If f(x)=ax^2+bx+c and f(0)=-4 and f(1)=-2 and f(2)=6, what is the value of A and B and C?

Answer:

[tex]m = 10[/tex]

Step-by-step explanation:

Looking at the angles, we can see that this is a 30-60-90 triangle.

The side that is with the 30° angle and the 90° angle is represented by [tex]x\sqrt{3}[/tex].

So let's find x.

[tex]x\sqrt{3} = 5\sqrt{3}[/tex]

Divide both sides by [tex]\sqrt{3}[/tex]:

[tex]x = 5[/tex].

Now the hypotenuse is always [tex]2x[/tex] (the leg with the 90° and 60° is just x.) So,

[tex]2x = 2\cdot5 = 10[/tex].

Hope this helped!

Answer:

2 sqrt(41) = x

Step-by-step explanation:

This is a right triangle so we can use the Pythagorean theorem

a^2 + b^2 = c^2

8^2 + 10 ^2 = x^2

64+ 100 = x^2

164 = x^2

Take the square root of each side

sqrt(164) = sqrt(x^2)

sqrt(4) sqrt(41) = x

2 sqrt(41) = x

Answer:

Step-by-step explanation:

Answer:

y - 1 = -2(x - 4).

Step-by-step explanation:

First, we need to find the slope. Two sets of coordinates are (-3, 3), and (-2, 1).

(3 - 1) / (-3 - -2) = 2 / (-3 + 2) = 2 / (-1) = -2.

The line will be parallel to the given line, so the slope is the same.

Now that we have a point and the slope, we can construct an equation in point-slope form.

y1 = 1, x1 = 4, and m = -2.

y - 1 = -2(x - 4).

Hope this helps!

The slope of the line passing  parallel to the given line and passes through the point (4, 1) is y = -2x + 9

The equation of a straight line is given by:

y = mx + b

where y, x are variables, m is the slope of the line and b is the y intercept.

The slope of the line passing through the points (-3,3) and  (-2,1) is:

[tex]m=\frac{y_2-y_1}{x_2-x_1} \\\\m=\frac{1-3}{-2-(-3)} \\\\m=-2[/tex]

Since both lines are parallel, hence they  have the same slope (-2). The line passes through (4,1). The equation is:

[tex]y-y_1=m(x-x_1)\\\\y-1=-2(x-4)\\\\y=-2x+9[/tex]

Find out more at: https://brainly.com/question/18880408

Answer:

simply convert first feets into miles

Given is 5280 feets=1 miles

63756 /5280=12.075 miles

70 minutes  = 1.16666= 1.17 hrs

rate is 12.075 miles/1.17 hrs

Step-by-step explanation:

Answer:

[tex]|R_n (x)| \leq \dfrac{|x - \dfrac{\pi}{2}|^{n+1}}{(n+1)!}[/tex]

Step-by-step explanation:

From the given question; the objective is to show that :

[tex]\lim_{n \to \infty} R_n (x) = 0[/tex] for all x in the interval of convergence f(x)=cos x, a= π/2

Assuming for the convergence f the taylor's series , f happens to be the derivative on an open interval I with a . Then the Taylor series for the convergence of f , for all x in I , if and only if  [tex]\lim_{n \to \infty} R_n (x) = 0[/tex]  

where;

[tex]\mathtt{R_n (x) = \dfrac{f^{(n+1)} (c)}{n+1!}(x-a)^{n+1}}[/tex]

is a remainder at x and c happens to be between x and a.

Given that:

a= π/2

Then; the above equation can be written as:

[tex]\mathtt{R_n (x) = \dfrac{f^{(n+1)} (c)}{n+1!}(x-\dfrac{\pi}{2})^{n+1}}[/tex]

so c now happens to be the points between π/2 and x

If we recall; we know that:

[tex]f^{(n+1)}(c) = \pm \ sin \ c \ or \ cos \ c[/tex] (as a result of the value of n)

However, it is true that for all cases that  [tex]|f ^{(n+1)} \ (c) | \leq 1[/tex]

Hence, the remainder terms is :

[tex]|R_n (x)| = | \dfrac{f^{(n+1)}(c)}{(n+1!)}(x-\dfrac{\pi}{2})^{n+1}| \leq \dfrac{|x - \dfrac{\pi}{2}|^{n+1}}{(n+1)!}[/tex]

If [tex]\lim_{n \to \infty} R_n (x) = 0[/tex]   for all x and x is fixed, Then

[tex]|R_n (x)| \leq \dfrac{|x - \dfrac{\pi}{2}|^{n+1}}{(n+1)!}[/tex]

Answer:

Although the question is not clear, It most likely looks like you were asking for the calculation of the savings for the month after increase.

savings for the month after increase = $1172.4

Step-by-step explanation:

First, let us calculate how much was saved before the increase in savings:

monthly income = $19,540

Percentage saved = 4% of monthly income

= 4/100 × 19,540 = 0.04 × 19,540 = $781.6

Next, we are given the ratio of increase in savings as 3:2

Let the new savings amount be x

3 : 2 = x : 781.6

[tex]\frac{3}{2} = \frac{x}{781.6} \\781.6\ \times 3\ =2x\\2344.8 = 2x\\x =\frac{2344.8}{2} \\x = \$1172.4[/tex]

therefore savings for the month after increase = $1172.4

Just incase you were looking for the savings before the increase, the answer is $781.6 (as calculated above)

Answer:

3/500

Step-by-step explanation:

3/5 x 1%

=> 3/5 x 1/100

=> 3/500

Hope it helps you

Answer:

Step-by-step explanation:

First lets focus on, y is no greater than 4,

y < 4

Now we focus on, more than –2,

y > -2

Combining these inequalities get us,

-2 < y < 4

Answer:

-2<y≤4

Step-by-step explanation:

Answer:

Step-by-step explanation:

2x + 3y = 6

2x = 6-3y

x = (6-3y)/2

x - 3y = 9

(6-3y)/2 -3y = 9

(6-3y)/2 -6y/2 = 9

(6-9y)/2 = 9

6 - 9y = 9×2

-9y = 18-6

y = 12/-9

y = -4/3

2x + 3y = 6

2x + 3(-4/3) = 6

2x -4 = 6

2x = 6+4

2x = 10

x = 10/2

x = 5

Therefore x = 5 and y = (-4/3)

I used subsitution method

please click thanks and mark brainliest if you like :)

Answer:

x = 5; y = -4/3

Step-by-step explanation:

One equation has 3y. The other equation has -3y. Add the equations to eliminate y and solve for x.

     2x + 3y = 6

(+)     x - 3y = 9

---------------------

      3x        = 15

x = 5

2x + 3y = 6

2(5) + 3y = 6

3y + 10 = 6

3y = -4

y = -4/3

Answer: x = 5; y = -4/3

Answer:

a² + b² = c²

13² + 13² = c²

169 + 169 = c²

338 = c²

c = √338 or 18.385 or 13√2

Answer:

18.4

Step-by-step explanation:

13² + 13² = x²

169 + 169 = x²

338 = x²

x = 18.38477....

In terms of the trigonometric ratios for ΔABD, what is the length of line segment BD?

Answer:

[tex] BD = c*sin(A) [/tex]

[tex] BD = c*cos(B) [/tex]

[tex] BD = b*tan(A) [/tex]

Step-by-step explanation:

∆ABD is a right triangle.

Recall: trigonometric ratios of any right triangle can easily be understood or remembered with the acronym, SOHCAHTOA.

SOH => sin(θ) = opposite/hypotenuse

CAH => Cos(θ) = adjacent/hypotenuse

TOA = tan(θ) = opposite/adjacent

Thus, the length of segment BD, in terms of trigonometric ratios for ∆ABD can be done as follows:

Let BD = x

AB = c

AD = b

=>The sine ratio for the length of line segment BD = x, using SOH.

θ = A

Opposite = DB = x

hypotenuse = AB = c

[tex] sin(A) = \frac{x}{c} [/tex]

Make x the subject of formula.

[tex] c*sin(A) = x [/tex]

[tex] BD = x = c*sin(A) [/tex]

=>The Cosine ratio for the length of line segment BD = x, using CAH

θ = B

Adjacent = DB = x

hypotenuse = AB = c

[tex] cos(B) = \frac{x}{c} [/tex]

Make x the subject of formula.

[tex] c*cos(B) = x [/tex]

[tex] BD = x = c*cos(B) [/tex]

=>The Tangent ratio for the length of line segment BD = x, using TOA

θ = A

Adjacent = DB = x

hypotenuse = AD = b

[tex] tan(A) = \frac{x}{b} [/tex]

Make x the subject of formula.

[tex] b*tan(A) = x [/tex]

[tex] BD = x = b*tan(A) [/tex]

Answer:

Step-by-step explanation:

Edit:

y = (7/9)x = 3

9514 1404 393

Answer:

  y = 11/3x -3

Step-by-step explanation:

The slope of a line is the tangent of the angle it makes with the x-axis. The slope of the given line is 3/2, so the angle it makes with the x-axis is arctan(3/2) ≈ 56.310°. We want a line that makes an angle of arctan(1/3) ≈ 18.435° with the given line, so its slope will be ...

  tan(56.310° +18.435°) = tan(74.745°) = 11/3

The y-intercept of the desired line is given as (0, -3), so the equation of the line we want is ...

  y = 11/3x -3

_____

Additional comment

The desired slope can be found using the formula for the tangent of the sum of angles. However, simply adding the angles on a calculator saves a lot of arithmetic. (Full precision values must be used.)

The line we have found is at the desired angle measured CCW from the point of intersection with the given line. If you allow the line to have that angle measured CW from the point of intersection, then the slope will be 7/9, and the equation will be ...

  y = 7/9x -3

Answer:

Step-by-step explanation:

3/40 is the correct answer

Answer:

C

Step-by-step explanation:

So we already know that:

[tex]2^x=30[/tex]

And we want to find the value of:

[tex]2^{x+3}[/tex]

So, what you want to do here is to separate the exponents. Recall the properties of exponents, where:

[tex]x^2\cdot x^3=x^{2+3}=x^5[/tex]

We can do the reverse of this. In other words:

[tex]2^{x+3}=2^x\cdot 2^3[/tex]

If we multiply it back together, we can check that this statement is true.

Thus, go back to the original equation and multiply both sides by 2^3:

[tex]2^x(2^3)=30(2^3)\\[/tex]

Combine the left and multiply out the right. 2^3 is 8:

[tex]2^{x+3}=30(8)\\2^{x+3}=240[/tex]

The answer is C.

Answer:

the answer is c

Step-by-step explanation:

Answer:

1.691

Step-by-step explanation:

Standard error of the mean is expressed as SEM = S/√n

S is the population standard deviation

n is the sample size (number of observation)

Given S = 27 and n = 255

SEM = 27/√255

SEM = 27/15.97

SEM = 1.691

Hence the standard error of the mean is 1.691

=======================================================

Explanation:

Check out the diagram below.

Draw a vertical number line with 0 at the center. The positive values are above it, while the negative values are below it.

Between -15 and -16, closer to -16, plot the value -15.8 to indicate Ben's position. I have done so as the point B.

We move 4.2 units up to arrive at Cam's position

-15.8 + 4.2 = -11.6

So Cam is 11.6 meters below the surface of the water.

Answer:

[tex]\boxed{Slope = 0}[/tex]

Step-by-step explanation:

Hey there!

We’ll y = -2 creates a horizontal line,

and horizontal lines have a slope of zero.

Slope = 0

Hope this helps :)

Answer:

The slope of a linear equation is always the coefficient of the x value when the equation is solved for y. Since we don't have an x value on this expresion, the coefficient of x is 0. Hence, the slope of the line is 0.

Answer:

0.25meters

As 100cm=1metre

so, 25cm=25/100meter

=0.25metre

Step-by-step explanation:

If you like my answer than please mark me brainliest

The answer is 0.25 meters

Answer:

see below (I hope this helps!)

Step-by-step explanation:

9) We know that the perimeters of the square and triangle are equal so to find x, we can write:

4(x - 5) = x + x + 12

4x - 20 = 2x + 12

2x = 32

x = 16

10) To find the perimeter, we can substitute x = 16 into 4(x - 5) which would be 4(16 - 5) = 4 * 11 = 44.

Answer:

D) 1

Step-by-step explanation:

using the distributive property we have ax+a+bx-b-2=0. because the equation is true for all real x, ax=-bx. this means a-b-2=0 and a=-b. a-b-2=0 becomes a=b+2. then we substitute a for -b and get -b=b+2 which becomes 2b=-2 so b=-1. since a=-b, a=1

Answer:

72 58 62 38 44 66 42 49 76 52 ( arrange it!)

38 42 44 49 52 58 62 66 72 76 (done!)

Median: Find the number in the middle after we arranged, so the answer is (52+58)/2= 110/2 = 55

Mode : None (there is no number appear more than other number)

Mean = (38+42+44+49+52+58+62+66+72+76)/10

=559/100

=5,5

Hope it helps ^°^

Answer:

C

Step-by-step explanation:

You are looking at the domain which is on the K axis. It starts at 6 and ends at 11. The range J is 80 to 120

Step-by-step explanation:

A rotation about point A a reflection across the line containing AR a reflection across the line containing AQ a rotation about point R

Answer:

A rotation about point A

Step-by-step explanation:

I am taking the test if it is wrong I will add a comment

Answer:

slope = 6

tangent line y=6x-5

Step-by-step explanation:

Answer:

x = 3

Step-by-step explanation:

6 + 5x = 21

5x = 15

x = 3

I hope this helps

:)

If there is such a scalar function f, then

[tex]\dfrac{\partial f}{\partial x}=4y^2[/tex]

[tex]\dfrac{\partial f}{\partial y}=8xy+4e^{4z}[/tex]

[tex]\dfrac{\partial f}{\partial z}=16ye^{4z}[/tex]

Integrate both sides of the first equation with respect to x :

[tex]f(x,y,z)=4xy^2+g(y,z)[/tex]

Differentiate both sides with respect to y :

[tex]\dfrac{\partial f}{\partial y}=8xy+4e^{4z}=8xy+\dfrac{\partial g}{\partial y}[/tex]

[tex]\implies\dfrac{\partial g}{\partial y}=4e^{4z}[/tex]

Integrate both sides with respect to y :

[tex]g(y,z)=4ye^{4z}+h(z)[/tex]

Plug this into the equation above with f , then differentiate both sides with respect to z :

[tex]f(x,y,z)=4xy^2+4ye^{4z}+h(z)[/tex]

[tex]\dfrac{\partial f}{\partial z}=16ye^{4z}=16ye^{4z}+\dfrac{\mathrm dh}{\mathrm dz}[/tex]

[tex]\implies\dfrac{\mathrm dh}{\mathrm dz}=0[/tex]

Integrate both sides with respect to z :

[tex]h(z)=C[/tex]

So we end up with

[tex]\boxed{f(x,y,z)=4xy^2+4ye^{4z}+C}[/tex]

Answer:

let us do one night

Step-by-step explanation:

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