you toss a ball straight upward so it leaves your hand at a speed of 10.1 m/s. if the 3.3 kg ball started at rest and the tossing action lasted 0.33 s, what was the strength of the force exerted on the package by your hand?

480 W  is the power output of the secondary coil.

primary  coil current = ip = 4A

primary coil  voltage = vp = 120v

power out put of secondary coil

p = vi

   = 120v * 4A = 480W.

Power is the amount of work completed in a given amount of time. Watt (W), which is derived from joules per second (J/s), is the SI unit of power. Horsepower (hp), which is roughly equivalent to 745.7 watts, is a unit of measurement sometimes used to describe the power of motor vehicles and other devices.

The rate at which work is performed on an object is referred to as its power. Power is a temporal concept. It has to do with how quickly a task gets completed. The power equation is described below.

Power = Time + Work

P = W / t

The standard metric unit for power is a Joule/second, which is defined as the product of the standard metric units of work (the Joule) and time (the second).

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The drag force acting on the rocket is 80N.

The divergence in velocity between the fluid and the item, also known as drag, exerts a force on it. Between the liquid and the solid object, there should be motion. Drag is absent in the absence of motion.

The air molecules are more compressed (pushed together) on the surfaces that are facing the front while being more dispersed (spread out) on the surfaces facing the back. Turbulent flow, which occurs when air layers split from the surface and start to swirl, is what causes this.

The drag force acting on the rocket F = ma

Given,

m = 4kg, a = 20ftm/s²

Substituting m and a values in the above formula,

The drag force acting on the rocket F = 4×20

The drag force acting on the rocket F = 80N.

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The moment of inertia of the boxer's forearm that has an angular acceleration of 125.0 rad / s² is 0.25 kg m²

τ = F * ⊥d

τ = Torque

F = Force

⊥d = Perpendicular distance

F = 1495 N

⊥d = 2.1 cm = 0.021 m

τ = 1495 * 0.021

τ = 31.395 N m

τ = I α

I = Moment of inertia

α = Angular acceleration

α = 125 rad / s²

I = τ / α

I = 31.395 / 125

I = 0.25 kg m²

Therefore, the moment of inertia of the boxer's forearm is 0.25 kg m²

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(1) The ball is in the air for 1.4 seconds.

(2) The horizontal velocity of the ball as it rolls off the table is 6.32 m/s.

(3) The vertical velocity of the ball right before it hits the ground is 13.72 m/s.

(4) The horizontal velocity of the ball right before it hits the ground is 6.32 m/s.

(5) The initial vertical velocity as soon as the ball comes of the cliff is 13.72 m/s​.

The time of motion of the ball is calculated by applying the following equation.

t = √(2h/g)

where;

t =  √(2h/g)

t = √(2 x 9.63 / 9.8)

t = 1.4 seconds

The horizontal velocity of the ball is calculated as follows;

v = d/t

where;

v = 8.85 m / 1.4 s

v = 6.32 m/s

The vertical velocity of the ball before it hits the ground is calculated as;

vf = vi + gt

vf = 0 + 9.8 x 1.4

vf = 13.72 m/s

The horizontal velocity of the ball right before it hits the ground is calculated as;

the initial velocity of a projectile = final horizontal velocity

vxf = vxi = 6.32 m/s

The initial vertical velocity as soon as the ball comes off the cliff = final vertical velocity = 13.72 m/s

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The correct statements which describes current theories about dark energy and dark matter among the choices above are given below:

The answers are options a, b, and d.

Dark energy refers to that energy which acts against gravity, thereby resulting in the expansion of the universe. It's major constituent is current characterized with vacuum fluctuation. It is on this premise that dark energy was theorized to be causing the expansion of the universe to accelerate and itself including dark matter is filled in empty space.

So therefore, from the simple note above, it can be deduced that this type of energy does not produce electromagnetic radiation.

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Answer:

a b d

Explanation:

Which statements explain current theories about dark energy and dark matter? Check all that apply.

Space that appears empty actually contains dark energy and dark matter.

Dark matter does not emit electromagnetic radiation.

Scientists believe dark energy will cause the universe to collapse inward to a single point.

Scientists theorize that dark energy is causing the expansion of the universe to accelerate.

Dark matter includes all of the dust, ice, and debris that scientists observe in black holes.

(a) For the first 50 m:

h1 = 0.5 x a x t12

50 m = 0.5 x 9.8 m/s2 x t12

t1 = 3.19 s

Time to fall first 50 m = 3.19 s

(b) For the full 100 m:

h2 = 0.5 x a x t22

100 m = 0.5 x 9.8 m/s2 x t22

t2 = 4.52 s

Time to fall second 50 m = t2 - t1 = 1.33 s

Dropped rocks and other objects gain speed rapidly as they fall. Velocity defines the direction in which a body or object is moving. Velocity is primarily a scalar quantity. Velocity is basically a vector quantity. Rate of change of distance.

If our planet loses gravity for even 5 seconds it means the end of life on Earth as we know it. Gravity pulls objects together. The greater the mass of an object, the stronger its gravitational pull. Any submarine you choose for skydiving should be designed with movement in mind. If the weather is cool on the day of skydiving, you should choose pants that cover the entire leg. We recommend wearing sweatpants or sweatpants.

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The flow rate and the volume that passes through the artery in a period of 20 s is Q= 4.1448cm³/s and V= 82.896cm³.

We must define both the volume V and the instant in time it is flowing past represented by t in order to determine the Flow Rate denoted by Q, which is equal to V/t. In addition, the relationship between flow rate and velocity can be seen in the equation Q = Av, where A is the flow's cross-sectional area and v is its average velocity.

We must utilize the equation Q=V x A, where Q is the flow rate, V is the velocity, and A is the area, to determine the flow rate.

We must apply this formula to determine the volume. V = Q x t, where Q is the flow rate, t is the time, and V is the volume.

Converting 2mm to cm is the first thing we must accomplish.

2mm x 0.1= 0.2 cm

Currently, we utilize the calculation Q=V x A, but we must keep in mind that the area of an artery is circular, therefore we swap out A with the formula π r2.

Q= 33 cm/s x 3,14x (0.2cm)²

Q= 33cm/s x 0.1256cm²/s

Q= 4.1448cm³/s.

There is a flow at 4.1448cm³/s.

Now, using the flow rate (Q), we may

V=  4.1448 cm³/s x 20s

V= 82.896cm³.

82.896cm3 of fluid travels through the artery every 20 seconds.

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Answer:

Explanation:

Work:

A = m·g·h = 32·9.8·0.1 = 31.36 L

Power:

N = A / t = 31.36 / 0.83 ≈ 38 W

Mass of the heaviest book is 0.733 kg.

Heaviest book has weight

= (6 + 6) * 0.6 N

= 7.2 N

If m = mass of the heaviest book in kg

m = 7.2/9.81 kg

   = 0.733 kg.

Children often bring a well-established "life-view" of friction with them because of their experiences with slippery surfaces like frozen ponds (low friction) and "gripping" surfaces like deep pile carpets (high friction) and the effects they have on movement. This way of existence needs to be expanded and understood in the perspective of science.

The force that modifies movement as a result of surface/surface interaction is known scientifically as friction (all changes of movement require the action of a force). When using diagrams to portray forces in action, the direction of the frictional force should be depicted as being opposed to that of the movement.

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Answer:

The change in momentum of the ball = 81 kg·m/s

Explanation:

Given:

m = 1.5 kg

V₁ = - 27 m/s

V₂ = + 27 m/s

____________

Δp - ?

The change in momentum of the ball:

Δp = m·ΔV

Δp = m· (V₂ - V₁) = 1.5·(27 - (-27)) = 1.5·(27 + 27) = 81 kg·m/s

The graph of the vertical component of the ball's velocity is in the attachment

Speed is the distance moved per unit time.

Velocity is the total displacement per unit time of an object.

Since a 0.1 kg ball is kicked from the edge of a cliff so that it attains a launch speed of 20 m/s at an angle of 37 to the horizontal, as shown above. To determine the vertical component of velocity,we use the equation of motion

v = u - gt where

So, substituting the values of the variables into the equation, we have

v = u - gt

v = u'sinФ - gt

v = (20 m/s)sin37° - (9.8 m/s²)t

v = (20 m/s) × 0.6018 - (9.8 m/s²)t

v = 12.04 m/s - (9.8 m/s²)t

So, for the first 3 seconds, we have

for t = 0 s

v = 12.04 m/s - (9.8 m/s²) × 0 s

v = 12.04 m/s - 0 m/s

v = 12.04 m/s

for t = 1 s

v = 12.04 m/s - (9.8 m/s²) × 1 s

v = 12.04 m/s - 9.8 m/s

v = 2.24 m/s

for t = 2 s

v = 12.04 m/s - (9.8 m/s²) × 2 s

v = 12.04 m/s - 19.6 m/s

v = -7.56 m/s

for t = 3 s

v = 12.04 m/s - (9.8 m/s²) × 3 s

v = 12.04 m/s - 29.4 m/s

v = -17.36 m/s

So, we plot the graph of the vertical component of the ball's velocity using the equation v = 12.04 m/s - (9.8 m/s²)t

Find the graph in the attachment

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Answer:

The fact that change in moment is equal to force times duration can be derived from Newton's Second Law of Motion (assuming that the net force on the object is constant.)

Explanation:

Let [tex]m[/tex] denote the mass of an object. Let [tex]\Delta v[/tex] denote the change in the velocity of this object. The change in momentum of this object will be [tex]\Delta p = m\, \Delta v[/tex].

Let [tex]F_{\text{net}}[/tex] denote the net force (resultant force) on the object. Let [tex]a[/tex] denote the acceleration of this object. By the law of motion, [tex]F_{\text{net}} = m\, a[/tex], or equivalently, [tex]a = (F_{\text{net}} / m)[/tex].

Assume that this net force is constant and is exerted on this object over a period of [tex]\Delta t[/tex]. With an acceleration of [tex]a = (F_{\text{net}} / m)[/tex], the velocity of this object would have changed by:

[tex]\begin{aligned}\Delta v &= a\, \Delta t \\ &= \left(\frac{F_{\text{net}}}{m}\right)\, (\Delta t) \\ &= \frac{F_{\text{net}}\, \Delta t}{m}\end{aligned}[/tex].

Multiply both sides of this equation by the mass [tex]m[/tex] of the object to obtain:

[tex]m\, \Delta v = F_{\text{net}}\, \Delta t[/tex].

Note that [tex]m\, \Delta v[/tex] is equal to the change in momentum ([tex]\Delta p = m\, \Delta v[/tex].) Therefore, if the net force [tex]F_{\text{net}}[/tex] on the object is constant, the change in the momentum [tex]\Delta p[/tex] over time period [tex]\Delta t[/tex] will be equal to [tex]F_{\text{net}}\, \Delta t[/tex] (net impulse on the object.)

The number of waves that pass by each second is the frequency of a wave, which is expressed in Hertz (Hz). For instance, a sound wave may have a frequency of 450 Hz.

The wave frequency is the quantity of waves that pass a certain location in a predetermined amount of time. The SI unit for wave frequency is the hertz (Hz), and 1 hertz is equal to 1 wave passing through a fixed point in 1 second. When two waves of equal amplitude and frequency are compared, the higher frequency wave has greater energy.

Divide the wave's velocity by its wavelength to determine its frequency. The unit for frequency is Hertz (Hz), so use that while writing your response. The frequency will be the inverse of the time, or 1 divided by T, if you need to determine it from the amount of time it takes for a wave cycle to complete, or T.

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The planets move on linear motion without acceleration. Motion in one spatial dimension is described as linear motion, often known as uniform motion or rectilinear motion.

Moving in a straight line is the motion that an object naturally exhibits. A forceless item will move in a straight line indefinitely, according to Newton's First Law of Motion.

An object is said to be moving linearly when it has a tendency to move in a straight line. Rectilinear motion is another name for linear motion. Many of the things we do every day, like walking, bowling, playing on a slide, etc., exhibit linear motion in reality.

Both the ultimate displacement and the velocity are positive, indicating that they are moving in the same direction. The link between displacement, average velocity, and time is described by the equation x = x0+(average v)t.

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The blade goes through 25 evolutions throughout this period.

Angular velocity is the speed at which an object rotates or revolves around an axis or alters the angle between two bodies. The angle between a line on one body and a line on the other in the illustration serves as a representation of this displacement.

Formula using,

Ф = (ω+ω')t/2

Where Ф = amount of revolution the blade undergo,

Given: ω = 1200 rev/min,

ω' = 300 rev/min,

t = 2 seconds = (2/60) min = 1/30 min

Substitute into equation 1

Ф = (1200+300)(1/30)/2

Ф = 1500/(30×2)

Ф = 1500/60

Ф = 25revolutions.

The blade goes through 25 evolutions throughout this period.

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Work done when a 125 g tomato is lifted 13.6 m is calculated as 16.66 J .

The product of the component of force in the direction of the displacement and the magnitude is called work done by force and energy is defined as the ability to do work.

Work can be calculated by multiplying force with distance in the direction of force , and can be written as :

W = F × d

Given m= 125g = 0.125 kg

h= 13.6 m

W= P E

= m *g *h

= 0.125 * 9.8 * 13.6

Work done = 16.66 J

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Answer:

Pressure = 223 kPa

Explanation:

Given:

p₁ = 112 kPa = 112 000 Pa

t₁ = 35°C;    T₁ = 273 + 35 = 308 Pa

t₂ = 340°C;    T₂ = 273 + 35 = 613 Pa

V - const

___________

p₂ - ?

Charles' law:

p₁ / T₁ = p₂ / T₂

The pressure:

p₂ = p₁·T₂ / T₁

p₂ = 112 000·613 / 308 ≈ 223 000 Pa   or  p₂ = 223 kPa

Answer:

250N

Explanation:

weight of object - air resistance= net force

weight=mg

=30×10

=300N

air resistance =50

300-50=250

With the aid of your spectroscope and E = (h*c)/wavelength, you can determine the energy of the emitted light to be 3.97 x 10-19.

mathematical representation The movement v (in the x direction), frequency f, and wavelength of traveling sinusoidal waves are frequently expressed mathematically as follows: where y is the value of the wave at any place x and time t, and A is the wave's amplitude.

The symbol for the wavelength in the SI is typically m, or one metre. The multiples or fractions of something like a meter are also employed for measuring wavelength. Notably, when wavelengths are a significant attribute, exponential powers of 10 are employed. Shorter wavelengths are given as negative exponentials.

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the final velocity of the car (in m/s) after the collision is 6.25 m/s

12.5 m/s is moving in the initial direction of the car

1. A car of mass 1500 kg moving at a speed of 25.0 m/s collides with a truck of mass 4500 kg at rest. the bumpers of both vehicles lock on impact.

A. Compare the force exerted by the car on the truck with the force exerted by the truck on the car during the collision. Is one force greater than the other, or are they equal in magnitude?

the force exerted by the car on the truck and the force exerted by the truck in the collision.

creates a pair of actions and reactions

are equal in magnitude and opposite in direction according to Newton's third law

b. What is the final speed of the car and the truck just after the collision? show your calculations.

v=m1u1+m2u2/m1+m2=1500*25+0/1500+4500=6.25 m/s

2. the same collision as in the above question occurs, but this time the car and truck bounce off each other completely elastically.

C. Compare the force exerted by the car on the truck with the force exerted by the truck on the car in the collision. is one force greater than the other or are they equal?

the force exerted by the car on the truck and the force exerted by the truck in the collision.

creates a pair of actions and reactions

are equal in magnitude and opposite in direction according to Newton's third law

d. what is the final speed of the car and truck just after the collision?

view the calculation

v1=[m1-m2/m1+m2]u1+[2m2/m1+m2]u2=[1500-4500/6000]*25+[9000/6000]*0=-12.5 m/s

a negative sign means the car is moving backwards at 12.5 m/s

v2=[m2-m1/m1+m2]u2+[2m1/m1+m2]u1=[4500-1500/6000]*0+[3000/6000]25=12.5 m/s

moves in the original direction of the car

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Work done by the sprinter in first 2.5 s will be 702.699 J.

Work done is the product of force and distance covered.

Mass of the sprinter = 58 kg

Distance covered by the sprinter = s = 60 m

Total time taken by the sprinter = t = 7.8 s

u = initial velocity = 0

a = constant acceleration

60 =  [tex]\frac{1}{2}a7.8^{2}[/tex]

60.84 a = 60 * 2

a = 1.97 [tex]m/s^{2}[/tex]

For a = 1.97 [tex]m/s^{2}[/tex] and t = 2.5 s

d =  [tex]\frac{1}{2}at^{2}[/tex]

Here also u is '0' because the distance is being measured from the starting point.

d = [tex]\frac{1}{2} *1.97*(2.5)^{2}[/tex]

d = 6.15 m

Work done by the sprinter = F * d

Force = mass * acceleration

F = 58 * 1.97

F = 114.26 N

distance for first 2.5 sec is 6.15 m

Therefore Work done = 6.15 * 114.26

W = 702.699 J

Work done by the sprinter is 702.699 J.

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The neighborhood can help children build new relationships by holding a winter festival with activities for children and families.

In today's world, where everyone is quite busy in their own world, children have academic pressure and many more.

They tend to detach themselves from people, and hence many relationships ruin.

Building relationship helps the children grow and makes them more sociable. It boots their intelligence and makes them aware of the importance of having a relationship and building bonds with people.

The neighborhood holds a winter festival with activities for children and families is a great way to build new relationships.

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Answer:

The distance between the poles is 46 m.

Given information indicates that the two towers are 50 meters tall and that the cable is 80 meters long. The midpoint of the cable, designated as h, is 10 meters above the ground.

Let the height be y and the distance from the midpoint to either tower be x. therefore by catenary equation, we get,      

                              y=hcos(x/h)

                            =>50=10cos(x/10)

                  Therefore  5=cosx/10

By the tabulated value from the hyperbolic cosine function, we get the value of

                          cos⁻¹(5)=x/10

                         =>2.3=x/10

                         =>x=23

Therefore the distance between the poles is 2x = 2 x 23 = 46 m.  

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When an astronomer rambles on and on about the luminosity of a star she is studying, she is talking about  the amount of energy the star gives off each second.

Luminosity and apparent brightness are about brightness, but from a different point of view. The difference between luminosity and apparent brightness is that luminosity tells us exactly how bright a star really is while apparent brightness only tells us its brightness seen from Earth.

L / Lsun = ( d / dsun )² = b / bsun

L = Luminosity of a star

Lsun = Luminosity of sun

d = Distance of star

dsun = Distance of sun

b = Brightness of star

bsun = Brightness of sun

Therefore, when an astronomer rambles on and on about the luminosity of a star she is studying, she is talking about  the amount of energy the star gives off each second.

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The atmosphere supports a column of mercury with a height of 760 mm. Supports a 32 m high water column. And, of course, that's why we fill the barometer with mercury instead of water or alcohol.

The vapor pressure of mercury is also minimal. Therefore, the pressure at the exit point is equal to atmospheric pressure. This pressure is therefore equal to 10 to the power of 5 times 1.1. The base area of ​​this water cube is 12" x 12" = 144 square inches. So, the pressure at the bottom of the water cube is 62.4 pounds / 144 square inches = 0.433 pounds per square inch (psi). The RCC column minimum size is 9" x 9" and incorporates four 12mm bars steel stiffeners and cleats of 8mm steel rings spaced 150mm center to center.

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Answer:

The answer is photons.

When rock on Earth's surface is broken into smaller pieces, forming loose material  is called Weathering.

Physical weathering and chemical weathering are the two basic types of weathering. On this page, we discuss mechanical weathering (and more).

Rocks naturally fracture at a number of different levels. The borders between mineral grains can be a source of weakness in the rock. Sedimentary rocks are frequently stratified, and the layers are occasionally not tightly bonded together. As larger, more massive rocks are exposed by erosion, joints (cracks with no relative motion across them, merely spreading) may form in the rocks. These rock fissures become wider due to physical deterioration. Of course, biological weathering refers to weathering caused by living creatures.

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The second student must push with a force greater than 150 N to cause the car to accelerate.

The net force on the car is the sum of all the forces acting on the car. The direction of the net force on the car will determine the direction of motion of the car.

According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

The net force on the car is calculated as follows;

F(net) = F - Ff

ma = F - Ff

where;

For the car to move, sum of the applied forces must be greater than the force of friction.

200 + F > 350

F > 350 - 200

F > 150

Thus, the second student must push with a force greater than 150 N before the car can accelerate.

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Displacement from the center line for minimum intensity is 1.35 mm , width of the slit  is 0.75 so  Wavelength of the light  is 506.25.

When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.

This is a straightforward situation in which we can apply the

Fraunhofer single slit diffraction equation:

y = mλD/a

Where:

y = Displacement from the center line for minimum intensity =  1.35 mm

λ =  wavelength of the light.

D = distance

a = width of the slit = 0.75

m = order number = 1

Solving for λ

λ = y + a/ mD

Changing the information that the issue has provided:

λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2  

=5.0625 *10^-7 = 506.25

so

Wavelength of the light 506.25.

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