Find DE
3x - 28
3x - 30
D
G
E
F
33

Answer:

connect the points (0, 3) and (4, 2)

By using the concept of linear progression and some algebraic handling, we conclude that Joe will earn an amount of $ 31 700 in the 14th year.

According to the statement, we have a case of linear progression as income increases at same rate in time. Linear progressions are described by this formula:

c' = c + r · t     (1)

Where:

First, we calculate the increase rate:

r = (29 600 - 22 600)/10

r = 700

Now we proceed to find when Joe will earn an annual income of $ 31 700:

31 700 = 22 600  + 700 · t

t = 13

By using the concept of linear progression and some algebraic handling, we conclude that Joe will earn an amount of $ 31 700 in the 14th year.

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Using the corresponding angles postulate:

m∠3 = 150°

m∠5 = 150°

According to the corresponding angles postulate, corresponding angles, ∠3 and ∠5 are congruent to each other.

Thus, we would have the following equation:

m∠3 = m∠5

Plug in the values

50x - 100 = 25x + 25

50x - 25x = 100 + 25

25x = 125

x = 125/25

x = 5

m∠3 = 50x − 100 = 50(5) − 100 = 150°

m∠5 = 25x + 25 = 25(5) + 25 = 150°

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Answer:

>>   [tex]6\frac{5}{18}[/tex]

Step-by-step explanation:

1) Add the whole numbers first.

[tex]5+\frac{5}{6} +\frac{4}{9}[/tex]

2) Find the Least Common Denominator (LCD) of [tex]\frac{5}{6} ,\frac{4}{9}[/tex] . In other words, find the Least Common Multiple (LCM) of [tex]6,9[/tex].

Method 1: By Listing Multiples

1. List the multiples of each number.

Multiples of 6 : 6, 12, 18, ...

Multiples of 9 : 9, 18, ...

2. Find the smallest number that is shared by all rows above. This is the LCM.

LCM = 18

3. Make the denominators the same as the LCD.

[tex]5+\frac{5\times 3}{6\times 3}+\frac{4\times 2}{9\times 2}[/tex]

4. Simplify. Denominators are now the same.

[tex]5+\frac{15}{18}+\frac{8}{18}[/tex]

5.  Join the denominators.

[tex]5+\frac{15+8}{18}[/tex]

6. Simplify.

[tex]5+\frac{23}{18}[/tex]

7. Convert [tex]\frac{23}{18}[/tex] to mixed fraction.

[tex]5+1\frac{5}{18}[/tex]

8. Simplify.

[tex]6\frac{5}{18}[/tex]

Decimal Form: 6.277778

Cheers.

The addition of 3 5/6 + 2 4/9  is 113/18

The fractional bar is a horizontal bar that divides the numerator and denominator of every fraction into these two halves.

Given:

3 5/6 + 2 4/9

Now, writing it into normal fraction

3 5/6 + 2 4/9

= 23/ 6 + 22/9

= 23/6 x 3/3 + 22/9 x 2/2

= 69/ 18 + 44/18

= 113/18

Hence, the addition is 113/18

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Answer: -5=x

Step-by-step explanation:

kmbtvonpvnp4tnv

Answer: B

Step-by-step explanation:

The parabola has an open hole at x=2, and the line has a closed hole at x=2.

This means the top part of the function should have domain [tex]x < 2[/tex], and the second part of the function should have domain [tex]x \geq 2[/tex].

This eliminates everything except for B.

we conclude that 900 cubes enter in the given box.

We need to find the volumes of both figures.

The blocks are cubes of 2cm by 2cm by 2cm, then the volume of each block is:

[tex]V = (2cm)^3 = 8cm^3[/tex]

The box has dimensions of 10cm by 12cm by 60cm, then the volume is:

[tex]V = 10cm*12cm*60cm = 7,200 cm^3[/tex]

The number of cubes that enter in the box is N such that:

[tex]N*8cm^3 = 7,200cm^3[/tex]

Solving for N, we get:

[tex]N = 7200cm^3/8cm^3 = 900[/tex]

In this way, we conclude that 900 cubes enter in the given box.

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The possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are [tex]\mathbf{\pm\{1,2,4,\frac 13, \frac 23,\frac{4}{3}}\}[/tex]

The function is given as:

f(x) = 3x^6 + 4x^3 -2x^2 + 4

The leading coefficient of the function is:

p = 3

The constant term is

q = 4

Take the factors of the above terms

p = 1 and 3

q = 1, 2 and 4

The possible zeros are then calculated as:

[tex]\mathbf{Zeros = \pm\frac{Factors\ of\ q}{Factors\ of\ p}}[/tex]

So, we have:

[tex]\mathbf{Zeros = \pm\frac{1,2,4}{1,3}}[/tex]

Expand

[tex]\mathbf{Zeros = \pm\frac{1,2,4}{1},\pm\frac{1,2,4}{3}}[/tex]

Solve

[tex]\mathbf{Zeros = \pm\{1,2,4,\frac 13, \frac 23,\frac{4}{3}}\}[/tex]

Hence, the possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are [tex]\mathbf{\pm\{1,2,4,\frac 13, \frac 23,\frac{4}{3}}\}[/tex]

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Answer:

(-4,3）

Step-by-step explanation:

The intervals are denoted as:

Closed intervals = [a, b]

This interval includes a and b.

Open intervals = (a, b)

This interval does not include a and b.

The interval that denotes the values between -4 and 3 on the given number line is [-4, 3].

The intervals are numbers or values between two given point

The intervals are denoted as:

Closed intervals = [a, b]

This interval includes a and b.

Open intervals = (a, b)

This interval does not include a and b.

We have,

A number line.

The set of values that is in the blue line is from -4 to 3.

This means that the blue line includes values from -4 to 3.

There are infinite numbers between -4 to 3.

The blue line denoted that the values -4 and 3 are also included.

The interval that denotes the values between -4 and 3 is:

= [-4, 3]

Thus,

The interval that denotes the values between -4 and 3 on the given number line is [-4, 3].

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Answer: x>2

Step-by-step explanation:

[tex]8(x-1) > 12-2x\\\\8x-8 > 12-2x\\\\10x-8 > 12\\\\10x > 20\\\\x > 2[/tex]

Answer: About 830 dollars

Step-by-step explanation: find 15% off on 897 then find 7.5 percent of 897, then add them together.

Answer:

A.

Step-by-step explanation:

1) according to the given graph, the real roots are: -1 and 4, it means the given expression can be evaluated using (x+1)(x-4)=x²-3x-4.

2) if to divide the given expression by (x²-3x-4), then

x⁴-7x³+23x²-29x-60=(x²-3x-4)(x²-4x-15), where

3) x=-1;4 - real roots, and

[tex]x=2^+_-i\sqrt{11} \ -nonreal \ roots.[/tex]

The composition of transformation that maps ABCD to EHGF is reflect over the y-axis, then translate (x - 1, y + 1)

Transformation is the movement of a point from its initial location to a new location. Types of transformations are reflection, rotation, translation and dilation.

Translation is the movement of a point either up, left, right or down in the coordinate plane.

The composition of transformation that maps ABCD to EHGF is reflect over the y-axis, then translate (x - 1, y + 1)

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See below for how the domain and the range are calculated

Function, y = -x^4 + 4

The function is given as:

y = -x^4 + 4

See attachment for the graph

From the attached graph, we have:

Function, y = 2x^3 - 1

The function is given as:

y = 2x^3 - 1

See attachment for the graph

From the attached graph, we have:

Function, y = ∛(2x + 8)

The function is given as:

y = ∛(2x + 8)

See attachment for the graph

From the attached graph, we have:

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A patient should be given 8 and a half tablets and Approx. 8 days should the patient stay on the medication.

Given:

To find:

Solution:

If each tablet contains 7 mg and the doctor orders 60 mg of Benadryl.

Then the patient should be given 60/7 tablets i.e., 8 and a half tablets.

If the patient is only to take 1 tablet per day, then approx 8 days the patient we stay on the medication.

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$9.75

Given the information, we know that for the first 3 days, she spends a total of $7.25. On the fourth day, she deposits $10 before buying lunch for $3.

This means she had $20, but spent $10.25. $20-$10.25=$9.75 is the amount she has in her account.

The solution set of the inequalities y ≤ x² – 3 and y > –x² + 2 is the darker region shown in the graph.

An equation is an expression that shows the relationship between two or more variables and numbers.

Inequality is an expression that shows the non equal comparison of two or more numbers and variables

The solution set of the inequalities y ≤ x² – 3 and y > –x² + 2 is the darker region shown in the graph.

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The graphs of f(x) and g(x) are transformed function from the function y = x^2 and the solution of the set of inequalities is (±1.581, -0.5)

The complete question is in the attached image (the first graph)

From the graph, we have:

f(x) = x^2 - 3 and g(x) = -x^2 + 2

To derive y ≤  x^2 - 3, we simply change the equality sign in the function f(x) to less than or equal to.

To derive y > -x^2 + 2, we simply change the equality sign in the function g(x) to greater than

The inequalities of the graphs become

y ≤ x^2 - 3 and y > -x^2 + 2

From the graph of the above inequalities (see attachment 2), we can see that the curves of the inequalities intersect at (±1.581, -0.5)

Hence, the solution of the set of inequalities is (±1.581, -0.5)

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The statement which does not adequately describe a developmental progression is Choice C- A developmental progression is a skill check- list that four-years- olds must master to be prepared for kindergarten.

The Developmental Progression of Functional Skills is a concept which describes the child's growth in which case, the child's develops relationship with family members and a sense of self in the process and this concept in discuss is not limited to four-year olds.

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Answer:

(2, -11)

Step-by-step explanation:

(x + 3, y + 2) = (5, -9)

x + 3 = 5

y + 2 = -9

x = 2

y = -11

Answer:

In question 20

B) the triangles are not similar

Step-by-step explanation:

u can see that 1 triangle length is 14 and other 49 and one triangle breath is 8 and other 28 so how they are same

Answer:

IN question 19

what is your question I can't understand

By trigonometric solution of triangles we conclude that the actor is staying at the balcony of the second floor.

This problem presents an application of trigonometric resolution of triangles to find the floor where the actor is in terms of the height of the building. Based on the picture seen in the image, we find that all known dimensions of the triangle , three angles and a side, are:

A = 140°, B = 30°, C = 10°, p = 6 m    

First, we must find the length of side AP by law of sines:

b / sin 30° = 6 / sin 10°

b = 6 × sin 30° / sin 10°

b ≈ 17.276 m

Second, the height of the building is found by trigonometric functions:

h = (17.276 m) · sin 40°

h ≈ 11.105 m

Therefore, the floor where the actor stays is:

3.8 + 3 · n = 11.105

3 · n = 7.305

n = 2.435

n = 2

By trigonometric solution of triangles we conclude that the actor is staying at the balcony of the second floor.

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Answer:

Step-by-step explanation:

8x + 2(x - 7) = 7x + 3x - 14

8x + 2x - 14 = 7x + 3x - 14                 Distributive property.

10x - 14 = 10x - 14                              Combine the like terms.

-14 = -14                                             Subtraction.

0 = 0                                                  Addition.

Since the statement 0 = 0 is true regardless of the value of x, there is infinitely many solutions.

Answer:

Median

Explanation:

Real estate prices are virtually usually biased to the right. If we estimate the price of a typical home in a city at $500,000. We would have no trouble locating properties for $2 million and $3 million, and perhaps even some $5 or $6 million residences. However, you won't find houses for under $1.5 million. Because of this, the mean value is pulled toward the high end more than the median value.

Part 1

[tex]f(a)=4-7a+16a^2[/tex]

Part 2

[tex]f(a+h)=4-7(a+h)+16(a+h)^2\\\\=4-7(a+h)+16(a^2 +2ah+h^2)\\\\=4-7a-7h+16a^2 +32ah+16h^2[/tex]

Part 3

[tex]\frac{f(a+h)-f(a)}{h}=\frac{(4-7a-7h+16a^2 +32ah+16h^2-(4-7a+16a^2)}{h}\\\\=\frac{-7h+32ah+16h^2}{h}\\\\=32a+16h-7[/tex]

The maximum height of the object is 15.4 m and occurs at 0.295 sec. The object touches ground at 2.06 seconds

An equation is an expression that shows the relationship between two or more variables and numbers.

A ball is thrown upward from the top of a building 15 meters high, at a velocity of 2.8m/sec. Hence:

s = -4.9t² + 2.8t + 15

The maximum height is at s'(t) = 0, hence:

-9.8t + 2.8 = 0

t = 0.295 s

s = -4.9(0.295)² + 2.8(0.295) + 15 = 15.4 m

The object reaches ground when s = 0, hence:

0 = -4.9t² + 2.8t + 15

t = 2.06 seconds

The maximum height of the object is 15.4 m and occurs at 0.295 sec. The object touches ground at 2.06 seconds

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Answer:

Step-by-step explanation:

hello :

 f(x) = √(2x)

g(x) = √(8x)

(f g)(x) = f(x)×g(x) =√(2x)×√(8x) = √(16x²) =4/x/

x ≥ 0: /x/ = x        (f g)(x) = 4x......(answer : A)

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

[tex]\qquad \sf  \dashrightarrow \: scale \: \: factor = \cfrac{new \: \: measure}{original \: measure} [/tex]

[tex]\qquad \sf  \dashrightarrow \: s = \dfrac{6}{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: s = 3[/tex]

so, correct choice is D