Ali was supposed to meet his friend in th evening every sunday. The first time he came at 4.30,the next time at5. 20,then at 6.30.Then at8. 00.When did he turn up the last time after that?

Answer: (-1, -2)

Step-by-step explanation:

so at first you have (1, 2)

then you were asked to reflect about y=x which is (x, y) = (y, -x)

(1, 2) = (2, -1)

then followed by y=-x which is (x, y) = (-y, -x)

(2, -1) = (-1, -2)

I hope this helps!

Answer:

22, 24, 26, 28, 30

Step-by-step explanation:

If the sum of 5 numbers is 130, that means the average of these numbers is 26.

If it is the average then it is the middle, or the third number. The two numbers before it would then be 22 and 24 by subtracting twos, and the two numbers after it would be 28 and 30 by adding twos.

22, 24, 26, 28, 30

Answer:

22,24,26,28,30

Step-by-step explanation:

I call the unknown number x

I write consecutive numbers in terms of x.

x+ (x+2) + (x+4) + (x+6) + (x+8) = 130

5x + 20 = 130

5x = (130 - 20)

5x = 110

x = 22 = smallest even number

x + 2 = 24 = second even number

x +4 = 26

x + 6 = 28

x + 8 = 30

Answer:

-(1/(x+h-3)(x-3))

Step-by-step explanation:

y=1/(x-3)

(f(x+h)-f(x))/h=(1/(x+h-3)-1/(x-3))/h=-(1/(x+h-3)(x-3))

Answer/Step-by-step explanation:

A. [tex] 4b + 3b [/tex]

Using b = 2

[tex] 4(2) + 3(2) = 8 + 6 = 14 [/tex]

Using b = 4

[tex] 4(4) + 3(4) = 16 + 12 = 28 [/tex]

Using b = 6

[tex] 4(6) + 3(6) = 24 + 18 = 42 [/tex]

Using b = 8

[tex] 4(8) + 3(8) = 32 + 24 = 56 [/tex]

Using b = 10

[tex] 4(10) + 3(10) = 40 + 30 = 70 [/tex]

Using b = 2

[tex] 4(12) + 3(12) = 48 + 36 = 84 [/tex]

B. [tex] 3(x - 2) [/tex]

Using x = 3

[tex] 3(3 - 2) = 3(1) = 3 [/tex]

Using x = 5

[tex] 3(5 - 2) = 3(3) = 9 [/tex]

Using x = 7

[tex] 3(7 - 2) = 3(5) = 15 [/tex]

Using x = 9

[tex] 3(9 - 2) = 3(7) = 21 [/tex]

Using x = 11

[tex] 3(11 - 2) = 3(9) = 27 [/tex]

Using x = 13

[tex] 3(13 - 2) = 3(11) = 33 [/tex]

C. [tex] 5(4a - 1) [/tex]

Using a = 2

[tex] 5(4(2) - 1) = 5(8 - 1) = 5(7) = 35 [/tex]

Using a = 3

[tex] 5(4(3) - 1) = 5(12 - 1) = 5(11) = 55 [/tex]

Using a = 4

[tex] 5(4(4) - 1) = 5(16 - 1) = 5(15) = 75 [/tex]

Using a = 5

[tex] 5(4(5) - 1) = 5(20 - 1) = 5(19) = 95 [/tex]

Using a = 6

[tex] 5(4(6) - 1) = 5(24 - 1) = 5(23) = 115 [/tex]

Using a = 7

[tex] 5(4(7) - 1) = 5(28 - 1) = 5(27) = 135 [/tex]

D. [tex] 6y - 2y + 4 [/tex]

Using y = 2

[tex] 6(2) - 2(2) + 4 = 12 - 4 + 4 = 12 [/tex]

Using y = 3

[tex] 6(3) - 2(3) + 4 = 18 - 6 + 4 = 18 - 2 = 16 [/tex]

Using y = 5

[tex] 6(5) - 2(5) + 4 = 30 - 10 + 4 = 30 - 6 = 24 [/tex]

Using y = 10

[tex] 6(10) - 2(10) + 4 = 60 - 20 + 4 = 60 - 16 = 44 [/tex]

Using y = 8

[tex] 6(8) - 2(8) + 4 = 48 - 16 + 4 = 48 - 12 = 36 [/tex]

Using y = 6

[tex] 6(6) - 2(6) + 4 = 36 - 12 + 4 = 36 - 8 = 28 [/tex]

Answer:

-26!!!! :))))

Step-by-step explanation:

Answer:

Please see the attached images

Step-by-step explanation:

Answer:

(0,-3)

Step-by-step explanation:

2x-y = 3

x+2y = -6

Multiply the first equation by 2 so we can eliminate y

2(2x-y =3)

4x -2y = 6

Add this to the second equation

4x -2y = 6

x+2y = -6

-----------------

5x +0y = 0

x = 0

Now find t

x+2y = -6

0+2y = -6

2y =-6

Divide by 2

y = -3

Answer:

Step-by-step explanation:

Let's try to eliminate y.

First we multiply the first equation by 2,

4x - 2y = 6

x + 2y = -6

Then we add them together

5x = 0

x = 0

Now we plug x into the first equation,

4(0) - 2y = 6

-2y = 6

y= -3

Now we plug x into the second equation,

0 + 2y = -6

2y = -6

y = -3

So our answer is,

(0,-3)

Answer:

a ≥ -1/3

Step-by-step explanation:

The square root must be greater than or equal to zero

sqrt(1+3a /25) ≥ 0

Square each side

(1+3a)/25≥ 0

Multiply each side by 25

1+3a≥0

Subtract 1

3a ≥ -1

Divide by 3

a ≥ -1/3

Answer:

Clarissa will take 10 hours by herself

Step-by-step explanation:

Let s = time for shawna

s-5 = time for clarissa

The formula for determining the time is

1/a + 1/b = 1/c  where a and b are the times alone and c is the time together

1/s + 1/(s-5) = 1/6

Multiply each side by 6s(s-5) to clear the fractions

6s(s-5) ( 1/s + 1/(s-5)) = 1/6 *6s(s-5)

Distribute

6(s-5) + 6s = s(s-5)

Distribute

6s -30 +6s = s^2 -5s

Combine like terms

12s -30 = s^2 -5s

Move everything to the right

0 = s^2 -5s -12s +30

0 = s^2 -17s +30

Factor

0 = ( s-15) (s-2)

Using the zero product property

s-15 =0   s-2 =0

s =15     s=2 ( This is not a reasonable answer since it is less than the time together)

s=15

s-5 = 10

Clarissa will take 10 hours by herself

Answer:

(-5) ^ 11

Step-by-step explanation:

(-5) ^5 / (-5) ^ -6

We know that a^ b / a^ c = a^ ( b-c)

(-5)^ (5 - -6)

(-5) ^ (5+6)

(-5) ^ 11

Answer:

-5

Step-by-step explanation:

Mathaway

Answer:

[tex]\large \boxed{\sf \bf \ \ x^2-6x+45 \ \ }[/tex]

Step-by-step explanation:

Hello, please consider the following.

You need to develop the expression.

[tex]y=(x-3)^2+36\\\\=x^2-2 * 3 * x +3^2+36\\\\=x^2-6x+9+36\\\\=x^2-6x+45[/tex]

Thank you.

Answer:

D

Step-by-step explanation:

Answer:

[tex]\boxed{=2x(x^2+6y^2)}[/tex]

Step-by-step explanation:

Remember:

[tex](a+b)(a-b)=a^2-b^2\\\\a^3+b^3=(a+b)(a^2-ab+b^2)\\\\\\(x+2y)^3+(x-2y)^3\\\\=(x+2y+x-2y)((x+2y)^2-(x+2y)(x-2y)+(x-2y)^2)\\\\=2x(x^2+4xy+4y^2-(x^2-4y^2)+x^2-4xy+4y^2)\\\\=2x(x^2+6y^2)\\[/tex]

Answer:

turn the 10 to 5 and divide 250 by 2 which will give you your l and w subract 2 from your l and add 2 to your  your w

Step-by-step explanation:

Answer:

Step-by-step explanation:

If the area is to be 250 ft^2, one possible set of dimensions would be

25 ft by 10 ft.

If 1 unit on the coordinate plane represents 10 feet, then the dimensions of the drawing would be 2.5 units by 1 unit.

Step-by-step explanation:

Total Surface Area of original cylinder

= (2×(22/7)×9)(9+24)

=18×22/7×33

=1,866.8

Total Surface Area of new cylinder

=(2×(22/7)×9/3)(9/3+24/3)

=(2×(22/7)×3)(3+8)

=6×22/7×11

=207.4

Change or Ratio of org. cylinder to new cylinder

=1,866.8/207.4

=9.0009

Answer:

a. -2

b. s = 2 and y = -5

c. (2.5, -9)

d. -7x - 2

Step-by-step explanation:

a. In the image, I have used rise over run, which is -8/4 or -2.

b. slope formula is mx + b = y, where m is slope and b is the y-intercept. In the equation 2x - 5y = -10, 2 is the slope and -5 is the y-intercept.

c. Plug in all given numbers into an equation and the ones you do not have will be in the points you need it to be. Once you graph the equation you will receive (2.5, -9).

d. y = mx + b

   5 = (-7)(-1) + b

   5 = 7 + b

   -2 = b

y = -7x - 2  

Answer:

AA Postulate

Step-by-step explanation:

The bottom lines are parallel. In this case they are also congruent. Combined with the top angle this makes in AA postulate

Answer:

500×4 =2400 I think would help u

Answer:

The equation of the perpendicular line (PR) to line PQ is; y = -0.5x - 1.5

Step-by-step explanation:

The line is perpendicular to line adjoined by points P(-3,0) and Q(0,6)

The slope of line PQ is;

Slope = change in y ÷ change in x = [tex]\frac{6 - 0}{0 -- 3}[/tex] = 2

The product of slopes of two perpendicular lines = -1

Hence the slope of line PR = -1 ÷ slope of line PQ = -1/2

Taking another point (x,y) and point P(-3,0) the equation of line PR is;

Slope = [tex]\frac{y - 0}{x - -3} = -\frac{1}{2}[/tex]

Cross-multiplying gives;

2y = -x - 3 , y = -x/2 - 3/2 , y = -0.5x - 1.5

Here Mass is constant

Using Newtons s law

[tex]\\ \sf \longmapsto F=ma[/tex]

[tex]\\ \sf \longmapsto \dfrac{F}{a}=m[/tex]

[tex]\\ \sf \longmapsto \dfrac{F_1}{a_1}=\dfrac{F_2}{a_2}[/tex]

[tex]\\ \sf \longmapsto \dfrac{8}{4}=\dfrac{F_2}{3}[/tex]

[tex]\\ \sf \longmapsto F_2=\dfrac{24}{4}[/tex]

[tex]\\ \sf \longmapsto F_2=6N[/tex]

Answer:

F = 6N

Step-by-step explanation:

Equation

F = ka

F - force

k - constant of proportionality

a - acceleration

Step 1 - find k  

8N=k*4m/s^2

k=2

Step 2 - find F

F=2*3m/s^s

F=6

6 cm from what im seeing

Answer: 7 cm

Step-by-step explanation:

Answer:

36

Step-by-step explanation:

6^2

This is 6 multiplied by itself 2 times

6*6

36

Answer:

your answer is

2 X l+b

2 X 6x + 3x

8x + 10...

Answer:

658ft

Step-by-step explanation:

you first have to calculate the angle next to that 28°angle,if you look at the two they form a 90° so to find that angle you have to subtract 90-28=62

the x is the opposite of angle 62 and the 350 si the adjacent so you can use the tan ratio to find the answer

tan62=opposite/adjacent

tan62=y/350

y=tan62×350

=658ft

I hope this helps

Answer:

12.5

Step-by-step explanation:

2.5 * 5 = 12.5

Answer:

(7,-4) ; 12

Step-by-step explanation:

Basically, three corners of a rectangle are already on the graph. If you put a dot at (7,-4), that is the last corner(vertex) that finishes the rectangle

Then to find base of the rectangle, you find the length of the longer side, (the distance between the x coordinates). So you would subtract -5 from 7 and get 12, and 12 is the length of your base.

Answer:

perimeter=40m

Step-by-step explanation:

PERIMETER=(AREA ROOT)*4

                   =10*4=40m

Answer:

The expression (-root3·a - a)², can be simplified into the form a² × (4 + 2·√3)

Step-by-step explanation:

The given expression can be written as follows;

(-root3·a - a)² = (-√3·a - a)²

Which can be expanded to give;

(-√3·a - a) × (-√3·a - a) = 3·a² + 2·√3·a² +a²

We collect like terms to get;

3·a² + 2·√3·a² +a² =  3·a² +a²+ 2·√3·a² = 4·a² + 2·√3·a²

We factorize out the common coefficients of the terms  to have;

4·a² + 2·√3·a² = a² × (4 + 2·√3)

Which gives the initial expression (-root3·a - a)², to presented in the form a² × (4 + 2·√3).

Answer/Step-by-step explanation:

a. The sides of ∆ABC can be labelled as follows, taking θ as the reference point.

Adjacent = side AB

Opposite = side BC

Hypotenuse = side AC

b. I. "<B is an acute angle" => FALSE. It is a right angle (90°)

II. "The side opposite to <C is BC" => FALSE. The side opposite to <C is AB.

III. The side adjacent to <A is AB => TRUE

IV. The side opposite to <B is not the longest. => FALSE. It is the hypotenuse and the longest side.

c. Cos θ = [tex] \frac{adjacent}{hypotenuse} = \frac{AB}{AC} [/tex]

Tan θ = [tex] \frac{opposite}{adjacent} = \frac{BC}{AB} [/tex]

d. Sin C = [tex] \frac{opp}{hypo} = \frac{AB}{AC} [/tex]

Cos C = [tex] \frac{adjacent}{hypotenuse} = \frac{BC}{AC} [/tex]

Tan C = [tex] \frac{opp}{adjacent} = \frac{AB}{BC} [/tex]