Activity
In this activity, you will examine the difference between opinions, facts, theories, and laws. To do so, examine the table
below. Carefully read each example in the table before answering the questions thatfollow.

Answer: D. 3Ag+ + PO43- = Ag3PO4

Explanation:

Overall Chemical Equation:

Ensure that the elements on both sides of the equation are balanced.

3C2H3AgO2 + Na3O4P = Ag3PO4 + 3C2H3NaO2

Solubility Equation:

Determine the state or phase of each substance (gas=g, liquid=l, solid/non-soluble=s, aqueous/soluble=aq) in its undissociated form.

3C2H3AgO2(aq) + Na3O4P(aq) = Ag3PO4(s) + 3C2H3NaO2(aq)

Complete Ionic Equation:

The complete ionic equation includes spectator ions. Write it by breaking all the soluble ionic compounds into their respective ions.

3Ag+(aq) + 3CH3COO-(aq) + 3Na+(aq) + PO43-(aq) = Ag3PO4(s) + 3Na+(aq) + 3CH3COO-(aq)

Net Ionic Equation:

The balanced net ionic equation includes only species that are involved in the reaction. It can be found by removing ions that occur on both the reactant and product side of the complete ionic equation.

3Ag+(aq) + PO43-(aq) = Ag3PO4(s)

The protons of a strong acid would be completely transferred to the solvent when dissolved.

An acid is defined as a substance that contains hydrogen that it can donate when reacting with another substance.

There are two main types of an acid which include:

A strong acid is a type of acid that has the ability to donate it's hydrogen/ protons completely in a chemical reaction.

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Answer:

2.8 moles BrO₃⁻

Explanation:

To find the amount of moles, you need to convert moles Br₂ to moles BrO₃⁻ using the mole-to-mole ratio. This ratio is made up of the balanced equation coefficients in front of the relevant molecules.

3 Br₂ + 6 OH⁻ -----> 5 Br⁻ + 1 BrO₃⁻ + 3 H₂O

8.5 moles Br₂           1 mole BrO₃⁻
-----------------------  x  ----------------------  =  2.8 moles BrO₃⁻
                                  3 moles Br₂

Answer: D) 2.37°C

Explanation:

[tex]4.39x10^5J(\frac{g°C}{4.184J} )(\frac{kg}{1000g})(\frac{1}{44.3kg} )[/tex] [tex]=2.37°C[/tex]

Answer:

See below

Explanation:

Conversion factor :  1 ft^3  = 28 .317  liters

$ 1.30 /( 17 ft^3 *  28.317 liters/ft^3)    =   $.0027  per liter  

The equation for carbon-14 emission by Radium-223 nuclei is given below:

[tex]^{223}_{88}Ra \rightarrow\: ^{209}_{82}Pb + \:^{14}_{6}C[/tex]

Radioactivity is the spontaneous decay of a substance with emission of radiation.

The equation for carbon-14 emission by Radium-223 nuclei is given below:

[tex]^{223}_{88}Ra \rightarrow\: ^{209}_{82}Pb + \:^{14}_{6}C[/tex]

In conclusion, the emission of carbon-14 by Radium-223 nuclei produces Lead-209 nuclei.

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7.32 moles of Chromium is present in 4.41 × 10²⁴ atoms.

Number of moles = [tex]\frac{\text{Given number of atoms}}{\text{Avogadro's Number}}[/tex]

Avogadro's number is the number of particles in one mole of substance. 6.022 × 10²³ is known as Avogadro's Constant / Avogadro's Number.

Avogadro's Number = 6.022 × 10²³

Now put the values in above formula we get

Number of moles = [tex]\frac{\text{Given number of atoms}}{\text{Avogadro's Number}}[/tex]

                             = [tex]\frac{4.41 \times 10^{24}}{6.022 \times 10^{23}}[/tex]

                             = 7.32 moles

Thus from the above conclusion we can say that 7.32 moles of Chromium is present in 4.41 × 10²⁴ atoms.

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Answer:

The uncertainty principle says this view is only a guess, a snapshot of what the electrons around the nucleus could possibly look like. Specifically, the uncertainty principle says that we cannot know the exact location and speed of the electrons. Therefore, the planetary-like arrangement of the electrons around the nucleus is rarely ever assumed.

Answer:

Explanation:

green

Answer:

Mg₂P₂O₇ · 3 H₂O

Explanation:

(Step 1)

First, you need to convert each mass to moles via the molar masses of each element/compound.

Molar Mass (Mg): 24.305 g/mol

4.86 grams Mg              1 mole
------------------------  x  ------------------------  = 0.200 moles Mg
                                   24.305 grams

Molar Mass (P): 30.974 g/mol

6.20 grams P              1 mole
---------------------  x  ------------------------  =  0.200 moles P
                                30.974 grams

Molar Mass (O): 15.998 g/mol

11.20 grams O               1 mole
-----------------------  x  -----------------------  =  0.700 moles O
                                  15.998 grams

Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol

Molar Mass (H₂O): 18.014 g/mol

5.40 grams H₂O               1 mole
--------------------------  x  -----------------------  =  0.300 moles H₂O
                                     18.014 grams

(Step 2)

To find the amount of each element/compound in the formula, you need to divide each molar value by the smallest molar value. This allows you to determine the accurate molar ratio the hydrated salt should have. In this case, 0.200 moles is the smallest value.

0.200 moles Mg / 0.200  =  1 mole Mg

0.200 moles P / 0.200  =  1 mole P

0.700 moles O / 0.200  =  3.5 moles O

0.300 moles H₂O / 0.200  =  1.5 moles H₂O

There can only be whole number amounts of each element/compound in the formula. Therefore, you need to multiply each amount by 2.

1 mole Mg x 2 = 2 moles Mg

1 mole P x 2 = 2 moles P

3.5 moles O x 2 = 7 moles O

1.5 moles H₂O x 2 = 3 moles H₂O

(Step 3)

Now that we know the amount of each element/compound, we can build the formula. The amount of each element is represented by subscripts and the amount of each compound (H₂O) is represented by coefficients.

Mg₂P₂O₇ · 3 H₂O

STEP 1: ON TREATING CHLOROETHANE WITH KCN WE GET PROPANE - NITRILE . STEP 2: ON TREATING PROPANE - NITRILE WITH LiAlH4 WE GET PROPANAMINE.

Answer:

A.) Change only the coefficients

Explanation:

An equation is balanced when there is an equal quantity of each type of element on both sides of a reaction. When balancing an equation, the only way to manipulate the amounts of each element is by changing the coefficient values. The coefficients alter the amount of each molecule in the reaction.

The subscripts cannot be altered. If you were to change the subscripts, you would be altering the amount of atoms in a particular molecule.

The number of photons given off will be 50 photons.

To find the answer, we need to know about the plank's equation.

                     [tex]E=-13.6(\frac{1}{(n_f)^2}- \frac{1}{(n_i)^2})eV\\[/tex]

                     [tex]n_f=4\\n_i=2\\N=50[/tex]

                  [tex]E=-13.6(\frac{1}{(4)^2}- \frac{1}{(2)^2})eV\\\\E=-13.6*-0.188=2.55eV[/tex]

                [tex]E=50*2.55eV=127.5eV[/tex]

                            E=nhf

                    [tex]n=\frac{E}{h*f} =\frac{127.5*1.67*10^{-19}J}{(6.63*10^-34)Js} \\[/tex]

                       [tex]\frac{1}{wave length}=R_H(\frac{1}{(n_i)^2}- \frac{1}{(n_f)^2})\\\\1/wv= 1.1*10^5(\frac{1}{(2)^2}- \frac{1}{(4)^2})=20625cm^{-1}.\\wavelength=486nm.[/tex]

                 [tex]f=\frac{c}{wavelength} =\frac{3*10^8}{486*10^{-9}} =6.172*10^{14}s{-1}[/tex]

                       [tex]n=\frac{E}{h*f} =\frac{127.5*1.67*10^{-19}J}{(6.63*10^-34)Js*6.17*10^{14} s^{-1}} \\\\n=52.05 photons[/tex]

Thus, we can conclude that, the number of photons given off will be 50 photons.

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The Percentage mass of NaCl is 1.78%.

The percent mass concentration of NaCl in the saline solution is determined from the molality of the solution.

The molality of the solution is further obtained from the freezing point depression formula.

The freezing point depression formula is given as follows:

where;

For the solution of NaCl;

ΔT = 0 - (-1.13) = 1.13

Kf = 1.86 °/m

i = 2

m = ΔT/(Kf * i)

m = 1.13/(1.86 * 2)

m = 0.3038 mol/kg

molar mass of NaCl = 58.5 g/mol

Mass of NaCl = 0.3038 * 58.5 = 17.8 g in

Percentage mass of NaCl = (17.8/1000) * 100

Percentage mass of NaCl = 1.78%

In conclusion, the percent mass of NaCl is obtained from the molality of the solution.

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Filling out the table of elements below following the outlined order:

An element can be defined as a substance that can not be broken down into simpler substances.

An element serves as a building blocks for compounds and mixtures.

In conclusion, each element and its property as requested in the table are given above.

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The correct option is (a) Availability of fish and furs. An incentive for profit to settle the Mississippi Valley region

Arkansas, Illinois, Iowa, Kentucky, Louisiana, Michigan, Minnesota, Mississippi, Missouri, North Dakota, Tennessee, Wisconsin, and South Dakota are among the 13 states that are either entirely or partially included in the division of Mississippi Valley region

The canoe was the first ferry to travel on the Mississippi River. Long before the white settlers ventured as far west as the Mississippi, it provided the Indians with a means of crossing. It is also one of the most significant commercial waterways in the world and a key fish and bird migration route in North America. Native Americans used the river for transportation and food while they lived along its banks.

Therefore, The correct option is (a) Availability of fish and furs. An incentive for profit to settle the Mississippi Valley region.

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Answer:

163 L

Explanation:

To find the volume, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = constant (0.0821 L*atm/mol*K)

-----> T = temperature (K)

Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.

P = 3.50 atm                         R = 0.0821 L*atm/mol*K

V = ? L                                   T = 75.3 °C + 273.15 = 348.45 K

n = 20.0 moles

PV = nRT

(3.50 atm)V = (20.0 moles)(0.0821 L*atm/mol*K)(348.45 K)

(3.50 atm)V = 572.1549

V = 163 L

Answer:

Mole Fraction (H₂O)  =  0.6303

Mole Fraction (C₂H₅OH)  =  0.3697

Explanation:

(Step 1)

Calculate the mole value of each substance using their molar masses.

Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol

Molar Mass (H₂O): 18.014 g/mol

200.0 g H₂O            1 mole
---------------------  x  ------------------  =  11.10 moles H₂O
                                 18.014 g

Molar Mass (C₂H₅OH): 2(12.011 g/mol) + 6(1.008 g/mol) + 15.998 g/mol

Molar Mass (C₂H₅OH): 46.068 g/mol

300.0 g C₂H₅OH              1 mole
----------------------------  x  --------------------  =  6.512 moles C₂H₅OH
                                         46.068 g

(Step 2)

Using the mole fraction ratio, calculate the mole fraction of each substance.

                                            moles solute
Mole Fraction  =  ------------------------------------------------
                               moles solute + moles solvent

                                                  11.10 moles H₂O
Mole Fraction  =  -------------------------------------------------------------
                               11.10 moles H₂O + 6.512 moles C₂H₅OH

Mole Fraction (H₂O)  =  0.6303

                                             6.512 moles C₂H₅OH
Mole Fraction  =  -------------------------------------------------------------
                               11.10 moles H₂O + 6.512 moles C₂H₅OH

Mole Fraction (C₂H₅OH)  =  0.3697

Taking into account the reaction stoichiometry, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.

In first place, the balanced reaction is:

C₄H₆O₃ + C₇H₆O₃ (Salicyclic Acid) →C₉H₈O₄ (aspirin) + C₂H₄O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 138 grams of salicyclic acid form 180 grams of aspirin, 2.08 grams of salicyclic acid form how much mass of aspirin?

[tex]mass of aspirin=\frac{2.08 grams of salicyclic acidx 180 grams of aspirin}{138 grams of salicyclic acid}[/tex]

mass of aspirin= 2.713 grams

Then, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.

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The concentration will be 12 M. The first option is the correct one.

It is calculated by dividing the number of moles of solute present in a solution by the volume of the solution.

In this case, the number of moles of solute = 1.2 mols

volume of solvent = 100 mL or 0.1 L

Concentration of the solution = 1.2/0.1 = 12 mol/L or 12 M

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1.506 × 10²³ molecules in  120.0 g of oxygen gas.

The slightest particle of importance contains all of the physical and chemical properties of that substance. Molecules are made up of one or more atoms.

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The concentration of solution in mass percent is 60%.

Mass percentage refer to the percentage of solute present in solution.

The concentration of substance can be expressed in mass percent.

So, we can write,

Mass percent = mass of solute / mass of solution x 100.

Mass of solution = mass of solute + solvent.

Here, sucrose is the solute and water is solvent.

Mass of solute is 1.5Kg and mass of solvent is 1Kg.

Mass of solution = 1.5 + 1 = 2.5 Kg.

Mass percent = 1.5/2.5x100

So, Concentration of solution in mass percent = 60%.

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The freezing point of the sucrose solution is -0.435°C.

The freezing point of the solution is determined from the freezing point depression formula below:

Kf(H₂O) = 1.86 Cm

m is molality of solution = moles of solute/mass of solvent

moles of sucrose = 8.0/342.3 = 0.0233 moles

m = 0.0233/0.1 = 0.233 molal

ΔT = 0.233 m * 1.86°C/m.

ΔT = 0.435 °C.

Freezing point of sucrose solution = 0°C - 0.435°C

Freezing point of sucrose solution  = -0.435°C.

In conclusion, the freezing point of sucrose solution is determined from the freezing point depression.

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Answer:

nah what questionExplanation:

The chemical equation for the reaction is [tex]2Cr (s) + 3CoCl_2 (aq) --- > 2CrCl_3 (aq) + 3Co (s)[/tex]

Chromium metal is higher in the reactivity series than cobalt. Thus, chromium will displace cobalt from solutions.

Therefore, the equation for the reaction between chromium metal and cobalt (II) chloride will be written as:

[tex]2Cr (s) + 3CoCl_2 (aq) --- > 2CrCl_3 (aq) + 3Co (s)[/tex]

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Chromium metal is immersed in an aqueous solution of cobalt(II) chloride. Express your answer as a chemical equation. Identify all of the phases in your answer. Enter no reaction if no reaction occurs.

The mass of CO2 produced will be 8.01 grams

The balanced equation of the reaction is written as:

[tex]2CaO (s) + 5C (s) --- > 2CaC_2 (s) + CO_2 (g)[/tex]

The mole ratio of CaO and C is 2:5 from the balanced equation.

Mole of 51.2 g CaO = mass/molar mass = 51.2/56 = 0.91 moles

Mole of 50.0 g C = 50/12 = 4.17 moles

From the mole ratio, 0.91 mole CaO will require 5/2 x 0.91 = 2.28 moles C.

This means 4.17 moles carbon is excessive. In other words, C is the limiting reagent.

The mole ratio of C and CO2 is 5:1. Thus, the equivalent mole of CO2 that will be produced from 0.91 moles C will be:

                                  0.91/5 = 0.182 moles.

Mass of 0.182 moles CO2 = mole x molar mass = 0.182 x 44 = 8.01 grams

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Sodium bicarbonate and acetic acid are not good substitute for sodium azide in airbags since the require more mass and produce less gas.

The chemical equation for the production of nitrogen gas from sodium azide is given below:

1 mole or 66 go of sodium azide produces 3 moles or 67.2 L of nitrogen gas.

The equation for the production of carbon dioxide from sodium bicarbonate and acetic acid is given below:

1 mole, 106 g of Na₂CO₃ and 1 mole, 82 g of CH₃COOH are required to produce 1 mole or 22.4 L of CO₂.

The mass of sodium azide required is less than that of sodium bicarbonate and acetic acid required. Also, sodium azide produces a greater volume of gas. Therefore, sodium bicarbonate and acetic acid are not good substitute for sodium azide in airbags.

In conclusion, sodium azide is a better choice in airbags.

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Answer:

boiling point can be used to tell how long something I.e water would take to boil.

boiling point can also tell us the amount if heat needed to be applied for the substance to boil

Answer:

28.0 grams CsF

Explanation:

To find the mass of CsF, you need to (1) convert grams CsXeF₇ to moles CsXeF₇ (via molar mass), then (2) convert moles CsXeF₇ to moles CsF (via mole-to-mole ratio from equation coefficients), and then (3) convert moles CsF to grams CsF (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value.

Molar Mass (CsF): 132.91 g/mol + 18.998 g/mol

Molar Mass (CsF): 151.908 g/mol

Molar Mass (CsXeF₇): 132.91 g/mol + 131.29 g/mol + 7(18.998 g/mol)

Molar Mass (CsXeF₇): 397.186 g/mol

1 CsF + XeF₆ -----> 1 CsXeF₇

73.1 g CsXeF₇             1 mole                 1 mole CsF              151.908 g
----------------------  x  --------------------  x  ------------------------  x  ------------------  =
                                  397.186 g           1 mole CsXeF₇             1 mole

=  27.958 g CsF

=  28.0 g CsF

The difference between an element and a compound is that an element is a substance made of same type of atoms, whereas a compound is made of different elements in definite proportions.Examples of elements include iron, copper, hydrogen and oxygen. Examples of compounds include water (H2O) and salt (Sodium Chloride - NaCl).