Answer: 18.56 m/sec
Explanation:
Average velocity =distance/time=5400/(4.85*60)=18.56 m/sec
A toy rocket travels at an initial velocity of 144 feet per second. The height of the rocket can be modeled by the function h(t)-144t-16t^2 where t is the time in seconds. When will the rocket return to the ground?
Answer:
t = 4.5 second
Explanation:
A toy rocket travels at an initial velocity of 144 feet per second. The height of the rocket can be modeled by the function as follows :
[tex]h(t)=-16t^2+144t[/tex]
t is time in seconds
We need to find the time when the rocket return to the ground.
When it reaches ground, h(t) = 0
So,
[tex]-16t^2+144t=0\\\\t(-32t+144)=0\\\\t=0\ \text{and} -32t+144=0\\\\t=0\ \text{and}\ t=4.5\ s[/tex]
So, at 4.5 second the rocket will return to the ground.
1) An astronaut has a mass of 40Kg. Calculate his weight on earth if Gravity (g) = 10m/s^2.
2) The same astronaut goes to the International Space Station. Here the gravitational pull is equal to .5 m/s^2. Calculate his weight.
3) Our astronaut friend is assigned to study a neutron star. He travels to the surface using a special suit. Here the gravitational force is terrible at 150m/s^2 What is the astronaut’s weight?
Answer:
The formula is W=mg.
1.) W=40×10=400.
2.)W=40×5=200.
3.)W=40×150=6000.
car travels 80 meters due north in 12 seconds then the car turns around and travels 30 Mi do South in 4 seconds calculate the average speed and average velocity of the car during this 60-second interval use guess method
Answer:
1) 3.1 m/s
2) 7 m/s
Explanation:
Distance due north = 80 m
Distance due south = 30 m
Distance between north and south = (80 - 30) m = 50 m
Total time = (12 + 4) sec = 16 sec
1) Average speed = 50/16 = 3.1 m/s
2) Average velocity = Total distance/total time = (80 + 30) m/16 s = 110/16 = 7 m/s
What is the average speed of a car that traveled 300 meters in 5.5 seconds?
Answer: 54.55 m/s
Explanation:
Distance = 300 m
Time = 5.5 s
Average Speed = Total Distance/Total Time
= 300/5.5
= 54.55 m/s
Hope this helped..
354 cm + 64565 mm = ______________m?
Answer:
68.105m
Explanation:
Convert to meters. So,
3.54 + 64.565 = 68.105
Black object are good at?
Explanation:
Absorbing heat from the sun rather than reflecting.
solve this questions please
Answer:
10.37×10³j
Explanation:
hope this helps you !!!
A ship sets out to sail to a point 154 km due north. An unexpected storm blows the ship to a point 72 km due east of its starting point. How far must it now sail to reach its original destination
Answer:
170kmExplanation:
If a ship sets out to sail to a point 154 km due north and an unexpected storm blows the ship to a point 72 km due east of its starting point, then the ships distance from the original destination can be gotten by finding the displacement of the ship and this can be gotten by using pythagoras theorem.
Let D be the unknown displacement
According to the theorem;
D² = 154² + 72²
D² = 23716 + 5184
D² = 28900
D = √28900
D = 170km
This means that the ship must now sail a distance of 170km for it to reach its original destination.
Mr. Ben drove from Town A to Town B. For the first 3 h, he traveled at an average speed of
60 km/h, and after that, he drove at another average speed of 70 km/h. If the distance
between Town A and B is 460 km, what was the total time for the whole journey?
Answer:
It’s 7 hours
Explanation:
You have to use the formula your teacher has given to you plug in the numbers then solve be sure to use a calculator made for physics it helps a lot :)
1) Find out the equivalent resistance.
2) find out all the current's in every resistors.
3) find out the voltage in resistor 1 and 4.
Answer:
1) 2.388ohms
2) R1 3.36A
R2 1.682A
R3 2.88A
R4 2.16A The current has 5.048A over all
3) Voltage in R1 is 3.36v
Voltage in R4 is 8.63v
Explanation:
1. Each of the resistance R1 and R2 are in parallel in series combination with R3 and R4 so we calculate
R1 and R2 which is 1×2÷(1+2)= 0.6667ohms
R3 and R4 which is 3×4÷( 3+4)= 1.71ohms
so the equivalent resistance is 0.667+ 1.71= *2.377ohms*
2. The overall current = voltage source ÷ total resistance
= 12÷ 2.377= 5.048Amps
so current in every resistor will be
current in 1ohms will be (2÷3)×5.048= 3.36Amps
current in 2ohms will be (1÷3)×5.048= 1.68Amps
current in 3ohms will be (4÷7)×5.048= 2.88amps
current in 4ohms will be (3÷7)× 5.048= 2.16amps
3. voltage in R1 is 0.667ohms × 5.048amps= 3.36v
voltage in R4 is 1.71ohms × 5.048amps= 8.63v
Which of the following is a helpful process in evaluating scientific claims? (2 points)
A.quoting statistics
B. Making Lists
C. Biased thinking
D. Critical thinking
Answer:
I think D. Critical thinking is the answer
Assume that before separation, the weight of the milk bottle's contents (mixed milk and cream) is wmix. How does the combined weight of the milk and cream after separation, wsep, compare to wmix
Answer:
Wsep = Wmix
Explanation:
When Cream and milk up in a bottle they might appear homogeneous but after the bottle must have settled down for a while i.e kept in a position without shaking the bottle. the contents ( cream and milk ) will be separated. this is because Milk and cream do not mix up just like some other liquids that don't mix-up. Wmix represents the weight of the bottle before separation while Wsep represents the weight after separation. but since both liquids are in the same bottle the weight after separation would remain the same
Wsep = Wmix
The bottle contents have separated. Now compute , the gauge pressure on the bottom of the milk bottle after the milk and cream have separated
When Cream and milk up in a bottle they might appear homogeneous but after the bottle must have settled bottle for a while i.e kept in a position without shaking the bottle. the contents ( cream and milk ) will be separated. this is because Milk and cream do not mix up just like some other liquids that don't mix-up. Wmix represents the weight of the bottle before separation while Wsep represents the weight after separation. but since both liquids are in the same bottle the weight after separation would remain the same.
learn more about milk bottle
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Which items in this image are electrically conductive? Check all that apply.
Answer: a and d
Explanation: A.) the power lines themselves
B.) the wooden pole that supports the lines
C.) the rubber soles on the worker’s boots
D.) the metal tools the worker uses
E.) the wooden ladder leaning against the lines
A man dropped a dime in a wishing well , he heard it 5 sec later ..Find distance traveled if moving at 10 m/s 2
Answer:
The distance traveled is 109.58 m
Explanation:
The Speed of sound in air = 344 m/s
Let the time in which the dime dropped by the man reach an impact in the well = t₁
Let the time in which the sound travel from the well to the man = t₂
Then
1/2× 10 × t₁² = 344 × t₂ which gives;
5 × t₁² = 344 × t₂.........................(1)
Also the total time before the man heard the dime = t₁ + t₂ = 5
Therefore;
t₂ = 5 - t₁
Substituting the value of t₂ in equation (1), we have;
5 × t₁² = 344 × (5 - t₁)
5·t₁² + 344·t₁ - 1720 = 0
Using the quadratic formula, we have;
[tex]x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}[/tex]
Which gives;
[tex]t_1 = \dfrac{-344\pm \sqrt{344^{2}-4\times 5\times (-1720)}}{2\times 5}[/tex]
t₁ = 4.68 s or -73.48 s
Therefore, with the positive value for t₁ = 4.68 s, we have
The distance = 1/2× 10 × 4.68² = 109.58 m
The distance traveled = 109.58 m.
(PLEASE HELP!!) Identify two types of motion where an object's speed remains the same while it continues to change direction.
One of the descriptions below is from the perspective of anatomical study, the rest are from a physiological perspective. Select the description below that comes from
an anatomical perspective
Answer:
The innermost lining of the lungs is composed primarily of thin tissue cakes simple squamous epithelium.
Explanation:
How much time will have passed by the time a sample of an isotope has decayed to 6.25% of its original mass if the half-life is 15 days? 45 days 60 days 75 days 30 days
Answer:
60 days.
Explanation:
Let the original mass (N₀) = 1 g
Amount remaining (N) = 6.25% of its original mass
= 6.25% × 1
= 6.25/100 × 1
= 0.0625 g
Half life (t½) = 15 days
Time (t) =?
Next, we shall determine the rate of decay. This can be obtained as follow:
Decay constant (K) = 0.693/ half life
K = 0.693 / t½
Half life (t½) = 15 days
Decay constant (K) =?
K = 0.693 / t½
K = 0.693 / 15
K = 0.0462 / day
Finally, we shall determine the time taken for the sample of the isotope to decay to 6.25% of its original mass.
This can be obtained as follow:
Original amount (N₀) = 1 g
Amount remaining (N) = 0.0625 g
Decay constant (K) = 0.0462 / day
Time (t) =?
Log (N₀/N) = Kt/2.3
Log (1/0.0625) = 0.0462 × t / 2.3
Log 16 = 0.0462 × t / 2.3
1.2041 = 0.0462 × t /2.3
Cross multiply
0.0462 × t = 1.2041 × 2.3
Divide both side by 0.0462
t = (1.2041 × 2.3)/0.0462
t = 59.9 ≈ 60 days
Therefore, the time taken for the sample of the isotope to decay to 6.25% of its original mass is 60 days
Select all the correct answers. In most cases, what happens to a liquid when it cools? Its density increases. Its density decreases. Its mass increases. Its mass decreases. Its volume increases. Its volume decreases.
Answer:
its density decrease
Explanation:
Explanation: As the molecules of a liquid are cooled they slow down. As the molecules slow down they take up less volume. Taking up less room because of the molecules lower energy causes the liquid to contract.
Answer:
A & F
Explanation:
As the liquid cools down, it means the temperature decreases the density of the liquid increases in most o the cases.
Now the volume is inversely proportional to the density of substance so density increases.
what is the mass of density=2 g/mL volume= 20mL?
m = 40 g
Explanation:d = m/V => m = d×V
m = 2g/ml×20ml
= 40 g
A student conducts an experiement in their class. They determine that when you increase a mass by four times it's original amount, the acceleration is experiences also drops to 1/4th of it's original value. What value was the student holding constant during this experiment? a Force b Mass c Acceleration d Weight
Answer:
Correct answer is A Force
Explanation:
The experiment that the students are carrying out is to verify Noten's second law, which has the equation
F = m a
where F is the force, the acceleration and m the mass of the body.
In this case, they indicate that slats were increased 4 times and the acceleration decreased 4 times, therefore when replacing
F = (4m) (a/4)
from here we can see that the force remains constant.
Correct answer is A
A wedge is a double inclined plane. why?
Answer:
A wedge is a double inclined plane. ... When a wedge is moved, it applies force on an object. It applies an output force greater than your input force. In the case of an axe, the output force is so great that it causes wood to split.
in a hyrdo electic power plant the moving water turns the turbine creating ____________ energy.
Answer:
....................
Explanation:
................
Answer:
Mechanical Energy
Explanation:
Mechanical energy is energy possessed by motion. A hydroelectric power plant creates energy by motion.
Super fine 40-gauge copper wire has a diameter of only 0.080mm and weighs only 44.5/gkm. Suppose a spool of 40-gauge wire weighs 570.g less after some wire is pulled off to wind a magnet. How could you calculate how much wire was used? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols.
Answer:
[tex]Amount\ of\ wire\ used=\frac{M}{44.5\ g/km}[/tex]
mount of wire used=12.808989 Km
Amount of wire used=12808.989 m
Explanation:
Given Data:
Diameter of wire=d=0.080 mm=0.00008 m
Weight of wire per unit length=44.5 g/km
Spool weighs=M=570 g
Required:
Amount of wire used=L=?
Solution:
Formula is:
[tex]Amount\ of\ wire\ used=\frac{Spool\ weighs}{Weight\ per\ unit\ length}[/tex]
[tex]Amount\ of\ wire\ used=\frac{M}{44.5\ g/km}[/tex]
The above expression is mathematical model of finding how much wire is used. just put the Value of M we will get the answer.
[tex]Amount\ of\ wire\ used=\frac{570\ g}{44.5\ g/km}[/tex]
Amount of wire used=12.808989 Km
Amount of wire used=12808.989 m
a second class lever needs less effort to lift a heavy load.why give reason
Answer:second class lever needs less force to lift a load
Explanation: because the load is between the fulcrum/pivot point and the force. The fulcrum is far away from the force
A ball rolled at a velocity of 12 m/sec. After 36 seconds, it comes to a stop. What is the acceleration of the ball? Round to the nearest tenth.
Solving the problem mathematically,
Initial velocity of the ball 12m/s
Final velocity 0m/s
Travel time 36s
Assuming the velocity follows a straight line, then the slope of the curve is equal to the rate of change of velocity (acceleration)
ie taninv(dv/dt) since it is linear taninv(12/33)= 0.33 m/s^2 deceleration.
If in case the velocity doesn’t follow the linear path acceleration= d(velocity profile)/dt. ie the first order differentiation of velocity is the acceleration.
HELP ME PLEASE !!!!!!!!!!!!!!!!!
Answer:
Option D. 6.1 m/s²
Explanation:
We'll begin by calculating the acceleration due to gravity in each case. This is illustrated below:
1. For Rock:
Mass (m) = 20 g
Force (F) = 0.1224 N
Acceleration due to gravity (g) =?
Next, we shall convert 20 g to kg. This can be obtained as follow:
1000 g = 1 kg
Therefore,
20 g = 20/1000
20 g = 0.02 kg
Finally, we shall determine the acceleration due to gravity as follow:
Force of gravity (F) = mass (m) x Acceleration due to gravity (g)
F = mg
Mass (m) = 0.02 kg
Force (F) = 0.1224 N
Acceleration due to gravity (g) =?
F = mg
0.1224 = 0.02 × g
Divide both side by 0.02
g = 0.1224/0.02
g = 6.12 m/s²
2. For Grain of sand:
Mass (m) = 0.8 g
Force (F) = 0.00501 N
Acceleration due to gravity (g) =?
Next, we shall convert 0.8 g to kg. This can be obtained as follow:
1000 g = 1 kg
Therefore,
0.8 g = 0.8/1000
0.8 g = 0.0008 kg
Finally, we shall determine the acceleration due to gravity as follow:
Force of gravity (F) = mass (m) x Acceleration due to gravity (g)
F = mg
Mass (m) = 0.0008 kg
Force (F) = 0.00501 N
Acceleration due to gravity (g) =?
F = mg
0.00501 = 0.0008 × g
Divide both side by 0.0008
g = 0.00501/0.0008
g = 6.26 m/s²
3. For Metal bolt:
Mass (m) = 79 g
Force (F) = 0.4871 N
Acceleration due to gravity (g) =?
Next, we shall convert 79 g to kg. This can be obtained as follow:
1000 g = 1 kg
Therefore,
79 g = 79/1000
79 g = 0.079kg
Finally, we shall determine the acceleration due to gravity as follow:
Force of gravity (F) = mass (m) x Acceleration due to gravity (g)
F = mg
Mass (m) = 0.079 kg
Force (F) = 0.4871 N
Acceleration due to gravity (g) =?
F = mg
0.4871 = 0.079 × g
Divide both side by 0.079
g = 0.4871/0.079
g = 6.17 m/s²
From the above calculation we obtained the following values for acceleration due to gravity (g):
Object >>>> Acceleration due to gravity
Rock >>>>> 6.12 m/s²
Sand >>>>> 6.26 m/s²
Metal >>>>> 6.17 m/s²
Thus, closest approximation of the acceleration due to gravity of the planet is 6.1 m/s²
Una bala de cañón se dispara horizontalmente con una velocidad inicial de 120m/s y un ángulo de elevación de 35°.Encuentra:a)su alcance maximo,b)si altura máxima,c)si tiempo maximo de vuelo
Answer:
a) x = 1353,2 m.
b) [tex]y_{max}[/tex] = 236,9 m [/tex]
c) [tex]t_{v} = 13,8 s[/tex]
Explanation:
a) El alcance máximo se puede calcular usando la siguiente ecuación:
[tex] y = y_{0} + tan(\theta)*x - \frac{g}{2}*\frac{x^{2}}{(v_{0}cos(\theta))^{2}} [/tex] (1)
En donde:
y: es la altura final = 0
[tex]y_{0}[/tex]: es la altura inicial = 0
x: es el alcance
θ: es el angulo respecto a la horizontal = 35°
[tex]v_{0}[/tex]: es la velocidad inicial = 120 m/s
g: es la gravedad = 10 m/s²
Resolviendo la ecuación (1) para x, tenemos:
[tex] x = \frac{2tan(\theta)*(v_{0}cos(\theta))^{2}}{g} = \frac{2tan(35)*(120 m/s*cos(35))^{2}}{10 m/s^{2}} = 1353,2 m [/tex]
El alcance máximo es 1353,2 m.
b) La altura máxima es:
[tex] y_{max} = \frac{v_{0}_{y}^{2}}{2g} = \frac{(v_{0}sen(\theta))^{2}}{2g} = \frac{(120 m/s*sen(35))^{2}}{2*10 m/s^{2}} = 236,9 m [/tex]
Entonces, la altura máxima es 236,9 m.
c) El tiempo de vuelo es el siguiente:
[tex]t_{v} = \frac{x}{v_{0}cos(\theta)} = \frac{1353,2 m}{120 m/s*cos(35)} = 13,8 s[/tex]
Por lo tanto, el tiempo de vuelo es 13,8 s.
Espero que te sea de utilidad!
A sample of 2 moles of an ideal diatomic gas experiences a temperature increase of 60 K at constant volume. (a) Find the increase in internal energy if only translational and rotational motions are possible. 8.73 103 J (b) Find the increase in internal energy if translational, rotational, and vibrational motions are possible. 0.01222 (c) What fraction of the energy calculated in (b) is translational kinetic energy?
Answer:
A. To find increase in internal energy
We use
CV= f/2* R
=20.77J/molK
So change in internal energy is
nCvdt
So substituting
= 2 x 20.77x 60K
= 2493J
B.
We know that molar specific heat increase by R/2
So CV= (f/2+1)R
Which is 29.1J/milk
So
Increase in internal energy will be
nCvdt
= 2* 29.1*60
= 3490.2J
C. the translational energy is 3/2R
And the total molar specific heat capacity is 7/2R
So the fraction of energy in b due to K.E will be
3/7 * 3490.2
=1495.8J
500 cm³ of water at 100°C is added to another 500 cm³ of water at a temperature of 30°C. Assuming no heat is lost to the surrounding, what is the final temperature of the mixture when thermal equilibrium is achieved?
Answer: 35 degree Celsius
Explanation: Subtract both the temperatures And divide by two.
Highest molecular motion, highest kinetic energy, no forces of attraction, least dense packaging of molecules."Which state of matter is defined by this description?
Answer: Plasma
Explanation:
Plasma is a state of matter that consists of hot ionized gas. It should also be noted that plasma contains negatively charged electrons and positive ions.
Therefore, Highest molecular motion, highest kinetic energy, no forces of attraction, least dense packaging of molecules describes plasma.