y = 3x

9 = 3x.

Divide both sides of the equation by 3:

The spring stretches 9 inches with 3 kilograms of weight attached to it.

Answer:

depth 5 8.3 ft, length 5 24.9 ft, width 5 16.8 ft

Answer:

Hello your question has some missing parts below is the complete question

In a survey of 2065 adults in a certain country conducted during a period of economic​ uncertainty, 63​% thought that wages paid to workers in industry were too low. The margin of error was 4 percentage points with ​95% confidence. For parts​ (a) through​ (d) below, which represent a reasonable interpretation of the survey​ results? For those that are not​ reasonable, explain the flaw.

part a:(We are 95 % confident 63 % of adults in the country during the period of economic uncertainty felt wages paid to workers in industry were too low.)

part b:  We are 91 % to 99 % confident 63 % of adults in the country during the period of economic uncertainty felt wages paid to workers in industry were too low.

part c:  We are 95 % confident the proportion of adults in the country during the period of economic uncertainty who believed wages paid to workers in industry were too low was between 0.59 and 0.67. Is the interpretation reasonable?

part d: In 95 % of samples of adults in the country during the period of economic uncertainty, the proportion who believed wages paid to workers in industry were too low is between 0.59 and 0.67. Is the interpretation reasonable?

Answer : For part A :

The interpretation is flawed. No interval has been provided about the population proportion.  

part B :

The interpretation is flawed. The interpretation indicates that the level of confidence is varying.  

Part C

The interpretation is reasonable.

Part D

The interpretation is flawed. The interpretation suggests that this interval sets the standard for all the other intervals, which is not true.

Step-by-step explanation:

Given data: Population = 2065 ,

probability = 63% = 0.6,

margin of error = 4% = 0.04

confidence interval (95%) = ( 0.59,0.67 )  

For part A :

The interpretation is flawed. No interval has been provided about the population proportion.  this is because the confidence interval is not mentioned

part B :

The interpretation is flawed. The interpretation indicates that the level of confidence is varying.  this is because the confidence interval is a fixed value

Part C

The interpretation is reasonable.

this is because the confident level given is fixed

Part D

The interpretation is flawed. The interpretation suggests that this interval sets the standard for all the other intervals, which is not true.

1: 8 faces and 9 with the base 9 vertices and 16 edges

2: 3 faces and 5 with the bases 6 vertices and 9 edges

3: 3 faces and 4 with the base 4 vertices and 6 edges

Hope this can help you.

1: 8 faces and 9 with the base 9 vertices and 16 edges

2: 3 faces and 5 with the bases 6 vertices and 9 edges

3: 3 faces and 4 with the base 4 vertices and 6 edges

Answer:

44.8

Step-by-step explanation:

Using the Cosine formula, we first have Cos 48 = 30/x. So then we just solve for x and get 44.8342965, which rounds to 44.8

I hope this helped! :D

[tex]\dfrac{5bc}{10b^2}=\dfrac{\not 5\cdot \not b\cdot c}{2\cdot \not 5\cdot \not b\cdot b}=\dfrac{c}{2b}[/tex]

Answer:

c / ( 2b)

Step-by-step explanation:

5bc/10b^2

Lets look at the numbers first

5/10 = 1/2

Then the variable b

b / b^2 = 1/b

Then the variable c

c/1 = c

Putting them back together

1/2 * 1/b * c/1

c/ 2b

Answer:

f¯¹(x) = 23/ (6x + 3)

Step-by-step explanation:

f(x) = (23 – 3x)/6x

The inverse, f¯¹, for the above function can be obtained as follow:

f(x) = (23 – 3x)/6x

Let y be equal to f(x)

Therefore, f(x) = (23 – 3x)/6x will be written as:

y = (23 – 3x)/6x

Next, interchange x and y.

This is illustrated below:

y = (23 – 3x)/6x

x = (23 – 3y)/6y

Next, make y the subject of the above expression. This is illustrated below:

x = (23 – 3y)/6y

Cross multiply

6xy = 23 – 3y

Collect like terms

6xy + 3y = 23

Factorise

y(6x + 3) = 23

Divide both side by (6x + 3)

y = 23/ (6x + 3)

Finally, replace y with f¯¹(x)

y = 23/ (6x + 3)

f¯¹(x) = 23/ (6x + 3)

Therefore, the inverse, f¯¹, for the function f(x) = (23 – 3x)/6x is

f¯¹(x) = 23/ (6x + 3)

Answer:

C(t) = 20t

Step-by-step explanation:

The graph of C(t) appears to be linear

The y intercept is 0

The slope is 200/10 = 20

y = mx+b  where m is the slope and b is the y intercept

y = 20x+0

y = 20x

C(t) = 20t

Answer:

the answer is c (t) = 20 t

Step-by-step explanation:

[tex]\sf{}[/tex]

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Answer:

The  null hypothesis is  [tex]H_o : \mu = 445[/tex]

The  alternative hypothesis  [tex]H_a : \mu < 445[/tex]  (This is the original claim[ It is believed that the machine is under filling the bags] )

Step-by-step explanation:

From the question we are told that  

    The population mean is   [tex]\mu = 445 \ g[/tex]

    The  sample size is  [tex]n = 12[/tex]

    The  sample mean is  [tex]\= x = 442 \ g[/tex]

     The  standard deviation is  [tex]\sigma = 20[/tex]

     The  level of significance is  [tex]\alpha = 0.05[/tex]

The  null hypothesis is  [tex]H_o : \mu = 445[/tex]

The  alternative hypothesis  [tex]H_a : \mu < 445[/tex]  (This is the original claim )

Answer:

y = (9/4)x - 9

Step-by-step explanation:

The x-intercept is (4, 0) and the y-intercept is (0, -9).

As we move from (0, -9) to (4, 0), x (the 'run' increases by 4 and y (the 'rise' increases by 9.  Thus, the slope of the line connecting these two points is m = rise/run = 9/4, from which we can write the desired equation in the form y = mx + b:

y = (9/4)x - 9

Answer:

  10 hours

Step-by-step explanation:

In order to answer this question, you must assume that all air time not spent on news is spent on music & entertainment. That would usually not be the case, as there would usually be advertisements and public service programming along with everything else.

The time spent on news is ...

  (1/6)(12 hours) = 2 hours

If the rest is spent on music and entertainment, then ...

  12 -2 = 10 . . . hours are used for music and entertainment

Step-by-step explanation:

mark it as the brainliest

Answer:

i need help with this too

Step-by-step explanation:

Answer:

.................

Step-by-step explanation:

............

true false false true...is the quick answer

Remember that negatives are always less than positive numbers.

Step-by-step explanation:

n mathematics, an arithmetic progression (AP) or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant. ... For instance, the sequence 5, 7, 9, 11, 13, 15, . . . is an arithmetic progression with common difference of 2.

Answer:

[tex]\boxed{\mathrm{view \: explanation}}[/tex]

Step-by-step explanation:

Apply rule : [tex]a^1 =a[/tex]

[tex]\displaystyle \frac{1}{g^1 } =\frac{1}{g}[/tex]

[tex]\displaystyle \frac{1}{g^{-1}}[/tex]

Apply rule : [tex]\displaystyle a^{-b}=\frac{1}{a^b}[/tex]

[tex]\displaystyle \frac{1}{\frac{1}{g^1 } }[/tex]

Apply rule : [tex]\displaystyle \frac{1}{\frac{1}{a} } =a[/tex]

[tex]\displaystyle \frac{1}{\frac{1}{g^1 } }=g[/tex]

Answer:

[tex]\frac{1}{g^1}[/tex]

= [tex]\frac{1}{g}[/tex]

[tex]\frac{1}{g - 1}[/tex]

= [tex]\frac{g^1}{1}[/tex]

= [tex]\frac{g}{1}[/tex]

= g

Hope this helps!

Answer:

x = 14

y = -7

z = -3

but this is none of the provided answer options !

Step-by-step explanation:

it's really easy by principle. it's just some work to do.

we try to find equations to express one variable in terms of the others.

but one thing there is : your teacher made a mistake.

the right solution is x = 14, y = -7, z = -3

your teacher made a typo at d.

but the right answer should be d.

just to give you an idea how this can be done (and also to prove that there is a mistake by the teacher):

we can directly try to transform one expression into one that describes x by y and z.

and then another to describe e.g. z by y. and then solve the third one just for y. and then we get the other 2 by these other expressions.

or we can e.g. add or subtract one equation to/from another. this is one of these cases, because we can find really simple expressions that way :

we do

5x + 6y + 7z = 7

- (3x + 4y + 3z = 5)

- (2x + 2y + 3z = 5)

---------------------------

0x + 0y + z = -3

=> z = -3

3x + 4y - 3×3 = 5

3x = -4y + 14

x = (-4y + 14)/3

2×(-4y + 14)/3 + 2y - 9 = 5

(-8y + 28)/3 + 2y = 14

-8y + 28 + 6y = 42

-2y = 14

y = -7

x = (-4×-7 + 14)/3 = (28+14)/3 = 42/3 = 14

Answer:

50.26 ft^2

Step-by-step explanation:

Area=pi*r^2

Area=pi*(4)^2=pi*16=50.26

Answer:

Estimated expenses for next 2 years:

Rent = 1100 * 12 * 2 = 26,400

Gym membership = 450 * 2 = 900

Gym monthly fee = 40 * 12 * 2 = 960

Renter's insurance = 60 * (12 * 2 / 6) = 240

Groceries = 300 * 12 * 2 = 7200

Eating out & entertainment = 175 * 52 * 2 = 18,200

Total estimated living expenses = $53,900

Step-by-step explanation:

Answer:

a) We reject H₀

b) The manager won´t be satisfied with nominal filling its cup

c) See step-by-step explanation

Step-by-step explanation:

Normal distribution  n <  30, therefore, we should use t - student table

Sample size  n  =  16

degree of freedom  =   df =  n - 1     df = 15

Sample mean    μ  = 5,85 ou

Sample standard deviation  is    s = 0,2 ou

Hypothesis test

Null hypothesis                               H₀              μ   >=  μ₀

Alternative hypothesis                   Hₐ               μ   <   μ₀

CI  = 95 %    then   α = 5 %     α = 0,05     α/2  =  0,025

Then in t-student table we find  t(c) = 1,753

To calculate  t(s)

t(s) =  (   μ   -  μ₀  ) s/√n

t(s)  =   ( 5,85 -  6 ) / 0,2/√16

t(s)  =  -  0,15* 4 / 0,2

t(s)  =  -  3

To compare  t(s) and t(c)

|t(s)| > |t(c)|        3 > 1,753

Then t(s) is in the rejection region. We should reject H₀. Data indicate that at 95 % of CI μ seems to be smaller than 6 ou

b) The manager won´t be satisfied with nominal filling its cup

Answer: There are 15 friends.

Step-by-step explanation:

We know that there is N friends (N is the number that we are looking for)

Each friend weights 1/20 ton.

Now, the weight of the N friends together is N times 1/20 ton.

Then we have:

N*(1/20) ton = 3/4 ton

We solve this for N.

First multiply both sides by 20.

20*N*(1/20) = N = 20*(3/4) = 60/4 = 15

Answer:

I can find the total number of people by dividing the total weight by the weight of one person.

Step-by-step explanation:

Rewrite 3 3/4 as an improper fraction

3 3/4 = 15/4

Now you have

15/5 / 5/7

When you divide fractions, change the division to multiplication and flip the second fraction over:

15/4 x 7/5

Now multiply the top numbers together and the bottom numbers together:

( 15 x 7) / (4 x 5) = 105/20

Write as a proper fraction:

105/20 = 5 1/4

Answer:

There is a positive correlation between X and Y.

Step-by-step explanation:

The estimated regression equation is:

[tex]\hat Y=20X+200[/tex]

The general form of a regression equation is:

[tex]\hat Y=b_{yx}X+a[/tex]

Here, [tex]b_{yx}[/tex] is the slope of a line of Y on X.

The formula of slope is:

[tex]b_{yx}=r(X,Y)\cdot \frac{\sigma_{y}}{\sigma_{x}}[/tex]

Here r (X, Y) is the correlation coefficient between X and Y.

The correlation coefficient is directly related to the slope.

And since the standard deviations are always positive, the sign of the slope is dependent upon the sign of the correlation coefficient.

Here the slope is positive.

This implies that the correlation coefficient must have been a positive values.

Thus, it can be concluded that there is a positive correlation between X and Y.

Answer:

the answer is 10

Step-by-step explanation:

900 ÷ 90

=> 10 [tex]\sf{}[/tex]

Answer:

The answer is 10.

Step-by-step explanation:

900/90=cut 0 of numerator and denominator then 90 divide by 9 is 10.

Answer:

The probability  is  [tex]P(x < 13) = 0.8732[/tex]

Step-by-step explanation:

From the question we are told that

    The  probability of success is    p = 0.70

     The  sample size is  [tex]n = 15[/tex]

Generally the distribution of U.S. households have vcrs follow a binomial distribution given that there are only two outcome (household having vcrs or household not having vcrs )

The probability of failure is mathematically evaluated as

       [tex]q = 1- p[/tex]

substituting values

      [tex]q = 1- 0.70[/tex]

      [tex]q = 0.30[/tex]

The probability that fewer than 13 have vcrs is mathematically represented as

          [tex]P(x < 13) = 1- [P(13) + P(14) + P(15)][/tex]

=>     [tex]P(x < 13) = 1-[( \left 15 } \atop {}} \right. C_{13} *p^{13}* q^{15-13})+ (\left 15 } \atop {}} \right. C_{14} *p^{14}* q^{15-14}) +( \left 15 } \atop {}} \right. C_{15} *p^{15}* q^{15-15}) ][/tex]

 Here  [tex]\left 15 } \atop {}} \right. C_{13}[/tex] means  15 combination 13 and the value is  105 (obtained from calculator)

 Here  [tex]\left 15 } \atop {}} \right. C_{14}[/tex] means  15 combination 14 and the value is  15 (obtained from calculator)

 Here  [tex]\left 15 } \atop {}} \right. C_{15}[/tex] means  15 combination 15 and the value is  1 (obtained from calculator)

So

 [tex]P(x < 13) = 1-[(105 *p^{13}* q^{2})+ (15 *p^{14}* q^{1}) +(1*p^{15}* q^{0}) ][/tex]

substituting values      

 [tex]P(x < 13) = 1-[(105 *(0.70)^{13}* (0.30)^{2})+ (15 *(0.70)^{14}* (0.30)^{1}) +(1*(0.70)^{15}* (0.30)^{0}) ][/tex]

 [tex]P(x < 13) = 0.8732[/tex]

Answer:

55*54

=2970

Step-by-step explanation:

Answer:

Area=49x^2+9-42x

Step-by-step explanation:

Area=(Side)^2

Area=(7x-3)^2

Area=49x^2+9-42x