A wire is 24.5 m long at 4.00°C and is 1.40 cm longer at 34.0°C. Find the wire's coefficient of linear expansion (in (°C)−1)

Answers

Answer 1

Answer:

1.9×10⁻⁵ °C⁻¹

Explanation:

Coefficient of linear expansion: This can be defined as as increase in length of a material, per unit length per degree rise in temperature, The S.I unit is (K⁻¹).

From the question above,

α = ΔL/L(T₂-T₁)................... Equation 1

Where α = coefficient of linear expansion, ΔL = Change in length, L = original length, T₁ = Initial Temperature, T₂ = Final temperature.

Given: ΔL = 1.4 cm = 0.014 m, L = 24.5 m, T₁ = 4.00°C, T₂ = 34°C

Substitute these values into equation 1

α = 0.014/[24.5(34-4)]

α = 0.014/735

α = 1.9×10⁻⁵ °C⁻¹


Related Questions

what is force magnifier for class 6​

Answers

Answer:

I think it will helps you dude!! :)

A lens that is "optically perfect" is still limited by diffraction effects. Suppose a lens has a diameter of 150 mm and a focal length of 620 mm. A. Find the angular width (that is, the angle from the bottom to the top) of the central maximum in the diffraction pattern formed by this lens when illuminated with 520 nm light.B. What is the linear width (diameter) of the central maximum at the focal distance of the lens?

Answers

Answer:

a

  w = 8.46 *10^{-6} \  rad

b

  D  =5.24 *10^{-6}

Explanation:

From the question we are told that

   The  diameter of the lens is  [tex]d =  150 \ mm  = 150*10^{-3} \  m[/tex]

    The  focal length is  [tex]f =  620 mm =  620 *10^{-3} \  m[/tex]

    The wavelength is  [tex]\lambda  =  520 \ nm  =  520 *10^{-9} \  m[/tex]

   

Generally the angular width is mathematically represented as

       [tex]w =  2 \theta[/tex]

Here  [tex]\theta[/tex] is the angular radius of the central maxima which is mathematically represented as

        [tex]\theta =  \frac{1.22* \lambda }{ d}[/tex]

=>    [tex]\theta  =  \frac{1.22 *  520 *10^{-9}}{ 150 *10^{-3}}[/tex]

=>    [tex]4.23 *10^{-6} \  rad[/tex]

Hence

      [tex]w =  2 *  4.23 *10^{-6}[/tex]

      =>  [tex]w = 8.46 *10^{-6} \  rad[/tex]

Generally linear diameter is mathematically represented as

      [tex]D  =  2 *  R[/tex]

Where  [tex]R[/tex] is the linear radius  which is  mathematically represented as

        [tex]R =  \frac{1.22 *  f  *  \lambda  }{ d}[/tex]

=>      [tex]R= \frac{1.22 *  620 *10^{-3} *  520 *10^{-9}}{150 *10^{-3}}[/tex]

=>     [tex]R  =  2.62*10^{-6} \  m[/tex]

Thus  

    [tex]D =  2 *  2.62 *10^{-6}[/tex]

     [tex]D  =5.24 *10^{-6}[/tex]

While John is traveling along a straight inter-
state highway, he notices that the mile marker
reads 241 km. John travels until he reaches
the 145 km marker and then retraces his path
to the 174 km marker.
What is John's resultant displacement from
the 241 km marker?
Answer in units of km.

Answers

Answer:

His displacement is 260 – 169  = 91 km

His distance traveled is (260 – 134) + ( 169 – 134 ) = 161 km

Explanation:

what are the x and y components of the vector that has a magnitude of 4N and a direction of 30 degrees

Answers

Answer:

We are given

vector as 4N and direction 30°

So since X-component is

adjacent /hypotenuse which is cosine we have

= 4 cos 30 = 3.46 N

And Y-component which is opposite/hypotenuse we have

= 4 sin 30 = 2N

Powerful sports cars can go from zero to 25 m/s (about 60 mph) in 6 seconds. What is the magnitude of the acceleration, including units

Answers

Answer:

The magnitude of the acceleration is 4.2 m/s²

Explanation:

Given;

initial velocity of the powerful sports car, u = 0

final velocity of the powerful sports car, v = 25 m/s

time of motion, t = 6 seconds

Acceleration = Δv / Δt

Δv is change in velocity

Δt is change in time

The magnitude of the acceleration of the powerful sports car during the motion is given by;

[tex]a = \frac{v-u}{t}\\\\a = \frac{25-0}{6}\\\\a = 4.2 \ m/s^2[/tex]

Therefore, the magnitude of the acceleration is 4.2 m/s²

The magnitude of the acceleration is 4.2 m/s²

The calculation is as follows:

Given that

initial velocity of the powerful sports car, u = 0

final velocity of the powerful sports car, v = 25 m/s

time of motion, t = 6 seconds

Now the magnitude should be

[tex]= (25 - 0) \div 6[/tex]

=  4.2 m/s²

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A 145 lb diver stands at the end of a rigid 7 ft long diving board. What is the magnitude of the torque the diver exerts on the diving board

Answers

Answer:

Torque = 1015 ft.lb

Explanation:

Torque is defined as the turning effect of force. It is the force that can cause an object to rotate and gain some angular acceleration. Torque is basically an angular analog of force. The method to calculate torque is simple. Take the perpendicular distance from the line of action of force to the axis of rotation. Multiply this distance with the magnitude of force. The magnitude of this product gives the torque. Therefore,

Torque = (Force)(Perpendicular Distance)

Since, the diver is standing at the end of diving board.

Therefore,

Perpendicular Distance = 7 ft

Force = 145 lb

Therefore,

Torque = (145 lb)(7 ft)

Torque = 1015 ft.lb

A radio technician measures the frequency of an AM radio transmitter. The frequency is . What is the frequency in megahertz? Write your answer as a decimal.

Answers

Complete Question

A radio technician measures the frequency of an AM radio transmitter. The frequency is 14603 kHz . What is the frequency in megahertz? Write your answer as a decimal.

Answer:

The value is  [tex]x = 14.6 \ MHz[/tex]

Explanation:

From the question we are told that

  The  frequency is  [tex]f = 14603 \ kHz = 14603 *1000 = 14603000 \ Hz[/tex]

Generally  

       [tex]1 Hz \to 1.0 *10^{-6} \ MHz[/tex]

       [tex]14603000 \ Hz \to x MHz[/tex]

=>   [tex]x = \frac{14603000 * 1.0*10^{-6}}{1 }[/tex]

=>    [tex]x = 14.6 \ MHz[/tex]

A person runs around a 400 m track. What is this person’s distance? What is this person’s displacement?

Answers

Explanation:

The distance is the length of the path, or 400 m.

The displacement is the difference between the final position and the initial position.  Since the track is a circle and the end back where they started, the displacement is 0 m.

If a person runs around a 400 m track,then the distance covered by the person would be 400 meters, while the displacement covered by the person would be zero meters.

What is displacement?

An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard.

Displacement describes this shift in location.

As given in the problem If a person runs around a 400 m track, then we have to find the distance and the displacement covered by him,

The distance is 400 meters, which is how long the path is.

The distance between the end location and the starting position is known as displacement. The displacement is 0 m since the track is round and ends where it began.

Learn more about displacement here, refer to the link;

https://brainly.com/question/10919017

#SPJ2

Describe the motion of an object:
a. for which the direction of the acceleration is the same as the direction of motion of the object.
b. for which the direction of the acceleration is opposite to the direction of motion of the object.
c. for which the change in velocity is zero.
d. for which the initial velocity is zero but the acceleration is not zero.

Answers

Answer:

A. Here object is moving with increasing velocity

B. Here the object is moving with decreasing velocity that is it is decelerating

C. Here the initial and final velocity are the same so the object moves at constant velocity

D. Here the object started from rest but reached a certain velocity with time so a non zero acceleration was attained

Answer:

Answer:

A. Here object is moving with increasing velocity

B. Here the object is moving with decreasing velocity that is it is decelerating

C. Here the initial and final velocity are the same so the object moves at constant velocity

D. Here the object started from rest but reached a certain velocity with time so a non zero acceleration was attained

Explanation:

An electron is located on the x ‑axis at x0=−2.05×10−6 m . Find the magnitude and direction of the electric field at x=2.77×10−6 m on the x ‑axis due to this electron.

Answers

Answer:

The  value is  [tex]E =  62 \  N/C[/tex]

Explanation:

From the question we are told that

   The initial position of the electron  [tex]x_o  =  -2.05*10^{-6} \  m[/tex]

     The  position that is  considered [tex]x=  2.77*10^{-6} \  m[/tex]

Generally the electric field is mathematically represented as

       [tex]E =  k * \frac{q}{r^2 }[/tex]

Here k is the coulombs constant  with value  [tex]k  =  9*10^9  \  \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.[/tex]

r is  the distance covered which is mathematically represented as

         [tex]r =  x- x_o[/tex]

        [tex]r =  2.77*10^{-6} -(-2.05*10^{-6})[/tex]

         [tex]r =  4.82 *10^{-5}[/tex]

So

     [tex]E  = \frac{9*10^9 *  1.60*10^{-19}}{ (4.82 *10^{-6})}[/tex]

      [tex]E =  62 \  N/C[/tex]

     

Answer:

Direction: Negative x-direction

Explanation:

The question tells you that both lie on the   ‑axis, and the data indicate that the electron is in the negative   ‑direction from the field point ( 0< ). Because the field produced by a negative source charge points toward the source, the field in this case points in the negative   ‑direction.

Calculate the kinetic energy, in joules of a 1160-kg automobile moving at 19.0 m/s.

Answers

Answer:

Explanation:

K.E=1/2 mv²

m=1160 kg

v=19.0 m/s

so k.e=1/2*1160*(19.0)²

K.E=1/2*1160*361

K.E=1/2*418760

K.E=209380=2.0*10^5 j

Two cars, C and D, travel in the same direction on a long, straight section of highway. During a particular time interval Ato, car D is ahead of car C and is speeding up while car C is slowing down. During the interval At, it is observed that car C gains on car D (i.e., the distance between the cars decreases). Explain how this is possible, and give a specific example of such a case.

Answers

Answer:

possibly because the car is running out of gas

Explanation:

what do u mean by the activity series of metals ??

Answers

Answer:

An activity series is a list of substances ranked in order of relative reactivity. For example, magnesium metal can knock hydrogen ions out of solution, so it is considered more reactive than elemental hydrogen. The activity series is a useful guide for predicting the products of metal displacement reactions.

A 400 N steel ball is suspended by a light rope from
the ceiling. The tension in the rope is​

Answers

Answer:

As force = tension in string so tension in string is 400N

Explanation:

Tension in the rope is "400 N".

Tension is the force developed inside a flexible material or medium, such as a cable, wire, or rope. This force depends upon the externally applied load. In the case of equilibrium, the tension in a rope or string is equal to the load applied to the rope or string, externally.

Since the steel ball and the rope system is in equilibrium in our case. Therefore, the tension in the rope must be equal to the load (weight) of the steel ball:

Tension = Weight of Steel Ball

Tension = 400 N

Learn more about Tension here:

https://brainly.com/question/19802859?referrer=searchResults

https://brainly.com/question/2008782?referrer=searchResults

The attached picture shows the tension on a steel ball hung by a rope.

what is achmedis principle

Answers

Answer:

Archimedes principle states that when a body is partially/wholly/completely immersed in fluid (liquid or gas),it experiences an upthrust which is equal to the weight of the fluid displaced....

Industrial espionage is the use of spying techniques to find out key information that is of economic value.
a) true
b) false

Answers

Answer:

The given statement is "True".

Explanation:

Industrial spying or espionage seems to be the surreptitious but sometimes unconstitutional method of trying to investigate competition in the market to gain a competitive advantage throughout the commercial enterprise. The investigation's goal may be a closely guarded secret including a patented product design or formulation, or growth strategy details.

The gravitational pull of the sun on Earth keeps Earth orbiting around the sun. Which statement is correct about the force that Earth exerts on the sun?


A. Earth pulls the sun away from itself with a force equal to the ratio of the mass of the sun to the mass of Earth.

B. Earth pulls the sun toward itself with a force equal to the ratio of the mass of the sun to the mass of Earth.

C. Earth pulls the sun away from itself with an equal force.

D. Earth pulls the sun toward itself with an equal force,​

Answers

Answer:

Earth pulls the sun towards itself with a force equal to the ratio of the mass of the sun to the mass of Earth

The Earth pulls the sun toward itself with an equal force. (Option D)

According to the 3rd Newton's Law, forces existing in the universe are shown in pairs, that is to say, for all action force, there is a corresponding reaction force of equal magnitude and opposite direction. By the Newton's Law of Gravitation we understand that gravitation between the Sun and the Earth is done because of a gravitational field created by mutual interaction, in terms of their masses and distance among them. The pair of forces is not based on direct contact.

Hence, we conclude that the Earth pulls the sun toward itself with an equal force.

We kindly invite to check this question on gravitation: https://brainly.com/question/3009841

Nina and Jon are practicing an ice skating routine. Nina is standing still. Jon, who is twice as heavy as Nina, skates toward her, pushing Nina away with force f. Assuming the system is closed, which statement is correct about this system? a. Nina experiences a force equal to f/2. b. Nina experiences a force equal to f^2. c. Nina experiences a force equal to 2f. d. Nina experiences a force equal to f.

Answers

Answer:

A

Explanation:

• Nina experiences a force equal to f.

Answer:

Nina experiences a force equal to f

Explanation:

got to get that 2nd answer slot correct too before an abusive expert verifier with an alt comes in and purposely verifies the wrong answer

What is a true statement about models in science? A. Models change to accommodate new discoveries. B. Models are only used by scientists. C. Models never change. D. Models are only used by engineers.

Answers

Answer:

Models change to accommodate new discoveries

Explanation:

Owing to the dynamism of science, scientific models also change to accommodate new ideas and discoveries. Science is not a static body of knowledge. Research consistently brings new information to the fore. This propels a change in certain scientific models to accommodate the new discoveries and present a more accurate representation of phenomena in nature.

Hence, scientific models change to accommodate new discoveries.

Answer:  Models change to accommodate new discoveries.

Explanation: I took the test

Explain how your weight can change even though your mass remains the same.

Answers

Answer:

See explanation below

Explanation:

Recall that Weight is a Force that results from the action of a gravitational field on our body mass. Therefore if one changes locations to places where the acceleration of gravity is different, our weight can change although the mass of our body stays the same.

For example, going to a high mountain, where the acceleration of gravity is a little smaller than at sea level, will produce such change. Also, going to another planet with different gravitational field, or going to the Moon (where the acceleration of gravity is about 1/6 of that on Earth which therefore will reduce our weight without reducing our mass)

Since weight is calculated with the equation:

Q=mg

the weight can also change when the gravitational acceleration (g) changes.

g can change at example when you travel to a different planet or (slightly) when gaining attitude on Earth (e.g. when climbing a mountain or flying on a plane you get lighter).

Most scientific experiments are what type experiment, mostly because it is simpler and easier to test single variables? a) Natural experiment. b) Controlled experiment. c) Forced experiment. d) Redundant experiment.

Answers

Answer:

The correct answer is : option B. controlled experiments.

Explanation:

A scientific experiment which deals with a single variable at a time and compared the independent variable to a controlled variable after measuring the change in dependent variable.

It is a very simple and easy test for single variable. In these experiments subjects are divided in two groups one one, with independent variable and other variable.

Thus, the correct answer is : option B. controlled experiments.

Two tuning forks having frequencies of 460 and 464 Hz are struck simultaneously. What average frequency will you hear, and what will the beat frequency be

Answers

Answer:

462Hz, 4Hz

Explanation:

The average frequency heard would be 462 Hz because that is the average between the two and we do not hear one note more than another so the average is 462 Hz. (460+464)/2 = 462Hz. The beat frequency is basically the difference between frequencies, so our beat frequency is 464-460=4Hz.

Hope this helped!

Which of Jafar's statements are correct regarding distance and displacement?

Answers

Answer:The distance and magnitude of displacement are sometimes equal." Jafar is correct. The distance traveled and the magnitude of displacement are equal if and only if the path is a straight line in one direction.

Explanation:

what is systematic error ?​

Answers

Explanation:

Systematic error (also called systematic bias) is consistent, repeatable error associated with faulty equipment or a flawed experiment design. These errors are usually caused by measuring instruments that are incorrectly calibrated or are used incorrectly.

The simplest branched-chain hydrocarbon is

A ethane

B ethene

C  propane

D  butane

Answers

Answer:

Butane

Explanation:

What will be the force if the particle's charge is tripled and the electric field strength is halved? Give your answer in terms of F

Answers

Answer:

1.5F

Explanation:

Using

E= F/q

Where F= force

E= electric field

q=charge

F= Eq

So if qis tripled and E is halved we have

F= (E/2)3q

F= 1.5Eq=>> 1.5F

Sabiendo que la velocidad de la luz en el Cuarzo es de 194.166.099 m/s y de 203.525.090 m/s en la glicerina: a) Hallar los índices de refracción absolutos en la glicerina y en el cuarzo. b) Hallar el índice de refracción relativo del agua respecto al diamante.

Answers

Answer:

a) glycerin  n = 1.5440 , quartz n = 1.4730

b)  n₂₁ = 0.550

Explanation:

The refractive index is

        n = c / v

where c is the speed of light in a vacuum and v the speed of light in the material medium

Let's use this expression to find the indexes of refraction

a) glycerin of v= 194166099 m / s

           n = 2,998 10 8/194166099

           n = 1.5440

quartz v = 203525090 m / s

          n = 2,998 108/203525090

         n = 1.4730

b) the relative refractive index is the relationship between the absolute refractive indices of two materials

      diamond n₁ = 2.417

      water n₂ = 1.33

   

the relative refractive index

              n₂₁ = n_water / n_diamond

              n₂₁ = 1.33 / 2.417

              n₂₁ = 0.550

The term 'Zero Age Main Sequence' refers to the time when a new star stops contracting and hydrogen fusion starts.A. TrueB. False

Answers

Answer:

True

Explanation:

When a star has reached the main sequence stage, hydrogen is converted into helium by nuclear fusion, . Also, the gravity and pressure are balanced because the star does not radiate more heat than it generates. A star usually spends most of its lifetime at this stage.

The Zero Age Main Sequence is the period during the main sequence when a star stops contracting, and begin to fuse hydrogen in its core.

1. An insect inside a bus flies from the back toward the front at 2 m/s. The bus is moving in a
straight line at 20 m/s. What is the total speed of the insect as seen by a person standing
side of the road?

Answers

Myncndjjzjzjjzjzjxjxj. H h h hhcxusksjje

explain the different methods that can be used to model the motion of an object.

Answers

Answer:Even things that appear to be at rest move.

When we describe the motion of one object with

respect to another, we say that the object is moving

relative to the other object.

• A book that is at rest, relative to the table it lies

on, is moving at about 30 kilometers per second

relative to the sun.

• The book moves even faster relative to the center

of our galaxy.

Explanation:

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