The higher temperature will be:
As the temperature is increased from 22°C to a higher temperature, the rate constant increases by a factor of 7.00. The final temperature will be 271.74K.
What is the activation energy?
Activation energy is defined as the extra energy provided required to activate the molecules to start reacting and forming intermediate and later product.
Arrhenius equations given the relation rate constant and activation energy.
[tex]LnK=Ae^{-\frac{E_a}{RT}\\\\[/tex]
Where,
K= Rate constant
A= Pre exponential factor
[tex]E_a=[/tex] Activation energy
When two rate constants are given [tex]K_1\,[/tex] and [tex]\,K_2[/tex]
[tex]ln\frac{K_2}{K_1}=\frac{E_a}{R}(\frac{1}{T_2}-\frac{1}{T_1})[/tex]
Given,
[tex]T_1[/tex] = 22°C = 295K
Rate constant[tex](K_1)[/tex] increases by a factor of 7,i.e, [tex]K_2=7K_1[/tex]
[tex]E_a[/tex]= 54 kJ/mole = 54000 J/mole
R= 8.314 [tex]J\,mol^{-1}K^{-1}[/tex]
Putting the values,
[tex]ln\frac{K_2}{K_1}=\frac{E_a}{R}(\frac{1}{T_2}-\frac{1}{T_1})[/tex]
ln 7 x 8.31454000 = (1/[tex]T_{2}\\[/tex] - 1/295)
0.299 x [tex]10^{-3}[/tex] + 1/295 = 1/[tex]T_{2}[/tex]
0.00368 = 1/[tex]T_{2}[/tex]
[tex]T_{2}[/tex] = 1/0.00368
[tex]T_{2}[/tex] = 271.74 K
Therefore,
The increase in temperature will change from 295K to 271.74K.
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In each of the following substances nah, h2, and h2s, hydrogen is assigned an oxidation number of +1. is this correct? explain your reasoning
No It is not correct.
Correct oxidation number of hydrogen in NaH,H2 and H2S are:
Let x be the Oxidation state of ’H’ by oxidation state rule.x+1 =0 (Sodium has +1 Oxidation state )
x=−1
Therefore, -1 is oxidation number of Hydrogen in NaH.
The oxidation number of an element's atom in its standard state is zero. As a result, the oxidation number for H2 is zero.The hydrogen oxidation number in H2 is +1. As a result, that hydrogen atom can be reduced to lower oxidation states of hydrogen, such as 0 and -1. However, because +1 is the highest oxidation state of hydrogen, the hydrogen atom cannot be reduced any further.What is oxidation number?In simple terms, the oxidation number is the number assigned to elements in a chemical combination. The oxidation number is the number of electrons that atoms in a molecule can share, lose, or gain when forming chemical bonds with atoms of a different element.
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Question 21 of 50
2 points
we would use the elements listed on the bottom of the reactivity list for all of the following except
_______.
a. pans for cooking and baking
b. jewelry
c. fireworks
d. water pipes in the house
The elements listed on the bottom of the reactivity list for all of the following except fireworks and is denoted as option C.
What is Reactivity?This is referred to the extent in which an element is able to take part in a chemical reaction.
The elements founds at the bottom of the reactivity list include gold which can't be used for making fireworks.
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(ii) Calculate the maximum mass of ethanol that could be obtained
g from 30.0 g of glucose.
Taking into account the reaction stoichiometry, 15.33 grams ethanol could be obtained from 30 grams of glucose.
Reaction stoichiometryIn first place, the balanced reaction is:
C₆H₁₂O₆ → 2 C₂H₅OH + 2 CO₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
C₆H₁₂O₆: 1 mole C₂H₅OH: 2 molesCO₂: 2 molesThe molar mass of the compounds is:
C₆H₁₂O₆: 180 g/moleC₂H₅OH: 46 g/moleCO₂: 44 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
C₆H₁₂O₆: 1 mole ×180 g/mole= 180 gramsC₂H₅OH: 2 moles ×46 g/mole= 92 gramsCO₂: 2 moles ×44 g/mole= 88 gramsMass of C₂H₅OH formedThe following rule of three can be applied: if by reaction stoichiometry 180 grams of glucose form 92 grams of ethanol, 30 grams of glucose form how much mass of ethanol?
[tex]mass of ethanol=\frac{30 grams of glucosex 92 grams of ethanol}{180 grams of glucose}[/tex]
mass of ethanol= 15.33 grams
Then, 15.33 grams ethanol could be obtained from 30 grams of glucose.
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A known amount of heat is transferred to a sample of iron and the iron raises its temperature by 4.0 degrees Celsius. What would be the temperature increase if the same amount of heat was transferred to the same mass of water
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part e
drop a single crystal of sodium acetate into the flask. observe the contents of the flask. what happens to the sodium acetate solution in the flask after you drop in the crystal?
Answer:
I dropped a crystal of sodium acetate into the solution it immediately became cloudy again, it became supersaturated.
Explanation:
I used this and scored 100% but if you copy and paste they will flag you for plagiarsm so make sure to rewrite it in your own words.
I dropped a crystal of sodium acetate into the solution it immediately became cloudy again, it became supersaturated.
What is Sodium acetate solution?Chemically known as CH3COONa, sodium acetate is a hygroscopic powder that is very water soluble. The addition of sodium acetate to products like heating pads, food, industries, and concrete is possible.
When administered intravenously, sodium acetate plays a critical role in medicine as an electrolyte replenisher. It is mostly recommended to treat hyponatremic patients' sodium levels. Additionally, it can be used to alkalinize urine and treat metabolic acidosis.
In patients with limited or no oral intake, salt should be added to high volumes of intravenous fluids to prevent or treat hyponatremia. for the patient's needs cannot be addressed by conventional electrolyte or nutrient solutions, it is also helpful as an addition for creating customized intravenous fluid formulas.
Therefore, I dropped a crystal of sodium acetate into the solution it immediately became cloudy again, it became supersaturated.
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The statement, in a mixture of gases, the total pressure is the sum of the individual partial pressures of gases in the mixture paraphrases ________.
Dalton's law
States that the total pressure exerted by a mixture of gases is the sum of the pressures exerted independently by each gas in the mixture.
What is Dalton's law of partial pressure ?Dalton's law, which states that a gas mixture's overall pressure is equal to the sum of its component gases' partial pressures. The pressure that each gas would produce if it occupied the same volume of the mixture by itself at the same temperature is known as the partial pressure.
The pressure that each gas would produce if it occupied the same volume of the mixture at the same temperature alone is referred to as the partial pressure.Learn more about Dalton's law of partial pressure here:
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How many grams of aluminum are required to react with 35 mL of 2.0 M hydrochloric acid, HCl?__ HCl + __ Al --> __ AlCl3 + __ H2
Answer:
0.6258 g
Explanation:
To determine the number grams of aluminum in the above reaction;
determine the number of moles of HCldetermine the mole ratio,use the mole ratio to calculate the number of moles of aluminum.use RFM of Aluminum to determine the grams required.Moles of HCl
35 mL of 2.0 M HCl
2 moles of HCl is contained in 1000 mL
x moles of HCl is contained in 35 mL
[tex]x \: mol \: = \: \frac{2 \: \times \: 35}{1000} \\ = 0.07 \: moles \: [/tex]
We have 0.07 moles of HCl.
Mole ratio
Balanced equation6HCl(aq) + 2Al(s) --> 2AlCl3(aq) + 3H2(g)
Hence mole ratio = 6 : 2 (HCl : Al
but moles of HCl is 0.07, therefore the moles of Al;[tex] = \frac{2}{6} \times 0.07 \\ \: = 0.0233333 \: moles[/tex]
Therefore we have 0.0233333 moles of aluminum.
Grams of Aluminum
We use the formula;
[tex]grams \: = moles \: \times \: rfm[/tex]
The RFM (Relative formula mass) of aluminum is 26.982g/mol.
Substitute values into the formula;
[tex] = 0.0233333 \: moles \: \times \: 26.982 \: \frac{g}{mol} \\ = 0.625799 \: grams[/tex]
The number of grams of aluminum required to react with HCl is 0.6258 g.
A certain mass of nitrogen gas occupies a volume of 8.56 L at a pressure of 3.72 atm. At what pressure will the volume of this sample be 10.94 L
The final pressure of the nitrogen gas with the increase in volume is 2.91 atm.
What is Boyle's Law?Boyle’s law is a gas law that states that the pressure exerted by a gas (of a given mass, kept at a constant temperature) is inversely proportional to the volume occupied by it.
The relation can be given as:
[tex]P_1V_1=P_2V_2[/tex]
The initial pressure of the gas, [tex]P_1[/tex] = 3.72 atm
The initial volume of the gas, [tex]V_1[/tex] = 8.56L
The final volume of the gas, [tex]V_2[/tex] = 10.94 L
Substituting the values, the final pressure [tex]P_2[/tex] is given as:
3.72 × 8.56 = [tex]P_2[/tex] × 10.94
[tex]P_2 =\frac{3.72 * 8.56}{10.94} \\\\P_2 =2.91 atm[/tex]
Therefore, the final pressure of the nitrogen gas with the increase in volume is 2.91 atm.
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Consider the reaction. At 298 K, the equilibrium concentration of O2 is 1.6 x 10-2 M, and the equilibrium concentration of O3 is 2.86 x 10-28 M. What is the equilibrium constant of the reaction at this temperature
The value of the equilibrium constant is 1.99 × [tex]10^-^5^0[/tex] .
Given:
Concentration of [tex]O_2 = 1.6[/tex] × [tex]10^-^2 M\\[/tex]
Concentration of [tex]O_3 = 2.86[/tex] × [tex]10^-^2^8 M[/tex]
A chemical reaction known as an equilibrium reaction occurs when the reactants remain in a stable condition both during and after the reaction.
The given balanced equilibrium reaction is,
[tex]3O_2 (g) = 2O_3 (g)[/tex]
The expression for equilibrium constant will be,
[tex]K_c = \frac{[O_3] ^2}{[O_2]^3}[/tex]
Now put all the given values in this formula, and we get
[tex]K_c = \frac{(2.86 * 10^-^2^8] ^2}{[1.6 * 10 ^-^2]^3}[/tex]
[tex]K_c = 1.99[/tex] × [tex]10^-^5^0[/tex]
Therefore, the value of the equilibrium constant is 1.99 × [tex]10^-^5^0[/tex] .
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I NEED HELP ASAPPPP
Once extracted and purified, 20.0 grams of a pure sample of
substance X is thermally decomposed at 840oC. The two products of this reaction are calcium oxide and carbon dioxide gas. Write a balanced chemical equation and calculate the mass of calcium oxide produced. Show your process.
BALANCED CHEMICAL EQUATION:
PROCESS:
Answer:
11.2 grams CaO
Explanation:
It appears that substance X may be calcium carbonate: CaCO3
CaCO3 can be thermally decomposed to CO2 and CaO in the following balanced reaction:
CaCO3(s) ⇒ CaO(s) + CO2(g) (with applied heat, 840°C)
The molar ratio between the product, CaO, and the reactant, CaCO3, is 1:1. If we start with 1 mole CaCO3, we should produce 1 mole of CaO.
We have 20.0 grams of substance X, which we'll label CaCO3. Calculate the moles of CaCO3 by using its molar mass of 100.1 grams/mole.
20.0 grams/(100.1 grams/mole) = 0.1998 or 0.200 moles of CaCO3.
This should produce, with a molar ratio of 1 to 1, 0.200 moles of CaO
Convert this to grams CaO by multiply by it's molar mass of 56.1 g/mole:
(0.200 moles)*(56.1 g/mole) = 11.2 grams CaO. Any less, then blame it on your lab partner. But don't try taking credit if you have more than 11.2 grams. Scraping debri off the counter into the beaker doesn't count.
When a redox reaction that takes place in an acidic solution involves an oxygen imbalance, oxygen should be balanced by adding _____ as needed, while hydrogen should be balanced by adding _____.
Balancing redox reactions:
Oxygen should be balanced by adding [tex]H_{2}O[/tex] as needed, while hydrogen should be balanced by adding [tex]H^{+}[/tex].
What is a redox reaction?
Redox reactions, also known as oxidation-reduction reactions, involve the simultaneous oxidation and reduction of two different reactants.
The Half-Equation Method is one technique used to balance redox processes. The equation is divided into two half-equations using this technique: one for oxidation and one for reduction.
By changing the coefficients and adding [tex]H_{2}O[/tex], [tex]H^{+}[/tex], and [tex]e^{-}[/tex] in that order, each reaction is brought into equilibrium:
By putting the right number of water ([tex]H_{2}O[/tex]) molecules on the other side of the equation, the oxygen atoms are brought into balance.By adding [tex]H^{+}[/tex] ions to the opposing side of the equation, one can balance the hydrogen atoms (including those added in step 2 to balance the oxygen atom).Total the fees for each side. Add enough electrons ([tex]e^{-}[/tex]) to the more positive side to make them equal. (As a general rule, [tex]e^{-}[/tex] and [tex]H^{+}[/tex]are nearly always on the same side.)The [tex]e^{-}[/tex] on either side must be made equal; if not, they must be multiplied by the lowest common multiple (LCM) in order to make them equal.One balanced equation is created by adding the two half-equations and canceling out the electrons. Additionally, common terms should be eliminated.Now that the equation has been verified, it can be balanced.Learn more about redox reaction here,
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When testing the temperature of catalase, what would happen if you changed the temperature using the same tube with the same catalase and hydrogen oxide mixture?.
The substrate and enzyme would bind and react before all temperatures could be tested.
Before all temperatures could be tested, the enzyme would stop functioning after a short while.
What happens to the substrate and the enzyme?The enzyme and the substrate would bind and the reaction would breakdown hydrogen peroxide into hydrogen and oxygen. Once the majority of the substrate was consumed, the reaction would not proceed even if the enzyme was at the optimal temperature.
Specific substrate binding is a property of enzymes. For example, the enzyme catalase exclusively binds to hydrogen peroxide as a substrate.
The enzyme forms a complex with the substrate when it attaches to its active site, breaking down the substrate into products.
I understand the question you are looking for is this:
When testing the temperature of catalase, what would happen if you changed the temperature using the same tube with the same catalase and hydrogen oxide mixture?
The substrate would stop working after a few minutes before all temperatures could be tested.The enzyme would stop working after a few minutes before all temperatures could be tested.The substrate and enzyme would bind and react before all temperatures could be tested.Learn more about enzymes here:
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How many moles of MgCl₂ are present in 60.0 mL of 0.100 M MgCl₂ solution?
There is 0.0600moles of MgCl2 in 60.0ml of 0.100M MgCl2 solution.
Explanation:
First we need to determine the number of moles of MgCl2 in 60.0L of solution.
After determining the number of moles,now multiply moles of MgCl2 by its Molar mass i.e (95.205g/mol)
We know Molarity= mol of solute/L solution
∴ 0.10 M MgCl2 = 0.10mol MgCl2/L
Step1:
First convert 60.0ml to litres.
1L=1000mL
60.0mL×1L/1000mL=0.0600L
Step2:
To determine moles of MgCl2, multiply 0.0600 L by the molarity of the solution
0.0600L×0.10mL/1L=0.0600mol MgCl2
∴ 0.0600moles of MgCl2 are present in 60.0mL of 0.100M MgCl2 solution.
what is molar mass?Relative molar mass is defined as the smallest mass unit of a compound with one twelfth of the mass of one carbon – 12 atom.
In a substance, the amount of entities present for e.g. atoms, molecules, ions, is defined as a mole. A mole of any substance is 6.022×1023 molecules. Just as we take a standard value to calculate different things e.g. 1 dozen =12 items similarly we use the mole to calculate the size of the smallest entities quantitatively.
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what is molarity?Molarity of a solution is defined as the number of moles of the solute dissolved per litre of the solution. I is represented as \textbf{`M`}. Thus a solution, which contains one gram mole of the the solution dissolved per litre* of the solution is regarded as molarity.
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Hurricanes derive their energy from: Group of answer choices the latent heat of condensation. the latent heat of fusion. the latent heat of sublimation. the latent heat of vaporization.
Hurricanes derive their energy from the Latent heat of condensation.
Hence, Option (1) is correct answer.
What is Latent Heat ?The heat that is released or absorbed during a phase change of a substance is known as Latent heat.
What is Hurricanes ?Hurricanes is basically a type of storm called a tropical cyclone. These are intense low pressure areas. Hurricanes derive their energy from the latent heat of CONDENSATION.
Thus from the above conclusion we can say that Hurricanes derive their energy from the Latent heat of condensation.
Hence, Option (1) is correct answer.
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Provide the organometallic reagent that is needed to perform the transformation shown below. The reagent should be formatted as LiR or BrMgR, where R is an alkyl group written as a Condensed Formula. Do not use subscripts.
The correct answer is [tex]LiCH_{3}CH(CH_{3} )CH_{3}[/tex] .
Organometallic reagentOrganometallic chemistry is the study of organometallic compounds, which are substances that contain at least one chemical bond between a carbon atom from an organic molecule and a metal. These substances include alkali, alkaline earth, and transition metals, as well as metalloids like boron, silicon, and selenium. In addition to links to organyl fragments or molecules, bonds to 'inorganic' carbon, such as those to carbon monoxide (metal carbonyls), cyanide, or carbide, are also typically regarded as organometallic. Although they are not strictly speaking organometallic compounds, some similar compounds, such as transition metal hydrides and metal phosphine complexes, are frequently included in discussions of such substances. The phrase "metalorganic compound," which is comparable but different, describes molecules that contain metals but do not have direct metal-carbon bonds but do have organic ligands.
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If the concentration of fluoride anion and aluminum cation was increased to 5 m, by how much would the measured ecell change?.
If the concentration of fluoride anion and aluminum cation was increased to 5M, then there would be decrease in Ecell by 0.055 volts
The standard reduction potential of Fluoride anion and aluminum cation are -
2Al -----> 2Al3+ + 6e- [tex]E^o[/tex]cell = +1.66
6e- + 3F2 -----> 6F- [tex]E^o[/tex]cell = +2.87
The complete reaction is -
2Al + 3F2 ------> 2Al3+ + 6F- [tex]E^o[/tex] = +4.53
Using Nernst Equation :-
E = [tex]E^o[/tex] – 0.0592/n*log[Al3+]^2[F-]^6
n = 6 (n = number of transferred electrons)
E = +4.53 - 0.0592/6*log(5)^2(5)^6
E = +4.53 - 0.00987*log(25)(1.56 x 10^4)
E = +4.53 – 0.00987*log(3.9 x 10^5)
E = + 4.53 -0.00987(5.59)
E = + 4.53 - 0.055
E = +4.47
The change in Ecell = 5 - 4.47 = 0.055V
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How many carbon monoxide molecules are in 0.75 moles of carbon monoxide?
Answer:
four 0.5 times 10 to the 23rd Adams of Neptune
Explanation:
Answer:
0.75 ( 6.02 × 10²³) = 4.515 x 10²³
Explanation:
0.75 ( 6.02 × 10²³) = 4.515 x 10²³
If 5. 0 grams of kcl is dissolved in 500 ml of water, what is the concentration of the resulting solution?
If 5.0 grams of KCl is dissolved in 500 ml of water, the concentration of the resulting solution will be 0.134M.
How to calculate concentration?The concentration of a solution can be calculated by using the following formula;
Molarity = no of moles ÷ volume
According to this question, 5.0 grams of KCl is dissolved in 500 ml of water. The concentration is calculated as follows:
no of moles of KCl = 5g ÷ 74.5g/mol = 0.067mol
Molarity = 0.067mol ÷ 0.5L = 0.134M
Therefore, if 5.0 grams of KCl is dissolved in 500 ml of water, the concentration of the resulting solution will be 0.134M.
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Entropy A. has a strong odor B. is a measure of correlation between numeric variables C. is used to calculate information gain D. is a measure of information gain
Correct option:
Entropy is used to calculate information gain.
What is entropy?
Entropy is the measure of data's uncertainty or randomness; the greater the randomness, the higher the entropy. Entropy is used by information gain to make choices. Information will increase if the entropy decreases.Decision trees and random forests leverage information gained to determine the appropriate split. Therefore, the split will be better and the entropy will lower the more information gained.Information gain is calculated by comparing the entropy of a dataset before and after a split.Entropy is a way to quantify data uncertainty. The goal is to maximize information gain while minimizing entropy. The method prioritizes the feature with the most information, which is utilized to train the model.Entropy is actually used when you use information gain.Learn more about entropy here,
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what is the formula n²o
Answer:
Nitrous oxide
Explanation:
Nitrous+ Oxygen (ygen becomes -ide when it is combined) = Nitrous oxide
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What amino acid is formed using the n-phthalimidomalonic ester synthesis when the following alkyl halides are used in the third step?.
Threre are two amino acid is formed using the n-phthalimidomalonic ester synthesis when the following alkyl halides are used in the third step -
a. leucine
b. methionine
What is Gabriel malonic ester synthesis?
A reaction that enables us to generate amino acids is the Gabriel synthesis, also referred to as the Gabriel malonic ester synthesis. We can convert primary alkyl halides into primary amines using this procedure. Remember that 19 of the 20 amino acids are actually primary amines.Who should not take methionine?
Supplemental methionine shouldn't be used by people with the genetic condition homocystinuria type I. Methionine can become more homocysteine if you take methionine supplements without getting enough folic acid, vitamin B-6, or vitamin B-12. Your risk of heart disease could rise as a result.What does leucine do in the body?
Leucine is an essential amino acid for protein synthesis. Additionally, similarly to other amino acids, the carbon skeleton of leucine can be used to generate ATP. However, leucine can also regulate several cellular processes such as protein synthesis, tissue regeneration, and metabolism.Learn more about Gabriel malonic ester synthesis
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The complete question is -
What amino acid is formed using the N-phthalimidomalonic ester synthesis when the following alkyl halides are used in the third step?
a. Ch3Ch(Ch3)Ch2-Br
b. Ch3SCh2Ch2-Br
It is a long tube-like canal ,also called alimentary canal where digestion take place.
Explanation:
The alimentary canal is the long tube of organs - including stomaches and intestines
Answer: digestive strat.
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Which law states that the volume of a gas is proportional to the moles of the gas when pressure and temperature are kept constant?
Boyle’s law
Dalton’s law
Charles’s law
Avogadro’s law
The law that states that the volume of a gas is proportional to the moles of the gas when pressure and temperature are kept constant is Avogadro’s law. That is option D.
What is Avogadro’s law?Avogadro’s law states that the volume of a gas is proportional to the moles of the gas when pressure and temperature are kept constant.
Mathematically the Avogadro’s law can be represented by the following:
V1/n1= V2/n1
Where,
V1 = first volume
n1 = first amount of gas
V2 = second volume
n2 = second amount of gas
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Answer:D
Explanation:Trust me bro
Calculate the concentration of a solution if 15 g of salt is added to 170 g of water.
Considering the definition of percentage by mass, the concentration of a solution if 15 g of salt is added to 170 g of water is 8.108 %.
Percentage by massThe percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.
In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.
The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:
[tex]percentage by mass=\frac{mass of solute}{mass of solution}x100[/tex]
Concentration of the solutionIn this case, you know:
mass of solute= 15 gmass of water= 170 gmass of solution= mass of solute + mass of water= 15 + 170 g= 185 gReplacing in the definition of percentage by mass:
[tex]percentage by mass=\frac{15 grams}{185 grams}x100[/tex]
Solving:
percent by mass= 8.108 %
Finally, the concentration of a solution if 15 g of salt is added to 170 g of water is 8.108 %.
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Consider a 175.7 g sample of the compound manganese(IV) perchlorate.
Using the formula Mn(ClO₄)₄ (MM = 452.74), What quantity in moles of oxygen are in 175.7 g of manganese perchlorate?
Answer:
6.21 moles O
Explanation:
To find the moles of oxygen, you need to (1) convert grams Mn(ClO₄)₄ to moles Mn(ClO₄)₄ (via molar mass) and then (2) convert moles Mn(ClO₄)₄ to moles O (via mole-to-mole ratio from formula subscripts). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units.
Molar Mass (Mn(ClO₄)₄): 452.74 g/mol
1 Mn(ClO₄)₄ = 1 Mn and 4 Cl and 16 O
175.7 g Mn(ClO₄)₄ 1 mole 16 moles O
--------------------------- x ------------------- x --------------------------- = 6.21 moles O
452.74 g 1 mole Mn(ClO₄)₄
One type of acid-base buffer is composed of a weak , which will react with any added base, and its conjugate , which will react with any added acid.
One type of acid-base buffer is composed of a weak acid , which will react with any added base, and its conjugate base, which will react with any added acid.
The buffer's weak base and strong acid combine to form a weak acid, which changes the pH only little and releases few H ions into solution.
What is a Buffer solution ?A weak acid and the conjugate base of the weak acid, or a weak base and the conjugate acid of the weak base, are combined to form the buffer solution, a water-based solvent solution.
They withstand being diluted or having modest amounts of acid or alkali added to them without changing their pH.In order to maintain the moderate pH, buffers act by neutralising any additional acid (H+ ions) or base (OH- ions), making them a weaker acid or base.Learn more about Buffer solution here:
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At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. What partial pressure (in atm) of He would give a solubility of 0.200 M
At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the partial pressure of He would give a solubility of 0.200 M.
What is Henry's Law ?Henry's Law is a gas law states that at a constant temperature the amount of gas that dissolved in a liquid is directly proportional to the partial pressure of that gas.
What is relationship between Henry's Law constant and Solubility ?The solubility of gas is directly proportional to partial pressure.
It is expressed as:
[tex]S_{\text{gas}} = K_{H} P_{\text{gas}}[/tex]
where,
[tex]S_{\text{gas}}[/tex] = Solubility of gas
[tex]K_{H}[/tex] = Henry's Law constant
[tex]P_{\text{gas}}[/tex] = Partial pressure of gas
Now put the values in above expression we get
[tex]S_{\text{gas}} = K_{H} P_{\text{gas}}[/tex]
0.080M = [tex]K_{H}[/tex] × 1.7 atm
[tex]K_{H} = \frac{0.080\ M}{1.7\ \text{atm}}[/tex]
= 0.047 M/atm
Now we have to find the partial pressure of He
[tex]S_{\text{gas}} = K_{H} P_{\text{gas}}[/tex]
0.200 M = 0.047 M/atm × [tex]P_{\text{gas}}[/tex]
[tex]P_{\text{gas}} = \frac{0.200 M}{0.047\ \text{M/atm}}[/tex]
= 4.25 atm
Thus from the above conclusion we can say that At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the partial pressure of He would give a solubility of 0.200 M.
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Regions in the human genome where one nucleotide has been substituted for another in at least 1% of the population are called:_______
Regions in the human genome where one nucleotide has been substituted for another in at least 1% of the population are called single nucleotide polymorphism
What are nucleotides?Nucleotide can simply be defined as the basic building block of nucleic acids either RNA and DNA
Generally, nucleotides consists of a sugar molecule (either ribose in RNA or deoxyribose in DNA) attached to a phosphate group and a nitrogen-containing base.
A region is any considerable and connected part of a space or surface; specifically, a tract of land or sea of considerable but indefinite extent, a country, a district, in a broad sense, a place without special reference to location or extent but viewed as an entity for geographical, social or cultural reasons.
So therefore, regions in the human genome where one nucleotide has been substituted for another in at least 1% of the population are called single nucleotide polymorphism.
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Which halogen or halogen-containing compound is typically used as a form of topical antisepsis?
The halogen or halogen-containing compound is typically used as a form of topical antisepsis will be "iodophor".
Iodine will be employed as an antiseptic in the manner of a tincture of iodine, essentially an alcoholic solution.
Iodophor would be an iodine-containing solution that also contains a solubilizing agent, like povidone or a surfactant. Iodophor would be a common sanitizer in the dairy but also brewing sectors. Generally, a high molecular weight carrier, commonly a polymer, has been polymerized with iodine.
Therefore, the halogen or halogen-containing compound is typically used as a form of topical antisepsis will be "iodophor".
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when in extinguishing agent is determined to be safe and effective for you from combustible Metals it will
Dry powder extinguishers
They are for Class D or combustible metal fires, only. They are ineffective on all other classes of fires.
What is an Extinguishing agent ?Extinguishing Agent means a source of extinguishment in which to quickly and effectively suppress the fire.
They consist of ABC Dry Chemical, BC Dry Chemical, Dry Powder, Water, Foam, Wet Chemical, Halogenated, and Carbon Dioxide. Dry Chemical extinguishers: Dry chemical extinguishers are the most common and available in few types.Learn more about Extinguishing agent here:
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