Im the diagram shown JKL~ MNP. Find MP and PN.

Answer:38

Step-by-step explanation:4+5×6+4=4+30+4=38

The ratio of its width to its length is; 5 :9.

The ratio of its length to its perimeter is; 9: 28.

1). From the task content, the land measures 4.5 km long and 2.5 km wide. Hence, the ratios is; 2.5: 4.5.

Therefore, we have; 5: 9 by expression as whole number ratios.

2) Since the perimeter of the rectangle is; 2(2.5+4.5) = 14.

The ratio of length to perimeter expressed simply is therefore; 9: 28.

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The equation will be like this,

6.89 + t = 8.00

t = 8 - 6.89

t = 1.11

tips = $1.11

6.89 + t = 8.00

To sum up the total amount of cash and coins you have, first, sort each invoice and coin by denomination. Create a separate stack for each denomination and count how many denominations or coins you have.

For each denomination of banknotes and coins, multiply the number you have by the denomination. For example, if you have 4 out of $ 10, multiply by 4x10 to get $ 40. If you have three $ 5 bills, multiply by 3x5 to get $ 15.

Sum the totals to calculate the total amount.

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The days of the year (excluding Sundays) paul attends school is 183 days

Months Paul skipped school = January, February, June, July August

= 31 + 28 + 30 + 31 + 31

= 151 days

Days he attend school excluding Sunday = Total days in a year - (Months Paul skipped school + Sundays)

= 365 - (151 + 31)

= 365 - 182

= 183 days

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Answer:240.5

Step-by-step explanation:

Angle C = 87°(calculated)

AB=C

AC=220=b

Sine laws c\sin87=220\66

c=240.5

Answer:

Step-by-step explanation:

[tex]\sf 1.1)\dfrac{Sin \ \theta-Cos \ \theta}{Sin \ \theta + Cos \ \theta}=\dfrac{(Sin \ \theta-Cos \ \theta)}{((Sin \ \theta + Cos \ \theta)}*\dfrac{(Sin \ \theta-Cos \ \theta)}{(Sin \ \theta-Cos \ \theta)}[/tex]

                           [tex]\sf = \dfrac{(Sin \ \theta-Cos \ \theta)^2}{Sin^2 \ \theta-Cos^2 \ \theta}\\\\=\dfrac{Sin^2 \ \theta+Cos^2 \ \theta-2Sin \ \theta \ Cos\ \theta}{(Sin \ \theta-Cos \ \theta)}\\\\\\\bf Identity: \ (a +b)^2= a^2 + b^2 - 2ab\\\\\\=\dfrac{1-2Sin \ \theta \ Cos \ \theta}{(Sin \ \theta-Cos \ \theta)} = LHS[/tex]

[tex]\sf 1.2) LHS = tan^2 \ x - Sin^2 \ x = \dfrac{Sin^2 \ x}{Cos^2 \ x}-Sin^2 \ x[/tex]

                                        [tex]\sf =\dfrac{Sin^2 \ x}{Cos^2 \ x}-\dfrac{Sin^2 \ x*Cos^2 \ x}{1*Cos^2 \ x}\\\\\\ = \dfrac{Sin^2 \ x - Sin^2 \ x*Cos^2 \ x}{Cos^2 \ x}\\\\\\= \dfrac{Sin^2 \ x *(1 -Cos^2 \ x)}{Cos^2 \ x}\\\\=\dfrac{Sin^2 \ x*Sin^2 \ x}{Cos^2 \ x} \\\\ \bf 1 - Cos^2 \ x = Sin^2 \ x\\\\= \dfrac{Sin^2 \ x}{Cos^2 \ x}*Sin^2 \ x\\\\=tan^2 \ x * Sin^2 \ x = RHS[/tex]

[tex]\sf 1.3) LHS = \dfrac{1-Cos \ x}{Sin \ x}-\dfrac{Sin \ x}{1+Cos \ x} =\dfrac{(1-Cos \ x)(1+Cos \ x)}{Sin \ x*(1+Cos \ x)}-\dfrac{Sin \ x*Sin \ x}{(1+Cos \ x)*Sin \ x}\\[/tex]

              [tex]\sf =\dfrac{1 - Cos^2 \ x}{Sin \ x*(1+Cos \ x)}-\dfrac{Sin^2 \ x}{Sin \ x*(1+Cos \ x)}\\\\=\dfrac{Sin^2 \ x}{Sin \ x*(1+Cos \ x)} - \dfrac{Sin^2 \ x}{Sin \ x*(1+Cos \ x)}\\\\=\dfrac{Sin^2 x - Sin^2 \ x}{Sin \ x*(1+Cos \ x)} \\\\= 0 = RHS[/tex]

[tex]\sf 1.4) LHS = Sin x - \dfrac{1}{Sin \ x + Cos \ x}+Cos \ x \\[/tex]

              [tex]\sf = \dfrac{Sin \ x *(Sin \ x + Cos \ x) - 1 + Cos \ x * (Sin \ x + Cos \ x)}{Sin \ x + Cos \ x }\\\\\\= \dfrac{Sin \ x * Sin \ x + Sin \ x*Cos \ x -1 + Cos \ x*Sin \ x + Cos \ x*Cos \ x}{Sin \ x + Cos \ x}\\\\\\=\dfrac{Sin^2 \x + Sin \ x \ Cos \ x - 1 + Cos \ x \ Sin \ x + Cos^2 \x}{Sin \ x + Cos \ x}\\\\=\dfrac{Sin^2 \ x + Cos^2 \ x - 1 + Sin \ xCos \x +Sin \ x Cos \ x}{Sin \ x + Cos \ x}\\\\= \dfrac{1 - 1 +2Sin \ x Cos \ x}{Sin \ x + Cos \ x}\\\\= \dfrac{2Sin \ x Cos \ x}{Sin \ x + Cos \ x}[/tex]

The equivalent expression of [tex](1 + \frac{1}{y}) \div (1-\frac 1y)[/tex] is [tex]\frac{y + 1}{y-1}[/tex]

The fraction is given as:

[tex](1 + \frac{1}{y}) \div (1-\frac 1y)[/tex]

Take the LCM

[tex]\frac{y + 1}{y} \div \frac{y-1}y[/tex]

Express as products

[tex]\frac{y + 1}{y} \times \frac{y}{y-1}[/tex]

Evaluate the product

[tex]\frac{y + 1}{y-1}[/tex]

Hence, the equivalent expression of [tex](1 + \frac{1}{y}) \div (1-\frac 1y)[/tex] is [tex]\frac{y + 1}{y-1}[/tex]

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The density in pounds per cubic meter is 83 pounds per cubic metre.

The density is mass of a unit volume of a material substance.

In other words, density is the ratio between mass and volume or mass per unit .

Therefore, density can be represented mathematically as follows:

density = mass / volume

Hence,

mass = 5 ounces

5 ounces = 0.3125 pounds

1 gallon = 0.00378541 pounds

Therefore,

density = 0.3125 / 0.00378541

density = 82.5538052681

density = 83 pounds per cubic metre.

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Answer:

Domain:[-4,∞)

Range:[0, ∞)

Thus, choice C is the exact answer

Answer:

{x:x is a real number}

Since any value can replace x to give an integer.

{x:x is a real number}

The standard equation of the circle is x² + y² + 8x - 9 = 0 if the circle with center at (-1,-4) that passes through the point (-4,0).

According to the question,

The circle with center at (-1,-4) that passes through the point (-4,0).

To find the radius of the circle:

Radius r = √[(-4 - (-1))² + (0- (-4))²]

=√(-4+1)² + (4)²

=√9+16

=√25

=5.

In order to find the standard equation of the circle is

(x - (-4))² + (y - (0))² = (5)²

(x + 4)² + (y )² = 25

x² + 8x + 16 + y² = 25

x² + y² + 8x + 16 = 25

x² + y² + 8x = 25 - 16

x² + y² + 8x = 9

x² + y² + 8x - 9 = 0

Hence, the standard equation of the circle is x² + y² + 8x - 9 = 0.

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Answer:

[tex]y = -\frac{1}{2} x+4[/tex]

Step-by-step explanation:

Standard form for equation of line: y = mx + c

where m = gradient or slope

c = y-intercept

From the question we know that,

x = 2

y = 3

m = - 0.5

We will substitute these values into the equation to find c.

3 = (-0.5)(2) + c

3 = - 1 + c

c = 3 + 1 = 4

Therefore the equation of this line is [tex]y = -\frac{1}{2} x+4[/tex]

Using the concept of vertical and horizontal asymptotes, it is found that the function will have a horizontal asymptote at y = 2 and a vertical asymptote at x = 1 for a = -1 and m = 1.

In this problem, the function is:

[tex]f(x) = \frac{2x^m}{x + a}[/tex]

It has a vertical asymptote at x = 1, hence:

x + a = 0

1 + a = 0

a = -1

It has a horizontal asymptote at y = 2, hence:

[tex]\lim_{x \rightarrow \infty} f(x) = 2[/tex]

[tex]\lim_{x \rightarrow \infty} \frac{2x^m}{x + a} = 2[/tex]

[tex]\lim_{x \rightarrow \infty} \frac{2x^m}{x} = 2[/tex]

[tex]2^{m-1} = 2[/tex]

Then, since we want to simplify, the exponents at the numerator and the denominator have to be equal, hence m = 1.

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The number of songs that Deante' would have downloaded during month 9 is 58 songs.

A regression line is a statistical line that best describes the behavior of a data set and such, it is a line that best fits a set of data.

By using Microsoft excel to plot the data on a scatter plot, we can logically deduce that line of best fit for the songs downloaded is given by:

y = 2.03x + 39.7

Thus, the number of songs that Deante' would have downloaded during month 9 is:

y = 2.03(9) + 39.7

y = 18.27 + 39.7

y = 57.97 ≈ 58 songs.

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Answer:

A) ŷ = 2.03X + 39.73

B) 58

Step-by-step explanation:

A line of best fit is a line drawn on a scatter plot that shows the trend and the best estimation of the relationship between x and y.

After graphing it, it's easy to find the point at which x and why intersect along the line where x is nine.

Using the equation, just replace x with nine and solve.

Answer:

53

Step-by-step explanation:

Let yazid's score be x

x + x + 17 + 2x = 161

4x + 17 = 161

4x = 144

x = 36

jack = x + 17

jack = 53

Answer:

Jack:  36

Bonus:  Yazid:  53 and Susan:  72

Step-by-step explanation:

Let J, Y, and K stand for Jack, Yazin, Susan's scores.

We are told that:

J = Y + 17  [Jack scored 17 marks more than Yazid]

S = 2Y  [Susan scored twice Yazid's score]

J + Y + S = 161  [total score is 161]

Substitute the first two expressions into the last equation:

J + Y + S = 161

(Y+17) + Y + (2Y) = 161

4Y = 144

Y = 36

Use Y = 36 to find the other scores:

J = Y + 17

J = 36 + 17

J = 53

S = 2Y

S = 2*(36)

S = 72

CHECK:

Does 36+53+72 = 161?

YES

Answer:

(2x + 20) ft^2.

Step-by-step explanation:

Area  = length * width

         =   2 * (x + 10)

         = (2x + 20) ft^2.

Let [tex]y=\cos(2x)[/tex], with first two derivatives

[tex]Dy = -2\sin(2x)[/tex]

[tex]D^2y = -4\cos(2x)[/tex]

Consider the linear ODE

[tex]aD^2y + bDy + cy = 0[/tex]

Substitute [tex]y[/tex] and its derivatives and solve for the unknown coefficients [tex]a,b,c[/tex].

[tex]-4a\cos(2x) - 2b\sin(2x) + c\cos(2x) = 0[/tex]

[tex]\implies \begin{cases}-4a+c=0 \\ -2b=0 \end{cases}[/tex]

[tex]\implies b=0 \text{ and } c= 4a[/tex]

Then the minimal ODE with this solution is

[tex]aD^2y + 4ay = 0 \implies \boxed{D^2y + 4y = 0}[/tex]

Answer:

[tex]\huge\boxed{\sf 81x^4 - 16y^4}[/tex]

Step-by-step explanation:

= (3x - 2y)(3x + 2y)(9x² + 4y²)

= [(3x)² - (2y)²] (9x² + 4y²)

= (9x² - 4y²)(9x² + 4y²)

Using the above formula again

= (9x²)² - (4y²)²

[tex]\rule[225]{225}{2}[/tex]

When preparing a representative sample from a list of 200 customers who complained about errors in their statements, a systematic sample might select every tenth customer for review.

Systematic random sampling is known to be a form of a random sampling method that needs one to select samples using a system of intervals where one has ranges of numbered population.

Note that When preparing a representative sample from a list of 200 customers who complained about errors in their statements, a systematic sample might select every tenth customer for review.

See options below

a. stratified sample

b. comprehensive sample

c. random sample

d. Systematic sample

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The length of the belt around the two pulleys is approximately 49.2 centimeters.

In this question we must determine the perimeter of a belt around two pulleys, whose centers are 10 centimeters apart. This perimeter is the sum of part of the circumference of small pulley, part of the circumference of the big pulley and two times the segment tangent to the two pulleys.

Now we proceed to determine the parts of the perimeter of the belt:

Big pulley

s' = (214.92° / 180°) · π · (6 cm)

s' ≈ 22.506 cm

Small pulley

s'' = (145.08° / 180°) · π · (3 cm)

s'' ≈ 7.596 cm

Tangent segments

l = (10 cm) · sin 72.54°

l ≈ 9.539 cm

Lastly, the perimeter of the belt is:

L = s' + s'' + 2 · l      (1)

L = 22.506 cm + 7.596 cm + 2 · (9.539 cm)

L = 49.180 cm

The length of the belt around the two pulleys is approximately 49.2 centimeters.

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The volume of the cuboid is 132 cubic inches.

Given length of cuboid 7 1/3 inches, breadth being 6 2/3 inches , height being 2 7/10 inches.

Volume is amount of liquid a container can hold in its capacity. Cuboid is a 3 dimensional figure having length , breadth and height.Volume of cuboid is the product of length, breadth and height of cuboid.

We have to calculate volume of cuboid.

We have to make a simple fraction showing length , breadth and height.

Length=(3*7+1)/3=22/3

Breadth=(3*6+2)/3=20/3

Height=(10*2+7)/10=27/10

Volume=22/3*20/3*27/10

=11880/90

=132 cubic inches.

Hence the volume of cuboid having length of 22/3 inches, breadth of 20/3 inches and height of 27/10 is 132 cubic inches.

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Question is incomplete as it should include figure.

The dimension of the length and width of the rectangle with the given perimeter are 33ft and 16.5ft respectively.

Perimeter of rectangle is expressed as;

P = 2( l + w )

Given that;

We substitute into the formular above.

P = 2( l + w )

99ft = 2( x + 2x )

99ft = 2x + 4x

99ft = 6x

x = 99ft/6

x = 16.5ft

Width = x = 16.5ft

Length = 2x = 2( 16.5ft ) = 33ft

Therefore, the dimension of the length and width of the rectangle with the given perimeter are 33ft and 16.5ft respectively.

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Answer:

b = 21

Step-by-step explanation:

In general for these trig problems look for the angle whose measure you are given or need to find and for the sides you are given lengths or whose sides you need to find.

Given:

side AB = 10 cm

m<C = 25°

Find:

side AC

The angle of interest here is <C whose measure is 25°.

Now look at the given side and the side you are looking for with respect to angle C, the given angle.

For angle C, AC is the adjacent leg.

For angle C, AB is the opposite leg.

Which trig function relates the opposite leg to the adjacent leg?

It is the tangent, since, in general, tan X = opp/adj.

tan C = opp/adj

tan 25° = AB/AB

tan 25° = 10 cm/b

Solve for b.

b × tan 25° = 10 cm

b = 10 cm / tan 25°

Using your calculator, divide 10 by the tangent of 25°.

b = 21.44506...

Answer: b = 21

Answer:

[tex]b = \bf 21 \space\ cm[/tex]

Step-by-step explanation:

• To solve for a side using SOH CAH TOA, first check the angle whose measure is given.

In this case, we know ∠ C is 25°.

• Next we have to figure out the relationships between the given angle and two sides: one side whose length we know, and the other whose length we have to find.

In this case, the side opposite to ∠ C is known to be 10 cm, and the side adjacent to ∠ C is AC, whose length, b, we have to find.

• The trigonometric ratio that relates the adjacent and opposite sides of an angle is tan, where:

[tex]\boxed{tan \theta = \frac{opposite}{adjacent} }[/tex] .

We can use this relationship to calculate the value of b:

⇒ [tex]tan (25 \textdegree) = \frac{10}{b}[/tex]

Solving for b:

⇒ [tex]b \cdot tan (25 \textdegree) = 10[/tex]

⇒ [tex]b = \frac{10}{tan (25 \textdegree)}[/tex]

⇒ [tex]b = 21.45[/tex]

⇒ [tex]b \approx \bf 21 \space\ cm[/tex]  (rounded to the nearest whole number)

The natural number , n is 30

Given;

GCF(n, 70) = 10

LCM(n, 70) = 210

We have that;

LCM(A,B) x GCF(A, B)= A x B

Then,

(n, 70) = n × 70 = 70n

10 × 210 = 2100

Equate the two expressions

70n = 2100

n = [tex]\frac{2100}{70}[/tex]

n = [tex]30[/tex]

Thus, the natural number , n is 30

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The correlation coefficient r between the two data sets is 0.33

From the table of values, we make use of the following representations:

Using the above representations, we can now plot our data values in the Excel software

From the Excel application, we have the following summary:

X Values

∑ = 424

Mean = 21.2

∑(X - Mx)2 = SSx = 101.2

Y Values

∑ = 151.8

Mean = 7.59

∑(Y - My)2 = SSy = 8.238

X and Y Combined

N = 20

∑(X - Mx)(Y - My) = 9.54

R Calculation

r = ∑((X - My)(Y - Mx)) / √((SSx)(SSy))

This gives

r = 9.54 / √((101.2)(8.238))

Evaluate

r = 0.3304

Approximate

r = 0.33

Hence, the correlation coefficient r between the two data sets is 0.33

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Answer:Divide your speed in feet per minute by 60

Step-by-step explanation:

10u + t is the expressions shows the value of the reversal of digits in a two digit number, t = the tens digit and u = the ones digit. This can be obtained by multiplying 10 with the tens digit and adding unit digit.

Given that, in a two digit number,

t = the tens digit

u = the ones digit

The expression for the digit will be ,

10×t + u = 10t + u

The value of its reversal,

u = the tens digit

t = the ones digit

10×u + t = 10u + t is the required expression

For example,

37 = 10×3 + 7 = 30 + 7 and its reverse 73 = 10×7 + 3 = 70 + 3

Hence 10u + t is the expressions shows the value of the reversal of digits in a two digit number, t = the tens digit and u = the ones digit.

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The perimeter of the quadrilateral illustrated is 30cm.

The information is incomplete. Therefore, an overview will be given. It should be noted ha perimeter simply means the addition of the sides given.

Let's assume that that we've a rectangle with length and width of 10 and 5cm.

The perimeter will be:

= 2(l + w)

= 2(10 + 5)

= 30cm

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Putting the other player's king in check is always a good move. true

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Using it's formula, the area of the right triangle is of 750 inches squared.

The area of a right triangle is given by half the multiplication of the two legs, which are the two smaller sides.

In this problem, the two legs are 25 inches and 60 inches, hence the area of the triangle is:

A = 0.5 x 25 x 60 = 750 inches².

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