(a) The diameter of the largest orbit just before the protons exit the cyclotron is 39 cm.
(b) The number of orbits completed by the proton during this 1.0 ms is 14000 revolutions.
What is kinetic energy?
The kinetic energy of an object is the energy that it possesses due to its motion.
It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.
Formula of KE:
K.E = 1/2mv²
mv² = 2 K.E
v = sqrt( 2*KE / M)
Here,
(a)
The KE of the medical isotopes = 6.5 MeV
substituting the values,
v = sqrt( 2* 6.5* 1.6* 10^-13 / 1.67* 10^-27 )
v = 3.53 × 10⁷ m/s
Now the centripetal force:
mv² / R = qvB
r = q*v / mv²
r = ( 1.67* 10^-27 * 3.53 × 10⁷ ) / ( 1.9* 1.6* 10^-19 )
r = 0.19415 m
diameter d = 2r,
d= 2(0.19415 m)
d= 0.39 m ≅ 39 cm
(b)
The time period to complete a revolution around the spiral trajectory is:
T = 2πr / v
T = 2*3.14* 0.1941 / 3.53*10^7
T = 0.7 × 10⁻⁷ s
Thus, the number of orbits that the proton does to complete the revolution in 1 ms is:
n = t / T
n = 10^-3 / (0.7*10^-7)
n = 14285.71 ≅ 14000 revolutions
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Your question is incomplete, but most probably full question was:
A medical cyclotron used in the production of medical isotopes accelerates protons to 6.5 MeV. The magnetic field in the cyclotron is 1.9 T.
(a) What is the diameter of the largest orbit, just before the protons exit the cyclotron? Express your answer with the appropriate units. d = 57 cm Previous
(b) A proton exits the cyclotron 1.0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1.0 ms?
A 500.0 kg elevator is pulled upward with a constant force of 5500.0 N for a distance of 50.0 m. What is the work done by the 5500.0 N force on the elevator?
Group of answer choices
a. -2.45 x 105 J
b. -5.20 x 105 J
c. 2.75 x 105 J
d. 3.00 x 104 J
C. The work done by the 5500.0 N force on the elevator is 275,000 J.
Work done by the applied force
The work done by the 5500.0 N force on the elevator is calculated as follows;
W = Fd
where;
F is the applied forced is the displacementW = 5500 x 50
W = 275,000 J
Thus, the work done by the 5500.0 N force on the elevator is 275,000 J.
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A 7.55 × 1014 hz electromagnetic wave travels in carbon tetrachloride with a speed of 2.05 ×108 m/s. what is the wavelength of the wave in this material?
Answer:
2.72×10^-7
Explanation:
velocity = frequency × wavelength
2.05×10^8=7.55×10^14 wavelength
wavelength = 2.05×10^8/7.55×10^14
wavelength = 2.72×10^-7
What mass will accelerate at 3 m/s² when a net force of 150 N acts on it?
Answer:
[tex]\huge\boxed{\sf m = 50\ kg}[/tex]
Explanation:
Given data:Acceleration = a = 3 m/s²
Force = F = 150 N
Required:Mass = m = ?
Formula:F = ma
Solution:Put the givens in the formula
150 = m (3)
Divide 3 to both sides
150/3 = m
50 kg = m
m = 50 kg
[tex]\rule[225]{225}{2}[/tex]
According to max weber, flaunting of one’s wealth to show one’s status is called?
Status refers to a person's prestige, social honor, or reputation in society. Weber stated that political strength become now not rooted entirely in capital fees, but additionally in a single's individual popularity. Poets or saints, for example, can own a massive impact on society, often with little monetary worth.
The German sociologist Max Weber formulated a three-component theory of stratification that defines a status group (additionally status class and status estate) as a group of humans within a society who can be differentiated by means of non-financial characteristics along with honor, prestige, ethnicity, race, and religion.
Social stratification entails society as a system of hierarchical categories. Max Weber defined stratification because the division of a society into distinct communities, that have varying assignments of “status honor” or status.
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Two boys with masses of 40 kg and 60 kg stand on a horizontal frictionless surface holding the ends of a light 10-m long rod. The boys pull themselves together along the rod. When they meet the 40-kg boy will have moved what distance?.
When they meet the 40-kg boy will have moved a distance of 6 m.
Displacement of the 40 kg boy
The displacement of the 40 kg boy is calculated from the principle of center mass.
X(40 kg) = (60 x 10 m + 40 x 0)/(40 kg + 60 kg)
X(40 kg) = (600)/(100) = 6 m
X(60 kg) = (60 x 0 + 40 x 10 m)/(40 kg + 60 kg)
X(60 kg) = (400)/(100) = 4 m
Thus, when they meet the 40-kg boy will have moved a distance of 6 m.
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When hydrogen is fused into helium, energy is released from Choose one: A. the increase in pressure. B. the decrease in the gravitational field. C. conversion of mass to energy. D. gravitational collapse.
The nuclear fusion of hydrogen atoms releases a huge amount of energy. So the correct choice is C. Conversion of mass to energy.
What is nuclear fusion?
When two small nuclei join to form a new nucleus, then this process is termed nuclear fusion. A huge amount of energy is released when there occurs nuclear fusion between the two nuclei. And a new element is formed.
It has been observed that the amount of energy released in nuclear fusion is equal to the mass difference between the mass of the formed nucleus and the total mass of old nuclei. Hence in the nuclear fusion of hydrogen nuclei to form a helium nucleus, the energy is released due to the conversion of mass into energy.
The pressure is increased to make the hydrogen atoms fuse but this change in pressure does not contribute to the energy released in the fusion of hydrogen.
The magnitude of the gravitational field is too low and it does not contribute to the energy released in the fusion of hydrogen.
The gravitational collapse does not occur between the two hydrogen atoms. This phenomenon occurs in celestial bodies so this also does not contribute to the energy released in the fusion of hydrogen.
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a pulley is assumed massless and frictionless and rotates freely about its axle. the blocks have masses m1=40g and a block m2= 20g, and block m1 is pulled to the right by a horizontal force magnitude f=0.03n. find the magnitude of acceleration of a block m2 and the tension in the cord.....?
The magnitude of acceleration of a block m₂ is 0.05 m/s² and the tension in the cord is 0.01 N.
Given:
mass of block 1, m₁ = 40 gm = 40×10⁻³ kg
mass of block 2, m₂ = 20 gm = 20×10⁻³ kg
Applied force, F = 0.03 N
Calculation:
Consider the free-body diagram of the system as shown below. Using Newton's second law of motion we get:
F = ma
where F is the applied force
m is the total mass of the system
a is the acceleration of block 2 (as it is pulled by horizontal force)
From the above equation we get:
0.03 N = (m₁+m₂) a
⇒ a = (0.03 N) / (m₁+m₂)
⇒ a = (0.03 N) / (40×10⁻³ kg + 20×10⁻³ kg)
⇒ a = 0.5 m/s²
Now, from the free-body diagram of block 2 as shown in figure 3, we get:
Balancing the forces along the horizontal:
∑Fₓ = 0
∴ T = m₂ a
where T is tension in the string
a is the acceleration of block 2
Applying values in the above equation we get:
T = (20×10⁻³ kg) × (0.5 m/s²)
= 0.01 N
Therefore, the acceleration of block 2 due to the applied horizontal force is 0.5 m/s² and the tension in the cord is 0.01 N.
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After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 55.0 cmcm. She finds that the pendulum makes 110 complete swings in a time of 145 ss.
Hi there!
First, let's find the period of the pendulum. This can be found by solving for the amount of time it takes for the pendulum to make ONE complete swing.
[tex]T = \frac{\text{Total time}}{\text{Number of complete swings} }\\\\T = \frac{145}{110} = 1.318 s[/tex]
Now, let's use the equation for the period of a simple pendulum:
[tex]T = 2\pi \sqrt{\frac{L}{g}}[/tex]
T = Period (1.318 s)
L = length of string (0.55 m)
g = acceleration due to gravity on planet (? m/s²)
Let's solve for 'g' doing some quick rearranging of the equation:
[tex]T^2 = 4 \pi^2 (\frac{L}{g})\\\\g = \frac{4\pi^2 L}{T^2}\\\\[/tex]
Solving for 'g' by plugging in values:
[tex]g = \frac{4\pi^2 (0.55)}{(1.318)^2}\\ \\= \boxed{12.496 \frac{m}{s^2}}[/tex]
This simulation has three parts: Intro, Compare, & Mystery.I. Explore the Intro section of this simulation.1. Based on your exploration how will you define the density D, of a substance? Writedown an algebraic expression relating D to the mass and volume of a substance.2. Does the density of a substance change with its mass? If yes, how? If no, why not?
a) Density is mass of a unit volume of a material substance
b) Algebraic expression relating Density = m / v
c) Density is an intensive property, which means the density does not change as the amount of the substance present changes
a) Density is mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is the measurement of how tightly a material is packed together.
The more closely packed particles are, the more dense the object. The amount of mass in a particular space or volume. The more particles (or mass) in a given space, the more dense it is.
b) Algebraic expression relating Density = mass / volume or m/v
where d is density, M is mass, and V is volume.
c) Density (ρ) is the amount of mass (m) per unit volume (V) of a substance. Density is an intensive property, which means the density does not change as the amount of the substance present changes.
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The question is in the picture
Answer:
See below
Explanation:
Power = amps * volts = .27 * 12 = 3.24 watts
V= IR
R = V/I = 12/.27 = 44.44 ohms
Car A is traveling with a constant speed of 80 km>h due north, while car B is traveling with a constant speed of 100 km>h due east. Determine the velocity of car B relative to car A
Answer:
80J
Explanation:
K.E = ½ mv²
k.e = ½ * 80*
100²
ke= 4*20
ke= 80 J
What is the energy of a photon of ultraviolet radiation with a frequency of 4.4 × 1015 hz? planck’s constant is 6.63 × 10–34 j • s. 2.9 × 10–18 j 2.9 × 10–34 j 2.9 × 10–48 j
The energy of a photon of ultraviolet radiation is E = 2.91 * 10^-18 J
What is a photon?
A photon is a particle of light defined as a discrete bundle (or quantum) of electromagnetic energy.
The energy of a photon is obtained by multiplying Planck's constant by the frequency of electromagnetic radiation:
E = h * f
where,
h is Planck's constant
h= 6.63×10⁻³⁴ Js
f= 4.4×10^15 Hz
Substituting the values in the equation for Energy:
E = (6.63×10⁻³⁴) * ( 4.4×10^15)
E = 2.91 * 10^-18 J
Hence,
The energy of a photon of ultraviolet radiation is E = 2.91 * 10^-18 J
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Answer: the first choice!
Explanation: did it the question on edg!:)
You're holding an open house for Brenda. Walt and Mary walk in and ask you for a flyer that gives details about the property. At this point, what's your relationship with Walt and Mary
Walt and Mary are my Customers at this point.
To construct proper client relationships you need to: greet clients and approach them in a way that is herbal and suits the character scenario. show customers that you recognize what their desires are. be given that a few humans may not want your merchandise and concentrate on constructing relationships with people who do.
Use the time period clients, with an apostrophe before the “s” to expose a possessive form for a single consumer. Use the time period clients', with an apostrophe after the “s” to show the possessive plural shape of a couple of patrons. Do now not use an apostrophe if there's no possessive indication needed.
The definition of a consumer is a person who buys services or products from a store, restaurant, or different retail vendor. An example of a patron is someone who is going to an electronics save and buys a tv. (Casual) a person, mainly one engaging in a few types of interaction with others.
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Work is best described as?
Answer:
Explanation:
In physics, work can be described as force multiplied by the displacement of the object (distance caused by the force acted on the object).
Work is a form of energy, therefore, it is measured in joules.
If Alex pushed on an object with 10N of force, and the object moved 2 meters, the work of Alex will be equal to:
W = Ft
W = 10N * 2m
W = 20 Joules
But, if we have John, that pushed on an object with 2N of force, but, since the object was way smaller, therefore it had way less inertia, the object moved a distance equal to 10 meters. Let's also calculate his work.
W = Ft
W = 2N * 10m
W = 20 Joules
And we got the same result.
Work can also be used to calculate power.
Power is equal to P = Work / time
It can also be written as P = delta Work / delta time
Power is measured in joules per second.
With power you can make the difference between someone that got a 2 kg object up in 2 second, and someone that got a 2 kg object up in 5 second.
The more powerful one would be the one who managed to make the same work in less time.
Hope it Helped!
Work is described as: the measure of energy transfer resulting from the application of force over a displacement.
What is Work?In the field of physics, work is most accurately defined as the outcome of multiplying the force exerted on an object by the distance the object is displaced in the same direction as the force.
This calculation serves to quantify the energy transferred to or from the object. For instance, if an individual applies a 50 Newton force to push a box across a 5-meter distance in the force's direction, the work done on the box would equal 250 Joules (50 N × 5 m).
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According to the superstring theories, gravitation has its own energy-sharing particles called _____, analogous to photons and electromagnetism.
Graviton
Graviton, postulated quantum that is thought to be the carrier of the gravitational field. It is analogous to the well-established photon of the electromagnetic field.
What is Superstring theories ?String theory states that everything in our Universe is made up of tiny vibrating strings. These strings are one dimensional objects and are identical to one another.
Every fundamental particle that we know such as electrons, quarks, photons, gluons, etc are made up of these strings.String theory has contributed a number of advances to mathematical physics, which have been applied to a variety of problems in black hole physics, early universe cosmologyLearn more about Superstring theories here:
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5.1 What is the nucleus composed of ?
Answer:
5.1 The DNA double helix is the most recognizable nucleic acid structure, but these are ribozymes.
Which element of the promotional mix is most helpful in inducing trial?
Sales Promotion, Income advertising publications to short-term and transient incentives to buy or result in trials of new items.
Sales advertising is an advertising approach in which an enterprise uses a transient campaign or provide to increase interest or demand in its service or product. There are numerous motives why a commercial enterprise may additionally choose to apply an income promotion (or 'promo'), however, the primary purpose is to reinforce income.
sales promotion is one of the elements of the promotional mix. The number one element within the promotional blend is advertising and marketing, private selling, direct marketing, and exposure/public relations.
Examples encompass contests, coupons, freebies, loss leaders, a factor of purchase shows, charges, prizes, product samples, and rebates. sales promotions may be directed at both the patron, sales group of workers, or distribution channel individuals (such as outlets).
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What should a driver do when he/she gets to a speed hump? a maintain current speed. b accelerate. c brake. d reduce speed to suggested limit.
It is usually best to reduce speed to suggested limit when a driver gets to a speed hump and is denoted as option D.
What is Deceleration?This refers to a situation in which the speed or acceleration of a body is reduced while in the other hand, acceleration refers to the condition in which a body increases its speed or acceleration.
Speed humps are structures which are placed in the road in other to slow vehicles to between 10 to 15 mph. They ensure over speeding is checked due to it being dangerous to other users.
Applying brake or maintaining current speed may lead to the vehicle being tilted towards the front end which may result in collision and other forms of accident.
This therefore the reason why reducing speed to suggested limit is the most appropriate choice.
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The weight of a hydraulic barber's chair with a client is 2000 N. When the barber steps on the input piston with a force of 40 N, the output plunger of a hydraulic system begins to lift the chair. Determine the ratio of the radius of the output plunger to the radius of the input piston.
Answer: The weight of a hydraulic barber's chair with a client is 2000 N. When the barber steps on the input piston with a force of 40 N, the output plunger of a hydraulic system begins to lift the chair. Then the ratio of the radius of the output plunger to the radius of the input piston will be 7.07.
Explanation: To find the answer, we have to know more about the Pascal's law and the hydraulic lift.
What is pascal's law and how it is used in case of hydraulic lift?The law states that, the pressure exerted at any point on an enclosed liquid is transmitted equally in all directions.A hydraulic lift consists of two cylinders connected to each other by pipe.If the force F1 applied on the smaller piston of area A1, the pressure exerted will be,[tex]P_1=\frac{F_1}{A_1}[/tex]
By pascal's law, the pressure transmitted to the large piston of large area A2 will be,[tex]P_2=\frac{F_2}{A_2}[/tex]
Then,[tex]\frac{F_2}{A_2} =\frac{F_1}{A_1}[/tex]
How to solve the problem?We have to find the ratio of the radius of the output plunger to the radius of the input piston.We have the equation for this as,[tex]\frac{A_{Plunger}}{A_{piston}} =\frac{F_{Plunger}}{F_{piston}}[/tex]
[tex]\frac{R_{Plunger}}{R_{piston}}=\sqrt{ \frac{F_{Plunger}}{F_{piston}}}=\sqrt{\frac{2000}{40} } =7.07[/tex]
Thus, we can conclude that, the ratio of the radius of the output plunger to the radius of the input piston will be 7.07.
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He wavelengths of the sounds produced by two horns are 6.0 m and 7.0 m, respectively. what beat frequency is heard when the horns are sounded on a day when the speed of sound is 340 m/s?
The beat frequency will be 8.1 Hz when the horns are sounded on a day when the speed of sound is 340 m/s
frequency = speed / wavelength
f1 = 340 / 6 = 56.67 Hz
f2 = 340 / 7 = 48.57 Hz
Beat frequency = fb = | f2 - f1 |
= | 48.57 - 56.67 |
= 8.1 Hz
The beat frequency will be 8.1 Hz when the horns are sounded on a day when the speed of sound is 340 m/s
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A piece of copper of mass 150g at temperature of mass 70g containing 60g of water at temperature of 20°C. Ignoring heat losses, what would be the final steady temperature of the mixture? [Specific of heat capacity of copper = 4.0× 10²J/kg-1/K ^-1. Please any Physics student can help or if you have any idea, you can help me out. Thanks.✨✨
Answer:
The final temperature is [tex]29.6^oC[/tex].
Explanation:
When the two masses come in contact, one releases heat and the other absorbs it. The former can be modelled with the equation [tex]HeatLost = (Mass1 (kg))(c1)(T1-T)[/tex], and the latter by [tex]HeatGained=(Mass2(kg))(c2)(T-T2)[/tex]
m1=0.15 kg
m2=0.06 kg
T1 = 70 degrees Celsius = 343 K
T2 = 20 degrees Celsius = 293 K
T= Final temperature
c1 = Specific heat capacity of copper
c2 = Specific heat capacity of water
Because there is no heat lost into the surroundings, the heat removed from one substance is the same as the heat gained in the other. Therefore:
[tex](Mass1)(c1)(T1-T)=(Mass2)(c2)(T-T2)[/tex]
[tex](0.150)(400)(343-T)=(0.06)(4184)(T-293)[/tex]
[tex](60)(343-T)=(251.04)(T-293)[/tex]
[tex]20580-60T=251.04T-73554.72[/tex]
[tex]-311.04T=-94134.72[/tex]
[tex]T=302.6 K[/tex]
[tex]T=29.6^oC[/tex]
Hope this helps! (My apologies if the answer is wrong, it has been a while since I've done this)
irius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Another bright star, Regulus , has a parallax of 0.042 arcseconds. What is its distance in parsecs
The actual distance of Regulus from Earth is 23.81 parsecs.
Given:
Parallax of Regulus, p = 0.042 arc seconds
Calculation:
When an observer changes their position, an apparent change in the object's position takes place. This change can be calculated using the angle ( or semi-angle) made by the observer and object i.e. the angle made between the two lines of observation from the object to the observer.
Thus from the relation of parallax of a celestial body we get:
S = 1/ tan p ≈ 1 / p
where S is the actual distance between the object and the observer
p is the parallax angle observed
Here for Regulus, we get:
S = 1 / p
= 1 / (0.042) [ 1 parsecs = 1 arcseconds ]
= 23.81 parsecs
We know that,
1 parsecs = 3.26 light-years = 206,000 AU
Converting the actual distance into light years we get:
23.81 parsecs = 23.81 × (3.26 light yrs) = 77.658 light-years
Therefore, the actual distance of Regulus from Earth is 23.81 parsecs which is 77.658 in light years.
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how do you use atomic models
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A car generator turns at 400 rpm (revolutions per minute) when the engine is idling. It has a rectangular coil with 300 turns of dimensions 5.00 cm by 5.22 cm that rotates in an adjustable magnetic field. What is the field strength needed to produce a 24.0 V peak emf
The field strength needed to produce a 24.0 V peak emf is 0.73T.
To find the answer, we need to know about the expression of emf.
What's the expression of peak emf produced in a rotating rectangular loops?
The peak emf produced in a rotating loops= N×B×A×wN= no. of turns of the loop, B= magnetic field, A= area of loop and w= angular frequencySo, B = emf/(N×A×w)What's the magnetic field applied to the loop, when rectangular coil with 300 turns of dimensions 5.00 cm by 5.22 cm rotates at 400 rpm produce a 24.0 V peak emf?N= 300, A= 5cm × 5.22cm = 0.05m × 0.0522m = 0.00261 m²Emf= 24V, w= 2π×400 rpm= 2π×(400rps/60) = 42 rad/sNow, B= 24/(300×0.00261×42)B= 24/(300×0.00261×42) = 0.73T
Thus, we can conclude that the magnetic field is 0.73T.
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Tina is singing a song. At a certain point in the song, she forces a large volume of air out of the glottis and at the same time increases the tension on her vocal cords. The sound that she produces is
The sound that Tina produces while singing is loud and high-pitched.
How is a sound produced?
Vibrations that travel through the air or another medium and can be heard by an observer are called sounds. Sound is produced by the following cycle:
A column of air in the lungs leads to the opening of the bottom section of vocal folds. It then continues to move upwards towards the top of the vocal folds and escapes out. This causes Bernoulli's effect, that is as low pressure gets created behind the fast-moving air column, the bottom section of the vocal folds closes, followed by the top. The air gets cut off due to the closure of the vocal folds which releases a pulse of air and the cycle continues.Therefore, when Tina sings larger vibrations are created, and the tension within her vocal cords increases producing a very high-pitched loud sound.
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What is the energy of an electromagnetic wave that has a wavelength of
7.0 x 10-12 m? Use the equation E= hc where hc = 1.99 × 10-25 J-m.
OA. 2.8 × 10-14 J
OB. 1.4 x 10-36 J
OC. 9.0 x 10-37 J
OD. 7.2 x 1035 J
SUBMIT
[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Here we go ~
[tex]\qquad \sf \dashrightarrow \:E = \dfrac{hc}{\lambda} [/tex]
here,
[tex] \sf{hc = 1.99 × {10}^{-25} J - m} [/tex][tex] \sf{\lambda = 7.0 × {10}^{-12}} [/tex]____________________________________
[tex]\qquad \sf \dashrightarrow \: E = \cfrac{1.99 \times 10 {}^{ - 25} }{7 \times 10 {}^{ - 12} } [/tex]
[tex]\qquad \sf \dashrightarrow \: E= \cfrac{1.99}{7} \times 10 {}^{ (- 25 + 12)} { } [/tex]
[tex]\qquad \sf \dashrightarrow \:E= 0.284 \times 10 { }^{ - 13} [/tex]
[tex]\qquad \sf \dashrightarrow \: E= 2.84 \times 10 { }^{ - 14\:\; } J\: \: [/tex]
so, correct choice is A
When a car driving up a hill with constant speed: I. its kinetic energy is decreasing. II. its potential energy is constant. III. its total mechanical energy is constant. Group of answer choices II I III none of the above
A car driving up a hill at a constant speed experiences no change in its kinetic energy while it's potential energy increases with increasing height, thus none of the options are correct.
Understanding the concept
Consider a car moving up the hill at a constant speed as shown in the figure below. The following forces act on the car:
N is the normal reaction force acting in an upward directionf_s is the static friction force exerted due to friction between the road and the tires of the carf_k is the rolling friction force in the direction opposing that of the tiremg is the force acting in a downward direction.θ is the angle of inclination.Here as the car is moving up the hill at a constant speed, the net force exerted on the car is zero. Also, the kinetic energy of the car will not change as its velocity is constant and the potential energy will change with increasing height. Thus, none of the given options are correct.
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A ball of mass 4 kg is initially traveling at 2 m/s and has a 5 N force applied to it for 3 s. What is the final velocity of the ball?
A. 4 m/s
B. 12 m/s
C. 5.75 m/s
D. 3.25 m/s
Answer:
the answer to your question will be D
Explanation:
5 N* 3S =3.25
A 0.10-m 3 0.20-m 3 0.30-m block is suspended from a wire and is completely under water. What buoyant force acts on the block
The buoyant force acting on the block is 58.8 N.
Calculation:The dimensions of the block are given as 0.10 m, 0.20 m and 0.30 m.
The volume of the block will be = 0.10 × 0.20 × 0.30 m³
= 0.006 m³
We know that,
W = mg .....(1)
where,
W = weight of the block
m = mass of the block
g = acceleration due to gravity = 9.8 m/s²
We also know that mass is proportional to density and volume
m = ρ.V .....(2)
Substituting the equation (2) in (1)
W = ρ.V.g .....(3)
Density of water, ρ = 1000 kg/m³
Force is the net weight acting on the block
F = W = ρ.V.g
F = 1000 × 0.006 × 9.8
F = 58.8 N
Therefore, the buoyant force acting on the block is 58.8 N.
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Even with the best and largest telescopes, we can’t see all the stars in the milky way galaxy, even though these same telescopes can show us other galaxies. Why is that?
Because starlight cannot pass through black space, we are unable to view all of the stars in the Milky Way galaxy, even with the best and largest telescopes.
In the Milky Way galaxy, the Earth is situated. Part of it can be seen as a broad, opaque ring of stars and dust on a clear night (from sufficiently dark areas). We can see thousands of these stars with our unaided eyes, and a telescope can reveal many more.
However, a large number of the Milky Way's stars are obscured. The supermassive black hole at the centre of the galaxy and the bulge, which is made up of stars, gas, and dust, are to blame for this. The substance in this is opaque to all but the most powerful telescopes.
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