A boat goes 24 miles at a constant speed in 4 hours against a river current. It takes the boat 3 hours to go the same distance at the same speed with the current of the river. What is the speed of the boat and what is the current of the river?

Boat speed: Speed of Current:

Answer:

-4

Step-by-step explanation:

6 − 4x − 8 + 2

The variable is x

The coefficient is the number in front of the variable ( it will include the sign)

-4 is the coefficient

Answer:

-4

Step-by-step explanation:

Answer:

big area/small area = (big length/small length)^2

24/small area = (6/3)^2

24/sa = 4

sa= 6

Answer:

x=27

Step-by-step explanation:

expanding the above expression we get

5x+5=4x+32

grouping numbers with coefficient of x at the left side and constant at the right side we get

5x-4x=32-5

x=27

Answer:

66

Step-by-step explanation:

The figure of triangle JKL is attached. JA = 9, AL = 10, and CK = 14.

According to two tangent theorem, the tangent to a circle that meets at the same point is equal to each other. Therefore:

AJ = BJ, AL = CL, CK = BK.

Since AJ = 9, BJ = AJ = 9

AL = 10, CL = AL = 10

CK = 14, BK = CK = 14.

Therefore the lengths of the triangle sides are:

JL = AJ + AL = 9 + 10 = 19

JK = BJ + BK = 9 + 14 = 23

KL = CL + CK = 14 + 10 = 24

The perimeter of the triangle is the sum of all its sides, it is given as:

Perimeter = JL + JK + KL = 19 + 23 + 24 = 66

Answer:

2 hours

Step-by-step explanation:

first tap= 3hours

therefore work done is = 1/3

second tap= 6hours

therefore work done = 1/6

so, 1/3+ 1/6

=2/6 + 1/6

=3/6

=1/2

=2/1 hours

=2 hours

Answer:

[tex]4\sqrt{3}[/tex]

Step-by-step explanation:

[tex]4\sqrt{3}[/tex] = [tex]\sqrt{6}[/tex] x [tex]\sqrt{8}[/tex]

Answer:

4 root 3 is the answer

Step-by-step explanation:

hope its help

Answer:

2x + 3

Step-by-step explanation:

(10x² + 19x + 6) ÷ (5x + 2)​ =

= (10x² + 15x + 4x + 6) ÷ (5x + 2)​

= [5x(2x + 3) + 2(2x + 3)] ÷ (5x + 2)​

= [(5x + 2)(2x + 3)] ÷ (5x + 2)​

= 2x + 3

Answer:

2x+3 is your answer

Answer:

33 1/3 %

Step-by-step explanation:

120degree is shaded

There are 360 degrees in a circle

120/360

1/3

.33333

33 1/3 %

Answer: please find the attached file for the graph.

Step-by-step explanation:

Number of minutes 1 2 3 4 5 6 7 8 9 10Number of trainees 2 3 5 10 15 30 25 15 10 5

Given that data set above, the time in minutes will be on the x axis while the number of trainees will be in the y axis.

In bar chart, the bars will not touch each other.

Please find the attached file for the solution and figure

Answer:

510 cm²

Step-by-step explanation:

To find how much construction paper is needed for the model, we calculate the total areas of each of its sides.

The area of the first triangular sides is A₁ = 15 cm × 5 cm = 75 cm²

The area of the second triangular sides is A₂ = 15 cm × 13 cm = 195 cm²

The area of the third triangular sides is A₃ = 15 cm × 12 cm = 180 cm²

The area of each triangular side is A₄ = 1/2 × 5 cm × 12 cm = 30 cm²

The area of the two triangular sides is A₅ = 2A₄ = 2 × 30 cm² = 60 cm²

The total surface area of a wedge of cheese is A = A₁ + A₂ + A₃ + A₅ = 75 cm² + 195 cm² + 180 cm² + 60 cm² = 510 cm²

So the amount of construction paper needed equals the total surface area of the wedge of cheese = 510 cm²

Answer:

510

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Note the expansion

tan(a - b) = [tex]\frac{tana-tanb}{1+tanatanb}[/tex]

We are given the right side of the expansion , then left side is

tan([tex]\frac{\pi }{7}[/tex] - [tex]\frac{\pi }{8}[/tex] )

= tan([tex]\frac{8\pi -7\pi }{56}[/tex] )

= tan ([tex]\frac{\pi }{56}[/tex] ) → A

Answer:

[tex]243.2cm^{2}[/tex]

Step-by-step explanation:

Step 1: Understand what this shape is constructed out of

2 Congruent Trapezoid

2 Congruent Rectangles

1 Small Rectangle

1 Large Rectangle

Step 2: Find the surface area of the shapes

Area of 2 Trapezoids =[tex](\frac{a+b}{2}h)2=(\frac{4+6}{2}2.8)2=(\frac{10}{2}2.8)2=((5)}(2.8))2= (11.6)(2)=23.2cm^{2}[/tex]

Area of 2 Rectangles = [tex](3)(10)(2)=(60)(2)=120cm^{2}[/tex]

Area of Smaller Rectangle = [tex](4)(10)=40cm^{2}[/tex]

Area of Larger Rectangle = [tex](6)(10)=60cm^{2}[/tex]

Step 3: Add the surface areas up

[tex]23.2cm^{2} +120cm^{2} +40cm^{2} +60^{2} =243.2cm^{2}[/tex]

Therefore the surface area of the Trapezoidal Prism is [tex]243.2cm^{2}[/tex]

Answer/Step-by-step explanation:

Use the distance formula, [tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex], to solve each problem.

1. Distance between A(0, 0) and B(-5, 7):

[tex] (0, 0) = (x_1, y_1) [/tex]

[tex] (-5, 7) = (x_2, y_2) [/tex]

[tex] AB = \sqrt{(-5 - 0)^2 + (7 - 0)^2} = \sqrt{(-5)^2 + (7)^2} = \sqrt{25 + 49} [/tex]

[tex] AB = \sqrt{74} [/tex]

2. Distance between A(-3, 1) and B(-11, 1):

[tex] (-3, 1) = (x_1, y_1) [/tex]

[tex] (-11, 1) = (x_2, y_2) [/tex]

[tex] AB = \sqrt{(-11 - (-3))^2 + (1 - 1)^2} = \sqrt{(-8)^2 + (0)^2} = \sqrt{64 + 0} [/tex]

[tex] AB = \sqrt{64} = 8 [/tex]

3. Distance between A(-3, -2) and B(5, 6):

[tex] (-3, -2) = (x_1, y_1) [/tex]

[tex] (5, 6) = (x_2, y_2) [/tex]

[tex] AB = \sqrt{(5 - (-3))^2 + (6 - (-2))^2} = \sqrt{(8)^2 + (8)^2} = \sqrt{64 + 64} [/tex]

[tex] AB = \sqrt{128} = \sqrt{64*2} [/tex]

[tex] AB = 8\sqrt{2} [/tex]

4. Distance between A(-2, -5) and B(-6, 1):

[tex] (-2, -5) = (x_1, y_1) [/tex]

[tex] (-6, 1) = (x_2, y_2) [/tex]

[tex] AB = \sqrt{(-6 - (-2))^2 + (1 - (-5))^2} = \sqrt{(-4)^2 + (6)^2} = \sqrt{16 + 36} [/tex]

[tex] AB = \sqrt{52} [/tex]

None of the choices are correct

Answer:

Step-by-step explanation:

Given that :

the  perpendicular distance of the point from x axis = 2 units

the perpendicular distance from y axis is 3 units

The objective is to the write the coordinates of the points if it lies in

(i) | Quadrant  (ii) || Quadrant (iii) ||| Quadrant (iv) |v Quadrant

The position of a point in a plane is conveniently specified by the distances fro two perpendicular lines.The lines are called the x-axis and y-axis and their [point of intersection is called the origin.

The perpendicular distance from the y-axis is called the x- coordinate or abscissa and the perpendicular distance from x-axis is called the y-coordinate or ordinate,The  coordinate form an ordered pair with the abscissa written as first.

With that be said, So In the given question,

the  perpendicular distance of the point from x axis = 2 units

y coordinate = ±2

the perpendicular distance from y axis is 3 units

x coordinate = ±3

The ordered pair of the coordinates = ( ±3, ±2)

Therefore;

in | quadrant ; we have (3,2)   where  x and y are both on the positive axis

in || quadrant ; we have (-3,2)   x is on the negative axis and y is on the positive axis

In ||| quadrant ; we have (-3. -2) both x and y are on the negative axis

In |v quadrant ; we have ( 3, -2)  x is on the positive axis and y is on the negative axis.

Answer:

x = 67°

Step-by-step explanation:

The 2 base angles x are congruent , then

x = [tex]\frac{180-46}{2}[/tex] = [tex]\frac{134}{2}[/tex] = 67°

Answer:

X= 67 degrees.

Step-by-step explanation:

All triangles must add up to 180°. This is an isosceles triangle which means once you have one degree you can find the other two.

In order to get the answer start with 180°-46°

180-46=134

The two x's equal each other. So you can divide the remaining degrees by 2 to get the answer.

134÷2=67.

So the answer is 67°.

Hi, I'm happy to help!

First, we need to solve for x. We know that ABD is 78 degrees. (5x+3), and (5x-5) combined are also 78 degrees. So, we combine the like terms of these to get a new expression.

(5x+3) +(5x-5)

10x-2=78

From here, we want to single out the x, by editing both sides in the same way.

10x-2=78

    +2  +2

10x=80

÷10 ÷10

x=8

Now that we know what x is, we can plug it in to the previous expressions to get the angles of ABC and DBC.

(5x-5)

((5·8)-5)

(40-5)

35

Now, we know that ABC is 35 degrees.

(5x+3)

((5·8)+3)

(40+3)

43

Now, we also know that DBC is 43 degrees.

To verify our answer we can add ABC and DBC together to check if it totals to ABD.

35+43=78

Now, we know that the answer: ABC is 35 degrees and DBC is 43 degrees is correct.

I hope this was helpful, keep learning! :D

Answer:

x =  127º

Step-by-step explanation:

y = 127º    {Corresponding angles}

x = y      {Vertically opposite angles}

x = 127º

Answer:

5/2 OR 2.5

Step-by-step explanation:

( x + 2y ) = 7 , ( x - 2y ) = 5

x = 7 - 2y , x = 5 + 2y

substitute the two eqns together:

7 - 2y = 5 + 2y

7 - 5 = 2y + 2y

2 = 4y

y = 1/2

when y = 1/2 ,

5y = 5(1/2)

= 5/2 OR 2.5

Answer:

Yes, it is a polynomial, and the degree is 5

Step-by-step explanation:

A polynomial is a combination of terms separated using + or − signs and normally have exponents. So, this equation is a polynomial. The degree is just the highest exponential value, which is 5 because -5y is being raised to the 5th power

Answer: B. down

Step-by-step explanation:

Translation rules:

For a function h(x):

Here, the graph of f(x) becomes the graph of g(x) =f(x)-4 which is similar to "h(x)-c".

That means , f(x) is shifted 4 units down to become g(x).

So, correct option : B. down

let breadth be X

length = 2x

height = 8m

rate of painting the four wall= 20/m^2

cost of painting=9600

Area of four wall= cost of painting / rate

= 9600/20

= 480m^2

again,

Area of four wall = 2 h(l+b)

or, 480=2×8(X+2x)

or, 480/16=3x

or, 30/3=X

or, X= 10m

again,

2x= 2×10m=20m

again,

Area of floor = length × breadth

= 20×10

=200m^2

again,

rate of carpeting the floor= 400/m^2

cost of carpeting the floor = rate × area

= 400× 200

= Rs. 80000

This question is solved using sampling, and proportions concepts.

The sample proportion is the point estimate for the population proportion, and we use this to find the estimate, which we find as 15% = 0.15, which is the sample proportion.

----------------------------------------------------

Proportion:

A proportion is the number of desired outcomes divided by the number of total outcomes.

----------------------------------------------------

In this question:

You take a sample of 30 candies. Your sample proportion

of yellow candies is 15%.

Thus, the point estimate of the true proportion of yellow candies in the sample, according to your sample, is of 15%.

----------------------------------------------------

A similar problem can be found at: https://brainly.com/question/24083999

Answer:

A. 3.8 grams

Step-by-step explanation:

A baking scale measures mass to the tenth of a gram, up to 650 grams. Which of the following measurements is possible using this scale?

a.3.8 grams

b.120.01 grams

c.800.0 grams

d.54 milligrams

Solution

The scale measures mass to the tenth of a gram

The scale measures up to 650 grams

a.3.8 grams

This measures to the tenth of a gram (to one decimal place) and it is not up to 650 grams

b.120.01 grams

This measures to hundredth of a gram ( 2 decimal places) and it is not up 650 grams.

c.800.0 grams

This measures to the tenth of a gram but exceeds the 650 grams limit

d.54 milligrams

This is in milligram, so it is wrong

Option a.3.8 grams is the only possible scale measurement among the options.

Answer:

34.5

Step-by-step explanation:

5 times x(2.3) = 11.5.

11.5 times 3 is 34.5

you put 2.3 in place of x because x was the unknown value, but now that we know it is 2.33 we plug it in.

Answer:

33

Step-by-step explanation:

For every 5 squares, two are red and three are green.  So 3/5 of the squares are green.

3/5x55=33

Answers:

======================================================

How to get those answers:

Let w be the unknown width in centimeters. This variable is some positive real number. This means w > 0 which will be useful later.

The length is "1 cm less than 3 times its width" and it tells us the length is defined by the expression 3w-1. Whatever w is, we triple it to get 3w and then subtract 1 to get the final length.

Multiply the length and width to get the area 102

length*width = area

(3w-1)*w = 102

3w^2-w = 102

3w^2-w-102 = 0

We could guess and check our way to factoring this, but that's not very efficient. The quadratic formula is the better option. It may seem a bit messy, but it's a more direct path that doesn't involve guessing.

[tex]w = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\w = \frac{-(-1)\pm\sqrt{(-1)^2-4(3)(-102)}}{2(3)}\\\\w = \frac{1\pm\sqrt{1225}}{6}\\\\w = \frac{1\pm35}{6}\\\\w = \frac{1+35}{6}\ \text{ or } \ w = \frac{1-35}{6}\\\\w = \frac{36}{6}\ \text{ or } \ w = \frac{-34}{6}\\\\w = 6\ \text{ or } \ w \approx -5.667\\\\[/tex]

We ignore the second solution (w = -5.667 approximately) because we stated earlier that w > 0. In other words, a negative length does not make sense, so that's why we ignore it.

-----------------

If w = 6 cm is the width, then 3w-1 = 3*6-1 = 18-1 = 17 cm is the length.

Note that length*width = 17*6 = 102 which is the proper area we want. This confirms the answers.

Answer:

2(x + 9)(x + 1)

Step-by-step explanation:

-2(x^2 + 10x + 9)

→ The main quadratic equation is equal to ax^2 + bx + c.

2(x + 9)(x + 1)

The expression cannot be factored any further.

Answer:Answer:

[tex]\sum\left {{7} \atop {1}} \right -n(3+n)[/tex]

Step-by-step explanation:

Given the sequence -4,-6,-8..., in order to get sigma notation to represent the sum of the first seven terms of the sequence, we need to first calculate the sum of the first seven terms of the sequence as shown;

The sum of an arithmetic series is expressed as [tex]S_n = \frac{n}{2}[2a+(n-1)d][/tex]

n is the number of terms

a is the first term of the sequence

d is the common difference

Given parameters

n = 7, a = -4 and d = -6-(-4) = -8-(-6) = -2

Required

Sum of the first seven terms of the sequence

[tex]S_7 = \frac{7}{2}[2(-4)+(7-1)(-2)]\\\\S_7 = \frac{7}{2}[-8+(6)(-2)]\\\\S_7 = \frac{7}{2}[-8-12]\\\\\\S_7 = \frac{7}{2} * -20\\\\S_7 = -70[/tex]

The sum of the nth term of the sequence will be;

[tex]S_n = \frac{n}{2}[2(-4)+(n-1)(-2)]\\\\S_n = \frac{n}{2}[-8+(-2n+2)]\\\\S_n = \frac{n}{2}[-6-2n]\\\\S_n = \frac{-6n}{2} - \frac{2n^2}{2}\\S_n = -3n-n^2\\\\S_n = -n(3+n)[/tex]

The sigma notation will be expressed as [tex]\sum\left {{7} \atop {1}} \right -n(3+n)[/tex]. The limit ranges from 1 to 7 since we are to  find  the sum of the first seven terms of the series.