an Alpha particle moving in north direction give reasons​

Answers

Answer 1

Your question has been heard loud and clear.

An alpha particle , can move in any direction randomly. But with a magnetic field , we can deflect the alpha particle in any direction we want.

So , the magnetic field must be placed to the west of the alpha particle , so that the particle gets deflected and moves towards the north direction.

Thank you.

Answer 2

Like AL2006 said reasons for what


Related Questions

If three forces are equal and their resultant force is zero, then measure of its internal angle is: a)0° b)90° c)60° d)45°

Answers

Answer:

60

Explanation:

As the forces are equal and resultant force is 0 , it forms an equilateral triangle and equilateral triangle has an angle of 60 degrees

Hope this Helps U...,

thank u

what is force magnifier​

Answers

Answer:

It is an instrument which increases the amount of force available to a single hypothetical person.

Examples;

Levers, pulleys are force magnifiers.

How many electrons flow through a point in a wire in 7.00 s if there is a constant current of I = 4.35 A?

Answers

Answer:

1.90×10²⁰ Electrons

Explanation:

From the question,

Q = It.................... Equation 1

Where Q = charge flowing through the wire, I = current, t = time

Given: I = 4.35 A, t = 7.00 s

Substitute these values into equation 1

Q = 4.35(7.00)

Q = 30.45 C.

But,

1 electron contains 1.6×10⁻¹⁹ C

therefore,

30.45 C = 30.45/1.6×10⁻¹⁹  electrons

= 1.90×10²⁰ Electrons

A pure copper sphere has a radius of 0.935 in. How many copper atoms does it contain? [The volume of a sphere is (4>3)pr3 and the density of copper is 8.96 g>cm3.]

Answers

Answer:

47.68 x 10²³ or 4.768 x 10²⁴ copper atoms

Explanation:

Given:

Radius of the copper sphere (r) = 0.935 in

First convert the radius from inches to centimeters

1 in = 2.54cm

0.935in =  0.935 x 2.54cm = 2.3749cm

∴ r = 2.3749cm

Calculate the volume of the copper sphere as follows

Volume = [tex]\frac{4}{3}\pi r^{3}[/tex]          [substitute r = 2.3749cm and π = 22 / 7]

Volume = [tex]\frac{4}{3}(\frac{22}{7} ) (2.3749)^{3}[/tex]

Volume = 56.108cm³

From the volume and given density, calculate the mass of the copper sphere

mass = density x volume           [density = 8.96g/cm³]

mass = 8.96 x 56.108 = 502.73g

From known facts

1 mole of copper = 63.5g of copper = 6.022 x 10²³ copper atoms.

Then,

502.73 g of copper = [tex]\frac{502.73 * 6.022*10^{23}}{63.5}[/tex]  = 47.68 x 10²³ copper atoms

Therefore, the sphere contains 47.68 x 10²³ copper atoms

Answer:

=4.8*10^-24atoms

Explanation:

To find volume of a sphere

= 5.61*10^-5m³ x 8.96gx 100³m³

=502.7g

So we use density of copper to convert volume to mass so

1atm of cux( 1mol of cu/6.02Eatm of cu)*(63.54g of cu/1 mole of cu)

So = 1.055*10-22g cu

So

= 502.7/1.055*10-22g cu

=4.8*10^-24atoms

A wooden artifact is found in an ancient tomb. Its carbon-14 14 6 C activity is measured to be 55.0% of that in a fresh sample of wood from the same region. Assuming the same amount of 14C was initially present in the artifact as is now contained in the fresh sample, determine the age of the artifact (in years)

Answers

Answer:

[tex] t = 4.942\times10^{3}[/tex]

Explanation:

we know that

[tex]t =-\frac{ln\frac{R}{R_0} }{\lambda}[/tex]

the symbols have their usual meaning

Also,

[tex]t=-T_{1/2}\frac{ln\frac{R}{R_0} }{ln2}[/tex]

now plugging the values we get

[tex]t=-5730\frac{ln(0.55) }{ln(2)}[/tex]

[tex] t = 4.942\times10^{3}[/tex]  years

A car is traveling at a speed of 80 ft/s when the brakes are suddenly applied, causing a constant deceleration of 10 ft/s2. Determine the time required to stop the car and the distance traveled before stopping.

Answers

Answer:

Time taken = 8 second

Distance traveled = 320 ft

Explanation:

Given:

Initial velocity (u) = 80 ft/s

Acceleration (a) = (-)10 ft/s²

Final velocity (v) = 0 ft/s

Find:

Time taken

Distance traveled

Computation:

v = u + at

0 = 80 + (-10)(t)

t = 8 second

Time taken = 8 second

s = ut + (1/2)(a)(t)²

s = (80)(8) + (1/2)(-10)(8)²

s = 320 ft

Distance traveled = 320 ft

The north pole of a bar magnet points towards a thin circular coil of wire containing 40 turns. The magnet is moved away from the coil, so that the ux through one turn inside the coil decreases by ∆Φ = 0.3 T.m2 in a time ∆t = 0.2 s. What is the average EMF induced in the (whole) coil during this time interval? Viewed from the side opposite of the bar magnet (from the right), does the induced current run clockwise or counterclockwise? Explain briey. [2 p.]

Answers

Answer:

60 V

Current will flow anticlockwise from the right side of the magnet.

Explanation:

The number of turns on the coil = 40 turns

The magnetic flux changes by ∆Φ = 0.3 T.m^2

The time changes by ∆t = 0.2 s

The induced emf can be gotten as

E = N∆Φ/∆t

substituting values, we have

E = (40 x 0.3)/0.2 = 60 V

If we move the magnet away from the coil, then from Lenz law, the induced current on the coil will try to oppose the motion of the magnet by attracting the magnet towards the coil. For this to happen, the coil must possess the equivalent of a magnetic south pole. For the equivalent of a magnetic south pole, the current on the coil will flow in the clockwise direction when viewed from the left side of the magnet. This will appear as an anticlockwise direction, when viewed from the right side of the magnet.

What voltage battery would you need to send 2.5A of current through a light bulb of resistance 3.6 ohm

Answers

Given :

Current flow light bulb = 2.5[tex]\sf{A}[/tex]

Resistance of light bulb = 3.6Ω

To Find :

We have to find voltage of battery[tex].[/tex]

Solution :

➠ As per ohm's law, current flow through a conductor is directly proportional to the applied potential difference.

➝ V ∝ I

V = I × R

Where, R is the resistance of conductor.

⇒ V = I × R

⇒ V = 2.5 × 3.6

V = 9 volt

Place these bodies of our solar system in the proper order of formation

Answers

Answer:

solar nebula, the sun, planetesimals, inner planets, and last but not least outer planets

Answer:

Solar nebula, The sun, planetesimals , inner planets, outer planets

Explanation:

You are throwing a stone straight-up in the absence of air friction. The stone is caught at the same height from which it was thrown. the speed of the stone when thrown is equal to the speed when caught.A. TrueB. False

Answers

Answer:

A. True

Explanation:

When a stone is thrown straight-up, it has an initial velocity which decreases gradually as the stone move to maximum height due to constant acceleration due to gravity acting downward on the stone, at the maximum height the final velocity of the stone is zero. As the stone descends the velocity starts to increase and becomes maximum  before it hits the ground.

Height of the motion is given by;

[tex]H = \frac{u^2}{2g}[/tex]

g is acceleration due to gravity which is constant

H is height traveled

u is the speed of throw, which determines the value of height traveled.

Therefore, when the stone is caught at the same height from which it was thrown in the absence of air resistance, the speed of the stone when thrown will be equal to the speed when caught.

explain the different methods that can be used to model the motion of an object.

Answers

In physics, motion is the phenomenon in which an object changes its position over time. Motion is mathematically described in terms of displacement, distance, velocity, acceleration, speed, and time. The motion of a body is observed by attaching a frame of reference to an observer and measuring the change in position of the body relative to that frame with change in time. The branch of physics describing the motion of objects without reference to its cause is kinematics; the branch studying forces and their effect on motion is dynamics.

Answer:

You can describe the motion of an object by its position, speed, direction, and acceleration. An object is moving if its position relative to a fixed point is changing. idk if this helps.

Explanation:  

1. Explain the difference between accuracy and precision 2. Name a statistical quantity that can be used to indicate an accuracy level. 3. Name a statistical quantity that can be used to indicate a precision level. 4. To what level of accuracy (1 cm, 0.1 cm, 0.01 cm. 0.001 cm) can the ruler used to measure the lengths of the pencil in the above example be read?

Answers

Answer:

Accuracy explains the closeness or nearness of a measured or studied quantity to the actual value while precision explains the ability of a measuring device to get the same measured value when measured repeatedly

2 Accuracy is determined by percentage error while precision is by taking the ratio of standard deviation with the individual measurements

3. The accuracy of the ruler is 0.001 cm because that's the least measurement it can take

Which best describes those that can pass through? They are concentrated. They are soluble. They are diluted. They are heated.

Answers

Answer:

B

Explanation:

SmARt

The term “solubility” describes a property that describes a substance's capacity to dissolve in a solvent. It is calculated as the highest solute concentration that can be dissolved in a solvent at equilibrium. A saturated solution is the term used to describe the outcome. Thus, option B is correct.

What best describes those that can pass through?

The solute is the substance that dissolves. The solvent is the material that dissolves it. Solvents and solutes can exist in any material state. Water is a strongly polar substance, making it a very good solvent for many solutes.

Because they share chemical characteristics with the plasma membrane, some substances can pass through it. Which definition best sums up those who can pass through? They focus intensely. They dissolve easily.

Therefore, The maximum amount of a chemical that will dissolve in a given amount of solvent at a given temperature is referred to as its solubility.

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A man has a total of 200 apples divided evenly among 5 boxes. How many apples are in each box?
. What are the units for your answer?
/

Answers

Answer:

40 units

Explanation:

200 divided evenly by 5 is 40. Therefore there are 40 units

(200 apples) / (5 boxes) = 40 apple/box

What is the magnitude of the force of a +25 microCoulomb charge exerts on a +2.5 miliCoulomb charge 28 cm away?

Answers

Answer:

7.175 N

Explanation:

From coulomb's law of electrostatics,

F = kQq/r²........................... Equation 1

Where F = magnitude of the force, M = first Charge, q = second Charge, r = distance between the charges and k = coulomb's constant

Given: Q = +25 micro-Coulomb = + 25×10⁻⁶ C, q = +2.5 micro-coulomb = +2.5×10⁻⁶ C, r = 28 cm = 0.28 m.

Constant: k = 9×10⁹ Nm²/C²

Substitute these values into equation 1

F = 9×10⁹(25×10⁻⁶)(2.5×10⁻⁶)/ 0.28²

F = 562.5×10⁻³/0.0784

F = 7.175 N

White light is shining on the surface of a soap bubble, which has the same index of refraction as water. Find the minimum thickness, in nanometers, of a soap bubble which appears red (a wavelength of 725 nm) when the light is perpendicular to its surface.

Answers

Answer:

The minimum thickness is  [tex]t = 1.363 *10^{-7} \ m[/tex]

Explanation:

From the question we are told that

   The  index of refraction of the bubble is  [tex]n = 1.33[/tex] =  index of refraction of water

    The wavelength is  [tex]\lambda =725nm = 725 *10^{-9} \ m[/tex]

Generally the condition for constructive interference is  mathematically represented as

       [tex]2 * t = [m + \frac{1}{2} ] * \frac{\lambda }{n}[/tex]

Now t is the thickness and at minimum t,   m(order of maximum ) = 0  

So

    [tex]2 * t = [0 + \frac{1}{2} ] * \frac{ 725 *10^{-9} }{ 1.33}[/tex]

=>    [tex]t = 1.363 *10^{-7} \ m[/tex]

Light of wavelength 500 nm illuminates a round 0.50-mm diameter hole. A screen is placed 6.0 m behind the slit.. Find the width of the central maximum on the screen.
A) 6.0 mm.
B) 12 mm.
C) 260 mm.
D) 7.3 mm.
E) 15 mm.

Answers

Answer:

15mm

Explanation:

We know that for circular holes first dark spot is given by

sin စ = 1.22 λ/D

Also we know that at the same time

tan စ = r/L

So

r = L tanစ = 6 x tan( arcsin(1.22x 500 x10^9/0.50 x 10^ 3))

= 0.0073 m = 7.3 mm

However since the size is twice that so 14.6 mm which is approx 15mm

El tubo de entrada que suministra presión de aire para operar un gato hidráulico tiene 2 cm de diámetro. El pistón de salida es de 32 cm de diámetro. ¿Qué presión de aire se tendrá de aire se tendrá que usar para levantar un automóvil de 17,640 N?`

Answers

Answer:

P₁ = 219.3 Pa

Explanation:

This fluid mechanics problem, we can use that the pressure is distributed with the same value throughout the system, which is Pascal's principle.

Let's use the subinidce1 for the small diameter and the subscript 2 for the larger diameter.

              P₁ = P₂

pressure is defined by

             P = F / A

we subtitute

             F₁ / A₁ = F₂ / A₂

             F₁ = F₂ A₁ / A₂

the area in a circle is

             A = π r² = π d² / 4

we substitute

            F₁ = F₂ (d₁ / d₂)²

we calculate

           F₁ = 17640 (2/32)²

           F₁ = 68.9 N

Having the force to be applied we can find the air pressure on the small plunger

          P₁ = F₁ / A₁

          P₁ = F₁ 4 / π d₁²

let's calculate

          P₁ = 68.9 4 / (π 0.02²)

          P₁ = 219.3 Pa

Momentum of 0.5 kg moving ball with the velocity of 5 m / s ​

Answers

Answer:

2.5

Explanation:

Momentum = Mass × Velocity

Answer:

[tex] \boxed{ \bold{ \huge{\boxed{ \sf{2.5 \: kg \: m \: / \: s}}}}}[/tex]

Explanation:

Mass ( m ) = 0.5 kg

Velocity ( v ) = 5 m / s

Momentum ( p ) = ?

Finding the momentum

[tex] \boxed{ \sf{momentum \: ( \: p \: ) \: = \: mass \: \times \: velocity}}[/tex]

⇒[tex] \sf{momentum \: = \: 0.5 kg \times 5 \: meter \: \: per \: second}[/tex]

⇒[tex] \sf{momentum = 2.5 \: kg \: m \: / \: s}[/tex]

Hope I helped!

Best regards! :D

A proton is located at <3 x 10^-10> m. What is r, the vector from the origin to the location of the proton

Answers

Complete Question

A proton is located at <3 x 10^{-10}, -5*10^{-10}  , -5*10^{-10}> m. What is r, the vector from the origin to the location of the proton

Answer:

The  vector position is   [tex]\=r=<3*10^{-10}i-5*10^{-10}j -5*10^{-10}k>[/tex]

Explanation:

From the question we are told that

  The  position of the proton is [tex]<3 * 10^{-10}, -5*10^{-10}  , -5*10^{-10}> m[/tex]

Generally the vector location of the proton is mathematically represented as

       [tex]\= r = <xi  + yj  + zk>[/tex]

So substituting values

     [tex]\=r=<3*10^{-10}i-5*10^{-10}j -5*10^{-10}k>[/tex]

What approximately is the percent uncertainty for a measurement given as 1.57 m^2?

Answers

Answer:

The value is   [tex]u =  0.64[/tex]%

Explanation:

From the question we are told that

  The measurement is  [tex]A =  1.57 \ m^2[/tex]

The  percent uncertainty is mathematically evaluated as

       [tex]u =  \frac{0.01 * 100}{A}[/tex]

Here 0.01 is uesd due to the fact that the value given is in three decimal places

     [tex]u =  0.64[/tex]%

     

The approximately percent uncertainty for the measurement is 0.64%.

The given parameters:

Area of the measurement, A = 1.57 m²

The uncertainty in the measurement of the area = ±0.01 m²

The approximately percent uncertainty for the measurement is calculated as follows;

[tex]Uncertainty = \frac{0.01}{1.57} \times 100\%\\\\Uncertainty = 0.64 \ \%[/tex]

Thus, the approximately percent uncertainty for the measurement is 0.64%.

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As astronaut visiting Planet X, you’re assigned to measure the free-fall acceleration. Getting out your meter stick and stopwatch, you time the fall of a heavy ball from several Heights. You data is as follows:
Height (m) Fall Time (s)
0.0 0.00
1.0 0.54
2.0 0.72
3.0 0.91
4.0 1.01
5.0 1.17
a.) Analyze these data to determine the free-fall acceleration on Planet X. Your analysis should involve fitting a straight lie to an appropriate graph. Place the graph here. (Hint Kinematics)
b.) Determine the uncertainty in the free-fall acceleration.

Answers

Answer:

g = (0.13 + - 0.05) m / s²

Explanation:

a) The equations of physics are valid in all inertial systems, therefore the kinematic relationships on this planet are the same as on Earth.

        y = v₀ t - ½ g t²

From the statement it follows that the body is released, so its initial velocity is zero

        y = 1/2 g t²

where we take the downward direction as positive

With this expression to make a linear graph we must graph t² vs y, see attached.  Observe that the controlled variable is the height, so this is the independent variable and must go on the x axis, the values ​​of the slope and point of cut can be obtained from this graph  by lineal regretion

           y ’= m x + b

           y ’= 0.2668 x + 0.00406

If we compare this equation of the line with the equation of free fall

          y ’= t2

          x = y

          m = 0.2668

          b = 0.00406

Since the value of b is very small, we can say that our assumption that the initial velocity is zero is correct.

Now we can compare the expressions of free fall and the equation of the line obtained

             y = ½ g t2

             y ’= m x

to be functionally equivalent

            x = 1 / m y '

now we can see the slope

          1 / m = ½ g

          g = 2 / m

          g = 2 / 0.2668

          g = 7.496 m / s²

b) the uncertainty of the acceleration is

          Δg = dg/dm   Δm

the uncertainty of m is given by the fit of the linear regression of the program Δm = 0.025

          dg / dm = 1 / 2m

           

           Δg = 1 /2m  Δm

           Δg = 1 / (2 0.2668) 0.025

           Δg = 0.047

The result of this exercise with the correct significant figures

          g = (0.13 + - 0.05) m / s²

A light plane must reach a speed of 33 m/s for takeoff. How long a runway is needed if the constant acceleration is 3.0 m/s2

Answers

Answer:

181.5 m

Explanation:

From the question,

Applying the equation of motion,

v² = u²+2as................. Equation 1

Where a = acceleration of the light plane, v = final velocity of the light plane, u = initial velocity of the light plane, s = length of the runway.

make s the subject of formula in equation 1

s = (v²-u²)/2a.............. Equation 2

Given: v = 33 m/s, u = 0 m/s(from rest), a = 3.0 m/s²

Substitute these values into equation 2

s = (33²-0²)/(2×3)

s = 1089/6

s = 181.5 m

What replaced copper wires in long distance communicationas they are cheaper and less bulky than copper cables carrying the same information

Answers

Answer:

Optical Fiber

Explanation:

Optical fibers have replaced copper wire in long distance communication as they are cheaper and less bulky than copper cables carrying the same information. Optical Fibers transfer information from one place to another by sending pulses of infrared light signals. Light act as carrier waves.

2. The higher the temperature of water, the faster the egg will cook. What
is the dependent variable? *
A. the stove
B. the egg
C.temperature of water
D. the person stirring

Answers

Answer:

The dependent variable is the cook time of the egg

The higher the temperature of the water, the faster the egg will cook, then the dependent variable is the temperature of the water, therefore the correct answer is the option C

What is thermal energy?

It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.

Thermal energy can be produced with help of various means such as by burning fossil fuels, with the help of solar energy.

The correct direction for heat flow is from hot to cold because heat always moves naturally from a higher thermal potential to a lower thermal potential unless additional work is provided by an external machine.

Thus, The dependent variable is the water's temperature, and since the egg will cook more quickly at higher water temperatures, option C is the best choice.

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How is the radiating electric field (or electromagnetic signal) produced when radio stations broadcast

Answers

Answer:

Radio stations have dipole type antennas

this field increases in intensity and propagates outwards,

Explanation:

Radio stations have dipole type antennas, that is, all sides are isolated from each other, when the AC signal from the radio station arrives, the lcharge begins at times and by the Lens law a field appears that opposes this movement, this field increases in intensity and propagates outwards, when the voltage reaches a maximum, the generated wave also reaches the maximum, now the incident wave begins to decrease, an electric hand appears to oppose this prisoner, and in this way a cap is created. electric .

"If we increase the frequency of transverse waves on a string, what happens to the period of oscillation of any given point on the string?"

Answers

Answer:

Period will decrease

Explanation:

Because from the relationship

T = K/f

Period inversely proportional to frequency so as frequency increase period decrease and vice versa

LAGOS PROVINCE 10
TEXT:
TOPIC
SPEAKER
DATE:
s
Sussend
5 Gorg
ve
Cand
care. The pre
density is haragin
cable?
s
terson​

Answers

Answer:

Explanation:

what?

A 550 lines/mm diffraction grating is illuminated by light of wavelength 500 nm . Part A How many bright fringes are seen on a 3.8-m-wide screen located 2.2 m behind the grating?

Answers

Answer:

7bright fringes

Explanation:

First we know that

Sinစ m,max= Mmax, x lambda/d

To find Mmax

Sin90° = Mmax x lambda/d = 1

So

Mmax= d/ lambda

= lambda= 500nm

d= 1/550mm

So

= 1.8 x10-6/500x 10^-9m

= 3.6

So m is approx 3

So 3 bright fringes above below and the central bright fringe itself making 7bright fringes

Fluid flows at 2.0 m/s through a pipe of diameter 3.0 cm. What is the volume flow rate of the fluid?

Answers

Answer:

The volume flow rate of the pipe is 1.41 x 10⁻³ m³/s

Explanation:

Given;

velocity of the fluid, v = 2.0 m/s

diameter of the pipe, d = 3.0 cm = 0.03 m

The volume flow rate is given by;

Q = Av

Where;

A is the area of the pipe

v is the velocity of the fluid

circular surface Area of the pipe is given by;

A = ¹/₄ πd²

A = ¹/₄ π(0.03)² = 7.07 x 10⁻⁴ m²

Q = (7.07 x 10⁻⁴)(2)

Q = 1.41 x 10⁻³ m³/s

Therefore, the  volume flow rate of the pipe is 1.41 x 10⁻³ m³/s

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