Answers
Answer:
f(1) = -2
f(x) =1 when x=0 or x=-2
Step-by-step explanation:
f(1) is the y value when x=1
f(1) = -2
f(x) = 1 means find the x value when y=1
when y =1, x =0 and -2
Related Questions
Within what values will 95.44 percent of sample means of this process fall, if samples of n = 8 are taken and the process is in control (random)?
Answers
This question is incomplete, here is the complete question:
Specifications for a part for a DVD player state that the part should weigh between 25.2 and 26.2 ounces. The process that produces the parts has a mean of 25.7 ounces and a standard deviation of .25 ounce. The distribution of output is normal. Use Table-A
a) What percentage of parts will not meet the weight specs? (Round your "z" value and final answer to 2 decimal places.
b) Within what values will 95.44 percent of sample means of this process fall, if samples of n = 8 are taken and the process is in control (random)
Answer:
a) What percentage of parts will not meet the weight specs = 4.56%
b) values within which 95.44 percent of sample means of this process falls are;
UCL = 25.88 ounces
LCL = 25.52 ounces
Step-by-step explanation:
Given that;
Mean u = 25.7 ounces
Std deviation = 0.25 ounces
a)
Z-score (Upper) = (X- u) / s = (26.2 - 25.7) / 0.25 = 2
Z-score (Lower) = ( 25.2-25.7 ) / 0.25 = -2
using the T - table
For Z = 2.0
the area in the tail of the curve to the right of the mean (upper) = 0.4772
therefore;
Number of defective = 0.5000 - 0.4772 = 0.0228
These are errors on one side of normal distribution.
To get the total error, we say
Total error = 2 × 0.0228
Total error = 0.0456 ≈ 4.56% ( 2 decimal place )
b)
given that;
n = 8,
standard deviation = 0.25 ounce
Standard deviation of X = Std deviation / √n
= 0.25 /√8 = 0.088
Now for 95.44% of confidence interval, Z = 2
UCL = Mean + Z × Standard deviation of X
= 25.7 + 2 × 0.088
= 25.88 ounces
LCL = Mean - Z × Standard deviation of X
= 25.7 - 2 × 0.088
= 25.52 ounces
Find the surface area of the solid given the net.
Answers
Answer:
288
Step-by-step explanation:
Area of two triangles=2(½bh)
=bh
=8×6
=48
For the rectangles=lb + lb +lb
l(b+b+b)
=12(8+6+6)
=12×20
=240
Total area=240 +48=288
which artistic tradition was founded by Masaccio
Answers
Answer:
Renaissance Naturalism
Step-by-step explanation:
just took the quiz
At the beginning of March, a store bought a fancy watch at a cost of $250 and marked it up 20%. At the end of the month, the fancy watch had not sold, so the store marked it down 10%. What was the discounted price?
Answers
Answer:
$270
Step-by-step explanation:
Price after markup was 1.20($250) = $300
Price after discounting: (1.00 - 0.10)($300) = $270
Find the distance between the points. Give an exact answer and an approximation to three decimal places.
TI
(S.
(3.1, 0.3) and (2.7, -4.9)
Th
(Rd
Answers
Answer:
5.215 units (rounded up to three decimal places)
Step-by-step explanation:
To find the distance between points (3.1 , 0.3) and (2.7, -4.9)
We use the Pythagoras Theorem which states that for a right triangle of sides a,b and c then;
a² + b² = c² , Where c is the hypotenuse.
In our case, the distance between the two points is the hypotenuse of triangle formed by change in y-axis and change in x-axis.
The distance (hypotenuse) squared = (-4.9 - 0.3)² + (2.7 - 3.1)² = 27.04 + 0.16 = 27.2
Hypotenuse (the distance between) = [tex]\sqrt{27.2}[/tex] = 5.215 units (rounded up to three decimal places)
find the 5th term in the sequence an=n÷n+1
Answers
Answer:
The 5th term of a sequence is defined as the term with n = 5. So for this sequence, a sub 5 = 5/6
heeeeeeeeelpppppppppppp
Answers
Answer:
1). x = 2.67 units
2). x = 4.80 units
3). x = 6.00 units
Step-by-step explanation:
1). By applying Pythagoras theorem,
Hypotenuse² = [Leg(1)]² + [leg(2)]²
12² = x² + b² [Let the base of both the triangles = b units]
144 = x² + b² ------(1)
Similarly, 13² = (x + 3)² + b²
169 = x² + 6x + 9 + b²
169 - 9 - 6x = x² + b²
160 - 6x = x² + b² ------(2)
From equation (1) and (2)
144 = 160 - 6x
6x = 160 - 144
x = [tex]\frac{16}{6}[/tex]
x = 2.67 units
2). By applying Pythagoras theorem,
10² = x² + h² [Let the height of the triangle = h]
100 = x² + h² ------(1)
13² = (2x)² + h²
169 = 4x² + h² -----(2)
By substituting equation (1) from equation (2),
169 - 100 = (4x² + h²) - (x² + h²)
69 = 3x²
x² = 23
x = √23
x = 4.795
x ≈ 4.80 units
3). By applying Pythagoras theorem,
9² = x² + h² [Let the height of the triangle = h units]
81 = x² + h² ------(1)
7² = (x - 4)² + h²
49 = x² + 16 - 8x + h²
49 - 16 = x² + h² - 8x
33 + 8x = x² + h² -------(2)
From equation (1) and (2)
81 = 33 + 8x
8x = 48
x = 6.00 units
Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) f(x) = 8x3 − 12x2 − 48x
Answers
Answer:
(2, -1)Step-by-step explanation:
Given the function f(x) = 8x³ − 12x² − 48x, the critical point of the function occurs at its turning point i,e at f'(x) = 0
First we have to differentiate the function as shown;
[tex]f'(x)= 3(8)x^{3-1}- 2(12)x^{2-1} - 48x^{1-1}\\ \\f'(x) = 24x^2 - 24x-48x^0\\\\f'(x) = 24x^2 - 24x-48\\\\At \ the\turning\ point\ f'(x)= 0\\24x^2 - 24x-48 = 0\\\\\\[/tex]
[tex]Dividing \ through \ by \ 24\\\\x^2-x-2 = 0\\\\On \ factorizing\\\\x^2-2x+x-2 = 0\\\\x(x-2)+1(x-2) = 0\\\\(x-2)(x+1) = 0\\\\x-2 = 0 \ and \ x+1 = 0\\\\x = 2 \ and \ -1[/tex]
Hence the critical numbers of the function are (2, -1)
A triangular lamina has vertices (0, 0), (0, 1) and (c, 0) for some positive constant c. Assuming constant mass density, show that the y-coordinate of the center of mass of the lamina is independent of the constant c.
Answers
The equation of the line through (0, 1) and (c, 0) is
y - 0 = (0 - 1)/(c - 0) (x - c) ==> y = 1 - x/c
Let L denote the given lamina,
L = {(x, y) : 0 ≤ x ≤ c and 0 ≤ y ≤ 1 - x/c}
Then the center of mass of L is the point [tex](\bar x,\bar y)[/tex] with coordinates given by
[tex]\bar x = \dfrac{M_x}m \text{ and } \bar y = \dfrac{M_y}m[/tex]
where [tex]M_x[/tex] is the first moment of L about the x-axis, [tex]M_y[/tex] is the first moment about the y-axis, and m is the mass of L. We only care about the y-coordinate, of course.
Let ρ be the mass density of L. Then L has a mass of
[tex]\displaystyle m = \iint_L \rho \,\mathrm dA = \rho\int_0^c\int_0^{1-\frac xc}\mathrm dy\,\mathrm dx = \frac{\rho c}2[/tex]
Now we compute the first moment about the y-axis:
[tex]\displaystyle M_y = \iint_L x\rho\,\mathrm dA = \rho \int_0^c\int_0^{1-\frac xc}x\,\mathrm dy\,\mathrm dx = \frac{\rho c^2}6[/tex]
Then
[tex]\bar y = \dfrac{M_y}m = \dfrac{\dfrac{\rho c^2}6}{\dfrac{\rho c}2} = \dfrac c3[/tex]
but this clearly isn't independent of c ...
Maybe the x-coordinate was intended? Because we would have had
[tex]\displaystyle M_x = \iint_L y\rho\,\mathrm dA = \rho \int_0^c\int_0^{1-\frac xc}y\,\mathrm dy\,\mathrm dx = \frac{\rho c}6[/tex]
and we get
[tex]\bar x = \dfrac{M_x}m = \dfrac{\dfrac{\rho c}6}{\dfrac{\rho c}2} = \dfrac13[/tex]
The center of mass for a uniform triangular shape is on its centroid. The y-coordinate of the center of mass of the lamina is 1/3 (independent of c).
What is the center of mass for a triangular shape?If the surface is plane triangle approximately and mass is uniformally distributed, then its center of mass will lie on the centroid of that triangle.
What is centroid of a triangle and its coordinates?The point of intersection of a triangle's medians is its centroid (the lines joining each vertex with the midpoint of the opposite side).
If the triangle has its vertices as [tex](x_1, y_1), (x_2, y_2) , \: (x_3, y_3)[/tex], then the coordinates of the centroid of that triangle is given by:
[tex](x,y) = \left( \dfrac{x_1 + x_2 + x_3}{3} + \dfrac{y_1 + y_2 + y_3}{3} \right)[/tex]
For this case, the triangular lamina has vertices (0, 0), (0, 1) and (c, 0)
Assuming its mass is spread regularly, the coordinates of its center of mass would be:
[tex](x,y) = \left( \dfrac{x_1 + x_2 + x_3}{3} + \dfrac{y_1 + y_2 + y_3}{3} \right)\\\\(x,y) = \left( \dfrac{0+0+c}{3} + \dfrac{0+1+0}{3} \right) = (c/3, 1/3)[/tex]
Thus, the y-coordinate of the center of mass of the lamina is 1/3 (independent of c).
Learn more about centroid here:
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Use the listing method to represent the following set. Hurry plz!!!
Answers
[tex]\\ \sf\longmapsto \left\{x|x \epsilon I,x\leqslant 3\right\}[/tex]
Here x belongs to set of Integersx is less than or equal to 3In listing
[tex]\\ \sf\longmapsto \left\{\dots,0,1,2,3\right\}[/tex]
The owner of a small hardware store employs three men and three women. He will select three employees at random to work on Christmas Eve. Find the probability that exactly two men (and one woman) will be selected to
work (2DP)
Answers
Answer:
Step-by-step explanation:
This is a hypergeometric distribution
[tex]\frac{{3\choose2}*{3\choose1}}{{6\choose3}}[/tex]=.45
What is the quotient of 35,423 ÷ 15?
Answers
Answer: 2361.53
Step-by-step explanation:
Use long division and round.
(The 3 is repeated)
The function f(x) = (x - 4)(x - 2) is shown.
What is the range of the function?
o all real numbers less than or equal to 3
o all real numbers less than or equal to -1
O all real numbers greater than or equal to 3
O all real numbers greater than or equal to -1
2
61
-1028
-2
Answers
Answer:
all real numbers greater than or equal to -1
Step-by-step explanation:
In order to solve this problem we need to know the vertex and the direction its pointing.
First we expand,
x^2-6x+8
To find the x value of the vertex we use this formula (-b/2a).
-(-6)/2(1) = 3
Now we plug 3 in the equation to get the y value,
(3)^2 - 6(3) + 8 = 9 - 18 + 8 = -1
The vertex is (3,-1)
We know the graph points up because x^2 is positive
The vertex is the lowest point, so we now know that -1 is the starting range and if the graph is pointing up, that means all values greater than -1.
This leads to our answer all real numbers greater than or equal to -1.
PLEASE HELP i’ll give brainliest to best and correct answer
Answers
Step-by-step explanation:
|- 9| + |- 3|
9 + 3
12
I hope this answers your question
Translate to an equation, then solve
Thirteen less than nine times a number is equal to 11 more than seven times the number.
Answers
Answer:
n=12
Step-by-step explanation:
13 less than 9 times a number: 13 less than 9n, 9n-13
11 more than 7 times a number: 11 more than 7n, 7n+11
9n-13=7n+11
2n=24
n=12
Part E
1e. Subtract the binomial 12y2 – 4y3 from the trinomial 7y - 2y3 + 5y2
Answers
Answer:
2y^3-7y^2+7y
Step-by-step explanation:
7y - 2y^3 + 5y^2 - ( 12y^2 – 4y^3)
Distribute the minus sign
7y - 2y^3 + 5y^2 - 12y^2 + 4y^3
Combine like terms
2y^3-7y^2+7y
Hello I'm new can anyone help me with this question?
Thank you so much! <3 xoxo
Answers
The vertices of a quadrilateral are listed below. A(8,-1), B(13,-1), C(18,-7), D(8,-7) Which of the following is the strongest classification that identifies this quadrilateral? A. The quadrilateral is a rhombus. B. The quadrilateral is a trapezoid. C. The quadrilateral is a square. D. The quadrilateral is a rectangle.
Answers
Answer:
A
Step-by-step explanation:
Because of we pur all the points on the Cartesian plane and we "connect" all the points comes a rhombus
SORRY FOR MY BAD ENGLISH BUT I AM ITALIAN
The average of 4 numbers is 15 , the sum of 3 numbers is 14 what is the fourth number
Answers
Answer:
46
Step-by-step explanation:
(14+x)/4 = 15
14 + x = 60
x = 46
Answer:
46
Step-by-step explanation:
Let a to d be number 1 to 4 respectively.
15 = (a + b + c + d) / 4
(a + b + c + d) = 60 ------> total sum of the 4 numbers
Since the sum of 3 numbers (assuming a to c) is 14,
Fourth number (d) = 60 - 14
= 46
That's how I would do it, hope this helps :)
In an examination, 40% of the candidates failed. The number candidates who failed was 160. How many candidates passed the examination?
Answers
Answer:
240 candidates
Step-by-step explanation:
40% candidates failed, i. e. out of every 100 candidates 40 failed.
40 failed ----------------------------- 100 total students
1 failed --------------------------------100/40 total students, given 160 failed therefore
160 failed ----------------------------(100/40) x 160 total students
Total students = (100/40) x 160 = 400
Number of candidates passed = (total candidates) - (total candidates failed)
= 400 - 160 = 240 candidates
Hey guys are you available?
Answers
Answer:
c
Step-by-step explanation:
Answer:C
Step-by-step explanation:
integration of 3^x (1-3^(x+1)^9)dx
Answers
Step-by-step explanation:
the answer is in picture
Find the length of FT¯¯¯¯¯¯¯ A. 77.71 B. 72.47 C. 56.84 D. 49.42
Answers
Answer:
D, 49.42
Step-by-step explanation:
ΔVFT=180-90-43=47
formula
a/sin A = b/sin B/ = c/sin C
So,
FV/sin90=53/sin47
FV=72.4684
FT=√(72.4684)^2-(53)^2
FT=49.4234
Ans:D
The length FT in the given right-angle triangle is 49.42.
So option D is the correct answer.
We are given a right-angle triangle and to find the length of any side we can use Pythagoras theorem or trigonometric identities.
In the triangle, we see that TV = 53 and ∠ FVT = 43°
We will find the length FT by using Pythagoras theorem or trigonometric identities.
What are trigonometric functions?
There are some commonly used trigonometric identities:
SinФ = Perpendicular / hypotenuse
Cos Ф = Base / hypotenuse
Tan Ф = Perpendicular / Base
We will use Tan Ф = Perpendicular / Base to find the length FT.
Because we need to use trigonometric identities that have TV and FT.
Tan Ф = FT / TV
Tan 43° = FT / 53
FT = Tan 43° x 53
FT = 0.932515 X 53
FT = 49.42
Thus we got FT = 49.42 using the tan function.
Learn more about trigonometric functions here:
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$SPJ2
All sacks of sugar have the same weight. All sacks of flour also have the same weight, but not necessarily the same as the weight of the sacks of sugar. Suppose that two sacks of sugar together with three sacks of flour weigh no more than 40 pounds and that the weight of a sack of flour is no more than 5 pounds more than the weight of two sacks of sugar. What is the largest possible weight (in pounds) of a sack of flour?
Answers
Answer:
The largest possible weight of flour is 11.25 pounds.
Step-by-step explanation:
To start with, we will assume that the weight of 1 sack of sugar = x pounds
We will also assume that the weight of 1 sack of flour = y pounds
So, the weight of 2 sacks of sugar = 2 * (x) = 2x
Same thing goes for the weight of 3 sacks of flour = 3 * (y) = 3y
Supposing that the weight of (2 sacks of sugar + 3 sacks of flour) ≤ 40 pounds
= 2x + 3y ≤ 40............ we'll call that equation 1.
Also, suppose that the weight of ( 1 sack of flour) ≤ 2 sacks of sugar + 5 pounds
= y ≤ 2x + 5........................ we'll call that equation 2
Therefore, we'll solve for the values of x and y in the two equations and we will get:
2x + 3y ≤ 40
y ≤ 2x + 5
Now, substitute the value of y into equation 1
2x + 3y ≤ 40 ⇒ 2x + 3(2x +5) =40
⇒ 2x + 6x + 15= 40
⇒ 8x + 15 = 40
⇒ 8x = 25
⇒ x = 25/8
⇒ x = 3.12
x cannot be more than 3.12 pounds, so we solve for y
Putting the value of x into equation 2, we'll get
⇒ 2y + 5 = 2(3.12) + 5
⇒ y = 11.25 pounds.
So, n cannot be more than 11.25 pounds
The perimeter of a rectangular Garden is 80 feet the garden is three times as long as it is wide the system of equation can be used to find the width in the length
Answers
Answer:
10 wide 30 long
Step-by-step explanation:
1. Start guess and check.
2. When you get to 10 follow this:
10x3=30. 30+30+10+10=80
80=80
find the value of x - Secant and Tangent Angles in Circles
Answers
Answer:
C. 70°
Step-by-step explanation:
The inscribed angle marked 15° intercepts an arc that is double that measure, so the intercepted arc on the right is 2×15° = 30°.
The external angle marked 20° is half the difference of the intercepted arcs, so is ...
20° = (1/2)(x - 30°)
40° = x - 30° . . . . . . multiply by 2
70° = x . . . . . . . . . . . add 30°
The value of x is 70°.
solve the following inequalities 7 x minus 5 / 8 x + 3 >4
Answers
Answer:
[tex]x> \frac{8}{51} [/tex]
Step-by-step explanation:
[tex]7x - \frac{5}{8} x + 3>4[/tex]
Bring constants to one side, simplify:
[tex] \frac{51}{8} x>4 - 3 \\ \frac{51}{8} x>1 \\ x>1 \div \frac{51}{8} \\ x>1 \times \frac{8}{51} \\ x> \frac{8}{51} [/tex]
*Note that the inequality sign only changes when you divide the whole inequality by a negative number.
Answer:
[tex]x>\frac{8}{51}[/tex]
Step-by-step explanation:
[tex]7x-\frac{5}{8}x+3>4\\\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}\\7x-\frac{5}{8}x+3-3>4-3\\\mathrm{Simplify}\\7x-\frac{5}{8}x>1\\\mathrm{Multiply\:both\:sides\:by\:}8\\7x\times \:8-\frac{5}{8}x\times \:8>1\times \:8\\\mathrm{Simplify}\\56x-5x>8\\51x>8\\\mathrm{Divide\:both\:sides\:by\:}51\\\frac{51x}{51}>\frac{8}{51}\\\\x>\frac{8}{51}[/tex]
I hope it helps :)
the grasshopper population in Georgia is currently 4,000. It's growing by 2.3% each year. Write an equation that models the situation.
Answers
Answer:
[tex]4000(1.023)^t\\\\[/tex]
Step-by-step explanation:
Using this exponential growth equation we can get an equation that models the situation.
A= Principal Amount
R= Rate of Growth
T= Amount of time
[tex]A=4000\\R=2.3/100=.023\\T= Non[/tex]
[tex]A(1+R)^t\\4000(1+0.23)^t\\4000(1.023)^t\\\\[/tex]
2000 people attended a baseball game. 1300 of the people attending supported the home team, while 700 supported the visiting team. What percentage of people attending supported the home team?
Answers
Answer:
Percentage of home team supporters =65%
Percentage of visiting team supporters =35%
Step-by-step explanation:
Total attendees=2,000 people
Home team supporters=1,300
Visiting team supporters=700
What percentage of people attending supported the home team?
Percentage of people attending who supported the home team = home team supporters / total attendees × 100
=1,300/2,000 × 100
=0.65 × 100
=65%
Visiting team supporters = visiting team supporters / total attendees
× 100
=700/2000 × 100
=0.35 × 100
=35%
Alternatively,
Visiting team supporters = percentage of total attendees - percentage of home team supporters
=100% - 65%
=35%
QUESTION TWO [25 MARKS] a) Your task is to interview a representative sample of attendees for the large concert venue where you work. The new season schedule includes 200 live concerts featuring all types of musicians and musical groups. Since neither the number of attendees nor their descriptive characteristics are known in advance you decide on nonprobability sampling. Based on past seating configurations, you can calculate the number of tickets that will be available for each of the 200 concerts. Thus, collectively, you will know the number of possible attendees for each type of music From attendance research conducted at concerts held by the Glacier Symphony during the previous two years, you can obtain gender data on attendees by type of music. How would you conduct a reasonably reliable nonprobability sampling? T5 marks] (b) A recent article in Nairobi Post Weekly Edition indicated that about 80% of the
Answers
Answer:
The answer to this question depends, in part, on the kinds of questions that you want to ask them. If the purpose of the survey is to try and figure out what concert patrons are thinking, then you want to try to get a good variety of ideas. In that case, you're no so interested in having a sample of individuals that's exactly representative of the population of concert goers. You only want to get a wide variety of the ideas that are out there. This is called heterogeneity sampling. That is, in this case, we'll be trying to get a sample not of people, but of ideas. In this case, we'd use brainstorming groups, panel sessions, and other group discussion methods to get all the ideas out there.
This approach is not an appropriate one if the purpose of the questions is to determine the preferences of the population of theater goers. That's because it doesn't communicate the popularity or prevalence of ideas in the sample. If this is a problem, and it likely is, it seems more appropriate to use some sort of purposive sampling method like modal interest sampling. This approach requires determining what the typical concert goer is like . If the company determines that the typical (or modal) attender is a young single person in college, then those people are sought out and interviewed. This is the sort of polling that is used in election polls where they interview "typical voters." For different genres of music and concert, a different typical concert goer could be postulated and different surveys and interview styles determined.
Probably most appropriate to this problem, though, is quota sampling. This form of purposive sampling uses demographic and other information to determine how many of different kinds of people to interview. For instance, if it is determined that only 20% of concert goers for a particular concert were women, then only 20% of the nonprobability sample should be made up of women. As long as these quotas are met, the sample can be sufficiently random.
I recommend using a combination of quota sampling and modal instance sampling. It seems to me that the kinds of people who attend concerts are idiosyncratic in some ways. Inasmuch as we can define universal characteristics of concert goers, we should seek to include only those people in the sample, but since we have demographic data as well, we should use these proportions as quotas as we select typical concert goers. For example, suppose we determine that the vast majority of people who attend operas make over $80,000/year, then we should limit our sample to people with that income level, but if we also know that 80% of opera attenders are women, we should work to insure that not more than 20% of our sample is men.