Answer:
The root of the equation is 2 with multiplicity 3
Step-by-step explanation:
8(x-2)^3=0
(x-2)^3=0
The root of the equation is 2 with multiplicity 3
Please help on my hw
Answer:
b. The solution is a non empty set.
Step-by-step explanation:
There are no common elements.
Suppose a triangle has two sides of length 33 amd 37, and that the angle between these two sides is 120°. What is the length of the third side of the triangle
Answer:
c = 60.65 cm
Step-by-step explanation:
Given that,
The two sides of a triangle are 33 cm and 37 cm.
The angle between these two sides is 120°.
We need to find the length of the third side of the triangle. Let c is the third side. Using cosine rule,
[tex]c^2=a^2+b^2-2ab\cos C[/tex]
a = 33 cm, b = 37 cm and C is 120°
So,
[tex]c^2=(33)^2+(37)^2-2\times 33\times 37\cos (120)\\\\c=60.65\ cm[/tex]
So, the length of the third side of the triangle is 60.65 cm.
How much work is done in lifting a 1.4-kg book off the floor to put it on a desk that is 0.7 m high?
Use the fact that the acceleration due to gravity is g = 9.8 m/s^2. How much work is done in lifting a 21-lb weight 6 ft off the ground?
Answer:
Step-by-step explanation:
Work is said to be done when a force applied to an object cause the body to move in a specified direction.
Work-done = Force * Distance
Since Force = mass * acceleration due to gravity
Work-done = mass * acceleration due to gravity * distance
Given mass = 1.4kg, distance = 0.7m and g = 9.8m/s²
Workdone in lifting the book off the floor = 1.4*0.7*9.8
Workdone = 9.604Joules
- Similarly, work done in lifting a 21-lb weight book 6 ft off the ground is expressed using the same formula as above;
Given mass = 21-lb, g = 32ft/s² and distance = 6ft
Workdone = 21 * 32 * 6
Workdone = 4,032 lb-ft²/s²
Hence, work-done in lifting a 21-lb weight book 6 ft off the ground is 4,032 lb-ft²/s²
The width of a rectangle is
3
inches less than the length. The perimeter is
54
inches. Find the length and the width.
please help asap!!!
Answer:
let length be x
b = x - 3
perimeter = 2( l + b)
54 = 2(x+x-3)
27 = 2x - 3
30 = 2x
x = 15
l = 15
b = 15 - 3
b = 12
A local statistician is interested in the proportion of high school students that drink coffee. Suppose that 20% of all high school students drink coffee.
What is the probability that out of these 75 people, 14 or more drink coffee?
Answer:
the probability that out of these 75 people, 14 or more drink coffee is 0.6133
Step-by-step explanation:
Given that:
sample size n = 75
proportion of high school students that drink coffee p = 20% = 0.20
The proportion of the students that did not drink coffee = 1 - p
Let X be the random variable that follows a normal distribution
X [tex]\sim[/tex] N (n, p)
X [tex]\sim[/tex] N (75, 0.20)
[tex]\mu = np[/tex] = 75 × 0.20
[tex]\mu =[/tex] 15
[tex]\sigma = \sqrt{p (1-p) n}[/tex]
[tex]\sigma = \sqrt{0.20(1-0.20) 75}[/tex]
[tex]\sigma = \sqrt{0.20*0.80* 75}[/tex]
[tex]\sigma = \sqrt{12}[/tex]
[tex]\sigma = 3.464[/tex]
Now ; if 14 or more people drank coffee ; then
[tex]P(X \geq 14) = P(\dfrac{X-\mu }{\sigma} \leq \dfrac{X-\mu}{\sigma})[/tex]
[tex]P(X \geq 14) =P(\dfrac{14-\mu }{\sigma} \leq \dfrac{14-15}{3.464})[/tex]
[tex]P(X \geq 14) = P(Z \leq \dfrac{-1}{3.464})[/tex]
[tex]P(X \geq 14) = P(Z \leq -0.28868)[/tex]
From the standard normal z tables; (-0.288)
[tex]P(X \geq 14) = P(Z \leq 0.38667)[/tex]
[tex]P(X \geq 14) = 1 - 0.38667[/tex]
[tex]P(X \geq 14) = 0.61333[/tex]
the probability that out of these 75 people, 14 or more drink coffee is 0.6133
When I add 45 to a certain number and divide the sum by 2, the result is the same as 5 times the number. What is the number?
Answer:
9
please mark brainliest
Answer:
9
Step-by-step explanation:
When we divide 45 by 2 which is 9, it is 5 times the number.
The graph of g(x) = x – 8 is a transformation of the graph of f(x) = x. Which of
the following describes the transformation?
(A) translation 8 units down
(B) translation 8 units up
(C) translation 8 units right
(D) translation 8 units left
Tại Trường Tiểu học ABC, số học sinh của Khối lớp 1, Khối lớp 2, Khối lớp 3, Khối lớp 4 và Khối lớp 5 chiếm tỉ lệ lần lượt là 28%; 22%; 20%; 16% và 14% tổng số học sinh toàn trường. Trong mỗi Khối, tỉ lệ học sinh giỏi năm nay của Khối lớp 1 là 45%, Khối lớp 2 là 50%, Khối lớp 3 là 55%, Khối lớp 4 là 65% và Khối lớp 5 là 75%. Xét trong Khối lớp 1, tỉ lệ học sinh giỏi của Khối lớp 1 là bao nhiêu?
Answer:
hello bro
Step-by-step explanation:
can you translate it on english so i can help you
Name:
Unit 1: Geometry Basics
Date:
Per: Homework 3: Distance & Midpoint Formulas
** This is a 2-page document! **
Directions: Find the distance between each pair of points.
1. 1-4.6) and (3.-7)
2. (-6,-5) and (2.0)
M=(-12,-1)
M=
4. (0.-8) and (3.2)
3. (-1, 4) and (1-1)
5.
.
Directions: Find the coordinates of the midpoint of the segment given its endpoints.
6. /15, 8) and B(-1,-4)
7. M(-5,9) and N[-2.7)
8. P(-3,-7) and Q13.-5)
9. F12.-6) and G(-8,5)
Gina Whion (All Things Algobro. LLC) 2014-2017
The midpoint is the point that divide a segment into two equal halves, while the distance between points is the number of units between both points.
The distance between
(1,-4.6) and (3,7) is 11.77(-6,-5) and (2,0) is 9.43(-1, 4) and (1-1) is 5.39(0.-8) and (3,2) is 10.44The coordinate of midpoint of:
(5, 8) and (-1,-4) is (2,2)(-5,9) and (-2,7) is (-.3.5,9)(-3,-7) and (13.-5) is (5,-6)(12,-6) and (-8,5) is (2,-0.5)The distance in a coordinate geometry is calculated using: [tex]d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}[/tex].
The distance between points is calculated as follows:
(1,-4.6) and (3,7)
[tex]d = \sqrt{(1 - 3)^2 + (-4.6 - 7)^2}[/tex]
[tex]d = \sqrt{138.56}[/tex]
[tex]d = 11.77[/tex]
(-6,-5) and (2,0)
[tex]d = \sqrt{(-6 - 2)^2 + (-5 - 0)^2}[/tex]
[tex]d = \sqrt{89}[/tex]
[tex]d = 9.43[/tex]
(-1, 4) and (1-1)
[tex]d = \sqrt{(-1 - 1)^2 + (4 - -1)^2}[/tex]
[tex]d = \sqrt{29}[/tex]
[tex]d = 5.39[/tex]
(0.-8) and (3,2)
[tex]d = \sqrt{(0 - 3)^2 + (-8 -2)^2}[/tex]
[tex]d = \sqrt{109}[/tex]
[tex]d = 10.44[/tex]
The midpoint (M) is calculated using: [tex]M = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})[/tex]
The coordinate of midpoint is calculated as follows:
(5, 8) and (-1,-4)
[tex]M = (\frac{5-1}{2},\frac{8-4}{2})[/tex]
[tex]M = (\frac{4}{2},\frac{4}{2})[/tex]
[tex]M = (2,2)[/tex]
(-5,9) and (-2,7)
[tex]M = (\frac{-5-2}{2},\frac{9+7}{2})[/tex]
[tex]M = (\frac{-7}{2},\frac{16}{2})[/tex]
[tex]M = (-3.5,9)[/tex]
(-3,-7) and (13.-5)
[tex]M = (\frac{-3+13}{2},\frac{-7-5}{2})[/tex]
[tex]M = (\frac{10}{2},\frac{-12}{2})[/tex]
[tex]M = (5,-6)[/tex]
(12,-6) and (-8,5)
[tex]M = (\frac{12-8}{2},\frac{-6+5}{2})[/tex]
[tex]M = (\frac{4}{2},\frac{-1}{2})[/tex]
[tex]M = (2,-0.5)[/tex]
Read more about distance and midpoints in coordinate geometry at:
https://brainly.com/question/3715220
A study was conducted to compare the effect of three diet types on the milk yield of cows (in lbs). The sample size, sample mean, and sample variance for each method are given below.
Diet A: n1 = 9, X1 = 39.1, s21 = 24.6
Diet B: n2 = 8, X2 = 29.9, s22 = 16.4
Diet C: n3 = 10, X3 = 45.9, s21 = 10.3
(a) Construct an ANOVA table including all relevant sums of squares, mean squares, and degrees of freedom.
(b) Perform an overall F test to determine whether the population means of milk yield are the same or not among the three diet types.
Answer:
(a) Anova table is attached below.
(b) The population means of milk yield are different among the three diet types
Step-by-step explanation:
In this case we need to perform a One-way ANOVA to determine whether the effect of three diet types on the milk yield of cows are significantly different or not.
The hypothesis can be defined as follows:
H₀: The effect of three diet types on the milk yield of cows are same.
Hₐ: The effect of three diet types on the milk yield of cows are significantly different.
(a)
The formulas are as follows:
[tex]\text{Grand Mean}=\bar x=\frac{1}{3}\sum \bar x_{i}\\\\SSB=\sum n_{i}(\bar x_{i}-\bar x)^{2}\\\\SSW=\sum (n_{i}-1)S^{2}_{i}\\\\N=\sum n_{i}\\\\DF_{B}=k-1\\\\DF_{W}=N-k\\\\DF_{T}=N-1\\[/tex]
The F critical value is computed using the Excel formula:
F critical value=F.INV.RT(0.05,2,24)
The ANOVA table is attached below.
(b)
The rejection region is defined as follows:
F > F (2, 24) = 3.403
The computed F statistic value is:
F = 34.069
F = 34.269 > F (2, 24) = 3.403
The null hypothesis will be rejected.
Thus, concluding that the population means of milk yield are different among the three diet types
Simplify 6 - (-2) - 3(-5).
Answer:
23
Step-by-step explanation:
6 - (-2) - 3(-5).
PEMDAS says multiply first
6 +2 +15
Add
23
Answer:
Answer is 23
Step-by-step explanation:
First open brackets:
[tex] = 6 + 2 + 15[/tex]
summ up:
[tex] = 23[/tex]
Given a sphere with radius r, the formula 4 r2 gives
O A. the volume
O B. the surface area
O c. the radius
O D. the cross-sectional area
Answer: surface area
Step-by-step explanation:
A box contain 12 balls in which 4 are white 3 are blue and 5 are red.3 balls are drawn at random from the box.find the chance that all three are selected
Answer:
3/11
Step-by-step explanation:
In the above question, we have the following information
Total number of balls = 12
White balls = 4
Blue balls = 3
Red balls = 5
We are to find the chance of probability that if we select 3 balls, all the three are selected.
Hence,
Probability ( all the three balls are selected) = P(White ball) × P(Blue ball) × P( Red ball)
Probability ( all the three balls are selected) = 4/12 × 3/11 × 5/10
= 60/1320
= 1/22
The number of ways by which we can selected all the three balls is a total of 6 ways:
WBR = White, Blue, Red
WRB = White, Red, Blue
RBW = Red, Blue, White
RWB = Red, White, Blue
BRW = Blue, Red, White
BWR = Blue, White, Red
Therefore, the chance that all three are selected :
1/22 × 6 ways = 6/22 = 3/11
Hello Pls help and thanks
Answer:
c.) in the correct answer
Question 2 (1 point)
Saved
A year ago, Rebecca purchased 100 shares of Havad stock for $20 per share.
Yesterday, she placed a limit order to sell her stock at a price of $33 per share before
the market opened. The stock's price opened at $23 and slowly increased to $26 in
the middle of the day, before declining to $22 by the end of the day. The stock did
not pay any dividends over the period in which Rebecca held it. Given Rebecca's
initial investment of $ 20 per share, her return is
Answer:
Rebecca does not have a return yet because the stock was not sold since there was a limit order at $33.
However, the value of her investment can be put around $2,400 (100 x $24 average price).
Step-by-step explanation:
Price of Havad Stock bought a year ago = $20
No. of shares = 100
Limit order selling price = $33
Stock prices during the limit order day = $23, $26, and $22
The stock cannot be sold, since its price did not reach $33.
Rebecca's limit order is an order to buy or sell her stock in Havad at $33 or better. Since her order is a sell limit order, it can only be executed at the limit price of $33 or higher. Unfortunately, the price of the stock did not reach the limit order on that particular day. This implies that her limit order is not guaranteed to execute.
pls help :c if anyone knows what to do
plzzzzzzzz helllllllppppppppp
Answer:
C
Step-by-step explanation:
He want's the bookshelf to be 1.5 feet taller than 1/4 of the height of his plant
If his plant's height is p, 1/4 of it's height would be 1/4p
As he wants the bookshelf to be 1.5 feet taller than this, the height should be
1.5 + 1/4p, which can also be written as p/4 + 1/5
Answered by g a u t h m a t h
Answer:
1/4p +1.5
Step-by-step explanation:
p = plant stand
The bookshelf is 1/4 the height of the plant stand plus 1.5 ft
1/4p +1.5
Triangles are worth 3 points. Quadrilaterals are worth 4 points. Parallelograms are worth 5 points. Each student identifies and names as many of each shape as they can then calculate their total score. Ryan says the greatest possible score is 156, but Janice says she can score more. Who do you agree with and why?
Answer:
I agree on janice because if is reliable and brilliant,she can score more than that
Write the expression
using only positive exponents.
-3/x-4
A potato chip company makes potato chips in two flavors, Regular and Salt & Vinegar. Riley is a production manager for the company who is trying to ensure that each bag contains about the same number of chips, regardless of flavor. He collects two random samples of 10 bags of chips of each flavor and counts the number of chips in each bag. Assume that the population variances of the number of chips per bag for both flavors are equal and that the number of chips per bag for both flavors are normally distributed. Let the Regular chips be the first sample, and let the Salt & Vinegar chips be the second sample. Riley conducts a two-mean hypothesis test at the 0.05 level of significance, to test if there is evidence that both flavors have the same number of chips in each bag. (a) H0:μ1=μ2; Ha:μ1≠μ2, which is a two-tailed test. (b) t≈1.44 , p-value is approximately 0.167 (c) Which of the following are appropriate conclusions for this hypothesis test?
A. There is insufficient evidence at the 0.05 level of significance to conclude that Regular and Salt & Vinegar chips have different amounts of chips per bag.B. There is sufficient evidence at the 0.05 level of significance to conclude that Regular and Salt & Vinegar chips have different amounts of chips per bag.C. Reject H0.D. Fail to reject H0.
Answer:
A. There is insufficient evidence at the 0.05 level of significance to conclude that Regular and Salt & Vinegar chips have different amounts of chips per bag.
D. Fail to reject H0.
Step-by-step explanation:
From the summary of the given test statistics.
The null and the alternative hypothesis are:
[tex]H_0:\mu_1=\mu_2 \\ \\ Ha:\mu_1 \neq \mu_2[/tex]
This test is also a two tailed test.
Similarly, the t value for the test statistics = 1.44
The p- value - 0.167
The level of significance ∝ = 0.05
The objective we are meant to achieve here is to determine which of the following from the given options are appropriate conclusions for this hypothesis test.
From what we have above:
Decision Rule: We fail to reject the null hypothesis since the p-value is greater than the level of significance at 0.05
CONCLUSION: Therefore, we can conclude that there is insufficient evidence at the 0.05 level of significance to conclude that Regular and Salt & Vinegar chips have different amounts of chips per bag as we fail to reject H0.
A random sample of size 100 is taken from a population described by the proportion p = 0.60. The probability that the sample proportion is less than 0.55 is ________.
Answer:hope it helps
Step-by-step explanation:
Result:
0.6
Enlarge
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Plain Text
Number line:
Number line
Rational form:
3/5
Length of tangent line - geometry please help
Answer:
12
Step-by-step explanation:
(whole secant) x (external part) = (tangent)^2
PC * PA = PB^2
(PA+AC) * PA = PB^2
(4+32) * 4 = PB^2
36*4 = PB^2
144 = PB^2
Taking the square root of each side
sqrt(144) = sqrt(PB^2)
12= PB
Answer:
a
Step-by-step explanation:
Given a tangent and a secant to a circle from an external point, then
The square of the tangent is equal to the product of the external part and the whole of the secant , that is
PB² = PA × PC = 4(4 + 32) = 4 × 36 = 144 ( take square root of both sides )
PB = [tex]\sqrt{144}[/tex] = 12 → a
Allison bought jelly beans to share with her friends. She bought pounds of blueberry jelly beans and pounds of lemon jelly beans. If she gave pounds of jelly beans away to her friends, how many pounds of jelly beans does Allison have left?
Answer: [tex]1\dfrac{11}{12}\text{ pounds}[/tex]
Step-by-step explanation:
The complete question is provided in the attachment.
Given, Amount blueberry jelly beans= [tex]1\dfrac{1}{4}[/tex] pounds
[tex]=\dfrac{5}{4}[/tex] pounds.
Amount lemon jelly beans = [tex]2\dfrac{1}{3}[/tex]pounds
[tex]=\dfrac{7}{2}[/tex] pounds
Total jelly beans she bought = Amount blueberry jelly beans + Amount lemon jelly beans
[tex]=(\dfrac{5}{4}+\dfrac{7}{3})[/tex] pounds
[tex]=\frac{15+28}{12}\text{ pounds}\\\\=\dfrac{43}{12}\text{ pounds}[/tex]
Amount of jelly beans she gave away = [tex]1\dfrac{2}{3}=\dfrac{5}{3}\text{ pounds}[/tex]
Amount of jelly beans she has left= Total jelly beans - Amount of jelly beans she gave away
=[tex]\dfrac{43}{12}-\dfrac{5}{3}\\\\=\dfrac{43-20}{12}\\\\=\dfrac{23}{12}\\\\=1\dfrac{11}{12}\text{ pounds}[/tex]
She has left [tex]1\dfrac{11}{12}\text{ pounds}[/tex] of jelly beans.
A box contains 30 widgets, 4 of which are defective. If 4 are sold at random, find the probability that (a) all are defective (b) none are defective.
Answer:
a. The probability that all are defective is 0.0003160493827
b. Probability that none are defective is 0.99968395
Step-by-step explanation:
Given that 4 of the 30 widgets contained on the box are defective, n = 4. The probability of picking a defective widget is p = 4/30 = 2/15.
Now, P(X = a) = (nCa)P^n(1 - P)^(n - a).
a. To find the probability that all are defective, we want to find P(X = 4)
= (4C4) × (2/15)^4 × (1 - 2/15)^(4 - 4)
= 1 × (2/15)^4 × 1
= 0.0003160493827
b. Probability that none are defective.
This is the same as saying (1 minus the probability that all are defective).
P = 1 - 0.0003160493827
= 0.99968395
HELPPPPPPP PLZZZZ ASPPPPPP
Answer: Choice B
[tex](f * g)(x) = \frac{x^2+6x+8}{x^2+2x-15}, \ \text{ for } x \ne -5 \text{ and } x \ne 3\\\\[/tex]
=================================================
Work Shown:
[tex]h(x) = (f * g)(x)\\\\h(x) = f(x) * g(x)\\\\h(x) = \frac{x^2-16}{x^2+3x-10}*\frac{x^2-4}{x^2-7x+12}\\\\h(x) = \frac{(x-4)(x+4)}{(x+5)(x-2)}*\frac{(x-2)(x+2)}{(x-3)(x-4)}\\\\h(x) = \frac{x+4}{(x+5)(x-2)}*\frac{(x-2)(x+2)}{x-3} \ \ \text{ ... see note 1}\\\\h(x) = \frac{x+4}{x+5}*\frac{x+2}{x-3} \ \ \text{ ... see note 2}\\\\h(x) = \frac{(x+4)(x+2)}{(x+5)(x-3)}\\\\h(x) = \frac{x^2+6x+8}{x^2+2x-15}\\\\[/tex]
note 1: A pair of (x-4) terms canceled
note 2: A pair of (x-2) terms canceled
------------------------------
Extra info (optional section):
The fact that [tex]x \ne -5 \text{ and } x \ne 3[/tex] is to avoid a division by zero error in the simplified version of h(x).
I would argue that [tex]x \ne 2 \text{ and } x \ne 4[/tex] should be thrown in as well simply so that the domains match up perfectly with the original f(x) and g(x) functions.
So I think the full domain should be that x is any real number but
[tex]x \ne -5 \text{ and } x \ne 2\\x \ne 3 \text{ and } x \ne 4[/tex]
Put another way: if x = 2 is allowed in h(x), then that clashes with the fact that it's not allowed in f(x). The same idea happens with x = 4 but with g(x) this time. It's possible your teacher glossed this fact over, or ran out of room.
Find the perimeter of the rectangle with the following vertices. (−6, −2), (0, −10), (5, 2), (−1, 10) 23 52 46 40
Answer:
46
Step-by-step explanation:
See attached for reference
The points given:
(−6, −2), (0, −10), (5, 2), (−1, 10)They form a rectangle as seen in the picture.
We can notice that this is a parallelogram, as respective lines have same difference of coordinates.
So calculating only the two of the sides will be sufficient to get its perimeter:
a = √(-1+6)² + (10+2)² = √25+144 = √169= 13b = √(0+6)² + (-10+2)² = √36+64 = √100 = 10So, the perimeter:
P = 2(13+10) = 46
Solve 5(2x + 4) = 15. Round to the nearest thousandth.
[tex]5(2x + 4) = 15\\10x+20=15\\10x=-5\\x=-\dfrac{5}{10}=-0,5[/tex]
Answer:
[tex]\huge\boxed{x=-0.5}[/tex]
Step-by-step explanation:
[tex]5(2x+4)=15\qquad\text{divide both sides by 5}\\\\\dfrac{5\!\!\!\!\diagup(2x+4)}{5\!\!\!\!\diagup}=\dfrac{15\!\!\!\!\!\diagup}{5\!\!\!\!\diagup}\\\\2x+4=3\qquad\text{subtract 4 from both sides}\\\\2x+4-4=3-4\\\\2x=-1\qquad\text{divide both sides by 2}\\\\\dfrac{2x}{2}=\dfrac{-1}{2}\\\\\boxed{x=-0.5}[/tex]
akram is 20 year old and his sister shazia is 15
1-what was the ratio of their ages before 4 years
2-what was the ratio of their ages after 5 years
3-what do the above two points explain about ratios
Answer:
1) akram : shazia
20-4 : 15-4
16 : 11
2) akram : shazia
20 + 5 : 15 + 5
25 : 20
5 : 4
3) ratios are not always constant
I NEED HELP WITH THESE 4 ASAP
Answer:
I'm confused by this. What do they mean by prove?
Step-by-step explanation:
please solve asap thanks
I think..
A' =( -1,-4 )
B' = ( 3,-2 )
C'=( - 2, 2 )
Answer:
A' (-3, 12)
B' (9, 6)
C' (-6, -6)
Step-by-step explanation:
A (-1 , 4 ) , K = 3 => K * each with coordinate of A => (-1 * 3, 4 * 3)
B ( 3 , 2 ) , K = 3 => K * each with coordinate of B => (3 * 3, 2 * 3)
C ( -2 , -2 ) , K = 3 => K * each with coordinate of C => (-2 * 3, -2 * 3)