Warming the bed with water is far more efficient than warming the bed with an iron, the difference is the specific heat capacity of water and iron.
The specific heat capacity of a substance can be defined as the amount of the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).
What is the Specific heat of Water?q = m x C x AT
As the specific heat of water is 4.18 J/g°C and the specific heat of iron is 0.450 J/g°C. Since, the specific heat of water is greater than the specific heat of iron.
Therefore, we can conclude that water is more efficient to warm your bed on a cold night with a hot water bottle that contains 1 kg of water at 50 degrees C.Learn more about Specific heat here:
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Radiation in the ultraviolet region of the electromagnetic spectrum is quite energetic. It is this radiation that causes dyes to fade and your skin to develop a sunburn. If you are bombarded with 1. 00 mol of photons with a wavelength of 370. Nm, what amount of energy, in kilojoules per mole of photons, are you being subjected to? energy mol submit answer try another versiorn 2 item attempts remaining.
The energy of photon in kJ/mol is 329kJ/mol.
Wavelength of radiation is 370nm. The frequency of given wavelength is
ν = c / λ
ν = 3×10^8 / 370×10^-9
ν = 8.11 × 10^14 s^-1
Now the energy of photon is:
E = hν
E = 6.63×10^-34 J.s/photon × 8.11×10^14s^-1
E = 5.41× 10^-19 J/photon
To find in mole
E = 5.41× 10^-19 × 6.022×10^23
E = 3.29 ×10^ 5 J/mol
So, the energy of mole of photon is equal to 329 kJ/mol.
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Consider two copper wires. one has twice the length and twice the cross-sectional area of the other. how do the resistances of these two wires compare?
Answer:
R = ρ L / A where R is the resistance and ρ the resistivity:
R2 / R1 = (L2 / A2) / (L1 / A1) = L2 * A1 / (L1 * A2)
R2 / R1 = (2 L * A) / (L * 2 A) = 1
Their resistances should be the same.
Describe and explain your observations using the law of conservation of charge and the properties of the conductors.
What is Law of conservation of charge?
Law of conservation of charge states that, "the total electric charge in an isolated system is always constant".
It can also be stated as, "Charge can neither be created nor destroyed but can only be converted from one form of energy to another".
What are the properties of conductors?
There is movement of electrons and ions in the conductor. Free charges exist on the surface of the conductor.The charge density of a conductor is zero.All points of a conductor are at the same potential.The electric field of a conductor is zero. This allows the electrons to flow within them.To learn more about Law of conservation of charge: https://brainly.com/question/4158552
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a ball is thrown vertically upward with an initial speed of 20 m/s. What is the velocity right before returning to y
The ball's return velocity is (-20 m/s) before reaching its starting location.
According to the 3rd equation of motion-
When an item is propelled higher by gravity, it progressively slows down until it achieves its maximum height.The earth's gravitational pull causes it to turn around after reaching its highest peak and fall freely back to the ground.An object that is falling freely has a starting velocity of "0"
The object accelerates at a rate of "g."
Let 'h' represent the distance the item travels while in free fall.
We can now get the ultimate velocity of the object shortly before it touches the earth with this equation,
v²=u²+2as
Assume that the ball returns to its originating place at "v". Although the ball's orientation changes as it returns to its original place, its speed stays constant.A positive direction should point upward, while a negative direction should point below.Calculation-
For upward motion,
providing that,
The ball's initial speed is u = +20 m/s.
So, v²= u² + 2as
⇒0= (20)² - 2gH [ where 'H' = maximum height reached]
⇒H= 400/2g
For downward motion,
v²=u²+2as
⇒v²= 0²+2g*400/2g
⇒v²= 400 m/s
⇒v= 20 m/s
Therefore, the ball's return velocity is (-20 m/s) before reaching its starting location.
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An airplane traveling at speed, 180 m/s, emits sound at a frequency of 2 000 Hz. What is the change in frequency (in Hz) heard by a stationary listener as the plane approaching and passing by
Answer:
As the plane moves toward the listener, the apparent frequency of the plane would be [tex]4250\; {\rm Hz}[/tex] ([tex]2250\; {\rm Hz}[/tex] higher than the frequency at the source.)
As the plane moves away from the listener, the apparent frequency of the plane would be approximately [tex]1308\; {\rm Hz}[/tex] (approximately [tex]692\; {\rm Hz}[/tex] lower than the frequency at the source.)
Assumption: the speed of sound in the air is [tex]340\; {\rm m\cdot s^{-1}}[/tex].
Explanation:
Crests of this sound wave travel toward the listener at a constant [tex]v = 340\; {\rm m\cdot s^{-1}}[/tex]. Since there is a pause of [tex]t = 1 / f = (1/2000)\; {\rm s}[/tex] between every two consecutive crests of this sound wave, the distance between each pair of consecutive crests would be:
[tex]\begin{aligned}\lambda &= \frac{v}{f} \\ &= \frac{340\; {\rm m \cdot s^{-1}}}{2000\; {\rm s^{-1}}} \\ &= 0.17\; {\rm m} \end{aligned}[/tex].
Hence, if the aircraft wasn't moving, the first crest would have a head start of [tex]\lambda = 0.17\; {\rm m}[/tex] relative to the second one. This head start would ensure that the first crest arrive [tex]t = \lambda / v = 0.17\; {\rm m} / (340\; {\rm m \cdot s^{-1}}) = (1/2000)\; {\rm s}[/tex] earlier than the second crest.
However, at a speed of [tex]v_{\text{s}} = 180\; {\rm m\cdot s^{-1}}[/tex], the aircraft would have travelled an additional [tex]v_\text{s}\, t = 180\; {\rm m\cdot s^{-1}} \times (1/2000)\; {\rm s} = 0.09\; {\rm m}[/tex] within that [tex]t = (1 / 2000)\; {\rm s}[/tex].
If the aircraft was travelling towards the listener, the head start of the first crest over the next one would be reduced to [tex]\lambda - v_\text{s}\, t =[/tex][tex]0.17\; {\rm m} - 0.09\; {\rm m} = 0.08\; {\rm m}[/tex]. The first crest would arrive earlier than the second one by [tex](\lambda - v_{\text{s}}\, t) / (v) = (0.08\; {\rm m}) / (340\; {\rm m\cdot s^{-1}}) \approx 0.000235\; {\rm s}[/tex].In contrast, if the aircraft was travelling away from the listener, the head start of the first crest over the next one would be increased to [tex]\lambda + v_\text{s}\, t = 0.17\; {\rm m} + 0.09\; {\rm m} = 0.26\; {\rm m}[/tex]. The first crest would arrive earlier than the second one by [tex](\lambda + v_{\text{s}}\, t) / (v) = (0.26\; {\rm m}) / (340\; {\rm m\cdot s^{-1}}) \approx 0.000765\; {\rm s}[/tex].In other words, if the aircraft was moving towards the listener, the period of the sound would appear to the listener to be approximately [tex]0.000235\; {\rm s}[/tex]. in contrast, if the aircraft was moving away from the listener, the period of the sound would appear to the listener as approximately [tex]0.000765\; {\rm s}[/tex].
Therefore:
When the aircraft moves toward the listener, the listener would hear a frequency of [tex]f = 1 / t \approx 1 / 0.000235\; {\rm s} = 4250\; {\rm Hz}[/tex].When the aircraft moves away from the listener, the listener would hear a frequency of approximately [tex]f = 1 / t \approx 1 / 0.000765\; {\rm s} \approx 1307\; {\rm Hz}[/tex].How do the resistances of two conducting wires compare if they have the same length, but one is twice the radius of the other?.
The thicker wire has one-fourth the resistance of the thinner wire.
What are resistance and resistivity?The characteristic of a substance that prevents the flow of current is known as resistance. The free electrons begin to move in a specific direction when a voltage is applied across the conductor. These electrons collide with atoms or molecules as they move, creating heat in the process. These atoms or molecules prevent free electrons from moving through a substance. Resistance is represented by the symbol R.
Specific resistance is another name for resistivity. A substance with certain dimensions, such as one meter in length and a cross-sectional area of one square meter, has a resistance that is represented by its resistivity. Resistivity or specific resistance is represented by ρ.
The relation between resistance R and resistivity ρ is given as:
R = ρL/A
where,
R = resistance of the conductor
ρ = resistivity of the material
L = length of the conductor
A = cross-sectional area of the conductor
Calculation:Given,
r₁ = 2r₂
L₁ = L₂
where
r₁ = radius of the first conductor
r₂ = radius of the second conductor
L₁ = length of the first conductor
L₂ = length of the second conductor
To find
R₁/R₂ =? (the ratio of R₁ and R₂)
If the radius is twice the other then the area will become,
A₁ = π r₁²
A₂ = π r₂²
A₁ = π (2r₂)²
= 4π r₂²
Therefore,
A₁ = 4 A₂
Now put the values in formula,
R = ρL/A
R₁/R₂ = ρ L₁ A₂/ ρ L₂ A₁
R₁/R₂ = L A₂/ L (4A₂)
R₁/R₂ = 1/4
R₁ = R₂/4
Hence, the thicker wire with twice the radius of thin wire has one-fourth the resistance of the thinner wire.
I understand the question you are looking for is this:
How do the resistances of two conducting wires compare if they have the same length, but one is twice the radius of the other?
(a) The thicker wire has half the resistance of the thinner wire
(b) The resistance is the same in both wires
(c) The thicker wire has one-fourth the resistance of the thinner wire
(d) The thicker wire has twice the resistance of the thinner wire.
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PLSLPSLLPSLPSLPS HELP I ONLY HAVE 5 MINS PLEASE
a bus slows down from 50.0 km/h to 36.5/h in the school zone. determine the magnitude of the vehicle's acceleration if it took 19.5 seconds to slow down.
Answer:
0.19m/s²
Explanation:
Initial velocity(u) = 50×1000/60×60
=13.88 m/s
Final velocity(v) = 36.5×1000/60×60
=10.13 m/s
Acceleration(a) = v-u/t
=10.13-13.88/19.5
a= -0.19m/s²
-a = 0.19m/s²
The magnitude of retar dation is 0.19m/s²
Answer:
[tex]\sf 0.192\:ms^{-2}\:\:(3\:s.f.)[/tex]
Explanation:
Given:
initial velocity (u) = 50.0 km/hfinal velocity (v) = 36.5 km/htime (t) = 19.6 secondsFirst, convert the velocities into meters per second by dividing by 3.6:
[tex]\implies \sf 50.0\: km h^{-1}=\dfrac{50.0}{3.6}\:ms^{-1}= \dfrac{125}{9}\:ms^{-1}[/tex]
[tex]\implies \sf 36.5\: km h^{-1}=\dfrac{36.5}{3.6}\:ms^{-1}= \dfrac{365}{36}\:ms^{-1}[/tex]
To find the vehicle's acceleration, use one of the constant acceleration equations with the given values:
[tex]\implies \sf v=u+at[/tex]
[tex]\implies \sf \dfrac{365}{36}=\dfrac{125}{9}+19.5a[/tex]
[tex]\implies \sf \dfrac{365}{36}-\dfrac{125}{9}=19.5a[/tex]
[tex]\implies \sf 19.5a=-3.75[/tex]
[tex]\implies \sf a=-\dfrac{3.75}{19.5}[/tex]
[tex]\implies \sf a=-0.1923076923...\:ms^{-2}[/tex]
Therefore, the magnitude of acceleration is:
[tex]\implies \sf |a|=|-0.19230...|=0.192\:ms^{-2}\:\:(3\:s.f.)[/tex]
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If a 100 ω resistor is placed across a 0. 10 μf charged capacitor which is initially charged to 3 v. How long does it take it to discharge to 2v to 1v?
1. The time taken to discharge to 2 V is 2×10⁻⁹ s
2. The time taken to discharge to 1 V is 5×10⁻¹⁰ s
Energy stored in a capacitorThe energy stored in a capacitor is given by
E = ½CV²
But
E = Pt
Thus,
Pt = ½CV²
Where
E is the energy C is the capacitorV is the voltageP is the power t is the timeWith the formula (Pt = ½CV²), we can determine the time in each case. Detail below:
1. How to determine the time required to discharge to 2 VData obtained from the question include:
Power (P) = 100 wCapacitor (C) = 0.10 μF = 1×10⁻⁷ FVoltage (V) = 2 VTime (t) = ?Pt = ½CV²
100 × t = ½ × 1×10⁻⁷ × 2²
Divide both sides by 100
t = (½ × 1×10⁻⁷ × 2²) / 100
t = 2×10⁻⁹ s
Thus, the time required to discharge to 2 V is 2×10⁻⁹ s
2. How to determine the time required to discharge to 1 VData obtained from the question include:
Power (P) = 100 wCapacitor (C) = 0.10 μF = 1×10⁻⁷ FVoltage (V) = 1 VTime (t) = ?Pt = ½CV²
100 × t = ½ × 1×10⁻⁷ × 1²
Divide both sides by 100
t = (½ × 1×10⁻⁷ × 1²) / 100
t = 5×10⁻¹⁰ s
Thus, the time required to discharge to 1 V is 5×10⁻¹⁰ s
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a bat emitts a sonar sound wave (343 m/s) that bounces off a mosquito 8.42 m away
The time lapse between when the bat emits the sound and when it hears the echo is 0.05 s.
From the question given above, the following data were obtained:
Velocity of sound (v) = 343 m/s
Distance (x) = 8.42 m
Time (t) =?
We can obtain obtained the time as illustrated below:
v = 2x / t
343 = 2 × 8.42 / t
343 = 16.84 / t
Cross multiply
343 × t = 16.84
Divide both side by 343
t = 16.84/343
t = 0.05 s
Thus, the time between when the bat emits the sound and when it hears the echo is 0.05 s.
How does a bat know how far away something is?A bat emits a sound wave and carefully listens to the echoes that return to it. The returning information is processed by the bat's brain in the same way that we processed our shouting sound with a stopwatch and calculator. The bat's brain determines the distance of an object by measuring how long it takes for a noise to return.
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Correction question:
A bat emits a sonar sound wave (343 m/s) that bounces off a mosquito 8.42 m away. How much time elapses between when the bat emits the sound and when it hears the echo? (Unit = s)
Calculate the speed of light in glycerol (n = 1.47). Use the GRASS method, write your solution on paper and insert an image of it below
The velocity of light in glycerol is 2.04 × 10⁸ m/s.
To find the answer, we need to know about the expression of velocity of light in any medium.
What's the expression of the speed of light in any medium?Mathematically, the speed of light in any medium= C/nC = speed of light in vaccum, n = refractive index of the mediumWhat's the speed of light in glycerol having refractive index of 1.47?Speed of light in glycerol= 3×10⁸/1.47 = 2.04 × 10⁸ m/s
Thus, we can conclude that the velocity of light in glycerol is 2.04 × 10⁸ m/s.
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In order to use the efficiency of a car engine in an optimal way, a maximum engine speed of .........rpm for shifting is recommended for gas engines.
In order to use the efficiency of a car engine in an optimal way, a maximum engine speed of 2,500 rpm for shifting is recommended for gas engines.
The maximum thermal efficiency of modern gasoline engines is over 50%, but legal cars on the road are only about 20% to 35% when used to power cars.
Unfortunately, even with regular car maintenance such as tuning and oil changes, the efficiency of today's gasoline engines is about 30-35%. In other words, about 65 cents per dollar spent on gasoline is wasted.
EPA's 2020 Automotive Trend Report preliminary data shows that the average fuel economy of 2020 model light trucks has increased to 25.7 miles per gallon (MPG). If this preliminary data holds, it will mark the highest average fuel economy ever for a new light commercial vehicle.
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(10%) Problem 2: The frequency range for AM radio is 540 to 1600 kHz. The frequency range for FM radio is 88.0 to 108 MHz.
188m - 556m is the wavelength range for AM radio.
2.77 - 3.40m is the wavelength range for FM radio.
1) For AM radio
f(max) = 1600 × 10³ Hz
f(min) = 540 ×10³Hz
c = fλ
λ = c/f where,
c = speed of light
f = frequency
λ= wavelength
So,
λ(min) = 3 × [tex]10^{8}[/tex] / 1600 × 10³ = 188 m
λ(max) = 3 × 10⁸/540 ×10³ = 556 m
So wavelength range of AM radio is 188 m - 556m
2) For FM radio
f(max) = 108 × 10⁶ Hz
f(min) = 88 × 10⁶ Hz
λ(min) = 3 × 10⁸ / 108 × 10⁶ = 2.77 m
λ(max) = 3 × 10⁸ / 88 × 10⁶ = 3.40 m
So wavelength range of FM radio is 2.77m - 3.40m
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Which of the following is an advantage of recorded presentations? A. Start-times and time zones are not a factor. B. Speakers can adapt topic coverage if necessary. C. Audience members have the opportunity to provide feedback D. More visual aids can be used.
The statement describes an advantage of recorded presentations is that the audience members have the opportunity to provide feedback. Thus, the correct option for this question is C.
What do you mean by Recorded presentations?A recorded presentation may be defined as a popular format of multimedia content with a duration of several seconds or minutes that significantly expresses the advantages of a product, service, or any idea with the support of interesting graphic images, concise text, and appropriate narration.
According to the context of this question, a recorded presentation delivers an advantage to the audience to provide feedback. This is because the process of recorded PowerPoint presentation gives the actual sense and understanding to the audience similar to the real event.
Therefore, the correct option for this question is C.
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What is the purpose of nucleophilic substitution reactions of akyly halides experiment?
The purpose of nucleophilic substitution reactions of alkyl halides experiment is to demonstrate in the laboratory setting Nucleophilic substitution reactions of alkyl halides.
In this it is been aimed to observe nucleophilic substitution reactions, SN1 and SN2 will by the addition of a solvent to mixtures of alkyl halides. In order to make this experiment effective a standard procedure is being used and noted observations while each reaction occurred.
Nucleophilic substitution reactions are an important class of reactions that allow the interconversion of functional groups. For alcohols, the range of substitution reactions possible can be increased by utilizing the tosylates (R-OTs), an alternative method of converting the -OH to a better leaving group.
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An object moving with 108 km/h moves 400 m in 8 seconds. find the velocity attained by the object.
Answer:50ms-1
Explanation:use the formula v=d/t
in order to find the velocity,devide the distance with time taken.
since distance is 400 meters devide it with seconds whiuch gives us 50.
The Trichromatic Theory of Color Vision states there are three different cones that process different wavelengths of light. These wavelengths correspond to the colors: Group of answer choices
These wavelengths correspond to the colors: green, red, blue
What is wavelength:
The wavelength of visible light determines the color that the light appears. Light with the longest wavelength appears red, and light with the shortest wavelength appears violet.
what is The Trichromatic Theory of Color Vision:
Trichromatic theory states that there are three types of receptor cells in the retina, which reacts to the light of three different wavelength.
These receptor cells are responsible for perception of colors.
A spectrally pure or monochromatic color can be produced by a single wavelength.
According to Trichromatic theory of color vision,
The colors are: green, blue and red.
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Energy in should always be equal to energy out. select an answer and submit. for keyboard navigation, use the up/down arrow keys to select an answer.
a. true
b. false
Energy in should always be equal to energy out. This is a False statement.
- Energy In: Energy put into the body in form of calories from food like fats, carbohydrates and proteins.
- Energy Out: Energy burn for basic functions of the body like beating of the heart during physical movements.
When we consume more energy but does not consume it upto its potential, the body keeps storing the excess amount of energy as body fat. Maintaining a balance between Energy In and Energy Out is important to live a healthy lifestyle since the disbalance creates problems to the body.
It is easier to accurately measure change in energy than to measure the amount of energy present.
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compare and contrast the medical understanding of death (that you have read about and learned about in this chapter) and the popular, typical understanding of death. this is chapter 11 for forensics
The medical understanding of death is related to the scientific approach, and the popular understanding is related to the inclusive spiritual and cultural approaches.
What is death for science?Death occurs when an individual's cardiorespiratory and brain functions cease due to some factor, thus ending his life.
Popular understanding, on the other hand, is aligned with scientific knowledge, but it is also encompassing cultural and religious teachings, which define topics not proven by science, such as life after death for example.
Therefore, death is a delicate topic for society, and spirituality is the basis found for greater emotional comfort in individuals who suffer significant losses of loved ones.
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Gravity follows an inverse square law. This means that if the distance between two masses is decreased by a factor of 4, the gravitational force between those two masses:________
A. increases by a factor of 4.
B. increases by a factor of 2.
C. increases by a factor of 16.
D. decreases by a factor of 4.
E. decreases by a factor of 16.
Gravity follows an inverse square law. This means that if the distance between two masses is decreased by a factor of 4, the gravitational force between those two masses: C. increases by a factor of 16.
Gravitational force is an attractive force that exists between all objects with mass; an object with mass attracts another object with mass; the magnitude of the force is directly proportional to the masses of the two objects and inversely proportional to the square of the distance between the two objects.
Force between two masses = G M1 M1 / [tex]R^{2}[/tex]
since , gravitation force d follows an inverse square law
F is directly proportional to 1/[tex]R^{2}[/tex]
If distance between two masses is decreased by a factor of 4
Let initial distance : R
when distance between two masses is decreased by a factor of 4 = 4R
Force = G M1 M1 / [tex](4R)^{2}[/tex]
Force = G M1 M1 / [tex]16R^{2}[/tex]
16 Force = G M1 M1 / [tex]R^{2}[/tex]
since , there is an inverse relation , so if distance is decreased , gravitation force will increase .
hence, gravitational force will increase by factor of 16
correct option C. increases by a factor of 16.
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When you lift twice the load twice as high, in half the time, the increase in potential energy is _______.
If you lift twice the load twice as high, in half the time then, the increase in potential energy is 4 times that of initial potential energy.
To find the answer, we need to know more about the gravitational potential energy.
What to find the potential energy?The form of mechanical energy possessed by a body by virtue of its position is called the potential energy.If the body is under the influence of gravitational field, then the energy possessed by the body is called gravitational potential energy.Given that,[tex]m'=2m\\h'=2h[/tex] where, m' and h' are the final mass and height.
We have the expression for potential energy as,[tex]U=mgh\\[/tex] , let us take this as the initial energy.
Then the final energy will be,[tex]U'=m'gh'=2m*g*2h=4mgh.\\U'=4U[/tex]
Thus, we can conclude that, the final potential energy is 4 times the initial.
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The final potential energy will be 4 times that of the initial, if we are twice the height and load.
To find the answer, we need to study about the gravitational potential energy.
Where can one find potential energy?Potential energy is the type of mechanical energy that a body possesses as a result of its position.The energy a body possesses is known as gravitational potential energy if it is being affected by a gravitational field.Due to that,[tex]m_f=2m\\h_f=2h[/tex]
where the final mass and height are denoted by mf and hf.
The phrase we use to describe potential energy is,[tex]U_i=mgh[/tex]
let's consider this to be the initial energy.
The final energy will then be,[tex]U_f=2m*2h*g=4mgh=4U_i[/tex]
As a result, we may say that the final potential energy is four times more than the original.
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what is the best fuse for 1000 w heater?
a)3A
b)4A
c)5A
d)11A
c)5A
Explanation:
As,
[tex]I = \frac{P}{V} = \frac{1000}{220} = 5[/tex]
How many excess electrons must be distributed uniformly within the volume of an isolated plastic sphere 26.0 cm in diameter to produce an electric field of 1440 N/C just outside the surface of the sphere
a metaphor for generosity and joy and joy and joy and joy organised a large wedding guests had to choose their meal from beef chicken tikka and a kind young women in the streets of St
The number of excess electrons needed to be distributed uniformly in the sphere to produce the given electric field is 1.69*10^(10).
What is an electric field?
The electric force exerted on a unit charge is called the electric field.
For a sphere of uniform charge density, the magnitude of the electric field on its surface is given by,
E=k*q/r^2
where E is the magnitude of the electric field, k is the coulomb's constant which has a value of 9*10^9 N m^(2) C^(-2), and q is the total charge of the sphere, and r is the radius of the sphere.
The radius of the sphere is half of the diameter. Given the diameter of the sphere is 26.0 m, the radius of the sphere r=26.0/2 cm or r=13.0 cm.
It is given that E=1440 N/C, r=13.0 cm, and the value of k is 9*10^9 N m^(2) C^(-2). Substitute these values in the formula of the electric field and solve it to get the value of the total charge on the sphere.
Note: 1 cm = 0.01 m.
1440 (N/C)= (9*10^9 N m^(2) C^(-2))*q/( 13 cm)^2
1440 (N/C)= (9*10^9 N m^(2) C^(-2))*q/( 13*0.01 m)^2
1440 ( N/C)= (532.54*10^(9) N C^(-2))*q
q=1440/(532.54*10^(9)) C
q=2.704*10^(-9) C
Since the charge is quantized, the total charge inside the sphere is the integral multiple of an elementary charge. In the given case, the value of that elementary charge is 1.6*10^(-19) C. The total charge is then given by,
q=ne
where q is the total charge, n is the number of elementary charges and e is the value of the elementary charge.
The value of q is 2.704*10^(-9) C and the value of e is 1.6*10^(-19) C.
Substitute these values in the formula of total charge and solve it to get the number of elementary charges.
2.704*10^(-9) C =n*1.6*10^(-19) C
n=2.704*10^(-9)/ 1.6*10^(-19)
n=1.69*10^(10)
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A sky-diver jumps from a stationary balloon. His initial downwards acceleration is 10m/s².
Fig. 1.1 shows the directions of the air resistance and the weight of the sky-diver.
The mass of the sky-diver is 60 kg and his weight is 600 N.
(a) Explain, using ideas about the forces, why his initial downwards acceleration is 10m/s².
Explanation:
a. The force acting down is gravity, on Earth gravity is 10 m/s^2. When the skydiver jump, the acceleration will start out as -10 m/s^2, but it will eventually equals the air resistance , which is called terminal velocity.
13. Which compound is most reactive?
ethene
ethyne
ethane
Answer:
Ethyne consists of a triple bond that is most easier to be broken as compared to that of ethyne with a double bond and benzene single bonds. Therefore ethyne is most reactive among the given options.
Explanation:
Answer: Ethyne
Explanation:
Calculate the “index of refraction” of a medium where the speed of light through it is 1.24 x 108 m/s. Use the GRASS method, write your solution on paper and insert an image of it below
The index of refraction of the medium where the speed of light is 1.24× 10⁸m/s, is 2.42.
To find the answer, we need to know about the relation between the refractive index and velocity of light.
What's the the expression of refractive index of a medium in term of velocity of light?Refractive index of any medium (n)= C/VC= speed of light in vaccum which is 3×10⁸ m/s , V = velocity of light in the mediumWhat's the refractive index of a medium in which speed of light is 1.24 x 10⁸ m/s?Refractive index of the medium =
3×10⁸/1.24 x 10⁸
= 2.42
Thus, we can conclude that the refractive index of the medium is 2.42.
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How to change a flat tire presentation?
Having a flat tire is one of the predominant inconveniences of riding. A guide car jack is designed to raise the vehicle high sufficient to eliminate the flat tire.
Converting a tire is definitely an alternative bodily trauma. we need to place a few muscles in getting the lug nuts off and cranking the jack, after which you need to bend down and lift the tire. regularly, oldsters will try to do all of this in a rush to get on their way, however, it really is a mistake.
To change eliminate the flat tire. The following steps should be followed:-
A spare tire. A lug wrench or torque wrench.Wheel wedges.A transportable tire inflator.A tire gauge to read the endorsed tire strain.Having a flat tire is one of the predominant inconveniences of riding. while a terrific spare is unavailable, you both have to call a tow truck or repair the tire ourselves. luckily, the process of fixing it yourself is noticeably sincere and requires only a few gears.
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Consider the elliptical orbit of a comet around the sun. where in its orbit is the comet moving the fastest?
Considering the elliptical orbit of a comet around the sun , the closer is the comet , the faster it will move .
Comets are thought to orbit the sun in either the Oort cloud or Kuiper belt. When another star passes by the solar system, its gravity pushes the Oort cloud and/or Kuiper belt and causes comets to descend toward the sun in a highly elliptical orbit with the sun at one focus of the ellipse. The closer is the comet , the faster it will move
It is been observed that comets motion is mostly get affected by sun's gravity. As a comet gets closer to the sun it moves faster and faster and as comet gets away from the sun , its speed get decreased. So, the comet should be as closer at it can be to the sun in order to move fastest
Here , it can be observed that comet's speed is inversely proportional to its distance from the sun.
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Astronomers and physicists now believe they know what is happening to the missing neutrinos from the Sun (the neutrinos that our theories say should be emerging from the Sun, but our experiments in that underground mine could not find). These neutrinos are:
The missing neutrinos from the sun had merely tranformed into muon and tau neutrinos escaped detection.Hardly interacting with other matter,neutrinos comes in three different types electron,muon,and tau.
Hence option (b) turning into different type of neutrino in a neutrino oscillation is correct
Disclaimer:The question given on the portal is incomplete .Here is the complete question .
Question :Astronomers and physicists now believe they know what is happening to the missing neutrinos from the Sun (the neutrinos that our theories say should be emerging from the Sun, but our experiments in that underground mine could not find). These neutrinos are:
a)not being produced by the Sun because our star's nuclear fusion period has ended
b)turning into a different type of neutrino in a neutrino oscillation
c)being converted to antimatter in the core of the Sun and being destroyed as they hit matter
d)changing course before they reach the Earth as they hit other neutrinos in space
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A 100-lb child stands on a scale while riding in an elevator. What does the scale read while the elevator slows to stop at the lowest floor
Answer: A 100-lb child stands on a scale while riding in an elevator. Then, the scale reading approaches to 100lb, while the elevator slows to stop at the lowest floor
Explanation: To find the correct answer, we need to know more about the apparent weight of a body in a lift.
What is the apparent weight of a body in a lift?Consider a body of mass m kept on a weighing machine in a lift.The readings on the machine is the force exerted by the body on the machine(action), which is equal to the force exerted by the machine on the body(reaction).The reaction we get as the weight recorded by the machine, and it is called the apparent weight.How to solve the question?Here we have given with the actual weight of the body as 100lbs.This 100lb child is standing on the scale or the weighing machine, when it is riding .During this condition, the acceleration of the lift is towards downward, and thus, a force of ma .There is also mg downwards and a normal reaction in the upward direction.when we equate both the upward force and downward force, we get,[tex]ma=mg-N\\N=mg-ma[/tex] i.e. during riding the scale reads a weight less than that of actual weight.
When the lift goes slow and stops the lowest floor, then the acceleration will be approaches to zero.Thus, from the above explanation, it is clear that ,when the elevator moves to the lowest floor slowly and stops, then the apparent weight will become the actual weight.
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An object starts at rest. Its acceleration over 30 seconds is shown in the graph below:
Answer:6m/s
Explanation:as you can see before twenty seconds there was no change in speed,but between twenty to thirty seconds,the speed changed from 0m/s to 6m/s,so change in speed is 6m/s.
The speed of an object between 20 and 30 seconds shown in the graph is 70 m/s.
Given:
Time, ΔT = 30-20 = 10s
Acceleration, a = 7 m/s²
The speed can be computed from the acceleration and time. The standard unit of velocity is meters per second.
For the given case, the speed can be computed from the acceleration and time given in the graph.
The speed is given as:
a = v/t
v = at
v = 7×10
v = 70 m/s
Hence, the speed of an object between 20 and 30 seconds shown in the graph is 70 m/s.
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