Answer:
22222222222222222222222222+22222222
simplify (4a) × (3b)
Answer:
Step-by-step explanation:
hello :
(4a) × (3b) =12ab
A sample of a radioactive isotope had an initial mass of 440 mg in the year 1990 and decays exponentially over time. A measurement in the year 1998 found that the sample's mass had decayed to 40 mg. What would be the expected mass of the sample in the year 2001, to the nearest whole number?
Using an exponential function, the expected mass of the sample in the year 2001 would be of 16 mg.
What is the exponential function for the amount of a substance?The function is:
[tex]A(t) = A(0)e^{-kt}[/tex].
In which:
A(0) is the initial amount.k is the decay rate.The information given is as follows:
A(0) = 440, A(8) = 40.
Hence:
[tex]A(t) = A(0)e^{-kt}[/tex].
[tex]40 = 440e^{-8k}[/tex].
[tex]e^{-8k} = 0.09090909[/tex]
[tex]\ln{e^{-8k}} = \ln{0.09090909}[/tex]
[tex]-8k = \ln{0.09090909}[/tex]
[tex]k = -\frac{\ln{0.09090909}{8}[/tex]
k = 0.29973691
Then the function is:
[tex]A(t) = 440e^{-0.29973691t}[/tex]
2001 is 11 years after 1990, hence the amount is:
[tex]A(11) = 440e^{-0.29973691 \times 11} = 16[/tex]
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Determine what type of model best fits the given situation:
Answer:
B. quadratic function graph
The length of a rectangle is two more than double the width. If the perimeter is 100 inches, find the
dimensions.
Answer:
width = 34 inches
length = 16 inches
Step-by-step explanation:
Given:
1.)The length of a rectangle is two more than double the width
2.)The perimeter is 100 inches
Let's analyze the first part,
The length is 2 more than double the width so if we let x represent the length the width would be 2x + 2
Now the second part,
the perimeter is calculated by the following formula:
2*(w+l)
(w: width, l: length)
2*(x+2x+2) first do inside the parenthesis by adding like terms
x+2x+2 = 3x + 2 now multiply both terms with 2
2*(3x+2) = 6x + 4 this is the perimeter of the rectangle, now write another equation using this
6x + 4 = 100 subtract 4 from both sides
6x = 96 divide both sides by 6
x = 16 this the length and the width would be
2x + 2 = 2*16 + 2 = 34
Which function is graphed?
Answer: A
Step-by-step explanation:
The parabola has an open hole at x=3 and the line has a closed hole at x=3, so there should be [tex]x < 3[/tex] for the parabola and [tex]x \geq 3[/tex] for the line.
This eliminates all the options except for A.
if A and B are events with P(A) = 0.2, P(B) = 0.8, P(A and B) = 0.07, find P(A or B)
Work Shown:
P(A or B) = P(A) + P(B) - P(A and B)
P(A or B) = 0.2 + 0.8 - 0.07
P(A or B) = 0.93
Linda is training to be an assistant at the local animal shelter. To become an assistant she needs to complete 48 h of training. Linda keeps a graph of the number of hours of training left to be completed. What is the rate of change of the number of hours remaining with respect to the number of days? Remember to include units.
The equation between the number of days remaining and number of hours is given as y= -5x+50.
How to illustrate the equation?Let y be the number of days remaining and x be the no.of hours.
From the graph the slope of the line is given by m.
m=(y2 - y1)/(x2 - x1)
m=(30 - 40)/(4 - 2)
m= -10/2 = -5.
The above slope is in between points 2 and 4. As the line has a constant rate of growth the slope is the same between any points of the line.
Therefore the equation between the no.of days remaining and no.of hours is given by
y=mx +c.
y=-5x+c
Now to find the value of c. This can be determined by substituting the x and y values at a particular instant. For x=0,y=50. Therefore by these values, we get,
50= -5(0)+c
c=50.
Therefore the relation between the number of days remaining and number of hours is given as y= -5x+50.
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Please Please Please help with this math problem
Based on the information provided, the cost function, C(x) is given by 80x + 6000 while the demand function, P(x) is given by -1/20(x) + 920.
Mathematically, the revenue can be calculated by using the following expression:
R(x) = x × P(x)
Revenue, R(x) = x(-1/20(x) + 920)
Revenue, R(x) = x(-x/20 + 920)
Revenue, R(x) = -x²/20 + 920x.
Expressing the profit as a function of x, we have:
Profit = Revenue - Cost
P(x) = R(x) - C(x)
P(x) = -x²/20 + 920x - (80x + 6000)
P(x) = -x²/20 + 840x - 6000.
For the value of x which maximizes profit, we would differentiate the profit function with respect to x:
P(x) = -x²/20 + 840x - 6000
P'(x) = -x/10 + 840
x/10 = 840
x = 840 × 10
x = 8,400.
For the maximum profit, we have:
P(x) = -x²/20 + 840x - 6000
P(8400) = -(8400)²/20 + 840(8400) - 6000
P(8400) = -3,528,000 + 7,056,000 - 6000
P(8400) = $3,522,000.
Lastly, we would calculate the price to be charged in order to maximize profit is given by:
P(x) = -1/20(x) + 920
P(x) = -1/20(8400) + 920
P(x) = -420 + 920
P(x) = $500.
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Which choice is a term in this expression -3x - 7(x+4)
-3x is a term in the expression -3x - 7(x+4)
How to determine the term?The expression is given as:
-3x - 7(x+4)
Considering the following expression
Ax + B(x - b)
The terms in the expressions are Ax and B(x - b)
This means that -3x is a term in the expression -3x - 7(x+4)
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What is the domain and range of the quadratic function given by the equation /(x) = 2(x-4)] - 2
The domain of the function is the set of all real numbers and the range of the function is the set of all values greater than -2
How to determine the domain and the range?The function is given as:
f(x) = 2(x -4)^2 - 2
A quadratic function can take any real number as its input.
So, the domain of the function is the set of all real numbers
The vertex of the above function is:
Vertex = (4, -2)
And the leading coefficient is:
a = 2
The y value of the vertex is;
y = -2
Because the value of a is positive, then the vertex is a minimum.
This means that the range of the function is the set of all values greater than -2
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This table reflects the result of a survey conducted in a town to find out the number of cars of a particular color.
Which of the following ranges would be appropriate to use in order to represent the numerical data on the vertical axis of a Bar Graph?
A. 10 to 20
B. 20 to 100
C. 0 to 50
D. 0 to 30
the range that would be the most appropriate to represent the numerical data on the vertical axis is B. 20 to 100.
what range would be most appropriate?the table is not included but the range of 20 to 100 is most appropriate for the number of cars in town with a particular color.
this is because towns would normally have between hundreds and thousands of cars which means that cars of a particular color would be between 20 and 100 at least.
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The range that would be the most approx to represent the numerical data on the vertical axis is B. 20 to 100.
Bar graph :
Bar graphs are the pictorial representation of data (generally grouped), in the form of vertical or horizontal rectangular bars, where the length of bars is proportional to the measure of data
The range that would be the most approximately to represent the numerical data on the vertical axis is B. 20 to 100.
because
it is not possible to have zero number of cars that have a particular color,
in That way, we can eliminate options C and D .
in option A the range is too small which is not possible.
the table is not included but the range of 20 to 100 is most appropriate for the number of cars in town with a particular color.
this is because towns would normally have between hundreds and thousands of cars which means that cars of a particular color would be between 20 and 100 at least.
The magnitude, M, of an earthquake is represented by the equation M=2/3logE/E0 where E is the amount of energy released by the earthquake in joules and E0=10^4.4 is the assigned minimal measure released by an earthquake. Which shows a valid step in the process of calculating the magnitude of an earthquake releasing 2.5 • 10^15 joules of energy?
2.5•10^15 = 2/3logE/10^4.4
10^4.4=2/3logE/2.5•10^15
M=2/3log(9.95•10^9)
M=2/3log(2.55•10^10)
M=2/3log(9.95•10^10)
The magnitude of an earthquake releasing 2.5 * 10¹⁵ Joules of energy is 7.33
What is an equation?
An equation is an expression that shows the relationship between two or more numbers and variables.
Given that:
M = (2/3) * log (E/E₀)
Where M is the magnitude, E is the amount of energy and E₀ = 10^4..4
For E = 2.5 * 10¹⁵:
M = (2/3) * log (2.5 * 10¹⁵/10^4.4)
M = 7.33
The magnitude of an earthquake releasing 2.5 * 10¹⁵ Joules of energy is 7.33
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Given AABC shown on the coordinate plane below.
AA"B"C" = Ro 90⁰(T(-4,3)(ABC))
Draw AA"B"C" if
You may use different colors for the separate transformations. Indicate your final answer.
Feel free to use the Dynamic Geometry Tool to complete the transformations.
02
PENCIL
The triangle ABC is shifted upwards by 3 units and towards the left by 4 units. After translation again it is rotated 90° counterclockwise. All these transformations are shown in the graph below.
What are transformation rules?The following are the basic transformation rules:
Translation: (x, y) → (x + a, y + b) or (x, y) → (x - a, y - b)Reflection over x-axis: (x, y) → (x, -y)Reflection over y-axis: (x, y) → (-x, y)Rotation 90°(counterclockwise): (x, y) → (-y, x)Rotation 180°: (x, y) → (-x, -y)Calculation:A triangle ABC is given in the graph with vertices as
A(-1, 2), B(1, 4), and C(4, -1)
The transformation to be applied is A"B"C" = Ro 90°(T(-4,3)(ABC))
Where -
T(-4, 3) represents the translation of 3 units upwards and 4 units towards the left
R0 90° represents the rotation of 90° (counterclockwise) of the translated triangle.
Step 1: applying translation (-4, 3):
The new vertices of the triangle ABC translated by (-4, 3) units are represented by A'B'C'. They are:
A' - (-1 - 4, 2 + 3) = (-5, 5)
B' - (1 - 4, 4 + 3) = (-3, 7)
C' - (4 - 4, -1 + 3) = (0, 2)
These are shown in the graph below.
Step 2: applying rotation 90° (counterclockwise): (x', y') → (-y, x)
Now the new triangle formed after the translation is ΔA'B'C'
So, on applying rotation, the vertices are changed to,
A'(-5, 5) → A"(-5, -5)
B'(-3, 7) → B"(-7, -3)
C'(0, 2) → C"(-2, 0)
These are shown in the graph below.
Therefore, Δ ABC → Δ A'B'C' (by T(-4, 3)) → Δ A"B"C" (by Ro 90°) i.e.,
Δ A"B"C" = Ro 90°(T(-4, 3) ABC).
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The hospital in patient admission rate for employees of the ramsey
The computation shows that the the hospital in-patient admission rate for the employees of the Prendergast Corporation is 104.5 admissions per 1000 employees.
How to calculate the value?The in-patient admission rate for Ramsey Manufacturing company = 100 admissions per 1000 employees.
It is given that the in-patient rate of Prendergast will be 10% higher than Ramsey's.
So, in-patient rate of Prendergast:
= 100 + 10% of 100
= 110 admissions
Now, it is also given that out of total in-patients, 5% are for tonsillectomies (which are not in-patient).
So, in-patient admission rate for Prendergast:
= 110 - 5% of 110
= 110 - 5.5
= 104.5 admissions per 1000 employees
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Complete question:
The hospital in-patient admission rate for employees of the Ramsey Manufacturing Company is 100 admissions per 1000 employees per year.
The Prendergast Corporation has older employees and is told that its hospital in-patient admission rate will be 10% higher than Ramsey’s. At the same time, however, all tonsillectomies will be done in the hospital’s outpatient department instead of requiring the patient to be admitted as an in-patient. Given that 5% of all in-patient admissions are for tonsillectomies, what is the hospital in-patient admission rate for the employees of the Prendergast Corporation?
A. 110.0 B. 115.0 C. 109.5 D. 100.0 E. 104.5 F. 117.0
Christine is putting money into a savings account. She starts with $650 in the savings account, and each week she adds $60. Let S represent the total amount of money in the savings account (in dollars), and let W represent the number of weeks Christine has been adding money. Write an equation relating S to W. Then use this equation to find the total amount of money in the savings account after 11 weeks.
Total amount of money in the savings account after 11 weeks is $1310.
Total money in the account =
Initial Money + Money added per week x Number of weeks
Given:
Initial Money = $650
Money added per week = $60
Total money in the account = S
Number of weeks = W
Substituting it in the above equation we get,
S = $650 + $60xW (General Equation)
Total amount of money in the savings account after 11 weeks
S = $650 + $60x11
S = $650 + $660
S = $1310
Thus total amount of money in the savings account after 11 weeks is $1310.
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solve asap please!!!
The following data depicts the relationship between the Amount spent on insurance and the amount of inventory loss.
X = Amt spent on protection
Y = Amt of inventory lost or stolen
The least squared regression line : Y = 86.43 – 38.47 X
How much will the amount of loss in inventory be if the amount of protection is $6.39? Leave your answer to 2 decimal places.
Using the given regression line, it is found that the amount of loss in inventory will be of $159.39.
What is the regression line?The regression line is:
Y = 86.43 - 38.47X
In which:
X is the amount spent on protection.Y is the amount of inventory lost.In this problem, we have that X = $6.39, hence:
Y = 86.43 - 38.47 x 6.39 = -$159.39.
The amount of loss in inventory will be of $159.39.
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Sand will be placed under a circular pool with a diameter of 20 feet. The sand depth should be 2 inches. How many cubic feet of sand are needed?
you need 628 square feet of sand.
How many cubic feets of sand are needed?
Here we need to find the volume of the sand needed.
The volume filled with sand will be a cylinder of diameter of 20ft, and a height of 2 inches.
First, the radius is half of the diameter, then:
R = 20ft/2 =10ft
Remember that:
1ft= 12in
Then:
R = 10ft = 10*(12 in) = 120 in
And remember that the volume of a cylinder of radius R and height H is:
[tex]V = pi*R^2*H[/tex]
Where pi = 3.14
Then we have:
[tex]V = 3.14*(120 in)^2*2in = 90,432 in^2[/tex]
To get that in feets, we need to divide by 12 squared, then:
[tex]90,432 in^2 = 90,432ft^2/(12^2) = 628 ft^2[/tex]
So you need 628 square feet of sand.
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Grocer Edwards graphs the relationship between the
diameter and heights of different cans in his store. The
graph is below.
Height (cm)
18-
D
16+
14+
12+
10+
8+
6+
4+
2+
2
Choose 1 answer:
4
●
6
8
A
●
10 12
What is the meaning of point A?
●
Diameter (cm)
●
14 16 18
A can with an 10 cm diameter has an 18 cm height.
A can with an 18 cm diameter has an 11 cm height.
A can with an 11 cm diameter has an 18 cm height.
A can with an 18 cm diameter has an 10 cm height.
Considering the given graph, the meaning of point A is given by:
A can with an 11 cm diameter has an 18 cm height.
What does the graph gives?The graph gives the height of the can as a function of the diameter. Both measures are in cm. Then, the axis are given as follows:
The x-axis is the diameter.The y-axis is the height.Point A has coordinates (11,18), that is, x = 11, y = 18, hence the interpretation is:
A can with an 11 cm diameter has an 18 cm height.
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Answer:
A
Step-by-step explanation:
just took the quiz and can confirm the other guy is valid :D
A sports center offers party packages. They advertise a flat rate of $325 for the first 10 guests. They charge $15 per person for each additional guest. A formula for the cost of the party is:
C = 325 + 15p
where p is the number of guests more than 10. (For example, if 12 people come to the party, p = 2.) Suppose you want to have a huge birthday celebration this year. However, you have budgeted $600 for your party. How many guests can you invite if you decide to have your party at this sports center?
Using the given linear equation, we conclude that you can invite a maximum number of 21 guests.
How many guests can you invite if you decide to have your party at this sports center?Here the function is:
C(p) = 325 + 15*p
Where p is the number of guests minus 10, now we know that your budget is $600, then the maximum value of guests allowed is such that:
C(p) = 600 = 325 + 15*p
Now we can solve this equation for p:
600 - 325 = 15*p
275 = 15*p
175/15 = p = 11.67
Then the maximum whole number that p can take is p = 11
This means that the maximum number of guest that you can have is:
Guests = 10 + p = 10 + 11 = 21.
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-275+156-(-293)-157 = 17
ME PUEDEN DAR EL PROCEDIMIENTO
PLIS
The procedure for solving -275+156-(-293)-157 = 17 is to follow bodmas operation
Evaluation-275+156-(-293)-157 = 17
Using BODMAS
b - bracketo - offd - divisionm - multiplicationa - additions - subtraction-275+156-(-293)-157 = 17
= -275 + 156 + 293 - 157
= 17
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look at the picture
Answer:
C
Step-by-step explanation:
x²-9x<-8
x²-9x+(-9/2)²<-8+(-9/2)²
(x-9/2)²<-8+81/4
(x-9/2)²<(-32+81)/4
(x-9/2)²<49/4
|x-9/2|<7/2
-7/2<x-9/2<7/2
add 9/2
9/2-7/2<x-9/2+9/2<7/2+9/2
2/2<x<16/2
1<x<8
For which interval is the function constant? (−4,0) begin ordered pair negative 4 comma 0 end ordered pair (4,∞) left parenthesis 4 comma infinity right parenthesis (0,4) begin ordered pair 0 comma 4 end ordered pair (−∞,−4)
Answer: (-4, 0)
Step-by-step explanation: I just took the quiz and got it correct!
The function is constant on the intervals: (-4, 0), (4, ∞), and (0, 4). Within these intervals, the function's output remains the same for all values of x in each interval.
To determine the interval in which the function is constant, we need to examine the given ordered pairs (x, y) and check if the function's output (y-values) remains the same within that interval.
Let's analyze each interval:
1. (-4, 0): This interval represents all x-values greater than -4 and less than 0. In this interval, the function takes the value 0 for all x-values in the interval. Therefore, the function is constant (equal to 0) within this interval.
2. (4, ∞): This interval represents all x-values greater than 4. In this interval, the function's output is given as "∞" (infinity) for all x-values in the interval. The function is constant (equal to infinity) within this interval.
3. (0, 4): This interval represents all x-values greater than 0 and less than 4. In this interval, the function takes the value 4 for all x-values in the interval. Therefore, the function is constant (equal to 4) within this interval.
4. (-∞, -4): This interval represents all x-values less than -4. In this interval, the function's output is not specified or may not be constant. The information provided does not give us the exact function to determine the output for all x-values in this interval.
The function is constant on the intervals: (-4, 0), (4, ∞), and (0, 4). Within these intervals, the function's output remains the same for all values of x in each interval. However, we don't have enough information to determine if the function is constant on the interval (-∞, -4).
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Question 2(Multiple Choice Worth 2 points)
(03.01 LC)
Assume you are working with a standard deck of 52 cards. There are 13 cards (2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, king, and ace) in each of four suits
and spades).
What is P(Jack Heart) if you draw one card?
O
-
52
13
52
Question 3(Multiple Choice Worth 2 points)
(03.02 MC)
Answer:
Assume you are working with a standard deck of 52 cards. There are 13 cards (2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, king, and ace) in each of four suits
and spades).
What is P(Jack Heart) if you draw one card? 13
Complete this activity.
If the first element of the following pairs of numbers is a measure of hours and the second element is a measure of distance in miles, write an equation for D.
B = {(t, D ): (1, 50), (2, 100), (3, 150), . . .}
D =
t /2
50 t
50/ t
Answer:
D = 50t
Step-by-step explanation:
we see, with every additional hour the distance increases by 50.
that means in general that the number of hours are multiplied by 50 to get the distance.
in other words, this just calculates for a vehicle going constantly 50 miles per hour the distance it is traveling.
Part 2 - Find the error(s) and solve the problem correctly. Explain your corrections. Solve: 2cos x = 4 cos x sin 2 x Answer: 2cos x = 4 cos x sin 2 x 2cos x = 4 cos x sin ( 2 x 2 cos x in common onboth sides) 1 = sin 2 x The only place sin x = 1 is where the angle is . π 2 x = π
Answer:
l dont know l am not studying it sorry
Answer:
hey what was the answer?
Step-by-step explanation:
I need help im going to failllll!!!!!!
According to the general equation for conditional probability, if P(AB) = and P(B) = 2, what is P(A/B)? 12 O A. 3/ О в. 4 O c. 2/ C. 5 O D. 9
Using conditional probability, it is found that:
[tex]P(A|B^\prime) = \frac{1}{3}[/tex]
What is Conditional Probability?Conditional probability is the probability of one event happening, considering a previous event. The formula is:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which:
P(B|A) is the probability of event B happening, given that A happened.[tex]P(A \cap B)[/tex] is the probability of both A and B happening.P(A) is the probability of A happening.For this problem, we are given that:
[tex]P(B^\prime) = 1 - P(B) = 1 - \frac{1}{3} = \frac{2}{3}[/tex].[tex]P(A \cap B^\prime) = \frac{2}{9}[/tex]Then:
[tex]P(A|B^\prime) = \frac{P(A \cap B^\prime)}{P(B^\prime)}[/tex]
[tex]P(A|B^\prime) = \frac{\frac{2}{9}}{\frac{2}{3}}[/tex]
[tex]P(A|B^\prime) = \frac{1}{3}[/tex]
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Compare the monthly payments and total loan costs for the following pairs of loan options. Assume that both loans are fixed rate and have the same closing costs. You need a $200,000 loan Option 1 a 30-year loan at an APR of 10% Option 2 a 15-year loan at an APR of 9.5%. Find the monthly payment for each option. The monthly payment for option 1 is S The monthly payment for option 2 is S (Do not round until the final answer Then round to the nearest cent as needed) Find the total amount paid for each option The total payment for option 1 is S The total payment for option 2 is S (Use the answers from the previous step to find this answer Round to the nearest cent as needed) Compare the two options Which appears to be the better option? OA Option 2 will always be the better option B. Option 1 is the better option, but only if the borrower plans to stay in the same home for the entire term of the loan OC. Option 1 will always be the better option OD. Option 2 is the better option, but only if the borrower can afford the higher monthly payments over the entire term of the loan 0
The monthly payment for option 1 is $1755.144 and option 2 is $2088.97, total amount for option 1 is $631851.84 and option 2 is $376014.6, and on comparing option 2 will be better option.
Given that for $200,000 loan Option 1 is a 30-year loan at an APR of 10% Option 2 is a 15-year loan at an APR of 9.5%.
A concept that implies that the future value of money will be lower than its present value due to several factors such as inflation is known as TVM(time of value money).
Monthly Payments
Option 1
Loan Amount = $200,000
Number of payments = 30×12 = 360
Monthly interest rate = 10%/12 = 0.008333333
Monthly payment = Loan amount (1+ monthly interest rate)ⁿ×monthly interest rate/[(1+monthly interest rate)ⁿ- 1]
Monthly payment=200,000×(1+0.008333333)³⁶⁰×(0.008333333)/[(1+0.008333333)³⁶⁰-1]
Monthly payment=33062.328/18.83739
Monthly payment=$1755.144
Option 2
Loan Amount = $200,000
Number of payments = 15 x 12=180
Monthly interest rate = 9.5%/12=0.00792
Monthly payment = 200,000(1+0.00792)¹⁸⁰(0.00792)/[(1+0.00792)¹⁸⁰-1]
Monthly payment=6553.096/3.137
Monthly payment=$2088.97
Total Payments
Option 1
As we've found out the monthly payments, we now need to multiply it by the number of months.
$1755.144×360 = $631851.84
Option 2
$2088.97×180 = $376014.6
Conclusion
Option 2 will always be the better option economically as it saves $255837.24 ($631851.84 - $376014.6) in total payments.
Hence, For $200,000 loan Option 1 a 30-year loan at an APR of 10% Option 2 a 15-year loan at an APR of 9.5% is the monthly payment for option 1 is $1755.144 and option 2 is $2088.97, total amount for option 1 is $631851.84 and option 2 is $376014.6, and on comparing option 2 will be the better option.
Learn more about monthly cost from here brainly.com/question/1476828.
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A ball is thrown from an initial height of 5 feet with an initial upward velocity of 31 ft/s. The ball's height (in feet) after t seconds is given by the following.
h=5+31t-16t^2
Find all values of t for which the ball's height is 19 feet.
t= _ seconds
Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)
Solving a quadratic function, it is found that the ball has a height of 19 feet at t = 0.72 seconds and t = 1.22 seconds.
What is a quadratic function?A quadratic function is given according to the following rule:
[tex]y = ax^2 + bx + c[/tex]
The solutions are:
[tex]x_1 = \frac{-b + \sqrt{\Delta}}{2a}[/tex][tex]x_2 = \frac{-b - \sqrt{\Delta}}{2a}[/tex]In which:
[tex]\Delta = b^2 - 4ac[/tex]
In this problem, the function is:
h(t) = -16t² + 31t + 5
The height is of 19 feet when h(t) = 19, hence:
19 = -16t² + 31t + 5
16t² - 31t + 14 = 0.
Then:
[tex]\Delta = (-31)^2 - 4(16)(14) = 65[/tex][tex]x_1 = \frac{31 + \sqrt{65}}{32} = 1.22[/tex][tex]x_2 = \frac{31 - \sqrt{65}}{32} = 0.72[/tex]More can be learned about quadratic functions at https://brainly.com/question/24737967
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Proofs and congruent triangles 2 forgot to put images last time 50 points ( serious answer or 1 star and report ) ( YOU NEED TO CHECK MY ANSWERS PLEASE )
Answer:
Step-by-step explanation:
Q3 asks for reasons of statements in a theorem proof.
1 Given is correct
2 Definition of right angle is correct
3 should be sum of interior angles in a triangle
4 is substitution
5 subtracting 90degree from left and right hand side
6 is definition of complementary