Find the value of .x.
(5r-24)
(8x + 9)-

The fraction of the patients that have a waiting time of more than 7 minutes found by using the area under the curve is 269/312

A fraction indicates the quantitative comparison showing the number of times one quantity is contained in another quantity.

The area under the frequency curve is found as follows;

Dividing the area into composite shapes of a rectangle, triangle and trapezoid, we get;

(9.2 - 5.5) × 4 + (4 + 2)×3/2 + (2.5 + (9.2 - 5.5)) × 1/2 + (2.5 + 1.2) × 2/2 + 1.2 × 1/2 = 31.2

The area for those that have a waiting time of more than 7 minutes is therefore;

(9.2 - 5.5) × 4 + (4 + 2)×3/2 + (2.5 + (9.2 - 5.5)) × 1/2 = 26.9

The fraction that have a waiting time of more than 7 minutes is therefore;

26.9/31.2 = 269/312  ≈ 0.862

The fraction of the patients that have a waiting time of more than 7 minutes is 269/312

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Answer:

x=19/24

Step-by-step explanation:

3/8=15/5x-2

3/8= 3x -2 |*8

3=24x-16

24x=19

x=19/24

Answer:

B is never true

Step-by-step explanation:

you can't get a negative number when you have a even power

Answer:

The correct equation is t = 12.25h.

The way the decrease in confidence affect the sample size​ required is: A. Decreasing the confidence level decreases the sample size needed.

Using this formula to find the decrease in sample size

n = [zs/E]^2

Where:

n = Sample size

zs = z-score

E=  margin of error

Confidence coefficient for 99% = 2.58

Hence,

2.58 × 13.8/sqrt(n) = 0.04

2.598 × 13.4 /0.04 = sqrt(n)

( 2.598× 13.8 /0.04)^2  = n

n=803,371.6

So,

Confidence coefficient for 90% = 1.64

n= (1.64× 13.8/0.04)^2

n =320,129.64

Therefore the correct option is A.

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The complete question is:

A doctor wants to estimate the mean HDL cholesterol of all​ 20- to​ 29-year-old females. How many subjects are needed to estimate the mean HDL cholesterol within 4 points with 99% confidence assuming S=13.8 based on earlier​ studies? Suppose the doctor would be content with 90 confidence. How does the decrease in confidence affect the sample size​ required?

How does the decrease in confidence affect the sample size required

A. Decreasing the confidence level decreases the sample size needed.

B. The sample size is the same for all levels of confidence.

C. Decreasing the confidence level increases the sample size needed.

Answer:

x=−5+ 21 ,−5− 21

Step-by-step explanation:

x= 4−20+4= 214−20−4 =21

​

​

Answer:

$26

Step-by-step explanation:

Answer:

$4.90

Step-by-step explanation:

He already has $13.70 (7.40+6.30) saved up so you have to subtract that from 18.60 to find the total Ace needs to save up.

18.60-13.70=4.90

To check your answer, you can add 7.40, 6.30, and 4.90 and see if you get a total of 18.60.

Check: 7.40+6.30+4.90=18.60

Answer:

$ 1.38

Step-by-step explanation:

5.50 ÷ 4 = 1.375. rounded to 2 dp: 1.38

She paid $1.375 per pound of strawberries.

What is the unit rate?

When expressed rate as a fraction, a unit rate has a denominator of 1.

Since 4 pounds cost $5.50, 1 pound of strawberries will cost 5.50/ 4 ≈ $1.375.

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Using simple mathematical operations, David's overall loss is -5.8.

So, the overall gain/loss of David is:

Now, calculate loss/gain as follows:

Therefore, using simple mathematical operations, David's overall loss is -5.8.

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The confidence interval that we have for the population mean is given as [869.9 , 890.7]

The confidence interval is the range of values that, if you repeated your experiment or resampled the population in the same manner, you would anticipate your estimate to fall within a specific proportion of the time.

We have the following data that we have to solve this problem with

The mean = x¯=880.3 pounds

The standard deviation = 10.4 pounds.

The confidence interval = 68%

To get the confidence interval for the true mean of the population weight we would have

mean ± standard deviation

880.3 ± 10.4

The interval would be written out as

880.3 - 10.4 and 880.3 + 10.4

the confidence interval =

[869.9 , 890.7]

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Using the simplification, the equivalent expression of 2.1+(–3.7h)+1.9h–1.4 is 0.7–1.8h.

In the given question we have to find the equivalent expression of the given expression.

The given expression is 2.1+(–3.7h)+1.9h–1.4

Now solving the given expression to find the equivalent expression.

Now solving the expression

=2.1 + (–3.7h) + 1.9h – 1.4

Firstly simplifying the bracket

=2.1–3.7h+ 1.9h – 1.4

=(–3.7h+ 1.9h)+(– 1.4+2.1)

= –1.8h + 0.7

We can write it as

=0.7–1.8h

Hence, the equivalent expression of 2.1+(–3.7h)+1.9h–1.4 is 0.7–1.8h.

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Answer:

US$1.00=EC$2.70 TT$1.00=EC$0.40 calculate the value of : 1.EC$1in TT$ 2.US$80inEC$ 3.TT$648 in US$

Step-by-step explanation:

that what i've got is that I hope that helps you

The two possible solutions of the given quadratic equation are -

x =  +√6 +5 and x =  -√6 +5

For the given question;

(x - 5)² - 6 = 0

Bring constant on other side.

(x - 5)² = 6

Taking square root both side.

√ (x - 5)² = √6

(x - 5) = ±√6

Separate the constant and variables.

x =  ±√6 +5

There are two possible solution.

x =  +√6 +5 and x =  -√6 +5

Thus, the two possible solutions of the given quadratic equation are -

x =  +√6 +5 and x =  -√6 +5.

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The equation of the relationship is 2x + 4y = 45 and the graph is attached

From the question, we have the following parameters:

This means that

Price of each drink = Half $4

Evaluate

Price of each drink = $2

Represent the number of drinks with x and the number of bucket of popcorn with y

So, we have the following representation

Total amount of popcorn + Total amount of drinks = Total amount

This gives

2x + 4y = 45

Next, we sketch the graph

See attachment for the graph of the equation

The graph is represented by a straight line

This means that it is a linear equation

Also, the graph touches the axes at (0, 11.25) and (22.5, 0)

This means that the highest number of drinks and buckets are 11.25 and 22.5 respectively

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24.

[tex](6x+3y)-\frac{z^{2}}{(2x)}[/tex]

[tex](6(3)+3(4))-\frac{(6)^{2}}{(2(3))}[/tex]

a) Solve parenthesis.

[tex](18+12)-\frac{(6)^{2}}{6}\\ \\30-\frac{(6)^{2}}{6}[/tex]

b) Solve the exponent.

[tex]30-\frac{36}{6}[/tex]

c) Divide.

[tex]30-6[/tex]

d) Subtract.

[tex]24.[/tex]

Answer:

Area =  l × w

=  2 × 0.875

=  1 3/4 yd^2 or 1.75 yd^2

hope i helped

Step-by-step explanation:

Answer:

See below

Step-by-step explanation:

I think you may have left some info out of your question post, but here is something that may help you:

x = walk speed    km/hr

x + 5 = run speed     km/hr

45 min = 3/4 hr  = .75 hr

(.75)(x+5)      +      3 * x   = total distance   in  km

3.75x + 3.75 = total distance

Answer:

100π = 314.1592654

Step-by-step explanation:

area of a circle πr²

π×10²

10×10 =100

100×π

The result of the expression as given in the task content is; 750/π.

It follows from the task content that the result of the division operation as given in the task content is to be determined.

Given the expression; 1000 ÷ (4/3)π

The expression can therefore be rewritten as follows;

1000 × (3/4) π

Hence, we have;

3000/4π

By further simplifying the expression; we have;

750/π

Hence, the result of the division as given in the task content is; 750/π.

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Answer:

50 gallons

Step-by-step explanation:

6400 ÷ 128

= 50

Answer: purple is the greatest

Using the system of equations and use the elimination method the two numbers are 82 and 48.

What is the elimination method?

To create an equation in one variable using the elimination approach, you can either add or subtract the equations. To eliminate a variable, add the equations when the coefficients of one variable are in opposition, and subtract the equations when the coefficients of one variable are equal.

Here, we

let the first number = x

let the second number = y

according to the given conditions:

x + y = 130 ........(1)

x - y = 34 .........(2)

Using the elimination method we add both equations (1) and (2) and we get

2x = 164

x = 164/2 = 82

Now, we substitute the value of x in eq (1) and we get

82 + y = 130

y = 130-82

y = 48

Hence, using the system of equations and use the elimination method the two numbers are 82 and 48.

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