Answers
Here ,
• Height of sign post = 30 m
• Distance between signpost and truck = 24 m
Let the
• Top of signpost = A
• Bottom of signpost = B
• The end of truck facing sign post be = C
Now as we can clearly imagine that the ladder will act as an hypotenuse to the Triangle ABC .
Where
• AB = Height of signpost = 30 m
• BC = distance between both = 24 m
• AC = Minimum length of ladder
→ AC² = AB² + BC² ( As we can see AB is perpendicular to BC )
→ AC² = (30)² + (24)²
→ AC² = 900 + 576
→ AC² = 1476
→ AC = 38.41875
or AC apx = 38.42
So minimum height of ladder = 38.42
This question can be solved by using the formula of "Pythagora's Theorem".
The ladder must be "38.42 m" long.
If we imagine the whole situation in terms of a right-angled triangle, we can safely assume the height of the billboard (which is the pole supporting the billboard) as the perpendicular of the right-angled triangle. The distance between the signpost and the truck can be assumed as the base of the triangle. The length of the ladder will then be acting as the Hypotenuse of the right-angled triangle.
The attached picture clearly depicts the condition explained in the above paragraph.
Now applying Pythagora's Theorem to this situation, we get:
[tex]Hypotenuse^2 = Perpendicular^2+Base^2\\Length\ of\ Ladder^2 = (30\ m)^2+(24\ m)^2\\L^2 = 1476\ m^2\\[/tex]
L = 38.42 m
Learn more about Pythagora's Theorem here:
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Related Questions
What is the threshold velocity vthreshold(water) (i.e., the minimum velocity) for creating Cherenkov light from a charged particle as it travels through water (which has an index of refraction of n
Answers
Answer:
2.3*10^8m/s
Explanation:
Using
V = c/n
Where c= speed of light
n = refractive index of water
By substituting
We have
V= 3*10^8m/s/1.33
= 2.3*10^8m/s
Select the correct answer. Physics is explicitly involved in studying which of these activities? A. the mixing of metals to form an alloy B. the metabolic functions of a living organism C. the motion of a spacecraft under gravitational influence D. the depletion of the atmospheric ozone layer due to pollutants E. the killing of cancerous cells by radiation therapy
Answers
Answer: C. the motion of a spacecraft under gravitational influence.
Explanation:
A is Metallurgy, B is Biology, C is astro-physics, I am not sure what D is, but it's safe to say it's not physics, E, micro-biology, and the study of radiation. C is the only one involving physics.
What is the potential energy of a 2 kg mass at a height of 40 meters?
Answers
Answer:
The potential energy of a 2 kg mass at a height of 40 meters is 784 J
Explanation:
Potential energy is that energy that a body possesses due to the height at which it is located and whose unit of measurement of the International System of Units is the joule (J).
The potential energy of a body is the result of multiplying its mass by its height and by gravity:
Ep=m*g*h
Potential energy Ep, is measured in joules (J), mass m is measured in kilograms (kg), gravity, g, in meters / second-squared ([tex]\frac{m}{s^{2} }[/tex]), and height, h , in meters (m).
In this case:
Ep=?m= 2 kgg= 9.8 [tex]\frac{m}{s^{2} }[/tex]h= 40 mReplacing:
Ep= 2 kg* 9.8 [tex]\frac{m}{s^{2} }[/tex] * 40 m
Solving:
Ep= 784 J
The potential energy of a 2 kg mass at a height of 40 meters is 784 J
A spherically spreading EM wave comes from an 1800-W source. At a distance of 5.0 m, what is the intensity, and what is the rms value of the electric field?
Answers
Explanation:
It is given that,
Power of EM waves, P = 1800 W
We need to find the intensity at a distance of 5 m. Also, the rms value of the electric field.
Intensity,
[tex]I=\dfrac{P}{4\pi r^2}\\\\I=\dfrac{1800}{4\pi\times (5)^2}\\\\I=5.72\ W/m^2[/tex]
The formula that is used to find the rms value of the electric field is as follows :
[tex]I=\epsilon_o cE^2_{rms}[/tex]
c is speed of light and [tex]\epsilon_o[/tex] is permittivity of free space
So,
[tex]E_{rms}=\sqrt{\dfrac{I}{\epsilon_o c}}\\\\E_{rms}=\sqrt{\dfrac{5.72}{8.85\times 10^{-12}\times 3\times 10^8}}\\\\E_{rms}=46.41\ V/m[/tex]
Hence, this is the required solution.
A woman exerts a horizontal force of 5 pounds on a box as she pushes it up a ramp that is 6 feet long and inclined at an angle of 30 degrees above the horizontal. Find the work done on the box.
Answers
Answer:
26 lbft
Explanation:
Given that
Force exerted by the woman, F = 5 lb
Length of the ramp, d = 6 ft
angle of inclination, θ = 30° above the horizontal
Work done on the box, W = ?
This is very much a straightforward question..
Work done, W = F * d, where the force takes the factor of the Angie if inclination. So that,
W = Fcosθ * d
On substituting, we have
W = 5 * cos 30 * 6
W = 5 * 0.866 * 6
W = 30 * 0.866
W = 25.98 lbft
Therefore, the work done on the box is 25.98 or approximately 26 lbft
A thin slab of Germanium is used as a Hall Effect probe. How would you orient a magnetic field to make the side facing out of the page be at a positive voltage with respect to the opposite side facing into the page
Answers
Answer:
the magnetic field must go in a direction parallel to the page perpendicular to the current.
Explanation:
The Hall effect is the voltage produced by the movement of electrons due to the effect of electric and magnetic fields in a material
F = eE + v x B
The electric field goes in the direction of the current that is opposite to the direction of the electrons, therefore the magnetic force must be perpendicular to it.
Therefore, if the current goes in a direction parallel to the page, in the x direction, the magnetic field must be perpendicular to it if we use the rule of the right wizard,
thumb points in the direction of E, x axis parallel page
The fingers extended should go parallel to the page in the direction and up
The palm is the direction of the Force, where the voltage will be produced points out the page, this is for positive charges, as in germanium the charges are negative, the real force goes into the page.
Therefore the electrons accumulate on the inside of the page and the voltage is negative in this part.
Therefore the voltage is positive on the outside of the sheet. In conclusion the magnetic field must go in a direction parallel to the page perpendicular to the current.
When light travels from air into water, Group of answer choices its velocity and wavelength change, but its frequency does not change.
Answers
Explanation:
When light travels from air into water, due to the change in refractive index of the two medium, refraction of light occurs.
Velocity of light in a medium is given by :
[tex]v=\dfrac{c}{n}[/tex]
c is speed of light
n is refractive index
The frequency remains the same in every medium. It means that the its velocity and wavelength change, but its frequency does not change.
Objects fall near the surface of the earth with a constant downward acceleration of 10 m/s2 . Suppose a falling object is moving downward at 10 m/s at a certain instant. How fast is it falling 2 sec later
Answers
Answer:
The final velocity of the object after 2 seconds is 30 m/s
Explanation:
Given;
constant downward acceleration, a = 10 m/s²
initial velocity of the object falling down, v = 10 m/s
time of fall, t = 2 s
The final velocity of the object is given by;
v = u + at
where;
v is the final velocity
v = 10 + (10)(2)
v = 10 + 20
v = 30 m/s
Therefore, the final velocity of the object after 2 seconds is 30 m/s
What is the average value of the magnitude of the Poynting vector S at 1 meter from a 100-watt lightbulb radiating in all directions
Answers
Answer:
The value is [tex]S = 7.96[/tex]
Explanation:
From the question we are told that
The power is [tex]P = 100 \ W[/tex]
The radius is [tex]r = 1 \ m[/tex]
Generally the average value of the magnitude of the Poynting vector is mathematically represented
[tex]S = \frac{P}{4 \pi r^2}[/tex]
=> [tex]S = \frac{ 100 }{ 4 *3.142 *1^2 }[/tex]
=> [tex]S = 7.96[/tex]
if you walk at 0.7 m/s, how long would it take to walk a mile which is 1609 m
Answers
Answer:
[tex]\Huge \boxed{\mathrm{2298.57 \ seconds}}[/tex]
[tex]\rule[225]{225}{2}[/tex]
Explanation:
[tex]\displaystyle \sf Speed = \frac{Distance \ covered }{Time \ taken}[/tex]
[tex]\displaystyle \sf s = \frac{d }{t}[/tex]
The speed is 0.7 m/s.
The distance covered is 1609 m.
[tex]\displaystyle \sf 0.7 = \frac{1609 }{t}[/tex]
Multiplying both sides by t.
Then dividing both sides by 0.7.
[tex]\displaystyle \sf t = \frac{1609 }{0.7}[/tex]
[tex]\sf t= 2298.57[/tex]
It would take 2298.57 seconds.
[tex]\rule[225]{225}{2}[/tex]
Answer:
[tex]\huge\boxed{\sf t = 2298.57\ secs}[/tex]
Explanation:
Given:
Speed = v = 0.7 m/s
Distance = S = 1 mile = 1609 metre
Required:
Time = t = ?
Formula :
v = S/t
Solution:
v = S/t
t = S/v
t = 1609 / 0.7
t = 2298.57 secs
Slogan for clinical psychologist
Answers
Hope this helps you ♥︎
If a planet was located approximately 24 thousand light-years from the center of a galaxy and orbits that center once every 194 million years, how fast is the planet traveling around the galaxy in km/hr? If needed, use 3.0 × 108 m/s for the speed of light.
Answers
84km/hr
Explanation:
To find one light yr
= 3E8m/s x 24x 365/1000
= 996980E7kms
So
Radius of orbit for 24000light years
=996980E7kms x 24000
Total orbit distance is = 2πr
= 2 *π x 996980E7kms x 24000
Total time will be
= 194E6 x 24x365 hrs
Finally speed = distance/ time
= 2 *π x 996980E7kms x 24000/194E6 x 24x365 hrs
= 84km/hr
define nuclear forces
Answers
The nuclear force is a force that acts between the protons and neutrons of atoms.
The nuclear force is a force that binds the protons and neutrons in a nucleus together.This force can exist between protons and protons,neutrons and protons and neutrons and neutrons.This force is what hold the nucleus together.
Fluid flows at 2.0 m/s through a pipe of diameter 3.0 cm. What is the volume flow rate of the fluid in m^3/
Answers
Answer:
Volume flow rate = [tex]1.41 \times 10^{-3}m^3/s[/tex]
Explanation:
The volume flow rate through a channel can be gotten by multiplying its area and its velocity.
The channel under consideration is a circular channel. Hence, the cross-sectional area can be calculated by using the relation for calculating the area of a circle
Cross-sectional area = [tex]\pi \times d^{2}/4[/tex]
[tex]A = \pi \times (3\times 10^-2)^2 /4 = 7.07 \times 10 ^-4 m^2[/tex]
volume flow rate= [tex]A = 7.07 \times 10 ^-4 m^2 X 2.0 = 1.41 \times 10^{-3}m^3/s[/tex]
Volume flow rate = [tex]1.41 \times 10^{-3}m^3/s[/tex]
When 10 N force applied at 30 degrees to the end of a 20 cm handle of a wrench, it was just able to loosen the nut. What magnitude of the force would require to just loosen the nut, of the force apply perpendicularly at the end of the handle
Answers
Answer:
5 N
Explanation:
From the question,
The magnitude of the force that would be required to just loosen the nut when the force is applied perpendicularly at the end of the handle is
Fy = Fsinθ................. Equation 1
Where Fy = force acting perpendicular at the end of the handle, F = Force applied to the handle, θ = angle of inclination of the force to the end of the handle.
Given: F = 10 N, θ = 30°
Substitute these values into equation 1
Fy = 10(sn30°)
Fy = 10(0.5)
Fy = 5 N.
How can Newton’s laws explain why the brain is in danger of injury when there is impact to the head? A. The brain is fixed in one place inside the skull and cannot move away from the impact. B. The brain moves inside the skull with a force equal and opposite to that of the impact. C. The blood vessels of the brain expand, so more blood flows to the brain. D. The blood vessels of the brain shrink, so less blood flows to the brain.
Answers
Answer:
B. The brain moves inside the skull with a force equal and opposite to that of the impact.
Explanation:
Just took the test and got it correct.
Applying Newton's laws the brain is in danger of injury when an impact is made to our head because ; ( B ) The brain moves inside the skull with a force equal and opposite to that of the impact
According to Newton's law an object will continue to be at rest except a force ( impact ) acts on it. also the third law of Newton states that when two objects interact ( The brain and the impact to the head ) they apply forces of equal magnitude to each other but in opposite directions from one another.
The Impact to the head will have a direct effect on the brain because the brain will move in opposite direction to the direction of the impact and with the same magnitude which will lead to an injury to the brain because the brain is suppose to be at rest at all times and not in motion.
Hence we can conclude that Applying Newton's laws the brain is in danger of injury when an impact is made to our head because The brain moves inside the skull with a force equal and opposite to that of the impact.
Learn more : https://brainly.com/question/13532462
what was the average speed in km/h of a car that travels 490.0 km in 4.2 h?
Answers
Answer:
BelowExplanation:
[tex]Distance = 490 \:km\\Time = 4.2 \:hours\\\\Average\:speed = \frac{Distance}{Time} \\\\A.V = \frac{490}{4.2} \\\\A.V = 116.67km/h[/tex]
A large tanker truck carrying Blazblue extract has a capacity of 29053 liters. The density of Blazblue extract is 0.770 grams per milliliter. What is the weight, in pounds, of a full load of Blyzblah extract.
Answers
Answer:
1319.14 lb
Explanation:
From the question above,
Density of the Blazblue extract = mass of Blazblue extract/volume of Blazblue extract.
D = m/v.............. Equation 1
make m the subject of the equation
m = D×v.................... Equation 2
Given: D = 0.770 grams per millilitre, v = 29053 liters = 29053000 millilitres
Substitute these values into equation 2
m = 0.770×29053000
m = 22370810 grams
If,
1 gram = 0.00220462 pounds,
Then,
22370810 grams = (22370810×0.00220462) = 41319.14 lb
Would hurt if u have a baby?
Answers
Answer:
yes it would.
Explanation:
4. A car increases velocity or speed from 25 m/s to 50 m/s in 5 seconds. What is the acceleration of the car ?
Answers
Answer:
5m/s²
Explanation:
v²-v¹ =50 - 25 = 25m/s = 5m/s²
t 5 5
How large a net force is required to accelerate a 1600-kg SUV from rest to a speed of 25 m/s in a distance of 200 m
Answers
Answer:
F=2496 N
Explanation:
Given that,
Mass of SUV, m = 1600 kg
Initial speed, u = 0
Final speed, v = 25 m/s
Distance, d = 200 m
We need to find the net force. Firstly, let's find acceleration using equation of motion.
[tex]v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(25)^2-(0)^2}{2\times 200}\\\\a=1.56\ m/s^2[/tex]
Net force, F = ma
[tex]F=1600\times 1.56\\\\F=2496\ N[/tex]
So, the net force is 2496 N.
The amount of net force that will be required to accelerate a 1600kg SUV from rest to a speed of 25 m/s in a distance of 200m is 2500N
HOW TO CALCULATE NET FORCE:
The net force of a body can be calculated by multiplying its mass by acceleration. However, the acceleration of this SUV needs to be calculated using the following equation of motion:v² - u² = 2asa = v² - u²/2sWhere:
a = acceleration (m/s²)v = final velocity (m/s)u = initial velocity (m/s)s = distance (m)a = 25² - 0²/2(200)a = 625/400a = 1.563m/s²Since a = 1.563m/s²
F = 1600 × 1.563F = 2500NTherefore, the amount of net force that will be required to accelerate a 1600kg SUV from rest to a speed of 25 m/s in a distance of 200m is 2500N.Learn more at: https://brainly.com/question/18031807?referrer=searchResults
Help!!! PLEASEEEEEEE
Answers
Answer:
I think the answer is D.
What is the electric field at a location vector b = <-0.2, -0.4, 0> m, due to a particle with charge +3 nC located at the origin?
Answers
Answer:
E = 134.85 N/C
Explanation:
We are given;
Electric field location; b = <-0.2, -0.4, 0> m
Charge: q = 3 nc = 3 × 10^(-9) C
From the location given, we have total distance;
r = √((-0.2²) + (-0.4)² + (0²))
r = √0.2
Formula for Electric field is;
E = kq/r²
where;
k is a constant with a value of 8.99 x 10^(9) N.m²/C²
q is charge on the proton particle with a costant value = 1.6 × 10^(-19) C
r is the distance
Plugging in the relevant values, we have;
E = (8.99 x 10^(9) × 3 × 10^(-9))/(√0.2)²
E = 134.85 N/C
Find out more information about <-0.2, -0.4, 0> here:
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it is better to sell used paper then to burn them
Answers
Answer:
Using sold paper is better than to burn it because burning paper may cause pollution.
Explanation:
Hope it will help ^_^
The path of an object projected at a 45 degree angle with initial velocity of 80 feet per second is given by the −32 2 function h(x) = (80)2 x + x where x is the horizontal distance traveled and h(x) is the height in feet. Use the TRACE feature of your calculator to determine the height of the object when it has traveled 100 feet away horizontally.
Answers
Answer:
50 feetExplanation:
Given the the path of an object at a 45° with initial velocity of 80 feet per second modeled by the equation [tex]h(x) = (-\dfrac{32}{80^2} )x^2 + x[/tex] where;
x is the horizontal distance traveled and h(x) is the height in feet, if x is given as 100 ft, the height of the object will be gotten by simply substituting x = 100 into the modeled function as shown;
[tex]h(x) = (-\dfrac{32}{80^2} )x^2 + x\\\\h(100) = (-\dfrac{32}{80^2} )100^2 + 100\\\\h(100) = (-0.005 )100^2 + 100\\\\h(100) = (-0.005 )10,000 + 100\\\\h(100) = -50 + 100\\\\h(100) =50 feet[/tex]
Hence height of the object when it has traveled 100 feet away horizontally is 50 feet.
The level of toluene (a flammable hydrocarbon) in a storage tank may fluctuate between 10 and 400 cm from the top of the tank. Since it is impossible to see inside the tank, an open-end manometer with water or mercury as the manometer fluid is to be used to determine the toluene level. One leg of the manometer is attached to the tank 500 cm from the top. A nitrogen blanket at atmospheric pressure is maintained over the tank contents. To atmosphere 500 e Toluene Manoseer luld (H,0 or Hg)
a) When the toluene level in the tank is 150 cm below the top (h=150cm),the manometer fluid level in the open arm is at the height of the point where the manometer connects to the tank. What manometer reading, R (cm), would be observed if the manometer fluid is (i) mercury, (ii) water? Which manometer fluid would you use, and why?
b) Briefly describe how the system would work if the manometer were simply filled with toluene. Give several advantages of using the fluid you chose in Part (a) over using toluene.
(c) What is the purpose of the nitrogen blanket?
Answers
Answer:
A. 23.9
B.22.9
C. The levels will be equal
D. Obviously that will be to maintain atmospheric pressure
Explanation:
For mercury the pressure in both tubes at R is same so
P_left = P_right
Thus
=>>>Po + rho_t x g x (5 + R - 1.5) = Po + rho_ m x g x R
rho_t x g x (5 + R - 1.5) = rho_m x g xR
rho_t x (3.5 + R) = rho_m x R
3.5 + R = (rho_m/rho_t) x R
3.5 + R = (13560/867) x R
3.5 + R = 15.64 x R
R x (15.64 - 1) = 3.5
R = 3.5/14.64
= 0.239 m
= 23.9 cm this is for Mercury
ii)water
similarly,
3.5 + R = (rho_w/rho_t) x R
3.5 + R = (1000/867) x R
3.5 + R = 1.153 x R
R X (1.153 - 1) = 3.5
R = 3.5/0.153
= 22.9m for water
Asteroid X orbits moon XYZ with a speed of 500m/s and a centripetal force of 1500N. Asteroid X, Y and Z all have the same mass. If asteroid Y orbits moon XYZ with the same orbital radius as asteroid X but at a speed of 100m/s. What is the centripetal force acting acting on asteroid Y? If asteroid Z orbits moon XYZ with a speed of 1500m/s but on orbital radius that is half of asteroid X, what is the centripetal force acting asteroid Z?
Answers
Answer this question
Explanation:
After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 53.0 cm. The explorer finds that the pendulum completes 105 full swing cycles in a time of 125 s.
What is the value of the acceleration of gravity on this planet?Express your answer in meters per second per second.
Answers
Answer:
The value is [tex]g = 16.104 \ m/s[/tex]
Explanation:
From the question we are told that
The length is [tex]l = 53.0 \ cm = 0.53 \ m[/tex]
The number of cycle is [tex]n = 105[/tex]
The time taken is [tex]t = 125 \ s[/tex]
The period is mathematically represented as
[tex]T = 2 \pi \sqrt{\frac{ l}{g} }[/tex]
Also the period is mathematically represented as
[tex]T = \frac{ t}{n}[/tex]
[tex]T = \frac{125}{110}[/tex]
[tex]T = 1.14 \ s/cycle[/tex]
So
[tex]1.14 = 2 * 3.142 \sqrt{\frac{ 0.53}{g} }[/tex]
=> [tex]g = \frac{ 4 * 3.142^2 * 0.53}{1.14^2}[/tex]
=> [tex]g = 16.104 \ m/s[/tex]
A stationary police car emits a sound of frequency 1205 Hz that bounces off of a car on the highway and returns with a frequency of 1255Hz. The police car is right next to the highway, so the moving car is traveling directly toward or away from it.
1. How fast was the moving car going?
2. Was the car moving away or towards the police?
3. What frequency would the police car have received if it had been traveling toward the other car at 25.0m/s?
Answers
Answer:
Let's take the frequency receive by police officer to be
f¹/f²= u-v/u+v
So 1255/1205= 340-v/340+v
V= 6.9m/s positive value implies that the car is moving toward the police
2 to find frequency we use
f/1205= 340+25/340-25
f= 1396Hz
In an 8.00km race, one runner runs at a steady 11.8 km/hr and another runs at 15.0 km/hr. How far from the finish line is the slower runner when the faster runner finishes the race?
Answers
Answer:
The slower runner is 1.71 km from the finish line when the fastest runner finishes the race.
Explanation:
Given;
the speed of the slower runner, u₁ = 11.8 km/hr
the speed of the fastest runner, u₂ = 15 km/hr
distance, d = 8 km
The time when the fastest runner finishes the race is given by;
[tex]Time = \frac{Distance }{speed}\\\\Time = \frac{8}{15} \\\\Time = 0.533 \ hr[/tex]
The distance covered by the slower runner at this time is given by;
d₁ = u₁ x 0.533 hr
d₁ = 11.8 km/hr x 0.533 hr
d₁ = 6.29 km
Additional distance (x) the slower runner need to finish is given by;
6.29 km + x = 8km
x = 8 k m - 6.29 km
x = 1.71 km
Therefore, the slower runner is 1.71 km from the finish line when the fastest runner finishes the race.