A bowling ball accidentally falls out of the cargo bay of an airliner as it flies along in a horizontal direction. As seen from the ground, which path would the bowling ball most closely follow after leaving the airplane?

Enormous energy get released from the sun due to fusion reaction.

Sun can generate enormous energy due to nuclear fusion. In this process, high temperature and pressure in the core of the sun force the nuclei to separate from their electrons which results in the  formation of one Helium atom releasing a large amount of energy.

So we can conclude that enormous energy get released from the sun due to fusion reaction.

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True. The partial pressure of gas that is made up of a mixture of gases is the sum of the individual pressure of the gases.

Dalton's law of partial pressure of gases is one of the gas laws that take into consideration the fact that a gas can be made from a mixture of non-reacting gases.

According to him, if a gas is made as such, the pressure of the gas would be the sum of the individual pressure of the component gases. This means that each gas contributes partially to the overall pressure of the gas mixture.

Thus, if gas A is a mixture of gas B and gas C. The pressure, P, of gas A is given as:

P = Pb + Pc where Pb and Pc are the partial pressure of gases B and C respectively.

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Answer:

The direction of the net force is at a tangent to the circle.

Answer:

none

Explanation:

stranger mid mid mid mid

Answer:

My favorite stranger things character is Eleven also known as Millie Bobby Brown

Explanation:

I hope this helps and have a good day!

In a dry pipe sprinkler system, pressurized air or nitrogen, rather than water, is used to fill the pipes. This air maintains the closed position of a remote valve, also referred to as a dry pipe valve.

The dry-pipe valve, which is situated in a hot area, keeps water from flowing into the pipe until a fire triggers the operation of one or more sprayer. When this occurs, the dry pipe valve releases and the air leaves. After that, water enters the pipe and pours onto the flames through open sprinklers.

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Absorption of Rum and cola:

A standard rum and cola absorb faster than a 5-ounce glass of wine because carbonation causes the pyloric valve to relax.

What are Rum and Cola:

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B. An ear squeeze occurs when the pressure inside the middle ear space is less than ambient (surrounding) pressure.

External ear squeeze occurs when gas trapped in the external ear canal remains at atmospheric pressure while the external water pressure increases during descent.

Thus, we can conclude that, an ear squeeze occurs when the pressure inside the middle ear space is less than ambient (surrounding) pressure.

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(a) The diameter of the largest orbit just before the protons exit the cyclotron is 39 cm.

(b) The number of orbits completed by the proton during this 1.0 ms is 14000 revolutions.

What is  kinetic energy?

The kinetic energy of an object is the energy that it possesses due to its motion.

It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.

Formula of KE:

K.E = 1/2mv²

mv² = 2 K.E

v = sqrt( 2*KE / M)

Here,

(a)

The KE of the medical isotopes = 6.5 MeV

substituting the values,

v = sqrt( 2* 6.5* 1.6* 10^-13 / 1.67* 10^-27 )

v = 3.53 × 10⁷ m/s

Now the centripetal force:

mv² / R = qvB

r = q*v / mv²

r = ( 1.67* 10^-27 * 3.53 × 10⁷ ) / ( 1.9* 1.6* 10^-19 )

r = 0.19415 m

diameter d = 2r,

d= 2(0.19415  m)

d= 0.39 m ≅ 39 cm

(b)

The time period to complete a revolution around the spiral trajectory is:

T = 2πr / v

T = 2*3.14* 0.1941 / 3.53*10^7

T = 0.7 × 10⁻⁷ s

Thus, the number of orbits that the proton does to complete the revolution in 1 ms is:

n = t / T

n = 10^-3 / (0.7*10^-7)

n = 14285.71  ≅ 14000 revolutions

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Your question is incomplete, but most probably full question was:

A medical cyclotron used in the production of medical isotopes accelerates protons to 6.5 MeV. The magnetic field in the cyclotron is 1.9 T.

(a) What is the diameter of the largest orbit, just before the protons exit the cyclotron? Express your answer with the appropriate units. d = 57 cm Previous

(b) A proton exits the cyclotron 1.0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1.0 ms?

Answer:

[tex]\huge\boxed{\sf v = 448\ m/s}[/tex]

Explanation:

Frequency = f = 16 Hz

Wavelength = λ = 28 m

Speed = v = ?

v = fλ

Put the givens.

v = (16)(28)

v = 448 m/s

[tex]\rule[225]{225}{2}[/tex]

A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)

In physics, power (P) is the work (W) done over a period of time.

The bodybuilder lifts a 215 kg (m) weight to a height of 0.90 m (h). Being the gravity (g) of 9.81 m/s², we can calculate the work done in each lift using the following expression.

W = m × g × h = 215 kg × 9.81 m/s² × 0.90 m = 1.9 × 10³ N

W = 10 × 1.9 × 10³ N = 1.9 × 10⁴ N

The bodybuilder does a work of 1.9 × 10⁴ N in a 45-s span.

P = 1.9 × 10⁴ N/45 s = 421 W

A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)

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Galaxy M33 is classified as a Triangulum normal spiral.

The galaxy M33 is the third largest galaxy in the Local Group after M31 and the Milky Way. The galaxy M33 has a moderate-sized central bulge and two spiral arms that emerge directly out of the bulge and wrap around in rather poorly defined arcs with many cross-connections between the arms.

This spiral galaxy is located in the triangle shaped constellation earning a pet name as triangular galaxy. This galaxy star formation rate is ten times higher than average found in Andromeda galaxy.  It has relatively bright apparent. This galaxy was given by Charles Messier and he classified it as Triangulum normal spiral.

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The magnitude of average force applied to the ball is 128N.

To find the answer, we need to know about the average force.

Thus, we can conclude that the average force is 128N.

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Emission lines are created by the star in the center's brightness.

A star in this kind of nebula uses UV radiation to energise the cloud's atoms. These atoms release radiation as they revert to lower energy states. It works in a manner like to a neon light. The nebula glows as a result of this.

The expelled shell of an evolved massive star is a planetary nebula.

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The terminal velocity as it falls through still air is 4.65154 in/s.

The diameter of small water droplet is 1.25 mil= 1.25×0.0254×10^-3 m

                                                                            = 3.175 × 10^-5 m

Now the viscosity of still air is η = 1.83× 10⁻⁵ Pa

 So the formula for drag force is:

                Fd = 6πηrv

  where,  v is the velocity.

Now to attain terminal velocity acceleration must be zero.

            →  W = Fd

                ρVg = 6πrηv

                ρ × 4/3 πr³×g = 6πrηv

                           v = 2/9 × ρgr³/ η

                           v =  2/9 × 10³×9.81×(3.175×10^-3) / 18.6×10^-6

                           v = 0.1181  m/s

                           v = 4.65154 in/s

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The first blank is robust watermark; a robust watermark will not resist tampering.

The second blank is fragile watermark; a fragile watermark will resist manipulations of the media.

A watermark is a faint design made in paper during manufacture that is visible when held against the light and clearly identifies the maker.

The watermark can be of different types depending on the application and they include:

Thus, The first blank is robust watermark; a robust watermark will not resist tampering.

The second blank is fragile watermark; a fragile watermark will resist manipulations of the media.

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F = ma is the formula of Newton's Second Law of Motion. Newton's Second Law of Motion is described as Force is equal to the rate of change of momentum. For a constant mass, force equals mass duration acceleration.

Newton's Second Law of Motion F=ma is very significant because it indicates the relationship between forces and motion. It permits you to calculate the acceleration (and therefore velocity and position) of an object with known forces. This is extremely helpful for scientists, engineers, inventors, etc.

Therefore : F is directly proportional to m×a. This relation F is directly proportional to m×a can be turned into an equation by placing in a constant k.

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you can use the graph to estimate the value of x when y is required to start a doubles match with the sun and the sky very well from her childhood and a kind young women who lives with her wearing a black and a veil and shows to be in that position or they have a bad past or bad life that they want to take revenge on every one by murder goes on by them in the streets of St and St Mary's Church and its followers are known as Sikhs and the other children claim she

(A) The speed of the pendulum when it reaches the bottom is 3.83 m/s.

(B) The speed of the  pendulum when it reaches the bottom after losing 18% of its energy is 3.47 m/s.

(C) The height reached by the pendulum after losing another 7% of its energy is 0.57 m.

(D) When the pendulum stops swinging, it has used all its energy to overcome frictional force of air.

Apply the principle of conservation of energy;

K.E = P.E

¹/₂mv² = mgh

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 0.75)

v = 3.83 m/s

K.E = (100 -  18)P.E

¹/₂mv² = 0.82mgh

V = √(0.82 x 2gh)

v = √(0.82 x 2 x 9.8 x 0.75)

v = 3.47 m/s

K.E = 0.5(1)(3.47)² = 6.02 J

When it losses 7% = 6.02 - (0.07 x 6.02) = 5.598 J

Height reached:

mgh = 5.598

h = 5.598/mg

h = 5.598/(1 x 9.8)

h = 0.57 m

When the pendulum stops swinging, it has used all its energy to overcome frictional force of air.

Thus, the speed of the pendulum when it reaches the bottom is 3.83 m/s.

The speed of the  pendulum when it reaches the bottom after losing 18% of its energy is 3.47 m/s.

The height reached by the pendulum after losing another 7% of its energy is 0.57 m.

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Highest to lowest number:

-less than 1 solar mass

-between 1 and 10 solar masses

-between 10 and 30 solar masses

-between 30 and 60 solar masses

Stellar mass is a phrase that is used by astronomers to describe the mass of a star.

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The element of a valid contract which is established by getting the signatures of all parties is mutual agreement

An element of a valid contract simply refers to that promise made between two or more parties that which allow the courts to make judgement.

Some elements of valid contract are:

So therefore, the element of a valid contract which is established by getting the signatures of all parties is mutual agreement

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relationship between these inflammatory markers and infection.

Recognised inflammatory biomarkers play important roles in the management of patients with for example, diagnosis, follow-up, assessment of treatment response and risk stratification

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Time for which box will remain in contact with spring is 1.1 sec

Given:

mass of box = 8 kg

initial speed of box = 1.5 m/s

spring constant = 69 N/m

To Find:

time for which box will remain in contact with spring

Solution: The time taken to complete one oscillation is called the time period. where m is the mass, and k is the spring constant.

Time period is given as

t = π √m/k

t = 3.14 √8/69

t = 1.1 sec

So time for which box will remain in contact with spring is 1.1 sec

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White lights can sometimes be found on red buoys.

Hence, Option C is correct answer.

Thus from the above conclusion we can say that White lights can sometimes be found on red buoys.

Hence, Option C is correct answer.

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❄ Hi there.

a pencil is composed mostly of wood.

Let's check if the other choices are right.

A. Sweaters are not made of wood

B. Tiles are not made of wood

C. Pencils are made of wood

D. Bricks are not made of wood

∴ the right choice is C.

❄

The period is √2 *T if the mass is doubled to 2m.

What is the time period?

The time period is the length of time during which an activity occurs or a condition remains.

The equation for the period T is given as:

[tex]T = 2\pi \sqrt{\frac{m}{k} }[/tex]

where k is the spring constant

mass of the system = m

Here,

If the mass id doubled to 2m for the system that is set in motion,

new mass is now  2m

So the equation for time period becomes,

[tex]T' = 2\pi \sqrt{\frac{2m}{k} }[/tex]

[tex]T' = \sqrt{2} * 2\pi \sqrt{\frac{m}{k} }[/tex]

[tex]T' = \sqrt{2}* T[/tex]

Hence,

The period is √2 *T if the mass is doubled to 2m.

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The period of a satellite, the time it takes for a complete revolution, depends on the satellite's mass of planet and the distance of satellite form center of the planet .

According to the question

The period of a satellite, the time it takes for a complete revolution, depends on the satellite's:

1. The mass of the planet being orbited

2. The distance of the satellite from the center of the planet.

Hence, The period of a satellite, the time it takes for a complete revolution, depends on the satellite's mass of planet and the distance of satellite form center of the planet .

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The only vertical forces acting on the wall are the weights of the man and the ladder as well as the normal force because the wall has no friction.

The maximal frictional forces are μsN2=(0.40)(900N)=360N, and N1=w1+wm=160N+740N=900N for the vertical forces to balance. At a height of 4.0 meters above the ground, the ladder makes contact with the wall. about the point of contact with the ground, balancing torques.

N2 = 174.0N because (4.0m)2 = (1.5m)(160N) + (1.0m)(35)(740N) =684N.m. It is necessary for the frictional force to counteract this horizontal force. Setting the frictional fore and n1 to a maximum of 360N and solving for the distance x along the ladder (0.4m)(360N)=(1.50m)(160N)+x(35)(740N) yields x=2.70m

When two sliding solid surfaces, fluid layers, or material components come into contact with one another, friction acts as a force to stop them from moving in the same direction. Friction comes in several forms:

The relative lateral motion of two solid surfaces in contact is opposed by dry friction. Between moving surfaces, there is kinetic friction, which is different from static friction. With the exception of atomic or molecule friction, asperities on the surface interact to produce dry friction.

When layers of a viscous fluid move in relation to one another, there is friction between them. This is known as fluid friction.

When a lubricant fluid separates two solid surfaces, it is called lubricated friction.

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Option b) Stomach is most likely to have the most muscles.

There are five main muscles in stomach pyramidalis, rectus abdominus, external obliques, internal obliques, and transversus abdominis.

Muscles circulate frame parts by contracting after which relaxing. muscular tissues can pull bones, however, they cannot push them to return to their unique role. so they paintings in pairs of flexors and extensors. The flexor contracts to bend a limb at a joint.

The muscle groups that circulate our frame elements are called skeletal muscles, and they're a form of striated muscle. We will actively manipulate those with our brains. another sort of striated muscle is those that maintain our hearts pumping, which we are not able to actively control.

Muscles pull at the joints, allowing us to move. a couple of muscular tissues are used for any sort of motion of a bone. Although we are sitting flawlessly nevertheless, muscle tissues at some point in the frame are constantly shifting.

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work done will be 2.5872 J

Given :

mass of block = 2kg

distance travelled by block = 20cm

angle of inclination = 40°

To Find :

Work done by gravity

Solution :

Gravity is defined as the force that attracts a body towards the earth or towards any other physical body having mass.

work done by gravity is mgh

If θ is the angle made when the body falls, the work done by gravity is given by,

W = m g h cosθ

W = 2 x 9.8 x 0.2 x cos40°

= 2.5872 J

So work done will be 2.5872 J

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The velocity when function p(t)=11 is 8 .

According to the question

The position of a car at time t  represented by function :

[tex]p(t)=t^{2} +2t-4[/tex]

Now,

When  function p(t) = 11 , t will be

[tex]p(t)=t^{2} +2t-4[/tex]

11 = t²+2t-4

0 = t² + 2t - 15

or

t² +2t-15 = 0

t² +(5-3)t-15 = 0

t² +5t-3t-15 = 0

t(t+5)-3(t+5) = 0

(t-3)(t+5) = 0  

t = 3 , -5  

as t cannot be -ve as given ( t≥0)

so,

t = 3

Now,

the velocity when p(t)=11

As we know velocity = [tex]\frac{position}{time}[/tex]

therefore to get the value of velocity from  function p(t)

we have to differentiate the function with respect to time

[tex]\frac{d(p(t))}{dt} =\frac{d}{dt} (t^{2} +2t-4)[/tex]

v(t) = 2t + 2  

where v(t) = velocity at that time

as t = 3 for  p(t)=11  

so ,

v(t) = 2t + 2  

v(t) = 2*3 + 2  

v(t) = 8

Hence, the velocity when function p(t)=11 is 8 .

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