Find the doubling time of an investment earning 8% interest if interest is compounded continuously. The doubling time of an investment earning 8% interest if interest is compounded continuously is ____ years.

Answers

Answer 1

Answer:

Step-by-step explanation:

Using FV = PV(1 + r)^n where FV = future value, PV = present value, r = interest rate per period, and n = # of periods

1/PV (FV) = (PV(1 + r^n)1/PV divide by PV

ln(FV/PV) = ln(1 + r^n) convert to natural log function

ln(FV/PV) = n[ln(1 + r)] by simplifying

n = ln(FV/PV) / ln(1 + r) solve for n

n = ln(2/1) / ln(1 + .08) solve for n, letting FV + 2, PV = 1 and rate = 8% or .08 compound annually

n = 9

n = ln(2/1) / ln(1 + .08/12) solve for n, letting FV + 2, PV = 1 and rate = .08/12 compound monthly

n = 104 months or 8.69 years

n = ln(2/1) / ln(1 + .08/365) solve for n, letting FV + 2, PV = 1 & rate = .08/365 compound daily

n = 3163 days or 8.67 years

Alternatively

A = P e ^(rt)

Given that r = 8%

= 8/100

= 0.08

2 = e^(0.08t)

ln(2)/0.08 = t

0.6931/0.08 = t

t= 8.664yrs

t = 8.67yrs

Which ever approach you choose to use,you will still arrive at the same answer.


Related Questions

find the measure of x

Answers

The answer is 43. You have to do: 180 (maximum in the triangle) - 47 - 90 (the angle that isn’t x) = 43. That’s the measure of x!

Answer:

[tex]B)\ x=43[/tex]

Step-by-step explanation:

One is given a circle with many secants within the circle. Please note that a secant refers to any line in a circle that intersects the circle at two points. A diameter is the largest secant in the circle, it passes through the circle's midpoint. One property of a diameter is, if a triangle inscribed in a circle has a side that is a diameter of a circle, then the triangle is a right triangle. One can apply this to the given triangle by stating the following:

[tex]x+47+90=180[/tex]

Simplify,

[tex]x+47+90=180[/tex]

[tex]x+137=180[/tex]

Inverse operations,

[tex]x+137=180[/tex]

[tex]x=43[/tex]

To find ∫ (x − y) dx + (x + y) dy directly, we must parameterize C. Since C is a circle with radius 2 centered at the origin, then a parameterization is the following. (Use t as the independent variable.)

x = 2 cos(t)
y = 2 sin(t)
0 ≤ t ≤ 2π

With this parameterization, find the followings

dy=_____
dx=_____

Answers

Answer:

Step-by-step explanation:

Hello, please consider the following.

[tex]x=x(t)=2cos(t)\\\\dx=\dfrac{dx}{dt}dt=x'(t)dt=-2sin(t)dt[/tex]

and

[tex]y=y(t)=2sin(t)\\\\dy=\dfrac{dy}{dt}dt=y'(t)dt=2cos(t)dt[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

The values of dx and dy are give as -2sin(t)dt and 2cos(t)dt respectively. The answer to the given problem can be stated as,

dy = 2cos(t)dt

And,  dx = -2sin(t)dt.

What is the integration of a function?

The integration can be defined as the inverse operation of differentiation. If a function is the integration of some function f(x) , then differentiation of that function is f(x).

The given integral over C is ∫ (x − y) dx + (x + y) dy.

And, the parameters for C are as follows,

x = 2cos(t)

y = 2sin(t)

0 ≤ t ≤ 2π

Now, on the basis of these parameters dx and dy can be found as follows,

x =  2cos(t)

Differentiate both sides with respect to t as follows,

dx/dt = 2d(cos(t))/dt

=> dx/dt = -2sin(t)

=> dx =  -2sin(t)dt

And, y = 2sin(t)

Differentiate both sides with respect to t as follows,

dy/dt = 2d(sin(t))/dt

=> dy/dt = 2cos(t)

=> dy = 2cos(t)dt

Hence, the value of dx and dy as per the given parameters is -2sin(t)dt and 2cos(t)dt respectively.

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boat costs $54,000. you pay 10% down and amortize the rest with equal monthly payments over a 15 year period. If you must pay 4.5 % comounded monthly, what is your monthly payment?

Answers

3385.8

Step-by-step explanation:

the length of a mathematical text book the is approximately 18.34cm and its width is 11.75 calculate ?​

the approximate perimeter of the front cover?

the approximate area of the front cover of the book?

Answers

Answer:

Perimeter=60.18cm

Area=215.495cm^2

Step-by-step explanation:

Given:

Length of book=18.34cm

Breadth=11.75cm

Solution:

Perimeter=2(l +b)

P=2(18.34+11.75)

P=2 x 30.09

P=60.18cm

Area=l x b

A=18.34 x 11.75

A=215.495 cm^2

Thank you!

The size of a television is the length of the diagonal of its screen in inches. The aspect ratio of the screens of older televisions is 4:3, while the aspect ratio of newer wide-screen televisions is 16:9. Find the width and height of an older 35-inch television whose screen has an aspect ratio of 4:3.

Answers

Answer:

The Width = 28 inches

The Height = 21 inches

Step-by-step explanation:

We are told in the question that:

The width and height of an older 35-inch television whose screen has an aspect ratio of 4:3

Using Pythagoras Theorem

Width² + Height² = Diagonal²

Since we known that the size of a television is the length of the diagonal of its screen in inches.

Hence, for this new TV

Width² + Height² = 35²

We are given ratio: 4:3 as aspect ratio

Width = 4x

Height = 3x

(4x)² +(3x)² = 35²

= 16x² + 9x² = 35²

25x² = 1225

x² = 1225/25

x² = 49

x = √49

x = 7

Hence, for the 35 inch tv set

The Width = 4x

= 4 × 7

= 28 inches.

The Height = 3x

= 3 × 7

= 21 inches

Sophia runs twice as fast as her friend Mia. If mia runs 3 mph how long will it tske sophia to run 6 miles? 9 miles?

Answers

Answer:

It will take Sophia 1 hour to run 6 miles.

And 1 1/2 hours for 9 miles.

Step-by-step explanation:

3. a) Why is X3 is a polynomial but
[tex] \frac{7}{x {}^{2} } [/tex]
, is not a polynomial? write in your words. ​

Answers

Answer:

because the power of variable is -2

Step-by-step explanation:

polynomials are a combination of constant and variable or only variable, being that power of variable is always positive natural no.

7/x^2 denotes 7x^-2

What are the zeros of , where

? help please need some help someone help please

Answers

[tex]{ \boxed{\boxed{\begin{array}{cc} \maltese  \bf \: given \\ \\ \rm \: f(x) = ( {x}^{2} + 16)( {x}^{2} - 9) \\ \\ \bf \: for \: zeroes \\ \\ \pink{ \boxed{\boxed{\begin{array}{c | c} \bf \: {x}^{2} + 16 = 0 & \bf \: {x}^{2} - 9 = 0 \\ \\ = > {x}^{2} = - 16& {x}^{2} = 9 \\ \\ = > x = \pm \sqrt{ - 16} &x = \pm \: \sqrt{9} \\ \\ = > x = \pm \sqrt{ {i}^{2} {4}^{2} } &x = \pm \: \sqrt{ {3}^{2} } \\ \\ = > x = \pm \: 4i&x = \pm3 \end{array}}}} \\ \\ \rm \: x = \pm3 \: and \pm \: 4i\end{array}}}}[/tex]

Option A is the correct answer

If the average yield of cucumber acre is 800 kg, with a variance 1600 kg, and that the amount of the cucumber follows the normal distribution. 1- What percentage of a cucumber give the crop amount between 778 and 834 kg? 2- What the probability of cucumber give the crop exceed 900 kg ?

Answers

Answer:

a

   The  percentage is

            [tex]P(x_1 < X < x_2 ) = 51.1 \%[/tex]

b

   The probability is  [tex]P(Z > 2.5 ) = 0.0062097[/tex]

Step-by-step explanation:

From the question we are told that

        The  population mean is  [tex]\mu = 800[/tex]

        The  variance is  [tex]var(x) = 1600 \ kg[/tex]

        The  range consider is  [tex]x_1 = 778 \ kg \ x_2 = 834 \ kg[/tex]

         The  value consider in second question is  [tex]x = 900 \ kg[/tex]

Generally the standard deviation is mathematically represented as

        [tex]\sigma = \sqrt{var (x)}[/tex]

substituting value

        [tex]\sigma = \sqrt{1600}[/tex]

       [tex]\sigma = 40[/tex]

The percentage of a cucumber give the crop amount between 778 and 834 kg  is mathematically represented as

       [tex]P(x_1 < X < x_2 ) = P( \frac{x_1 - \mu }{\sigma} < \frac{X - \mu }{ \sigma } < \frac{x_2 - \mu }{\sigma } )[/tex]

    Generally  [tex]\frac{X - \mu }{ \sigma } = Z (standardized \ value \ of \ X)[/tex]

So

      [tex]P(x_1 < X < x_2 ) = P( \frac{778 - 800 }{40} < Z< \frac{834 - 800 }{40 } )[/tex]

      [tex]P(x_1 < X < x_2 ) = P(z_2 < 0.85) - P(z_1 < -0.55)[/tex]

From the z-table  the value for  [tex]P(z_1 < 0.85) = 0.80234[/tex]

                                            and [tex]P(z_1 < -0.55) = 0.29116[/tex]  

So

             [tex]P(x_1 < X < x_2 ) = 0.80234 - 0.29116[/tex]

             [tex]P(x_1 < X < x_2 ) = 0.51118[/tex]

The  percentage is

            [tex]P(x_1 < X < x_2 ) = 51.1 \%[/tex]

The probability of cucumber give the crop exceed 900 kg is mathematically represented as

             [tex]P(X > x ) = P(\frac{X - \mu }{\sigma } > \frac{x - \mu }{\sigma } )[/tex]

substituting values

             [tex]P(X > x ) = P( \frac{X - \mu }{\sigma } >\frac{900 - 800 }{40 } )[/tex]

             [tex]P(X > x ) = P(Z >2.5 )[/tex]

From the z-table  the value for  [tex]P(Z > 2.5 ) = 0.0062097[/tex]

 

I need help with this question.​

Answers

Answer:

Complement = 15 Degrees

Supplement = 105 Degrees

Step-by-step explanation:

The complement of an angle refers to the measure that will make the angle 90 degrees.  So, the complement of 75 would be 15, since 90 - 75 = 15.

The supplement of an angle refers to the measure that will make the angle 180 degrees.  So, the supplement of 75 would be 105, since 180-75 = 105.

Cheers.

let f(x) = 9x - 2 and g(x) = -x + 3. find f(g(x)). a. -9x - 2 b. -9x + 5 c. -9x + 25 d. -9x + 27

Answers

Answer:

See below.

Step-by-step explanation:

[tex]f(x)=9x-2 \text{ and } g(x)=-x+3\\f(g(x))=f(-x+3)\\f(-x+3)=9(-x+3)-2\\\text{Distribute and Simplify}\\-9x+27-2\\=-9x+25\\\text{Therefore, f(g(x))=-9x+25}\\\text{The answer is C}[/tex]

If a teacher's guide to a popular SAT workbook is to be printed using a special type of paper, the guide must have at most 400 pages. If the publishing company charges 1 cent per page printed, what is the largest price, in dollars, that can be charged to print 20 copies of the workbook using the special paper?

Answers

Answer:

$80

Step-by-step explanation:

To find the largest price, assume that all 20 copies of the workbook will have 400 pages.

Since the company charges 1 cent per page, this means each workbook will cost 400 cents. This is equivalent to 4 dollars.

Find the total cost by multiplying this by 20:

20(4)

= 80

So, the largest price to print 20 copies is $80

The difference between two positive integers is 7 and the sum of their squares is 949. What are the numbers?

Answers

Answer:

25 and 18

Step-by-step explanation:

Let's say that the first number is x and the second one is y.

First, the difference between them is 7, so x-y=7

Next, the sum of their squares is 949, so x²+y² = 949

We have

x-y=7

x²+y²=949

One thing we can do to solve this problem is to solve for x in the first equation, plug that into the second equation, and go from there

Adding y to both sides in the first equation, we have

x = 7 + y

Plugging that into the second equation for x, we have

(7+y)²+ y² = 949

expand

(7+y)(7+y) + y² = 949

49 + y² + 7y + 7y + y² = 949

combine like terms

2y² +14y + 49 = 949

subtract 949 from both sides to put this in the form of a quadratic equation

2y² + 14y - 900 = 0

divide both sides by 2

y² + 7y - 450 = 0

To factor this, we want to find 2 numbers that add up to 7 and multiply to -450.

The factors of 450 are as follows:

1, 2, 3, 5, 6, 9, 10, 15, 18, 25, 30, 45, 50, 75, 90, 150, 225, and 450.

Note that we want to find two numbers with a difference of 7, as one will have to be negative for the multiplication to end up at -450. Two numbers that stand out are 18 and 25. To make them add up to 7, 18 can be negative. We therefore have

y² + 25y - 18y - 450 = 0

y(y+25) - 18(y+25) = 0

(y-18)(y+25) = 0

Solving for 0,

y-18 = 0

add 18 to both sides

y=18

y+25 = 0

subtract 25 from both sides

y= -25

As the question states "two positive integers", this means that y must be positive, so y = 18. We know x-y=7, so

x-18 = 7

add 18 to both sides to isolate x

x = 25

Can someone please help me ASAP:(

Answers

Answer:

3 =x

Step-by-step explanation:

(segment piece) x (segment piece) =   (segment piece) x (segment piece)

3x(x+1) = 4x*x

Divide each side by x

3(x+1) = 4x

Distribute

3x+3 = 4x

Subtract 3x from each side

3x-3x +3 = 4x-3x

3 =x

Can someone help me by solving this?

Answers

Answer:

30000 times 2.28 equals 68 400

Step-by-step explanation:

Customers receive rewards pints based on the purchase type:

Answers

Grocery, travel, dinning, and other.

The sum of the first 5 terms of an AP is 30 and the sum of the four term from T6 to T9 (inclusive) is 69. Find the AP​

Answers

Answer: The AP = 1, ⁷/₂, 6, ¹⁷/₂, 11 ..............

Step-by-step explanation:

From the first statement,

S₅ = ⁵/₂(2a + ( n - 1 )d }    = 30

       5(2a  + 4d )d           = 60

       10a    + 20d             = 60

reduce to lowest term to easy calculation by dividing through by 10

                      a + 2d       = 6 -----------------------------------1

second statement

sum of the next 4 terms inclusive

T₉  = ⁹/₂(2a + 8d )   = 69

        9(2a  + 8d )    = 30 + 69

            18a + 72d   = 99 x 2

            18a + 72d   = 198

divide through by 18 to reduce to lowest time

                a  + 4d    = 11 ------------------------------------------2

Now solve the two equation simultaneously to find a and d

                 a + 2d = 6

                 a + 4d = 11

                     -2d  = -5

                          d = ⁵/₂.

Now substitute  for d to get a

               a  + 2(⁵/₂) = 6

                a + 5       = 6

                           a   = 6 - 5

                            a = 1.

Therefore the AP = 1 , ⁷/₂ , 6 , ¹⁷/₂ , 11 , ..............

The AP if, The sum of the first 5 terms of an AP is 30 and the sum of the four terms from T6 to T9 is 69, is 1, ⁷/₂, 6, ¹⁷/₂, 11, and so on.

What is sequence?

An ordered collection of objects that allows repetitions is referred to as a sequence. It has members, just like a set does. The length of the sequence is determined by the number of items.

Given:

The sum of the first 5 terms of an AP is 30,

Write the equations as shown below,

S₅ = ⁵/₂(2a + ( n - 1 )d }  = 30

5(2a  + 4d )d = 60

10a    + 20d = 60

reduce to lowest term to easy calculation by dividing through by 10

a + 2d = 6

T₉  = ⁹/₂(2a + 8d )   = 69  (sum of the next 4 terms inclusive)

9(2a  + 8d )  = 30 + 69

18a + 72d  = 99 x 2

18a + 72d = 198

a  + 4d    = 11

Solve the equation as shown below,

d = ⁵/₂, and   a = 1.

Therefore, the AP = 1, ⁷/₂, 6, ¹⁷/₂, 11, and so on.

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prove (sinxsiny-cosxcosy)(sinxsiny+cosxcosy) =sin^2x-cos^2y

Answers

Step-by-step explanation:

Recall that [tex]\sin^2x + \cos^2x = 1[/tex]

[tex](\sin x \sin y - \cos x \cos y)(\sin x \sin y + \cos x \cos y)[/tex]

[tex]= \sin^2 x \sin^2 y - \cos^2 x \cos^2 y[/tex]

[tex]= \sin^2 x (1 - \cos^2 y) - \cos^2 x \cos^2 y[/tex]

[tex]= \sin^2 x - \sin^2 x \cos^2y - \cos^2x \cos^2y[/tex]

[tex]= \sin^2x - (\sin^2x + \cos^2x)\cos^2y[/tex]

[tex]= \sin^2x - \cos^2y[/tex]

A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater than that of its leading competitor. A sample of 19 phones from the manufacturer had a mean range of 1160 feet with a standard deviation of 32 feet. A sample of 11 similar phones from its competitor had a mean range of 1130 feet with a standard deviation of 30 feet.

Required:
Do the results support the manufacturer's claim?

Answers

Complete question is;

A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater than that of its leading competitor. A sample of 19 phones from the manufacturer had a mean range of 1160 feet with a standard deviation of 32 feet. A sample of 11 similar phones from its competitor had a mean range of 1130 feet with a standard deviation of 30 feet. Required:

Do the results support the manufacturer's claim?

Let μ1 be the true mean range of the manufacturer's cordless telephone and μ2 be the true mean range of the competitor's cordless telephone. Use a significance level of α = 0.01 for the test. Assume that the population variances are equal and that the two populations are normally distributed

Answer:

We will fail to reject the null hypothesis as there is no sufficient evidence to support the manufacturers claim.

Step-by-step explanation:

For the first sample, we have;

Mean; x'1 = 1160 ft

standard deviation; σ1 = 32 feet

Sample size; n1 = 19

For the second sample, we have;

Mean; x'2 = 1130 ft

Standard deviation; σ2 = 30 ft

Sample size; n2 = 11

The hypotheses are;

Null Hypothesis; H0; μ1 = μ2

Alternative hypothesis; Ha; μ1 > μ2

The test statistic formula for this is;

z = (x'1 - x'2)/√[(σ1)²/n1) + (σ2)²/n2)]

Plugging in the relevant values, we have;

z = (1160 - 1130)/√[(32)²/19) + (30)²/11)]

z = 2.58

From the z-table attached, we have a p-value = 0.99506

This p-value is more than the significance value of 0.01,thus,we will fail to reject the null hypothesis as there is no sufficient evidence to support the manufacturers claim.

answer no explantion pls i need asap

Answers

Answer:

Below.

Step-by-step explanation:

Area = 5(x + 3)

= 5x + 15

Perimeter = 2(x + 3) + 2(5)

= 2x + 6 + 10

= 2x + 16.

Let E and F be two events of an experiment with sample space S. Suppose P(E) = 0.6, P(F) = 0.3, and P(E ∩ F) = 0.1. Compute the values below.

(a) P(E ∪ F) =



(b) P(Ec) =



(c) P(Fc ) =



(d) P(Ec ∩ F) =

Answers

Answer:

(a) P(E∪F)= 0.8

(b) P(Ec)= 0.4

(c) P(Fc)= 0.7

(d) P(Ec∩F)= 0.8

Step-by-step explanation:

(a) It is called a union of two events A and B, and A ∪ B (read as "A union B") is designated to the event formed by all the elements of A and all of B. The event A∪B occurs when they do A or B or both.

If the events are not mutually exclusive, the union of A and B is the sum of the probabilities of the events together, from which the probability of the intersection of the events will be subtracted:

P(A∪B) = P(A) + P(B) - P(A∩B)

In this case:

P(E∪F)= P(E) + P(F) - P(E∩F)

Being P(E) = 0.6, P(F) = 0.3 and P(E ∩ F) = 0.1

P(E∪F)= 0.6 + 0.3 - 0.1

P(E∪F)= 0.8

(b)  The complement of an event A is defined as the set that contains all the elements of the sample space that do not belong to A.  The Complementary Rule establishes that the sum of the probabilities of an event and its complement must be equal to 1. So, if P (A) is the probability that an event A occurs, then the probability that A does NOT occur is  P (Ac) = 1- P (A)

In this case: P(Ec)= 1 - P(E)

Then: P(Ec)= 1 - 0.6

P(Ec)= 0.4

(c) In this case: P(Fc)= 1 - P(F)

Then: P(Fc)= 1 - 0.3

P(Fc)= 0.7

(d)  The intersection of two events A and B, designated as A ∩ B (read as "A intersection B") is the event formed by the elements that belong simultaneously to A and B. The event A ∩ B occurs when A and B do at once.

As mentioned, the complementary rule states that the sum of the probabilities of an event and its complement must equal 1. Then:

P(Ec intersection F) + P(E intersection F) = P(F)

P(Ec intersection F) + 0.1 = 0.3

P(Ec intersection F)= 0.2

Being:

P(Ec∪F)= P(Ec) + P(F) - P(Ec∩F)

you get:

P(Ec∩F)= P(Ec) + P(F) - P(Ec∪F)

So:

P(Ec∩F)= 0.4 + 0.3 - 0.2

P(Ec∩F)= 0.8

An expression is ???

Answers

Answer:

s-6

Step-by-step explanation:

difference means subtract

s-6

Solve the following formula for a.

Answers

Answer:

B is correct .trust me

Step-by-step explanation:

Determine whether or not F is a conservative vector field. If it is, find a function f such that F = ∇f. (If the vector field is not conservative, enter DNE.) F(x, y) = (3x2 − 2y2)i + (4xy + 4)j

Answers

In order for F to be conservative, there must be a scalar function f such that the gradient of f is equal to F. This means

[tex]\dfrac{\partial f}{\partial x}=3x^2-2y^2[/tex]

[tex]\dfrac{\partial f}{\partial y}=4xy+4[/tex]

Integrate both sides of the first equation with respect to x :

[tex]f(x,y)=x^3-2xy^2+g(y)[/tex]

Differentiate both sides with respect to y :

[tex]\dfrac{\partial f}{\partial y}=-4xy+\dfrac{\mathrm dg}{\mathrm dy}=4xy+4\implies\dfrac{\mathrm dg}{\mathrm dy}=8xy+4[/tex]

But we assume g is a function of y, which means its derivative can't possibly contain x, so there is no scalar function f whose gradient is F. Therefore F is not conservative.

In this problem, since the condition of equal derivatives does not apply, the vector field is not conservative.

A vector field can be described as:

[tex]F = <P,Q>[/tex]

It is conservative if:

[tex]\frac{\partial P}{\partial y} = \frac{\partial Q}{\partial x}[/tex]

In this problem, the field is:

[tex]F = <3x^2 - 2y^2, 4xy + 4>[/tex]

Then:

[tex]P(x,y) = 3x^2 - 2y^2[/tex]

[tex]\frac{\partial P}{\partial y} = -4y[/tex]

[tex]Q(x,y) = 4xy + 4[/tex]

[tex]\frac{\partial Q}{\partial x} = 4y[/tex]

Since [tex]\frac{\partial P}{\partial y} \neq \frac{\partial Q}{\partial x}[/tex], the field is not conservative.

A similar problem is given at https://brainly.com/question/15236009

What is the value of log,1252
PERE
3
5
Ο ΟΟΟ
15
Mark this and return
Save and Exit
Next

Answers

2 by 5 t get you 15k

What is the perimeter of the triangle?

Answers

Answer:

The perimeter will be 30

Step-by-step explanation:

Perimeter = all side lengths added

Step 1. Determine the length of the triangle

Answer: 5

Step 2. Determine the width of the triangle

Answer: 12

Step 3. Determine the diagonal line across the triangle

Answer + explanation:

For it to figure it out, we must use this method called Pythagorean Theorem

Pythagorean Theorem: a^2 + b^2 = c^2

Where a = 12 b = 5 and c = the diagonal line

12^2 + 5^2 = c^2

144 + 25 = c^2

c^2 = 169

c = 13

The diagonal line measures 13 units

Step 4. Add all of the dimensions we just reviewed

Answer:

Length = 5

Width = 12

Diagonal line = 13

5 + 12 + 13 = perimeter

perimeter = 30

Therefore, the perimeter is 30


The lines shown below are perpendicular. If the green line has a slope of 2/5
, what is the slope of the red line?



A.


B.


C.
-

D.
-

Answers

Answer:

C. [tex] -\frac{5}{2}} [/tex]

Step-by-step explanation:

If two lines on a graph are perpendicular to each other, their slope is said to be negative reciprocals of each other. This means the slope of one, is the negative reciprocal of the other.

This can be represented as [tex] m_1 = \frac{-1}{m_2} [/tex]

Where, [tex] m_1, m_2 [/tex] are slopes of 2 lines (i.e. the red and green lines given in the question) that are perpendicular to one another.

Thus, the slope of the red line would be:

[tex] m_1 = \frac{-1}{\frac{2}{5}} [/tex]

[tex] m_1 = -1*\frac{5}{2}} [/tex]

[tex] m_1 = -\frac{5}{2}} [/tex]

The slope of the red line = [tex] -\frac{5}{2}} [/tex]

what is the domain of f(x)=(1/4)^x

Answers

Answer:

B All real numbers

hope you wil understand

Answer:

[tex]\boxed{\sf B. \ All \ real \ numbers}[/tex]

Step-by-step explanation:

The domain is all possible values for x.

[tex]f(x)=(\frac{1}{4} )^x[/tex]

There are no restrictions on the value of x.

The domain is all real numbers.

Billy has x marbles. Write an
expression for the number of
marbles the following have…
a) Charlie has 5 more than Billy
b) Danny has 8 fewer than Billy
c) Eric has three times as many as
Billy

Answers

Answer:

[tex]Charlie = 5 + x[/tex]

[tex]Danny = x - 8[/tex]

[tex]Eric = 3x[/tex]

Step-by-step explanation:

Given

Billy's Marble = x

Required

Determine a,b and c

a. Charlie's Marble

"5 more" means 5 + or + 5

Since Billy's Marble is represented with x, then Charlie's Marbles will be

[tex]Charlie = 5 + x[/tex]

b. Danny's Marbles

Having "8 fewer" means we have to subtract 8 from Billy's marble;

Since Billy's Marble is represented with x, then Danny's Marbles will be

[tex]Danny = x - 8[/tex]

c. Eric Marbles

Having "three times as " means we have to multiply Bill's marble by 3;

Since Billy's Marble is represented with x, then Danny's Marbles will be

[tex]Eric = 3 * x[/tex]

[tex]Eric = 3x[/tex]

An ESP experiment used the "Ten Choice Trainer." This is like the Aquarius, but with 10 targets instead of 4. Suppose that in 1,000 trials, a subject scores 173 correct guesses.

Required:
a. Set up the null hypothesis as a box model.
b. The SD of the box is:_______
c. Make the z-test.
d. What do you conclude?

Answers

Answer:

a. The H0 is number of correct guesses is 173

b. Standard Deviation of box is 0.3

c. z-test value is 7.70

d. The difference does not appear due to chances of Variation.

Step-by-step explanation:

The standard deviation is :

[tex]\sqrt{0.1 * 0.9}[/tex] = 0.3

The standard deviation of the box is 0.3 approximately.

Z-score is [tex]\frac{x-u}{standard error}[/tex]

Z-score = [tex]\frac{173-100}{9.4868}[/tex]

the value of z-score is 7.70.

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