Based on the results of your titration, what volume of the sample would an adult need to consume to reach the recommended daily amount? 60 mg is the recommened daily amount of vitamin C.

Ascorbic acid Volume of DCPIP in Total Volume of DCPIP

concentration (g/L) final syringe (mL) used (mL)

0.00 2.18 mL 0.18 mL

0.50 3.1 mL 0.6 mL

1.00 4.6 mL 2.2 mL

1.50 5.56 mL 3.39 mL

2.00 6.37 mL 4.37 mL

Unknown Trial 1 3.21 mL 1.21 mL

Unknown Trial 2 3.11 mL 1.11 mL

Unknown Trial 3 3.15 mL 1.06 mL

Answers

Answer 1

Answer:  85.7 mL

Explanation:

Given the information from the question as plotted in the graph i will be uploading along side this answer,

Average of total volume of DCPIP used is

= (1.21 + 1.11 + 1.06)mL / 3

= 1.12 mL

and corresponding ( ascorbic acid ) is 0.70 g/L

Two parameter given as volume of DCPIP in final syringe and total volume of DCPIP are quite ambiguous

700mg ⇒ 1 L

THEREFORE volume that contains 60mg =  (1000/700) × 60 = 85.7 mL

Based On The Results Of Your Titration, What Volume Of The Sample Would An Adult Need To Consume To Reach

Related Questions

can anyone help me with nomenclature?​

Answers

Explanation:

a chemical nomenclature is a set of rules to generate systematic names for chemical compounds.

What types of knowledge and background did Underwood and Prescott bring to the problem?

Answers

Answer:

The answer is on the screenshot

Explanation:

30.0 mL of pure water at 282 K is mixed with 50.0 mL of pure water at 328 K. What is the final temperature of the mixture

Answers

Answer:

Explanation:

As the 50mL of water are in a big temperature will give heat to the other sample of water.

With the equation:

Q = m*C*T

Where Q is heat, m  is mass of the sample, C is specific heat of the sample (4.184J/molK for pure water) and T is temperature in K

We can determine the energy of each sample of water:

Sample 1:

Q = 30.0g*4.184J/molK*282K

Mass is 30.0g because density of water is 1g/mL

Q = 35396.6J

Sample 2:

Q = 50.0g*4.184J/molK*328K

Q = 68617.6J

Total energy is:

Q = 104014.2J

As total mass is 30+50 = 80g, final temperature is:

104014.2J = 80.0g*4.184J*T

310.7K is final temperature of the mixture

A 0.0678 M solution of a weak base has a pH of 9.44. What is the identity of the weak base? Weak Base Kb Ethylamine (CH3CH2NH2) 4.7 × 10–4 Hydrazine (N2H4) 1.7 × 10–6 Hydroxylamine (NH2OH) 1.1 × 10–8 Pyridine (C5H5N) 1.4 × 10–9 Aniline (C6H5NH2) 4.2 × 10–10

Answers

Answer:

The weak base is hydroxylamine

Explanation:

The general equilibrium of a weak base (A), is:

A(aq) + H₂O(l) ⇄ HA⁺ + OH⁻

Where Kb is:

Kb = [HA⁺] [OH⁻] / [A]

As both HA⁺ and OH⁻ comes from the equilibrium of A; HA⁺ = OH⁻. So, you can take:

Kb = [OH⁻]² / [A]

OH⁻ is determined from pH, thus:

pOH = -log [OH⁻]

pOH = 14 - pH

pOH = 14 - 9.44

pOH = 4.56

[OH⁻] = 10^{-4.56}

[OH⁻] = 2.75x10⁻⁵

As the concentration of the weak base is 0.0678M:

Kb = [OH⁻]² / [A]

Kb = [2.75x10⁻⁵]² / [0.0678M]

Kb = 1.1x10⁻⁸ = Kb of Hydroxylamine.

The weak base is hydroxylamine

Classify each of the following as either a physical change or a chemical change.
a. tearing a sheet of paper,
b. melting a piece of wax,
c. burning a log

Answers

Answer: A:Physical, B:Both, C: Chemical

Explanation:

Tearing paper is physical because only the appearance has changed. Melting wax can be either physical or chemical depending on whether the wax actually burns or not, burning a log is chemical because new substances are formed when wood burns.

One of the differences between a voltaic cell and an electrolytic cell is that in an electrolytic cell __________.

Answers

Answer:

a nonspontanenous reaction is forced to occur

Hope this helps :)

1.72 g elemental arsenic combined with excess chlorine gas to form 4.17 g of the arsenic chloride compound. If the molar mass is between 180-200 g/mol, write the balanced equation for this synthesis process.

Answers

Answer:

As + 3/2 Cl₂ → AsCl₃

Explanation:

The reaction of the problem is:

As + Cl₂ → AsₐClₓ

The problem consist in determine a and x from the formula to write the balanced equation.

1.72g of As are (Molar mass: 74.92g/mol):

1.72g * (1mol / 74.92g) = 0.02296 moles of As are added to the reaction.

As molar mass of the arsenic chloride is between 180-200g/mol, the moles produced are between:

4.17g * (1 mol / 180g) = 0.0232

4.17g * (1 mol / 200g) = 0.0209

As moles of As are 0.02296 the most logic is than 1 mole of As produce 1 mole of the compound, that means the arsenic compound contains 1 mole in each formula:

As₁Clₓ: AsClₓ

And also, 0.02296 moles of AsClₓ are produced, the molar mass is:

4.17g / 0.02296mol = 181.62g/mol.

The atom of As weighs 74.92g/mol. The mass of the chlorides is:

181.62 - 74.92 = 106.70g/mol.

1 atom of Cl weighs 35.45g/mol:

106.70g/mol / 35.45g/mol = 3.0 atoms of Cl are in the chemical formula, that is:

AsCl₃

And the balanced equation for this synthesis is:

As + Cl₂ → AsCl₃

As + 3/2 Cl₂ → AsCl₃

Calculate the mass of the air contained in a room that measures 2.50 m × 5.50 m × 3.00 m (density of air = 1.29 g/dm3 at 25°C).

Answers

Answer:

Explanation:

Volume of air = 2.5 x 5.5 x 3.00

= 41.25 m³.

Density of air = 1.29 g / dm³

a dm³ = ( 0.1 )³m³

= .001 m³

density in m³ = 1.29 / .001 gm⁻³

= 1290 g / m³

mass of air in the room

= 41.25 x 1290 g

= 53212.5 g

= 53.2125 kg .

Explanation:

please mark me as brainlest

Periodic Table High School Reference Sheet
Which of the following equations best describes the energy at point
C, assuming energy is conserved?
A PEA = KEC
B
PEA = KEC - PEC
C. PEB = KEO - PEO
D
PES = PEC

Answers

I believe it should be B

carbon dioxide at 25 degrees celsius and 101.3 kpa has a density of 1.799 kg/m^3 determine gas constant

Answers

Answer:

Explanation:

Temperature of gas in absolute scale T = 25 + 273 = 298 .

pressure of gas P = 1.013 x 10⁵ N / m²

density D = 1.799 kg / m³

= 1799 g / m³

From gas formula

PV / T = n R Where P is pressure , V is volume and T is absolute temperature , n is no of moles

P / T = n R / V

P / T = m R /M V where m is mass of gas and M is molecular weight .

m / V = D ( density )

P / T = DR/ M  

PM / DT = R

Putting the values

1.013 x 10⁵ x 44  /  (1799 x 298)

R = 8.314.09 J / K mole

Consider the reaction below. If the concentration of B decreases by 0.068 M, what will be the change in concentration for C? 3A(g)+4B(g)⇋5C(g)

Answers

Answer:

.085 M .

Explanation:

  3A(g)   +4B(g)  ⇋  5C(g)

4 moles of B reacts with A to form 5 moles of C

.068 moles of B will reacts with A to form  5 x .068 / 4 moles of C

Moles of C formed

= 5 x .068 / 4

= .085 moles .

What kind of molecular orbital would result when atomic orbitals are combined as indicated?

Answers

Provided question is incomplete as it lacks image or diagtram related to the question, however the correct indication is attach with answer :

Answer:

The correct answer is : antibonding molecular orbital

Explanation:

At the point when two atomic orbitals can consolidate directly produce two molecualr orbital, of which one is holding sub-atomic orbital of lower vitality and the other antibonding molecular orbital of higher energy.  

Holding molecular orbital would by and large outcomes which nuclear orbitals of same phase joins while antibonding molecular orbital would results when atomic orbitals of various stages can combine.  

In the given approach, it is obvious that one of S - orbital is going consolidate directly with opposite phase of p - orbital along their inter nuclear axis. Subsequently it prompts the formation of sigma antibonding molecular orbital.

Thus, the correct answer is : antibonding molecular orbital

how many grams of iron(ii) sulfate heptahydrate is needed to prepare 250.0 ml of a 3.25 molar aqueous solution

Answers

Answer:

The mass of FeSO₄.7H₂O  needed  [tex]\simeq[/tex] 225.89 grams

Explanation:

From the given question

The molecular weight of iron(ii) sulfate heptahydrate FeSO₄.7H₂O = 278.02 g/mol

Molarity = 3.25

Volume = 250.0 mL

The mass of FeSO₄.7H₂O  needed = [tex]\dfrac{moles \times molecular weight \times 250\ mL}{1000 \ mL}[/tex]

The mass of FeSO₄.7H₂O  needed  = [tex]\dfrac{3.25 \times 278.02 \times 250}{1000}[/tex]

The mass of FeSO₄.7H₂O  needed  = 225.89125 grams

The mass of FeSO₄.7H₂O  needed  [tex]\simeq[/tex] 225.89 grams

You have been injured in the laboratory (cut,burn,etc) first you should

Answers

Let the teacher know

Answer:tell the instructor of the lab

Explanation:

Tracy had seen her teacher perform the demonstration many times. The materials for the demonstration were lying on the teacher’s table. Tracy tied her long hair back and used the materials to perform the demonstration on her own. a) Write an action that Tracy did correctly. b) Write an action that Tracy did not follow.

Answers

Answer:

Tracy was able to remember what her teacher told her to do and she decided to try it,which was the right thing.

But since it's a demonstration then Tracy is supposed to wear all her protective equipments and with a teacher's permission.I hope this helps.Thanks

round 77.616 to two significant figures

Answers

Answer:

The answer to the question is 78

Answer:

78

Explanation:

In rounding off to two, we consider the third digit. if it is more than five we ad one to the second digit otherwise we truncate.

in the case of 77.616, we add one to the second digit and truncate the rest.

The distance from earth to the star Proxima Centauri is 4.22 light years, which means it would take a ray of light 4.22 years to travel from earth to the star. How many miles separate earth and Proxima Centauri?

Answers

Answer:

2.48x10¹³ miles is the distance from the earth to Proxima Centauri

Explanation:

Light years is an unit of distance used in Astronomy. That is because 1 light year = 9.461x10¹²km; a real big distance used in the science that study the universe.

In km, 4.22 light years are:

4.22 light years * (9.461x10¹²km / 1 light year) = 3.9925x10¹³km

As 1 mile = 1.60934km, this distance in miles is:

3.9925x10¹³km * (1 mile / 1.60934km) =

2.48x10¹³ miles is the distance from the earth to Proxima Centauri

What is the change in enthalpy when 9.00 mol of sulfur trioxide decomposes to sulfur dioxide and oxygen gas

Answers

Answer:

-891kj

Explanation:

We have the chemical equation as:

2SO2(g) + O2(g) ----2SO3; ∆H° = 198kj

If sulphur trioxide decomposes we have opposite reaction. Enthalpy of decomposition will not be positive for forward reaction.

2 moles of SO3 ----∆H° = -198Kj

1 mole = -198/2

9 moles = -198/2 x 9

= -891kj

Therefore change in enthalpy when 9 moles is decomposes is -891kj.

The average adult heart pumps about 84./mLs of blood at 72 beats per minute. Suppose you need to calculate how long it would take the average heart to circulate 3600.mL of blood. Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols.

Answers

Answer:

42.857 seconds

Explanation:

Given that:

The average adult heart pumps about 84./mLs  of blood at 72 beats per minute.

The total volume = 3600 mL

The objective is to calculate how long it would take the average heart circulate 3600 mL of blood.

Since 84 mL of blood takes 1 seconds to pump,

assuming q is the time required for heart to pump 3600 mL of blood

[tex]Time \ ( q )= \dfrac{3600 mL \times 1\ seconds}{84 \ mL}[/tex]

TIme (q) = 42.857 seconds

A student graphed distance versus time for an object that moves 14 every 2 s. What is the speed of the object?

Answers

Answer:

The speed is 7 every second.

Equation:

14/2 = 7

A student graphed distance versus time for an object that moves 14 every 2 s. The speed of the object is 7 m/sec.

What is speed?

The speed is the distance traveled by an object with a specific unit of time. Speed is calculated by dividing distance by time. The SI unit of speed is a meter per second.

S = d / t

Distance is the space or extent between two things. It is measured in meters and kilometers.

Time is a variable that equals the distance divided by time.

The slope of a graph is the rate at which the y and x axis change together, the "rise over the run." Slope can be simply calculated using this equation:

Given, that distance = 14 meters

The time is 2 sec.

By the formula

d = 14 / 2 = 7 m /sec.

Thus, the speed of the object is 7 m/sec.

To learn more about speed, refer to the link:

https://brainly.com/question/7359669

#SPJ2

Round off the following number to four significant figures.
19.9743

Answers

Answer:

4 sig fis so look at the next number which is "4"

answer is 19.97

all numbers not zeros are significant

The central Xe atom in the XeF4 molecule has ________ unbonded electron pair(s) and ________ bonded electron pair(s) in its valence shell.

Answers

Answer:

Lewis structure in attachment.

Explanation:

Atoms of elements in and beyond the third period of the  periodic table form some compounds in which more than eight electrons surround the  central atom. In addition to the 3s and 3p orbitals, elements in the third period also  have 3d orbitals that can be used in bonding. These orbitals enable an atom to form  an expanded octet.

The central Xe atom in the XeF₄ molecule has two unbonded electron pairs and four bonded electron pairs in its valence shell.

The central Xe atom in the XeF4 molecule has 2 unbonded electron pair(s) and 4 bonded electron pair(s) in its valence shell.

Xenon is the element with the following electronic configuration:

[Kr] 4d¹⁰5s²5p⁶

As we can see there are 6 electrons in the p block of its outer orbitalit means Xenon has 6 bonding electron pairs, therefore the electron geometry of octahedraltwo of the pairs of electrons on the central atom are unbonded, or lone pairs therefore the molecular geometry is square planar.four pairs are bonded in its valence cell.

Thus, The central Xe atom in the XeF4 molecule has 2 unbonded electron pair(s) and 4 bonded electron pair(s) in its valence shell.

Learn more:

https://brainly.com/question/18385138

The solubility of silver sulfate (Ag2SO4), in moles per liter, can be expressed in terms of the resulting ion concentrations. Which relationship is correct?

Answers

Answer:

Solubility = [SO₄²⁻]

Explanation:

Solubility of Ag₂SO₄ can be determined by its ksp equilibrium:

Ag₂SO₄(s) ⇄ SO₄²⁻ + 2Ag⁺

Where 1 mole of silver sulfate dissolves producing 1 mole of sulfate ion and 2 moles of silver ion.

Solubility is defined as the amount of solid that can be dissolved per liter of solution.

The moles of Ag₂SO₄ dissolved are equal to moles of SO₄²⁻.

That means:

Solubility = [SO₄²⁻]

Write the rate law for the following elementary reaction: H2(g) 2I(g) (g) Use to stand for the rate constant.

Answers

Answer:

rate = k ×[H₂] × [I]²

Explanation:

Write the rate law for the following elementary reaction: H₂(g) + 2 I(g) → 2 HI(g) Use k, to stand for the rate constant.

Step 1: Write the elementary reaction

H₂(g) + 2 I(g) → 2 HI(g)

Step 2: Write the rate law

The generic rate law is

rate = k ×[H₂]ᵃ × [I]ᵇ

where,

rate: reaction rate

k: rate constant

[H₂] and [I]: molar concentrations of the reactants

a and b: reaction orders for H₂ and I, respectively

For elementary reactions, the reaction orders coincide with the stoichiometric coefficients. Then, the rate law is:

rate = k ×[H₂] × [I]²

An element has three stable isotopes of masses 24, 25, and 26. They exist in abundances of 79%, 10%, and 11%, respectively. What is the average atomic mass, and what is the element? *

Answers

Answer:

12 this is your answer

hope you like it

Which type of phychologist would help to improve work productivity

Answers

Industrial and organizational psychologists study organizations and their employees to improve the productivity, satisfaction, safety, health and well-being of those within the workplace environment.

Your question has been heard loud and clear.

Well , work productivity is a necessity in all fields of science and businesses especially those dealing with commerce. So , for each of these fields , we have specific psychologists to help with work productivity.

Examples: Aviation Psychologists  (Field of Aviation)

These psychologists study the behavior of pilots and other flight crew members. Aviation psychologists also perform research on airline safety, develop new training equipment, and help select suitable employees.

Biopsychologists  (Field of biology)

These psychologists are also sometimes called biological psychologists or physiological psychologists. They study and perform research on the brain and behavior. By examining the neural bases of behavior, biopsychologists are able to understand different biological factors that might impact how people think, feel, and act.

Educational Psychologists  (Field of education)

These psychologists study how people learn and the educational process. This might involve developing instructional strategies and teaching techniques. Some educational psychologists study giftedness or learning disabilities.

Thank you.

"Splotchy" most likely refers to a mineral's:
O color
luster
streak
O hardness

Answers

Answer:Luster

Explanation: i'm tired so it is luster because splotchy wouldn't be referring to the others so it would be referring to Luster the reflection of light of the object. Hope it helps

PLZ BRAINLILEST I ONLY NEED ONE MORE

Answer:

the answer is color

Explanation:

i got it right on my assignment lol

Compare the following values:
1 grams vs. 10 decigrams
Determine if the values have the same numerical value. Explain your reasoning.

Answers

Answer:

1 Gram (g) is equal to 10 decigrams (dg).

Explanation:

this is because there is 0.1 grams in a decigram

A sample initially contains 4.4 moles of a radioactive isotope. How much of the sample remains after four half-lives?

Answers

Answer:

0.275

Explanation:

Given that:

Initial number of miles of radioactive isotope = 4.4 moles

How much if the sample remains after 4 half life's

Half-life refers to the time taken by a sample to reduce to half of it's initial value.

After the first half life :

Initial / 2 = 4.4 / 2 = 2.2 moles

Second half life :

2.2 / 2 = 1.1 moles

Third half life :

1.1 / 2 = 0.55 Moles

Fourth half life :

0.55 / 2 = 0.275 moles

A pool is 60.0 m long and 35.0 m wide. How many mL of water are needed to fill the pool to an average depth of 6.35 ft? Enter your answer in scientific notation.

Answers

Answer:

4.07 × 10⁹ mL

Explanation:

Step 1: Given data

Length of the pool (L): 60.0 m

Width of the pool (W): 35.0 m

Depth of water in the pool (D): 6.35 ft

Step 2: Convert "D" to m

We will use the relationship 1 m = 3.28 ft

[tex]6.35ft \times \frac{1m}{3.28ft} = 1.94m[/tex]

Step 3: Calculate the volume of water (V)

We will use the following expression.

[tex]V = L \times W \times D = 60.0m \times 35.0m \times 1.94 m = 4.07 \times 10^{3} m^{3}[/tex]

Step 4: Convert "V" to mL

We will use the relationship 1 m³ = 10⁶ mL.

[tex]4.07 \times 10^{3} m^{3} \times \frac{10^{6}mL }{1m^{3} } = 4.07 \times 10^{9} mL[/tex]

Other Questions
Which of the following techniques is an instance of supporting a point with testimony? a Telling an entertaining story about a personal experience b Mentioning a specific instance that is reflective of your larger point c Relating a point to a similar concept likely to be understood by the audience d Referring to a relevant quotation from a highly credible mathematician e Incorporating relevant data, either through visual aids or citation Prepaid Advertising has a debit balance in the Trial Balance section of the worksheet of $1500 and a credit entry of $550 in the adjustments section of the worksheet the balance of Prepaid Advertising in the Adjusted Trial Balance section of the worksheet is a:_______a) $1050 bin b) $1050 credh c) $4500 de d) $550 de You want to create an electric field vector E = < 0, 5 104, 0> N/C at location < 0, 0, 0>. Where would you place a proton to produce this field at the origin? Why did Plains farming tribes normally settle in regions along rivers in eastern Oklahoma?A. These regions received more precipitation.B. These regions had a larger buffalo population,C. These regions had a more established trade route.D. These regions had fertile floodplains. Which posed the greatest challenge to pioneers crossing the western mountains?o overpopulated rest areaslack of waterhot desert sando steep and Langerous passes 1. Use the diagram to the right to name the following.a) Four collinear points.b) A line that contains point M.c) A line that contains points H and K.d) Another name for line q.e) The intersection of lines p and r. A refrigerator thermometer is read ten times and registers degrees Celsius as:39.1, 39.4, 39.1, 39.2, 39.1, 39.2, 39.1, 39.1, 39.4, and 39.1. However, the realtemperature inside the refrigerator is 37 degrees C. Is this an example ofprecision, accurate, neither, both or neither, Make a selection and explain. I need help plz if someone know thi question help me!! what is the advantage of decreasing the field current of a separately excited dc motor below its nominal value find the slope and the y intercept of the line y=-5/4x+9 Which of the following statements is true about normal distributions? the tails on the normal distribution stop at three standard deviations the tails on the normal distribution cross the x-axis after one standard deviation the tails on a normal distribution go on forever and never touch the x-axis the tails on the normal distribution cross the x-axis after three standard deviations Which expression is equivalent to 1/2 x + (-70) - 2 1/4 x - (-2) DA = 0.0Trapezoid ABCD is congruent to trapezoid EFGH, and the side lengths of ABCD are given. Find GH.A. 9.0B. 14.0C. 20.0D. cannot be determined what is the equivalent expression of 14n+21? I really need help with this it is due in the morning and I have no clue what I'm doing please helppppppp apply properties of operatione to write an equivalent expression Identify the factors of the terms of the expressions. 3. 5+6a+11b4. 13m-2n Obtener la ecuacin de la elipse, sus focos, vrtices y grfica, si se sabe que un extremo del eje menor est en (0, 3) y un foco en (2,0). Buenos dias! Me llamo Carlos Manuel Which of the following correctly uses exponents to write "6 factors of 2"? 2 6 6 2 12 6 2 Give a systematic name for the following compound: CH3CH2CHCH2CHCH3, with a CH3 group attached to the third (from left to right) carbon and a Br atom attached to the fifth carbon.