The data of the customer responses would be classified as ordinal data.
What is ordinal data?Ordinal data is a category of categorical data that has a predetermined order or scale. Ordinal data, for instance, is said to have been gathered when a respondent rates their level of financial contentment on a scale from 1 to 10. There is no established scale for measuring the variance of each score in ordinal data.
Ordinal data is a categorical statistical data type when the distances between the categories are unknown and the variables have naturally occurring, ordered categories. On an ordinal scale, these data are available. By having a ranking, the ordinal scale differs from the nominal scale.
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Express each of the following subsets with bit strings (of length 10) where the ith bit (from left to right) is 1 if i is in the subset and zero otherwise.
Subsets with bit strings:
001110000010100100010111001110What are subsets?A set A is a subset of a set B if all of its items are also elements of B; B is, therefore, a superset of A. A and B can be equal; if they are unequal, then A is a legitimate subset of B. Inclusion refers to the relationship of one set being a subset of another.To find the subsets with bit strings:
We need to express a) b) and c) into bit strings.
Firstly, a number of elements in the universal set represent the number of bits in the bit string.
Secondly, 1 = yes element is present in both universal sets as well as in subset.
0 = No, the element is not present in the subset but present in the universal set.
Hence, we have:
a) Subset {3,4,5} = 0011100000 (As there are 3 1's which means only 3,4,5 are present in both universal set and subset.
Similarly,
b) Subset {1, 3, 6, 10} = 1010010001
c) Subset {2, 3, 4, 7, 8, 9} = 0111001110
Therefore, Subsets with bit strings:
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Complete question:
Suppose that the universal set is U={1,2,3,4,5,6,7,8,9,10}. Express each of the following subsets with bit strings (of length 10) where the ith bit (from left to right) is 1 if i is in the subset and zero otherwise.
a) {3, 4, 5}
b) {1, 3, 6, 10}
c) {2, 3, 4, 7, 8, 9}.
A punch recipe calls for mixing 2 parts of cranberry juice with 5 parts of apple juice
The proportion cranberry juice should be mixed with 84 ounces of apple juice 1:5 that is 1 parts of cranberry juice and 5 parts of lemon juice.
According to the question,
A punch recipe calls for mixing 2 parts of cranberry juice with 5 parts of apple juice.
84/2 = 42
5*42=210
Hence, the proportion cranberry juice should be mixed with 84 ounces of apple juice 1:5 that is 1 part of cranberry juice and 5 parts of lemon juice.
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Select the correct answer. A circle with center O (0,0) has point B (4,5) on its circumference, which is joined by a line to O. What is the general form of the equation for the given circle centered at O(0, 0)? A. x2 + y2 + 41 = 0 B. x2 + y2 − 41 = 0 C. x2 + y2 + x + y − 41 = 0 D. x2 + y2 + x − y − 41 = 0
The general form of the equation for the given circle centered at O(0, 0) is x^2 + y^2 = 41
How to determine the general form of the equation for the given circle centered at O(0, 0)?The given parameters are
Center = (0, 0)
Point = (4, 5)
Rewrite the given parameters are
(a, b)= (0, 0)
(x, y) = (4, 5)
The general form of the equation for the given circle is represented as:
(x - a)^2 + (y - b)^2 = r^2
Substitute the known values in the above equation to calculate the radius r
(4 - 0)^2 + (5 - 0)^2 = r^2
Evaluate the difference
4^2 + 5^2 = r^2
Evaluate the exponent
16 + 25 = r^2
Evaluate the sum
41= r^2
Rewrite as
r^2 = 41
Substitute r^2 = 41 in (x - a)^2 + (y - b)^2 = r^2
(x - a)^2 + (y - b)^2 = 41
Substitute (a, b)= (0, 0) in (x - a)^2 + (y - b)^2 = 41
(x - 0)^2 + (y - 0)^2 = 41
Evaluate the difference
x^2 + y^2 = 41
Hence, the general form of the equation for the given circle centered at O(0, 0) is x^2 + y^2 = 41
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i need a detailed explanation
The equation of the line in explicit form is y = - 2 · x + 5, whose implicit form is 2 · x + y = 5. (Correct choice: D)
How to find the equation of the line for the height of a triangle
In this question we must find the equation of the line perpendicular to the segment BC and that goes through the point A(x, y) = (1, 3). First, the slope of the line segment BC is:
m = [1 - (- 3)]/[5 - (- 3)]
m = 4/8
m = 1/2
And the slope of the line is:
m' = - 1/(1/2) = - 2
The intercept of the line is found by using the explicit form of equation of the line, m' = - 2 and (x, y) = (1, 3):
3 = - 2 · 1 + b
b = 5
The equation of the line in explicit form is y = - 2 · x + 5, whose implicit form is 2 · x + y = 5. (Correct choice: D)
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Give the center and radius of a circle with the equation: (x+1)²+(y-2)²=100
A-The center is (-1. 2) and the radius is 10
B-The center is (1, -2) and the radius is 50
C- The center is (1, -2) and the radius is 10
D- The center is (-1, 2) and the radius is 50
OPTION A is the correct answer
Your family is going on vacation for two nights. You don't want to spend more than $135 on a hotel room for your vacation. Write an inequality to represent how much you can spend each night on your hotel room.
Answer:
x ≤ 135/2
Step-by-step explanation:
x is the cost per night. You have to pay for 2 nights, and you do not want to spend more than $135 total. Another way to say that, is you want to spend less than or equal to $135.
x = cost per night
2 = number of nights
2x = total cost
Total cost must be less than or equal to $135.
2x ≤ 135
Divide each side by 2.
x ≤ 135/2
There is a total of 32 cubic centimeters of a liquid in two beakers. one of these beakers contains 15 cubic centimeters of the liquid. how much liquid does the other beaker contain? a. 13 cc b. 15 cc c. 16 cc d. 17 cc
The correct option is (d).
The other beaker contains 17 cc (cubic centimetres) of the liquid.
What is cubic centimetres of liquid mean?The volume of a cube with dimensions of 1 cm ×1 cm× 1 cm is equal to one cubic centimetre (or cubic centimetre in US English) (SI unit symbol: cm³; non-SI abbreviations: cc and ccm). A millilitre's volume is equal to one cubic centimetre.
According to the question,
The total liquid is 32 in cubic centimetres which is stored in the two beakers.
In the first beaker the liquid stored is 15 cubic centimetres.
The second beaker will contain the liquid = total liquid stored in both beakers - liquid stored in the first beaker.
Liquid in second beaker = 32 - 15
= 17
Therefore, the liquid stored in the second beaker is 17 cc (cubic centimetres).
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A man mows his 100 ft by 200 ft rectangular lawn in a spiral pattern starting from the outside edge. After a bit of hard work he stops for a water break, he is 40.5% done. How wide of a strip has he mowed around the outside edge
Based on the length and width of the rectangular lawn, and the percentage the man has mowed, the strip width would be 40.5 m.
what is the width of the strip mowed already?first, find the area of the lawn:
= 100 x 200
= 20,000 ft²
the area mowed is:
= 40.5% x 20,000
= 8,100 ft²
the width is therefore:
= 8,100 / 200
= 40.5 m
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Anyone know?? I’d appreciate it.
[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Here we go ~
[tex]\qquad \sf \dashrightarrow \: (1.6 \times 10 {}^{5} ) \sdot(2 .3 \times {10}^{1} )[/tex]
[tex]\qquad \sf \dashrightarrow \: (1.6 \times 2.3) \sdot(10 {}^{5} \times 10 {}^{1} )[/tex]
[tex]\qquad \sf \dashrightarrow \: 3.68 \times 10 {}^{6} [/tex]
Find the domain and range of the exponential function h(x) = 125 x .
Explain your findings.
As x decreases, does h increase or decrease? Explain.
As x increases, does h increase or decrease? Explain.
The domain of the exponential function given is the set of all real numbers while the range of the exponential function is the set of all real numbers greater than zero.
What is the domain and range of the exponential function?As with other exponential functions, it follows that the domain of the exponential function given is the set of all real numbers while the range of the exponential function is the set of all real numbers greater than zero.
Additionally, by observation, the function has a positive variable correlation, hence;
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8.
P₁V₁ = P₂V₂
T₁ T₂
Rewrite this expression to find T₂.
Answer:
[tex]T_{2} = \frac{P_{2} V_{2} T_{1}} {P_{1} V_{1}}[/tex]
Step-by-step explanation:
The Combined Gas Law expression is:
P₁V₁ / T₁ = P₂V₂ / T₂
To solve for T₂, you need to.....
[tex]\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }[/tex] <------ Original expression
[tex]\frac{T_{2} P_{1} V_{1} }{T_{1} } = {P_{2} V_{2} }[/tex] <----- Multiply both sides by T₂
[tex]{T_{2} P_{1} V_{1} } = {P_{2} V_{2} T_{1}}[/tex] <----- Multiply both sides by T₁
[tex]T_{2} = \frac{P_{2} V_{2} T_{1}} {P_{1} V_{1}}[/tex] <----- Divide both sides by P₁V₁
deeksha made cuboid of size 2 cm x 3 cm x 4 cm. how many such
cuboids will be required to make a cube?
b) in a right triangle pqr,
The number of cuboids of dimension 2 cm x 3 cm x 4 cm, required to make a cube is 9.
Dimensions of the cuboid Deeksha made are given as 2 cm x 3 cm x 4 cm.
Thus, the volume of this cuboid = 2*3*4 cm³ = 24 cm³.
Using the formula for the volume of cuboid as the product of the three sides.
Deeksha wants to make a cube combining some number of these cuboids.
Assuming the side length of the cube to a, the volume of the cube = a³.
Assuming the number of cuboids required to make 1 cube to be n, we can write that a³ = n*(24 cm³).
To make this relation true, we need the right-hand side to be a perfect cube.
Prime factorizing the volume of the cuboid, we get 24 cm³ = 2³ * 3 cm³.
To make it a perfect cube, we need to multiply 3², by it.
Thus, n = 3² = 9.
Thus, the number of cuboids of dimension 2 cm x 3 cm x 4 cm, required to make a cube is 9.
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The provided question is incorrect. The correct question is:
"Deeksha made cuboid of size 2 cm x 3 cm x 4 cm. how many such
cuboids will be required to make a cube?"
What is the domain and range of the following graph?
Using it's concepts, the domain and the range of the graph are given as follows:
Domain: all real values except x = -1.Range: All real values.What are the domain and the range of a function?The domain of a function is the set that contains all the values of the input. In a graph, it is given by the values of x, which is the horizontal axis of the graph.The range of a function is the set that contains all the values of the output. In a graph, it is given by the values of y, which is the vertical axis of the graph.In this graph, have that the function is defined for all values of x except x = -1, and assumes all real values, hence the domain and the range of the graph are given as follows:
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PLEASE I NEED HELP ASAP
The question is :
Danielle reflects shape S in the line x = - 1 , and then reflects the new shape in the line y = 2
Zachary reflects shape S in the line y = 2 , and then reflects the new shape in the line x = - 1
Work out the coordinates of the vertex that A maps to after
a) Danielle's two reflections.
b) Zachary's two reflections.
.
The coordinates of the vertex that A maps to after Daniel's reflections are (3, 4) and the coordinates of the vertex that A maps to after Zachary's reflections are (3, 2)
How to determine the coordinates of the vertex that A maps to after the two reflections?From the given figure, the coordinate of the vertex A is represented as:
A = (-5, 2)
The coordinates of the vertex that A maps to after Daniel's reflections
The rule of reflection across the line x = -1 is
(x, y) ⇒ (-x - 2, y)
So, we have:
A' = (5 - 2, 2)
Evaluate the difference
A' = (3, 2)
The rule of reflection across the line y = 2 is
(x, y) ⇒ (x, -y + 4)
So, we have:
A'' = (3, -2 + 4)
Evaluate the difference
A'' = (3, 4)
Hence, the coordinates of the vertex that A maps to after Daniel's reflections are (3, 4)
The coordinates of the vertex that A maps to after Zachary's reflections
The rule of reflection across the line y = 2 is
(x, y) ⇒ (x, -y + 4)
So, we have:
A' = (-5, -2 + 4)
Evaluate the difference
A' = (-5, 2)
The rule of reflection across the line x = -1 is
(x, y) ⇒ (-x - 2, y)
So, we have:
A'' = (5 - 2, 2)
Evaluate the difference
A'' = (3, 2)
Hence, the coordinates of the vertex that A maps to after Zachary's reflections are (3, 2)
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If you are given a table of values, how can you determine if a direct variation exists?
Answer:
If you divide it out and it comes out a whole number unless the original set of numbers is a fraction
Concrete blocks are 8in. high. if a 3/8-in. mortar joint is used, how high will a wal of 12 courses of concrete blocks be?
Answer:
100.5 inches
Step-by-step explanation:
If each course has 3/8 inch of concrete below it (including the bottom one)
8 in * 12 + 3/8 in * 12 = 100 1/2 inches
Which function in vertex form is equivalent to f(x) = x² + x +1?
○ f(x) = (x + 1/ 1³² + 1 ²1/0
3
4
○ f(x) = (x + 1)² + 2/1/2
○ f(x) = (x + ²/2 1²³ + ²/
4
5
f(x) = (x + 1/2-1² + ²/1/2
4
Answer:
[tex]\left( x+\frac{1}{2} \right)^{2} + \frac{3}{4}[/tex]
Step-by-step explanation:
NOTE :
[tex]x^2+ax=\left( x+\frac{a}{2} \right)^{2} -\left( \frac{a}{2} \right)^{2}[/tex]
………………………………………
f(x) = x² + x +1
[tex]=x^{2}+2\times \frac{x}{2} +1[/tex]
[tex]=\left( x+\frac{1}{2} \right)^{2} -\left( \frac{1}{2} \right)^{2} +1[/tex]
[tex]=\left( x+\frac{1}{2} \right)^{2} - \frac{1}{4}+1[/tex]
[tex]=\left( x+\frac{1}{2} \right)^{2} + \frac{3}{4}[/tex]
a machine makes 36 widgets in 20 minutes. at that rate, how many widgets will the machine make in an 8-hour day?
Consider the three functions:
f(x) = Three-halves(4)x g(x) = Three-halves(4)–x h(x) = –Three-halves(4)x
Which statements are true about the domain and range of f(x), g(x), and h(x)? Check all that apply.
f(x) has a domain of all real numbers.
g(x) has a range of y < 0.
h(x) has a range of y > 0.
g(x) has a domain of all real numbers.
h(x) has a domain of x > 0.
The statements that are true about the domain and range of the functions f(x), g(x), and h(x) include:
f(x) has a domain of all real numbers.g(x) has a domain of all real numbers.What is a function?It should be noted that a function simply means a relation between a set of inputs to a set of possible outputs.
In this case, f(x) has a domain of all real numbers as well as g(x) which also has a domain of all real numbers.
In conclusion, the correct options are A and D.
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Answer:
A and D
Step-by-step explanation:
Edge 2022
11y^2-xy dxUse the method for solving homogeneous equations to solve the following differential equation.
The solution to the homogenous differential equation, (11y² - xy)dx + x²dy = 0, is [tex]y = \frac{x}{11 ln (x) + C}[/tex].
A homogeneous differential equation has a homogeneous function as one of its components, if f(λx, λy) = λⁿf(x, y), for any non-zero constant λ, the function is said to be homogenous. The homogeneous differential equation's generic form is of the type f(x, y).dy + g(x, y).dx = 0. The degree of the homogeneous differential equation is the same for the equation's variables x and y.
In the question, we are asked to solve the homogeneous differential equation, (11y² - xy)dx + x²dy = 0.
The given equation can be solved as follows:
Grouping by differentials, gives us: x²dy = (xy - 11y²)dx.We now substitute, u = yx, making y = ux, or, dy = u.dx + x.du.Making the substitutions, we get: x²(u.dx + x.du) = (u - 11u²)x²dx.Expanding the parentheses, we get: ux².dx + x³.du = ux².dx - 11u²x².dx.Reducing ux².dx, we get: x³.du = -11u²x².dx.Dividing by x³ and u², we get du/u² = -11/x.Now, we integrate both sides of the equation: [tex]\int \frac{1}{u^2}du = \int -\frac{11}{x}dx[/tex]Calculating the resulting integrals, we get: -1/u = C - 11 ln(x).Undoing the substitution, u = y/x, we get: -x/y = C - 11 ln(x)The final solution is: [tex]y = \frac{x}{11 ln (x) + C}[/tex]Thus, the solution to the homogenous differential equation, (11y² - xy)dx + x²dy = 0, is [tex]y = \frac{x}{11 ln (x) + C}[/tex].
The provided question is incomplete. The complete question is:
"Use the method for solving homogenous equations to solve the following differential equation.
(11y² - xy)dx + x²dy = 0".
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Geometric Series
It has 6 terms, increases by a factor of 4, and has a sum of 1365. Find the value of the first term.
Since the geometric series has 6 terms, increases by a factor of 4, and has a sum of 1365, the value of the first term is 1.
What is the sum of a geometric series?The sum of a geometric series is given by
Sₙ = a(rⁿ - 1)/(r - 1) with r > 1 where
n = number of terms, a = first term and r = common ratioNow, since our Geometric Series has 6 terms, n = 6. Also, it increases by a factor of 4, so, r = 4 and has a sum of 1365, so Sₙ = 1356. So,we have that
n = 6, Sₙ = S₆ = 1365 andr = 4The value of the first termSince we require the first term, a , making a subject of the formula, we have
a = Sₙ(r - 1)/(rⁿ - 1)
Substituting the values of the variables into the equation, we have
a = Sₙ(r - 1)/(rⁿ - 1)
a = S₆(r - 1)/(r⁶ - 1)
a = 1365(4 - 1)/(4⁶ - 1)
a = 1365(3)/(4096 - 1)
a = 4095/4095
a = 1
So, the value of the first term is 1.
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Does anyone know how to do this
Considering the area of the rectangle, we have that the length is of 8 units and the width is of 10 units.
What is the area of a rectangle?The area of a rectangle of length l and width w is given as follows:
A = lw.
In this problem, the area is of 80 square units, while the length and the width are consecutive even integers, hence:
A = 80.w = l + 2.Then:
l(l + 2) = 80
l² + 2l - 80 = 0
(l + 10)(l - 8) = 0.
We need the positive measure, hence:
l - 8= 0 -> l = 8 units.
w = l + 2 = 10 units.
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y=x+3
y=-x-1
i need to find the solution of equations
Answer:
[tex]\huge\boxed{\sf \{(-2,1)\}}[/tex]
Step-by-step explanation:
Given equations:
y = x + 3
y = -x - 1
By comparing the above equations, we get:
x + 3 = -x - 1
Add x to both sides
x + x + 3 = -1 2x + 3 = -1Subtract 3 to both sides
2x = -1 - 3
2x = -4
Divide 2 to both sides
x = -4/2
x = -2Substitute x = -2 in first equation.
y = x + 3
y = -2 + 3
y = 1So,
Solution Set = {(x,y)}={(-2,1)}[tex]\rule[225]{225}{2}[/tex]
Answer:
[tex]x = - 2 \\ y = 1[/tex]
Step-by-step explanation:
The above are Simultaneous equations.
What are Simultaneous equations?Simultaneous equations are two or more algebraic equations which share same variables like X,Y or X,Y and Z.
They are called simultaneous equations because they can be solved the same time.
From the question,
[tex]y = x + 3 - - - - - - (1) \\ y = - x - 1 - - - - - - (2) \\ Substitute \: equation \: (2)into \: (1) \\ - x - 1 = x + 3 \\ Collect \: liketerms \\ - x - x = 3 + 1 \\ - 2x = 4 \\ Divide \: bothsides \: by \: - 2 \\ \frac{ - 2x}{ - 2} = \frac{4}{ - 2} \\ x = - 2 \\ Substitute \: the \: value \: of \: x \: into \: equation \: (1) \\ y = x + 3 \\ y = - 2 + 3 \\ y = 1 \\ Therefore \: x = - 2 \: \: and \: y = 1[/tex]
each of 16 students in a class made a poetry book. each book contained 24 poems. how many poems are in 16 books
Solve the following:
-5² + 10²
(2 × (-5) × 3) + 3³
Give your answer in simplest form.
Please help me with this
Answer:A or C
Step-by-step explanation: i guessed plus 19 hours ago
Find the missing side length of the triangle.
SOLUTION :
c² = 5² + 5²
c² = 25 + 25
c² = 50
c = √50 ft
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The vertex of a parabola is (0,0)and the focus is (1/8, 0) . What is the equation of the parabola?
The equation of a parabola whose vertex is (0, 0) and focus is (1 / 8, 0) is equal to x = 2 · y².
How to derive the equation of the parabola from the locations of the vertex and focus
Herein we have the case of a parabola whose axis of symmetry is parallel to the x-axis. The standard form of the equation of this parabola is shown below:
(x - h) = [1 / (4 · p)] · (y - k)² (1)
Where:
(h, k) - Coordinates of the vertex.p - Distance from the vertex to the focus.The distance from the vertex to the focus is 1 / 8. If we know that the location of the vertex is (0, 0), then the standard form of the equation of the parabola is:
x = 2 · y² (1)
The equation of a parabola whose vertex is (0, 0) and focus is (1 / 8, 0) is equal to x = 2 · y².
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Write an equation of a line in slope intercept form going through the points (1,6) and (3,0)
Answer:
y = -3x + 9
Step-by-step explanation:
The slope is
[tex] \frac{6 - 0}{1 - 3} = - 3[/tex]
Substituting into point-slope form, we get
y = -3(x-3)
y = -3x + 9
Volume=
Help me please!! Asap thanks so much
The volume of the oblique cylinder is 6867.18 cubic units
How to determine the volume?The given parameters are:
Height = 27
Radius = 9
The volume is calculated as:
[tex]V = \pi r^2 h[/tex]
So, we have:
[tex]V = 3.14 * 9^2 * 27[/tex]
Evaluate
V = 6867.18
Hence, the volume of the oblique cylinder is 6867.18 cubic units
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