enceladus is an icy moon of saturn experiencing tidal forces because of an elliptical orbit due to an orbital resonance with another moon dione. what are the consequences of tidal heating of enceladus because of this elliptical orbit?

The test section's pressure is lower than the ambient pressure.

In the physical sciences, pressure is defined as the perpendicular force per unit area or the stress at a particular location within a confined fluid.

Given,

Diameter of Test section, d₂ = 0.5m

Area, A₂ = π/4d₂² = π/4×0.5² = 0.19635m²

Now, At Inlet,

Po = 101325Pa

To = 288 k

s = 122 kg/m³

(a) Using Bernoulli Theorem, i'n Test Section,

Po = [tex]P_{t}[/tex] +1/2γ [tex]v_{t^{2} }[/tex]

101325 = [tex]P_{t}[/tex] + ½ (1.22) (200) ²

[tex]P_{t}[/tex] = 76925 Pa

[[tex]v_{t}[/tex] = 200m/s]

Now,

Static Temperature, [tex]T_{t}[/tex]

[tex]T_{0}[/tex] = [tex]T_{t}[/tex] +v²/2[tex]c_{p}[/tex]

288 = [tex]T_{t}[/tex] +200²/2×1005

[tex]T_{t}[/tex] = 268.09k.

Thus,

[tex]M_{t}[/tex] = [tex]v_{t}[/tex]/[tex]\sqrt{\nu RT_{t} }[/tex]

[tex]M_{t}[/tex] = 200/1.4×287×268

[tex]M_{t}[/tex]= 0.609

The test section's pressure is lower than the ambient pressure.

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Answer:A.

i know its a, i did quiz

Answer: That is not a question.

Explanation: It is a random jumble of letters. It also has no question mark.

The following formula can be used to determine an object's density if it is spherical.

ρ = 3/4 x π x r³

Here, r denotes the spherical object's radius.

and is a constant in mathematics with the value 22/7.

Assume that the object's initial diameter is d.

As a result, it will have a radius of = d/2 = 0.50d.

Let's enter this value and calculate density as 1.

ρ₁ = 3/4 x π x (r)³

ρ₁ = 1/2 x 22/7 x (0.5d)³

The object is currently being compressed so that its diameter is reduced to a fourth of what it was.

The object's new diameter would be d/2 = 0.50d.

The new radius would be 0.50d/2 = 0.25d as a result.

Find the new density 2 now.

ρ₂ = 1/2 x 22/7 x (0.25d)³

Compare numbers 1 and 2 now.

3/4 x 22/7 x (0.25d)3 divided by 3/4 x 22/7 x (0.5d)3 equals 2/1.

1/2 and 22/7 can be canceled here.

ρ₂/ρ₁ = (0.25d)³ / (0.5d)³

d is terminated.

ρ₂/ρ₁ = 0.125

ρ₂ = 0.125 ρ₁

The original density is 1, and the revised density is 2.

Since its new density would be 0.125 times that of its original, we can conclude that.

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the required equation for centripetal force is F = k m¹ v¹ r⁻¹.

A particle traveling uniformly in a circle experiences a centripetal force, F, which is dependent on the mass (m), velocity (v), and radius (r) of the circle.

the F formula using the dimensions method is

Suppose F = k mᵃvᵇrⁿ. (i)

Where a, b, and n are the respective powers of m, v, and r and k is the dimensionless constant of proportionality.

Upon putting the measurements of various amounts in (i)

we get

[M¹L¹T‐²] = Mᵃ[LT‐¹]ᵇ Lⁿ

=> [M¹L¹T‐²] = Mᵃ Lᵇ Lⁿ T⁻ᵇ

=> [M¹L¹T-²] = Mᵃ Lᵇ⁺ⁿ T⁻ᵇ

on comparing both sides we get

a = 1

b+n = 1

-b = -2 => b = 2

Then n = -1

Onputting these values in (i),

we get

F = k m¹ v¹ r⁻¹

Or

F=k(mv²)/r

This is the required equation for centripetal force.

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It will take 11 seconds for a car to travel 330 m at a speed of 30.0 m/s

By going through the formula of calculating the speed of the vehicle

that is, S=D/T

We get the equation T=D/S.........(i)

Where T stands for Time

D stands for Distance

S stands for Speed

Now, as per the given question

Distance(D)= 330 meters

Speed(S)= 30.0 meters per second

Time(T)= ?

Putting the values in equation (i),

                      T=330 meters/30 meters per second

                      T = 11 seconds.

Therefore, A car moving at a speed of 30.0 meters per second will traverse 330 meters in 11 seconds.

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In the absence of air resistance, the only force acting on both objects would be gravity. Both objects would experience the same 9.8 m/s² acceleration toward the ground.

Since the initial conditions of both projectiles are identical, the velocities of both projectiles will be the same at all times. Therefore, both projectiles will attain a zero vertical velocity at the same time, and it is at this point that they simultaneously reach their respective maximum heights.

The maximum heights will not be the same, and they will differ by precisely the amount of height difference between the launch points.

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Answer:

When two objects collide the total momentum before the collision is equal to the total momentum after the collision (in the absence of external forces). This is the law of conservation of momentum. It is true for all collisions.

Explanation:

...

Answer:

When two objects collide the complete momentum before the collision is similar to the complete momentum afterwards the collision (in the absence of outside forces) . This is the law of conservation of momentum . it's accurate for all collisions .

The maximum elastic potential energy store of the ball when it is fully compressed after hitting the ground is 110 J

Since the effects of friction is ignored, there is no loss of energy as heat. So the entire elastic potential energy store of the ball is converted into kinetic energy store.

Elastic potential energy = Kinetic energy

Kinetic energy = 110 J

Elastic potential energy = 1 / 2 k x²

Kinetic energy = 1 / 2 m v²

k = Spring constant

x = Displacement

m = Mass

v = Velocity

If friction is ignored,

1 / 2 k x² = 1 / 2 m v²

v / x = √ ( k / m )

Therefore, the maximum elastic potential energy store of the ball is 110 J

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The goalie slides on the frictionless ice at a speed of 0.076 m/s.

collision energy equals collision momentum

An object's momentum will vary as a result of a force applied for a specific length of time. In other words, an uneven force an object regardless of whether it is speeding up or slowin accelerates g down. When a force exerted against an object's motion slows it down.

The puck weighs 0.111 kg in terms of mass.

Hockey puck velocity is 55 meters per second.

Goalkeeper weight: 80 kg

Goalkeeper's speed is 0 meters per second.

Following the rule of linear momentum conservation, (0.111 kg 55 m/s) + (80 kg 0 m/s) = (0.111 kg + 80 kg) V V = (6.105 / 80.111) = 0.076 m/s (0.111 kg 55 m/s) + (0.111 kg + 80 kg) V = 0.076 m/s

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Among the given options the vehicle that has the most kinetic energy is a 900-kg car traveling 80 km/h

KE = 1 / 2 m v²

KE = Kinetic energy

m = Mass

v = Velocity

For A,

m = 1100 kg

v = 60 km / h

KE = 1 / 2 * 1100 * 60²

KE = 1980000 J

KE = 1980 KJ

For B,

m = 2000 kg

v = 50 km / h

KE = 1 / 2 * 2000 * 50²

KE = 2500000 J

KE = 2500 KJ

For C,

m = 900 kg

v = 80 km / h

KE = 1 / 2 * 900 * 80²

KE = 2880000 J

KE = 2880 KJ

For D,

m = 300 kg

v = 100 km / h

KE = 1 / 2 * 300 * 100²

KE = 1500000 J

KE = 1500 KJ

KEc > KEb > KEa > KEd

Therefore, the 900-kg car traveling 80 km/h has the most kinetic energy

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The distance of the image is 26.67 cm

The magnification is -1.67

The image is real

The image is inverted

The focal length of the concave mirror = 10 cm

The distance of the object from the concave mirror = 16 cm

                 1/p + 1/q = 1/f

where p is the distance of the object

          q is the distance of the image

          f is the focal length

                  1/q = 1/f - 1/p

                  1/q = (p - f)/fp

                    q = fp / (p - f)

                    q = 16 x 10 / ( 16 - 10)

                       = 160 / 6

                       = 26.67 cm

The distance of the image from the concave mirror is 26.67 cm

                  M = -q/p

where M is the magnification

                 M = -26.67 / 16

                     = -1.67

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To find out the kinetic friction, using the coefficient friction formula.

What is kinetic friction?

A force that acts between moving surfaces is called "kinetic friction." A force acting in opposition to the direction of a moving body on the surface is felt. The two materials' kinetic friction coefficients will determine how much force is applied.

What is coefficient friction?

A measure of the degree of friction between two surfaces is the coefficient of friction. A coefficient of friction is determined by calculating the resistance to motion at the intersection of two surfaces made of the same or different materials.

UK

U-coefficient of friction

K-Kinetic friction

Using UK

450+370-f=m*o

f=820=UK*260*9.8

UK=2.548

820/2.548

UK= 321.8210361

Therefore the coefficient of kinetic friction is 321.8210361

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Convex lenses when placed in the air, will cause rays of light (parallel to the central axis) to converge.

Converging lenses, commonly referred to as convex lenses, have thicker centers and narrower upper and lower margins. The edges are outwardly curled. This lens has the ability to concentrate a beam of parallel light rays coming from the outside onto a spot on the opposite side of the lens.

The image created is referred to be a genuine image when it is inverted relative to the object. On a screen, this kind of image can be recorded. When the object is positioned at a point farther than one focal length from the lens, a converging lens creates a true image.

A virtual image is one that cannot be produced on a screen and is formed when the image is upright in relation to the object. When an item is positioned within one focal length of a converging lens, a virtual image is created. It creates an enlarged image of the object on the same side of the lens as the image. It serves as a magnifier.

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The power that firefighter needed to reach the top of the building in 55s is equal to  463.3 Watts.

Power can be described as the rate of doing work and is also defined as the work done in unit time. The S.I. unit of power is Joule/second or Watt (W). The mathematical expression for power is mentioned below.

Power = work/ time

P = W/ t

Given, the height of the building, h = 20 m

The total mass of the firefighter and backpack, m =  85 + 45 = 130 Kg

The time taken to reach the top, t = 55 sec

The power that will be needed can be determined as:

[tex]{\displaystyle {P = \frac{m\times g\times h}{t}[/tex]

[tex]{\displaystyle {P = \frac{130\times 9.8\times 20}{55}[/tex]

P = 463.3 Watt

Therefore, with the power of 463.3 Watts, a firefighter will reach the top in 55s.

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Car A's frequency is determined to be 398.4 Hz.

The frequency heard by car A is calculated using the following equation.

f = fs(v - v₀) / (v - vs)

where;

v is the speed of sound = 343 m/s

v₀ is the speed car B = 19.2 m/s

vs is the speed of car A = 22 m/s

fs is the frequency of car A = 395 Hz

f is the frequency of car B = ?

f = 395(343 - 19.2) / (343 - 22)

The frequency will be calculated as below,

f = 395(1.0087)

f = 398.4 Hz

Therefore, car A's frequency is determined to be 398.4 Hz.

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Answer:

5 g

Explanation:

500 mg x 10 = 5000 mg

5000 x 10^-3 g = 5 g

Hello..!

To solve the problem and calculate the number of pills in the package, we will use the conversion factor.

The conversion factor or unit factor is a conversion method that is based on multiplying by one or more fractions where the numerator and denominator are equal quantities expressed in different units of measure, so that each fraction is equivalent to the unit.

Find out that 1 gram has a total of 1000 mg.

Problem:

How many g are in a carton containing 10 tablets of 500 mg each?

According to the previous text we can say that the conversion factor would be:

[tex] \: \: \: \: \: \qquad \qquad \large \sf\dfrac{1\ g}{1000\ mg}[/tex]

Now we must find out that the box has a total of 10 pills of 500 mg, so to know how many grams the box has we must know how many grams only one pill weighs:

[tex] \sf \qquad\boxed{\boxed{ \sf\large 500\ mg*\dfrac{1\ g}{1000\ mg}= 0.5\ g}}[/tex]

We know that a pill weighs 0.5 grams, now to calculate how many grams the box weighs we must multiply the total pills by the weight of just one pill:

[tex]\qquad \boxed{\boxed{ \sf\large 0.5\ g\times 10= 5\ g}}[/tex]

We conclude that one box contains 5 grams of tablet, option 1.

[tex]\begin{gathered}\rule{7cm}{0.01mm}\\\texttt{Good studies! :D}\\\rule{7cm}{0.01mm}\end{gathered}[/tex]

The layer that the hot-air balloon can travel to, in the layer of the atmosphere is troposphere. its can't a go to higher layers because it would be  affected by density.

The troposphere servesv as the lowest layer of Earth's atmosphere however it has the mass (about 75-80%) of the atmosphere  and most of  tthe types of clouds  can be seen in the troposphere, then the weather occurs within this layer.

It should be noted that the troposphere has the highest density, as well as the greatest air pressure,  however the water vapor, and a temperature range from 62,  layer that the hot-air balloon can travel to, in the layer of the atmosphere is troposphere.

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When the radial velocity is positive, it means the distance between the objects is or was becoming closer; when it is negative, it means the distance between the source and the observer is or was getting closer.

The portion of a particle's velocity that is moving in the direction of its radius vector. or radial motion, which is the speed at which an observer approaches or recedes from a celestial body or other source of radiation in the line that connects the two: speed in the visual field.

This technique is one of the detection methods that enables us to calculate an exoplanet's mass, a crucial factor in the hunt for worlds similar to Earth and other extraterrestrial life.

Radial velocity has been used to locate hundreds of distant planets and was the first effective approach for exoplanet discovery. Because stars do not need to be continuously monitored as they do with transit photometry, it is perfect for ground-based telescopes.

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A single collision results in a loss of 42% of the object's kinetic energy.

Kinetic energy is equal to 0.5 x mass x v2.

kinetic energy coming in = 0.5 x m x v2

v/u = Coefficient of restitution

0.76 = v/u

v = 0.76u

Kinetic energy expended = 0.5 x m x 0.76²

Kinetic energy expended = 0.5 x m x 0.5776

Kinetic energy expended = 0.5776 (0.5 x m x )

The kinetic energy that is coming in is 0.5 x m x x2.

kinetic energy expended = 0.5776 x (incoming kinetic energy)

The entering kinetic energy is equal to 57.76% of the exiting kinetic energy, as can be seen from the above.

A loss of energy of 100 - 57.76 = 42.24%

Therefore, a single collision results in a loss of 42.24% of the object's kinetic energy.

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Answer:

See below

Explanation:

Vertical component of the kick-off velocity is  8.4 sin21° = 3.01 m/s

Find the time-point where vertical velocity = 0   the ball is in the air for twice this long  ( as it still has to fall back down to the ground)

vf = vo + at

0  = 3.01 m/s   - 9.81 t     shows t = .307   twice this is .614 sec  

  ( what a sorry kick !)

If there is no air resistance, what is the net if there is 10 n of air resistance, what is the net force,the net force of an object is 0N and acceleration is 6N.

When compared to displacement and velocity, acceleration is like the wrathful, flaming dragon of motion variables. People may be terrified of it, it might be harmful, and if it's enormous, it draws your attention. When you're in a fast-turning corner in a car or go-kart or when you're in a plane during takeoff, you can feel your own acceleration.

Since velocity depends on both speed and direction, you can only accelerate by changing either one or the other, if not both. The object will be moving faster if the acceleration is pointing in the same direction as the velocity. Additionally, the item will slow down if the acceleration is pointing in the opposite direction from the direction of the velocity.

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Answer:

Explanation:

Given:

φ₁ = 350 V  -  potential of point A

φ₂ = 130 V - potential of point B

A = 4.7·10⁻⁴ J - Work of the electric field

______________________

Q - ?    

The magnitude of the electric charge:

Q = J / Δφ

Potential difference:

Δφ = φ₁ - φ₂ = 350 - 130 = 120 V

Then:

Q = J / Δφ = 4.7·10⁻⁴ / 120 ≈ 3.9·10⁻⁶  C  or  Q

Q = 3.9 mkC  

The diverging lens/concave lens is used as a corrective lens is used for a nearsighted person

Nearsightedness is also known as myopia where the person with myopia will be able to see the near object but far objects will look blurry.

Myopia is corrected with lenses called "minus power lenses". They are concave in shape and help the eye to focus light properly. Myopia causes distant objects to appear blurry. Prescription glasses or contact lenses can usually correct this blurry distance vision. Myopic eyes have a stronger ability to focus than normal eyes. Focus in front of the retina, not on the retina. Lenses used to correct nearsightedness work by reducing the eye's ability to focus.

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A scientific theory should make testable predictions and if those predictions are found to be incorrect the theory should be dismissed.

He argued that science advances best through the use of deductive reasoning, known as critical rationalism, as its primary emphasis. Popper coined the term critical rationalism to describe his philosophy. Popper rejected the empiricist view that basic statements are infallible.

Karl Popper was a scientific realist against his will. Despite his own limitations regarding the forms of acceptable scientific reasoning and the extent of empirical evidence, he advocated a very real conception of scientific goals and outcomes. A significant contribution stems from his rejection of induction in empirical science.

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Answer:

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What is the condition for a force to do work on a body ?

Question

What is the condition for a force to do work on a body ?

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Solution

The condition of force to do some work is that the force should be along the direction of displacement.

work is done when the object moves through a certain distance in a particular direction after the force had been applied on it.

Work Done = Force x Distance x Cos theta

For work to be done, the force must be applied and must not be zero.

The body on which the force is applied must move in one direction or the other and hence the S must not be zero.

The force must not be applied at 90 degrees angle upon the object as Cos 90 equals zero.

4 is the drift speed of the conduction electrons in wire b.

I = neA [tex]V_{d}[/tex]

[tex]V_{d}[/tex] = [tex]\frac{I}{neA}[/tex]

    = [tex]\frac{I}{ne\pi r^{2} }[/tex]

[tex]V_{d}[/tex] [tex]\alpha[/tex]   [tex]\frac{1}{r^{2} }[/tex]

r' = 2r

A' = [tex]\pi 2r^{2}[/tex]

   = 4[tex]\pi r^{2}[/tex]

[tex]\frac{Vd'}{Vd}[/tex]= [tex]\frac{r^{2} }{2r^{2} }[/tex] = 1/4

[tex]V_{d}[/tex] = 4

Subatomic particles like electrons move in random directions all the time. When electrons are exposed to an electric field, they  move randomly but  slowly drift in one direction,  the direction of the applied electric field. The net speed at which these electrons drift is called the drift speed.  Curvature can be defined as follows:

The average speed of charged particles (eg electrons) in a material under the influence of an electric field. the SI unit of yard speed is m/s. It is also measured in [tex]m^2[/tex]/(V.s).

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The person can jump 6 times higher on the moon compared to Earth.

The maximum height an object can Jump is the height vertical displacement of the object during an upward motion.

Mathematically, the maximum height an object can jump is given as;

H = u²sin²θ/2g

where;

When a person moves to the moon, the acceleration due to gravity becomes ; ¹/₆

The new height the object can jump is calculated as follows;

H = u²sin²θ/(2 x ¹/₆g)

H = 6( u²sin²θ/2g)

Thus, the person will jump higher on the moon due to lesser acceleration due to gravity.

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The car speeds remains constant.

Using the following equation for momentum:

Pi=Pf

(c=car and r=rock)
              McVc + MrVr = McV'c + MrV'r

Initially
                         Vc=Vr=Vi
and since rocks are being dropped directly downward, final momentum of the rocks (being dropped one at a time) should be zero because their falling down, out of the railroad car.
So:
Vi( Mc+Mr) = McV'c V'c = [Vi(Mr+Mc)] / Mc

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