Answer:
The value is [tex]\Delta h = 0.003 \ m[/tex]
Explanation:
From the question we are told that
The height of the water is [tex]h_1 = 10 \ cm = 0.10 \ m[/tex]
The density of oil is [tex]\rho_o = 950 \ kg/m^3[/tex]
The height of oil is [tex]h_2 = 6 \ cm = 0.06 \ m[/tex]
Given that both arms of the tube are open then the pressure on both side is the same
So
[tex]P_a = P_b[/tex]
=> Here
[tex]P_a = P_z + \rho_w * g * h[/tex]
where [tex]\rho_w[/tex] is the density of water with value [tex]\rho_w = 1000 \ kg/m^3[/tex]
and [tex]P_z[/tex] is the atmospheric pressure
and
[tex]P_b = P_z + \rho_o * g * h_2[/tex]
=> [tex]P_z + \rho_w * g * h = P_z + \rho_o * g * h_2[/tex]
=> [tex]\rho_w * h = \rho_o * h_2[/tex]
=> [tex]h = \frac{950 * 0.06 }{1000}[/tex]
=> [tex]h = 0.057 \ m[/tex]
The difference in height is evaluated as
[tex]\Delta h = 0.06 - 0.057[/tex]
[tex]\Delta h = 0.003 \ m[/tex]
Identify two types of motion where an object's speed remains the same while it continues to change direction.
Answer:
circular motionmotion of light (photons) on a non-linear pathExplanation:
Velocity is a vector with speed and direction components. If the speed does not change, then the direction must. In order to change the direction of a velocity vector, there must be some acceleration, and it must be orthogonal to the direction of motion.
Circular motion is motion that has a constant acceleration perpendicular to the direction of travel.
__
Another kind of motion that meets the requirement is the motion of light. Light travels at a constant speed, regardless. If light changes direction (as in a gravitational field or when reflected), its direction will change, but its speed will not.
In the absence of government, what would determine the way people act towards each other?
Answer:
In the absence of government, what would determine the way people act towards each other is the need to acquire means of survival such as food or shelter.
Thus, since the government regulates the rights and obligations of citizens to guarantee equal access to essential services and goods for life, in the event of the disappearance of the state as a form of social organization, people would tend to act selfishly. to provide itself with those goods and services.
Society would then return to a state of nature, where man competes with his peers for access to resources. So the need for those resources would ultimately determine the way humans relate to each other.
Throughout the absence of regulation, the necessity to gain means of subsistence, which includes extra help, would decide how individuals interact with one another.
Absence of Government:
As a consequence, while the organization governs individuals' rights and duties purpose of providing equitable access to vital services and products for life, if the community as more than just a form of social organization disappears, individuals might likely behave selfishly to offer such commodities.
The community would therefore revert to its natural condition, with man competing with equal fellows for distribution of wealth. As a result, the necessity for such resources would eventually decide how humans interact with one another.Thus the response above is right.
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which component of health related fitness is developed by performing a wall sit
Answer:
it develop isometric strength and endurance in glutes calves quadriceps,hamstring and adductor muscle
Why are experimental investigations the best type of scientific investigation o demonstrat cause-and-effect relationships?
Answer:
Isolation of Variables.
Explanation:
I am just taking a guess but Experimental investigations allow you to isolate variables (making most variables constant, allowing only the independent variable to have an impact on the dependent variable). With other scientific investigations, if they don't isolate the variables it is very possible that an unknown third variable could be skewing the results (which will result in correlation but not causation).
Answer:
Experimental investigations are the best type of scientific investigation to demonstrate cause-and-effect relationships because they allow the investigator to actively manipulate variables and control conditions. The independent variable can be isolated and manipulated, producing a change (or no change) in the dependent variable. This change can be measured to gather evidence to support or refute the cause-and-effect relationship. Experimental investigations also use a control group (a group that does not receive the factor being tested) for comparison.
Explanation:
Automated-response....it's right
A graph of x vs. t2 is linear, and intercepts the vertical axis at 12 m and the horizontal axis at 4 s2. What is the function?
Answer:
x = -3t² + 12
Explanation:
x vs t² is a line.
x = at² + b
The y intercept is 12.
x = at² + 12
At t² = 4s², x = 0.
0 = a(4) + 12
a = -3
Therefore, the function is:
x = -3t² + 12
Tim can type 2,000 words at a speed of 50 words per min.
Bob's typing speed is 80 words per min. How much less time
did Bob take than Tim to type 2000 words?
min
h
Answer: the awnser to this question is 15
Explanation:
First you will divide the typing speed and the total number of words by the speed 2000 ÷ 50
Then divide bobs typing speed by 2000 equation 2000÷80 once you get the total both you will subtract the 2 totals together and get 15 as your awnser.
Hoped this helped!
The horizontal and vertical components of the initial velocity of a projectile are 50 m/s and 120 m/s respectively. What is the magnitude of the initial velocity
Answer:
50 m/s
Explanation:
In a projectile motion, acceleration is only on the vertical plane, that is, the vertical velocity is the only velocity component that undergoes acceleration under gravitational force. The horizontal component of velocity dos not change with time, and hence is the same as the initial velocity of the projectile.
Approximately how long will it take light to travel to 1.7 AU in minutes? Use 3 × 108 m/s for the speed of light. unanswered
Answer:
14.1mins
Explanation:
We know that
Time =Distance/Speed
So
= 1.7 au/ (3 E8 m /s )
= 1.7 x 1.496 x 10^11 m /(3 x 10^8 m /s
Converting Au to meters (1.7 x 1.496 x 10^11 m)
= 847.7 s
=14.1 mins
Answer:
Time = 847.73 s = 14.12 min
Explanation:
The distance traveled by an object travelling at a constant speed is given by the following formula:
Distance = (Speed)(Time)
Time = Distance/Speed
where,
Distance = 1.7 AU
converting it into meters:
Distance = (1.7 AU)(1.496 x 10¹¹ m/1 AU) = 2.543 x 10¹¹ m
Speed = 3 x 10⁸ m/s
Therefore, using these values in the equation we get:
Time = (2.543 x 10¹¹ m)/(3 x 10⁸ m/s)
Time = 847.73 s = 14.12 min
To conduct a study on depression, you ask people to rate their depression on
a scale of 1 to 10. Their responses are a(n) ___ in your study.
A. discrete variable
B. hidden variable
C. variable
D. observation
Answer:
The answer is C variable. Just took the quiz.
Explanation:
Answer:
C. variable
Explanation:
To whom does the vha provide care for today ?
Answer:
The Veterans Health Administration (VHA) is the largest integrated health
care system in the United States, providing care at 1,255 health care
facilities, including 170 VA Medical Centers and 1,074 outpatient sites of care
of varying complexity ( VHA outpatient clinics) to over 9 million Veterans
enrolled in the VA .
Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. You blow across the open mouth of an empty test tube and produce the fundamental standing wave of the air column inside the test tube. The speed of sound in air is 344 m/s and the test tube acts as a stopped pipe. Required:a. If the length of the air column in the test tube is 14.0 cm, what is the frequency of this standing wave? b. What is the frequency of the fundamental standing wave in the air column if the test tube is half filled with water?
Answer:
a
[tex]f = 614.3 \ Hz[/tex]
b
[tex]f_h = 1229 \ Hz[/tex]
Explanation:
From the question we are told that
The speed of sound in the air is [tex]v_s = 344 \ m/s[/tex]
The length of the test tube is [tex]l = 14.0\ cm = 0.14 \ m[/tex]
Since the test tube is closed at on end the frequency is mathematically represented as
[tex]f = \frac{v_s}{ 4 l }[/tex]
=> [tex]f = \frac{344}{ 4 * 0.14 }[/tex]
=> [tex]f = 614.3 \ Hz[/tex]
From the part B the column of the test tube is half filled with water so the frequency becomes
[tex]f_h = \frac{v_s}{ 2 l }[/tex]
[tex]f_h = \frac{344}{ 2 * 0.14}[/tex]
[tex]f_h = 1229 \ Hz[/tex]
If one has twice the length of the other, what is the ratio of the diameter of the longer wire to the diameter of the shorter wire
Explanation:
The resistance of a wire is given by the formula as follows :
[tex]R=\rho \dfrac{l}{A}[/tex]
l is length of wire
A is area of cross section, [tex]A=\pi r^2[/tex]
Since, r=d/2, d = diameter
[tex]A=\pi \dfrac{d^2}{4}[/tex]
It is given in the problem that the resistance of two aluminum wires is same.
[tex]R_1=R_2\\\\\rho\dfrac{L_1}{\pi d_1^2/4}=\rho\dfrac{L_2}{\pi d_2^2/4}\\\\\dfrac{L_1}{L_2}=\dfrac{d_1^2}{d_2^2}[/tex]
We have, L₁=2L₂
So,
[tex]\dfrac{2L_2}{L_2}=\dfrac{d_1^2}{d_2^2}\\\\\dfrac{d_1^2}{d_2^2}=2\\\\\dfrac{d_1}{d_2}=\sqrt{2}[/tex]
So, the ratio of the diameter of the longer wire to the diameter of the shorter wire is [tex]\sqrt2:1[/tex]
If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance, after 10 s: How fast (speed) would it be traveling (in m/s)
Answer:
Explanation:
Using the equation of motion v = u + at to get the speed at which the object would be travelling.
v is the final speed (in m/s)
u is the initial velocity (in m/s)
a is the acceleration (in m/s²)
t is the time taken (in secs)
Given parameters
u = 0m/s
t = 10s
a = g = 9.8m/s²
Substituting this values into the formula;
v = 0+9.8(10)
v = 0+ 98
v = 98m/s
Hence the rock will be travelling at a speed of 98m/s.
A car travels in a straight line with an average velocity of 80 km/h for 2.5 h and then with an average velocity of 40 km/h for 1.Sh. What is the total displacement for the 4h trip and what is the average velocity for the total trip
Answer:
260 km
65 km/hr
Explanation:
The displacement of an object is the distance moved by that object in a particular direction.
velocity = displacement / time, therefore,
Displacement = velocity * time.
Total displacement for the 4 HR trip = displacement for 2.5 hr + displacement for 1.5 hr
total displacement = (80 * 2.5) + (40 * 1.5)
Total displacement = 200 + 60
Total displacement = 260 Km
average velocity for the total trip = total displacement / total time taken
average velocity = 260 km/ 4 hr
average velocity = 65 km/hr
A car traveling at 7 m/s accelerates at a rate of -0.8 m/s for an interval of 2 seconds.
Find the final velocity.
The nosition of a ninewood derhucar a ohraniodaturi
Answer:
6.2m/s
Explanation:
v=u+at
v=7+(-0.8/2)(2)
v=7-0.8
v=6.2m/s
State two precautions each that you will take while performing refractive index of a glass box experiment
Answer:
light should be direct
glass should not be cracked
pins should be pointed carefully
Explanation:
The harder a gas pedal in a car is pressed the faster the car's velocity increases. Which phrase best describes the relationship between how hard the gas pedal is pressed and the acceleration of the car?
A. There is both a negative correlation and causation
B. There is a positive correlation but no causation.
C. There is a negative correlation but no causation.
D. There is both a positive correlation and causation.
Answer:
D
There is both a positive correlation and causation
The relationship between how hard the gas pedal is pressed and the acceleration of the car is positive correlation and causation.
From the given statement the relationship between the cause (pedal) and the effect (velocity) can be described as direct relationship.
In direct proportionality, the outcome of one variable produces similar effect to the other variable.The harder the gas pedal in a car is pressed, the velocity increases. This shows that as the force applied to the gas pedal increases (the cause of the action), the greater the velocity of the car (the effect of the cause).
Thus, we can conclude that the relationship between how hard the gas pedal is pressed and the acceleration of the car is positive correlation and causation.
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Two students measure the speed of light. One obtains (3.001 0.001)10^8 m/s; the other obtains (2.999 0.006)10^8 m/s.Required:Which is more precise?
Answer:
(30010001) 10^8 m/s
Explanation:
Calculate the kinetic energy of an 88-kg scooter moving at 12 m/s .
Answer:
kinetic energy = 1/2 X m(v)^2
= 1/2 X 88 X 12
= 528 j
Your question has been heard loud and clear.
Kinetic energy formula= 1/2mv^2
Mass = 88kg (convert to grams because velocity is in m/s)
Mass in grams = 88000g or 88*10^3 g
Velocity= 12m/s
Now kinetic energy = 1/2 * 88000*12*12= 6336 joules
Kinetic energy = 6336 Joules or 6.336 Kilo joules
Thank you.
What is the power in D of the eyes of a woman who can see an object clearly at a distance of only 9.5 cm
Answer:
Explanation:
It is the far point an myopic person . For it she uses concave lens . For her ,
object distance u = infinity
image v = - 9.5 cm
f = ?
form the lens formula
[tex]\frac{1}{f} = \frac{1}{v} - \frac{1}{u} \\[/tex]
[tex]\frac{1}{f} = \frac{1}{-9.5} - 0 \\[/tex]
f = - 9.5 cm = - 9.5 / 100 m
P = 1 /f = - 100 / 9.5 = - 10.52 D .
Help me please !!!!!
Answer:
confounding cause they had exposure to many programmes
Answer:
Confounding should be your answer please mark brainliest
A spaceship is traveling through deep space to a space station and needs to make a course correction to go around a nebula. The captain orders the ship to travel 2.3 106 kilometers before turning 70° and traveling 1.5 106 kilometers to reach the space station. If the captain had not ordered a course correction, what would have been the magnitude and direction of the path of the spaceship if it had traveled to the space station through the nebula?
Answer:
Explanation:
Using the given values
Let
Px= 2.3 x 10^6, Py=0, Qx=1.5x10^6cos(70),
Qy= 1.5x10^6sin(70)
So let
Hx= Px+Qx=2.813 x 10^6, Hy=Py+Qy=1.401 x 10^6
Magnitude = √ ((2.813 x 10^6)^2+(1.401 x 10^6)^2)= 3.14 x 10^6
To find direction
tan စ = Hy/Hx = 1.401/2.813= 0.4980
စ = 26.5°
The magnitude and direction of the path of the spaceship if it had traveled to the space station through the nebula are 3.14 x 10⁶ m and 26.5°.
What is nebula?A nebula is a huge cloud consisting of dust and gas in space. Some nebula come from the gas and dust thrown out by the explosion of a dying star known as a supernova.
The captain orders the ship to travel in horizontal direction, Px= 2.3 x 10⁶ m, Py=0,
After turning 70° and it travels to reach the space station, Qx = 1.5x10⁶ x cos70° in horizontal direction.
and Qy= 1.5x10⁶sin70°
So, total horizontal distance moved is
Hx= Px+Qx = 2.813 x 10⁶
Total vertical distance moved is
Hy=Py+Qy = 1.401 x10⁶
Magnitude of the path = sq rt [(2.813 x 10⁶)²+(1.401 x 10⁶)²]
Path = 3.14 x 10⁶ m
Direction of the path,
tan α = Hy/Hx
tan α = 1.401/2.813
tan α = 0.4980
α = 26.5°
Thus, the magnitude and direction of the path of spaceship is 3.14 x 10⁶ m and 26.5°.
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A stretched string is 2.11 m long and has a mass of 19.5 g. When the string oscillates at 440 Hz , which is the frequency of the standard A pitch, transverse waves with a wavelength of 15.3 cm travel along the string. Calculate the tension T in the string.
Answer:
The tension of the string is 41.876 N
Explanation:
Given;
length of the string, L = 2.11 m
mass of the string, m = 19.5 g = 0.0195 kg
frequency of the wave, f = 440 Hz
wavelength, λ = 15.3 cm = 0.153 m
The velocity of the wave is given by;
v = fλ
v = 440 x 0.153
v = 67.32 m/s
Also the velocity of the wave is given by
[tex]v = \sqrt{\frac{T}{\mu} }[/tex]
where;
μ is mass per unit length = 0.0195 / 2.11 = 0.00924 kg/m
T is the tension of the string
T = v²μ
T = (67.32)²(0.00924)
T = 41.876 N
Therefore, the tension of the string is 41.876 N
Two long wires hang vertically. Wire 1 carries an upward current of 1.20 A. Wire 2, 20.0 cm to the right of wire 1, carries a downward current of 4.20 A. A third wire, wire 3, is to be hung vertically and located such that when it carries a certain current, each wire experiences no net force.
(a) Is this situation possible?
A. Yes
B. No
Is it possible in more than one way?
A. Yes
B. No
(b) Describe the position of wire 3.
distance ________ cm
direction: left of wire 1
(c) Describe the magnitude and direction of the current in wire 3.
magnitude
direction
down
Answer:
Explanation:
A, yes
b,
The force(per unit length) on wire 1 by 2 is to the left and
= μo*I1*I2/2πr
= 2*10^-7 * 1.2 * 4.2/0.20
= 5.04*10^-6N/m
From third law we have the force on wire2 by wire 1 is 5.04*10^-6N/m and to the right
So the magnitude of the force on each wire by wire 3 must be 4.2*10^-6N/m
Since the current in wire 2 is > wire 1 then wire 3 must be closer to wire 1 than 2
and wire 3 must be to the left of wire 1
Let x be the distance from wire 3 to wire 1 so x + 0.20 = distance from wire 3 to wire 2
Now μo*I1*I3/2πx = μo*I3*I2/2π(x + 0.20)
so solving for x we get
I1/x = I2/(x+0.20)
or x +0.20 = 4x
so x = 0.20/3 = 0.0667m
Now μo*I1*I3/2πx = 4.2*10^-6
so I3 = 4.2x10^-6 * 0.0667/(2.0x10^-7 * 1.2) = 1.167 A and its direction is down
If a proton and an electron are released when they are 7.00×10−10 m apart (typical atomic distances), find the initial acceleration of each of them. aelectron = nothing m/s2
Answer:
The acceleration of the proton is 2.823 x 10¹⁷ m/s²
The acceleration of the electron is 5.175 x 10²⁰ m/s²
Explanation:
Given;
distance between the electron and proton, r = 7 x 10⁻¹⁰ m
mass of proton, [tex]m_p[/tex] = 1.67 x 10⁻²⁷ kg
mass of electron, [tex]m_e[/tex] = 9.11 x 10⁻³¹ kg
The attractive force between the two charges is given by Coulomb's law;
[tex]F = \frac{k(q_p)(q_e)}{r^2}[/tex]
where;
k is Coulomb's constant = 9 x 10⁹ Nm²/c²
[tex]F = \frac{k(q_p)(q_e)}{r^2} \\\\F = \frac{(9*10^9)(1.602*10^{-19})(1.602*10^{-19})}{(7*10^{-10})^2} \\\\F = 4.714 *10^{-10} \ N[/tex]
Acceleration of proton is given by;
F = ma
[tex]F = m_pa_p\\\\a_p = \frac{F}{m_p}\\\\a_p = \frac{4.714*10^{-10}}{1.67*10^{-27}}\\\\a_p = 2.823 *10^{17} \ m/s^2[/tex]
Acceleration of the electron is given by;
[tex]F = m_ea_e\\\\a_e = \frac{F}{m_e}\\\\a_e = \frac{4.714*10^{-10}}{9.11*10^{-31}}\\\\a_e = 5.175 *10^{20} \ m/s^2[/tex]
Given:
Mass of proton, [tex]m_p = 1.67\times 10^{-27} \ kg[/tex]Mass of electron, [tex]m_e = 9.11\times 10^{-31 } \ kg[/tex]Distance between electron & proton, [tex]r = 7\times 10^{-10} \ m[/tex]By using Coulomb's law, the attractive force will be:
→ [tex]F = \frac{k(q_p) (q_e)}{r^2}[/tex]
By substituting the values, we get
[tex]= \frac{(9\times 10^9)(1.602\times 10^{-19}) (1.602\times 10^{-19})}{(7\times 10^{-10})^2}[/tex]
[tex]= 4.714\times 10^{-10} \ N[/tex]
Now,
The acceleration of proton will be:
→ [tex]F = ma[/tex]
[tex]= m_p a_p[/tex]
or,
→ [tex]a_p = \frac{F}{m_p}[/tex]
[tex]= \frac{4.714\times 10^{-10}}{1.67\times 10^{-27}}[/tex]
[tex]= 2.823\times 10^{17} \ m/s^2[/tex]
and,
The acceleration of electron will be:
→ [tex]F = m_c a_c[/tex]
or,
→ [tex]a_e = \frac{F}{m_e}[/tex]
[tex]= \frac{4.714\times 10^{-10}}{9.11\times 10^{-31}}[/tex]
[tex]= 5.175\times 10^{20} \ m/s^2[/tex]
Thus the above answer is correct.
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Which of these equations is dimensionally correct?
I. mv/ t= F
II. xv^2= Fx^3/ x^2
III. xt= vt^2+at^3
Answer: first and third.
Explanation:
An equation is dimensionally correct if the units are the same in both sides of the equation.
first, let's define the units used:
{m} = kg
{v} = m/s
{F} = kg*m/s^2
{x} = m
{t} = s
{a} = m/s^2
Now, let's analyze each option:
1) m*v/t = F
in the left side the units are:
{m}*{v}/{t} = kg*(m/s)*(1/s) = kg*m/s^2
And as is written above, these are the units of F, so this is correct.
2) x*v^2 = F*(x^3/x^2)
This is more trivial, in the right side we can see an F, that has mass units (kg) and in the left side we have x and v, and we know that none of these have mass units, so this expression is not correct.
3) xt= vt^2+at^3
the units in the right side are:
{x}*{t] = m*s
in the right side are:
{v}*{t}^2 + {a}*{t}^2 = (m/s)*s^2 + (m/s^2)*s^3 = m*s + m*s
So in both sides of the equation we have the same units, then this equation is dimensionally correct.
What is the momentum of a tiger that has a mass of 81 kg and runs with a velocity of 5.4 m/s to the east
Given :
Mass of tiger , m = 81 kg .
Velocity of tiger , v = 5.4 m/s .
To Find :
The momentum of tiger .
Solution :
We know , momentum of a body is given by the product of its mass and velocity .
[tex]P=m\times v[/tex]
Now , putting value of m and v in above equation , we get :
[tex]P=m\times v\\\\P=81\times 5.4 \ kg\ m/s\\\\P=437.4 \ kg\ m/s[/tex]
Therefore , the momentum of tiger is 437.4 kg m/s .
Hence , this is the required solution .
Answer:
437.4
Explanation: did the math
The electric flux through a spherical surface is 1.4 ✕ 105 N · m2/C. What is the net charge (in C) enclosed by the surface?
Answer:
The value is [tex]Q_{net} = 1.239 *10^{-6} \ C[/tex]
Explanation:
From the question we are told that
The electric flux is [tex]\Phi = 1.4*10^{5} \ N\cdot m^2/C[/tex]
Generally the net charge is mathematically represented as
[tex]Q_{net} = \Phi * \epsilon_o[/tex]
Here [tex]\epsilon_o[/tex] is the permetivity of free space with value
[tex]\epsilon_o = 8.85*10^{-12} \ \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2[/tex]
So
[tex]Q_{net} = 1.4*10^5 * 8.85*10^{-12}[/tex]
=> [tex]Q_{net} = 1.239 *10^{-6} \ C[/tex]
Light of wavelength 3500Å is incident on two metals A and B whose work functions are 3.2 eV and 1.9 eV respectively. Which metal will emit photoelectrons?
(a) A
(b) B
(c) Both A and B
(d) Neither A nor B
Answer:
(c) Both A and B
Explanation:
Given;
wavelength of the incident light, λ = 3500 Å = 3500 x 10⁻¹⁰ m
The energy of the incident light is given by;
E = hf
where;
h is Planck's constant = 6.626 x 10⁻³⁴ J/s
f is frequency = c / λ
[tex]E = \frac{hc}{\lambda} \\\\E = \frac{(6.626*10^{-34})(3*10^8)}{3500*10^{-10}}\\\\E = 5.68 *10^{-19} \ J\\\\E = 5.68 \ eV[/tex]
Work function is the minimum amount of energy required to liberate electrons from a metal surface.
The work function of metal A is 3.2 eV and
Th e work function of metal B is 1.9 eV
Both work functions are less than the incident energy of the light calculated as 5.68eV.
Thus, both metals will emit photoelectrons.
(c) Both A and B
"If we increase the amplitude of transverse waves on a string, what happens to the speed of a wave along the string?"
Answer:
It is increased
Explanation:
If the amplitude of a transverse wave in a string is increased, then also, the speed of that wave along the string also increases.
In transverse waves, the particles of the medium does move vertically, m either up or down and also moves at right angles to the direction of the wave. It should be noted also, that the wave amplitude of a transverse wave is defined as the difference in height between the crest(high) and the resting position(low).
The highest point particles of the medium reach is often tagged as the crest, while the lowest point is tagged as the resting position. The higher the height of the crests are, the greater the amplitude of the wave will be.