Answer:
i. Has a liver problems?
= 0.08
ii. Is a heavy drinker ?
= 0.066
iii. If a person is found to be a heavy drinker, what is the probability that this person has liver problem?
= 0.303
iv. If a person is found to have liver problems, what is the probability that this person is a heavy drinker?
= 0.25
v. If a person is found to be a non –drinker, what is the probability that this person has liver problems?
= 0.104
Step-by-step explanation:
We have 2 Events in this question
Event A: People with liver problems
Event B : People without liver problems
Event A: People with liver problems
Let us represent people with liver problems as = (L)
a)8% have liver problems. = P(L)
Under liver problems we have:
b) 25% are heavy drinkers = P( L & H)
c) 35% are social drinkers = P( L & S)
d) 40% are non-drinkers. = P( L & N)
Event B( no liver problem)
Let us represent no liver problem as NL
We are not given in the question but Probability of having no liver problem = 100 - Probability of having liver problem
= 100 - 8% = 92 %
P(NL ) = 92%
From the question, For people without liver problems, we have:
a) 5% are heavy drinkers = P(NL & H)
b) 65% are social drinkers = P( NL & S)
c) 30% do not drink at all = P( NL & N)
An adult is chosen at random, what is the probability that this person
i. Has a liver problems?
P(L) = 8% or 0.08
ii. Is a heavy drinker ?
From the question, we have:
Probability of people that have liver problems and are heavy drinkers P(L & H) = 25% = 0.25
Probability of people that have do not have liver problems and are heavy drinkers P(NL & H) = 5% = 0.05
Probability ( Heavy drinker) =
P(L) × P(L & H) + P(NL) × P(NL & H)
= 0.25 × 0.08 + 0.05 × 0.92
= 0.066
iii. If a person is found to be a heavy drinker, what is the probability that this person has liver problem?
Probability (Heavy drinker and has liver problem) = [P(L) × P(L & H)] ÷ [P(L) × P(L & H)] + [P(NL) × P(NL & H) ]
= [0.25 × 0.08] ÷ [0.25 × 0.08] + [0.05 × 0.92]
= 0.303030303
Approximately = 0.303
iv. If a person is found to have liver problems, what is the probability that this person is a heavy drinker?
P(L & H) = 25% = 0.25
v. If a person is found to be a non –drinker, what is the probability that this person has liver problems.?
People with liver problems are non-drinkers. = P( L & N) = 40% = 0.4
People without liver problems and do not drink at all = P( NL & N) = 30% = 0.3
Probability (non drinker and has liver problem) = [P( L & N) × P(L & H)] ÷ [P( L & N) × P(L & H)] + [ P( NL & N) × P(NL & H) ]
= [0.4× 0.08] ÷ [0.4 × 0.08] + [0.3 × 0.92]
= 0.1038961039
Approximately ≈ 0.104
WILL GIVE BRAINLIEST
Complete the equation describing how
x and y are related.
х
-3
-2
-1
0
1
2
3
y
12
8
4
0
-4
-8
-12
y = [? ]x
Answer:
[tex]y=4x[/tex]
Answer:
y = -4x
hope that helped.........
Helppppp plzzzzzzz!!!!!!!!!!! 15+ PTS and brainliest!!!!!!!!
Write the equation of the line with slope of 0, and y-intercept of 9.
Answer:
y=0x+9. Hope this helped.
Step-by-step explanation:
slope intercept form: y=mx+b
m represents slope
b represents the y intercept. Please give me the brainliest:)
(3+4i)^2
(2+4i)(7-8i)
Answer:
10 (-61 + 102 i)
(3 + 4 i)^2 (2 + 4 i) (7 - 8 i)
Step-by-step explanation:
(3 + 4 i)^2 (2 + 4 i) (7 - 8 i)
10 (-61 + 102 i)
r = 50 sqrt(565) (radio), θ = π - tan^(-1)(102/61) (ángulo)
50 sqrt(565) (cos(π - tan^(-1)(102/61))+i sin(π - tan^(-1)(102/61)))
50 sqrt(565) e^(i (π - tan^(-1)(102/61)))
x^2 + 1220 x + 1412500
Principal=2000,R=12percent,Time=2years and 6 months.
[tex]\boxed{\sf I=\dfrac{PRT}{100}}[/tex]
[tex]\\ \sf\longmapsto I=\dfrac{2000(12)(2.5)}{100}[/tex]
[tex]\\ \sf\longmapsto I=\dfrac{24000(2.5)}{100}[/tex]
[tex]\\ \sf\longmapsto I=\dfrac{60000}{100}[/tex]
[tex]\\ \sf\longmapsto I=600[/tex]
[tex] \large\begin{gathered} {\underline{\boxed{ \rm {\red{S.I \: = \: \frac{P × R × T}{100} }}}}}\end{gathered} [/tex]
Basic TermsSimple Interest - Simple interest is the method of calculating interest charged on the amount invested in a fixed deposit.Principle - The principal is the amount due on any debt before interest, or the amount invested before returns.Rate - An interest rate is the percentage of principal charged by the lender for the use of its money.Time = Time is duration (in months or years) in Simple Interest.SolutionAs we know that , first we need to convert 2 years 6 months into years.
[tex] \sf \ \implies \: 1 \: \: year \: = \: 12 \: \: months[/tex]
[tex] \sf \implies \: 2 \: \: years \: \: and \: \: 6 \: \: months \: = \: 30 \: \:months[/tex]
[tex] \sf \implies \: \:\frac{ \cancel{30} \: \: ^{2.5 \: \: years} }{ \cancel{12 \: }} \\ [/tex]
[tex]\bf{\blue{ Time \: = \: 2.5 \: \: years}}[/tex]
Now , we have to find the Simple interest.[tex]\Large\rm{\orange{ \begin{cases} \large\begin{gathered} {\underline{\boxed{ \rm {\purple{S.I \: = \: \frac{P × R × T}{100} }}}}}\end{gathered} \end{cases}}}[/tex]
Substuting the values[tex] \tt \large \longrightarrow \: \: S.I \: = \: \frac{2000 \: × \: 12 × \: 2.5}{100} \\ [/tex]
[tex] \tt \large \longrightarrow \: \: S.I \: = \frac{60000}{100} \\ [/tex]
[tex]\tt \large \longrightarrow \: \: S.I \: = \frac{600 \cancel0 \cancel0}{1 \cancel0 \cancel0} \\ [/tex]
[tex]\tt \large \longrightarrow \: \: S.I \: = \: 600[/tex]
[tex]\large \underbrace{\textrm {{{\color{navy}{Simple Interest \: = \: 600}}}}}[/tex]
Help!!! QUICK! What is the pattern of the exponents on the a terms in Pascal's Triangle?
A. The largest exponent value of the a terms is equal to one more than the value of the exponent on the binomial. The exponent values then decrease from left to right.
B. The largest exponent value of the a terms is equal to the value of the exponent on the binomial. The exponent values then decrease from left to right.
C. The largest exponent value of the a terms is equal to the value of the exponent on the binomial. The exponent values are then equal to 0 throughout the expansion.
D.The largest exponent value of the a terms is equal to one more than the value of the exponent on the binomial. The exponent values are then equal to 1 throughout the expansion.
Answer:
B. The largest exponent value of the a terms is equal to the value of the exponent on the binomial. The exponent values then decrease from left to right.
Step-by-step explanation:
The exponent values of the a terms increase from one side of the binomial to the other. The value of the largest exponent is equal to part of the binomial expression.
5. Two unbiased dice are rolled. Calculate the probability that the sum of the two dice is:
ws
(a) 4
(b) 7
(c) Less than 7
Consider the following. x = t − 2 sin(t), y = 1 − 2 cos(t), 0 ≤ t ≤ 2π Set up an integral that represents the length of the curve. 2π 0 dt Use your calculator to find the length correct to four decimal places.
Answer:
L = 13.3649
Step-by-step explanation:
We are given;
x = t − 2 sin(t)
dx/dt = 1 - 2 cos(t)
Also, y = 1 − 2 cos(t)
dy/dt = 2 sin(t)
0 ≤ t ≤ 2π
The arc length formula is;
L = (α,β)∫√[(dx/dt)² + (dy/dt)²]dt
Where α and β are the boundary points. Thus, applying this to our question, we have;
L = (0,2π)∫√((1 - 2 cos(t))² + (2 sin(t))²)dt
L = (0,2π)∫√(1 - 4cos(t) + 4cos²(t) + 4sin²(t))dt
L = (0,2π)∫√(1 - 4cos(t) + 4(cos²(t) + sin²(t)))dt
From trigonometry, we know that;
cos²t + sin²t = 1.
Thus;
L = (0,2π)∫√(1 - 4cos(t) + 4)dt
L = (0,2π)∫√(5 - 4cos(t))dt
Using online integral calculator, we have;
L = 13.3649
Which expression is equivalent to the following complex fraction?
Answer:
The correct choice is option B. y+1/y-1
Step-by-step explanation:
|5x|=3 please help me
Simplify the following expression:
7y + 2x − 10y + 3x2 − 10x
What is the surface area of a cone with a slant height of 12.5m and a diameter of 9m? Round to the nearest whole number.
9514 1404 393
Answer:
240 m²
Step-by-step explanation:
The lateral surface area is given by the formula ...
LA = πrs . . . . . cone with radius r and slant height s
The base area is given by the formula ...
BA = πr²
The total surface area is the sum of these:
SA = BA +LA = πr² +πrs = πr(r+s)
The radius is half the diameter, so is 9m/2 = 4.5 m. Then the surface area is ...
SA = π(4.5 m)(4.5 m +12.5 m) = 76.5π m² ≈ 240 m²
Answer:
1: A. 448 2: 209 pi cm^2 3: D. 351 m^2 4. B 240 cm^2 5. C. 561.1 cm^2
Step-by-step explanation:
just took the test!!!
4) If the perimeter of a square is 48cm",
What is the length of each side?
Simplify your answer.
Answer:
If the total perimeter of square is 48 cm, then the length of one side is equal to 48 divided by 4, since all sides of a square are the same.
So, the correct answer is 12.
Let me know if this helps!
The length of each side is 12cm.
Explanation:
The perimeter of a square is calculated by the formula:
P = 4a , where P = perimeter, and a = length of any side, all sides being equal in a square.
From the given data we write:
48 = 4a
Divide both sides by
4.12 = a
The length of each side is 12cm.
Simplify 6.92 to the exponent of 1000
Answer:
Whatever is raised to the power of 0 is 1
SO the answer is 1
Find the sum. 1. -7+(-5)
O-12
O-2
0 2
0 12
Answer:
-12
Step-by-step explanation:
-7+(-5)=
-7-5=
-12
To the nearest square inch, what is the surface area of the square pyramid shown in the image? A. 175 in.^2 B. 200 in.^2 C. 400 in.^2 D. 700 in.^2 Please show ALL work! :D
Answer: C. 400 in^2
Step-by-step explanation:
First find the surface area or the area of the base which is in the shape of a square and has a side length of 10 in. So square 10 to find the area.
Area of base: 10 * 10 = 100
Next find the area of one of the triangles.
As we could see the triangle has a slant height of 15 in and a base of 10. To find the area of a triangle we multiply the base times the height and multiply it by half.
Area of one triangle. 15 * 10 = 150 * 1/2 = 75
Since one side of the triangle has a surface area of 75 inches we will multiply it by 4 since there are four triangles to find the total surface area of the four faces.
75 * 4 = 300
We now know that the the 4 triangles surface area dd up to 300 so we will add it to the area of the base which is 100 to find the whole surface area of the figure.
300 + 100 = 400
Someone help me!!! Help
Answer B.ED
Step-by-step explanation:
Match the base to the corresponding height.
Base (b)
Height (h)
b
h
h
b
The base 1 is matched with height 2, base 2 is matched with height 3 and base 3 is matched with height 1. The base to the corresponding height is matched in the attached figure.
What is a triangle?Triangle is the closed shaped polygon which has 3 sides and 3 interior angles. The height of the triangle is the dimension of the elevation from the opposite peak to the length of the base.
Thus, the base 1 is matched with height 2, base 2 is matched with height 3 and base 3 is matched with height 1. The base to the corresponding height is matched in the attached figure.
In the given figure, three triangles is shown with base and height. Here,
The base 1 is matched with height 2, as the height shown in figure 2 is the dimension of the elevation from the opposite peak to the length of the base 1.Similarly, base 2 is matched with height 3.Base 3 is matched with height 1.
Thus, the base 1 is matched with height 2, base 2 is matched with height 3 and base 3 is matched with height 1. The base to the corresponding height is matched in the attached figure.
Learn more about the base and height of the triangle here;
https://brainly.com/question/26043588
#SPJ2
In the given figure, if POQ is a straight line then find ∠POT. please help !!!!!!
Answer:
∠POT = 78°
Step-by-step explanation:
If POQ is straight then
x + 18° + 50° + x + 24° = 180° add like terms
2x + 92° = 180°
2x = 180° - 92°
2x = 88° and x = 44 If we say SOT is a straight line then
∠POT + 50° + x + 18° = 180°
∠POT + 102° = 180°
∠POT = 78°
(Algebra)
Plz help me ASAP!! I’ll be so grateful!
Answer:
y > 1
Step-by-step explanation:
-2(7 + y) > -8(y + 1)
-14 -2y > -8y -8
-2y +8y > -8 +14
6y > 6
6y/6 > 6/6
y > 1
A rectangular tank that is 2048 ft cubed with a square base and open top is to be constructed of sheet steel of a given thickness. Find the dimensions of the tank with minimum weight.
Answer:
16ft by 16ft by 8ft.
Step-by-step explanation:
Let the total surface area of the rectangular tank be S = 2LW+2LH+2WH where;
L is the length of the box
W is the width of the box
H is the height of the box.
Since the box is openend at the top, S = lw + 2lh+ 2wh
If the base is a square base then, l = w
S = l(l) + 2wh+2wh
S = l²+4wh ............... 1
If volume = lwh
lwh = 2028 ft³
wh = 2048/l ................ 2
Substitute equation 2 into 1;
S = l²+4(2048/l)
S = l²+8192/l
dS/dl = 2l - 8192/l²
If dS/dl = 0 (since we are looking for dimensions of the tank with minimum weight.)
2l - 8192/l² = 0
2l = 8192/l²
2l³ = 8192
l³ = 8192/2
l³ = 4096
l =∛4096
l = 16 ft
Since the length is equal to the width, hence the width = 16ft (square based tank)
Given the volume V = lwh = 2048
lwh = 2048
16*16*h = 2048
256h = 2048
divide both sides by 256
256h/256 = 2048/256
h = 8ft
Hence, the dimensions of the tank with minimum weight is 16ft by 16ft by 8ft.
in a class of 40 students, 30 students read chemistry, 40 students read physics, if all students read at least one of the subject, find the probability a students is selected at random will read only chemistry
Answer: 0%
Step-by-step explanation:
There's 40 students, and 40 students read physics. That means that every student reads physics. So, no student could read only chemistry.
what principle will amount to Rs. 4000 in 20 yrs at 2.5%?
Answer:
3200Step-by-step explanation:
Consider principle =Rs.P, Time (T)=4 years
Consider principle =Rs.P, Time (T)=4 yearsRate =6
Consider principle =Rs.P, Time (T)=4 yearsRate =6 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 =
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest =
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R =
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P×
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 =
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P =
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P =
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 4
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =4000
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000P=Rs.3200
Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000P=Rs.3200Therefore, Principle =Rs.3200
If g(x) = x^2 + 8x - 24 find the value of g(6)
Answer:
hope it helps you..........
Answer:
60
Step-by-step explanation:
g(x)= x^2 +8x - 24
Substitute x for 6 in the equation
g(6)= 6^2 + 8(6) - 24
= 36+48-24
= 60
Classify the expression: 5x + 3x^2 − 7x^3 + 2
A. Linear Expression
B. Quadratic Expression C. Cubic Expression
D. Quartic Expression
Answer:
C. Cubic expression.
Step-by-step explanation:
The highest exponent is 3 ( in the term 7x^3) so it is cubic.
Answer:
C. Cubic Expression.
Step-by-step explanation:
5x + 3x^2 - 7x^3 + 2
= 3x^2 - 7x^3 + 5x + 2
= -7x^3 + 3x^2 + 5x + 2
The highest value of exponent in the equation is 3.
For a linear expression, the highest exponent is 1.
For a quadratic expression, the highest exponent is 2.
For a cubic expression, the highest exponent is 3.
For a quartic expression, the highest exponent is 4.
So, this is C. Cubic Expression.
Hope this helps!
HELP ASAP PLS :Find all the missing elements:
Answer:
a ≈ 1.59
b ≈ 6.69
Step-by-step explanation:
Law of Sines: [tex]\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}[/tex]
Step 1: Find c using Law of Sines
[tex]\frac{6}{sin58} =\frac{c}{sin13}[/tex]
[tex]c = sin13(\frac{6}{sin58})[/tex]
c = 1.59154
Step 2: Find a using Law of Sines
[tex]\frac{6}{sin58} =\frac{a}{sin109}[/tex]
[tex]a = sin109(\frac{6}{sin58} )[/tex]
a = 6.68961
Suppose you have a bag with the following in it: 5 one dollar bills, 4 fives, 3 tens, 5 twenties, and 3 fifties. Assuming the experiment requires drawing one bill from the bag at random, complete the probability distribution for this experiment.
Required:
What is the probability of drawing 9 dollars or less in a single draw?
Answer:
(a) Probility Distribution
Outcome probability
$1 5/15 = 1/3
$5 4/15
$10 3/15 = 1/5
$20 5/15 = 1/3
(b) P($9 or less) = 3/5
Step-by-step explanation:
(a) Probility Distribution
Outcome probability
$1 5/15 = 1/3
$5 4/15
$10 3/15 = 1/5
$20 5/15 = 1/3
Any other denomination
0
(b)
ways to draw $9 or less in a single draw
P($1) = 1/3
P($5) = 4/15
P($9 or less) = P($1) + P($5) = 1/3 + 4/15 = 9/15 = 3/5
Suppose that 1% of the employees of a certain company use illegal drugs. This company performs random drug tests that return positive results 99% of the time if the person is a drug user. However, it also has a 2% false positive rate. The results of the drug test are known to be independent from test to test for a given person.
a) Steve, an employee at the company, has a positive test. What is the probability that he is a drug user?
b) Knowing he failed his first test, what is the probability that Steve will fail his next drug test?
c) Steve just failed his second drug test. Now, what is the probability that he is a drug user?
Answer:
a) Pr(drug user| positive test) = 0.3333
b) The probability that he will failed his first test = 0.9703
c) the probability that he is a drug user since failed his second drug test
= 0.961165
Step-by-step explanation:
From the given information:
Suppose that 1% of the employees of a certain company use illegal drugs.
Probability of illegal drug user = 0.01
Probability of user that do not use drug = 1 - 0.01 = 0.99
From the person that is a illegal drug user, the company performs random drug tests that return positive results = 0.99
Therefore, the negative result for illegal drug user = 1 - 0.99 = 0.01
However, it also has a 2% false positive rate.
i.e the probability of the user that do not use drug has a positive result of 2% = 0.02
Thus, the probability of the user that do not use drug has a negative result of = 1 - 0.02
= 0.98
We are tasked to answer the following questions.
a) Steve, an employee at the company, has a positive test. What is the probability that he is a drug user?
i.e This employee we are taking about is a drug user and he has a positive test.
Thus;
Pr(drug user| positive test) = [tex]\dfrac{0.99 \times 0.01}{0.99 \times 0.01+ 0.02 \times 0.99}[/tex]
Pr(drug user| positive test) = [tex]\dfrac{0.0099}{0.0099+0.0198}[/tex]
Pr(drug user| positive test) = [tex]\dfrac{0.0099}{0.0297}[/tex]
Pr(drug user| positive test) = 0.3333
b) Knowing he failed his first test, what is the probability that Steve will fail his next drug test?
The probability that he will failed his first test = ((0.01 × 0.01) + (0.99×0.98))
The probability that he will failed his first test = ( 1 × 10⁻⁴ + 0.9702)
The probability that he will failed his first test = 0.9703
c) Steve just failed his second drug test. Now, what is the probability that he is a drug user?
the probability that he is a drug user since he failed his second drug test using Bayes theorem can be expressed as:
= [tex]\dfrac{0.01 \times(0.99\times 0.99)}{0.01 \times (0.99 \times0.99)+ 0.99(0.02 \times0.02)}[/tex]
the probability that he is a drug user since failed his second drug test
= [tex]\dfrac{0.01 \times(0.9801)}{0.01 \times (0.9801)+ 0.99(4 \times 10^{-4})}[/tex]
the probability that he is a drug user since failed his second drug test
= [tex]\dfrac{0.009801}{0.009801+ 3.96 \times 10^{-4}}[/tex]
the probability that he is a drug user since failed his second drug test
= 0.961165
BRAINLIST AND A THANK YOU AND 5 stars WILL BE REWARDED PLS ANSER
Answer:
The first picture's answer would be (6, 21)
Step-by-step explanation:
You have to find the points on the 8th and the 9th day, and then you would add them together, and then divide by two finding the average, which would be 24 and 18, so when added, you get 42, divided by 2 you get 21. You look on the graph for the point with 21, and you find it is on 6.
You found the prime factorization of the number 73 explain how you can check your answer
9514 1404 393
Explanation:
You can check your answer by making sure that each of the primes you found is actually a prime. (Compare to a list of known primes, for example.) After you have determined your factors are primes, multiply them together to see if the result is 73. If so, you have found the correct prime factorization.
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Additional comment
73 is prime, so its prime factor is 73.
73 = 73
A line passes through the point (2, 3) and has a slope of -8. Write an equation for this line.
Answer:
y = -8x+19
Step-by-step explanation:
The slope intercept form of a line is
y = mx+b where m is the slope and b is the y intercept
y = -8x+b
Substitute the point into the equation
3 = -8(2)+b
3 = -16+b
Add 16 to each side
3+16 = b
19 = b
y = -8x+19
Step-by-step explanation:
to find the equation of this line you use the equation of the slope intercept which is y-y1= m (x-x1)
y-3=-8(x-2)
y-3=-8x+16
y=-8x+16+3
y=-8x+19
I hope this helps