Complete the square to transform the expression x2 - 2x - 2 into the form a(x - h)2 + k

Complete The Square To Transform The Expression X2 - 2x - 2 Into The Form A(x - H)2 + K

Answers

Answer 1

Answer:

A

Step-by-step explanation:

Find the vertex form of the quadratic function below.

y = x^2 - 4x + 3

This quadratic equation is in the form y = a{x^2} + bx + cy=ax  

2

+bx+c. However, I need to rewrite it using some algebraic steps in order to make it look like this…

y = a(x - h)^2 + k

This is the vertex form of the quadratic function where \left( {h,k} \right)(h,k) is the vertex or the “center” of the quadratic function or the parabola.

Before I start, I realize that a = 1a=1. Therefore, I can immediately apply the “completing the square” steps.

STEP 1: Identify the coefficient of the linear term of the quadratic function. That is the number attached to the xx-term.

STEP 2: I will take that number, divide it by 22 and square it (or raise to the power 22).

STEP 3: The output in step #2 will be added and subtracted on the same side of the equation to keep it balanced.

Think About It: If I add 44 on the right side of the equation, then I am technically changing the original meaning of the equation. So to keep it unchanged, I must subtract the same value that I added on the same side of the equation.

STEP 4: Now, express the trinomial inside the parenthesis as a square of a binomial, and simplify the outside constants.

After simplifying, it is now in the vertex form y = a{\left( {x - h} \right)^2} + ky=a(x−h)  

2

+k where the vertex \left( {h,k} \right)(h,k) is \left( {2, - 1} \right)(2,−1).

Visually, the graph of this quadratic function is a parabola with a minimum at the point \left( {2, - 1} \right)(2,−1). Since the value of “aa” is positive, a = 1a=1, then the parabola opens in upward direction.

Example 2: Find the vertex form of the quadratic function below.

The approach to this problem is slightly different because the value of “aa” does not equal to 11, a \ne 1a  

​  

=1. The first step is to factor out the coefficient 22 between the terms with xx-variables only.

STEP 1: Factor out 22 only to the terms with variable xx.

STEP 2: Identify the coefficient of the xx-term or linear term.

STEP 3: Take that number, divide it by 22, and square.

STEP 4: Now, I will take the output {9 \over 4}  

4

9

​  

 and add it inside the parenthesis.

By adding {9 \over 4}  

4

9

​  

 inside the parenthesis, I am actually adding 2\left( {{9 \over 4}} \right) = {9 \over 2}2(  

4

9

​  

)=  

2

9

​  

 to the entire equation.

Why multiply by 22 to get the “true” value added to the entire equation? Remember, I factored out 22 in the beginning. So for us to find the real value added to the entire equation, we need to multiply the number added inside the parenthesis by the number that was factored out.

STEP 5: Since I added {9 \over 2}  

2

9

​  

 to the equation, then I should subtract the entire equation by {9 \over 2}  

2

9

​  

 also to compensate for it.

STEP 6: Finally, express the trinomial inside the parenthesis as the square of binomial and then simplify the outside constants. Be careful combining the fractions.

It is now in the vertex form y = a{\left( {x - h} \right)^2} + ky=a(x−h)  

2

+k where the vertex \left( {h,k} \right)(h,k) is \left( {{{ - \,3} \over 2},{{ - 11} \over 2}} \right)(  

2

−3

​  

,  

2

−11

​  

).

Example 3: Find the vertex form of the quadratic function below.

Solution:

Factor out - \,3−3 among the xx-terms.

The coefficient of the linear term inside the parenthesis is - \,1−1. Divide it by 22 and square it. Add that value inside the parenthesis. Now, figure out how to make the original equation the same. Since we added {1 \over 4}  

4

1

​  

 inside the parenthesis and we factored out - \,3−3 in the beginning, that means - \,3\left( {{1 \over 4}} \right) = {{ - \,3} \over 4}−3(  

4

1

​  

)=  

4

−3

​  

 is the value that we subtracted from the entire equation. To compensate, we must add {3 \over 4}  

4

3

​  

 outside the parenthesis.

Therefore, the vertex \left( {h,k} \right)(h,k) is \left( {{1 \over 2},{{11} \over 4}} \right)(  

2

1

​  

,  

4

11

​  

).

Example 4: Find the vertex form of the quadratic function below.

y = 5x^2 + 15x - 5  

Solution:

Factor out 55 among the xx-terms. Identify the coefficient of the linear term inside the parenthesis which is 33. Divide it by 22 and square to get {9 \over 4}  

4

9

​  

.

Add {9 \over 4}  

4

9

​  

 inside the parenthesis. Since we factored out 55 in the first step, that means 5\left( {{9 \over 4}} \right) = {{45} \over 4}5(  

4

9

​  

)=  

4

45

​  

 is the number that we need to subtract to keep the equation unchanged.

Express the trinomial as a square of binomial, and combine the constants to get the final answer.

Therefore, the vertex \left( {h,k} \right)(h,k) is {{ - \,3} \over 2},{{ - \,65} \over 4}  

2

−3

​  

,  

4

−65

​  

.

Answer 2

Answer:

(x - 1 )^2 - 3

Step-by-step explanation:

( x - 1 )^2 + ( -3)

x^2 - 2x + 1 - 3

x^2 - 2x - 2


Related Questions

is 1/5 a rational or irrational number (20 points pls help)

Answers

Answer:

rational

Step-by-step explanation:

Answer:

it's Rational Number

Step-by-step explanation:

since each integer can't be written in the fraction form or for this example it would be thus 5 so it would be a rational number

(2.05 MC) Triangle PQR is transformed to Triangle P'Q'R'. Triangle PQR has vertices P(4,0), Q(0,-4) and R(-8,-4). Triangle P'Q'R' has vertices P'(1,0), Q'(0,-1), and R'(-2,-1). Part A: What is the scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' Part B: Write The Coords of triangle P"Q"R" obtained after P'Q'R' is reflected about the y-axis Part C: Are the two Triangles PQR and P"Q"R" congruent?

Answers

Answer:

Part A: The scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' is 1/4

Part B:

P''(-1, 0)

Q''(0, -1)

R''(2, -1)

Part C:

The two Triangles PQR and P''Q''R'' are not congruent

Step-by-step explanation:

The coordinates of triangle PQR are;

P(4, 0)

Q(0, 4)

R(-8, -4)

The coordinates of triangle P'Q'R' are;

P'(1, 0)

Q'(0, -1)

R'(-2, -1)

Part A:

The scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' can be found from the ratio of the respective coordinates as follows;

The ratio of the x, and y coordinates of the points are;

P'/P  = x'/x = 1/4, y'/y =0/0

R'/R = x'/x = -2/-8 = 1/4, y'/y =-1/-4 = 1/4

Therefore, the scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' = 1/4

Part B: For reflection across the y-axis, we have;

Pre-image (x, y) becomes the image, (-x, y)

Therefore, we have;

Reflection of P'(1, 0) about the y-xis becomes P''(-1, 0)

Reflection of Q'(0, -1) about the y-xis becomes Q''(0, -1)

Reflection of R'(-2, -1) about the y-xis becomes R''(2, -1)

Part C:

The two Triangles PQR and P''Q''R'' are similar but they are not congruent as the dimensions of PQR are larger than the dimensions of the sides of triangle P''Q''R''.

(A) The scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R'  is 1/4

(B) Coordinates of Δ P"Q"R"

P" (-1,0)

Q"(0,-1)

R"(2,-1)

(C) Triangles PQR and P"Q"R" are not congruent.

Given

ΔPQR is transformed into ΔP'Q'R'

Coordinates of P, Q, R are

P (4,0),

Q(0,-4)

R(-8,-4)

Coordinates of P'Q'R' are

P'(1,0)

Q'(0,-1)

R'(-2,-1)

(A) By Distance formula we can find the distance between P Q and P'Q'

Distance formula = [tex]D= \sqrt{(X_2-X_1)^2+(Y_2-Y_1)^2 }[/tex]

Where D = Distance between two points [tex](X_1.Y_1) \; and\; (X_2.Y_2)[/tex]

from distance formula we can write that

[tex]PQ = \sqrt{(0-4)^2+ (-4-0)^2} }\\[/tex]

PQ = [tex]4\sqrt{2}[/tex]

Similarly

P'Q'= [tex]\sqrt{2}[/tex]

PQ /P'Q' = 4

hence the scale factor of dilation is 1/4 (Compression)

(B )The Coordinates of Reflection about y axis can be written for a point

[tex](x,y ) \; as \; (-x,y)[/tex]

So the Coordinated of Δ P"Q"R" can be written as

P" (-1,0)

Q"(0,-1)

R"(2,-1)

(C) ΔPQR  and ΔP"Q"R" are similar triangles but they are not  congruent because their sides  are not equal in size.

For more information please refer to the link below

https://brainly.com/question/12413243

PLEASE HELP ASAP
I WILL MARK BRAINLIEST

Answers

Answer:

Estimated 120 students

Step-by-step explanation:

Hi there!

The survey established that 3 out of the 75 students did not have social media accounts.

[tex]\displaystyle \frac{3}{75}[/tex]

Let [tex]x[/tex] be equal to the number of students in the entire school who does not have social media accounts.

[tex]\displaystyle\frac{x}{3000}[/tex]

Create a proportion:

[tex]\displaystyle \frac{3}{75}=\displaystyle\frac{x}{3000}[/tex]

Multiply both sides by 3000 to isolate [tex]x[/tex]:

[tex]\displaystyle \frac{3}{75}*3000=\displaystyle\frac{x}{3000}*3000\\\\\frac{9000}{75}=x\\\\120=x[/tex]

Therefore, the number of students in the entire school who do not have social media accounts is estimated to be 120.

I hope this helps!

Can someone please help me I don’t know how to do this (Due today)

Answers

First go to the y intercept (or the b in y=mx+b) look for the slope and plot the points on the graph they're talking about e.g. #23 the y-intercept is 6 go to the 6 on the y axis, and then look at the slope (x), so it goes up and over to the right since it's positive by 1

Given that ΔABC is a right triangle with the right angle at C, which of the following is true?

1. tan A = 1/(tan B)
2. tan A = sin B
3. cos A = 1/(cos B)
4. sin B = 1/(sin A)

Answers

Answer:

1. tan A = 1/(tan B)

Step-by-step explanation:

By definition,

tangent A = opposite / adjacent = a / b

and

tangent B = opposite / adjacent = b / a

Therefore tangent A = a/b = 1/tan(B)

Answer: Tan a=tan b

I belive

Step-by-step explanation:

Question 8 If f (2) = (1 + 3) and g (2) VO+ 7, find g (f (x)). 9(f()) = 1 + 10 O g(f ()) = VI + 3 +7 Og(f (x)) = v= + 10 Og(f (2)) = 2? + 10​

Answers

Answer:

x+10

Step-by-step explanation:

f(x) = (x+3)^2 and g(x) = sqrt(x)+7

g(f(x)) =

Replace f(x) in for x in the function g(x)

        = sqrt((x+3)^2)+7

        = x+3 +7

         = x+10

arav spent 1 3/4 hours in studies and 2 1/2 hours in playing cricket. how much time did he spent at all ??

Answers

To find the answer we need to add these fractions
= 7/4 + 5/2
= (7+10)/4
= 17/4
= 4 1/4

Answer:

[tex] \boxed{4 \frac{1}{4} \: \: hours}[/tex]

Step-by-step explanation:

Time spent in studies = [tex]1 \frac{3}{4} [/tex]

Time spent in playing cricket = [tex]2 \frac{1}{2} [/tex]

Now, let's find the hours that he spent at all:

[tex] \mathsf {1 \frac{3}{4} + 2 \frac{1}{2} }[/tex]

Convert mixed fraction into improper fraction

[tex] \mathsf{ = \frac{7}{4} + \frac{5}{2} }[/tex]

Take the LCM

[tex] \mathsf{ = \frac{7 + 5 \times 2}{4} }[/tex]

Multiply the numbers

[tex] \mathsf{ = \frac{7 + 10}{4} }[/tex]

Add the numbers

[tex] \mathsf{ = \frac{17}{4} }[/tex]

Convert the improper fraction into mixed fraction

[tex] \mathsf{ = 4 \frac{1}{4} }[/tex] hours

Hope I helped!

Best regards!

I'm under the water on this problem, please help me:

question: f(x)=10x−3

answer choices:

A. f(−5)

B. f(0)

C. f(7)

D. f(t^2+2)

E. f(12−x)

F. f(x+h)

Answers

Answer:

See below

Step-by-step explanation:

Okay so...I might be interpreting the question wrong-if I am please comment! I'll fix it to the best of my ability.

A) Plug in -5 to all x values

   f(-5)=10(-5)-3

          ==50-3

    f(-5)= -53

B) f(0)=10(0)-3

    f(0)= -3

C) f(7)=10(7)-3

         =70-3

    f(7)=67

D) f(t^2+2)=10(t^2+2)-3

                 =10t^2+20-3

     f(t^2+2)=10t^2+17

E) f(12-x)=10(12-x)-3

              =120-10x-3

    f(12-x)=117-10x

F) f(x+h)=10(x+h)-3

             =10x+10h-3

what is this supposed to be bro pls help

Answers

Answer: 1

Step-by-step explanation:

so i put the amount of flour to servings into ratios (fractions)

28:14

9:12

10:13

then I put them into the same denominators

2184:1092

819/1092

840/1092

the first one is the greatest

can someone please please help me :/ I have to get this right. please help​

Answers

Answer: Choice B. f(x) = 100 - 68x

Work Shown:

Solve for y. Then replace y with f(x).

[tex]680x + 10y - 1000 = 0\\\\10y - 1000 = -680x\\\\10y = -680x + 1000\\\\y = \frac{-680x + 1000}{10}\\\\y = \frac{-680x}{10} + \frac{1000}{10}\\\\y = -68x + 100\\\\y = 100 - 68x\\\\f(x) = 100 - 68x\\\\[/tex]

Effectively this involves adding 1000 to both sides and subtracting 680x from both sides, afterward we divide both sides by 10 to isolate y.

Answer:

choice B

Step-by-step explanation:

I did this problem like 6 months ago......

What is – x4 + 2x3 + 6x2 – 10x – 4 divided by X – 2?

Answers

Answer:

-x^3 + 6x + 2

Step-by-step explanation:

Which properties belong to all isosceles triangles? Check all that apply.

The base angles are congruent.
All three angles are congruent.
The two sides opposite the base angles are congruent.
All three sides are congruent.
The bisector of the vertex angle is the perpendicular bisector of the base.

Answers

3 Answers:  Choice A, Choice C, Choice E

=====================================================

Explanation:

Let's go through the answer choices to see which are true and which are false.

A) True. The base angles are the same measure, and they are opposite the congruent sides. Any isosceles triangle has exactly two congruent sides.B) False. This is describing an equilateral triangle (where all three angles are 60 degrees each).C) True. See choice A.D) False. This is describing an equilateral triangle where all sides are the same length. E) True. You can use the SAS (side angle side) congruence theorem to prove that the angle bisector is also the perpendicular bisector. Furthermore, this segment is also a median. This only applies to the vertex angle.

Answer:

The base angles are congruent.

The two sides opposite the base angles are congruent.

The bisector of the vertex angle is the perpendicular bisector of the base.

Step-by-step explanation:

. Each side of this ice cube measures 3.3 millimetres. What is the volume of this ice cube?

Answers

The volume of the ice cube is 35.937 mm^3

We know that for a cube of side length L, the volume is defined as:

V = L^3

Here, we do know that each side of our ice cube measures 3.3 mm, so we have:

L = 3.3mm

Then the volume of the cube is just:

V = (3.3 mm)^3 = 35.937 mm^3

We can conclude that the volume of the ice cube is 35.937 mm^3

If you want to learn more, you can read:

https://brainly.com/question/14075019

Factorise : x^2+x-72 Step by Step​

Answers

Answer:

(x + 9)(x - 8)

Step-by-step explanation:

f(x) = x^2 + x - 72

     = x^2 - 8x + 9x - 72

     = (x^2 - 8x) + (9x - 72)

     = x(x - 8) + 9(x - 8)

     = (x + 9)(x - 8)

Answer:

              x² + x - 72 = (x + 9)(x - 8)

Step-by-step explanation:

[tex]x^2+x-72\quad \implies\quad a=1\,,\quad b=1\,,\quad c=-72\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-1\pm\sqrt{1^2-4\cdot1\cdot(-72)}}{2\cdot1}=\dfrac{-1\pm\sqrt{1+288}}{2}=\dfrac{17\pm\sqrt{289}}{2}\\\\x_1=\dfrac{-1-17}{2}=-9\quad,\qquad x_2=\dfrac{-1+17}{2}=8\\\\\\x^2+x-72=(x-(-9))(x-8)=(x+9)(x-8)[/tex]

or:

     x² + x - 72 =

= x² + 9x - 8x - 72 =

= x(x + 9) - 8(x + 9) =

= (x + 9)(x - 8)

The volume of a prism is the product of its height and area of its base, V = Bh. A rectangular prism has a volume of 16y4 + 16y3 + 48y2 cubic units. Which could be the base area and height of the prism?

a base area of 4y square units and height of 4y2 + 4y + 12 units
a base area of 8y2 square units and height of y2 + 2y + 4 units
a base area of 12y square units and height of 4y2 + 4y + 36 units
a base area of 16y2 square units and height of y2 + y + 3 units

Answers

Answer: 4. A base area of 16y^2 square units and height of y^2 + y + 3 units

Step-by-step explanation:

Using the distributive property; you can see that 16y^2(y^2+y+3)=

16y^4+16y^3+48y^2

Answer:

D. a base area of 16y2 square units and height of y^2 + y + 3 units

Step-by-step explanation:

Ed22

find the volume of each figure. Round to the nearest tenth if necessary.​

Answers

Answer:

1385.4

Step-by-step explanation:

Volume=pi*r^2*h=pi*49*9=1385.4

multiply 2x^2-4x 6c^2-5x

Answers

Answer:

a

Step-by-step explanation:

2x^2-4x 6x^2-5x

2x^2 times 6x^2= 12x^4

2x^2 times -5x= -10x^3

-4x times 6x^2= -24x^3

-4x times -5x= 20x^2

12x^4-10x^3-24x^3+20x^2

12x^4-34x^3+20x^2

(Also Brainliest if this helps pls)

Point Q is located at (-4, 6). Point R is located at (8, 6).
What is the distance from point Q to point R?

Answers

Step-by-step explanation:

Hi there!

Given;

Point Q is located at (-4, 6). Point R is located at (8, 6).

Note: Use distance formula.

Now;

[tex](d) = \sqrt{( {x2 - x1)}^{2} + ( {y2 - y1)}^{2} } [/tex]

Keep all values;

[tex](d) = \sqrt{ {(8 + 4)}^{2} + ( {6 - 6)}^{2} } [/tex]

Simplify;

[tex](d) = \sqrt{( {12)}^{2} } [/tex]

Therefore, the distance is 12 units.

Hope it helps!

for the function y= -2+5 sin [pi/12(x-2)], what is the maximum value

Answers

Answer:

The answer is 0. There is no minum or maxium vaule, it equals 0.

Step-by-step explanation:

simplify : 2(3+a)+4=36​

Answers

Answer:

a = 13

Step-by-step explanation:

2(3 + a) + 4 = 36

Subtract 4 from both sides

2(3 + a) = 32

Multiply 2 by each number in “( )”

6 + 2a = 32

Subtract 6 from both sides

2a = 26

Divide 2 from both sides

a = 13

Therefore, a = 13

plot the inequality on the number line​

Answers

Answer:

Hope this helps!

pls help me ASAP !!!!!!!!!

Answers

Hopefully this help

what is the answer to -3/7 x -1 2/3

Answers

Answer:

-9x-35/21

Step-by-step explanation:

Answer:

[tex]\frac{5}{7}[/tex]

Step-by-step explanation:

[tex]\frac{-3}{7}* (-1\frac{2}{3})=\frac{-3}{7}*\frac{-5}{3}\\\\= \frac{5}{7}[/tex]

If 2 < 20x - 13 < 3. what is one possible value for x?

Answers

Answer:

one possible value for x is 31/40

Step-by-step explanation:

Let's isolate the 20x term.  Add 13 to all three terms:

2 + 13 < 20x - 13 + 13 < 3 + 13

and this simplifies to:

15 < 20x < 16

Dividing all three terms by 20, we get:

15/20 < x < 16/20

A fraction halfway between 15/20 and 16/20 is (31/20)/2, so

one possible value for x is 31/40.

Check by substituting this into the original equation and checking whether that equation is now true:

2 <20(31/40) - 13 < 3

or

2 < 31/2 < 16, or 2 < 15.5 < 16 (this is true, so 31/40 is a solution)

Rochelle deposits $6,000 in an IRA. What will be the value (in dollars) of her investment in 15 years if the investment is earning 9% per year and is compounded continuously? (Simplify your answer completely. Round your answer to the nearest cent.)

Answers

Answer:

$ 23,145

Step-by-step explanation:

This is a compound interest question where the interest is compounded continuously. Hence, the formula for the value of total amount of investment is:

A = P×e^rt

Where:

A = Total value of investment after t years

P = Principal or Initial amount invested = $6,000

e = Exponential function

r = interest rate = 9% = 0.09

t = time in years = 15

So:

A = $6000 × e^15 × 0.09

A = $6000 × e^1.35

A = $23,144.553184

Approximately , A ≈$23,145

Therefore, the value (in dollars) to the nearest cent of Rochelle's investment in 15 years if the investment is earning 9% per year and is compounded continuously is $23,145.

how many are 1 raised to 3 ???​

Answers

Answer:

1

Step-by-step explanation:

1^3

This is 1 multiplied by itself 3 times

1*1*1

1

Geometry, please answer question ASAP

Answers

Answer:

A,53.37°

360-306.63=53.37

Answer:

A

Step-by-step explanation:

a whole circle has 360 degrees (one time all around).

so, going from J over M to L is "using" already 306.63 degrees of that. going then from L to J just finishes the full trip of going one time around the whole circle.

so, LJ is just the missing "piece" to 360 degrees.

LJ = 360 - 306.63 = 53.37

Which expression is equivalent to 5/2?

Answers

Answer:

B

Step-by-step explanation:

5 divided by 2 is 5/2

Answer:

B

Step-by-step explanation:

5/2 the (/) is the divide sign

A file that is 276 megabytes is being dowloaded . If the downloaded is 16.7% complete how many megabytes have been dowloaded? Round ur answer to the nearest tenth ( can ya please hurry and answer thank you)

Answers

46.1 megabytes
276 x .167 = 46.092

Answer: 46.1 megabytes

Step-by-step explanation:

Scouts of ABC school made to run around a regular hexagonal ground fig 9, of perimeter 270 m .If they started running from point X and covered two fifth (2/5th) of the total distance.Which side of the ground will they reach?

Answers

Answer:

Scouts are on the third side in the sense they are running

Step-by-step explanation:

A regular hexagonal shape of perimeter 270 has each side of                 270/6 = 45  

Let´s call d  the run distance  then

d = 2/5 * 270      d = 108 m

We don´t have fig 9 available therefore if  X is a vertex in the hexagon or at the middle point of one side, scouts are 108 m from the starting point which means they had run 2,4 sides of the hexagon. If X is not either a vertex or a middle point of a side then, we have two solutions for the question depending on the sense the scouts took when began the run (clockwise or counterclockwise)

Other Questions
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