A 1.00-mole sample of dry ice (solid CO₂) is placed in a flexible, sealed container and allowed to sublime. After complete sublimation, what will be the
container volume, in liters, at 26°C and 0.983 atm pressure?

Taking into account the reaction stoichiometry, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.

In first place, the balanced reaction is:

C₄H₆O₃ + C₇H₆O₃ (Salicyclic Acid) →C₉H₈O₄ (aspirin) + C₂H₄O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 138 grams of salicyclic acid form 180 grams of aspirin, 2.08 grams of salicyclic acid form how much mass of aspirin?

[tex]mass of aspirin=\frac{2.08 grams of salicyclic acidx 180 grams of aspirin}{138 grams of salicyclic acid}[/tex]

mass of aspirin= 2.713 grams

Then, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.

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The Percentage mass of NaCl is 1.78%.

The percent mass concentration of NaCl in the saline solution is determined from the molality of the solution.

The molality of the solution is further obtained from the freezing point depression formula.

The freezing point depression formula is given as follows:

where;

For the solution of NaCl;

ΔT = 0 - (-1.13) = 1.13

Kf = 1.86 °/m

i = 2

m = ΔT/(Kf * i)

m = 1.13/(1.86 * 2)

m = 0.3038 mol/kg

molar mass of NaCl = 58.5 g/mol

Mass of NaCl = 0.3038 * 58.5 = 17.8 g in

Percentage mass of NaCl = (17.8/1000) * 100

Percentage mass of NaCl = 1.78%

In conclusion, the percent mass of NaCl is obtained from the molality of the solution.

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The endangered species in my region with their estimate population are:

This cheetah is said to be an endangered species because of their loss of their habitat and  also due to fragmentation, trade and little human-activities.

West African Lion is said to be an endangered species because the lion's historic range in West Africa was said to be lowered by a lot of amount or scale as a result of land use changes and human activities such as falling of trees, buildings, etc.

Hence the endangered species in my region with their estimate population are:

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Answer:

28.0 grams CsF

Explanation:

To find the mass of CsF, you need to (1) convert grams CsXeF₇ to moles CsXeF₇ (via molar mass), then (2) convert moles CsXeF₇ to moles CsF (via mole-to-mole ratio from equation coefficients), and then (3) convert moles CsF to grams CsF (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value.

Molar Mass (CsF): 132.91 g/mol + 18.998 g/mol

Molar Mass (CsF): 151.908 g/mol

Molar Mass (CsXeF₇): 132.91 g/mol + 131.29 g/mol + 7(18.998 g/mol)

Molar Mass (CsXeF₇): 397.186 g/mol

1 CsF + XeF₆ -----> 1 CsXeF₇

73.1 g CsXeF₇             1 mole                 1 mole CsF              151.908 g
----------------------  x  --------------------  x  ------------------------  x  ------------------  =
                                  397.186 g           1 mole CsXeF₇             1 mole

=  27.958 g CsF

=  28.0 g CsF

Answer:

Mg₂P₂O₇ · 3 H₂O

Explanation:

(Step 1)

First, you need to convert each mass to moles via the molar masses of each element/compound.

Molar Mass (Mg): 24.305 g/mol

4.86 grams Mg              1 mole
------------------------  x  ------------------------  = 0.200 moles Mg
                                   24.305 grams

Molar Mass (P): 30.974 g/mol

6.20 grams P              1 mole
---------------------  x  ------------------------  =  0.200 moles P
                                30.974 grams

Molar Mass (O): 15.998 g/mol

11.20 grams O               1 mole
-----------------------  x  -----------------------  =  0.700 moles O
                                  15.998 grams

Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol

Molar Mass (H₂O): 18.014 g/mol

5.40 grams H₂O               1 mole
--------------------------  x  -----------------------  =  0.300 moles H₂O
                                     18.014 grams

(Step 2)

To find the amount of each element/compound in the formula, you need to divide each molar value by the smallest molar value. This allows you to determine the accurate molar ratio the hydrated salt should have. In this case, 0.200 moles is the smallest value.

0.200 moles Mg / 0.200  =  1 mole Mg

0.200 moles P / 0.200  =  1 mole P

0.700 moles O / 0.200  =  3.5 moles O

0.300 moles H₂O / 0.200  =  1.5 moles H₂O

There can only be whole number amounts of each element/compound in the formula. Therefore, you need to multiply each amount by 2.

1 mole Mg x 2 = 2 moles Mg

1 mole P x 2 = 2 moles P

3.5 moles O x 2 = 7 moles O

1.5 moles H₂O x 2 = 3 moles H₂O

(Step 3)

Now that we know the amount of each element/compound, we can build the formula. The amount of each element is represented by subscripts and the amount of each compound (H₂O) is represented by coefficients.

Mg₂P₂O₇ · 3 H₂O

Caffeine - Lead (Pb) - Copper (II) chloride (CuCl2) - Sodium chloride (NaCl) - Silver (Ag) - Tungsten

Sodium bicarbonate and acetic acid are not good substitute for sodium azide in airbags since the require more mass and produce less gas.

The chemical equation for the production of nitrogen gas from sodium azide is given below:

1 mole or 66 go of sodium azide produces 3 moles or 67.2 L of nitrogen gas.

The equation for the production of carbon dioxide from sodium bicarbonate and acetic acid is given below:

1 mole, 106 g of Na₂CO₃ and 1 mole, 82 g of CH₃COOH are required to produce 1 mole or 22.4 L of CO₂.

The mass of sodium azide required is less than that of sodium bicarbonate and acetic acid required. Also, sodium azide produces a greater volume of gas. Therefore, sodium bicarbonate and acetic acid are not good substitute for sodium azide in airbags.

In conclusion, sodium azide is a better choice in airbags.

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1.2 x 10² L of oxygen is formed if 77.37 L of water is produced.

The density of water at STP = 0.99 g/ ml but we will assume 1 g/ml

Determine the mass of water ([tex]H_{2}[/tex]o) = 77.37 L × [tex]\frac{1000 ml}{1l}[/tex] × [tex]\frac{1g}{ml}[/tex]

The mass of water = 77370 g

Convert mass into moles = 77370 [tex]H_{2}[/tex]o × [tex]\frac{1mol}{18.01528} H _{2}O[/tex]

= 4294.6876 mol of [tex]H_{2} O[/tex]

Use stoichiometry to find how many mols of oxygen [tex]o_{2}[/tex] were used:

= 4294.6876 mol of [tex]H_{2} O[/tex] × [tex]\frac{13 mol }{10 mol}[/tex]

= 5583.0939 mol [tex]o_{2}[/tex]

Convert mols to mass = 5583.0939 mol ×[tex]\frac{32 g}{mol }[/tex]

= 178659.0059 g [tex]o_{2}[/tex]

Convert mass into liters

The density of [tex]o_{2}[/tex] at STP = [tex]\frac{1.439}{ml}[/tex]

Density of [tex]o_{2}[/tex] = 1.2 × [tex]10^{2}[/tex]

Hence,1.2 x 10² L of oxygen is formed if 77.37 L of water is produced.

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1.2 x 10² L of oxygen is formed  if 77.37 L of water are produced at STP. The term is derived from the Greek word "oxy genes," which means "forms acid." a periodic table column that is vertical.

What is oxygen ?

The chemical element oxygen has an atomic number of 8. At normal temperatures and pressures, oxygen transforms into the chemical compound (O2) of two atoms, which is a colorless gas.

The density of H₂O at STP = 0.99 g ÷ ml, but we will assume 1 g/ml

The mass of  H₂O = 77370 g

Use stoichiometry to find  moles of oxygen given by

= 4294.6876 mol of X

= 5583.0939 mol

Convert moles into mass = 5583.0939 mol X

= 178659.0059 g

Then convert it into liter. 1.2 x 10² L of oxygen is formed  if 77.37 L of water.

Thus, 1.2 x 10² L of oxygen is formed  if 77.37 L of water are produced at STP.

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Answer: 962 torr

Explanation:

The number of photons given off will be 50 photons.

To find the answer, we need to know about the plank's equation.

                     [tex]E=-13.6(\frac{1}{(n_f)^2}- \frac{1}{(n_i)^2})eV\\[/tex]

                     [tex]n_f=4\\n_i=2\\N=50[/tex]

                  [tex]E=-13.6(\frac{1}{(4)^2}- \frac{1}{(2)^2})eV\\\\E=-13.6*-0.188=2.55eV[/tex]

                [tex]E=50*2.55eV=127.5eV[/tex]

                            E=nhf

                    [tex]n=\frac{E}{h*f} =\frac{127.5*1.67*10^{-19}J}{(6.63*10^-34)Js} \\[/tex]

                       [tex]\frac{1}{wave length}=R_H(\frac{1}{(n_i)^2}- \frac{1}{(n_f)^2})\\\\1/wv= 1.1*10^5(\frac{1}{(2)^2}- \frac{1}{(4)^2})=20625cm^{-1}.\\wavelength=486nm.[/tex]

                 [tex]f=\frac{c}{wavelength} =\frac{3*10^8}{486*10^{-9}} =6.172*10^{14}s{-1}[/tex]

                       [tex]n=\frac{E}{h*f} =\frac{127.5*1.67*10^{-19}J}{(6.63*10^-34)Js*6.17*10^{14} s^{-1}} \\\\n=52.05 photons[/tex]

Thus, we can conclude that, the number of photons given off will be 50 photons.

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The amount of heat deposited on the skin is 2.26 kJ.

The amount of heat given off by steam is determined using the formula below:

Quantity of heat = mass * latent heat of vaporization.

Moles of steam = 1.0/18

Heat = 1.0/18 * 40.7

Heat deposited = 2.26 kJ

In conclusion, the quantity of heat is determined from the latent heat of vaporization and the moles of steam.

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The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.

Mass of solute = Mass percent of solute x  Mass of the solution

Here,

Mass percent of solute = 18.7 %

Mass of the solution = 27.2 kg

Now put the value in above formula we get

Mass of solute = Mass percent of solute x  Mass of the solution

                         = [tex]\frac{18.7}{100} \times 27.2\ kg[/tex]

                         = [tex]\frac{508.64}{100}[/tex]

                         = 5.086

Thus from the above conclusion we can say that The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.

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The freezing point of the sucrose solution is -0.435°C.

The freezing point of the solution is determined from the freezing point depression formula below:

Kf(H₂O) = 1.86 Cm

m is molality of solution = moles of solute/mass of solvent

moles of sucrose = 8.0/342.3 = 0.0233 moles

m = 0.0233/0.1 = 0.233 molal

ΔT = 0.233 m * 1.86°C/m.

ΔT = 0.435 °C.

Freezing point of sucrose solution = 0°C - 0.435°C

Freezing point of sucrose solution  = -0.435°C.

In conclusion, the freezing point of sucrose solution is determined from the freezing point depression.

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Answer:

163 L

Explanation:

To find the volume, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = constant (0.0821 L*atm/mol*K)

-----> T = temperature (K)

Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.

P = 3.50 atm                         R = 0.0821 L*atm/mol*K

V = ? L                                   T = 75.3 °C + 273.15 = 348.45 K

n = 20.0 moles

PV = nRT

(3.50 atm)V = (20.0 moles)(0.0821 L*atm/mol*K)(348.45 K)

(3.50 atm)V = 572.1549

V = 163 L

Answer:

ion exchange

Explanation:

because in the time period of chemical reactions it product ion

Answer:

Blue or green

Explanation:

A chemical called anthocyanin is in red cabbage juice, which changes color depending on the pH of its environment. Dishwasher soap is usually alkaline, making the juice turn a blue-green color.

If C3H8O is dissolved in water, it would be expected to be a strong electrolyte.

A strong electrolyte is a solute or solution (already an electrolyte) that can completely dissociates in solution.

C3H8O is one of those compounds expected to be a strong electrolyte.

Thus, if C3H8O is dissolved in water, it would be expected to be a strong electrolyte.

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Answer:

Mole Fraction (H₂O)  =  0.6303

Mole Fraction (C₂H₅OH)  =  0.3697

Explanation:

(Step 1)

Calculate the mole value of each substance using their molar masses.

Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol

Molar Mass (H₂O): 18.014 g/mol

200.0 g H₂O            1 mole
---------------------  x  ------------------  =  11.10 moles H₂O
                                 18.014 g

Molar Mass (C₂H₅OH): 2(12.011 g/mol) + 6(1.008 g/mol) + 15.998 g/mol

Molar Mass (C₂H₅OH): 46.068 g/mol

300.0 g C₂H₅OH              1 mole
----------------------------  x  --------------------  =  6.512 moles C₂H₅OH
                                         46.068 g

(Step 2)

Using the mole fraction ratio, calculate the mole fraction of each substance.

                                            moles solute
Mole Fraction  =  ------------------------------------------------
                               moles solute + moles solvent

                                                  11.10 moles H₂O
Mole Fraction  =  -------------------------------------------------------------
                               11.10 moles H₂O + 6.512 moles C₂H₅OH

Mole Fraction (H₂O)  =  0.6303

                                             6.512 moles C₂H₅OH
Mole Fraction  =  -------------------------------------------------------------
                               11.10 moles H₂O + 6.512 moles C₂H₅OH

Mole Fraction (C₂H₅OH)  =  0.3697

The concentration of solution in mass percent is 60%.

Mass percentage refer to the percentage of solute present in solution.

The concentration of substance can be expressed in mass percent.

So, we can write,

Mass percent = mass of solute / mass of solution x 100.

Mass of solution = mass of solute + solvent.

Here, sucrose is the solute and water is solvent.

Mass of solute is 1.5Kg and mass of solvent is 1Kg.

Mass of solution = 1.5 + 1 = 2.5 Kg.

Mass percent = 1.5/2.5x100

So, Concentration of solution in mass percent = 60%.

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The molecular formula of the compound is C₃H₄.

The molecular formula of the compound is determined from the molecular mass of the compound.

The molecular mass of the compound is derived using the general gas equation as follows:

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁T₂/P₂T₁

Volume at STP, V₂ = (415 * 371 * 298(760 * 314)

V₂ = 192.26 mL = 0.192 L

Molar mass of gas = 22.4/0.192 * 0.315 = 36.75 g

Molecular formula is then determined from the mole ratio of the elements;

Carbon = 0.9 * 36.75/12 = 3

Hydrogen = 0.1 * 40/1 = 4

Thus, the molecular formula of the compound is C₃H₄.

In conclusion, the molecular formula of the gas is derived from the molecular mass.

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The correct number of significant figures are,

Final volume of burette is 38.86ml

Volume of NaOH is 38.36ml

Initial volume of burette V(I)= 0.50ml

Molarity of NaOH is M1 = 0.4171M

Volume of Vinegar V2 = 10.00ml

Molarity of acetic acid M2= 1.6M

Final volume of burette V(f)= ?

volume of NaOH V1 = V(f) - V(I) = ?

Molarity = moles of solute / volume of solution

Molarity of acetic acid = moles of CH3C00H / Volume of vinegar

1.6 = moles of CH3C00H / 10.00

moles of CH3C00H = 1.6 * 10.00

Moles of CH3COOH is 16.00mols

In a volumetric titration the amount of Standard solution (titrant) used in the titration is stoichiometrically equivalent to amount of unknown solution (analyte) used for the titration at the endpoint.

Hence,

Moles of NaOH = Moles of CH3COOH

Moles of NaOH is 16.00mols

Molarity of NaOH = moles of NaOH / Volume of NaOH

0.4171 = 16.00 / V(f)-V(I)

0.4171 = 16.00 / V(f)- 0.50

V(f)  = ( 16 / 0.4171 ) + 0.50

V(f) = 38.86 ml

Final volume of NaOH V(f) is 38.86ml

Volume of NaOH V1 = 38.86 - 0.50

Volume of NaOH is 38.36ml

DISCLAIMER: Question is incomplete

Initial volume of burette = 0.50ml

Molarity of NaOH  = 0.4171M

Volume of Vinegar = 10.00ml

Molarity of acetic acid = 1.6M

Final volume of burette = ?

volume of NaOH  = ?

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Filling out the table of elements below following the outlined order:

An element can be defined as a substance that can not be broken down into simpler substances.

An element serves as a building blocks for compounds and mixtures.

In conclusion, each element and its property as requested in the table are given above.

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The protons of a strong acid would be completely transferred to the solvent when dissolved.

An acid is defined as a substance that contains hydrogen that it can donate when reacting with another substance.

There are two main types of an acid which include:

A strong acid is a type of acid that has the ability to donate it's hydrogen/ protons completely in a chemical reaction.

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Answer:

If a rock displaces 1.65L of water, its volume must be 1.65L.
If you want to convert that to cm^3 it's 1000 cm^3 per liter...so 1650 cm^3

Explanation:

Answer: D. 3Ag+ + PO43- = Ag3PO4

Explanation:

Overall Chemical Equation:

Ensure that the elements on both sides of the equation are balanced.

3C2H3AgO2 + Na3O4P = Ag3PO4 + 3C2H3NaO2

Solubility Equation:

Determine the state or phase of each substance (gas=g, liquid=l, solid/non-soluble=s, aqueous/soluble=aq) in its undissociated form.

3C2H3AgO2(aq) + Na3O4P(aq) = Ag3PO4(s) + 3C2H3NaO2(aq)

Complete Ionic Equation:

The complete ionic equation includes spectator ions. Write it by breaking all the soluble ionic compounds into their respective ions.

3Ag+(aq) + 3CH3COO-(aq) + 3Na+(aq) + PO43-(aq) = Ag3PO4(s) + 3Na+(aq) + 3CH3COO-(aq)

Net Ionic Equation:

The balanced net ionic equation includes only species that are involved in the reaction. It can be found by removing ions that occur on both the reactant and product side of the complete ionic equation.

3Ag+(aq) + PO43-(aq) = Ag3PO4(s)

Answer:

Radiation

Explanation:

Answer:

See below

Explanation:

Conversion factor :  1 ft^3  = 28 .317  liters

$ 1.30 /( 17 ft^3 *  28.317 liters/ft^3)    =   $.0027  per liter  

Answer:

Option (2)

Explanation:

The two compounds formed will be AgCl and NaNO₃.

We can see that this will result in a balanced equation, so the answer is Option (2).

Answer:

B) NaNO3 + AgCl (s)

Explanation:

edge 2023

Answer:

Explanation:

green