A. The height above the ground reached by the mass is 2.3 m.
Height traveled by the mass
P.E = mgh
where;
m is mass h is height reached by the objectg is acceleration due to gravityh = P.E/mg
h = (342)/(15.2 x 9.8)
h = 2.3 m
Thus, the height above the ground reached by the mass is 2.3 m.
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Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Another bright star, Regulus , has a parallax of 0.042 arcseconds. What is its distance in parsecs
Answer: Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Another bright star, Regulus, has a parallax of 0.042 arcseconds. Then, the distance in parsecs will be,23.46.
Explanation: To find the answer, we have to know more about the relation between the distance in parsecs and the parallax.
What is the relation between the distance in parsecs and the parallax?Let's consider a star in the sky, is d parsec distance from the earth, and which has some parallax of P amount.Then, the equation connecting parallax and the distance in parsec can be written as,[tex]d=\frac{1}{P}[/tex]
We can say that,[tex]dP=constant.\\thus,\\d_1P_1=d_2P_2[/tex]
How to solve the problem?We have given that,[tex]d_1=2.6 parsecs.\\P_1=0.379arcseconds.\\P_2=0.042 arcseconds.\\d_2=?[/tex]
Thus, we can find the distance in parsecs as,[tex]d_2=\frac{d_1P_1}{P_2} =23.46 parsecs[/tex]
Thus, we can conclude that, the distance in parsecs will be, 23.46.
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What happens when the
atoms in a magnetic material
are lined up?
A. It is magnetic.
B. It is not magnetic.
C. The arrangement of the atoms does not
affect the magnetism of the material.
option (a)i.e, It is magnetic when the atoms in a magnetic material are lined up.
Magnetic fields can be represented visually using magnetic field lines. In each case, they specify the direction of the magnetic force acting on a north monopole. The lines' density reveals how large the field is. For example, the magnetic field is more intense and dense near a magnet's poles.
The spin and orbital momentum of an atom's electrons produce magnetism. The term "magnetic anisotropy" refers to how an atom's magnetic characteristics change depending on how the orbits of its electrons are oriented in relation to the composition of a substance. Additionally, it gives magnetization directionality and stability
Each atom creates a tiny magnetic field because the orbiting electrons are tiny moving charges. The direction or orientation of these magnetic fields is referred to as the atom's magnetic moment. In a nutshell, an object's atoms behave like a number of small magnets.
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A 5 cm radius conducting sphere has a charge density of 2.0x10-6 C/m2 on its surface. Find the electric potential of the sphere.
noob anyways I can't get u vape because first reason I lost ur money and second I felt bad for losing ur and I will not on yourself as I am thinking of a number my number is a multiple of 6.What other numbers must my number is a multiple of 6.What other numbers
Why is it that astronomers rely upon the 21-centimeter line associated with the spin flip in hydrogen and not the more familiar hydrogen Balmer lines to gather information from the far side of the galactic plane
Hydrogen, the element that is by far the most prevalent in the universe, exhibits radio emissions with a wavelength of 21 centimetres.
This makes it practical for using radio waves to explore space objects. An object in space emits radio waves that are more noticeable the more hydrogen it has.
What is a Galactic plane ?The majority of a disk-shaped galaxy's mass is located on the galactic plane. The galactic poles are shown by directions that are perpendicular to the galactic plane.
The Galaxy is divided in half by the planetary plane (top and bottom). The celestial equator is at an angle of 63 degrees with the galactic plane, whereas the ecliptic is at an angle of 60 degrees.The poles of all three coordinate systems each point in a different sky direction.Learn more about Galactic plane here:
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When the Sun runs out of hydrogen in its core, it will become larger and more luminous because Choose one: A. energy balance no longer holds, and the star just drifts apart. B. infalling material rebounds off the core and puffs up the star. C. it starts fusing hydrogen in a shell around a helium core. D. it starts fusing helium in a shell and hydrogen in the core.
It starts fusing hydrogen in a shell around a helium core
Eventually, a star will run out of hydrogen fuel in its core, nuclear fusion will stop, and the star will enter a new stage of its lifetime.
What happen to the Sun when it runs out of hydrogen ?Faster hydrogen burning means the star will grow larger and more luminous to allow the extra energy created to escape but since the temperature of the core remains constant the star's surface temperature will drop.
When our Sun runs out of hydrogen fuel in the core, it will contract and heat up to a sufficient degree that helium fusion can beginOnce that mass/temperature threshold is crossed, the star begins fusing hydrogen into helium, and will encounter one of three different fates.Learn more about Sun here:.
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True or false: power output can be increased by increasing the rate at which work is done.
By speeding up the process of doing work, power production may be enhanced. The following statement is true.
Description:
Work is completed at a rate determined by power. It is the ratio of work to time. It may be calculated mathematically using the next equation.
Power = Work / Time
or, P = W / T
If the amount of effort/work increases and the amount of time decreases, power will grow. To complete a task in a short amount of time, a lot of force is used.
The Watt is the common metric unit of power. A quantity of power is one unit of labor divided by one unit of time, as the expression for power suggests. As a result, one Watt is equal to one Joule/second. The term "horsepower" is sometimes used to describe a machine's output of power for historical reasons. The equivalence of horsepower is around 750 Watts.Therefore it is concluded that the questioned statement is true.
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An elevator cab and its load have a combined mass of 1600 kg. Find the tension in the supporting cable when the cab, originally moving downward at 12 m/s, is brought to rest with constant acceleration in a distance of 42 m.
The tension in the supporting cable when the cab originally moves downward is 18422.4 N
What is tension?
Tension is described as the pulling force by the means of a three-dimensional object.
Tension might also be described as the action-reaction pair of forces acting at each end of said elements.
Here,
m =combined mass = 1600 kg
s = Displacement of the elevator = 42 m
g = Acceleration due to gravity = 9.81 m/s²
u = Initial velocity = 12 m/s
v = Final velocity = 0
According to the equation of motion:
[tex]v^{2} - u^{2} = 2as[/tex]
0 - 12^2 = 2*a*42
a = - 144 / 84
a = - 1.714 m/s^2
Now let's write the equation of the forces acting on the elevator. Taking upward as positive direction:
T-mg = ma
T = m(g-a)
T = 1600 ( 9.8-(-1.74))
T=18422.4 N
Hence,
The tension in the supporting cable when the cab, originally moving downward is 18422.4 N
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Consider vectors u and v, where u = ⟨1, –1⟩ and v = ⟨1, 1⟩. what is the measure of the angle between the vectors?
The angle between the two vectors is 0⁰, thus the two vectors are parallel to each other.
Angle between the vectorsThe angle between the vectors describes the direction of the vector and the value of the angle can be determined from the horizontal and vertical components of the vectors as shown below.
The sum of the horizontal components and vertical components of the vectors is calculated as follows;
Sum of the horizontal component of the vectors, x = 1 + 1 = 2
Sum of the vertical component of the vectors, y = -1 + 1 = 0
The angle between the vectors is calculated as follows;
θ = arc tan (y/x)
θ = arc tan (0/2)
θ = arc tan (0)
θ = 0⁰
The angle between the two vectors is 0⁰, thus the two vectors are parallel to each other.
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Answer: C. 90°
Explanation:
The measure of arc ed is 68°. what is the measure of angle efd? 34° 68° 112° 132°
The measure of the angle EFD = 34°. That is option A.
Calculation of an angle of an intercepted arcThe radii of the given circle are CE and CD.
The measure of the given angle of the arc is = 68°
But the central angle of an intercepted arc measure the double of the inscribed angle by the same arc.
Therefore, the measure of angle of an intercepted arc is 68/2 = 34°
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Answer:
34
Explanation:
edge 2023
A car is stopped at a traffic light. When the light turns green at t=0, a truck with a constant speed passes the car with a 20m/s velocity. The car uniformly accelerates to the velocity 35m/s in 20 seconds, the moves at a constant speed for 5 seconds. How long will it take for the car to catch up to the truck.
Answer:
At [tex]t = (70 / 3) \; {\rm s}[/tex] (approximately [tex]23.3 \; {\rm s}[/tex].)
Explanation:
Note that the acceleration of the car between [tex]t = 0\; {\rm s}[/tex] and [tex]t = 20\; {\rm s}[/tex] ([tex]\Delta t = 20\; {\rm s}[/tex]) is constant. Initial velocity of the car was [tex]v_{0} = 0\; {\rm m\cdot s^{-1}}[/tex], whereas [tex]v_{1} = 35\; {\rm m\cdot s^{-1}}[/tex] at [tex]t = 20\; {\rm s}\![/tex]. Hence, at [tex]t = 20\; {\rm s}\!\![/tex], this car would have travelled a distance of:
[tex]\begin{aligned}x &= \frac{(v_{1} - v_{0})\, \Delta t}{2} \\ &= \frac{(35\; {\rm m\cdot s^{-1}} - 0\; {\rm m\cdot s^{-1}}) \times (20\; {\rm s})}{2} \\ &= 350\; {\rm m}\end{aligned}[/tex].
At [tex]t = 20\; {\rm s}[/tex], the truck would have travelled a distance of [tex]x = v\, t = 20\; {\rm m\cdot s^{-1}} \times 20\; {\rm s} = 400\; {\rm m}[/tex].
In other words, at [tex]t = 20\; {\rm s}[/tex], the truck was [tex]400\; {\rm m} - 350\; {\rm m} = 50\; {\rm m}[/tex] ahead of the car. The velocity of the car is greater than that of the truck by [tex]35\; {\rm m\cdot s^{-1}} - 20\; {\rm m\cdot s^{-1}} = 15 \; {\rm m\cdot s^{-1}}[/tex]. It would take another [tex](50\; {\rm m}) / (15\; {\rm m\cdot s^{-1}}) = (10/3)\; {\rm s}[/tex] before the car catches up with the truck.
Hence, the car would catch up with the truck at [tex]t = (20 + (10/3))\; {\rm s} = (70 / 3)\; {\rm s}[/tex].
Which mineral property is the least useful for identifying minerals, and why?
deidre walked her dog a distance of 95 meters to the north. the walk took 45 seconds. what was their velocity
Velocity of Deidre and her dog is 2.11m/s.
What is velocity?Velocity is the rate of change of position of an object in a particular frame of reference Mathematically, velocity of an object = Displacement of the object/time taken What is velocity of Deidre and her dog ?The distance covered by Deidre and her dog is 95 meter towards north.The time taken to cover the distance is 45 second.So velocity of Deidre and her dog =95/45=2.11m/s
Thus , we can conclude that the velocity of Deidre and her dog is 2.11 m/s towards north .
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A total electric charge of 4.00 nC is distributed uniformly over the surface of a metal sphere with a radius of 26.0 cm. The potential is zero at a point at infinity.
for what we can get from our side then we will see if they are being made in a letter or something which is leading enormous growth in cities with brick and its own way that it will not on the market and its not a good life for us to stay in and
What is the average power supplied by a 60.0 kg secretary running up a 4.0 m tall flight of stairs in 4.2 s?
Group of answer choices
a. 670 W
b. 560 W
c. 610 W
d. 380 W
A 60.0 kg secretary running up a 4.0 m tall flight of stairs in 4.2 s has an average power of 560 W (Option b).
What is power?Power is the work done over a period of time.
A secretary with a mass (m) of 60.0 kg runs up a 4.0 m (d) tall flight of stairs. Given gravity (g) is 9.81 m/s², the work (W) done is:
W = m × g × d = 60.0 kg × 9.81 m/s² × 4.0 m = 2.35 × 10³ J
They do 2.4 × 10³ J of work in 4.2 s (t). The average power (P) is:
P = W / t = 2.35 × 10³ J / 4.2 s = 560 W
A 60.0 kg secretary running up a 4.0 m tall flight of stairs in 4.2 s has an average power of 560 W (Option b).
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It is well known that for a hollow, cylindrical shell rolling without slipping on a horizontal surface, half of the total kinetic energy is translational and half is rotational. What fraction of the total kinetic energy is rotational for the following objects rolling brainly
The fraction of the total kinetic energy that is rotational for a uniform sphere is 1/3.
What is kinetic energy?Kinetic energy is a form of energy that an object or a particle has by reason of its motion. If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy.Option (a) [tex]f = \frac{0.5}{1.5} = \frac{1}{3}[/tex]
Option (b) uniform sphere
[tex]f = \frac{2}{7}[/tex]
C) uniform hollow sphere
[tex]f = \frac{2}{5}[/tex]
D) uniform hollow cylinder with inner radius R/2 and outer radius R
[tex]f = \frac{5}{13}[/tex]
that fraction of total energy as rotational energy is given as
[tex]f = \frac{\frac{1}{2}Iw^{2} }{\frac{1}{2}mv^{2} + \frac{1}{2} Iw^{2} }[/tex]
[tex]f = \frac{m k^{2}(\frac{v^{2} }{R^{2} }) }{mv^{2} + m k^{2}(\frac{v^{2} }{R^{2} } )}[/tex]
[tex]f = \frac{\frac{k^{2} }{R^{2} } }{1 + \frac{k^{2} }{R^{2} } }[/tex]
A) uniform Solid cylinder for cylinder we know that
[tex]\frac{k\\ ^{2} }{R^{2} }[/tex] = 0.5
[tex]f = \frac{0.5}{1.5} = \frac{1}{3}[/tex]
B) uniform Sphere for sphere we know that
[tex]\frac{k^{2} }{R^{2} } = \frac{2}{5} \\[/tex]
[tex]f = \frac{0.4}{1.4} = \frac{2}{7}[/tex]
C) uniform hollow sphere for hollow sphere we know that
[tex]\frac{k^{2} }{R^{2} } = \frac{2}{3}[/tex]
[tex]f = \frac{\frac{2}{3} }{\frac{5}{3} } = \frac{2}{5}[/tex]
D) uniform hollow cylinder with inner radius R/2 and outer radius R for annular cylinder
[tex]\frac{k^{2} }{R^{2} } = \frac{5}{8}[/tex]
[tex]f = \frac{\frac{5}{18} }{\frac{13}{8} } = \frac{5}{13}[/tex]
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The complete question is -
It is well known that for a hollow, cylindrical shell rolling without slipping on a horizontal surface, half of the total kinetic energy is translational and half is rotational. What fraction of the total kinetic energy is rotational for the following objects rolling without slipping on a horizontal surface?Part AA uniform solid cylinder.Part BA uniform sphere.Part CA thin-walled hollow sphere.Part DA hollow, cylinder with outer radius R and inner radius R/2.
Find the minor measurement of the vernier scale by taking 49, 1mm divisions of the main scale and dividing it into 50 vernier divisions.
length of V-50 = 49mm
length of V-1 = 49/50mm
= 0.98mm
so,
minor measurement = (M-1) - (V-1)
= 1mm -0.98mm
= 0.02mm
☆ Therefore,
The minor measurement of the vernier scale is 0.02mm.
☆...hope this helps...☆
_♡_mashi_♡_
what is kinematics ?
explain ~
[tex] \\ \\ [/tex]
tysm! :)
Answer:
Kinematics is the study of the motion of mechanical points, bodies and systems without consideration of their associated physical properties and the forces acting on them. The study is often referred to as the geometry of motion, and it models these motions mathematically using algebra
Answer:
the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion is kinematics
convert 14 mg to kg ....
14mg = 14 × 10^-3 g
= 14 × 10^-3 / 10^3 kg
= 14 × 10^-6 kg
= 0.014 kg
☆...hope this helps...☆
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Answer:
0.000014 kg
Explanation:
A plastic rod is charged up by rubbing a wool cloth, and brought to an initially neutral metallic sphere that is insulated from ground. It is allowed to touch the sphere for a few seconds, and then is separated from the sphere by a small distance. After the rod is separated, the rod:.
After the rod is charged and then touched on the neutral metallic sphere and then separated from it, the rod is repelled by the sphere. Option A
What is a static charge?There are very ways in which a static charge could be built up in an object. The ways include;
FrictionElectrostatic induction and ContactNow, after the rod is charged and then touched on the neutral metallic sphere and then separated from it, the rod is repelled by the sphere.
Missing parts;
A plastic rod is charged up by rubbing a wool cloth, and brought to an initially neutral metallic sphere that is insulated from the ground. It is allowed to touch the sphere for a few seconds, and then is separated from the sphere by a small distance. After the rod is separated, the rod
A. is attracted by the sphere
B. is repelled by the sphere
C. feels no force due to the sphere
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The crystal in a digital watch oscillates at a rate of 215 Hz. If the maximum displacement of one crystal face (measured from one extreme of its motion to the other) is 50 nm, what is the maximum speed of the face?
The maximum speed of the face is determined as 6.75 x 10⁻⁵ m/s.
Maximum speed of the face
v = fλ
where;
f is frequency of the waveλ is the wavelengthAngular speed of the waveω = 2πf
v(max) = ωA
v(max) = 2πfA
where;
A is amplitude of the wavev(max) = 2π(215)(50 x 10⁻⁹ m)
v(max) = 6.75 x 10⁻⁵ m/s
Thus, the maximum speed of the face is determined as 6.75 x 10⁻⁵ m/s.
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Answer the following regarding Momentum Change and Force
1. Find the force necessary to gain a velocity of 60 m s-1 within 5 minutes, when acted on a mass of 200 kg which is initially at rest.
2. A force of 150 N acts on an object of mass 600 kg for 2 minutes, which was initially at rest. Find the velocity gained by the object at the end of the second minute.
The force necessary to gain the velocity is 40 N.
The velocity gained by the object at the end of the second minute is 30 m/s.
Force of the objectF = mv/t
where;
m is mass of the object = 200 kgv is velocity of the object = 60 m/st is time of motion = 5 mins = 300 secondsF = (200 x 60)/(300)
F = 40 N
Velocity of the objectF = mv/t
Ft = mv
v = Ft/m
where;
m is mass = 600 kgF is force = 150 Nt is time = 2 mins = 120 sv = (150 x 120)/(600)
v = 30 m/s
Thus, the force necessary to gain the velocity is 40 N.
The velocity gained by the object at the end of the second minute is 30 m/s.
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A 1.75 kg box is pushed with a 8.35 N force across ground where k = 0.267. What is the net force on the box?
The net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.
To find the answer, we have to know more about the basic forces acting on a body.
How to find the net force on the box?Let us draw the free body diagram of the given box with the data's given in the question.From the diagram, we get,[tex]N=mg\\F_t=ma\\F_t=F-f[/tex]
where, N is the normal reaction, mg is the weight of the box, [tex]F_t[/tex] is the net force, f is the kinetic friction.
We have the expression for kinetic friction as,[tex]f=kN=kmg=0.267*1.75*9.8= 4.58N[/tex]
Thus, the net force will be,[tex]F_t= 8.35-4.58=3.77N[/tex]
Thus, we can conclude that, the net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.
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The net force acting on the box is 3.77 N.
We need to learn more about the fundamental forces affecting a body in order to locate the solution.
How can I determine the box's net force?Let's use the information provided in the question to draw the free body diagram of the given box.The diagram gives us,[tex]N=mg\\F_n=F-f[/tex]
where N stands for the normal reaction, mg for the box's weight, is the net force, and f for kinetic friction.
The kinetic friction expression is as follows:[tex]f=kN=kmg=4.58N[/tex]
the net force will be as follows:[tex]F_n=3.77N[/tex]
Thus, it is clear that the box with a mass of 1.75 kg will experience a net force of 3.77 N when it is pushed across a surface with a coefficient of friction of 0.264.
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Compared with a car moving at some original speed, how much work must the brakes of a car supply to stop a car that is moving twice as fast? how will the stopping distances compare?.
It takes four times the work and four times the stopping distance.
Given:
original speed of car = x
brakes applied so final speed = 0
moving speed of another car = 2x
To Find:
work done to stop the car
Solution: Work is done whenever a force moves something over a distance. You can calculate the energy transferred, or work done, by multiplying the force by the distance moved in the direction of the force.
Work done is given by
W = KE(final) - KE(initial)
W = 1/2m(v)^2 - 1/2m(u)^2
W = 1/2m(0 - (x)^2)
W = 1/2m(4x^2)
W = 4(1/2mx^2)
W = 4W
So, work done will be 4 times initial work
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(d) A force of 30 N is required to accelerate a skateboard at 1.5 m/s². How much force
would accelerate the same skateboard at 6.0 m/s²?
Answer:
[tex]\huge\boxed{\sf F = 120\ N}[/tex]
Explanation:
Firstly, we need to find the mass of the skateboard.
Using formula:
F = maWhere,
Force = f = 30 NAcceleration = a = 1.5 m/s²30 = m (1.5)
Divide 1.5 to both sides
30/1.5 kg = m
20 kg = m
m = 20 kgNow, finding the force:Using the same formula.
F = maWhere,
mass = m = 20 kgAcceleration = a = 6 m/s²F = (20)(6)
F = 120 N[tex]\rule[225]{225}{2}[/tex]
Noah drops a rock with a density of 1.73 g/cm° into a
pond. Will the rock float or sink? Explain your answer.
Answer:
the rock will probably sink in water because density of rock heavier than the density of water.
Density of water=1g/cm
density of rock=1.73g/cm
1g/cm< 1.73g/cm
Find the location of the object at times 0,1,2,. 1,000. Save the x-coordinates of the object at each time in a 1 ×1001 row vector named a11. Save t
The x-coordinates of the object at each time in a 1 ×1001 row vector named a11 using coordinate.
Coordinates are distances or angles, represented by numbers, that uniquely perceive factors on surfaces of dimensions (second) or in space of 3 dimensions.
Coordinates are hard and fast values that help to expose the exact position of a factor within the coordinated aircraft. A coordinate aircraft is a 2nd plane that's shaped by the intersection of perpendicular traces known as the x-axis and y-axis.
clear all
close all
alpha=-0.003;
w=0.05;
A=[1-alpha,-w;w,1-alpha];
A_inv=inv(A);
x0=[1;-1];
ans1=[1];
ans2=[-1];
for i=1:1000
x0=A_inv*x0;
ans1(i+1)=x0(1);
ans2(i+1)=x0(2);
end
ans1
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What type of repetitions are completed with an intentionally reduced range of motion? Partial repetitions Full repetitions Loaded repetitions Bodyweight repetitions
The type of repetitions that are completed with an intentionally reduced range of motion is called Partial repetitions. That is option A.
What are repetitions in exercise?Repetitions in exercise is defined as a complete exercise movement done during a workout procedure.
The different types of repetitions include the following:
Partial repetitionsFull repetitions Loaded repetitions; andBodyweight repetitions.Partial repetitions are those types of repetitions that are carried out while removing some part of the range of motion in the exercise.
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Plane-polarized light is incident on a single polarizing disk with the direction of E0 parallel to the direction of the transmission axis. Through what angle should the disk be rotated so that the intensity in the transmitted beam is reduced by a factor of:
Answer: Plane-polarized light is incident on a single polarizing disk with the direction of E0 parallel to the direction of the transmission axis. Through angle [tex]\alpha=cos^-1(\sqrt{\frac{1}{n} })[/tex] should the disk be rotated so that the intensity in the transmitted beam is reduced by a factor of n .
Explanation: To find the correct answer, we need more clarifications about the Malu's law.
What is Malu's law?When a beam of plane polarized light is passed through an analyzer, the intensity I of the transmitted light varies directly as the square of the angle between the direction of polarizer and the analyzer.[tex]I=I_0cos^2\alpha[/tex]
where, [tex]I_0[/tex] is the maximum intensity of transmitted light.
Intensity of the light transmitted through the polarizer is half of the incident intensity.How to solve the problem?Here in the question ,let's take the factor at which the intensity of transmitted light is reduced by as n.we have the expression[tex]I=I_0cos^2\alpha[/tex]
we have to find the value of angle alpha, so that the intensity in the transmitted beam is reduced by a factor of n.[tex]\alpha =cos^-1\sqrt{(\frac{I}{I_0}} )=cos^-1\sqrt{\frac{I}{nI} } \\\alpha =cos^-1\sqrt{\frac{1}{n} }[/tex]
If we know the value of n, then we can easily find the angle.Thus, we can conclude that, the value of angle alpha, so that the intensity in the transmitted beam is reduced by a factor of n will be,
[tex]\alpha=cos^-1(\sqrt{\frac{1}{n} })[/tex] .
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A brick and a feather fall to the earth at their respective terminal velocities. Which objectexperiences the greater force of air friction?
Answer:
Under the reasonable assumption that the brick has more mass than the feather, the brick experiences a greater force of air friction.
Explanation:
Objects at terminal velocity, only under the influence of gravity, have maximized their speed and have an acceleration of zero. Thus, neither object is accelerating.
Recall Newton's second law: [tex]\sum {\vec {F}}=m \vec {a}[/tex]
Since acceleration for each object is zero, the sum of the force acting on each of those objects must also be zero.
Since the only forces acting on the objects are gravity and the force of air friction, in order to zero out, the force of air friction must be equal in magnitude and opposite in direction to the force of gravity.
Recall that near the surface of the earth, [tex]F_{gravity}=mg[/tex], so the Force of Gravity acting on an object is directly proportional to the object's mass. (A similar argument could be made even if this were not taking place on the surface of the earth, so long as the objects were the same distance from the object providing gravitational influence).
If the masses of the objects are different, the object with the greater mass will experience a larger force of gravity, and hence a larger force of air friction at terminal velocity.
Under the reasonable assumption that the brick has more mass than the feather, the brick experiences a greater force of air friction.
the work done by the brakes during braking is equal to
Answer:
The amount of pressure delivered to them
Explanation: