Find the lateral area of this pyramid whose
base is a regular hexagon with a side length of
3 cm and whose slant height is 12 cm.
12 cm
3 cm
[ ? ] cm2

The slope of the perpendicular line b is -1/7 if the slope of the perpendicular line a is 7.

According to the question,

Line 'a' is perpendicular to the line 'b'. If the slope of the line 'a' is 7.

The condition of slopes if two lines are perpendicular m₁ m₂ = -1

(7)(m₂) = -1

   m₂ = -1/7

Hence, the slope of the perpendicular line b is -1/7 if the slope of the perpendicular line a is 7.  

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Answer:

2.78%

Step-by-step explanation:

Probability Formula

[tex]\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}[/tex]

We are told that the six-sided dice is fair. This means that each of the faces has the same probability of being rolled.

Therefore, the probability of rolling one is:

[tex]\implies \sf P(x = 1)=\dfrac{1}{6}[/tex]

The probability of rolling six is:

[tex]\implies \sf P(x = 6)=\dfrac{1}{6}[/tex]

Therefore, the probability of rolling one and then six is:

[tex]\begin{aligned}\implies \sf P(x=1)\:and\:P(x=6) & = \sf \dfrac{1}{6} \times \dfrac{1}{6}\\& =\sf \dfrac{1}{36}\\& = \sf 0.0278\:(3\:s.f.)\\& = \sf 2.78\%\:(3\:s.f.)\end{aligned}[/tex]

Total elements in sample space=6

P(1)

P(6)

P(1 and 6)

Q14)

a) The smallest prime number is 2. The smallest composite number is 4.

b) Rs 720 - 20 [as loss]

=> Rs 790 = SP

c) Rs 500 - 30 [as profit]

=> Rs 470 = CP

d) a° + b° = 180°

Hope it helps you!

A = 6 cm; B = 3 cm; C = 8 cm; D = 10 cm

The Surface area of the prism = 120 cm².

Surface area = Area of A + B + C + D

The side lengths are:

A = 6 cm

B = 3 cm

C = 8 cm

D = 10 cm

Surface area of the prism = 2(area of triangular face) + area of rectangle 1 + area of rectangle 2 + area of rectangle 3

Area of triangular face = 1/2(b)(h) = 1/2(8)(6) = 24 cm

Area of rectangle 1 = (length)(width) = (10)(3) = 30 cm²

Area of rectangle 2 = (length)(width) = (6)(3) = 18 cm²

Area of rectangle 3 = (length)(width) = (8)(3) = 24 cm²

Surface area of the prism = 2(24) + 30 + 18 + 24 = 120 cm².

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Answer:

Gavin has 19 nickels & 114 quarters

Step-by-step explanation:

N : D : Q

1 : 3 : 6 = 57

x : 57 : y

57 / 3 = 19

1 x 19 : 3 x 19 : 6 x 19

19 : 57 : 114

Using translation concepts, the equations are given as follows:

a) [tex]y = \sqrt{16 - 4x^2}[/tex]

b) [tex]y = 3\sqrt{16 - x^2}[/tex]

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

In this problem, the parent function is:

[tex]y = \sqrt{16 - x^2}[/tex]

In item a, when it is horizontally compressed by a factor of 2, it means that x -> 2x, hence:

[tex]y = \sqrt{16 - (2x)^2} = \sqrt{16 - 4x^2}[/tex]

In item b, the transformations are given as follows:

Then:

[tex]y = 3\sqrt{16 -(-x)^2} = 3\sqrt{16 - x^2}[/tex]

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[tex] {\qquad\quad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

[tex]\qquad \sf  \dashrightarrow \: {x}^{2} + \cfrac{1}{ {x}^{2} } = 34[/tex]

[ add 2 on both sides ]

[tex]\qquad \sf  \dashrightarrow \: {x}^{2} + \cfrac{1}{ {x}^{2} } + 2 = 34 + 2[/tex]

[ form identity : a² + b² + 2ab ]

[tex]\qquad \sf  \dashrightarrow \: {(x)}^{2} + { \bigg(\cfrac{1}{ {x}^{} } \bigg) }^{2} + 2 \sdot(x) \sdot \bigg(\cfrac{1}{x} \bigg) = 36[/tex]

[ a² + b² + 2ab = (a + b)² ]

[tex]\qquad \sf  \dashrightarrow \: {\bigg (x + \cfrac{1}{x} \bigg) }^{2} = 36[/tex]

[tex]\qquad \sf  \dashrightarrow \: {\bigg (x + \cfrac{1}{x} \bigg) }^{} = \sqrt{ 36}[/tex]

[tex]\qquad \sf  \dashrightarrow \: x + \cfrac{1}{x} = \pm 6[/tex]

so, the value of required expression is 6

[usually positive value is considered, but if asked the value can be either positive or negative]

Answer: 7

Step-by-step explanation:

By the triangle proportionality theorem,

[tex]\frac{?}{21}=\frac{3}{9}\\\\?=7[/tex]

The inverse function of g(x) is:

[tex]f(x) = -\frac{3}{x + 4}[/tex]

So the correct option is D.

Here we have the function:

[tex]g(x) = -\frac{3}{x} - 4[/tex]

Remember that two functions f(x) and g(x) are inverses if:

[tex]f(g(x)) = x\\g(f(x)) = x[/tex]

Then we must have:

[tex]g(f(x)) = -\frac{3}{f(x)} - 4 = x[/tex]

Solving for f(x), we get:

[tex]-\frac{3}{f(x)} - 4 = x\\\\ \frac{3}{f(x)} +4 = -x[/tex]

[tex]\frac{3}{f(x)} = -x - 4\\\\3 = (-x - 4)*f(x)\\\\\frac{3}{-x - 4} = f(x) = -\frac{3}{x + 4}[/tex]

Then the correct option is D.

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Using an exponential function, it is found that there will be 32,768 bacteria after 3 hours.

An exponential function is modeled by:

[tex]y = ab^x[/tex]

In which:

For this problem, the parameters are:

a = 8, b = 4.

3 hours is 6 periods of 30 minutes, hence the amount is:

[tex]y = 8 \times 4^6 = 32768[/tex]

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The surface area of pyramid is 47km^2

A regular pyramid has a base that is a regular polygon and a vertex that is above the center of the polygon.

A pyramid is named after the shape of its base. A rectangular pyramid has a rectangle base. A triangular pyramid has a triangle base.

Given that the base of the pyramid is 5 km and the slant height is 4.7km

We need to find the surface area of pyramid

We know that

The lateral surface of pyramid = 4 *(1/2* length of base * slant height)  

= 2*5*4.7

=47km^2

Hence the surface area of the pyramid is 47km^2

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the one you selected is correct

The amount of money Kim, maneet and Sutopa have is $115.6, $97.6 and $73.2 respectively.

x + (x - 18) + 3/4(x-18) = 286.40

x + x - 18 + 3/4x - 13.5 = 286.40

2 3/4x = 286.40 + 13.5 + 18

11/4x = 317.9

x = 317.9 ÷ 11/4

= 317.9 × 4 / 11

= 1,271.6 / 11

x = $115.6

So,

Kim = x

= $115.6

Maneet = x - 18

= 115.6 -18

= $97.6

Sutopa = 3/4(x-18)

= 3/4(97.6)

= $73.2

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We have lcm(2, 3, 5) = 30, but none of 30/2 = 15, 30/3 = 10, nor 30/5 = 6 are divisible by 2, 3, and 5, respectively.

To account for this, take the square of 30, 30² = 900. Then 900/2 = 450, 900/3 = 300, and 900/5 = 180 are respectively divisible by 2, 3, and 5.

Multiply this by 2 to get a 4-digit number. It follows that [tex]\boxed{a=1800}[/tex].

The given statements:

1) ΔQRS ≅ ΔSTU (according to the ASA axiom)

2) The congruent ∠S: ∠RSQ ≅ ∠UST (Vertical angles)

The ASA axiom states that "two triangles are said to be congruent if two pairs of corresponding angles and the sides between these angles are equal".

It is given that,

S is the midpoint of QT.

So, SQ ≅ ST <S>

Since ∠S is at the intersection of two transversal lines, ∠RSQ ≅ ∠UST <A>.  This is beacuse they are vertically opposite.

And QT is the transverse line for the parallel lines, QR║UT. So, the alternate angles(interior) are congruent. I.e., ∠SQR ≅ ∠UTS <A>.

From this, the given triangles have two equal corresponding angles and congruent sides in between them.

So, ΔQRS ≅ ΔSTU according to ASA axiom.

Therefore, ΔQRS ≅ ΔSTU and ∠RSQ ≅ ∠UST.

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Answer:

[tex]T_{23}=-153[/tex]

Step-by-step explanation:

[tex]T_{23}=a+(n-1)d\\[/tex]

[tex]=a+(23-1)d=a+22d[/tex]

Now [tex]a=-21[/tex] and

[tex]d=-27-(-21)\\=-6[/tex]

So [tex]T_{23}==21+((22)6\times-1)[/tex]

[tex]=-153[/tex]

Answer:

x=12

Step-by-step explanation:

x^9=12^9

power of 9 cancel eachother at both sides of equation.

so

x=12

Answer:

C

Step-by-step explanation:

[tex]\frac{x+1}{x-4}[/tex] × [tex]\frac{5x}{x+1}[/tex] ← cancel x + 1 on numerator and denominator

= [tex]\frac{1}{x-4}[/tex] × [tex]\frac{5x}{1}[/tex]

= [tex]\frac{5x}{x-4}[/tex]

Answer:

5x/(x-4)

Step-by-step explanation:

To multiply fractions, all we have to do is multiply the numerators together and the denominators together. If we do that, we get the following:

[tex]\frac{x+1}{x-4}*\frac{5x}{x+1}=\frac{(x+1)(5x)}{(x-4)(x+1)}[/tex]

We notice that both the numerator and the denominator have an (x+1) term. Whenever you have something divided by itself, you get 1. In other words, they cancel out. As such, we can remove them from our answer to simplify it:

[tex]\frac{5x}{x-4}[/tex]

If we do that, we get the expression above. 5x/(x-4) is the reduced product of the rational expression given.

Answer:

a₃₂ = 131

Step-by-step explanation:

the nth term of an arithmetic sequence is

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

here a₁ = 7 and d = 4 , then

a₃₂ = 7 + (31 × 4) = 7 + 124 = 131

The quadrants in which all the coordinates given are located is; As explained below.

1) (2, 4) is located in Quadrant I where both x and y-values are positive.

2) (0, -3) is located in Quadrant II where x - values are positive but y-values are negative.

3) (-1, 1/2) is located in Quadrant IV.

4) (-2 1/2, -7) is located in Quadrant III where x and y values are both negative.

5) (0, 6) is located in Quadrant I where both x and y-values are positive.

6) (-5, 0) is located in Quadrant IV where x is negative but y is positive.

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The  truncation error for s3  is 0.008

The  truncation error serves as the  difference between a truncated value as well as  the actual value.

This truncated quantity can be a numeral having a fixed number of allowed digits.

Therefore the value of S_3=0.008

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❄ Hi there,

let us revise the rounding rules and then, get down to rounding the number.

[tex]\sf{Rounding \ Rules:}[/tex]

Now we can start the rounding process.

Reading the problem & the directions, we notice that we need to round to 3 decimal places (3 numbers after the decimal point).

Looking at the fourth number, we notice that it's less than 5.

∴ we need to round down ↡

↬[tex]\sf{18.57631 \ rounded \ to \ 3 \ DP \ = \bf{18.576}}[/tex]

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

❄

It takes Jay, Elle and Kay to work individually for 70 minutes, 105 minutes and 52.5 minutes respectively

A ratio can sometimes be regarded as fraction. While rate has something to do with time.

Given that Jay and Kay can pack the shelves in one aisle of the supermarket in 30 minutes. Kay and Elle take 35 minutes to do the same job. When Jay and Elle work together, the job takes 42 minutes.

Let

The interpretation of the question go thus;

1/J + 1/K = 1/30 ........ (1)

1/K + 1/E = 1/35 .........(2)

1/J + 1/E = 1/42 .........(3)

Make 1/J and 1/E the subject of formula in equation 1 and 2 respectively and substitute them in equation 3

1/J = 1/30 - 1/K  ........ (4)

1/E = 1/35 - 1/K  .........(5)

1/30 - 1/K + 1/35 - 1/K = 1/42

Collect the like terms

- 1/K - 1/K = 1/42 - 1/30 - 1/35

-2/K = (35 - 49 - 42)/1470

-2/K = -56/1470

1/K = 28/1470

Reciprocate both sides

K = 1470/28

K = 52.5 minutes.

Substitute K in both equation 4 and 5

1/J = 1/30 - 28/1470

1/J = (49 - 28)/1470

1/J = 21/1470

Reciprocate both sides

J = 1470/21

J = 70 minutes

1/E = 1/35 - 28/1470

1/E = (42 - 28)/1470

1/E = 14/1470

Reciprocate both sides

E = 1470/14

E = 105 minutes

Therefore, it takes Jay, Elle and Kay to work individually for 70 minutes, 105 minutes and 52.5 minutes respectively

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Answer:

The distance between the points (4,3) and (1,-1) is C. 5 units.

Step-by-step explanation:

Answer:

(f-g)(x)= (3x + 10) - (5x -3)

f-g = 3x + 10 - 5x + 3

f-g = -2x + 13

Answer:

12/13

Step-by-step explanation:

there are 4 7's in a 52 card deck, that means the other 48 cards are not 7's. 48/52 = 12/13

No, this not plagiarism .You can use generally accepted facts without citing them.

What defines self-plagiarism?

Self-plagiarism is defined as a type of plagiarism in which the writer republishes a work in its entirety or reuses portions of a previously written text while authoring a new work.

What is considered general knowledge in plagiarism?

How to Avoid plagiarism common knowledge?

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