help please precalc will give brainliest

Answer:

P-value = 0.0455

Step-by-step explanation:

In this question, we are concerned with calculating the P- value in a test.

Mathematically we know that;

P-value = 2 * P(Z > |z|)

Please check attachment for complete solution and by step explanation

Answer:

Step-by-step explanation:

[tex]xy^{2}[/tex],   [tex]5y^{2}x[/tex],   [tex]\frac{-3}{5}[/tex][tex]xy^{2}[/tex]

[tex]-3x^{2}y[/tex],   [tex]\frac{2}{3}[/tex][tex]yx^{2}[/tex]

Hope this helps

plz mark it as brainliest!!!!!

Answer:

Stratified Random sampling.

Step-by-step explanation:

As per the scenario, It is stratified random sampling as it divides students into strata which represent Sophomores, Juniors, and Seniors.

Simple random samples of the given sizes of the proportional to the size of the stratum which is to be taken from every stratum that is to be about 10 percent of students from every class that is selected here.

Hence, according to the given situation, the correct answer is a random stratified sampling.

Answer:

Cube C

Step-by-step explanation:

[tex]{ \sf{because \: it \: is \: identical}}[/tex]

The value of g + 100 is 150.

Given that,

The average of g and 100 is 75.

And we have to determine the value of g + 100.

So that means

The arithmetic mean of g and 100 is 75.

So, mathematically it should be

[tex]\frac{g + 100}{2} = 75\\\\[/tex]

So, g + 100 = 150

Therefore we can conclude that the value of g + 100 is 150

Learn more about the mean here: brainly.com/question/11230531

Answer:

the answer is d i believe.

Answer:

The answer is D I took the test the other person is right!

Step-by-step explanation:

Answer:

A large box weighs 18.5 kilograms and a small box weighs 15.5 kilograms

Step-by-step explanation:

Create a system of equations where l is the weight of one large box and s is the weight of one small box.

2l + 12s = 223

5l + 3s = 139

Solve by elimination by multiplying the bottom equation by -4:

2l + 12s = 223

-20l - 12s = -556

Add these together and solve for l:

-18l = -333

l = 18.5

So, a large box weighs 18.5 kilograms. Plug in 18.5 as l into one of the equations, and solve for s:

5l + 3s = 139

5(18.5) + 3s = 139

92.5 + 3s = 139

3s = 46.5

s = 15.5

A large box weighs 18.5 kilograms and a small box weighs 15.5 kilograms.

9514 1404 393

Answer:

Step-by-step explanation:

Two equations for the total weight can be written in general form as ...

  2L +12S -223 = 0

  5L +3S -139 = 0

These can be solved using the "cross multiplication method" by computing three differences:

  d1 = (2)(3) -(5)(12) = 6 -60 = -54

  d2 = (12)(-139) -(3)(-223) = -1668 +669 = -999

  d3 = (-223)(5) -(-139)(2) = -1115 +278 = -837

Then the weighs of the boxes are ...

  1/d1 = L/d2 = S/d3

  L = d2/d1 = -999/-54 = 18.5

  S = d3/d1 = -837/-54 = 15.5

The large box weighs 18.5 kg; the small box weighs 15.5 kg.

_____

Additional comment

If the coefficients are written in two rows of four numbers, with the first repeated at the end, the pattern of differences can be seen to be (ad -cb) for [a, b] in the first row and [c, d] in the second row of a pair of adjacent columns. This method of solution is fully equivalent to solution using Cramer's Rule for a system of equations represented by a matrix equation.

Step-by-step explanation:

[tex]thank \: you[/tex]

Answer:

20x⁵⁰

Step-by-step explanation:

With the equation √400x¹⁰⁰

we need to take the square root away separately

√400 = √20*20 = 20

Then with x¹⁰⁰

√x¹⁰⁰ = √x⁵⁰*x⁵⁰ = x⁵⁰

So √400x¹⁰⁰ = 20x⁵⁰

hope this helps

Answer:

b=a/2

c=a/2

b=c

a=2b and a=2c

Answer:

i [tex]\to[/tex] a

    [tex]n = 96040000[/tex]

i [tex]\to[/tex] b

    [tex]n_1 =24010000[/tex]

i [tex]\to[/tex] c

    [tex]n_2 =41602500[/tex]

ii[tex]\to[/tex]a

     [tex]E = 58.16[/tex]

ii[tex]\to[/tex]b

    [tex]291.84 < \mu < 408.16[/tex]\

ii[tex]\to[/tex]c

    There is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval

Step-by-step explanation:

From the question we are told that

     The sample size is [tex]n = 8[/tex]

      The sample mean is  [tex]\= x = \$ 350[/tex]    

      The sample standard deviation is  [tex]\$ 100[/tex]

Considering question i

    i [tex]\to[/tex] a

         At   [tex]E = 0.02[/tex]  

given that the confidence level is 95%  =  0.95

         the level of significance would be  [tex]\alpha =1-0.95 = 0.05[/tex]

The critical value of  [tex]\frac{\alpha }{2}[/tex] from the normal distribution table is  

        [tex]Z_{\frac{ \alpha }{2} } = 1.96[/tex]

So  the sample size is mathematically evaluated as

            [tex]n = [ \frac{Z_{\frac{\alpha }{2} } * \sigma }{E} ]^2[/tex]

=>        [tex]n =[ \frac{ 1.96 * 100}{ 0.02} ]^2[/tex]

=>         [tex]n = 96040000[/tex]

 i [tex]\to[/tex] b

  At  [tex]E_1 = 0.04[/tex]    and  confidence level  = 95%  =>  [tex]\alpha_1 = 0.05[/tex]   =>  [tex]Z_{\frac{\alpha_1 }{2} } = 1.96[/tex]

             [tex]n_1 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_1} ]^2[/tex]

=>           [tex]n_1 =[ \frac{ 1.96 * 100}{ 0.04} ]^2[/tex]

=>           [tex]n_1 =24010000[/tex]

 i [tex]\to[/tex] c

       At   [tex]E_2 = 0.04[/tex]     confidence level  = 99%  =>    [tex]\alpha_2 = 0.01[/tex]

The critical value of  [tex]\frac{\alpha_2 }{2}[/tex] from the normal distribution table is  

        [tex]Z_{\frac{ \alpha_2 }{2} } = 2.58[/tex]

=>    [tex]n_2 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_2} ]^2[/tex]

=>    [tex]n_2 =[ \frac{ 2.58 * 100}{ 0.04} ]^2[/tex]

=>    [tex]n_2 =41602500[/tex]

Considering ii

Given that the level of significance is  [tex]\alpha = 0.10[/tex]

Then the critical value  of  [tex]\frac{\alpha }{2}[/tex] from the normal distribution table is  

           [tex]Z_{\frac{\alpha }{2} } = 1.645[/tex]

Generally the margin of error is mathematically represented as

          [tex]E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }[/tex]

substituting values

         [tex]E = 1.645 * \frac{100 }{\sqrt{8} }[/tex]

         [tex]E = 58.16[/tex]

Generally the 90% confidence interval is mathematically evaluated as

         [tex]\= x - E < \mu < \= x + E[/tex]

=>      [tex]350 - 58.16 < \mu < 350 + 58.16[/tex]

=>     [tex]291.84 < \mu < 408.16[/tex]

So the interpretation is that there is 90% confidence that the mean  fee charged to H&R Block customers last year is in the interval .So there is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval.

Answer: about 40.54°

Step by step explanation:

7^2 =  5^2 + 10^2  - 2(5)(10)cos(B)

cos(B)  = (7^2 - 5^2 - 10^2) / (-2(5)(10) )

B = cos-1 [ (7^2 - 5^2 - 10^2) / (-2(5)(10) ]  =  cos-1 (.76) = about 40.54°

Answer:

It's 28 3/4

Step-by-step explanation:

Answer:

Answer is 19.5

Step-by-step explanation:

27-9+(12-5)÷4

27-9+6÷4   [BOD MAS Rule]

27-9+1.5

28.5-9

19.5

Answer:

1. confidence interval = (0.163, 7.237)

1. confidence interval = (0.163, 7.237)2. t = 2.366

1. confidence interval = (0.163, 7.237)2. t = 2.3663. critical value of one tailed test = 1.833

Step-by-step explanation:

before after    dt(before - after)   d²

74         73          1                            1

83         77           6                          36

75         70          5                          25

88         77           11                         121

84         74           10                         100

63         67           -4                         16

93          95         -2                           4

84         83           1                            1

91           84          7                           49

77           75          2                          4

∑dt = 37    

d* = 37/10

since sample space = 10

d* = 3.7

s.d from the question = 4.95

df = 10 - 1 = 9

critical value at 0.05 significance

t(0.025 at df of 9) = ±2.262

marginal error computation:

= (2.262) × (4.945/√10)

= 2.262 × 1.5637

= 3.5370

confidence interval CI = d* + marginal error

= 3.7 ±3.5730

= (0.163, 7.237)

The logic course give an improvement on abstract reasoning. The confidence interval shows that the result is significant.

H₀: Цd = 0

H₁: Цd > 0

∝ = 0.05

t = (3.7 - 0)/(4.945/√10)

t = 3.7/1.564

t = 2.366

for a right tailed test at 0.05 significance, and df of 9, the critical value is 1.833

please refer to the attachment to see the rejection region.

Answer:

To solve for a, you will need to get that variable alone on one side. First you will multiply each side by variable b. This will give you the equation pb = 3a + 4. Next you subtract 4 from each side. This puts it at pb - 4 = 3a. After that you’ll divide both sides by 3 and get a alone. This gives you (pb - 4)/3 = a or, if you switch it around, a = (pb - 4)/3. This is the simplest form when solving for a in this equation.

Answer:

Hello,

All my sentences will be written in mathematical language.

Step-by-step explanation:

[tex]p=\dfrac{3a+4}{b} \\\\p*b=3a+4 \ :\ \forall\ x,y,z\in\mathbb{R},z\neq 0:x=y\Longleftrightarrow\ x*z=y*z\\\\p*b-4=3a \ :\forall\ x,y,z\in\mathbb{R} :x=y\Longleftrightarrow\ x+z=y+z\\\\\dfrac{p*b-4}{3} =a \ :\forall\ x,y,z\in\mathbb{R},z\neq 0:x=y\Longleftrightarrow\ x*z=y*z\\\\a=\dfrac{p*b-4}{3} \ :\forall\ x,y\in\mathbb{R}:x=y\Longleftrightarrow\ y=x[/tex]

The mass density in kg/m3 will be -  15 x [tex]10^{-2}[/tex] Kg/m3.

We have a 100.0 m long polymer cable of uniform circular cross section and of diameter 0.4cm has a mass of 1885.0 gm.

We have to determine its mass density in kg/m3.

The amount of mass per unit volume present in the body is called its mass density.

According to question, we have -

Length of polymer cable = 100.0 m

diameter of polymer cable = 0.4 cm = 0.004 m

Therefore, its radius = 0.002 m

The mass density of the wire will be -

[tex]\rho =\frac{m}{\pi r^{2} l}[/tex]

[tex]\rho[/tex] = [tex]\frac{1885}{3.14 \times0.002 \times 0.002 \times 100 }[/tex]

[tex]\rho = \frac{1885}{0.001256}[/tex] = 1500796.1 g/m3

1 Kg = 1000g

1g = 1/1000kg

1500796.1g = 1500.7 Kg = 15 x [tex]10^{-2}[/tex] Kg

Therefore, mass density = 15 x [tex]10^{-2}[/tex] Kg/m3

Hence, the mass density in kg/m3 will be -  15 x [tex]10^{-2}[/tex] Kg/m3.

To solve more questions on mass density, visit the link below -

https://brainly.com/question/4893600

#SPJ2

Answer:

L = 29,550 mm

Step-by-step explanation:

i think i've done this before.. but anyway Lets make it simple and easy.

Let A = 600mm

Let B = 300mm

Let C = 16 as number turns

Let d = 20mm

L = sqrt ((3.14 * (600 - 20))² + 300³)    * 16

L = 29,550 mm

Answer:

[tex]x^6 - \frac{7x^5}{5} - 3x^3 + C[/tex]

[tex]10[/tex] divisions between $15.59$ and $15.6$ so each division is $\frac{15.60-15.59}{10}=0.001$

A is 5 division from $15.59$, so, A is $15.59+5\times 0.001=15.595$

similarly, C is 4 division behind $15.59$ so it is $15.590-4\times0.001=15.586$

and B is $15.601$

Answer:

3 s'mores

Step-by-step explanation:

If we center our attention on how many marshmallows you need per s'more which is 2 and you only have 7 you can only make 3 with one marshmallow remaining.

Answer:

120 ways

..................

Answer:

24

Step-by-step explanation:

4  friends

1st seat: 4 different people could sit here

Now there are 3 friends left

2nd seat: 3 different people could sit here

Now there are 2 friends left

3rd seat: 2 different people could sit here

Now there are 1 friends left

4th seat: 1 different people could sit here

4*3*2*1

24 ways

Answer:

(x + 3i) * (x - 3i) = x^2 + 3xi - 3xi - 9(i^2) = x^2 + 9

Step-by-step explanation:

Answer:

[tex]y+6=-\frac{1}{2} (x-3)[/tex]

Step-by-step explanation:

Since point-slope form is  [tex]y-y1=m(x-x1)[/tex], you have to plug in the values given to you to create the equation. The "y1" is the "y" coordinate given to us, while the x1 is the x coordinate given to us. So, you have to plug in the x and y coordinates, 3 and -6, into the equation. Since two negatives cancel out to be a positive, y--6= y+6. The "m" stands for the slope, so -1/2 is inserted into the equation, giving us  [tex]y+6=-\frac{1}{2} (x-3)[/tex].

Answer:

.kpokojj8nvchrfhuthuvu9jeuvh

Step-by-step explanation:

j8tguhrhfgzhedh8ugh8euweuhujdhhruehf hhcufe7fhd fu y in my as 08ygrt8hthts8hewhrs8h8h8

Answer:

[tex]L + \frac{5}{8} = 1[/tex]

Step-by-step explanation:

Given

A cup of coffee

Kelly drank 5/8 of the coffee

Required

Determine how much is left

Start by representing the amount of coffee left with L

Because the amount of coffee Kelly drank is in fraction (5/8), the total cup of coffee will equate to 1;

Hence, the addition equation as requested in the question to represent the scenario is

[tex]L + \frac{5}{8} = 1[/tex]

Answer:

[tex]Probability = \frac{3}{7}[/tex]

Step-by-step explanation:

Given

Electrician = 6

Mechanic = 8

Required

Determine the probability of selecting an electrician

First, we need the total number of employees;

[tex]Total = n(Electrician) + n(Mechanic)[/tex]

[tex]Total = 6 + 8[/tex]

[tex]Total = 14[/tex]

Next, is to determine the required probability using the following formula;

[tex]Probability = \frac{n(Electrician)}{Total}[/tex]

[tex]Probability = \frac{6}{14}[/tex]

Divide numerator and denominator by 2

[tex]Probability = \frac{3}{7}[/tex]

Hence, the probability of selecting an electrician is 3/7

Answer:

x=3

Step-by-step explanation:

● -3 (-4x+4) = 15 + 3x

Multiply -3 by (-4x+4) first

● (-3) × (-4x) + (-3)×(4) = 15 + 3x

● 12 x - 12 = 15 +3x

Add 12 to both sides

● 12x - 12 + 12 = 15 + 3x +12

● 12 x = 27 + 3x

Substract 3x from both sides

● 12x -3x = 27 + 3x - 3x

● 9x = 27

Dividr both sides by 9

● 9x/9 = 27/9

● x = 3

ANSWER: You can make 16 refrigerator magnets.

If you divide 10 by 5/8, you multiply by the reciprocal of 5/8 which is 8/5. You have 8/5 x 10. Cross simplify and you have 16.

hopefully this answer can help you to answer the next question

| - 4 | = 4

Thus :

f ( | - 4 | ) = f ( 4 )

f ( 4 ) = ( 4 )^2 - 2(4) + 4

f ( 4 ) = 16 - 8 + 4

f ( 4 ) = 16 + 4 - 8

f ( 4 ) = 20 - 8

f ( 4 ) = 12