a)
3. A bag contains chocolates: 3 Snickers, 5 Hershey Bars, 6 Kit-Kat Bars, 6 Milky Ways
Without replacing any of the chocolates back to the bag
a) What is the probability of selecting 2 Snickers?
b) What is the probability of selecting a Snickers and Hershey Bar in that order?
c) What is the probability of selecting a Milky Way and a Kit Kat bar in that order?

Answers

Answer 1

The probability of selecting 2 Snickers is 3/190. The probability of selecting a Snickers and Hershey Bar in that order is 3/76. The probability of selecting a Milky Way and a Kit Kat bar in that order is 18/190.

Number of Snickers = 3

Number of Hershey Bars = 5

Number of Kit-Kat Bars = 6

Number of Milky Ways = 6

Total number of chocolates = 20

a) What is the probability of selecting 2 Snickers?

= 3/20 × 2/19

= 3/190

The probability of selecting 2 Snickers is 3/190

b) What is the probability of selecting a Snickers and Hershey Bar in that order?

= 3/20 × 5/19

= 3/76

The answer is 3/76

c) What is the probability of selecting a Milky Way and a Kit Kat bar in that order

= 6/20 × 6/19

= 18/190

The probability is 18/190

Read related link on:

https://brainly.com/question/13604758


Related Questions

Which statements are true about triangle QRS?

Select
three options.

Answers

Answer:

The side opposite <Q is RS

The hypothenuse is QR

The side adjacent to <Q is QS

Step-by-step explanation:

Side RS is directly opposite <Q. The first statement provided in the options is correct.

The side that is opposite to <R is QS. The second statement in the options is not correct.

The longer leg of a right triangle is always the hypotenuse. Side QR in ∆QRS is the hypotenuse. The third statement given in the options is correct.

The side adjacent to <R is not SQ. RS is the side adjacent to <R. The fourth statement in the given options is not correct.

Side QS is adjacent to <Q. The fifth option is correct.

Answer:

A, C, E

Step-by-step explanation:

on edge! hope this helps!!~ (‐^▽^‐)

In 2004, 50 out of every 100 drivers at the National Trucking Company passed their driver's license exam on their first try. In 2005, 62 of the drivers passed on their first attempt. What was the percent increase in the passing rate?

Answers

Answer:

I believe it's a 12 percent increase.

Step-by-step explanation:

50/100= 50%

62/100= 62%

62%-50%=12%

WORTH 30 POINTS PLEASE HELP!!!!! WILL GIVE POINTS

Answers

Answer:

2/3 and 4/6

Step-by-step explanation:

2/3 and 4/6.

This is because if we take 2/3 and multiply each number by 2, we get 4/6. Therefore, they are equal.

A cupboard costing Rs.16800 is depreciated at the rate of 15% per year. What will be the cost of the cupboard after 2 years.​

Answers

Answer:

Rs. 11132

Step-by-step explanation:

formula for depriciation= P(1-R/100)^T

p= principal, r=rate, t=time

Answer:

15162

Step-by-step explanation:

after 1 year= 16800*95%= 15960

after 2 year= 15960*95%= 15162

The sum of four
consecutive odd number is 8o. Find the number​

Answers

Answer:

The sum of 4 consecutive odd number is 80

Let X be the first of these numbers

Then the next odd number is X+2

The third is X+4The fourth is X+6

All of these add up to 80

(X) + (X+2) + (X+4) + (X+6) = 80

Using the commutative and associative laws, let's transform this equation into

(X + X + X + X) + (2 + 4 + 6) = 804X + 12 = 80

Subtract 12 from both sides of the equation gives4X = 68

Divide both sides by 4 gives

X = 17

Going back to the original question:What are the 4 consecutive odd numbers: 17, 19, 21, 23Checking our answer:17 + 19 + 21 + 23 = 80 Correct!

List the angles in order from the largest to the smallest for ABC.
AB= 14, AC = 15, BC = 16

Answers

Answer:

B. ∠A, ∠B, ∠C

Step-by-step explanation:

1. Draw a model with AB as the shortest line and BC as the longest line.

∠A connects the two shortest lines, making it the largest angle.

∠B connects the shortest and the longest lines, making it the second largest angle.

∠C connects the two longest lines, making it the smallest angle.

Answer:

A > B > C

Step-by-step explanation:

Ypu probably wouldn't think about it unless someone pointed it out, but if you look at a triangle of any type you can see that the sizes of the sides are directly related to the sizes of the angles opposed to them.

By this I mean, the largest side will have the largest angle across from it and the smallest side will have the smallest angle.

Based off of my drawing, it looks like the order is angle A, then B, then, and then C.

Determine the decision criterion for rejecting the null hypothesis in the given hypothesis​ test; i.e., describe the values of the test statistic that would result in rejection of the null hypothesis. Suppose you wish to test the claim that ​, the mean value of the differences d for a population of paired​ data, is greater than 0. Given a sample of n15 and a significance level of ​0.01, what criterion would be used for rejecting the null​ hypothesis?

Answers

Answer:

reject null hypothesis if calculated t value > 2.624

Step-by-step explanation:

n = 15

To calculate degree of freedom, n -1 = 14

The claim says ud>0

The decision rule would be to reject this null hypothesis if the test statistics turns out to be greater than the critical value.

With df =14

Confidence level = 0.01

Critical value = 2.624 (for a one tailed test)

If the t value calculated is > 2.624, we reject null hypothesis.

Using the t-distribution and it's critical values, the decision rule is:

t < 2.624: Do not reject the null hypothesis.t > 2.624: Reject the null hypothesis.

At the null hypothesis, we test if the mean is not greater than 0, that is:

[tex]H_0: \mu \leq 0[/tex]

At the alternative hypothesis, we test if the mean is greater than 0, that is:

[tex]H_1: \mu > 0[/tex].

We then have to find the critical value for a right-tailed test(test if the mean is more than a value), with 15 - 1 = 14 df and a significance level of 0.01. Using a t-distribution calculator, it is [tex]t^{\ast} = 2.624[/tex].

Hence, the decision rule is, according to the test statistic t:

t < 2.624: Do not reject the null hypothesis.t > 2.624: Reject the null hypothesis.

A similar problem is given at https://brainly.com/question/13949450

If In (x) = 3.53, what is the value of x ?

Answers

I need more information please ?

A sample of a radioactive substance decayed 11% over the course of 3 weeks. How many grams were in the sample originally if 30.26 grams of the substance were remaining after the 3 weeks?

Answers

Answer:

34 grams

Step-by-step explanation:

If the remaining sample has 30.26 grams of radioactive substance, and 11% of it decayed, that means that 30.26 grams is 89% of the original. Let the original be x.

30.26=0.89x

Multiply both by one hundred

3026=89x

Divide both by 89

34=x

x=original, so the original was 34 grams.

A basketball player made 5 baskets during a game. Each basket was worth either 2 or 3 points. How many different numbers could represent the total points scored by the player?

Answers

The lowest he will get is 10 points and highest 15, 3-2=1 so minimum increment is 1. Count 10 to 15 by increment of 1 you will have 6 different numbers.

If vectors i+j+2k, i+pj+5k and 5i+3j+4k are linearly dependent, the value of p is what?​

Answers

Answer:

[tex]p = 2[/tex] if given vectors must be linearly independent.

Step-by-step explanation:

A linear combination is linearly dependent if and only if there is at least one coefficient equal to zero. If [tex]\vec u = (1,1,2)[/tex], [tex]\vec v = (1,p,5)[/tex] and [tex]\vec w = (5,3,4)[/tex], the linear combination is:

[tex]\alpha_{1}\cdot (1,1,2)+\alpha_{2}\cdot (1,p,5)+\alpha_{3}\cdot (5,3,4) =(0,0,0)[/tex]

In other words, the following system of equations must be satisfied:

[tex]\alpha_{1}+\alpha_{2}+5\cdot \alpha_{3}=0[/tex] (Eq. 1)

[tex]\alpha_{1}+p\cdot \alpha_{2}+3\cdot \alpha_{3}=0[/tex] (Eq. 2)

[tex]2\cdot \alpha_{1}+5\cdot \alpha_{2}+4\cdot \alpha_{3}=0[/tex] (Eq. 3)

By Eq. 1:

[tex]\alpha_{1} = -\alpha_{2}-5\cdot \alpha_{3}[/tex]

Eq. 1 in Eqs. 2-3:

[tex]-\alpha_{2}-5\cdot \alpha_{3}+p\cdot \alpha_{2}+3\cdot \alpha_{3}=0[/tex]

[tex]-2\cdot \alpha_{2}-10\cdot \alpha_{3}+5\cdot \alpha_{2}+4\cdot \alpha_{3}=0[/tex]

[tex](p-1)\cdot \alpha_{2}-2\cdot \alpha_{3}=0[/tex] (Eq. 2b)

[tex]3\cdot \alpha_{2}-6\cdot \alpha_{3} = 0[/tex] (Eq. 3b)

By Eq. 3b:

[tex]\alpha_{3} = \frac{1}{2}\cdot \alpha_{2}[/tex]

Eq. 3b in Eq. 2b:

[tex](p-2)\cdot \alpha_{2} = 0[/tex]

If [tex]p = 2[/tex] if given vectors must be linearly independent.

Find all complex solutions of 2x^2+x+6=0. (If there is more than one solution, separate them with commas.)

Answers

Answer:

x=-1/4+i*sqrt(47)/4 and x=x=-1/4-i*sqrt(47)/4

Step-by-step explanation:

Using quadratic formula, x=(-1±sqrt(1-48))/4.

x=-1/4+i*sqrt(47)/4 and x=x=-1/4-i*sqrt(47)/4

Answer:

If you do not understand any steps, please feel free to comment down below.

A human factor expert recommends that there be atleast 9 square ft of floor space in a classroom for every student in the class. Find the min space required for 49 students

Answers

I think the answer is 441 ft I’m sorry if it’s wrong

In a random sample of ​people, the mean driving distance to work was miles and the standard deviation was miles. Assume the population is normally distributed and use the​ t-distribution to find the margin of error and construct a ​% confidence interval for the population mean . Interpret the results. Identify the margin of error.

Answers

Complete  Question

In a random sample of  ten  people, the mean driving distance to work was  23.1 miles and the standard deviation was  6.6 miles. Assume the population is normally distributed and use the​ t-distribution to find the margin of error and construct a  99​%  confidence interval for the population mean Interpret the results.  Identify the margin of error.

Answer:

The  99% confidence interval is  [tex]16.32< \mu <29.88[/tex]

The interpretation is that there is 99% confidence that the true mean lies within the limits

The margin of error is  [tex]E = 6.783[/tex]

Step-by-step explanation:

From the question we are told that

   The sample mean is  [tex]\= x = 23.1[/tex]

     The standard deviation is  [tex]\sigma = 6.6 \ miles[/tex]

    The  sample size is  n = 10

     

Generally the degree of freedom is mathematically represented as

     [tex]df = n-1[/tex]

=>  [tex]df = 10-1[/tex]

=>  [tex]df =9[/tex]

Given that the confidence level is 99% , the n the level of significance is mathematically evaluated as

         [tex]\alpha = 100 - 99[/tex]

         [tex]\alpha =1\%[/tex]

        [tex]\alpha =0.01[/tex]

Next we obtain the critical value of  [tex]\frac{\alpha }{2}[/tex] with a df of  9  from from the student t-distribution table the value is  

          [tex]t _{\frac{\alpha }{2} , df } = 3.250[/tex]

Generally the margin of error is mathematically represented as

           [tex]E = t_{\frac{\alpha }{2} , df } * \frac{\sigma }{\sqrt{n} }[/tex]

          [tex]E = 3.250 * \frac{6.6 }{\sqrt{10} }[/tex]

         [tex]E = 6.783[/tex]

The 99% confidence interval is

      [tex]\= x - E < \mu < \= x + E[/tex]

=>   [tex]23.1 - 6.78 < \mu <23.1 + 6.78[/tex]

=>  [tex]16.32< \mu <29.88[/tex]

The interpretation is that there is 99% confidence that the true mean lies within the limits

   

       

     

eastern Aviation equipment pays bob Coleman a $1310 monthly salary plus a 12% commission on merchandise he sells each month. assume Bob's sales were $76,200 for the last month amount of commission: gross pay:​

Answers

Answer:

12/100 *76200 =$9144

so gross pay = $1310 +$9144 =$10454

In a survey of 15000 students of different schools, 40% of them were found to have tuition before the see examination. Among them 50% studied only mathematics ,30% only science and 10% studied others subject. how many student studied mathematics as well as science.

Answers

Answer:

600

Step-by-step explanation:

first, 40% of 15000 is 6000,

10% of 6000, which is the number of students studying mathematics as well as science, 600

Answer:

•600 students studied both the subject.

For real numbers x and y, what is the largest possible value of [tex]5 - (x-3)^2[/tex]?

Answers

Answer:

5

Step-by-step explanation:

Anything other than making x - 3 = 0 will make x - 3 have a value. No matter what happens  (x - 3)^2 is positive. There is a minus sign outside the brackets which makes (x - 3)^2 negative.

That means that something is always taken away from 5 unless x = 3. Try and find any value that will make a number bigger than or equal to five that isn't x = 3.

By the way, I'm assuming the question is y = 5 - (x - 3)^2



The intersection of plane A and plane S will be
The intersection of lines n and k is
Point X is the intersection of

Answers

Answer:

bjbjbfbdvdjbfv

Step-by-step explanation:

fdbfdvbdjv

If we were to make a poset of the form (A, |), where is the symbol for divisibility, which of the following sets A would yield a poset that is a total ordering?
I. A- (1, 4, 16, 64)
II. A- (1.2,3, 4, 6, 12)
III. A 1,2,3, 4, 6, 12, 18, 24)
IV. A+{1 , 2, 3, 6, 12)

Answers

Answer:

IV. A+{1, 2, 3, 6, 12}

Step-by-step explanation:

The set of natural numbers form a poset number under relation of > or =. The discrete variables are used to form a poset. The symbols for divisibility in poset form are when an integer is divided by the variable without integer. The correct answer is therefore 4th option.

Subtract 2x^2 -9x - 7 from 8x^2 -5x + 9.

Answers

Answer:

-6x² -4x -16

Step-by-step explanation:

be watchful of signs to avoid making errors

4(x/2-2) > 2y-11 which of the following inequalities is equivalent to the inequality above?
1) 4x+2y-3 > 0
2) 4x-2y+3 > 0
3) 2x+2y-3 > 0
4) 2x-26+3 > 0

Answers

4) 2x-2y+3 > 0

although it is spelt "26" on the choices

Joseph is 33 years old. Five years ago, He was twice as old as Ann. How old will Ann be in 5 years time?

Answers

Answer:

19 years old

Step-by-step explanation:

[tex]Joseph = 33 \:years \:old\\ \\Let \: ann's \:age be x\\\\33-5 = 2x\\\\28 = 2x\\\\Divide \:both \:sides \:of \:the \:equation \: by \:2\\\\\frac{2x}{2} = \frac{28}{2} \\\\x = 14\\\\Ann's \:present \:age \:= 14\\\\In \:5 \:years \:time ; \\\\14+5 = 19\\[/tex]

xThe closing price of Schnur Sporting Goods Inc. common stock is uniformly distributed between $18 and $28 per share. What is the probability that the stock price will be: More than $20? (Round your answer to 4 decimal places.)

Answers

Answer:

The  probability is [tex]P(X > 20 ) = 0.8[/tex]

Step-by-step explanation:

From the question we are told that

  The closing price of Schnur Sporting Goods Inc. common stock is uniformly distributed between $18 and $28 per share.

Given that the stock is uniformly distributed then the probability that the stock price will be more than $20 is mathematically evaluated as

       [tex]P(X > 20 ) = 1 - P(X < 20 )[/tex]

Since it is uniformly distribute  between $18 and $28 per share then we can solve is as follows

=>     [tex]P(X > 20 ) = 1 - [\frac{ 20 - 18 }{28 -18} ][/tex]

=>    [tex]P(X > 20 ) = 0.8[/tex]

Solve this inequality: 4x-8>-40

Answers

Answer:

x > - 8

Step-by-step explanation:

4x - 8 > - 40

4x > - 40 + 8

4x > - 32

Divide 4 on both sides,

4x / 4 > - 32 / 4

x > - 8

Answer:

x > 12

Step-by-step explanation:

4x - 8 > 40

Add 8 to both sides

4x > 48

Divide both sides by 4

x > 12

Diana get a gift card with a value of $55, and her favorite drink cost $2.20. How many plain black coffee can she buy with the gift card

Answers

Answer:

Twouufyjughgyuioiu567uhu888

Answer:

55/2.20=25 so 25 black coffees

Step-by-step explanation:

Find the least whole number that can replace
to make the statement true.
110< =47

Answers

Answer:

it is false

Step-by-step explanation:i cant explain but trust

football team, won 35 out of 39 games over a period of 4 years. if they keep winning pace, predict how many games you would expect them to win over the next 78 football games

Answers

Answer:

70

Step-by-step explanation:

If the team continues with same pace, they expected wins as per previous ratio:

35/39*78 = 70

Expected wins 70 out of 78 games

How many terms of the series 2 + 5 + 8 + … must be taken if their sum is 155

Answers

9514 1404 393

Answer:

  10

Step-by-step explanation:

The sum of terms of an arithmetic series is ...

  Sn = (2a +d(n -1))·n/2 = (2an +dn^2 -dn)/2

For the series with first term 2 and common difference 3, the sum is 155 for n terms, where ...

  155 = (3n^2 +n(2·2 -3))/2

Multiplying by 2, we have ...

  3n^2 +n -310 = 0 . . . . . arranged in standard form

Using the quadratic formula, the positive solution is ...

  n = (-1 +√(1 -4(3)(-310)))/(2(3)) = (-1 +√3721)/6 = (61 -1)/6 = 10

10 terms of the series will have a sum of 155.

Answer: 10 terms

Step-by-step explanation:

[tex]\displaystyle \ \Large \boldsymbol{} S_n=\frac{2a_1+d(n-1)}{2} \cdot n =155 \\\\ \frac{4+3(n-1)}{2} \cdot n =155 \\\\\\ 4n+3n^2-3n=310 \\\\ 3n^2+n-310=0 \\\\D=1+3720=3721=61^2\\\\n_1=\frac{61-1}{6} =\boxed{10} \\\\\\n_2=\frac{-61-1}{3} \ \ \o[/tex]

Find the area of the figure.

A =

Is it m, m2, or m3

Answers

Answer:

348 m^2

Step-by-step explanation:

The figure is made up of a rectangle 24 m by 12 m, and a triangle with a 24 m base and a 5 m height.

A = LW + bh/2

A = 24 m * 12 m + (24 m)(5 m)/2

A = 288 m^2 + 60 m^2

A = 348 m^2

Identify each x-value at which the slope of the tangent line to the function f(x) = 0.2x^2 + 5x − 12 belongs to the interval (-1, 1).

Answers

Answer:

Step-by-step explanation:

Hello, the slope of the tangent is the value of the derivative.

f'(x) = 2*0.2x + 5 = 0.4x + 5

So we are looking for

[tex]-1\leq f'(x) \leq 1 \\ \\<=> -1\leq 0.4x+5 \leq 1 \\ \\<=> -1-5=-6\leq 0.4x \leq 1-5=-4 \\ \\<=> \dfrac{-6}{0.4}\leq 0.4x \leq \dfrac{-4}{0.4} \\\\<=> \boxed{-15 \leq x\leq -10}[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval is (-15,-10).

What is the slope of the tangent line to a function f(x) at point x = x_0?

It is given by the derivative at x = x_0, that is:

m = f'(x_0)

In this problem, the function is:

f(x) = 0.2x^2 + 5x − 12

Hence the derivative is:

f'(x) = 0.4x + 5

For a slope of -1, we have that,

0.4x + 5 = -1

0.4x = -6

x = -15.

For a slope of 1, we have that,

0.4x + 5 = 1.

0.4x = -4

x = -10

Hence it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval is (-15,-10).

More can be learned about derivatives and tangent lines at;

brainly.com/question/8174665

#SPJ2

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