Answer:
Technician A
Explanation:
Technician A is correct. Technician B is wrong, as different drive vehicles (FWD, RWD, AWD, 4WD) each require a certain rotation for optimal tire wear.
The autorotation spin characteristics of a straight-wing aircraft are induced by Group of answer choices
Answer:
More Drag on the down going wing and More Lift on the up going wing
Explanation:
The autorotation spins of blades used in airborne wind energy technology sectors help drive and move the winds and water propeller-type turbines or shafts of generators to produce electricity at altitude and transmit the electricity to earth through conductive tethers.
Sometimes autorotation takes place in rotating parachutes, kite tails. Etc.
As a result, more Drag usually induces the autorotation spin characteristics of a straight-wing aircraft on the downgoing wing and More Lift on the up-going wing.
Steam enters an adiabatic turbine with a mass flow rate of 6 kg/s with a specific enthalpy of h = 3248.4 kJ/kg). It exits the turbine at a pressure of 15 kPa and a quality of 0.9. The power generated by this turbine, in kW, is
Answer:
5318.346
Explanation:
From the question we have
M = 6kg/s
P = 15kpa
h1 = 3248.4kj
x = 0.9
H2 is unknown
From the steam table
hf = 225.85
hg = 2599.36
H2 = HF + x(hg -hf)
h2= 225.85+0.9(2599.36 - 225.85)
= 225.85 + 0.9(2373.51)
= 225.85 + 2136.159
= 2362.009
To find The power generated by this turbine:
We insert all the parameters into the equation below:
m(h1 - h2)
= 6(3248.4 - 2362.009)
= 6 x 886.391
= 5318.346KW
Where should the Q point of an amplifier be on a DC load line to have the LARGEST linear output?
Answer:
At the middle of the DC load
Explanation:
For the Q point of an amplifier to have the Largest linear output. the Q plant has to be biased at the middle of the DC load line, this is because when the input voltage is low the transistor will be in the cutoff region while when the input voltage is very high the transistor will be in the saturation, hence when the Q point is biased at the middle it is will be higher linearly in relation to the active region
The Ksp for Ag2CrO4 is 9.0 x 10-12. If 200 mL of 0.0050 M AgNO3 is combined with 300 mL of 0.0020 M K2CrO4, will a precipitate form?
Answer:
Qsp > ksp
Explanation:
given data
Ag2CrO4 = 9.0 × [tex]10^{-12}[/tex]
solution
new [[tex]Ag^+[/tex]] = [tex]\frac{0.005 \times 200}{200+300}[/tex] = 0.002 M .................1
and
new [[tex]CrO^{2-}_4[/tex]] = [tex]\frac{0.002 \times 300}{200+300}[/tex] = 0.0012M ..............2
so here solubility equation will be as
[tex]Ag_2CrO_4(s)[/tex] ⇄ 2[tex]Ag^+[/tex] (aq) + [tex]CrO^{2-}_4[/tex] (aq) ......................3
so
Qsp = [tex][Ag^+]^2[/tex] [ [tex]CrO^{2-}_4[/tex]]
put here value
Qsp = (0.002)² × (0.0012)
Qsp = 4.80 × [tex]10^{-9}[/tex]
so that we can say that Qsp > ksp
Sam constructs a circuit, connects a lead acid battery of 2 V to a lamp of resistance 3 Ω and places an ammeter across it. What must be the reading of the ammeter?
A.
0.66 A
B.
0.5 A
C.
0.54 A
D.
0.61 A
Answer:
A. 0.66 Amps
Explanation:
Using ohms law, we can say that Voltage is equivalent to Current times Resistance. We are given the voltage and the resistance of the circuit, so we simply need to find the current.
V = IR
Solve for I, where V = 2volts and R = 3ohms.
V = IR
V * 1/R = I * R * 1/R
I = V/R
I = 2/3 Amps
Hence, we should choose option A, 0.66 Amps for the current in this simple circuit.
Cheers.
Why should low and high side access valves be installed when recovering refrigerant from a household refrigerator
Answer:
Because it helps to speed up recovery and required recovery efficiency When recovering refrigerant from a household refrigerator who's compressor does not run
The input resistance at the base of a biased transistor depends mainly on
(a) bDC
(b) RB
(c) RE
(d) bDC and RE
Answer:
D
Explanation:
What is the purpose of an engineer?
Answer:
Their purpose is to invent, design, analyze, build and test machines, complex systems, structures, gadgets and materials to fulfill functional objectives and requirements while considering the limitations imposed by practicality, regulation, safety and cost.
Answer:
To make things
Explanation:
In a four-stroke engine, the piston rises in the cylinder, which triggers the _______ stroke.
intake
compression
exhaust
power
Answer: It is power stroke
Pick up the correct statement from the following:
A. The theory of formation of concrete is based on the phenomena of formation of voids
B. The bulking of sand is taken into account while volumetric proportioning of the aggregates
C. The dry sand and the sand completely flooded with water, have practically the same volume
D. All the above
Answer:
D. All the above
Explanation:
A is correct. The theory of formation of concrete is based on this phenomenon of formation of voids because, a coarse aggregate aggregate on its own, contain voids. When a fine aggregate like sand is added, it occupies these voids. Further, when finely powdered cement is added to the mixture, it further occupies the voids between the sand particles.
B is correct. The bulking of sand should be taken into account when volumetric proportioning of the aggregates is adopted. Otherwise, less quantity of concrete per bag of cement will be produced, which naturally will increase the cost of concrete. This is because sand particles when left on their own, do not pack properly near each other due to sand buckling, leaving too many void spaces between the sand particles.
C is correct . The dry sand and the sand completely flooded with water have practically the same volume. This is due to the bulking of sand. When water is added to the sand, up to complete flooding, the sand particles pack near each other and the amount of bulking of sand is decreased. The addition of the volume of water, leads to a decrease in the volume of the sand due to the extra voids. These cancels out to practically leave the dry sand and the flooded sand with the same volume.
How can visual communication enhance the message conveyed with the speaker? Cite with a particular situation where in it is best to use visual communication
Answer:
1) Visual Communication involves the use of images ans symbolism for the exchange of ideas from a source to the intended audience.
Visual Communication can help enhance the message conveyed by the speaker when the message being conveyed is new to the audience, such as instructional or educational presentation by enable the audience to more quickly understand the the point of view of the speaker
2) A particular situation where it is best to use visual communication is in a communication that involves giving of traffic and way finding details to a tourist
Explanation:
Visual communication can improve the message that is transmitted with the speaker through the transmission of additional concepts to the message, such as gestures, body expressions or communicative looks, which add meanings to the words emitted.
Today, visual communication is extremely developed and is designed to perform several tasks at once. Communication through visual images is progressing thanks to the development of new technologies. Visual communication is one of the key components of modern media and social media.
Learn more in https://brainly.com/question/6753854
Briefly explain why small-angle grain boundaries are not as effective in interfering with the slip process as are high-angle grain boundaries.
Answer:
Explanation:
Small-angle grain boundaries are not as effective in interfering with the slip process as are high-angle grain boundaries because there is not as much crystallographic misalignment in the grain boundary region for small-angle, and therefore not as much change in slip direction.
Low angle grain boundaries (quasi-coherent) are formed by the dislocation network positioned along the geometric plane with small tilt angle differences between successive peers that is tilt boundary made up edge dislocations therefore it may only divert the slip direction of the incoming gliding dislocation with very little frictional stresses. And on the other hand, a high angle grain boundary region because of their disordered almost liquid like structure which acts as a strong barrier against dislocation slip motion and causes actually formation of dislocations file-up against it by arresting their motion unless that the stress concentration at the leading dislocation becomes high enough to go though the barrier.
Since most architects have at least a bachelor's degree, they do not require on-the-job training.
O True
O False
Answer:
The answer is false, I hope this helps. :3
Answer:
False
Explanation:
I took the quiz and it was correct
which of the following devices are used in networking? check all that apply?
switches, hubs,TCP or routers
Answer:
Hub , switch port , transmission media , hope I helped
Explanation:
The repair and rehabilitation of damaged or spalled concrete is done by removing the:____________A. Loose concreteB. CollapsingC. BreakageD. Bonding
Answer:
A. Loose concrete
Explanation:
Concrete is a solid composite structural material.It is the most used component in setting up a structure. Concrete is known for its very good ability to bear load, but can sometimes fail, or can be damaged. To rehabilitate or repair a concrete, the loose concrete must first be removed, so that the surface can be cleaned and well set before the material used for repair is applied on it.
The amount of time an activity can be delayed and yet not delay the project is termed:_________
A. Total slack.
B. Free slack.
C. Critical float.
D. Float pad.
E. Slip pad.
The correct answer is A. Total slack
Explanation:
Projects include multiple tasks or activities; moreover, each activity and the project itself have a specific due date. Besides this, activities can be delayed and this might affect or not the due date of the project. Indeed, some activities can have extra time without any effect on the date of the project, which is known as total slack or total float (delay in activities that does not delay the project.) Additionally, total slack is possible if activities or tasks are flexible, for example, if each task in a project should take 1 day and one of the tasks takes one day and a half, this can be compensated if another task takes less time. According to this, the correct answer is A.
A spherical ball of solid, nonporous naphthalene, a "mothball," is suspended in still air. The naphthalene ball slowly sublimes, releasing the naphthalene vapor into the surrounding air by the molecular diffusion-limited process. Estimate the time required to reduce the diameter from 2.0 to 0.50 cm when the surrounding air is at 347 K and 1.0 atm. Naphthalene has a molecular weight of 128 g/mol, a solid density of 1.145 g/cm3, and diffusivity in the air of 8:19 10␣6 m2=s, and exerts a vapor pressure of 5.0 Torr (666 Pa) at 347 K.
Answer:
The time required to reduce the diameter of solid spherical ball from 2 cm to 0.50 cm = 61.60 hours
Explanation:
Given that:
The bulk gas temperature T = 347 K
The pressure = 1.0 atm
Molecular weight of naphthalene = 128 g/mole
density of the solid = 1.145 g/cm³
diffusivity in the air of coefficient = 8.19 × 10 ⁻⁶ m²/s
vapor pressure = 5.0 Torr (666 Pa)
The shape of the ball in this given study is spherical. So, the first step we need to carry out is to state the general differential equation for the mass transfer in the system of the spherical coordinates. After that , we will make use of simplified differential expression form of Fick's Flux. From there we'll determine the surface concentration (c) of the species and finally determine the material balance equation on the naphthalene which will be used in solving the time required to reduce the diameter from 2.0 cm to 0.50cm.
THE DETAILED EXPLANATION OF WHAT WE JUST SAID CAN BE SEEN IN THE ATTACHED IMAGES BELOW.
A concrete column has a diameter of 390 mm and a length of 2.8 m . If the density (mass/volume) of concrete is 2.45 Mg/m3, determine the weight of the column in pounds.
Answer: 1804.61 lbs
Explanation:
Given, diameter of concrete column = 390 mm
= 0.390 m [ 1 mm =0.001 m]
⇒ Radius = [tex]\dfrac{0.390}{2}=0.195\ m[/tex]
also, Length = 2.8 m
Volume of column (cylindrical)= [tex]\pi r^2l[/tex]
[tex]=(3.14)(0.195)^2(2.8)[/tex]
[tex]=0.3343158\ m^3[/tex]
Density [tex]=\dfrac{Mass }{Volume}=2.45\ Mg/m^3[/tex]
⇒ Mass = 2.45 x (Volume)
= 2.45 (0.3343158) Mg
= 0.81907371 Mg
⇒ Mass = 819.07271 kg [1 Mg =1000 kg]
Weight = [tex]{mass}\times{gravity}={819.07271}\times{9.8}=8026.91\ N[/tex]
1 N= 0.22482 lb
Then, Weight = [tex]0.22482\times 8026.91=1804.61\ lb[/tex]
Weight of the column in pounds.= 1804.61 lbs (approx)
Weight of the column is 1804.61 lbs.
Given that,
Diameter of column is 390mm or 0.39m.Length (l) of column is 2.8m.Density of column is 2.45 Mg/m3According to the given data, calculation are as follows,
Diameter = 0.39m
So, radius (r) = 0.39 [tex]\div[/tex] 2 = 0.195m
Volume of column = [tex]\pi r^{2}l [/tex]
By putting the value, we get
Volume = [ (3.14)[tex]\times[/tex] [tex](0.195)^{2} [/tex] [tex]\times[/tex] 2.8m ]
= [tex]0.3343158m^{3} [/tex]
Now, as we know that,
Density = Mass [tex]\div[/tex] Volume
Or, Mass (M) = Density [tex]\times[/tex] Volume
= 2.45 [tex]\times[/tex] 0.3343158
= 819.07271 kg
Now Weight = (M [tex]\times[/tex] Gravity ) Value of gravity is 9.8.
Weight = 819.07271 kg [tex]\times[/tex] 9.8
= 8026.91N
Where, 1N = 0.22482 lbs
So, Weight of the column = 1804.61 lbs
Learn more : https://brainly.com/question/21667661
Tech a says that only a certain few people will find jobs in the automotive industry. Tech b says the automotive industry offers numerous career choices . Who's correct?
Answer: Tech B
Explanation:
From the question above, tech B saying the automotive industry offers numerous career choices is the correct answer. Pursuing a career in automotive industry is challenging and rewarding as one works with both vehicles and technology.
Examples of career choices in the automotive industry are car detailer, tire technician, car rental agent, auto mecahnic, vehicle inspector, auto electrician, auto engineer etc.
Who is father of Engineer?
John Smeatom, U.K. 18th century, was the first self-proclaimed, civil engineer in the 18th century and IS considered “the father of modern, civil engineering”.
hoped this helped! :)
Answer:
Sir Mokshagundam Visvesvaraya
You are driving on a roadway with multiple lanes of travel in the same direction, and are approaching an emergency vehicle parked along the roadway. You must:a. Leave the lane closest to the emergency as soon as it is safe to do so, or slow down to a speed of 20 MPH below the posted speed limit.b. Yield to the emergency vehicle.c. If you are in the lane closest to the emergency vehicle, immediately come to a complete stop and ask if anyhelp is needed.d. All of the above.
Answer: a. Leave the lane closest to the emergency as soon as it is safe to do so, or slow down to a speed of 20 MPH below the posted speed limit.
Explanation:
Giving a way to the law enforcement vehicle and a medical emergency vehicle is necessary. If one approaches an emergency vehicle parked along the roadway one should change the lane as the vehicle may not move and the driver may also waste his or her time also one should also slow down his or her speed while approaching the vehicle as most of the emergency vehicle are in rush to reach the hospital so the driver should maintain some distance with the medical emergency vehicle.
If a transistor is operating with 5 mA of Collector Current, 100uA of Base Current and VCE = 10 V. What is the power dissipation?
Answer:
well its 31.4226804124
Explanation:
What is the approximate probability that no people in a group of seven have the same birthday?
(A) 0.056
(B) 0.43
(C) 0.92
(D) 0.94
Answer: (D) 0.94
P(7 distinct birthdays) = 363/365 = 0.9438 (0.94)
The probability that no people in a group of seven have the same birthday is; D: 0.94
How to find the probability?The probability that no people in a group of seven have the same birthday is;
P(no two people in a group of seven) = P(1) * P(2) * P(3) * P(4) * P(5) * P(6) *P(7)
⇒ 365/365 * 364/365 * 363/365 * 362/365 * 361/365 * 360/365 * 359/365 = 0.9438 ≈ 0.94
Read more about Probability at; https://brainly.com/question/24756209
#SPJ9
A man weighs 145 lb on earth.Part ASpecify his mass in slugs.Express your answer to three significant figures and include the appropriate units.Part BSpecify his mass in kilograms.Express your answer to three significant figures and include the appropriate units.Part CSpecify his weight in newtons.Express your answer to three significant figures and include the appropriate units.Part DIf the man is on the moon, where the acceleration due to gravity is gm = 5.30 ft/s2, determine his weight in pounds.Express your answer to three significant figures and include the appropriate units.Part EDetermine his mass in kilograms.Express your answer to three significant figures and include the appropriate units.
Answer:
a) 4.51 lbf-s^2/ft
b) 65.8 kg
c) 645 N
d) 23.8 lb
e) 65.8 kg
Explanation:
Weight of the man on Earth = 145 lb
a) Mass in slug is...
32.174 pound = 1 slug
145 pound = [tex]x[/tex] slug
[tex]x[/tex] = 145/32.174 = 4.51 lbf-s^2/ft
b) Mass in kg is...
2.205 pounds = 1 kg
145 pounds = [tex]x[/tex] kg
[tex]x[/tex] = 145/2.205 = 65.8 kg
c) Weight in Newton = mg
where
m is mass in kg
g is acceleration due to gravity on Earth = 9.81 m/s^2
Weight in Newton = 65.8 x 9.81 = 645 N
d) If on the moon with acceleration due to gravity of 5.30 ft/s^2,
1 m/s^2 = 3.2808 ft/s^2
[tex]x[/tex] m/s^2 = 5.30 ft/s^2
[tex]x[/tex] = 5.30/3.2808 = 1.6155 m/s^2
weight in Newton = mg = 65.8 x 1.6155 = 106
weight in pounds = 106/4.448 = 23.8 lb
e) The mass of the man does not change on the moon. It will therefore have the same value as his mass here on Earth
mass on the moon = 65.8 kg
Copper (Cu) has FCC crystal structure. Atomic mass of Cu is 63.55 gmol-1 and radius of a copper atom is 0.128 nm, mean speed of conduction electrons in Cu is 1.5 × 10^6 m/s and frequency of vibration of the Cu atoms at 27 ° is 4 × 10^12 s-1. Nordheim’s Coefficient of Au in Cu is 5500 nΩ −m. a) Calculate the atomic density of copper b) Estimate the drift mobility of electrons in Cu c) Find the resistivity of pure Cu d) Find the resistivity of Cu if 1 at.% of Au is mixed in Cu. pls solve it
Answer:
First, there are 4 atoms in the FCC unit cell.
The unit volume of the unit can be calculated based on the atomic radii, in which case the hypotenuse of the cube of the unit cell would be 4 X 0.1278
Next, find the weight of one atom by taking (63.55g / mol) X (mols / 6.0221415 x 10 ^ 23 atoms)
So now you have all the numbers you need. Take the weight of the atom X 4 divided by the cube volume taken from the hypotenuse.
Explanation:
The resultant force is directed along the positive x axis and has a magnitude of 1330 N.
Determine the magnitude of F_A. Express your answer to three significant figures and include the appropriate units. Determine the direction theta of F_A. Express your answer using three significant figures.
Answer:
the magnitude of F_A is 752 N
the direction theta of F_A is 57.9°
Explanations:
Given that,
Resultant force = 1330 N in x direction
∑Fx = R
from the diagram of the question which i uploaded along with this answer
FB = 800 N
FAsin∅ + FBcos30 = 1330 N
FAsin∅ = 1330 - (800 × cos30)
FA = 637.18 / sin∅
Now ∑Fx = 0
FAcos∅ - FBsin30 = 0
we substitute for FA
(637.18 / sin∅)cos∅ = 800 × sin30
637.18 / 800 × sin30 = sin∅/cos∅
and we know that { sin∅/cos∅ = tan∅)
so tan∅ = 1.59295
∅ = 57.88° ≈ 57.9°
THEREFORE FROM THE EQUATION
FA = 637.18 / sin∅
we substitute ∅
so FA = 637.18 / sin57.88
FA = 752 N
Argon is compressed in a polytropic process with n = 1.2 from 100 kPa and 30°C to 1200 kPa in a piston–cylinder device. Determine the final temperature of argon.
Answer:
181 °C
Explanation:
Initial pressure [tex]P_{1}[/tex] = 100 kPa
Initial temperature [tex]T_{1}[/tex] = 30 °C = 30 + 273 K = 303 K
Final pressure [tex]P_{2}[/tex] = 1200 kPa
Final temperature [tex]T_{2}[/tex] = ?
n = 1.2
For a polytropic process, we use the relationship
([tex]T_{2}[/tex]/[tex]T_{1}[/tex] ) = ([tex]P_{2}[/tex]/[tex]P_{1}[/tex])^γ
where γ = (n-1)/n
γ = (1.2-1)/1.2 = 0.1667
substituting into the equation, we have
([tex]T_{2}[/tex]/303) = (1200/100)^0.1667
[tex]T_{2}[/tex]/303 = 12^0.1667
[tex]T_{2}[/tex]/303 = 1.513
[tex]T_{2}[/tex] = 300 x 1.513 = 453.9 K
==> 453.9 - 273 = 180.9 ≅ 181 °C
The final temperature of Argon in polytropic process is T = 181°C
Given data:
The initial pressure [tex]P_{1}=100kPa[/tex]
The final pressure [tex]P_{2}=1200kPa[/tex]
The initial temperature [tex]T_{1}=303K[/tex]
The value of n = 1.2
For a polytropic process:
[tex]\frac{T_{2}}{T_{1}} =\frac{P_{1}}{P_{2}}^{\beta }[/tex]
The value of [tex]\beta = \frac{(n-1)}{n}[/tex]
So, [tex]\beta =0.1667[/tex]
Substituting the values in the equation:
[tex]\frac{T_{2}}{303} =\frac{1200}{100}^{0.1667 }[/tex]
So, the value of [tex]T_{2}=453.9K[/tex]
The temperature in degree Celsius is [tex]T_{2}=181C[/tex].
Hence, the final temperature is T = 181°C.
To learn more about polytropic process, refer:
https://brainly.com/question/34358941
#SPJ6
what is
entrained
the difference between Air-
and Air- entrapped,
2
Answer:
sometimes small air bubbles are intentionally incorporated (entrained) into the mix using admixtures; other times larger bubbles are entrapped during mixing. When the bubbles are smaller than 0.04 inch, the air is called entrained; larger, and it's called entrapped.
Explanation:
Once the ideas were narrowed down and divided into categories, the group was split into four smaller teams. What phase(s) of the design process was each of these groups responsible for?
A. Shopping
B. Safety
C. Checkout
D. Finding stuff you need
Answer:
Finding stuff you need ( D )
Explanation:
Once an idea is narrowed down and divided into categories, The next line of action would be to create smaller groups that will be brainstorm solutions towards resolving the problem/ implement the idea faced by the team.
The phase of the design process that the smaller teams created will be focused on is to model and build a prototype ( finding stuff you need ) that would help implement the ideas
The output current of an amplifier is 190 mA and the input current is 32 mA. The current gain of the amplifier is:
Answer:
-5.9375 (or 5.9375 depending)
Explanation:
The current gain of the amplifier is simply the output current over the input current negated.
-190 mA / 32 mA == -5.9375
So the current gain for the amplifier was -5.9375
The answer a program may be looking for may not be negative, but based on the derivation, the gain should be negative for amplifiers.
Cheers.