Answer:
14.1mins
Explanation:
We know that
Time =Distance/Speed
So
= 1.7 au/ (3 E8 m /s )
= 1.7 x 1.496 x 10^11 m /(3 x 10^8 m /s
Converting Au to meters (1.7 x 1.496 x 10^11 m)
= 847.7 s
=14.1 mins
Answer:
Time = 847.73 s = 14.12 min
Explanation:
The distance traveled by an object travelling at a constant speed is given by the following formula:
Distance = (Speed)(Time)
Time = Distance/Speed
where,
Distance = 1.7 AU
converting it into meters:
Distance = (1.7 AU)(1.496 x 10¹¹ m/1 AU) = 2.543 x 10¹¹ m
Speed = 3 x 10⁸ m/s
Therefore, using these values in the equation we get:
Time = (2.543 x 10¹¹ m)/(3 x 10⁸ m/s)
Time = 847.73 s = 14.12 min
Anyone able to also give me the working to how they figured it out?
Answer:
Lamp 1: 4 Volts, and 0.2 Amps
Lamp 2 : 4 Volts, and 0.2 Amps
Explanation:
Considering that the three lamps are equal (they have the same resistance R), we can find the actual resistance of the lamps with the information they provide that the potential difference measured across lamp 3 is 8 volts, using Ohm's Law:
[tex]V = I\,*\,R\\R = \frac{V}{I}\\R= \frac{8}{0.4} \\R = 20\,\,\Omega[/tex]
We can also estimate the potential difference across the lamps 1 and 2 (which are connected in parallel) using Kirchhoff's loop law, which tells us that the 12 volts provided by the battery should equal the addition of voltage drops in lamp 3 plus the drop in the parallel combination of lamps 1 and 2 (call that X):
12 V = 8 V + X
X = 12 - 8 = 4 V
Now, the current circulating through lamp 1 should be given by Ohm's Law:
[tex]V = I\,*\,R\\I = \frac{V}{R} \\I = \frac{4}{20}\\I = 0.2 \,\,Amps[/tex]
Notice that lamp 2 is equal to lamp 1 so the current value should be the same: 0.2 Amps
Which of the following are subjects of scientific laws?a. gravityb. motionc. thermodynamics
What is the average power output (in W) of a heart defibrillator that dissipates 435 J of energy in 10.5 ms?
Answer:
The power is [tex]P = 41429 \ W[/tex]
Explanation:
From the question we are told that
The energy is [tex]E = 435 \ J[/tex]
The time taken is [tex]t = 10.5 \ ms = 10.5 *10^{-3} \ s[/tex]
Generally the the average power is mathematically represented as
[tex]P = \frac{E}{t}[/tex]
=> [tex]P = \frac{ 435}{ 10.5*10^{-3}}[/tex]
=> [tex]P = 41429 \ W[/tex]
A hockey puck moves 26 meters northward, then 12 meters southward, and finally 6 meters
northward
For this motion, what is the distance moved?
What is the magnitude and direction of the displacement?
Answer:
The distance moved is 44 metres.
The magnitude of displacement is 20 metres with northward direction.
Answer:
44 m.
North 20 m.
Explanation:
Distance moved = 26 + 12 + 6
= 44 m.
Magnitude of the displacement = 26 - 12 + 6
= 20m
Direction is Northward.
The presence of dwarf galaxies around the Milky Way supports what picture of our galaxy’s formation?
Answer:
The presence of dwarf galaxies around the Milky Way supports what picture that our galaxy was formed by a coming together or combination of smaller systems
while working out a man performed 375J of work in 11 seconds what was his power
Answer:
power=work done /time taken
therefore..375/11
=34.09
there he used 34.1
give me an example of orderliness In nature
Answer:
Here are some examples of orderliness In nature
1. The proposal that the order of nature showed evidence of having its own human-like "intelligence" goes back to the origins of Greek natural philosophy and science, and its attention to the orderliness of nature, often with special reference to the revolving of the heavens.
2. For Stillman, the orderliness of Astaire-like dance is an actual cure for destructive emotions.
3. Tells about the orderliness of the crowds, and of the dispatch with which the trains were being filled and emptied.
43 Points For Answering & +22 for Brainliest
Question 1
A student conducts an experiment to test how the temperature of a ball affects its bounce height. The same ball is used for each test, and the ball is dropped from the same height each time. What is the dependent variable?
A.The type of ball
B.The temperature of the ball
C.The drop height of the ball
D.The bounce height of the ball
Question 2
A student conducts an experiment to test how the temperature affects the amount of sugar that can dissolve in water. In the experiment, she uses 100 millilitres of water in each trial and stirs for five minutes each time. What is the independent variable?
A.The amount of water
B.The temperature of the water
C.The amount of sugar
D The time stirred
Question 3
Which of the following is a way for scientists to limit the amount of errors in their experimentation?
A.Using controls
B.Only completing an experiment once
C.Using equipment to measure the experiment that has been damaged
D.There is no need to record data from an experiment
Answer:
Question 1: D because the height the ball bounces depends on all the other factors in the experiment.
Question 2: B because the the temperature of the water is not affected by the other variables.
Question 3: A because the more that they can control in the experiment, the more accurate the results will be.
Hopefully this helps :)
1:D 2:B 3:A
just took the test
1st block
Worksheet: Metric Prefixes
A. Circle the larger unit:
1.millimeter, centimeter
2. kilogram, megagram
3. microsecond, millisecond
4.dL, mL
5.mg, kg
Answer:
2
Explanation:
kilogram and megagram is the larger unit
ame
2. A train moving at 15 m/s slows down, and eventually stops after 5
seconds. What is the acceleration of the train?
G: Vi =
Vf=
U:
E: Formula
S: Substitute
S: Solve
Answer:
Acceleration, a = -3 m/s²
Explanation:
Given that,
Initial speed, u = 15 m/s
Final speed, v = 0
Time, t = 5 s
We need to find the acceleration of the train. It is equal to the change in velocity divided by time taken. So,
[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{0-15\ m/s}{5\ s}\\\\a=-3\ m/s^2[/tex]
So, the acceleration of the train is 3 m/s² and it is deaccelerating.
(a) A narrow beam of light containing yellow (580 nm) and green (550 nm) wavelengths goes from polystyrene to air, striking the surface at a 30.0°30.0° incident angle. What is the angle between the colors when they emerge?
Answer:
0.043°
Explanation:
Snell's law States that the ratio of the angle of incidence to angle of refraction is a constant for a given pair of media.
n = sin(i)/sin(r)
n1/n2 = sin(i)/sin(r)
For the green polystyrene
n2 = refractive index of green polystyrene = 1.493
n1 = refractive index of air = 1
1/1.493= sin30°/sin(r1)
sin(r1) = sin30°×1.493
sin(r1) = 0.5×1.493
sin(r1) = 0.7465
r1 = sin^-1(0.7465)
r1 = 48.288°
For the yellow polystyrene
n2 = refractive index of yellow polystyrene = 1.492
n1 = refractive index of air = 1
1.492/1= sin30°/sin(r2)
sin(r2) = sin30°×1.492
sin(r2) = 0.5×1.492
sin(r2) = 0.746
r2 = sin^-1(0.746)
r2 = 48.245°
The angle between the colors when they emerge = r1-r2
angle between the colors when they emerge = 48.288°-48.245°
angle between the colors when they emerge = 0.043°
The siren of a fire engine that is driving northward at 31.0 m/s emits a sound of frequency 2020 Hz. A truck in front of this fire engine is moving northward at 19.0 m/s.
a) What is the frequency of the siren's sound that the fire engine's driver hears reflected from the back of the truck?
b) What wavelength would this driver measure for these reflected sound waves?
Answer:
A. Using
Fl= ( v+vl/v+vz)fz
= (340+19/340+31) x 2020
= 1954.7Hz
Then to find the frequency of sound when reflected from the truck such that the driver becomes the listener
we use
F"= ( v+vz/v+vl) fz
= 340+31/340+19 x 2020
2087.5Hz
B to find the wavelength of sound we use
Wavelength= V+vl/ F"
= 340+31/2087.5= 0.18m
What do civic heroes contribute to their society?
the quest for civic virtue
Explanation:
improving schools, the society....to help educators like yourself, the bill of rights institute has written a New classroom-friendly curriculum called Heroes and Villains....
Which observation is the most objective? a My frog died after 3 days in the aquarium. I will miss him. b My frog died after three days in the aquarium. We will test the temperature and water conditions to find out why. c Frogs tend to die in captivity. Ours did after three days.
Answer:
b
Explanation:
a looks so silly
an Alpha particle moving in north direction give reasons
Your question has been heard loud and clear.
An alpha particle , can move in any direction randomly. But with a magnetic field , we can deflect the alpha particle in any direction we want.
So , the magnetic field must be placed to the west of the alpha particle , so that the particle gets deflected and moves towards the north direction.
Thank you.
Like AL2006 said reasons for what
Why is it harder pushing a car than pushing a bike?
Answer:
When inertia increases, it's because the mass increased, which increases the normal force, which ultimately increases friction.
Martin is conducting an experiment. His first test gives him a yield of 5.2 grams. His second test gives him a yield of 1.3 grams. His third test gives him a yield of 8.5 grams. On average, his yield is 5.0 grams, which is close to the known yield of 5.1 grams of substance. Which of the following are true?
Complete Question
Martin is conducting an experiment. His first test gives him a yield of 5.2 grams. His second test gives him a yield of 1.3 grams. His third test gives him a yield of 8.5 grams. On average, his yield is 5.0 grams, which is close to the known yield of 5.1 grams of substance. Which of the following are true?
A His results are accurate but not precise.
B His results are neither accurate nor precise.
C His results are both accurate and precise
D His results are precise but not accurate.
Answer:
Correct option is A
Explanation:
From the question we are told that
The yield of the first test [tex]k = 5.2 \ g[/tex]
The yield of the second is [tex]u = 1.3 \ g[/tex]
The third yield is [tex]p = 8.5 \ g[/tex]
The average yield [tex]A = 5.0 \ g[/tex]
The know yield is [tex]A_S = 5.1 \ g[/tex]
From the data given we see that
[tex]A_S \ne A[/tex]
Since his average yield is closer to the known yield then the answer is accurate
But since the yield for each test are not repeated the answer is not precise
So the answer is accurate but not precise
His results are accurate but not precise.
Your question is not complete, it seems to be missing the following information;
"A His results are accurate but not precise.
B His results are neither accurate nor precise.
C His results are both accurate and precise.
D His results are precise but not accurate."
The given parameters;
first measurement = 5.2 gsecond measurement = 1.3 gthird measurement = 8.5 gaverage measurement = 5.0known substance average yield = 5.1 gEach of the measurement is far from each other. That is 5.2 grams, 1.3 grams and 8.5 grams are all far apart. So this measurement is not precise.
The known average (5.1 g) and the measured average (5.0 g) are close to each other, so the measurement is accurate.
Thus, we can conclude that his results are accurate but not precise.
Learn more here: https://brainly.com/question/13377944
15. Two like charges: A. Attract each other B. Repel each other C. Must be neutrons D. Neutralize each other
Answer:
B. Repel each other
Explanation:
Two like charges have the same sign. Example an electron with a negative charge (-e) and another electron with same charge(-e). Or a proton with a positive charge (+e) and another proton with same charge (+e). Since each of these pair charges have the same sign, they will repel each other.
On the other hand, if the charges are opposite, ie negative charge and positive charge, they will attract each other.
B. Repel each other
You drive your car in a straight line at 15 m/s for 10 kilometers, then at 25 m/s for another 10 kilometers.
a. What is your average speed?
b. Choose the best explanation from among the following:
1) More time is spent at 15 m/s than at 25 m/s.
2) The average of 15 m/s and 25 m/s is 20 m/s.
3) Less time is spent at 15 m/s than at 25 m/s.
Answer:
A) Average speed = 18.75 m/s
B) More time is spent at 15 m/s than at 25 m/s.
Explanation:
Let the first distance be d1 and the second distance be d2.
We are given;
d1 = 10 km = 10000 m
d2 = 10 km = 10000 m
Speed; v1 = 15 m/s
Speed; v2 = 25 m/s
Now, the formula for distance is; Distance = speed x time
Thus:
d1 = v1 x t1
t1 = d1/v1 = 10000/15 = 666.67 seconds
Also,
d2 = v2 x t2
t2 = d2/v2 = 10000/25 = 400 seconds
Average speed = total distance/total time = (10000 + 10000)/(666.67 + 400) = 18.75 m/s
From earlier, since t1 = 666.67 seconds and t2 = 400 seconds, then;
More time at 15 m/s than at 25 m/s.
Density is calculated by dividing
Answer:
Density is the mass of an object divided by its volume. Density often has units of grams per cubic centimeter (g/cm3). Remember, grams is a mass and cubic centimeters is a volume (the same volume as 1 milliliter).
Explanation:
Hey, there!
Density is defined as mass per unit volume. so, when we keep is as a formula we get like,
[tex]density = \frac{mass}{volume} [/tex]
So, you can state that density is calculated by dividing mass by its unit volume.
Hope it helps...
Which term describes a quantity that has both magnitude and direction?
Vector explanation is apex and I got 100 on the test and it’s the definition
Two small metal cubes with masses 2.0 g and 4.0 g are tied together by a 4.7-cm-long massless string and are at rest on a frictionless surface. Each is charged to +2.5 μC .
What is the energy of this system?
Express your answer using two significant figures.
What is the tension in the string?
Express your answer using two significant figures.
The string is cut. What is the speed of each sphere when they are far apart?
Hint: There are two conserved quantities. Make use of both.
Express your answers using two significant figures. Enter your answers numerically separated by a comma.
(v2g,v4g)=_____m/s
Answer:
1.2J
26 N
(-28, 14) m/s
Explanation:
energy
U = kQq / d = 8.99*10^9 * (2.5*10^-6C)² / 0.047m
U = 0.0562/0.047
U = 1.20 J
to two significant figures
tension
T = kQq / d²
T = U / d
T = 1.2 / 0.047
T = 25.53 N = 26 N to 2 sf
Momentum is conserved, and the initial momentum is zero:
0 = 0.0020 * V2 + 0.0040 * V4
so
V2 = -2 * V4
Energy is also conserved:
½ * 0.0020 * (-2V4)² + ½ * 0.0040 * (V4)² = 1.2 J
-½ * 0.0080 * V4² + ½ * 0.0040 * V4² = 1.2 J
-0.0040V4² + 0.002V4² = 1.2 J
0.0060V4² = 1.2 J
V4² = 1.2/0.0060
V4² = 200
V4 = √200
V4 = 14 m/s
and since V2 = -2 * V4
V2 = -28 m/s
(V2, V4) = (-28, 14)
The energy of this system is 1.2J
The tension in the string is 26 N
The speed of each sphere when they are far apart is (-28, 14) m/s
Calculation of energy, tension, and speed:The energy should be
U = kQq / d
= 8.99*10^9 * (2.5*10^-6C)² / 0.047m
U = 0.0562/0.047
U = 1.20 J
The tension should be
T = kQq / d²
T = U / d
T = 1.2 / 0.047
T = 25.53 N
= 26 N
The speed should be
Since Momentum should be conserved, and the initial momentum is zero:
So,
0 = 0.0020 * V2 + 0.0040 * V4
Now
V2 = -2 * V4
Due to this, Energy is also conserved:
½ * 0.0020 * (-2V4)² + ½ * 0.0040 * (V4)² = 1.2 J
-½ * 0.0080 * V4² + ½ * 0.0040 * V4² = 1.2 J
-0.0040V4² + 0.002V4² = 1.2 J
0.0060V4² = 1.2 J
V4² = 1.2/0.0060
V4² = 200
V4 = √200
V4 = 14 m/s
and now V2 = -2 * V4
V2 = -28 m/s
(V2, V4) = (-28, 14)
Learn more about energy here: https://brainly.com/question/15182235
What linear speed must an Earth satellite have to be in a circular orbit at an altitude of 203 km above Earth's surface
Answer:
7,790.38 m/s
Explanation:
Given the following :
What linear speed must an Earth satellite have to be in a circular orbit at an altitude of 203 km above Earth's surface
Altitude = 203 km
Using the formula :
V = √GM/r
Where G = gravitational constant =6.67×10^-11
Kindly check attached picture for detailed explanation.
A 50 kg child is riding on a carousel (merry-go-round) at a constant speed of 5 m/s. What is the magnitude of the change in the child's momentum ∣Δp⃗ ∣∣ in going all the way around (360∘)?In going halfway around (180∘)? It is very helpful to draw a diagram, and to do the vector subtraction graphically.
Answer:
a) [tex]\mathbf{|\Delta p^{\to}_{11}| = 0 \ kg.m/s}[/tex]
b) [tex]\mathbf{|\Delta p^{\to}_{12}| = 500 \ kg.m/s}[/tex]
Explanation:
From the image attached below.
Suppose the child goes all the way around, i.e., 360, the child will execute a movement of 1 complete revolution and be at his starting point. At that point, the velocity vector is towards the y-direction.
Thus, the velocity of the child is:
[tex]v_1^{\to} = v \hat _v_1} \\ \\ v_1^{\to} = (5)(0,1,0)\\ \\ v_1^{\to} = (0,5,0) \ m/s[/tex]
the momentum will be:
[tex]p_1^{\to} = m v_1^{\to} \\ \\ p_1^{\to} = (50)(0,5,0) \\ \\ p_1^{\to} = (0,250,0) \ kg.m/s[/tex]
the change in momentum now is [tex]\Delta p = p_1^{\to} -p_1^{\to}[/tex] since that is the child's momentum initially.
∴ [tex]\Delta p =(0,250,0) - (0,250,0)[/tex]
[tex]\mathbf{\Delta p =(0,0,0) \ kg.m/s}[/tex]
By subtracting the two vector graphically as being asked in the question, we have :
[tex]|\Delta p^{\to}_{11}| = \sqrt{(0)^2+(0)^2 +(0)^2 }[/tex]
[tex]\mathbf{|\Delta p^{\to}_{11}| = 0 \ kg.m/s}[/tex]
b) In going halfway around (180°), the child will be opposite with respect to the starting point. Hence, the velocity vector will be in the negative y-direction.
Thus, the velocity of the child is:
[tex]v_2^{\to} = v \hat _v_2} \\ \\ v_2^{\to} = (5)(0,-1,0)\\ \\ v_2^{\to} = (0,-5,0) \ m/s[/tex]
the momentum will be:
[tex]p_2^{\to} = m v_2^{\to} \\ \\ p_2^{\to} = (50)(0,-5,0) \\ \\ p_2^{\to} = (0,-250,0) \ kg.m/s[/tex]
the change in momentum now is [tex]\Delta p = p_2^{\to} -p_1^{\to}[/tex] since that is the child's momentum initially.
∴ [tex]\Delta p =(0,-250,0) - (0,250,0)[/tex]
[tex]{\Delta p =(0,-500,0) \ kg.m/s[/tex]
By subtracting the two vector graphically as being asked in the question, we have :
[tex]|\Delta p^{\to}_{12}| = \sqrt{(0)^2+(-500)^2 +(0)^2 }[/tex]
[tex]|\Delta p^{\to}_{12}| = \sqrt{250000}[/tex]
[tex]\mathbf{|\Delta p^{\to}_{12}| = 500 \ kg.m/s}[/tex]
In the drawing, what is the vector sum of forces A→+B→+C→ if each grid square is 7.00 N on a side? If the resultant is eastward, enter a positive value and if the resultant is westward, enter a negative value.
Answer:
resultant force = 14 N ( East direction)
Explanation:
A = [tex]\sqrt{(4*7)^2 + (4*7)^2}[/tex]
A = 39.6 N
B = 4 * 7
B = 28 N
C = 2 * 7
C = 14 N
∑ y forces = Ay - B = (4*7) - 28 = 0
∑ x forces = Ax - C = (4*7) - 14 = 14 N
so the resultant force = 14 N ( East direction)
Answer:
resultant = 14 N to the right
Explanation:
A→+B→+C→
adding all forces acting on x
and
adding all forces acting on y
A = sqrt(4*7)^2 + (4*7)^2 = 39.6
B = 4 * 7 = 28
C = 2 * 7 = 14
forces acting on x = (4*7) - 28 = 0
forces acting on y = (4*7) - 14 = 14 N
so the resultant = 14 N to the right
A farmer lifts his hay bales into the top loft of his barn by walking his horse forward with a constant velocity of 8 ft/s. Determine the velocity and acceleration of the hay bale when the horse is 10 ft away from the barn.
Answer:
Velocity = 8 ft/s
Acceleration = 0 m/s²
Explanation:
Since, the horse is moving with a constant velocity, whose magnitude is given as equal to 8 ft/s. Therefore, it will have the same velocity when it is 10 ft away from the barn. And the velocity of hay bale will be same as the velocity of horse, as the horse is carrying the bales. Therefore:
Velocity = 8 ft/s
Coming to the second part of the question, which relates to the acceleration of the hay bale, when horse is 10 ft away from the barn. The formula for acceleration is given as:
Acceleration = Change in Velocity/ Time
But, the velocity of the horse in constant, which means there is no change in velocity. Hence,
Change in Velocity = 0
Therefore,
Acceleration = 0/Time
Acceleration 0 m/s²
1. A particle is moving along the x-axis. Its position as a function of time is given as x = bt − ct 2 . a) What must be the units of the constants b and c, if x is in meters and t in seconds?
Answer:
Given x = bt-c²
We know that t= time (s)
x= distance (m)
So
bxt= meters
m/s x s= m
And then c= m/s²
And b= m/s
A large magnetic flux change through a coil must induce a greater emf in the coil than a small flux change. A) True B) False
Answer:
False
Explanation:
Faraday's law gives the relationship between the induced emf and the rate of change of magnetic flux i.e.
[tex]\epsilon=\dfrac{-d\phi}{dt}[/tex]
The given statement "A large magnetic flux change through a coil must induce a greater emf in the coil than a small flux change" is false. The reason is that if the rate of change of magnetic flux is greater, then its will induce more emf. It would mean it does not say about emf.
Hence, it is false.
At t = 0, one toy car is set rolling on a straight track with initial position 13.0 cm, initial velocity -3.6 cm/s, and constant acceleration 2.20 cm/s2. At the same moment, another toy car is set rolling on an adjacent track with initial position 11.5 cm, initial velocity 5.40 cm/s, and constant zero acceleration. (a) At what time, if any, do the two cars have equal speeds? (Enter NA if the cars never have equal speeds.) s (b) What are their speeds at that time? (Enter NA if the cars never have equal speeds.) cm/s (c) At what time(s), if any, do the cars pass each other? (If there is only one time, enter NA in the second blank. If there are two times, enter the smaller time first. If they never pass, enter NA in both blanks.) s s (d) What are their locations at that time? (If there is only one position, enter NA in the second blank. If there are two positions, enter the smaller position first. If they never pass, enter NA in both blanks.) cm cm (e) Explain the difference between question (a) and question (c) as clearly as possible.
Answer:
that's too much to read
A beam of helium-3 atoms (m = 3.016 u) is incident on a target of nitrogen-14 atoms (m = 14.003 u) at rest. During the collision, a proton from the helium-3 nucleus passes to the nitrogen nucleus, so that following the collision there are two atoms: an atom of "heavy hydrogen" (deuterium, m = 2.014 u) and an atom of oxygen-15 (m = 15.003 u). The incident helium atoms are moving at a velocity of 6.346 x 10° m/s. After the collision, the deuterium atoms are observed to be moving forward (in the same direction as the initial helium atoms) with a velocity of 1.531 x 107 m/s.A) What is the final velocity of the oxygen-15 atoms? B) Compare the total kinetic energies before and after the collision.
Answer:
Explanation:
We shall apply law of conservation of momentum to solve the problem .
Helium-3 collides with nitrogen-14 at rest . After the collision the newly formed deuterium atom and oxygen-15 atom moves .
momentum before the collision
= 3.016 x 6.346 x 10⁶ + 14.003 x 0 = 19.14 x 10⁶ unit
momentum after collision
2.014 x 1.531 x 10⁷ + 15.003 V
3.083 x 10⁷ + 15.003 V units
Applying the law of conservation of momentum ,
19.14 x 10⁶ = 3.083 x 10⁷ + 15.003 V
1.914 x 10⁷ = 3.083 x 10⁷ + 15.003 V
15.003 V = - 1.169 x 10⁷
V = .077917 x 10⁷
= 7.79 x 10⁵ m /s
= .0779 x 10⁷ m /s
mass of helium atom = 3.016 u = 3.016 x 1.67 x 10⁻²⁷ kg
velocity = 6.346 x 10⁶ m /s
kinetic energy = 1 /2 x 3.016 x 1.67 x 10⁻²⁷ x (6.346 x 10⁶ )²
= 101.42 x 10⁻¹⁵ J
kinetic energy of nitrogen atoms = 0
Total energy before collision = 101.42 x 10⁻¹⁵ J
Similarly kinetic energy after collision
= 1 /2 x [ 2.014 x 1.531² + 15.003 x .0779² ] x 1.67 x 10⁻²⁷ x 10¹⁴
= .835 x [ 4.72 + .09 ] x 10⁻¹³ J
= 4.016 x 10⁻¹³ J
= 401.6 x 10⁻¹⁵ J
value of kinetic energy is increased .