Answer: 3.41x10^3
Step-by-step explanation:
At the beginning of the year, we have:
R = 6.2x10 rats.
And we know that, in one year, each rat produces:
O = 5.5x10 offsprins.
Then each one of the 6.2x10 initial rats will produce 5.5x10 offsprings in one year, then after one year we have a total of:
(6.2x10)*(5.5x10) = (6.2*5.5)x(10*10) = 34.1x10^2
and we can write:
34.1 = 3.41x10
then: 34.1x10^2 = 3.41x10^3
So after one year, the average number of rats is: 3.41x10^3
Factor by grouping cd-9d-4c+36
Answer:
(d-4)(c-9)
Step-by-step explanation:
cd-9d-4c+36
d(c-9)-4(c-9)
pull out the (c-9),
(d-4)(c-9)
To determine her water pressure, Denise divides up her day into three parts: morning, afternoon, and evening. She then measures her water pressure at 2 randomly selected times during each part of the day.What type of sampling is used?a. Simple random b. Cluster c. Stratified d. Convenience e. Systematic
Answer:
The correct answer is:
Stratified (c.)
Step-by-step explanation:
Stratified sampling technique is one in which the groups of data are divided into smaller groups or strata, based on shared common characteristics in these groups, and the samples randomly selected from each group in a proportional way. In this example, the sub-groups used is "times of the day" ie. morning, afternoon or evening. Other strata that can be used are; age, gender, continents etc. Stratification is done when the researcher wants to understand the relationships between the two or more groups. Stratified random sampling is also known as proportional random sampling or quota random sampling.
:) (8x2 + 7y2 – z2 + 2yz + 3xz - 5xy) (2x – 3y) slove this in vertical method
Step-by-step explanation:
8x² + 7y² - z² + 2yz + 3xz - 5xy
x 2x - 3y
-----------------------------------------------
-24x²y - 21y³ + 3yz² - 6y²z - 9xyz + 15xy²
+ 16x³ + 14xy² - 2xz² + 4xyz + 6x²z - 10x²y
-----------------------------------------------------------
16x³-21y³-34x²y+6x²z+29y²x-6y²z-2xz²+3yz²-5xyz
x-(-4x-(y + y)); use x = -4, and y = -3 evaluate
please mark this answer as brainlist
Write a inequality.
Question: twice a number is no more than 14
Please help
Answer:
2x[tex]\leq[/tex]14
Step-by-step explanation:
Answer:
2x ≤ 14
Step-by-step explanation:
twice a number is no more than 14
2x ≤ 14
How are we supposed to find the Perimeter?
To compare the teaching methodologies of two of its eighth-grade math teachers, a school decides to compare student test scores from the two classes throughout the year.
Which type of statistical study is the school conducting?
a) Matched-pair design study
b) Meta-analysis
c) Retrospective observational study
d) Prospective observational study
Answer:
D) Prospective observational study
Step-by-step explanation:
A study which gathers data moving forward is called a prospective study. Since the data is gathered on students without controlling the setting moving forward, it is a prospective observational design.
PLEASE ANSWER ASAP!!!
Fill in the box for the missing numerator in the set of equivalent expressions in the picture
Answer options are also shown in picture
any unrelated answer will be reported
Answer:
A. 14z - 28
Step-by-step explanation:
simplify z² - 3z
a. z(z - 3)
the denominator on the right has z(z - 3). but it is also multiplied by (z - 2)
this means the numerator must also be multiplied by (z - 2)
14 x (z - 2) = 14z - 28
hope this helps :)
Please help me with this ,
Answer:
(a) -2.3°/min
(b) -2.9°/min
Step-by-step explanation:
The average rate of change is the ratio of the difference in R values to the difference in the corresponding t values.
(a) m = (157.6 -226.6)/(30 -0) = -69/30 = -2.3 . . . degrees per minute
__
(b) m = (61.6 -119.6)/(70 -50) = -58/20 = -2.9 . . . degrees per minute
find the measure of a
Answer:
Hello,
answer D 48°
Step-by-step explanation:
In the right triangle down, a+42°=90° ==> a=90°-42°=48°
. One sample has M = 18 and a second sample has M = 14. If the pooled variance for the two samples is 16, what is the value of Cohen’s d?
Answer:
Cohen's d : 1.00
Step-by-step explanation:
We know that M₁ = 18, and M₂ = 14. Given that the pooled variance for the these two samples are 16, S²Pooled = 16, and therefore S - pooled = 4.
The formula to solve for the value of Cohen's d is as follows,
d = M₁ - M₂ / S - pooled,
d = 18 - 14 / 4 = 4 / 4 = 1
Therefore the value of Cohen's d = 1
Find the midpoint of the segment with the given endpoints.
(7,10) and (-1,- 8)
Answer:
(3,1) is the midpoint
Step-by-step explanation:
To find the x coordinate of the midpoint, average the x coordinates of the endpoints
(7+-1)/2 = 6/2 =3
To find the y coordinate of the midpoint, average the y coordinates of the endpoints
(10+-8)/2 = 2/2 = 1
(3,1) is the midpoint
Answer:
(3, 1)
Step-by-step explanation:
We can use the formula [ (x1+x2)/2, (y1+y2/2) ] to solve for the midpoint.
7+(-1)/2, 10+(-8)/2
6/2, 2/2
3, 1
Best of Luck!
Please help quick !
Answer:
vertical angles
Step-by-step explanation:
Angle 1 and 3 are vertical angles. The angles are made from the same lines and share a vertex. They are opposite it each other
Find the missing side length. Leave your answers radical in simplest form. PLEASE HURRY
Answer:
u= 2 ; v = 1
Sen 60 = [tex]\frac{\sqrt{3}}{u}[/tex] so u=2
Using the pythagoras theorem [tex]u^{2} =v^{2} +\sqrt{3}^{2}[/tex] so v =[tex]\sqrt{2^{2} - 3}[/tex] =1
A cyclist rides her bike at a speed of 30 kilometers per hour. What is this speed in kilometers per minute? How many kilometers will the cyclist travel in 2
minutes? Do not round your answers.
Answer:
0.5 km/min and 1km
Step-by-step explanation:
30 km in an hour
30 km in 60 mins, 30/60 km in one minute so she cycle 0.5km/min. They will cover 1 km in 2 minutes
The average price of a college math textbook is $158 and the standard deviation is $26. Suppose that 40 textbooks are randomly chosen. Round all answers to 4 decimal places where possible.
What is the distribution of ¯xx¯? ¯xx¯ ~ N(,)
For the group of 48, find the probability that the average price is between $153 and $155.
Find the first quartile for the average textbook price for this sample size. $ (round to the nearest cent)
For part b), is the assumption that the distribution is normal necessary? Yes No
Please only answer if you are able to answer correctly and entirely.
The probability that the average price is between $153 and $155 is 0.04.
What is the probability?Probability refers to a possibility that deals with the occurrence of random events.
The probability of all the events occurring need to be 1.
The average price of a math textbook =$158
The standard deviation =$26
The mean= 158
n =number of textbooks randomly chosen which is 40
n=10
Then
σ = 26
σₓ = σₓ/√n
= 26/√40
Therefore. σₓ² = 16.90
For the group of 48, find the probability that the average price is between $153 and $155.
The probability that the average price is between $153 and $155
= 0.04
Learn more about probability here;
https://brainly.com/question/11234923
#SPJ1
Please help. I’ll mark you as brainliest if correct!
Answer: x= -1, z=2, y= -4
Step-by-step explanation:
System of equations:
-5x - 4y - 3z= 15 +
-10x + 4y + 6z= 6
-15x + 3z = 21 ------> 3 (-5x + z) = 7.3
-5x + z = 7
now,
-10x + 4y + 6z= 6
2(-5x + z) + 4y + 4z = 6
14 + 4y + 4z = 6
7 + 2y + 2z = 3
2y + 2z= -4
y+z=-2
Now we were using the equation: 20x + 4y + 4z = -28
20x + 4(y+z) = 20x -8= - 28
20 x = -20
x= -1
With this we can find y and z
X=-1
-5x + z = 7
z= 2
y+z=-2
y=-4
Finally we have: x= -1, z=2, y= -4
I hope this can help you.
Thank you
PLEASE PLEASE PLEASE HELP ME ANSWER THIS QUESTION QUICK!! The picture of the question is down below. The answer choices are increased or decreased.
Answer:
NEGATIVE; DECREASED.
Step-by-step explanation:
A correlation coefficient of -0.76 indicates that there is a "fairly" strong negative relationship between the daily temperature and the number of people who visit the store.
This implies that, as the daily temperature increases, number of customers who come to the store decreases.
Therefore, the interpretation of the situation is:
"There is a NEGATIVE association between x and y. As the high temperature of the day increases across days, the number of customers who come to the store DECREASED.
The mean temperature for the first 4 days in January was 8°C. The mean temperature for the first 5 days in January was 7°C. What was the temperature on the 5th day? SOMEONE HELP FIRST ANSWER BRAINLIEST THIS TIME I PROMISE LOL
Answer:
The temperature of the 5th day was 3°C
Step-by-step explanation:
Mean temperature of the first 4 days = 8°C
Note that:
Mean = Sum of temperatures ÷ number of days
∴ 8 = sum of temperature ÷ 4
[tex]= 8 = \frac{sum\ of\ temperatures}{4}[/tex]
[tex]= sum\ of\ temperatures\ = 8\ \times\ 4 = 32[/tex]
Therefore the sum of the first 4 days = 32
Let the temperature of the next day (the fifth day) be m
Hence,
sum of the temperatures of first 5 days = 32 + m - - - - (1)
Next, the sum of the first 5 days can be calculated from the given average of the first 5 days as follows:
Mean temperature of the first 5 days = 7
[tex]Mean = \frac{sum\ of\ temperatures}{number \ of\ days}\\\\7 = \frac{sum\ of\ temperatures}{5} \\sum\ of\ temperatures\ = \ 7\ \times\ 5\ = 35\\sum\ of\ temperature\ of\ the\ first\ 5\ days\ =\ 35 - - - - - (2)[/tex]
Now, you will notice that equation (1) = equation (2)
∴ 32 + m = 35
m = 35 - 32 = 3
therefore, the temperature of the 5th day was 3°C
please help asap
Addition prop of equality
subtraction prop of quality
multiplication prop of equality
Division prop of equality
simplifying
distrib prop
Answer:
multiplication prop of equality, (multiplying both sides by 6)
simplifying, (not distrib prop as there is no parentheses)
Addition prop of equality, (adding 18 to each side)
simplifying
Find the equation of the circle in standard form for the given center (h, k) and radius R:(H,K)=(4/3,-8/8),R=1/3
Answer:
The answer is option BStep-by-step explanation:
Equation of a circle is given by
( x - h)² + ( y - k)² = r²
where r is the radius and
( h , k) is the center of the circle
From the question the radius R = 1/3
the center ( h ,k ) = (4/3 , -8/3)
Substituting the values into the above equation
We have
[tex](x - \frac{4}{3} )^{2} + {(y - - \frac{8}{3}) }^{2} = ({ \frac{1}{3} })^{2} [/tex]
We have the final answer as
[tex](x - \frac{4}{3} )^{2} + {(y + \frac{8}{3}) }^{2} = \frac{1}{9} [/tex]
Hope this helps you
Solve for x
A. 9
B. 10
C. 42
D. 12
Answer:
Option D, 12
Step-by-step explanation:
4x-8=80/2
or, 4x-8=40
or, 4x=48
or, x=12
Answer:
Given:-
m∠DEF= (4x-8) °
m DE= 80°
Using a property :- m ∠DEF= 1/2 (m DE)
[tex](4x-8)[/tex] ° [tex]= 1/2 (80)[/tex]
[tex](4x-8)[/tex]° [tex]=(40)[/tex] °
[tex]4x-8=40[/tex]
Add 8 to both sides:-
[tex]4x=48[/tex]
Divide both sides by 4:-
[tex]\frac{4x}{4}=\frac{48}{4}[/tex]
[tex]x=12[/tex]
OAmalOHopeO
Find the equation (in terms of x) of the line through the points (-2,-3) and (4,-1)
Answer:
y = 1/3x - 7/3
Step-by-step explanation:
y2 - y1 / x2 - x1
-1 - (-3) / 4 - (-2)
2/6
= 1/3
y = 1/3x + b
-1 = 1/3(4) + b
-1 = 4/3 + b
-7/3 = b
Robert has $20,000, part or all of which he wants to invest into a combination of government bonds and municipal bonds. He wants to invest no more than $5,000 into municipal bonds, and at least twice as much into government bonds than into municipal bonds.
Answer:
x + y ≤ 20,000y ≤ 5,000x ≥ 2yStep-by-step explanation:
Given:
Total amount = $20,000
Assume
Government bonds = x
Municipal bonds = y
Computation:
1. Invest total money
x + y ≤ 20,000
2. invest no more than $5,000 into municipal bonds
y ≤ 5,000
3. at least twice as much into government bonds.
x ≥ 2y
in triangle JKL, angle JKL is a right angle, line KM is an altitude, JL=20, ML=4. Find KM
9514 1404 393
Answer:
KM = 8
Step-by-step explanation:
The ratio of long side to short side is the same for all of the triangles in this geometry:
KM/ML = JM/KM
KM² = ML·JM = 4(20-4) = 64
KM = √64 = 8
The length of KM is 8 units.
Determine whether (a) x = -1 or (b) x = 2 is a solution to this equation
Answer:
x = 2 is the solution to x + 1.5 = 3.5
Step-by-step explanation:
x + 1.5 = 3.5
-1.5 -1.5
--------------------
x = 2
pls help :Find the missing side or angle.
Round to the nearest tenth.
Answer:
C° = 71.6056
Step-by-step explanation:
Law of Cosines: c² = a² + b² - 2abcosC°
Step 1: Plug in known variables
29² = 30² + 15² - 2(30)(15)cosC°
Step 2: Evaluate
841 = 900 + 225 - 900cosC°
-59 = 225 - 900cosC°
-284 = -900cosC°
71/225 = cosC°
cos⁻¹(71/225) = C°
C° = 71.6056
And we have our answer!
Answer:
79.0°
Step-by-step explanation:
The Law of Cosines is used for this purpose. It tells you ...
a² = b² +c² -2bc·cos(A)
Solving for A gives ...
cos(A) = (b² +c² -a²)/(2bc) = (15² +29²-30²)/(2(15)(29)) = 166/870
Using the inverse cosine function, we find the angle to be ...
A = arccos(166/870) ≈ 79.00026°
A ≈ 79.0°
In a large on-the-job training program, half of the participants are female and half are male. In a random sample of six participants, what is the probability that an investigator will draw at least one male?† (Round your answer to four decimal places.) P(X ≥ 1) =
Answer: 0.9844
Step-by-step explanation:
given data:
sample size n = 6
It’s assumed that half the population are male and the remaining half are females
F = 1/2
M = 1/2
the probability that the investigator would draw altleats one male
P ( x ≥ 1 ) =
= 1 - ( 0.5 ) ^ 6
= ( 0.5 )^6
= 0.9844
round 1,965 to the nearest tenth
Step-by-step explanation:
1965 round to the nearest tenth is 1970
Answer:
1965.0
Step-by-step explanation:
2065 Q.No. 2 a A firm produced 100 calculator sets during its first year. The total number of calculator sets produced at the end of five years is 4,500. Assume that the production increases uniformly each year. Estimate the increase in production each year. [3] Ans: 400
Answer:
400
Step-by-step explanation:
First, the firm produces 100 sets its first year. This means that our equation starts at 100. Next, the total number of calculator sets in 5 years is 4500. With y₁ representing the amount of calculator sets produced during year 1, y₂ representing the amount of sets during year 2, and so on, we can say that
y₁+y₂+y₃+y₄+y₅ = 4500
100 + y₂+y₃+y₄+y₅ = 4500
Next, we are given that the production increases uniformly by an amount each year. Representing that amount as a, we can say that
y₁+a = y₂
y₂+a = y₃
y₁+a+a = y₃
y₁+ 2 * a = y₃
and so on, so we have
100 + y₂+y₃+y₄+y₅ = 4500
100 + (100+a) + (100+2a) + (100+3a) + (100+4a) = 4500
500 + 10a = 4500
subtract 500 from both sides to isolate the a and its coefficient
4000 = 10a
divide both sides by 15 to isolate a
a = 400