Answer:
Step-by-step explanation:
[tex]p(\overline{X}-\sigma \leq X \leq \overline{X}+\sigma)\\\\=p(\dfrac{\overline{X}-\sigma -\overline{X} }{\sigma} \leq Z \leq \dfrac{\overline{X}+\sigma -\overline{X} }{\sigma} )\\\\=p ( -1 \leq Z \leq 1)\\\\=2*(\ p (Z \leq 1)-0.5)\\\\=2*(0.8413-0.5)\\\\=0.6826\\\\\approx{68\%}[/tex]
Identify the segments that are parallel, if any, if ∠ADH≅∠ECK.
A. AE || CB
B. AD|| CB
C. none of these
D. AC|| CD
9514 1404 393
Answer:
C. none of these
Step-by-step explanation:
The given information tells us ΔACD is isosceles, but gives no information about any lines that might conceivably be parallel.
find the common ratio of the geometric sequence 4,3,9/4
Answer:
3/4
Step-by-step explanation:
To find the common ratio, take the second term and divide by the first term
3/4
Check with the third and second terms
9/4 ÷3
9/4 *1/3= 3/4
The common ratio is 3/4
a=5,and 5+z=14,so a+z=14
Answer:
Z=9
Step-by-step explanation:
Insert A into A+Z=14
5+z=14
Subtract 5 on both sides, to find Z.
-5 -5
z=9
Find the value of x to the nearest tenth of a degree.
20.4
21.8
42.9
68.2
Answer:
Answer is 20.4 .........
20,000 is 10 times as much as
Answer:
2000
Step-by-step explanation:
20,000 is 2000 times the number 10.
What is an expression?Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.
Given numbers are 20000 and 10. The number 20000 is how many times the number 10 will be calculated by dividing the number 20000 by 10.
E = 20000 / 10 = 2000
Therefore, the number 20,000 is 2000 times the number 10.
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Solve 2(x - 1) + 3 = x - 3(x + 1) (make sure to type the number only)
Answer:
x = -1
Step-by-step explanation:
2(x - 1) + 3 = x - 3(x + 1)
Distribute
2x -2+3 = x -3x-3
Combine like terms
2x +1 = -2x-3
Add 2x to each side
2x+1 +2x = -2x-3+2x
4x+1 = -3
Subtract 1 from each side
4x+1-1 = -3-1
4x= -4
Divide by 4
4x/4 = -4/4
x = -1
Evaluate the expression for y=-1? 14+5y=
Answer:
The answer is 9Step-by-step explanation:
14 + 5y
To solve the expression substitute the value of y that's - 1 into the expression
That's
14 + 5(-1)
= 14 - 5
= 9
Hope this helps you
Solve the equation.
please help, will give brainliest for correct answer
ain't it just 3 for each one unless i'm missing something
What is the error in this problem
Answer:
10). m∠x = 47°
11). x = 30.96
Step-by-step explanation:
10). By applying Sine rule in the given triangle DEF,
[tex]\frac{\text{SinF}}{\text{DE}}=\frac{\text{SinD}}{\text{EF}}[/tex]
[tex]\frac{\text{Sinx}}{7}=\frac{\text{Sin110}}{9}[/tex]
Sin(x) = [tex]\frac{7\times (\text{Sin110})}{9}[/tex]
Sin(x) = 0.7309
m∠x = [tex]\text{Sin}^{-1}(0.7309)[/tex]
m∠x = 46.96°
m∠x ≈ 47°
11). By applying Sine rule in ΔRST,
[tex]\frac{\text{SinR}}{\text{ST}}=\frac{\text{SinT}}{\text{RS}}[/tex]
[tex]\frac{\text{Sin120}}{35}=\frac{\text{Sin50}}{x}[/tex]
x = [tex]\frac{35\times (\text{Sin50})}{\text{Sin120}}[/tex]
x = 30.96
I will rate you brainliest Select the best description of what the LCM of a set of polynomials is. a.It is the quotient of all the factors of the polynomials. b.It is the common numerator of a rational expression. c. It is the product of the prime factors that are either unique to or shared by the polynomials. d. It is all the polynomials in the set.
Answer:
C. It is the product of the prime factors that are either unique to or shared by the polynomials.
Step-by-step explanation:
LCM of polynomials is:
=> Finding the factors of all the numbers and variable in the expression
=> Next, we multiply the unique numbers and the variable of the expression to find the LCM.
So, C is the correct answer.
The LCM of a set of polynomials is the product of the prime factors that are either unique to or shared by the polynomials.
What is LCM of polynomial?To find the lowest common multiple (L.C.M.) of polynomials, we first find the factors of polynomials by the method of factorization and then adopt the same process of finding L.C.M.
Example : The L.C.M. of 4a2 - 25b2 and 6a2 + 15ab.
Factorizing 4a2 - 25b2 we get,
(2a)2 - (5b)2, by using the identity a2 - b2.
= (2a + 5b) (2a - 5b)
Also, factorizing 6a2 + 15ab by taking the common factor '3a', we get
= 3a(2a + 5b)
L.C.M. is 3a(2a + 5b) (2a - 5b)
According to the question
The LCM of a set of polynomials is
is the product of the prime factors that are either unique to or shared by the polynomials.
(from above example we can see that )
Hence, It is the product of the prime factors that are either unique to or shared by the polynomials.
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What is the answer and how is this solved?
Answer:
Sum : 65
Step-by-step explanation:
In this notation, n is our starting value, and hence we start at 3 and go to 7. Given the set of values : { 3, 4, 5, 6, 7 }, we can substitute in our expression " 4n - 7 " for n and solve. The sum of these values is our solution.
4( 3 ) - 7 = 12 - 7 = 5,
4( 4 ) - 7 = 16 - 7 = 9,
4( 5 ) - 7 = 20 - 7 = 13,
Our remaining values for n = 6 and n = 7 must then be 17 and 21. This is predictable as we have an arithmetic series here, the common difference being 4. As you can see 9 - 5 = 4, 13 - 9 = 4, 17 - 13 = 4, 21 - 17 = 4.
Therefore we have the series { 5, 9, 13, 17, 21 }. This adds to an answer of 65.
Find the product: 12 x 3/5 =
Answer:
12 x 3/5 = 7 1/5
Step-by-step explanation:
12 x 3/5
Add 1 below 12 as a denominator to make it an improper fraction
= 12/1 x 3/5
Multiply numerators from both fractions as long as the denominators:
12 x 3 = 36
1 x 5 = 5
12/1 x 3/5 = 36/5
36/5 SIMPLIFIED IS 7 1/5
Hope this helps!
Answer:
36/5 = 7.2 = 7 1/5
Step-by-step explanation:
12 x 3/5
Change 12 into fraction form to make it easier.
12/1 x 3/5
Now multiply the numerators and the denominators.
12 x 3 = 36
1 x 5 = 5
12/1 x 3/5 = 36/5
If you don't want the answer as an improper fraction, 36/5 = 7.2 which is also equal to 7 1/5
what is the prime factorization of 7?
As Prime factorization is a process of writing all numbers as a product of primes then The prime factorization of number 7 is 7.
What is Number system?A number system is defined as a system of writing to express numbers.
Prime factorization is a process of writing all numbers as a product of primes
The number 7 is a prime number, which means it is only divisible by 1 and itself.
Therefore, the prime factorization of 7 is simply 7 itself.
Hence, the prime factorization of number 7 is 7.
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Help please anyone. Thank You
Answer:
A) 144 yd²
Step-by-step explanation:
Base= 8x8=64
Side = 1/2*8*5=20
64+20+20+20+20=144 yd²
Answer:
168 sq yds
Step-by-step explanation:
5x8/2x2=40
8x8/2x2=64
8x8=64
40+64+64=168
A rectangular city is 3 miles long and 10 miles wide. What is the distance between opposite corners of the city? The exact distance is ______ miles How far is it to the closest tenth of a mile? Answer: The distance is approximately ______ miles.
Answer:
The exact distance is [tex]\sqrt{109}[/tex] miles.
The distance is approximately 10.4 miles.
Step-by-step explanation:
It is given that a rectangular city is 3 miles long and 10 miles wide. So,
Length = 3 miles
Width = 10 miles
We need to find the distance between opposite corners of the city. It means, we need to find the length of the diagonal of the rectangle.
Using Pythagoras theorem, the length of diagonal is
[tex]d=\sqrt{l^2+w^2}[/tex]
where, l is length and w is width.
Substitute l=3 and w=10.
[tex]d=\sqrt{(3)^2+(10)^2}[/tex]
[tex]d=\sqrt{9+100}[/tex]
[tex]d=\sqrt{109}[/tex]
The exact distance is [tex]\sqrt{109}[/tex] miles.
Now,
[tex]d=\sqrt{109}[/tex]
[tex]d=10.4403065[/tex]
[tex]d\approx 10.4[/tex]
The distance is approximately 10.4 miles.
se pueden calcular las edades de Juanita y de su madre si se sabe que:
1) actualmente la suma de sus edades es 44 años
2) dentro de 11 años la edad de juanita será la mitad de la edad de su mamá
Responder:
Juanita = 11, madre = 33
Explicación paso a paso:
Dado lo siguiente:
Suma de sus edades = 44
En 11 años, Juanita tendrá la mitad de la edad de su madre
Sea la edad de la madre = my la edad de juanita = j
m + j = 44 - - - - (1)
(j + 11) = 1/2 (m + 11)
j + 11 = 1/2 m + 5,5; j - 1/2 m = - 5,5; 2j - m = - 11
2j - m = - 11 - - - - (2)
Desde (1): m = 44 - j
Sustituyendo m = 44- j en (2)
2j - (44 - j) = - 11
2j - 44 + j = - 11
3j = - 11 + 44
3j = 33
j = 11
De 1)
m + j = 44
m + 11 = 44
m = 44 - 11
m = 33
A family has two cars. The first car has a fuel efficiency of 35 miles per gallon of gas and the second has a fuel efficiency of 15 miles per gallon of gas. During one particular week, the two cars went a combined total of 1825 miles, for a total gas consumption of 75 gallons. How many gallons were consumed by each of the two cars that week?
Answer:
1) 35 gallons by the first car 2) 40 gallons by the second car
Step-by-step explanation:
Suppose the first car used x gallons, when the second car used the rest- 75-x
If the first car's efficiency is 35 miles per galon, its milleage is 35*x, the second car's milleage is 15*(75-x). And the summary milleage is equal to 1825.
35x+15(75-x)=1825
35x+1125-15x= 1825
20x=700
x=35- gallons consumed by the first car,
75-35=40- gallons consumed by the second one
for the functions f(x) = 4x^4+4x^3-8x^2-13x-5 and g(x) = x+1, find (f/g)(x) and (f/g)(2)
Answer:
(f/g)(x) = 4x³ - 8x - 5(f/g)(2) = 11Step-by-step explanation:
f(x) = 4x⁴ + 4x³ - 8x² - 13x - 5
g(x) = x + 1
To find (f/g)(2) first find (f/g)(x)
To find (f/g)(x) factorize f(x) first
That's
f(x) = 4x⁴ + 4x³ - 8x² - 13x - 5
f(x) = ( x + 1)( 4x³ - 8x - 5)
So we have
[tex] (f/g)(x) = \frac{( x + 1)( 4x³ - 8x - 5)}{x + 1} [/tex]
Simplify
We have
(f/g)(x) = 4x³ - 8x - 5To find (f/g)(2) substitute 2 into (f/g)(x)
That's
(f/g)(2) = 4(2)³ - 8(2) - 5
= 4(8) - 16 - 5
= 32 - 16 - 5
= 11
(f/g)(2) = 11Hope this helps you
The U.S. National Whitewater Center in Charlotte uses a pump station to provide the flow of water necessary to operate the rapids. The pump station contains 7 pumps, each with a capacity to deliver 80,000 gallons per minute (gpm). The water channels and ponds in the facility contain 13 million gallons of water. If the pump station is operating 5 pumps simultaneously, assuming ideal conditions how long will it take to completely pump the volume of the system through the pump station
Answer:
t = 32,5 minutes
Step-by-step explanation:
Volume to fill = 13000000 Gal
5 pumps delivering 80000 gal/min
5 * 80000 = 400000 gal/min
If we divide the total volume by the amount of water delivered for the 5 pumps, we get the required time to fill the volume, then
t = 13000000/ 400000
t = 32,5 minutes
write two properties of Zero
Answer:
the addition properties of zero and multiplication properties of zero
zero is even, not odd not neutral.
zero is neither positive or negative.
Explain why this quadrilateral is not a parallelogram.
Answer:
A parallelogram has two sets of parallel sides. This quadrilateral only has on set of parallel sides, so therefore it cannot be a parallelogram.
At the dog show, there are 4 times as many boxers as spaniels. If there are a total of 30 dogs,how many dogs are spaniels? Plz help me
Answer:
6 spaniels
Step-by-step explanation:
Create 2 equations to represent this, where b is the number of boxers and s is the number of spaniels:
4s = b
s + b = 30
We can plug in 4s as b into the second equation, s + b = 30:
s + b = 30
s + 4s = 30
5s = 30
s = 6
So, there are 6 spaniels.
Find the degree, leading coefficient, and the constant term of the polynomial.
[tex] \LARGE{ \boxed{ \purple{ \rm{Answers;)}}}}[/tex]
☃️ Degree of the polynomial- The highest degree of any term in a polynomial. Here the highest degree is 5.
⇛ 4x⁴ + 5 + 6x⁵ - 2x(° of polynomial = 5)
☃️ Leading coefficient- The coefficient of the term having the highest degree of the polynomial. Here, the highest degree is 5 and the term is 6x⁵
⇛ 4x⁴ + 5 + 6x⁵ - 2x (Leading coeff. = 6)
☃️ Constant term- It is the term having no coefficients, only a fixed real number. This remains constant in any value of polynomial.
⇛ 4x⁴ + 5 + 6x⁵ - 2x (Constant term = 5)
━━━━━━━━━━━━━━━━━━━━
look at the image for the question
Volume = l × b × h
Length = 7m
Breadth = 7m
Height = 9m
Volume = 7×7×9
441m³
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list the domain and range of the relation {(6,8), (7,7), (0,-8), (7,1), (6,8)}
Answers:
Domain = {0, 6, 7}
Range = {-8, 1, 7, 8}
======================================================
Explanation:
The domain is the set of allowed x inputs. So we simply list the x coordinates. Toss out any duplicates. Sorting the values is optional.
The range is the set of y coordinates. Like with the domain, we'll toss out any duplicates and optionally we can sort the y values.
a cubical water tank is 80 CM broad how many CC of water does it hold
Answer:
I think: vol of h20 inside = side³ = (80cm)³ =512000 cm³
Please refer!
Step-by-step explanation:
I'm not sure but hope it helps.
In the Olympic tennis event ( in which each tennis player gets eliminated from the tournament after the first defeat) there are 37 players participating. Can you − in 5 seconds − count how many matches there need to be until there is one
Answer:
approximately 19 matches for single player contest and 9 matches for double player contest
Step-by-step explanation:
However, it is important to note that a tennis match is usually between two players (one player to one) or two teams of players (two players to two players),
So, there may be approximately 19 matches for single player
([tex]\frac{37 players}{2}[/tex]) and approximately 9 matches ([tex]\frac{18.5}{2}[/tex]) for double player contest.
Two complementary angles have measures of s and t. if t is less than twice s, which system of linear equations can be used to determine the measure of each angle? Please explain answer. I know s+t=90. But how do you get to t=2s-90
The required expressions are both equations 1 and 2 as shown:
[tex]s + t = 90 ......... 1[/tex]
[tex]t<2s[/tex] .... 2
Complementary angles are angles that sum up to 90 degrees. For instance, and A and B are complementary if A + B = 90.
According to the question, if two complementary angles have measures of s and t then:
[tex]s + t = 90 ......... 1[/tex]
Twice of 's' is expressed as [tex]2s[/tex]
If t is less than twice s, this can be expressed as [tex]t<2s[/tex] .... 2
The required expressions are both equations 1 and 2 as shown:
[tex]s + t = 90 ......... 1[/tex]
[tex]t<2s[/tex] .... 2
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Find the differential coefficient of
[tex]e^{2x}(1+Lnx)[/tex]
Answer:
[tex] \rm \displaystyle y' = 2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x} [/tex]
Step-by-step explanation:
we would like to figure out the differential coefficient of [tex]e^{2x}(1+\ln(x))[/tex]
remember that,
the differential coefficient of a function y is what is now called its derivative y', therefore let,
[tex] \displaystyle y = {e}^{2x} \cdot (1 + \ln(x) )[/tex]
to do so distribute:
[tex] \displaystyle y = {e}^{2x} + \ln(x) \cdot {e}^{2x} [/tex]
take derivative in both sides which yields:
[tex] \displaystyle y' = \frac{d}{dx} ( {e}^{2x} + \ln(x) \cdot {e}^{2x} )[/tex]
by sum derivation rule we acquire:
[tex] \rm \displaystyle y' = \frac{d}{dx} {e}^{2x} + \frac{d}{dx} \ln(x) \cdot {e}^{2x} [/tex]
Part-A: differentiating $e^{2x}$
[tex] \displaystyle \frac{d}{dx} {e}^{2x} [/tex]
the rule of composite function derivation is given by:
[tex] \rm\displaystyle \frac{d}{dx} f(g(x)) = \frac{d}{dg} f(g(x)) \times \frac{d}{dx} g(x)[/tex]
so let g(x) [2x] be u and transform it:
[tex] \displaystyle \frac{d}{du} {e}^{u} \cdot \frac{d}{dx} 2x[/tex]
differentiate:
[tex] \displaystyle {e}^{u} \cdot 2[/tex]
substitute back:
[tex] \displaystyle \boxed{2{e}^{2x} }[/tex]
Part-B: differentiating ln(x)•e^2x
Product rule of differentiating is given by:
[tex] \displaystyle \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)[/tex]
let
[tex]f(x) \implies \ln(x) [/tex][tex]g(x) \implies {e}^{2x} [/tex]substitute
[tex] \rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \frac{d}{dx}( \ln(x) ) {e}^{2x} + \ln(x) \frac{d}{dx} {e}^{2x} [/tex]
differentiate:
[tex] \rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \boxed{\frac{1}{x} {e}^{2x} + 2\ln(x) {e}^{2x} }[/tex]
Final part:
substitute what we got:
[tex] \rm \displaystyle y' = \boxed{2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x} }[/tex]
and we're done!
Answer:
Product Rule for Differentiation
[tex]\textsf{If }y=uv[/tex]
[tex]\dfrac{dy}{dx}=u\dfrac{dv}{dx}+v\dfrac{du}{dx}[/tex]
Given equation:
[tex]y=e^{2x}(1+\ln x)[/tex]
Define the variables:
[tex]\textsf{Let }u=e^{2x} \implies \dfrac{du}{dx}=2e^{2x}[/tex]
[tex]\textsf{Let }v=1+\ln x \implies \dfrac{dv}{dx}=\dfrac{1}{x}[/tex]
Therefore:
[tex]\begin{aligned}\dfrac{dy}{dx} & =u\dfrac{dv}{dx}+v\dfrac{du}{dx}\\\\\implies \dfrac{dy}{dx} & =e^{2x} \cdot \dfrac{1}{x}+(1+\ln x) \cdot 2e^{2x}\\\\& = \dfrac{e^{2x}}{x}+2e^{2x}(1+\ln x)\\\\ & = \dfrac{e^{2x}}{x}+2e^{2x}+2e^{2x} \ln x\\\\& = e^{2x}\left(\dfrac{1}{x}+2+2 \ln x \right)\end{aligned}[/tex]