A) The army has acquired radar that can track an artillery shell in flight and determine its origin before it hits. The system erects a sensitive electronic plane over a broad area and can detect any projectile piercing that plane. After tracking the shell and plotting its path, system's computer back tracks the trajectory to the firing location. The enemy has fired a shell at the radar station. The radar detects the shell at the coordinates (400 m, 75 m) and again at (200 m, 50 m). Given that the path of a projectile projected near the surface of the earth is a parabolic, determine (i) the angle of projection of the shell and (ii) the initial velocity of projection.

Answer: its does not have any charge but it still might have nuetrons.

Explanation:

Answer:

it will change to become a positively charged ion called a cation.

Explanation:

Ions are formed when an atom gains or loses electrons from its valence shell. This process causes an imbalance between the number of positively charged protons and negatively charged electrons, so the overall ion will carry a net positive or negative charge (I got this explanation from google)

Answer:

Car B is travelling at a faster speed

Explanation:

We are given;

Speed of car A; V_a = 30 m/s

Speed of car B; V_b = 110 km/h

Now, V_a is already in m/s, so let's convert V_b to m/s too.

From conversions, 36 km/h = 10 m/s, therefore, 110 km/h would give;

(110 × 10)/36 = 30.56 m/s

Thus, V_b = 30.56 m/s

Comparing both speeds in m/s, we can see that 30.56 m/s > 30 m/s.

Thus, Car B is travelling at a faster speed.

Answer

ANSWER WITH FULL EXPLANATION

If a speed is given  km/h, then the formula to convert the speed from km/h to m/s is  

km/h = m/s

In other words, if you want to convert the given speed from km/h to m/s, then multiply the given number by  and put "m/s" after it.  

The speed of a car is 72 km/h.  

Converting the speed into m/s

72 km/h =  m/s = 20 m/s

∴ The speed of the car (expressed in m/s) is 20 m/s.

SHORT ANSWER

1km/h=5/18m/s

72km/h=72×5/18m/s

=4×5m/s

=20m/s.

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Answer:

d students show that stress can make people sick

Answer: Newton, the unit of force, is defined based on Newton's Second Law (F=ma), as the force required to give a mass of one kilogram an acceleration of 1 meter/second2. Thus, it is derived from these other units.

Explanation:

Answer:

The unit of force is a derived unit.

Why because it isn't part of the fundamental units which is MLT which stands for mass,length and time.....MLT are the units that brings out the derived units that's why it is called derived units because it is derived from fundamental units so Newton/force is not part of the fundamental unit and if we find the dimension of force you will see that it will be L^2T^-2.....which means it is derived from fundamental unit which makes it a derived unit....Thank you for the question

Answer:

a) The maximum speed of the bus is 10 m/s

b) The bus was stationary for 3 seconds

c) The total distance travelled is about 126 m

d) The average velocity of the bus is approximately 5.04 m/s

Time = distance / speed

Time = (100 km) / (5.7 km/yr)

Time = 17.5 years

If this is true, then it's not likely that any member of the species has ever traveled 100 km in its lifetime.  Weird !

Answer:

Vf = 98 m/s

Explanation:

The dime is in a free fall motion under the influence of gravity. For the final velocity of the dime, we use 1st equation of motion here:

Vf = Vi + gt

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s (Since, the initially the dime was at rest)

g = acceleration due to gravity = 9.8 m/s²

t = time taken = 10 s

Therefore, using these values, we get:

Vf = 0 m/s + (9.8 m/s²)(10 s)

Vf = 98 m/s

Answer:

The velocity is 39.24 m/s

Explanation:

The time of fall t = 4 seconds

The initial velocity u = 0 m/s  (since the ball is dropped, meaning it starts from rest)

Final velocity v = ?

Using

v = u + gt

where g is the acceleration due to gravity = 9.81 m/s^2

substituting, we'll have

v = 0 + (9.81 x 4)

v = 39.24 m/s

Answer:

100 L

Explanation:

10 dL =  1 L

Answer: C

Explanation: just did it

Answer:

C

Explanation:

edg 2021 AP Physc

Answer:

The  value is    [tex]v = 47 \  m/s[/tex]

Explanation:

From the question we are told that

   The initial  speed of the roller coaster is [tex]u =  13 \  m/s[/tex]

    The  length of the hill is  [tex]l   = 400 \  m[/tex]

    The  acceleration of the  roller coaster is [tex]a=4.0 \ m/s^2[/tex]

Generally the acceleration is mathematically represented as

      [tex]a =  \frac{ v - u}{ t_f -  t_i }[/tex]

Here  [tex]t_i[/tex] is the initial time which is equal to zero

         [tex]v_f[/tex] is the final velocity which is mathematically represented as

          [tex]v_f  =  \frac{d}{ t_f}[/tex]

So  

     [tex]a =  \frac{ \frac{d}{d_f}  - u }{ t_f - t_i}[/tex]

     [tex]4 = \frac{\frac{400}{ t_f}  - 13}{t_f - 0}[/tex]

      [tex]4 =  \frac{400 - 13t_f}{ t_f} *  \frac{1}{t_f}[/tex]

     [tex]4t_f ^2  +13f  + 400 =[/tex]

Solving this using quadratic formula we obtain

    [tex]t_f =  8.5 \ s[/tex]

     [tex]t_f =  -11.8 \ s[/tex]

Generally  time cannot be negative so

       [tex]t_f =  8.5 \ s[/tex]

Generally the  final velocity is mathematically represented as

         [tex]v = \frac{400}{8.5}[/tex]

         [tex]v = 47 \  m/s[/tex]

Answer:58 m/s

Explanation:

That’s what it says

Answer:

B) a chemical change .

Explanation:

There will be no chemical reaction when the gases ammonia and carbon dioxide are mixed together . But when there is presence of ammonium hydroxide , chemical reaction takes place between carbon dioxide and ammonium hydroxide resulting into the formation of ammonium carbonate  as follows

2NH₄OH + CO₂ =( NH₄)₂CO₃  + H₂O.

The growth of white crystals inside the bottle indicates the presence of ammonium carbonate .

So it is a chemical change .

Answer:

Explanation:

[tex]Speed = 4m/s\\Time = 2m = 120 secods\\\\Distance = ?\\Distance = Speed \times time \\\\Distance = 4 \times 12\\= 48\: meters[/tex]

The distance covered by the person is 480 meters.

We have a a person who runs at 4 m/s for 2 minutes.

We have to determine how far he had run.

The distance travelled by the body can be given by -

d = v x t

where -

v - velocity of body

t - time for which the body travelled

According to question, we have -

v = 4 m/s

t = 2 minutes = 120 seconds

Therefore, the distance travelled will be -

d = v x t

d = 4 x 120

d = 480 meters

Hence, the distance covered by the person is 480 meters.

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Answer:

4.80 seconds

Explanation:

The velocity of sound is obtained from;

V= 2d/t

Where;

V= velocity of sound = 329.2 ms-1

d= distance from the wall = 790.5 m

t= time = the unknown

t= 2d/V

t= 2 × 790.5/ 329.2

t= 4.80 seconds

Answer:

The force magnitude is 1.75 μN acting outward from the origin towards x₂

Explanation:

The given parameters, are;

The location of q₁ = The origin

The location of q₂ = 14.7 mm from q₁

The repulsive force exerted on q₂ by q₁ = 2.62 μN

The location the particle q₂ is located to =  18.0 mm from q₁

By Coulomb's law, we have;

[tex]F = k\dfrac{q_1 \times q_2 }{r^2}[/tex]

Where;

k = Coulomb constant ≈ 8.99 × 10⁹ kg·m³/(s²·C²)

r = The distance between the particles

F = The force acting between the particles

When r = 14.7 mm F = 2.62 μN

∴ q₂ × q₁ = r² × F/k = (14.7×10^(-3))²×2.62×10^(-6)/(8.9875517923^9) ≈ 1.48 × 10⁻¹⁸

q₂ × q₁ = 1.48 × 10⁻¹⁸ C²

When the distance is increased to 18.0 mm, we have;

F = (8.9875517923^9) × 1.4796647 × 10^(-18)/((18×10^(-3))²) = 1.75 × 10⁻⁶ N

∴ F = 1.75 μN.

Therefore;

The force magnitude is 1.75 μN outward from the origin towards  x₂.

To magnitude of the force that [tex]q_2[/tex] exerts on [tex]q_1[/tex] at this new location is 1.75 µN.

Given the following data:

Scientific data:

To calculate the force (magnitude and direction) that [tex]q_2[/tex] exerts on [tex]q_1[/tex] at this new location, we would apply Coulomb's law:

Mathematically, the force in an electric field is given by this formula:

[tex]F=\frac{kq_1q_2}{r^2}[/tex]

Where:

[tex]q_1q_2 =\frac{F}{k} \times r^2\\\\q_1q_2 =\frac{2.62 \times 10^{-6}}{8.99 \times 10^9} \times 0.0147^2\\\\q_1q_2 = 2.914 \times 10^{-16} \times 0.00021609\\\\q_1q_2 = 6.30 \times 10^{-20}\;C^2[/tex]

For the force, when r = 0.018:

[tex]F =\frac{8.99 \times 10^9 \times 6.30 \times 10^{-20}}{0.018^2} \\\\F =\frac{5.66 \times 10^{-10}}{0.000324} \\\\F = 1.75 \times 10^{-6}[/tex]

Note: 1 µN = [tex]1 \times 10^{-6}\;N[/tex]

Force, F = 1.75 µN.

In conclusion, the direction of the force at the new location is outward from the origin along [tex]X_2[/tex].

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Answer:

3 Mg, 2 P, 14 O, 12 H

Explanation:

Explanation:

Total displacement =30+20=50 Km

Average velocity =displacement /time

V=50/1.5=33.33km/hr

Answer:

Total Displacement: 10

Average velocity, closest option is 10.

Explanation:

30-20=10

Answer:

[tex]F=\frac{mgh-\frac{1}{2} mv^2}{d}[/tex]

Explanation:

Step 1: Write out equation

[tex]\frac{1}{2} mv^2+Fd=mgh[/tex]

Step 2: Subtract FD on both sides

[tex]\frac{1}{2} mv^2=mgh-Fd[/tex]

Step 3: Subtract mgh on both sides

[tex]\frac{1}{2} mv^2-mgh=-Fd[/tex]

Step 4: Divide both sides by -d

[tex]\frac{\frac{1}{2} mv^2-mgh}{-d} =F[/tex]

Step 5: Rewrite

[tex]F=\frac{mgh-\frac{1}{2} mv^2}{d}[/tex]

Answer:

[tex]= 4.21\times 10^{-10}J/cm^4[/tex]

Explanation:

According to the given situation, the computation is shown below:-

[tex]1kPa=10^3Pa[/tex]

So,

[tex]1Km = 10^5cm[/tex]

[tex]1kPa=0.01Pa/Cm[/tex]

[tex]1kPa=10^{-8}J/cm^4[/tex]

Now as per the question it is given that

r = 0.0421KPa/Km

= [tex]0.0421KPa/Km \times \frac{10^{-8}J/cm^4}{1KPa/Km}[/tex]

after solving the above equation we will get

= [tex]0.0421\times 10^{-8}J/cm^4[/tex]

or we can write the above equation in this manner, that is

[tex]= 4.21\times 10^{-10}J/cm^4[/tex]

Therefore we have solved the equation to reach the right answer.

Answer:

What shape is it? the formula is different depending on the shaping

Explanation:

Square P=4s

Rectangle P=2L+2W

Triangle a+b+c

Circle     P=C=2πr=πd

and so on

Answer:

Please see explanation below

Explanation:

Recall that trigonometric functions like cosine (cos) and sine (sin) of an angle are defined based on the relationships between the sides and hypotenuse of a right angle triangle:

[tex]sin(\theta)=\frac{opposite}{hypotenuse} \\cos(\theta)=\frac{adjacent}{hypotenuse}[/tex]

where the terms "opposite" and "adjacent" refer to the sides opposite and adjacent to the angle in question.

Based on such, one can solve for example for the "adjacent" side (the horizontal component of the 200 N vector you need to find) to the known angle ([tex]\theta[/tex]) in the following way:

[tex]cos(\theta)=\frac{adjacent}{hypotenuse}\\cos(\theta)=\frac{adjacent}{hypotenuse}\\cos(30^o)=\frac{adjacent}{200}\\adjacent=200\,\,cos(30^o)[/tex]

Answer:

Mary is practicing kinetic energy so she can use 1/2mv^2.

Mary is bouncing her basketball down the court and wants to find out how much mechanical energy she has, then she has to use the formula

Mechanical energy  = 1/2mv² + mgh

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy.

As total mechanical energy is the sum of all the kinetic as well as potential energy stored in the system.

ME = KE + PE

As Mary is bouncing the basketball this means it would have some kinetic energy because of the movement along with the potential energy which is due to the height of the bouncing basketball

The total kinetic energy of the basketball

KE = 1/2mv²

Similarly, the total potential energy of the basketball

PE = mgh

Thus, when Mary is bouncing her basketball down the court and has to use the formula to calculate how much mechanical energy she has.

1/2mv² + mgh = mechanical energy.

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[tex]\large{\bf{\gray{\underline{\underline{\orange{Given:}}}}}}[/tex]

Mass of rifle = 4kg

Mass of bullet = 50g = 0.05kg

Initial velocity of bullet = 35m/s

[tex]\large{\bf{\gray{\underline{\underline{\green{To\:Find:}}}}}}[/tex]

Recoil velocity of rifle.

[tex]\large{\bf{\gray{\underline{\underline{\pink{Solution:}}}}}}[/tex]

Recoil velocity of rifle is given by

[tex]\dag\:\boxed{\bf{\purple{V=-\dfrac{mv}{M}}}}[/tex]

[tex]:\implies\sf\:V=-\dfrac{mv}{M}[/tex]

[tex]:\implies\sf\:V=-\dfrac{0.05\times 35}{4}[/tex]

[tex]:\implies\sf\:V=-\dfrac{1.75}{4}[/tex]

[tex]:\implies\bf\:V=-0.437\:ms^{-1}[/tex]

[Note : -ve sign shows opposite direction]

Answer:

MgVg=MbVb.

4×Vg=0.05×35.

4Vg=1.75.

Vg=1.75/4

=0.4375 ~ 0.4m/s.

Answer:

Explanation:

b 0.2m

Answer:

D. 1.0M Fe3+

Explanation:

I just took a took a test on this exact question.

Answer:

The answer is "In any element ,all the atoms are the same".

Answer:

The trains will collide at a distance 1660 m from the station

Explanation:

Let the train traveling due north with a constant speed of 100 m/s be Train A.

Let the train traveling due south with a constant speed of 136 m/s be Train B.

From the question, Train B leaves a station 2,881 m away (that is 2,881 m away from Train A position).

Hence, the two trains would have traveled a total distance of 2,881 m by the time they collide.

∴ If train A has covered a distance [tex]x[/tex] m by the time of collision, then train B would have traveled [tex](2881 - x)[/tex] m.

Also,

At the position where the trains will collide, the two trains must have traveled for equal time, t.

That is, At the point of collision,

[tex]t_{A} = t_{B}[/tex]

[tex]t_{A}[/tex] is the time spent by train A

[tex]t_{B}[/tex] is the time spent by train B

From,

[tex]Velocity = \frac{Distance }{Time }\\[/tex]

[tex]Time = \frac{Distance}{Velocity}[/tex]

Since the time spent by the two trains is equal,

Then,

[tex]\frac{Distance_{A} }{Velocity_{A} } = \frac{Distance_{B} }{Velocity_{B} }[/tex]

[tex]{Distance_{A} = x[/tex] m

[tex]{Distance_{B} = 2881 - x[/tex] m

[tex]{Velocity_{A} = 100[/tex] m/s

[tex]{Velocity_{B} = 136[/tex] m/s

Hence,

[tex]\frac{x}{100} = \frac{2881 - x}{136}[/tex]

[tex]136(x) = 100(2881 - x)\\136x = 288100 - 100x\\136x + 100x = 288100\\236x = 288100\\x = \frac{288100}{236} \\x = 1220.76m\\[/tex]

[tex]x[/tex]≅ 1,221 m

This is the distance covered by train A by the time of collision.

Hence, Train B would have covered (2881 - 1221)m = 1660 m

Train B would have covered 1660 m by the time of collision

Since it is train B that leaves a station,

∴ The trains will collide at a distance 1660 m from the station.

Answer:

Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer

Explanation:

Given the following length measurement :

micrometer Kilometer decimeter centimeter nanometer dekameter.

Sorting in increasing order of magnitude from Smallest to Largest.

Expressing in terms of meters :

1 meter = 0.1 decameter

1 meter = 1 × 10^9 nanometer

1 meter = 1 × 10^2 centimeter

1 meter = 1 × 10^1 decimeter

1 meter = 0.001 kilometer

1 meter = 1 × 10^6 micrometers

Hence, arranging from Smallest to Largest :

Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer

Answer:

The position nature and size of an image when an object placed at a distance equal to its focal length of rear view mirrors in vehicle will be

1) Position: Behind the mirror

2) Nature: Virtual

3) Size: Smaller than the object

Explanation:

Due to the nature and use of rear view mirrors, which are meant to enable the front facing driver visualize a wide area of the back portion of the vehicle, such that the images of the object will always remain smaller than the object, require a convex image

The image size, location, nature and orientation of an object placed in front of a convex mirror is diminished, behind the mirror of the upright, virtual, and upright

Therefore, the position nature and size of an image when an object placed at a distance equal to its focal length of rear view mirrors in vehicle will be

Position: Behind the mirror

Nature: Virtual

Size: Smaller than the object.