Answer:
depth 5 8.3 ft, length 5 24.9 ft, width 5 16.8 ft
Which representation would be best for determining how many planes had an average cruising speed of 0.84 Mach?
Answer:
Question: 1
A dot plot shows individual values. So, we can most easily tell from the dot plot that 5 planes had an average cruising speed of 0.84 Mach
Question: 2
A box plot breaks data into quartiles, each representing 25% of the data. So to find the middle 50% of the data, look at the data that lies between the first and third quartiles of the box plot. The box plot shows that the first and third quartiles are 0.8175 and 0.85, respectively, so 50% of the data lies between 0.8175 and 0.85.
Question: 3
The histogram would be the best data representation for quickly determining how many planes had a speed less than 0.84 Mach. Adding the frequencies of the 3 bins less than 0.84 shows that 17 planes had a speed of less than 0.84 Mach. The dot plot could also be used to determine this, but it would take more time to count each individual dot.
Step-by-step explanation:
answer from plato
Thank me later
The graphical representation which would be best for determining the number of planes that had an average cruising speed of 0.84 Mach is a: histogram.
What is a histogram?A histogram can be defined as a type of graph (chart) that is used to graphically represent a data set (statistical information) into user-specified ranges through the use of rectangles.
Generally, the area of each rectangle of a histogram is directly proportional to the data frequency and its width is equal to the class interval.
In this scenario, a histogram is the graphical representation which would be best for determining the number of planes that had an average cruising speed of 0.84 Mach.
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the height of a soccer ball that is kicked from the ground can be approximated by the function:
y = -12x^2 + 60x
where y is the height of the soccer ball in feet in x seconds after it is kicked. Find the time, in seconds, it takes from the moment soccer is kicked until it returns to the ground
Answer:
5 seconds
Step-by-step explanation:
Well we know that when the soccer ball is on the ground the height will be 0.
So we replace y with 0 and solve for x.
0=-12x²+60x
factor out and divide x, (this x is x=0, which is before he kicked it)
0=-12x+60
subtract 60 from both sides
-60=-12x
x=5
Which side of the pentagon on the right corresponds to
side KJ on the pentagon on the left.
Answer:
side st.Step-by-step explanation:
st corresponds to kj since a it has five sides.What is the value of x that makes l1||l2?
A. 15
B. 25
C. 18
D. 29
Answer:
x = 29
Step-by-step explanation:
The angles are corresponding angles and corresponding angles are equal when the lines are parallel
3x+17 = 4x-12
Subtract 3x from each side
3x+17-3x = 4x-12-3x
17 = x-12
Add 12 to each side
17+12 = x-12+12
29 =x
Answer:
D. 29
Step-by-step explanation:
If you plug in 29 in the missing values for L1 and L2, you get
L1 = 3(29) + 17 = 104
L2 = 4(29) - 12 = 104
I know I am correct because since both L1 and L2 are parallel and T in cutting them, I know that they are both going to be the same degrees, 104.
So, your answer would be D. 29
Hope the helps! :)
Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation:
21, 14, 13, 24, 17, 22, 25, 12
Required:
a. Calculate the sample mean and the sample standard deviation.
b. Construct the 90% confidence interval for the population mean.
c. Construct the 95% confidence interval for the population mean
Answer:
a
[tex]\= x = 18.5[/tex] , [tex]\sigma = 5.15[/tex]
b
[tex]15.505 < \mu < 21.495[/tex]
c
[tex]14.93 < \mu < 22.069[/tex]
Step-by-step explanation:
From the question we are are told that
The sample data is 21, 14, 13, 24, 17, 22, 25, 12
The sample size is n = 8
Generally the ample mean is evaluated as
[tex]\= x = \frac{\sum x }{n}[/tex]
[tex]\= x = \frac{ 21 + 14 + 13 + 24 + 17 + 22+ 25 + 12 }{8}[/tex]
[tex]\= x = 18.5[/tex]
Generally the standard deviation is mathematically evaluated as
[tex]\sigma = \sqrt{\frac{\sum (x- \=x )^2}{n}}[/tex]
[tex]\sigma = \sqrt{\frac{\sum ((21 - 18.5)^2 + (14-18.5)^2+ (13-18.5)^2+ (24-18.5)^2+ (17-18.5)^2+ (22-18.5)^2+ (25-18.5)^2+ (12 -18.5)^2 )}{8}}[/tex]
[tex]\sigma = 5.15[/tex]
considering part b
Given that the confidence level is 90% then the significance level is evaluated as
[tex]\alpha = 100-90[/tex]
[tex]\alpha = 10\%[/tex]
[tex]\alpha = 0.10[/tex]
Next we obtain the critical value of [tex]\frac{ \alpha }{2}[/tex] from the normal distribution table the value is
[tex]Z_{\frac{ \alpha }{2} } = 1.645[/tex]
The margin of error is mathematically represented as
[tex]E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }[/tex]
=> [tex]E =1.645 * \frac{5.15 }{\sqrt{8} }[/tex]
=> [tex]E = 2.995[/tex]
The 90% confidence interval is evaluated as
[tex]\= x - E < \mu < \= x + E[/tex]
substituting values
[tex]18.5 - 2.995 < \mu < 18.5 + 2.995[/tex]
[tex]15.505 < \mu < 21.495[/tex]
considering part c
Given that the confidence level is 95% then the significance level is evaluated as
[tex]\alpha = 100-95[/tex]
[tex]\alpha = 5\%[/tex]
[tex]\alpha = 0.05[/tex]
Next we obtain the critical value of [tex]\frac{ \alpha }{2}[/tex] from the normal distribution table the value is
[tex]Z_{\frac{ \alpha }{2} } = 1.96[/tex]
The margin of error is mathematically represented as
[tex]E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }[/tex]
=> [tex]E =1.96 * \frac{5.15 }{\sqrt{8} }[/tex]
=> [tex]E = 3.569[/tex]
The 95% confidence interval is evaluated as
[tex]\= x - E < \mu < \= x + E[/tex]
substituting values
[tex]18.5 - 3.569 < \mu < 18.5 + 3.569[/tex]
[tex]14.93 < \mu < 22.069[/tex]
A clothing factory makes small, medium, and large sweaters. Last week, the factory made
1,612 sweaters. The factory made 3 times as many small sweaters as large sweaters. They
made 3 times as many medium sweaters as small sweaters.
How many small sweaters did the factory make last week?
This requires finding the number of small sweaters the company made last week
Number of small sweaters the company produced last week is 372
Total sweaters made = 1,612
Let
Small sweaters = 3x
Medium sweaters = x
Large sweaters = 3(3x) = 9x
Total = small + medium + large
1,612 = 3x + x + 9x
1612 = 13x
Divide by 13
x = 1612/13
Medium sweaters = x = 124
Small sweaters = 3x
= 3(124)
= 372
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PLEASE HELP FAST!! The cone and the cylinder below have equal surface area. True or False??
Answer:
B. FALSE
Step-by-step explanation:
Surface area of cone = πr(r + l)
Where,
r = r
l = 3r
S.A of cone = πr(r + 3r)
= πr² + 3πr²
S.A of cone = 4πr²
Surface area of cylinder = 2πrh + 2πr² = 2πr(h + r)
Where,
r = r
h = 2r
S.A of cylinder = 2πr(2r + r)
= 4πr² + 2πr²
S.A of cylinder = 6πr²
The surface are of the cone and that of the cylinder are not the same. The answer is false.
Answer:false
Step-by-step explanation:
False
Given two points M & N on the coordinate plane, find the slope of MN , and state the slope of the line perpendicular to MN . (there's two questions)
1) M(9,6), N(1,4)
2) M(-2,2), N(4,-4)
Answer:
Problem 1) [tex] m = \dfrac{1}{4} [/tex] [tex] slope_{perpendicular} = -4 [/tex]
Problem 2) [tex] m = \dfrac{1}{3} [/tex] [tex] slope_{perpendicular} = -3 [/tex]
Step-by-step explanation:
[tex] slope = m = \dfrac{y_2 - y_1}{x_2 - x_1} [/tex]
[tex] slope_{perpendicular} = \dfrac{-1}{m} [/tex]
Problem 1) M(9,6), N(1,4)
[tex] slope = m = \dfrac{6 - 4}{9 - 1} = \dfrac{2}{8} = \dfrac{1}{4} [/tex]
[tex] slope_{perpendicular} = \dfrac{-1}{\frac{1}{4}} = -4 [/tex]
Problem 2) M(-2,2), N(4,-4)
[tex] slope = m = \dfrac{4 - 2}{4 - (-2)} = \dfrac{2}{6} = \dfrac{1}{3} [/tex]
[tex] slope_{perpendicular} = \dfrac{-1}{\frac{1}{3}} = -3 [/tex]
The radius of a circle measures 5 inches A central angle of the circle measuring 12 radians cuts off a sector
What is the area of the sector?
Enter your answer as a simplified fraction in the box
area =
inches squared
Answer:
25/4 square inches
Step-by-step explanation:
The area of a sector of a circle is given by the formula ...
A = (1/2)r²θ
where r is the radius and θ is the central angle in radians.
For your sector, the area is ...
A = (1/2)(5 in)²(1/2) = 25/4 in²
Kevin's total payroll deductions are 30% of his earnings. If his deductions add up to $369 for a two week period, how much were his earnings for the period?
Answer:
His earnings for the period= $123
Step-by-step explanation:
Kevin's total payroll deductions are 30% of his earnings. His deductions add up to $369 for a two week period.
If 30% of his earnings = $369
His earnings = x
30/100 * x= 369
X= 369*100/30
X= 123*10
X=$ 1230
His earnings for the period= $123
Can I have help I am stuck on this problem It would mean the world if u helped me and tysm!! =-)
Answer:
8192
Step-by-step explanation:
2 cells at beginning, so the equation is (2)*(2^(4t)) where t is in hours. At the end of 3 hours, the cells will be 2*(2)^(12)=8192
Please help! Stuck on this question!!
Answer:
The 2 Gallon Tank is Enough
Step-by-step explanation:
A drink bottler needs to bottle 16 one-pint bottles. He has a 2 gallon tank and a 3 gallon tank.
There are 8 pints in a gallon. This means that 2 gallons would be 16 pints.
[tex]8 * 2 = 16[/tex]
So, the 2 gallon tank has 16 pints, which means that the 2 gallon tank should be enough to bottle all 16 bottles.
Answer:
2 gallon tank
Step-by-step explanation:
16 pints is the same as 2 US gallons
Perimeter =68 Length (L) is 4 less than twice the width (W)
Answer:
Length = 21.3333333333; Width: 12.6666666667
Step-by-step explanation:
Perimeter = 68
Perimeter of a rectangle:
2 (L +W)
Length (L) = 2W - 4
Width = W
2 ( 2W -4 +W) = 68
=> 2 (3W - 4) = 68
=> 6w -8 = 68
=> 6w = 76
=> w = 12.6666666667
Length = (12.6666666667 X 2) - 4
=> 21.3333333333
Martin currently has a balance of $948 in an account he has held for 20 years. He opened the account with an initial deposit of $600. What is the simple interest on the account?
A - 1.8%
B - 2.9%
C - 3.2%
D - 7.9%
An entry in the Peach Festival Poster Contest must be rectangular and have an area of 1200 square inches. Furthermore, it's length must be 20 inches longer than it's width. Find the dimensions.
Answer:
The length is 46.05551275 inches, and the width is 26.05551275 inches.
Step-by-step explanation:
We know that the area must be 1200 square inches. Using this information, we can create an equation, where x is length and y is width:
x*y=1200
We know that its length must be 20 inches longer than its width. Therefore, x=y+20. Using this new information, we can replace 'x' in 'x*y=1200' with 'y+20':
(y+20)*y=1200
[tex]y^{2} +20y=1200[/tex]
[tex]y^{2} +20y-1200=0[/tex]
I have decided to use the quadratic formula, but you could also factor this equation into the 'intercept' form to determine the roots, which ultimately provides the same answer.
[tex]y=\frac{-b+\sqrt{b^{2} -4ac} }{2a}[/tex]
[tex]y=\frac{-(20)+\sqrt{(20)^{2} -4(1)(-1200)} }{2(1)}[/tex]
[tex]y=\frac{-(20)+\sqrt{400+4800} }{2}[/tex]
[tex]y=\frac{-(20)+\sqrt{5200} }{2}[/tex]
[tex]y=\frac{52.11102551 }{2}[/tex]
[tex]y=26.05551275[/tex] inches
[tex]x=y+20[/tex]
[tex]x=(26.05551275)+20[/tex]
[tex]x=46.05551275[/tex] inches
Therefore, the length is 46.05551275 inches, and the width is 26.05551275 inches.
Which table has a constant of proportionality between 7 and x of 1/4? Choices are in the image
Answer:
A. has a constant proportion of 1/4.
g If A and B are disjoint events, with P( A) = 0.20 and P( B) = 0.30. Then P( A and B) is: a. .00 b. .10 c. .50 d. 0.06
Answer: A) 0
P(A and B) = 0 when events A and B are disjoint, aka mutually exclusive.
We say that two events are mutually exclusive if they cannot happen at the same time. An example would be flipping a coin to have it land on heads and tails at the same time.
(All yes or no questions). Determine whether each of the following pairs of angles have equal measures:
a. KJLand LJM
b. MJP and PJR
C. LJP and NJR
d. MJK and PJR
9514 1404 393
Answer:
a) no
b) yes
c) yes
d) no
Step-by-step explanation:
Angle LJM is complementary to KJL, so is ...
angle LJM = 90° -42° = 48°
Angle NJP is marked as congruent to angle PJQ, so is also 48°.
__
a) ∠KJL = 42° ≠ 48° = ∠LJM . . . . NO
b) ∠MJP = 46°+48° = 48° +46° = ∠PJR . . . . YES
c) ∠LJP = 48° +46° +48° = 48° +48° +46° = ∠NJR . . . . YES
d) ∠MJK = 90° ≠ 48° +46° = ∠PJR . . . . NO
9. Marvin Gate bought some fencing from a wholesaler for $6,000. The wholesaler offered a trade discount of 35%. What was the original price?
(Round to the nearest cent.)
A. $6,230.77
O B. $9.230.77
O C. $6,930.77
D. 55,930 77
Mark for review (Will be highlighted on the review page)
Answer:
B - %9230.77
Step-by-step explanation:
the original price of the fencing before the trade discount was approximately $9,230.77.
To find the original price of the fencing before the trade discount, we need to calculate the amount that corresponds to a 35% decrease from the discounted price.
Let's denote the original price as "P". The discounted price is given as $6,000.
The discounted price is calculated by subtracting the discount amount from the original price:
Discounted price = Original price - Discount amount
The discount amount is determined by multiplying the original price by the discount rate:
Discount amount = Original price × Discount rate
Given that the discount rate is 35% (or 0.35), we have:
Discount amount = P × 0.35
Substituting the discounted price of $6,000, we can write the equation as:
$6,000 = P - (P × 0.35)
Simplifying the equation:
$6,000 = P(1 - 0.35)
$6,000 = P(0.65)
To solve for P, we divide both sides of the equation by 0.65:
P = $6,000 / 0.65
P ≈ $9,230.77
Therefore, the original price of the fencing before the trade discount was approximately $9,230.77.
The correct answer is B. $9,230.77.
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Will Give Brainliest Please Answer Quick
Answer:
Option (2)
Step-by-step explanation:
If a perpendicular is drawn from the center of a circle to a chord, perpendicular divides the chord in two equal segments.
By using this property,
Segment MN passing through the center Q will be perpendicular to chords HI ans GJ.
By applying Pythagoras theorem in right triangle KNJ,
(KJ)² = (KN)² + (NJ)²
(33)² = (6√10)² + (NJ)²
NJ = [tex]\sqrt{1089-360}[/tex]
NJ = [tex]\sqrt{729}[/tex]
= 27 units
Since, GJ = 2(NJ)
GJ = 2 × 27
GJ = 54 units
Option (2) will be the answer.
Which value is a solution to w∕18 ≥ –1?
Answer:
w ≥ -18
Step-by-step explanation:
Answer:
w is greater than or equal to-18
An airplane has an air speed of 700 kilometers per hour at a bearing of 30 degrees The wind velocity is 40 kilometers per hour from the west Use vectors to find the art speed of the plane Round to the nearest hundredth
Answer:
The red arrow shows the resultant vector. We have a Side Angle Side triangle ABC so can use The Cosine Rule:
a2=b2+c2−2bccosA
This becomes:
R2=7002+402−(2×700×40×cos45)
R2=491,600−39,597.9
R=672.3xkm/hr
This is the groundspeed of the aircraft.
To find θ we can use The Sine Rule:
sinCc=sinAa
This becomes:
sinθ40=sin45672.3
sinθ=0.04207
θ=2.41∘
This is known as the drift angle and is the correction the pilot should apply to remain on course.
The heading is the direction the aircraft's nose is pointing which is 000∘.
The track is the actual direction over the ground which is 357.6∘
An alternative method to this would be to separate each vector into vertical and horizontal components and add.
The resultant can be found using Pythagoras.
If f(x)=3x^2-x+6, evaluate f(-4)
Answer:
f(-4) = 58
Step-by-step explanation:
Let x = -4:
[tex]f(-4)=3(-4)^2-(-4)+6\\\\f(-4)=3(16)+4+6\\\\f(-4)=48+4+6\\\\f(-4)=58[/tex]
2
Select the correct answer.
which number is the additive Inverse of -10 ?
O A 10 1
Ос. о
OD. -41
Reset
Next
Answer:
[tex]\boxed{\sf 10}[/tex]
Step-by-step explanation:
The additive number of any number is the number when added to the number gives a result of zero.
So, if we add 10 to -10 we get a result of zero.
=> -10+10
=> Zero
anybody know how to do this? if so, please explain!
Answer:
The x-intercepts are at (-4, 0) and (3, 0). The y-intercept is at (0, 1.2).
The graph is increasing at (-4, 0), (2.082, -0.604), (3, 0).
The graph is decreasing at (-2.082, 3.004), (0, 1.2), (1, 0)
Step-by-step explanation:
A sample of 81 observations is taken from a normal population with a standard deviation of 5. The sample mean is 40. Determine the 95% confidence interval for the population mean.
Answer:
38.911≤p≤41.089
Step-by-step explanation:
The formula for calculating confidence interval for a population mean us as shown below;
CI = xbar ± Z×S/√N where;
xbar is the sample mean = 40
Z is the z score at 95% confidence interval = 1.96
S is the standard deviation = 5
N is the sample size = 81
Substituting this parameters in the formula we have;
CI = 40±1.96×5/√81
CI = 40±(1.96×5/9)
CI = 40±(1.96×0.556)
CI = 40±1.089
CI = (40-1.089, 40+1.089)
CI = (38.911, 41.089)
The 95% confidence interval for the population mean is 38.911≤p≤41.089
Answer:
38.9 ≤ U ≤ 41.1
Step-by-step explanation:
Mean, m = 40; standard deviation, α = 5; Confidence limit, U = 95% or 0.95
N = 81
The standard error, α(m) = α/√(N) = 5/√81 =5/9
Using table: 0.95 = 0.0379
Z(0.95) = 2 - 0.0379 = 1.9621 or 1.96
Hence, confidence interval = { m - 1.96(α/√N) ≤ U ≤ m +1.96(α/√N)}
But, 1.96(α/√N) = 1.96 X 5/9 = 1.96 X 0.56 = 1.1
(40 - 1.1 ≤ U ≤ 40 + 1.1)
∴ the confidence interval = 38.9 ≤ U ≤ 41.1
The following data represents the age of 30 lottery winners.
22 26 27 27 31 34
36 42 43 44 48 49
52 53 55 56 57 60
65 65 66 67 69 72
75 77 78 78 79 87
Complete the frequency distribution for the data.
Age Frequency
20-29
30-39
40-49
50-59
60-69
70-79
80-89
Answer:
Step-by-step explanation:
This is an example of a frequency distribution for a class interval. In order to complete the frequency distribution, we will count the number of data occurring in each group, and write that number as the frequency for that group. This is done as shown below:
Age Frequency ages in class
20-29 4 22, 26, 27, 27
30-39 3 31, 34, 36
40-49 5 42, 43, 44, 48, 49
50-59 5 52, 53, 55, 56, 57
60-69 6 60, 56, 65, 66, 67, 69
70-79 6 72, 75, 77, 78, 78, 79
80-89 1 87
Total 30
70 points! Please answer fast!
Answer:
slope = 2
Step-by-step explanation:
will make it so simple and short
slope = rise / run
slope = 6 / 3
slope = 2
Answer:
B
Step-by-step explanation:
The formula for slope is (y2-y1)/(x2-x1)
In this case it is (1+5)/(3-0)
6/3
2
Help me please thank y’all
x= 30 degrees
Step-by-step explanation:
there's 180 degrees in a triangle. You can see 60 degrees right there. Theres a 90 degree angle right next to it. 180-150=30
Given that a random variable X is normally distributed with a mean of 2 and a variance of 4, find the value of x such that P(X < x)
Given that a random variable X is normally distributed with a mean of 2 and a variance of 4, find the value of x such that P(X < x)=0.99 using the cumulative standard normal distribution table
Answer:
6.642
Step-by-step explanation:
Given that mean = 2
standard deviation = 2
Let X be the random Variable
Then X [tex]\sim[/tex] N(n,[tex]\sigma[/tex])
X [tex]\sim[/tex] N(2,2)
By Central limit theorem;
[tex]z = \dfrac{X - \mu}{\sigma} \sim N(0,1)[/tex]
[tex]z = \dfrac{X - 2}{2} \sim N(0,1)[/tex]
P(X<x) = 0.09
[tex]P(Z < \dfrac{X-\mu}{\sigma })= 0.99[/tex]
[tex]P(Z < \dfrac{X-2}{2})= 0.99[/tex]
P(X < x) = 0.99
[tex]P(\dfrac{X-2}{2}< \dfrac{X-2}{2})=0.99[/tex]
[tex]P(Z< \dfrac{X-2}{2})=0.99[/tex]
[tex]\phi ( \dfrac{X-2}{2})=0.99[/tex]
[tex]( \dfrac{X-2}{2})= \phi^{-1} (0.99)[/tex]
[tex]( \dfrac{X-2}{2})= 2.321[/tex]
X -2 = 2.321 × 2
X -2 = 4.642
X = 4.642 +2
X = 6.642