I need ans for Q2, 5 and 7. QUICK PLEASE!!!

Answer:

u = [tex]\frac{r}{w+q}[/tex]

Step-by-step explanation:

Given

uw + uq = r ← factor out u from each term on the left side

u(w + q) = r ← divide both sides by (w + q)

u = [tex]\frac{r}{w+q}[/tex]

The equation uw + uq = r is solved for u will be written as u = r / (w + q).

The distribution of weights to the variables involved that establishes the equilibrium in the calculation is referred to as a result.

Making anything easier to accomplish or comprehend, as well as making it less difficult, is the definition of simplification.

The equation is given below.

uw + uq = r

Simplify the equation for u, then the equation will be written as,

uw + uq = r

u(w + q) = r

u = r / (w + q)

The equation uw + uq = r is solved for u will be written as u = r / (w + q).

More about the solution of the equation link is given below.

https://brainly.com/question/545403

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Answer:

The ratio of milk cartons drunk to total milk cartons put out= 3 : 5

Step-by-step explanation:

Total milk cartons put out for breakfast=100

Milk cartons left after breakfast=40

Total milk cartons drunk during breakfast = Total milk cartons put out for breakfast - Milk cartons left after breakfast

=100 - 40

=60

Total milk cartons drunk during breakfast = 60

What is the ratio of milk cartons drunk to total milk cartons put out?

Total milk cartons drunk during breakfast : Total milk cartons put out for breakfast

= 60 : 100

=3 : 5

The ratio of milk cartons drunk to total milk cartons put out= 3 : 5

Answer:

-7, -8, -9, -10

Step-by-step explanation:

Is this actually the whole problem? If so, the answer is anything less than -6. z < -6 includes all the numbers less than -6, so that would include -7, -8, -1000, -6.000001, etc.; you get what I mean. This would NOT include -6, though, because z is less than, not equal to, -6.

You can visualize it on a number line. If every value that could possibly equal z had a dot on it, you would see an infinite number of dots starting from -6 and going left to infinity. Like: <-------------o, if o was -6.

Please mark as Brainliest! :)

Answer:

D) x-3

Step-by-step explanation:

(4x+1)-(3x-4)=

4x-3x+1-4=

x-3

Answer:

the value of theta i 45°

Answer:

y=-12/137

Step-by-step explanation:

Answer:

[tex]y=\frac{4}{5}x[/tex]

Step-by-step explanation:

Equations in the given options are linear, so the table given represent a linear function.

Let the equation of the linear function is,

y = mx + b

Since this equation passes through (0, 0),

0 = m(0) + b

b = 0

Therefore, equation of the line will be,

y = mx

Slope of the line passing through (10, 8) and (5, 4),

m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

   = [tex]\frac{8-4}{10-5}[/tex]

   = [tex]\frac{4}{5}[/tex]

Therefore, equation of the line will be,

[tex]y=\frac{4}{5}x[/tex]

Option (2) will be the answer.

Answer:

7a) 5/8 cup

7b) 4  3/8 cup

Step-by-step explanation:

a) Divide 1 1/4 by 2:

Do this by putting the 1 into the fraction and then convert to 8th

1 1/4 = 5/4 = 10/8

(10/8)/2 = 5/8

b) 3 1/2 * 1 1/4 = 7/2 * 5/4 = 7*5/(2*4) = 35/8 = 4 3/8

Answer:

y = 11

Step-by-step explanation:

We use the definition of Supplementary Angles and Adjacent Angles.

Step 1: Set up equation 1 (Definition of Supplementary Angles)

5x - 4 +7x - 8 = 180

Step 2: Solve for x

12x - 4 - 8 = 180

12x - 12 = 180

12x = 192

x = 16

Step 3: Plug in x

5(16) - 4

80 - 4

76°

Step 4: Set up equation 2 (Definition of Supplementary Angles)

76 + 9y + 5 = 180

Step 5: Solve for y

9y + 81 = 180

9y = 99

y = 11

Answer:

60%

Step-by-step explanation:

57/95×100

hope this helps :)

Answer:

60%

Step-by-step explanation:

There is a total of 95 tickets, and 57 of them were early-admission tickets.

To find the percentage, we divide early-admission tickets by the total number of tickets, which is 57/95.

We can then simplify 57/95, getting 3/5, or 0.6, which is 60%.

Answer and Step-by-step explanation:

There are three reciprocal trigonometric functions

making a total of six including cosine, sine, and tangent.

→The reciprocal cosine function is secant: sec(Ф)=1/cos(Ф).

→The reciprocal sine function is cosecant, csc(Ф)=1/sin(Ф).

→The reciprocal tangent function is cotangent, expressed two ways: cot(Ф)=1/tan(Ф) or cot(Ф)=cos(Ф)/sin(Ф).

We've already learned the basic trig ratios:

sin(A) = a/c

cos(B) = b/c

tan(C) = a/b

But there are three more ratios to think about:

→Instead of  a/c, we can consider c/a  

​→Instead of  b/c, we can consider c/b  

→Instead of  a/b, we can consider b/a  

These new ratios are the reciprocal trigonometric ratios, and we’re about to learn their names.

The cosecant (csc)

The cosecant is the reciprocal of the sine. It is the ratio of the hypotenuse to the side opposite a given angle in a right triangle.

sin(A) = opp / hyp  = a/c

csc(A) = hyp / opp = c/a

The secant (sec)

The secant is the reciprocal of the cosine. It is the ratio of the hypotenuse to the side adjacent to a given angle in a right triangle.

cos(A) = adj/hyp = b/c

sec(A) = hyp/adj = c/b  

The cotangent (cot)

The cotangent is the reciprocal of the tangent. It is the ratio of the adjacent side to the opposite side in a right triangle.

tan(A) = opp/adj = a/b

cot(A) =adj/opp = b/c

Answer:

[tex]\Huge \boxed{x=6}[/tex]

[tex]\rule[225]{225}{2}[/tex]

Step-by-step explanation:

[tex](2^{2x +2}) (2^{3x -7})= 2^{25}[/tex]

When multiplying same bases, add the exponents.

[tex](2^{2x +2+3x -7})= 2^{25}[/tex]

[tex](2^{5x -5})= 2^{25}[/tex]

Cancelling the same bases from both sides.

[tex]5x-5=25[/tex]

Adding 5 to both sides.

[tex]5x=30[/tex]

Dividing both sides by 5.

[tex]x=6[/tex]

[tex]\rule[225]{225}{2}[/tex]

Answer:

Expand the left side, group like terms on both sides, and get

(2a)x + 3a = 10x + 15

To be true for all x, equate like terms from both sides and get

2a = 10

3a = 15

Solution: a = 5

You can test the answer.

Step-by-step explanation:

Expand the left side, group like terms on both sides, and get

(2a)x + 3a = 10x + 15

To be true for all x, equate like terms from both sides and get

2a = 10

3a = 15

Solution: a = 5

You can test the answer.

Answer:

270 degrees counter clockwise

Step-by-step explanation:

360-90=270

Answer:

6.83 is the answer

Step-by-step explanation:

Answer:

There is 55.9 mL of acid in the solution.

Step-by-step explanation:

We have:

V = 354 mL

%(a): concentration of acid = 15.8 %

Hence, we can find the number of milliliters of acid as follows:

[tex] x = V*\%_{a} [/tex]

[tex] x = 354*\frac{15.8}{100} = 55.9 mL [/tex]

Therefore, there is 55.9 mL of acid in the solution.

I hope it helps you!

Answer:

5

Step-by-step explanation:

0 is 10ths 5 is 100ths

Answer:

33 2/6 miles

Step-by-step explanation:

So we know that every 6 inches equals 8 miles. To find one mile, we would divide both sides by 8, so every 6/8 of an inch is 1 mile. if the two cities are 25 in apart on a map, that means that we can first do 6*4:8*4 for the ease of it to get 24 inches and 32 miles. So so far it's already 32 miles. Then we have to calculate the leftover one inch. To find out how many miles one inch is, we can divide both sides by 6, so one inch=8/6 of a mile.

So then we add 32+8/6=33 2/6

Tell me if that works for you

Answer:

Well make sure your answer is correct. If it’s correct extend your graph.

Step-by-step explanation:

Answer:

The roots are

Step-by-step explanation:

9x² + 54x + 82 = 0

Using the quadratic formula

That's

From the question

a = 9 , b = 54 , c = 82

Substitute the values into the above formula and solve

That's

Separate the real and imaginary parts

That's

We have the final answer as

Hope this helps you

Answer:

PT = 22

Step-by-step explanation:

Given that T is the midpoint of PQ, then

PT = TQ , substitute values

5x + 2 = 7x - 6 ( subtract 5x from both sides )

2 = 2x - 6 ( add 6 to both sides )

8 = 2x ( divide both sides by 2 )

4 = x

Thus

PT = 5x + 2 = 5(4) + 2 = 20 + 2 = 22

Answer:

Hope this helps

Step-by-step explanation:

1/4x = -22 + 18

1/4x = -4

4(1/4x) = 4(-4)

x = -16

Answer:

He drove 63 miles in one day

Step-by-step explanation:

151.2/2.4=63

Answer:

m<PKN = 270 - m<JKN

Step-by-step explanation:

The measures of the three right angles JKM, MKL, and LKN add to 270 deg.

The measures of the angles JKP and PKN add to 270 deg.

m<PKN = 270 - m<JKN

Newton's Law of Cooling:

[tex]T(t)=T_{s}+(T_{o}-T_{s})e^{-kt}[/tex]

[tex]T(t) =[/tex] Temperature given at a time

[tex]t =[/tex] Time

[tex]T_{s} =[/tex] Surrounding temperature

[tex]T_{o}=[/tex] Initial temperature

[tex]e =[/tex] Constant (Euler's number) ≈ 2.72

[tex]k =[/tex] Constant

Using this information, find the value of [tex]k[/tex], to the nearest thousandth, then use the resulting equation to determine the temperature of the water cup after 4 minutes.

First, plug in the given values in the equation and solve for [tex]k[/tex]:

[tex]T(t) =[/tex] 197°, [tex]t =[/tex] 1.5 minutes, [tex]T_{s} =[/tex] 70° and [tex]T_{o}=[/tex] 210°  

[tex]T(t)=T_{s}+(T_{o}-T_{s})e^{-kt}\\197=70+(210-70)e^{-1.5k} \\197 -70 = (140)e^{-1.5k} \\127 =(140)e^{-1.5k}\\\frac{127}{140}=e^{-1.5k} \\ln(\frac{127}{140})=-1.5k\\-0.097=-1.5k\\0.0649 = k[/tex]

[tex]k[/tex] ≈ [tex]0.065[/tex]

Let the temperature of the water cup after [tex]t = 4[/tex] minutes be [tex]T(t) = x[/tex]

Now, let's plug the new time and [tex]k[/tex] constant in the equation and solve for [tex]x[/tex]:

[tex]T(t)=T_{s}+(T_{o}-T_{s})e^{-kt}\\\\\x=70+(210-70})e^{-0.065*4}\\\\x=70+(140})e^{-0.26}, -0.26=-\frac{26}{100}=-\frac{13}{50} \\[/tex]

[tex]x=70+(140})e^{-\frac{13}{50}}\\\\[/tex]

[tex]x=70+(140})e^{\frac{1}{\frac{13}{50}}\\\\\\[/tex]

[tex]x=70+e^{\frac{140}{\frac{13}{50}}\\\\\\[/tex]

[tex]x=70+{\frac{140}{\sqrt[50]{e^{13}}}\\[/tex]

[tex]x = 70 +\frac{140}{1.3} \\x=70+107.947\\[/tex]

[tex]x=177.95[/tex] ≈ [tex]178[/tex]

Temperature of water after 4 minutes is 178°

sorry if there's any misspelling or wrong step but I hope my answer is correct ':3

Answer:

[tex]Domain = \{9, 10, 11, 12\}[/tex]

[tex]Range = \{22, 32, 41, 30\}[/tex]

Step-by-step explanation:

Given

Grade 9: 22

Grade 10: 32

Grade 11: 41

Grade 12: 30

Required

Determine the domain and the range

The domain and range of a function is represented as thus (x,y)

From the given parameters;

[tex](x,y) = (Grade\ 9, 22), (Grade\ 10, 32) (Grade\ 11, 41), (Grade\ 12, 30)[/tex]

Remove "Grade" to represent as only digits

[tex](x,y) = (9, 22), (10, 32), (11, 41), (12, 30)[/tex]

Split to x and y values:

Where x = domain and y = range

[tex]Domain = \{9, 10, 11, 12\}[/tex]

[tex]Range = \{22, 32, 41, 30\}[/tex]

So, from the list of given options; option C answers the question.