Answer:
Tension on the string is 48 N
Explanation:
Mass of A = 6 kg
mass of B = 4 kg
If the 9 kg accelerates downwards then the equation for the 6 kg mass side of the pulley will be
6g - T = 6a ....1
where
g is acceleration due to gravity = 10 m/s^2
a is the acceleration of the body
T is the tension in the string.
For the 4 kg mass side of the string, we have
T - 4g = 4a ....2
transposing, we have
T = 4a + 4g ....3
substitute equation 3 in equation 1, we have
6g - (4a + 4g) = 6a
6g - 4a - 4g = 6a
6g - 4g = 6a + 4a
2g = 10a
but g = 10 m/s^
2 x 10 = 10a
20 = 10a
acceleration a = 20/10 = 2 m/s^2
substitute value of a in equation 1
6g - T = 6a
6(10) - T = 6(2)
60 -T = 12
60 - 12 = T
T = 48 N
The graphs display velocity data Velocity is on the y-axis (m/s), while time is on the x-axis (s). Based on the graphs, which data set represents constant acceleration?
Answer:
The first graph is showing the constant acceleration (1 m/s)
Explanation:
The second graph showing the flexible velocity therefore a in the graph is different at t1, t2, t3, t4
The last graph is showing constant velocity therefore there is no acceleration (a = 0)
Answer:
A
Explanation:
on edge
A bull pulls a plough with constant force of 200N along a field through a distance of 10m in 10s. What is the power of bull?
Answer:
we have to find out the work done in order to find the power since power is the amount of joules spent every second
work done by the bull = Force * Displacement
work done = 200 N * 10 m
work done = 2000 Nm or 2000 j
since we know that the bull spent the 2000 j in 10 seconds,
we will find the amount of energy spent in a second:
power = work done / time
power = 2000 / 10
power = 200 W
a brainly will be appreciated
Answer:
200W
Explanation:
as power = work/time
= force * distance /time
= 200 * 10/ 10
==200W
In physics, a field refers to a quantity that has a value for every point in a space. In a sense, a field is like a function in mathematics; the input is some point in space and the output is some object. A familiar example of a field is elevation. At every point on earth's surface, we can ask how far above or below sea level we are.
1) (Introduction) For the following physical quantities, decide which are fields and which are not. You may remember that vectors are physical quantities that have a direction (and magnitude) and scalars physical quantities that are just numbers. If you decide the quantity is a field, s it a scalar field?
a) Temperature at ground level
b) Wind velocity at 100 feet above the ground.
c) Gravitational force on Roessler Hall.
d) Height of a person in your group.
e) Height (above sea level) of the ground.
f) Slope of the surface of the earth.
Answer:
Explanation:
a ) Temperature at ground level is a field and it is scalar field .At any point in space near ground level , the temperature is specific so it is a field . It is scalar because temperature has no direction .
b )
Wind velocity at 100 feet above the ground is also a field but it is a vector field . At any point in space , the wind velocity is specific so it is a field . It is vector because velocity has a particular direction at any point .
c )
Gravitational force on Roessler Hall is a vector field because gravitational force also depends on location in space and it has direction.
d )
Height of a person in your group is not a space because it does not depend upon location is space . It is same for all location .
e )
Height (above sea level) of the ground is a field because it also depends upon location in space . It is scalar field .
f )
Slope of the surface of the earth is a scalar field .
A 15.0 nC point charge is 15 m from a second point charge, and the electric force on one of them due to the other is 5.0 N. What is the magnitude of t
Answer:
t = 125 C
Explanation:
The force on a charge due to other charge is given by Coulomb's Law, as follows:
F = kq₁q₂/r²
where,
F = Electric Force = 5 N
k = Coulomb Constant = 9 x 10⁹ N.m²/C²
q₁ = magnitude of first charge = 15 nC = 1.5 x 10⁻⁸ C
q₂ = Magnitude of 2nd Charge = t = ?
r = distance between charges = 15 m
Therefore,
5 N = (9 x 10⁹ N.m²/C²)(1.5 x 10⁻⁸ C)t/(15 m)²
t = (5 N)/(0.04 N/C)
t = 125 C
[tex]\huge\underline\mathcal \pink{QUESTION:-}[/tex]
THREE DISADVANTAGES OF NUCLEAR POWER.
Answer:
Here are some of the main cons of nuclear energy.
•Expensive to Build. Despite being relatively inexpensive to operate, nuclear power plants are incredibly expensive to build—and the cost keeps rising. ...
•Accidents. ...
•Produces Radioactive Waste. ...
•Impact on the Environment. ...
•Security Threat. ...
•Limited Fuel Supply.
[tex]\huge\underline\mathcal\pink{Answer:-}[/tex]
The nuclei of atoms contain a large amount of energy. Releasing this energy would free the world from having to use fossil fuels. There are two methods of doing this: fission and fusion.
1. Nuclear is a bad match for renewables.
2. Building nuclear power stations is very expensive.
3.There are huge costs beyond simply constructing the power stations.
4 Nuclear power stations take at least a decade to build.
[tex]\huge\red{kya \: aap \: samajhe?}[/tex]
Which shows the temperatures of three substances, in order, from greatest to least?
ОООО
water vapor, ice, water
ice, water, water vapor
water, water vapor, ice
water vapor, water, ice
Answer:
Hey !.
I think the answer will be water vapour,ice ,water.
Answer:
water vapor, water, ice
Hope this answer correct ✌️
three equal charges are fixed at the three corners of a rectangle what is the force on the top left charge from the bottom left
Answer:
hello your question is incomplete attached below is the missing parts and the detailed solution of the problem
answer : [tex]\frac{1}{4\pi e_{0} } * \frac{q^2}{h^2} i_{y}[/tex] ( D )
Explanation:
The force on the top left charge from the bottom left can be determined applying the equations/expression as represented in the detailed solution
option D was chosen because it accurately represents the force on the top left charge( positive y axis ) from the bottom left
Two asteroids identical to those above collide at right angles and stick together; i.e, their initial velocities were perpendicular to each other (take A initially moving to the right and B initially moving up). Use momentum conservation (make a complete Momentum Chart) to find the velocity (magnitude and direction with-respect-to the velocity asteroid A had before the collision) of the asteroids after the collision.
Answer:
velocity = 62.89 m/s in 58 degree measured from the x-axis
Explanation:
Relevant information:
Before the collision, asteroid A of mass 1,000 kg moved at 100 m/s, and asteroid B of mass 2,000 kg moved at 80 m/s.
Two asteroids moving with velocities collide at right angles and stick together. Asteroid A initially moving to right direction and asteroid B initially move in the upward direction.
Before collision Momentum of A = 1000 x 100 = [tex]$ 10^5$[/tex] kg - m/s in the right direction.
Before collision Momentum of B = 2000 x 80 = 1.6 x [tex]$ 10^5$[/tex] kg - m/s in upward direction.
Mass of System of after collision = 1000 + 2000 = 3000 kg
Now applying the Momentum Conservation, we get
Initial momentum in right direction = final momentum in right direction = [tex]$ 10^5$[/tex]
And, Initial momentum in upward direction = Final momentum in upward direction = 1.6 x [tex]$ 10^5$[/tex]
So, [tex]$ V_x = \frac{10^5}{3000} $[/tex] = [tex]$ \frac{100}{3} $[/tex] m/s
and [tex]$ V_y=\frac{160}{3}$[/tex] m/s
Therefore, velocity is = [tex]$ \sqrt{V_x^2 + V_y^2} $[/tex]
= [tex]$ \sqrt{(\frac{100}{3})^2 + (\frac{160}{3})^2} $[/tex]
= 62.89 m/s
And direction is
tan θ = [tex]$ \frac{V_y}{V_x}$[/tex] = 1.6
therefore, [tex]$ \theta = \tan^{-1}1.6 $[/tex]
= [tex]$ 58 ^{\circ}$[/tex] from x-axis
What is the threshold velocity vthreshold(water) (i.e., the minimum velocity) for creating Cherenkov light from a charged particle as it travels through water (which has an index of refraction of n
Complete Question
The complete question is shown on the first uploaded image
Answer:
A
[tex]v_w = 2.256 *10^{8} \ m/s[/tex]
B
[tex]v_e = 2.21 *10^{8} \ m/s[/tex]
C
The correct option is B
Explanation:
From the question we are told that
The refractive index of water is [tex]n_w = 1.33[/tex]
The refractive index of ethanol is [tex]n_e = 1.36[/tex]
Generally the threshold velocity for creating Cherenkov light from a charged particle as it travels through water is mathematically evaluated as
[tex]v_w = \frac{c}{n_w }[/tex]
Where c is the speed of light with value [tex]c = 3.0 *10^{8} \ m/s[/tex]
[tex]v_w = \frac{3.0 *10^{8}}{1.33 }[/tex]
[tex]v_w = 2.256 *10^{8} \ m/s[/tex]
Generally the threshold velocity for creating Cherenkov light from a charged particle as it travels through water is mathematically evaluated as
[tex]v_e = \frac{ c}{n_e }[/tex]
=> [tex]v_e = \frac{3.0 *10^{8}}{1.36 }[/tex]
=> [tex]v_e = 2.21 *10^{8} \ m/s[/tex]
How many time constants must elapse if an initially charged capacitor is to discharge 90% of its stored energy through a resistor
Answer:
t = log9/10 x RC
Explanation:
Let's say initial energy is
E= 1/2Q²/C
But if 90% is discharged what will be remaining will be
E= E"/100= 1/2Q²/C
So if we divide the first by the second equation we have
Q'= Q/10
Then using
q=q0(1-e^-t /RC)
So that
Q= Q/10(1-e^-t /RC)
t/RC= log9/10
So t = log9/10 x RC
Convert the number from scientific into standard notation: 5.9 x 10-2
Which of the following situations describes static friction? a. A heavy crate standing on a rough patch of mud and is being pushed by two workers, but they cannot get it to move b. A large piano resting on a sheet of ice is being pushed by a child, but the child is not strong enough to get it to move
Answer:
A.
Explanation:
The answer is A because the weight of the crate is sitting on something rough. The roughness is going to resist anything that tries to move against it because the force being exerted by the 2 workers is not strong enough to get the crate to move out of its place on the mud since it's static.
The answer can't be B because ice is smooth and doesn't have any friction, the little girl can't move it because it's to heavy for her to move, not because there's friction acting against it.
The resistance one encounters when attempting to move a stationary object over a surface without also moving their bodies in relation to the surface is known as static friction. Thus, option A is correct.
What the best situations describes static friction?An object cannot move down the path due to a force known as static friction. Two materials sliding over one another causes this friction. Conflict can be found everywhere around us. Consider how the ground is in contact with our feet when we walk.
When there is no relative motion between the object and the surface, a body is subjected to the effects of static friction. As a result, it can still act when the body is moving, but there shouldn't be any relative motion.
Therefore, Static friction slows the car down if the tire is moving so smoothly that the ground-contact surface is never slipping. Kinetic friction will cause the wheels to slow down if they are locked and sliding.
Learn more about Static friction here:
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three equal charges are fixed at the howdy corners of a rectangle what is the force on the top left charge from the bottom left
Answer:
Let the resultant be
A= ( C2 + B2 )1/2
So
sin = B / ( C2 + B2 )1/2
And
cos = C / ( C2 + B2 )1/2
So the total force is
F = FA + FC + FY
= - k y2 i / c2 + k y2 j / B2 + k y Q ( -cos i + sin j ) / ( C2 + B2 )
F = 0
- k y2 i / C2 + k y2 j / B2 + k y Q ( -sin i + sin j ) / ( L2 + H2 ) = 0
- k y2 i / C2 + k y2 j / B2 + k y Q ( - C / ( C2 + B2 )1/2 i + B/ ( C2+ B )1/2 j ) / ( C2 + B2 )1/2 = 0
Q = - y ( C2 + B )3/2 / C3
k y2 / B2 + k y Q B/ ( C2 + B2 )3/2 = 0
Q = -y ( C2 + b2 )3/2 / B
So equating both " Q " values
- y ( C2 + B2 )3/2 / L3 = - y( C2 + B2 )3/2 / B
so the possible length and the relationship is C= B
The pressure gauge on a tank registers the gauge pressure, which is the difference between the interior pressure and exterior pressure. When the tank is full of oxygen (O2), it contains 11.0 kg of the gas at a gauge pressure of 35.0 atm. Determine the mass of oxygen that has been withdrawn from the tank when the pressure reading is 19.4 atm. Assume the temperature of the tank remains constant.
Answer:
mass of oxygen that has been withdrawn from the tank = 4.77 kg
Explanation:
We are given;
Initial mass of oxygen gas;m1 = 11 kg
Initial gauge pressure;p'1 = 35 atm
Final gauge pressue;p'2 = 19.4 atm
Now, for thia question we cannot use gauge pressure but absolute pressures.
Thus, formula for absolute pressure = gauge pressure + external atmospheric pressure.
External atmospheric pressure = 1 atm.
Thus;
P1 = 35 + 1 = 36 atm
P2 = 19.4 + 1 = 20.4 atm
Now, formula for ideal gas equation is;
PV = nRT = (m/M)RT
Where;
m is mass of gas
M is molar mass of gas
R is gas constant
T is temperature
Thus, for state 1,we have;
P1 × V1 = (m1/M)RT1 - - - (eq 1)
For state 2,we have;
P2 × V2 = (m2/M)RT2 - - - - - (eq 2)
Divide equation 1 by equation 2 to give;
(P1 × V1)/(P2 × V2) = (m1 × T1)/(m2 × T2)
The gas remains confined in the tank, thus, V1 = V2
Also, the temperature is constant, thus T1 = T2.
Thus, V1 & V2 and also T1 & T2 will cancel out to give;
P1/P2 = m1/m2
Since we are looking for the mass of oxygen( Δm) that has been with withdrawn from the tank, we have to rewrite the equation to accommodate Δm. Now, Δm is simply m1 - m2
Thus,
From P1/P2 = m1/m2, we have;
P1/P2 = m1/(-(m1 - m2) + m1)
This gives;
P1/P2 = m1/(m1 - Δm)
Cross multiply to get;
(m1 - Δm)(P1/P2) = m1
Cross multiply to get;
m1 - Δm = (P2/P1)m1
Δm = m1 - (P2/P1)m1
Δm = m1(1 - (P2/P1))
Plugging in the relevant values to get;
Δm = 11(1 - (20.4/36))
Δm = 4.77 kg
Based on your answer to the previous question (bullet embeds in block), what type of collision would you classify the bullet-block impact?
Answer:
An inelastic collision.
Explanation:
When a bullet impacts on the block, and is embedded in the block, the bullet-block system moves away together, with a single velocity together. This is called "an inelastic collision"
In this type of collision, only the momentum of the system is conserved.
If the voltage across the plates is increasing at the rate of 220 V/s, what is the displacement current in the capacitor
Complete Question
A parallel-plate capacitor has square plates 20 cm on a side and 0.50 cm apart. If the voltage across the plates is increasing at the rate of 220 V/s, what is the displacement current in the capacitor?
Answer:
The value is [tex]I = 1.416*10^{-8} \ A[/tex]
Explanation:
From the question we are told that
The length and breath of the square plate is [tex]l = b = 20 \ cm = 0.2 \ m[/tex]
The distance of separation between each plate is [tex]k = 0.50 \ cm = 0.005 \ m[/tex]
The rate of voltage increase is [tex]\frac{dV}{dt} = 200 \ V/s[/tex]
Generally the charge on the plate is mathematically represented as
[tex]Q = CV[/tex]
Now C is the capacitance of the capacitor which is mathematically represented as
[tex]C = \frac{\epsilon_o * A}{k}[/tex]
Here A is the cross-sectional area which is mathematically represented as
[tex]A = l^2[/tex]
=> [tex]A = 0.2^2[/tex]
=> [tex]A = 0.04 \ m^2[/tex]
So
[tex]C = \frac{8.85 *10^{-12} * 0.04}{0.005}[/tex]
[tex]C = 7.08*10^{-11} \ F[/tex]
Now the change of the charge flowing through the plates with time is mathematically represented as
[tex]\frac{d Q}{dt} = C \frac{dV}{dt}[/tex]
So
[tex]\frac{d Q}{dt} = 7.08 *10^{-11} * 200[/tex]
[tex]\frac{d Q}{dt} = 1.416*10^{-8}[/tex]
Generally [tex]\frac{d Q}{dt} = \ current \ i.e \ I[/tex]
So
[tex]I = 1.416*10^{-8} \ A[/tex]
How much would it cost to cover the entire land area of the U.S. in dollar bills?
How much would it take to cover the entire land area of the U.S. in dollar bills?
The contiguous United States can be approximated as a rectangle that measures 1000 x 3000 miles, while Alaska has about 1/5 of the area of the contiguous U.S. Ignore Hawaii for this calculation. Also note that the dollar bill measures roughly 6.5cm x 15.5cm.
How much would it cost to cover the entire land area of the United States?
*Round your answer to one significant figure*
Answer:
$900 trillion
Explanation:
If Alaska is 20% of the contiguous US, then the approximate area of interest is ...
1200 miles × 3000 miles = 3.6×10^6 square miles.
The size of a dollar bill is about ...
(6.5 cm)·(15.5 cm) = 100.75 cm^2
One mile is 160,934.4 cm, so 1 square mile is about ...
1 mi^2 = (160,934.4 cm)^2 ≈ 2.59·10^10 cm^2
The number of dollars of interest is then ...
(3.6 · 10^6 mi^2)(2.59 · 10^10 cm^2)/(100.75 cm^2) ≈ 9.3·10^14
≈ 930 × 10^12 . . . dollars
It would cost about 900 trillion dollars to cover the land area of the US in $1 bills.
If the maximum acceleration that is tolerable for passengers in a subway train is 1.39 m/s2 and subway stations are located 780 m apart, what is the maximum speed a subway train can attain between stations
Answer:
The maximum speed a subway train can attain between stations is 32.93 m/s.
Explanation:
Given;
maximum tolerable acceleration = 1.39 m/s²
distance between subway train, d = 780 m
The distance available to accelerate between stations = ¹/₂ x 780 m = 390 m
Apply the following kinematic equation to determine the maximum speed;
v² = u² + 2ad
v² = 0 + 2ad
v² = 2(1.39)(390)
v² = 1084.2
v = √1084.2
v = 32.93 m/s
Therefore, the maximum speed a subway train can attain between stations is 32.93 m/s.
On a straight road (taken to be in the x direction) you drive for an hour at 60 km per hour, then quickly speed up to 120 km per hour and drive for an additional two hours. What is your average x component of velocity
Answer:
The average velocity is 180 km/hr
Explanation:
Given;
initial velocity, u = 60 km per hour
final velocity, v = 120 km per hour
initial time = 1 hour
final time = 2 hour
Initial position = 60 km/h x 1 hour = 60 km
final position = 120 km/h x 2 hour = 240 km
The average velocity is given by;
[tex]V_{avg} = \frac{Final \ position\ - \ Initial \ position}{final \ time\ - \ initial \ time}\\\\V_{avg} = \frac{240km \ - \ 60km}{2hr\ - \ 1hr} \\\\V_{avg} = \frac{180 \ km}{1hr} \\\\V_{avg}= 180 \ km/hr[/tex]
Therefore, the average velocity is 180 km/hr
Galileo drops a ball from the Leaning Tower of Pisa. Consider the ball's motion from the moment it leaves his hand until a microsecond before it hits the ground. Your diagram should be vertical.
Answer:
Following are the answer to this question:
Explanation:
Galileo claims that perhaps the air resistance is due to an object falling slower. The object gradually falls under its control of free-fall gravity.
A free-falling object is also an object, which is affected by gravity only. The object operated only by the gravitational force is considered to get into a condition of free fall and the Items, that fall free may not feel air resistance.
please find the attachment.
Use the graph to compare the three local teams that play in the summer basketball league. Predict which local team would have the best finish in a basketball tournament. Explain your answer.
Answer:
Sample Response: The Jaguars would probably have the best finish in a basketball tournament because they have won the most games every season.
Explanation:
Answer:
Sample Response: The Jaguars would probably have the best finish in a basketball tournament because they have won the most games every season.
Explanation:
As shown on the graph, the Jaguars had the most wins each season compared to the Wolves and the Hawks. In conclusion, you can predict that the Jaguars would probably have the best finish in a basketball tournament.
what do we have to take note of when completing a ray diagram?
Answer:
Marked image of the top of the object
A 54 kg pig runs at a speed of 1.0
What is the pig's kinetic energy?
Round answer to two significant digits.
Answer:
27 Joules.
Explanation:
use the formula for kinetic energy:
KE = 1/2mv^2
A 54 kg pig runs at a speed of 1.0 m/s.
What is the pig’s kinetic energy?
Answer: 27 J
A 3.0kg mass tied to a string
is swirled round with a uniform
speed of 20.0mls. If the length of
the string is 40cm Find the
tension in the string
Answer:
[tex] \boxed{\sf Tension \ in \ the \ string \ (T) = 3 \ kN} [/tex]
Given:
Mass (m) = 3.0 kg
Uniform speed (v) = 20 m/s
Length of string (r) = 40 cm = 0.4 m
To Find:
Tension in the string (T)
Explanation:
Tension (T) is the string will be equal to centripetal force ([tex] \sf F_c [/tex]).
[tex] \boxed{ \bold{ T = F_c = \frac{m {v}^{2} }{r} }}[/tex]
Substituting value of m, v & r in the equation:
[tex] \sf \implies T = \frac{3 \times {20}^{2} }{0.4} \\ \\ \sf \implies T = \frac{3 \times 400}{0.4} \\ \\ \sf \implies T =3 \times 1000 \\ \\ \sf \implies T =3000 \: N \\ \\ \sf \implies T =3 \: kN[/tex]
[tex] \therefore[/tex]
Tension in the string (T) = 3 kN
A 12-V DC automobile head lamp is to be used on a fishing boat with a 24-V power system. The head lamp is rated at 50 W. A resistor is to be connected in series with the lamp to permit it to operate on 24 V. What should be the resistance and power rating of the resistor?
Answer:
The resistance is [tex]R = 2.88 \ \Omega[/tex]
Explanation:
From the question we are told that
The voltage rating of the headlamp is [tex]V_1 = 12 \ V[/tex]
The voltage of the power system is [tex]p = 24 \ V[/tex]
The power rating of the headlamp is [tex]P = 50 W[/tex]
Generally the power which the resistor dissipates is mathematically represented as
[tex]P = V_L * I[/tex]
=> [tex]50 = 12 * I[/tex]
=> [tex]I = 4.1667 \ A[/tex]
Generally the resistance is
[tex]R = \frac{V_1 }{I}[/tex]
[tex]R = \frac{12 }{4.1667}[/tex]
[tex]R = 2.88 \ \Omega[/tex]
7. A local sign company needs to install a new billboard. The signpost is 30 m tall, and the ladder truck is parked 24 m away from the bottom of the post due to an uneven ravine. How long must the ladder be in order to reach the top of the signpost from the ladder truck?
Here ,
• Height of sign post = 30 m
• Distance between signpost and truck = 24 m
Let the
• Top of signpost = A
• Bottom of signpost = B
• The end of truck facing sign post be = C
Now as we can clearly imagine that the ladder will act as an hypotenuse to the Triangle ABC .
Where
• AB = Height of signpost = 30 m
• BC = distance between both = 24 m
• AC = Minimum length of ladder
→ AC² = AB² + BC² ( As we can see AB is perpendicular to BC )
→ AC² = (30)² + (24)²
→ AC² = 900 + 576
→ AC² = 1476
→ AC = 38.41875
or AC apx = 38.42
So minimum height of ladder = 38.42
This question can be solved by using the formula of "Pythagora's Theorem".
The ladder must be "38.42 m" long.
If we imagine the whole situation in terms of a right-angled triangle, we can safely assume the height of the billboard (which is the pole supporting the billboard) as the perpendicular of the right-angled triangle. The distance between the signpost and the truck can be assumed as the base of the triangle. The length of the ladder will then be acting as the Hypotenuse of the right-angled triangle.
The attached picture clearly depicts the condition explained in the above paragraph.
Now applying Pythagora's Theorem to this situation, we get:
[tex]Hypotenuse^2 = Perpendicular^2+Base^2\\Length\ of\ Ladder^2 = (30\ m)^2+(24\ m)^2\\L^2 = 1476\ m^2\\[/tex]
L = 38.42 m
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A baseball has a mass of about 155 g. What is the magnitude of the momentum of a baseball thrown at a speed of 86 miles per hour
Answer:
Magnitude of the momentum (P) = 5.96 Kg.m /s (Approx)
Explanation:
Given:
Mass of baseball (m) = 155 gram = 0.155 kg
Velocity (v) = 86 miles/ hour
Find:
Magnitude of the momentum (P)
Computation:
1 mile = 1,609.344 meters
So,
Velocity (v) = 86 × (1,609.344 / 3600)
Velocity (v) = 38.45 m/s
Magnitude of the momentum (P) = mv
Magnitude of the momentum (P) = (0.155)(38.45)
Magnitude of the momentum (P) = 5.96 Kg.m /s (Approx)
Please give an example of a scenario with distance and displacement.
Answer:
distance means the length of any thing that have one starting point mad ending point
displacement means the short distance that move by an object due to help of any force
Answer:
there is examples and defination for distance and displacement
You fly east in an airplane for 100 km. You then turn left 60 degrees and fly 200 km. In what direction are you from the starting point
Answer:
North east
Explanation:
r_1 = 100 i
r_2 = 200 (cos60i + sin60j) = 100i + 173.2j
By vector addition
r = r_1 + r_2 = 200i + 173.2j
Distance (Or magnitude) = sqrt(200^2 + 173.2^2) = 264 km
Direction from the starting point is north of east.
average wavelength of radio waves
Answer:
Radio waves have frequencies as high as 300 gigahertz(GHz)to as low as 30 hertz(Hz).At 300 GHz the corresponding wavelength is 1mm and at 30Hz is 10,000 km
The average wavelength of radio waves ranges from roughly two millimeters to more than 150 kilometers. The wavelengths of radio waves are the longest in the electromagnetic spectrum
What is Wavelength?It can be understood in terms of the distance between any two similar successive points across any wave for example wavelength can be calculated by measuring the distance between any two successive crests.
It is the total length of the wave for which it completes one cycle.
The wavelength is inversely proportional to the frequency of the wave as from the following relation.
C = νλ
They also have the lowest frequencies, ranging from around 4,000 cycles per second, or 3 kilohertz, to roughly 280 billion hertz, or 280 gigahertz.
The wavelengths of radio waves are the longest in the electromagnetic spectrum, ranging from roughly two millimeters to more than 150 kilometers.
To learn more about wavelength from here, refer to the link given below;
brainly.com/question/7143261
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