A) Linear
B) Quadratic
C) Exponential
D) Functional

Answer:

Remember you can replace the varibles in the equation above with the number equal to the main varible to get your answer

Step-by-step explanation:

Hope this helps!

Answer:

No, theyre not proportional

Step-by-step explanation:

48/84=4/7

60/96=5/8

5/8 does not equal 4/7

Answer: 5

Step-by-step explanation:

Answer:

Cups 32 80 96. 128. 160

Gallons 2. 5. 6. 8. 10

I think it will help you

Answer:

( a+b) ( m^2 + n^2)

Step-by-step explanation:

factorise like terms

m^2 ( a + b ) + n^2 ( m^2 + n^2)

then put like terms together put remaining terms in a bracket

( a + b) ( m^2 + n^2 )

Answer: i think D sorry if wrong

can we be friend

Answer:

200mm^2 is the area of shadded region

Answer:

no parallelogram, mr clean thus cannot answer.

A: no se

B: 200 pesos x 4 semanas  = 800

C: jose  por que eso significa no se :(

D:  Por que son 900 alumnos  y se va 700 de excurcion eston se va el 70% de excurcion

Answer:

5+z7=12

Step-by-step explanation:

I think this is the answer idek if its an option but I hope u get it right:) Hope this helped

The quotient of 12 divided by y increased by 7 is equals to [tex]\frac{12}{y} +7[/tex].

" Division is defined as the distribution of a number into equal parts as per the given condition."

According to the question,

Given number = 12

Divisor = y

Condition given = quotient of 12 divided by y increased by 7

As per the given condition the required quotient of given division ,

[tex]\frac{12}{y} +7[/tex]

Hence, the quotient of 12 divided by y increased by 7 is equals to [tex]\frac{12}{y} +7[/tex].

Learn more about division here

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Answer:

Step-by-step explanation:

2:27

The Cena can take 7 courses

We have given that the karate charges $35 for the first course and $22.50 for each course after that. Our total is $170.

[tex]22.50x + 35 = 170[/tex]

for solving this linear equation

First, subtract 35 from both sides.

[tex]22.50x = 135[/tex]

isolate x so divide both sides by 22.50.

[tex]x=\frac{135}{22.50}[/tex]

Therefore we get x = 6

Remember to add the additional class, so x is actually 7.

So,the Cena can take 7 courses.

To learn more about the linear equation visit:

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Answer:

7 courses

Step-by-step explanation:

Answer:

협의회는 지난 해 올해

Step-by-step explanation:

업 하고 있는 것 같은 기분 좋은 시간 보내고 왔습니다 그리고 저는 이렇게 잘 지내고 있습니다 저는 너무 힘들고 또 제 자신이 정말 많은 것 같아요

Answer:

x=8.

Step-by-step explanation:

according to the given coordinates the required line is vertical (the value of 'x' is 8), then the required equation is: x=8.

Step-by-step explanation:

this is one of the formulas you should remember for life :

the general solution for a quadratic equation

ax² + bx + c = 0

is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case that is

x = (-4 ± sqrt(4² - 4×1×-1))/(2×1) = (-4 ± sqrt(16 + 4))/2 =

= (-4 ± sqrt(20))/2 = (-4 ± sqrt(4×5))/2 =

= (-4 ± 2×sqrt(5))/2 = -2 ± sqrt(5)

x1 = -2 + sqrt(5) = 0.236067977...

x2 = -2 - sqrt(5) = -4.236067977...

so, the negative solution is the x2 solution :

-4.236067977...

I don't know to how many decimal positions you are supposed to round. it is not specified in your problem definition.

Step-by-step explanation:

-5x - 3 = -18

that's the answer

Answer:

B. Different of Squares

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

The first components should not be duplicates, otherwise the second components should be the same. Therefore, the second option is correct.

Answer:

6

Step-by-step explanation:

Pls, choose me as brainliest!

Answer:

541686

Step-by-step explanation:

678,686-137,000=541686

Answer:

23. Reflexive property

24. Transitive property

Step-by-step explanation:

In algebra, the reflexive property of equality states that a number is always equal to itself. Reflexive property of equality. If a is a number, then a = a

The Transitive Property states that for all real numbers x ,y, and z, if x=y and y=z , then x=z .

Answer:

D

Step-by-step explanation:

x,y 2,3 just trust me good sir

Answer:

y = -2/3x - 6 (B)

Step-by-step explanation:

There not really an explanation to be made. You've got to count points correctly and number your graph appropriately to get a correct answer.

Answer:

I don't know. You need to ask someone else.

Answer:

Step-by-step explanation:

Simplify

[tex]\\ \rm\longmapsto y=(x-20)^2+5[/tex]

[tex]\\ \rm\longmapsto y=x^2-40x+405[/tex]

Graph attached

Answer:

no real zeros

Step-by-step explanation:

We are given the following quadratic function:

[tex]y = {(x - 20)}^{2} + 5[/tex]

firstly simplify it to standard form which is

[tex]y = {x}^{2} -40x + 405[/tex]

To figure out the real zeros, set y to 0:

[tex] {x}^{2} - 40x + 405 = 0[/tex]

recall that,a quadratic equations has real zeros in case its discriminant is greater than or equal to 0, therefore

consider,

now substitute:

[tex] { (- 40)}^{2} - 4(1)(405) \stackrel{ ? }{ \geq}0[/tex]

simplifying yields:

[tex] 1600 - 1620 \stackrel{ ? }{ \geq}0 \\ - 20 \ngeq 0[/tex]

hence, The function has no real zeros

Answer:

Step-by-step explanation:

1) 8.9

2) 27.8

3) 24.3

4) 11.4

5) 27.5

6) 49.2

7) 8.1
8)4.8

Answer:

There are a total of twelve possible outcomes. This is because flipping a coin has two possible outcomes (either heads or tails) and rolling a number cube has 6 of them (1-6) so 2 times 6 is 12.

If you want to draw a tree diagram, first split your tree into two branches, one for heads and one for tails. Then, split both branches into 6 sub-branches each, so each branch has a full set of numbers from 1-6.

Or you can do it the other way around, first split your tree into 6 branches, then split all branches into 2 sub-branches each.

hope this helps :)

Answer:50.3m

Step-by-step explanation:

Answer:

[tex] \\ [/tex]

Step-by-step explanation:

To find the circumference of the circle, we must know this formula

[tex]\\{ \longrightarrow \qquad{ \underline {\boxed{ \pmb{ \mathfrak{ \: \: Circumference_{(circle)} = 2 \pi r}}}}}} \: \: \bigstar \\ \\ [/tex]

Where,

With the help of this formula, we can find the circumference of the circle.

[tex] \\ [/tex]

Now, we'll substitute the values in the formula :

[tex] \\ { \longrightarrow \qquad{ \sf{ \: \: Circumference_{(circle)} = 2 \times 3.14 \times 8}}} \: \: \\ \\ [/tex]

[tex]{ \longrightarrow \qquad{ \sf{ \: \: Circumference_{(circle) }= 3.14 \times 16 }}} \: \: \\ \\ [/tex]

[tex]{ \longrightarrow \qquad{ \pmb{ \frak { Circumference_{(circle) }= 50.24\: }}}} \: \: \\ \\ [/tex]

Therefore,