Answer:
Explanation:
On rubbing a glass rod with silk, the electrons from the glass rod get transferred to the silk. The silk now has an excess of electrons and so is negatively-charged. On the other hand, the glass rod is deficient in electrons and hence is positively-charged.
In the above case, the silk undergoes negative electrification.
Now, when the positively charged glass rod is touched on the disc of a negatively charged gold leaf electroscope, the electrons shifts towards rod, hence amount of charge on gold leaves decreases and the divergence between the gold leaves decreases as unlike charges attract each other.
Hence, the divergence decreases when a glass rod rubbed with silk is brought near the disc of negatively charged electroscope.
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A pulley system is made of 3 pulley write its velocity ratio
Almost 3 times fast than normal pulley system
mark me
1
A force 2ON acts at a distance of 2n from a pivot.
what is the moment
force about the pivot
Answer:
[tex]\large \boxed{\mathrm{40 \ Nm}}[/tex]
Explanation:
[tex]\sf Moment \ (Nm) = Force \ (N) \times Distance \ from \ pivot \ (m)[/tex]
[tex]M=20 \times 2[/tex]
[tex]M=40[/tex]
Express the time spent to daily life activities during holidays as a fraction of whole day 1. Represent the fractions in pictorial form. 2. Write the fractions in simplest form. 3. Arrange them in ascending order.
Answer:
(II). The fractions in simplest form
[tex]\dfrac{31}{35}[/tex], [tex]\dfrac{91}{165}[/tex] and [tex]\dfrac{13}{5}[/tex]
(III). The fractions in ascending order
[tex]\dfrac{91}{165}<\dfrac{31}{35}<\dfrac{13}{5}[/tex]
Explanation:
Given that,
(I). Represent the fractions in pictorial form
(II). Write the fractions in simplest form.
(III). Arrange them in ascending order.
Suppose, The fractions in pictorial form
(a). [tex]\dfrac{3}{5}+\dfrac{2}{7}[/tex]
(b). [tex]\dfrac{9}{11}-\dfrac{4}{15}[/tex]
(c). [tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}[/tex]
We need to write in simplest form
Using given fraction
(a). [tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{3\times7}{5\times7}+\dfrac{2\times5}{7\times5}[/tex]
[tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{21}{35}+\dfrac{10}{35}[/tex]
[tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{21+10}{35}[/tex]
[tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{31}{35}[/tex]
(b). [tex]\dfrac{9}{11}-\dfrac{4}{15}=\dfrac{9\times15}{11\times15}-\dfrac{4\times11}{15\times11}[/tex]
[tex]\dfrac{9}{11}-\dfrac{4}{15}=\dfrac{135-44}{165}[/tex]
[tex]\dfrac{9}{11}-\dfrac{4}{15}=\dfrac{91}{165}[/tex]
(c). [tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7}{10}+\dfrac{2\times2}{5\times2}+\dfrac{3\times5}{5\times2}[/tex]
[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7}{10}+\dfrac{4+15}{10}[/tex]
[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7+4+15}{10}[/tex]
[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{26}{10}[/tex]
[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{13}{5}[/tex]
We need to arrange them in ascending order
Using simplest form
The simplest fraction in ascending order
[tex]\dfrac{91}{165}<\dfrac{31}{35}<\dfrac{13}{5}[/tex]
Hence, This is required solution.
If 60 L of a gas are at 4 atm and 27 C °, what pressure would it have if the volume is 40 L 127 C °?
Answer:
8 atm
Explanation:
Ideal gas law:
PV = nRT
where P is pressure, V is volume, n is moles, R is universal gas constant, and T is absolute temperature.
If n is constant:
PV / T = PV / T
(4 atm) (60 L) / (27 + 273) K = P (40 L) / (127 + 273) K
0.8 atm = 0.1 P
P = 8 atm
Once a scientist has made a hypothesis, what would they typically do next? (2 points)
a
Analysis
b
Testing
C
Research
d
Sharing
Answer:Testing
Explanation:Once a scientist has made a hypothesis, what would they typically do TESTING nextn
Once a scientist has made a hypothesis, they would typically do testing, therefore the correct answer is option B
What is the scientific claim?Scientific claims are statements made in science based on an experiment.
These Scientific claims are backed by the experimental data and their true results obtained from scientific investigation and experimentation.
When a scientist performs a fair test is one in which all other circumstances are maintained while just one variable is changed at a time.
Scientists frequently discover that their hypotheses and predictions were not supported by the results of their experiments. In these situations, they will communicate the findings of their experiment before revising their original hypotheses and predictions in light of the new knowledge they have gained.
The right response is option B because once a scientist has made a theory, they usually do testing.
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An athlete runs four laps of a 400 m track. What is the athlete's total displacement?
Answer:
○ 0 [tex]\checkmark[/tex]
Explanation:
Even if the athelete runs four laps of a 400 m track, its displacement will be 0 because the displacement is the shortest distance from its to final position. And, here the final and initial position is same since he comes to its initial position after covering certain distance. So, displacement is 0.
calculate the average speed of an athele who runs a distance of 100m in 16 s and an additional of 400m in a 44s
Explanation:
speeds = distance/time
=100/16
=6.25m/s
second speed is;
400/44 =9.09
av. speed = total speed /n
= (6.25+9.09)/2
=7.67 m/s
Exercise b) 1) Fill in the blanks with the appropriate word: a) The pressure exerted by the air in atmosphere is called b) Pressure is the applied per unit area, c) The pressure ........as the depth of liquid increases. d) The SI unit of density is Az object fisats on water if the ...of the object is leva
Answer:
atmospheric pressure
b)
c)increases
d) ....
A position of a particle moving on an x axis is given by x=7•4 + 9•2t - 2•1 t^3, with x in meters and t in seconds. what is its velocity at t=3•5s? is the velocity,or is it Continuously changing?
Answer:
The velocity at that time would be [tex](-67.975\; \rm s)[/tex]. The velocity of this particle is continuously changing.
Explanation:
Differentiate the expression for position [tex]x[/tex] with respect to time [tex]t[/tex] to find an expression for velocity.
[tex]\begin{aligned}v(t) &= \frac{d}{dt}[x(t)] \\ &= \frac{d}{dt} \left[ 7.4 + 9.2\, t - 2.1\, t^{3}\right]\\ &= 9.2 - 6.3\, t^{2}\end{aligned}[/tex].
Hence, at [tex]t = 3.5\; \rm s[/tex], velocity would be [tex]v(3.5) = 9.2 - 6.3 \times (3.5)^{2} = -67.975\; \rm m[/tex].
Since velocity [tex]v(t)[/tex] changes with time [tex]t[/tex], the velocity of this particle is continuously changing.
64. A heart pacemaker fires 72 times a minute, each time a 25.0-nF capacitor is charged (by a battery in series with a resistor) to 0.632 of its full voltage. What is the value of the resistance
Answer:
=33 .3×10^6Ω
=33.3M Ω
Explanation:
We were told to calculate the Resistance value,
Given the heart pacemaker fires as 72 times a minute, which is the time constant
Then we can convert the pacemaker fires of 72 times a minute to seconds for unit consistency.
1 minutes= 60secs
Then ,Time constant τ=60secs/72=0.8333 seconds
Time constant τ can be calculated using the formula below
τ= RC
Where R= resistance
C = capacitance
Then making RESISTANCE subject of formula we have
R=τ/C
But Capacitance=25.0-nF = 25×10^25F
Substitute the values we have
R=0.833/25×10^25
=33 .3×10^6 Ω
But can still be converted to M Ω= 33.3M Ω
Therefore, the resistance is 33 .3×10^6 Ω or 33.3M Ω
NOTE: 1M= 10^6
The value of the resistance will be "3.33×10⁷ Ω".
Resistance based problem:According to the question,
Capacitor, C = 25.0 nF
60 sec - 72 fires
now,
Time for 1 fire,
[tex]t = \frac{60}{72}[/tex]
[tex]= \frac{5}{6} \ sec[/tex]
Now,
⇒ [tex]V = V_0 (1-e^{-\frac{t}{RC} })[/tex]
[tex]0.632 V_0=V_0(1-e^{\frac{-\frac{5}{6} }{R.25 n C} })[/tex]
[tex]e^{-\frac{1}{R\times 30\times 10^{-9}} } = 1-0.632 = 0.368[/tex]
[tex]= 2.72[/tex]
By taking "log" both sides,
⇒ [tex]ln \ e^{\frac{1}{R\times 30\times 10^{-9}} } = ln \ 2.72[/tex]
hence,
The Resistance be:
⇒ [tex]R = \frac{10^9}{30}[/tex]
[tex]= 3.33\times 10^7 \ \Omega[/tex]
Thus the above approach is right.
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a body weighs 100newtons when submerged in water. calculate the upthrust action on the body
Answer:
Upthrust = 20 N
Explanation:
The question says that "A body weighs 100N in air and 80N when submerged in water. Calculate the upthrust acting on the body ?"
Upthrust is defined as the force when a body is submerged in liquid, then liquid applies a force on it.
ATQ,
Weight of body in air is 100 N
Weight of body in water is 80 N
Upthrust is equal to the weight of body in air minus weight of body in water.
Upthrust = 100 N - 80 N
Upthrust = 20 N
So, 20 N of upthrust is acting on the body.
A car accelerates at a rate of 3 m/s^2. If its original speed is 8 m/s, how many seconds will it take the car to reach a final speed of 25 m/s?
Answer:
[tex]\Large \boxed{\mathrm{5.67 \ seconds }}[/tex]
Explanation:
[tex]\displaystyle \mathrm{acceleration \ = \ \frac{final \ velocity - initial \ velocity }{elapsed \ time}}[/tex]
[tex]\displaystyle A \ = \ \frac{V_f - V_i }{t}[/tex]
[tex]\displaystyle 3 \ = \ \frac{25 - 8 }{t}[/tex]
[tex]\displaystyle 3 \ = \ \frac{17 }{t}[/tex]
[tex]\displaystyle t \ = \ \frac{17 }{3} \approx 5.67[/tex]
An object of mass 25kg is at rest. What is its momentum ?
Answer:
[tex]\boxed{0}[/tex]
Explanation:
Momentum is the measure of mass in motion.
[tex]\sf momentum = mass \times velocity[/tex]
An object at rest has a velocity of 0.
[tex]p=mv[/tex]
[tex]p = 25 \times 0[/tex]
[tex]p=0[/tex]
The momentum of an object at rest is always 0.
Cho hai điện trở R1 = 12Ω và R2 = 18Ω được mắc nối tiếp nhau. Điện trở tương R12 của đoạn mạch có thể nhận giá trị nào trong các giá trị
Answer:
For two resistors R1 = 12Ω and R2 = 18Ω are connected in series. The equivalent resistance R12 of the circuit can take any of the values
element X has two isotopes: X-27 and x-29. x-27 has an atomic mass of 26.975 and a relative abundance of 82.33%, and X-29 has an atomic mass of 29.018 and a relative abundance of 17.67%. calculate the atomic mass of element X. show your work
Answer:
27.34 (no unit)
Explanation:
26.975*82.33%+29.018*17.67%
=27.34
Describe what happens to water waves when they strike a flat surface?
Answer:
In this case reflection occurs.
Explanation:
This happens when they bounce on objects that they can not pass through.
Hope it helps
okay.
A skydiver falls toward the ground at a constant velocity. Which statement best applies Newton’s laws of motion to explain the skydiver’s motion? An upward force balances the downward force of gravity on the skydiver. The skydiver’s inertia is zero, which no longer allows for acceleration. An unbalanced force pulls the skydiver toward the ground. The mass of the skydiver is so great that there is no acceleration.
Answer:
The answer is (a.) An upward force balances the downward force gravity on the skydiver
The skydiver is falling at a constant velocity because the upward force is balancing the downward force of gravity. According to Newton, the opposite force balance each other. This is stated in Newton's second law of motion.
The statement that best applies Newton’s laws of motion to explain the skydiver’s motion is that An upward force balances the downward force of gravity on the skydiver.
Newton's 3rd law often applies to skydiving.
When gravity is not acting upon the skydivers they would continue moving in the direction the vehicle they jumped from was moving.
If no air resistance takes place, then the skydivers would still accelerating at 9.8 m/s until they hit the ground.
The skydiver after leaving the aircraft will accelerates downwards due to the force of gravity
usually as there is no air resistance acting in the upwards direction, and there is a resultant force acting downwards, the skydiver will accelerates towards the ground.
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A wire of length 5mm and Diameter 2m extends by 0.25 when a force of 50N was use. calculate the
a. Stress of the wire.
b. Strain of the wire
Answer and Explanation:
Data provided in the question
Force = 50N
Length = 5mm
diameter = 2.0m = [tex]2\times 10^{-3}[/tex]
Extended by = 0.25mm = [tex]0.25\times 10^{-3}[/tex]
Based on the above information, the calculation is as follows
a. The Stress of the wire is
[tex]= \frac{force\ applied}{area\ of \ circle}[/tex]
here area of circle = perpendicular to the are i.e cross-sectional i.e
= [tex]\frac{\pi d^{2}}{4}[/tex]
= [tex]\frac{\pi(2\times 10^{-3})^2}{4}[/tex]
Now place these above values to the above formula
[tex]= \frac{4\times 50}{\pi\times 4 \times 10^{-6}} \\\\ = \frac{50}{\pi}[/tex]
= 15.92 MPa
As 1Pa = 1 by N m^2
So,
MPa = 10^6 N m^2
b. Now the strain of the wire is
[tex]= \frac{Change\ in\ length}{initial\ length} \\\\ = \frac{0.25\times 10^{-3}}{5}[/tex]
= [tex]5 \times 10^{-5}[/tex]
2 Which invention was crucial to the development of cell theory?
Answer:
I guess i would say the microscope
Explanation:
Because of the microscope, we can see the cells.
Need help finding the average speed.
Explanation:
To find the average of these numbers, we just have to add the three numbers together and divide by 3.
2.07 + 0. 74 + 1.33 = 4.14. 4.14 / 3 = 1.381.09 + 1.40 + 0.31 = 2.8. 2.8 / 3 ≈ 9.3333333/ 9 1/30.95 + 1.61 + 0.56 = 3.12 / 3 = 1.040.81 + 1.89 + 1.08 = 3.78 / 3 = 1.26explain the delay in hearing of a sound
Answer:
Humans naturally have what's known as binaural hearing, which is the ability to hear in two ears.
Imagine that you are using a similar computer simulation to conduct an experiment on ph value of different liquid hand soap solutions and water. What is a potential source for error in such a computer model?
Please help!!
The computer model would rely on the labeled pH values of various hand soap brands however the labled pH value might not be entirely accurate, which could comprise the accuracy of the computer model.
Inaccuracies in the simulation's underlying chemistry model could be a potential source of mistake in an experiment involving the pH values of several liquid hand soap solutions and water.
The outcomes could differ from actual behavior if the model does not adequately represent the intricate chemical interactions that control pH fluctuations. Furthermore, because they might not exactly match the varied properties of real hand soap solutions, the simulation's assumptions and parameters could introduce bias. Disparities between simulation results and empirical findings may also result from inadequate consideration of temperature impacts and ambient factors. To reduce such possible mistakes, careful simulation validation against empirical data and chemistry model modification are required.
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ball is thrown upward from a window that is 12 m above the ground. The ball reaches a maximum height of 4 m above the window before falling all the way down to the ground. What distance did the ball travel?
Answer:
20 m
Explanation:
The ball travels 4 m up, then 16 m down. It travels a total distance of 20 m.
1. explain the procedure undertaken if you have to measure the density of the contents of a milk carton. 2. two objects have the same mass. How about the density of the two objects?
To calculate the density of a substance, its mass and volume has to be determined. So that:
i. For the milk in the carton, its mass and volume should be known.
ii. For the two objects given in the question, their individual masses and volumes have to be determined.
Density of a substance (ρ) is the rate of the mass (m) of the substance to its volume (V). It is measure in kg/[tex]m^{3}[/tex].
i.e ρ = [tex]\frac{m}{V}[/tex]
The density of a substance can be determined once the mass and its volume have been accurately measured.
1. How to measure the density of the contents of a milk carton.
a. Determine the mass of the milk carton with its content.
b. Determine the mass of the milk carton when empty.
c. Subtract the mass of the milk carton when empty from the mass of the carton with its content. This will give the mass of the milk in the carton.
d. Using a beaker, measure the volume of the milk.
e. Divide the mass of the milk by its volume to determine its density.
2. How to measure the densities of two objects of equal mass.
a. Fill an Eureka's can or a beaker with sprout with water to its brim.
b. Slowly drop the mass into the beaker with water so as to collect the volume of the liquid displaced into another beaker.
c. The volume of the liquid displaced is the volume of the mass.
d. Divide the mass of the object by its volume to determine its density.
NB: These procedures are observed to determine the densities of the two object individually.
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Why is figure 5 an unhelpful visualization tool for this data set?
Please help!
Explanation:
Because the temperature and the radiation are not correlated, they're not represented as functions of each other, they're represented as independent variables thus using graph 5 you cannot figure out how one affect another
Answer:
It doesn’t show how temperature and radiation relate to each other. It’s difficult to draw conclusions from data that’s separated this way.
A ball is dropped from a height of 180m- Calculate the velocity of the ball when it strikes the ground
Answer:
6s , 60mls
Explanation:
hope this helps love
Answer:
0m/s
Explanation:
When the object strikes the ground, it then becomes in uniform motion and when an object is in uniform motion, the velocity is 0
whats the beginning of life called
Answer:
Abiogenesis in evolutionary science, not sure about creation science
Explanation:
liquids with convex meniscus
Mercury in a glass tube.
How much heat does 25 g of aluminum lose when cooled from 100 ° C to 20 ° C? Express your result in BTU
Answer:
1.7 BTU
Explanation:
q = mCΔT
q = (25 g) (0.9 J/g/°C) (100°C − 20°C)
q = 1800 J
q = 1800 J × (1 BTU / 1055 J)
q = 1.7 BTU
Which is
easier
Push
or pull.
when force is at angle
Answer:
pull
Explanation:
because when you push there is one component of force that adds to tge weight of body and hence there is more friction. Whwn you pull the vertical component of force is against the weight of body and hence friction is low.