In the absence of a strong magnetic field), what is the chief factor that determines what type of electromagnetic radiation objects give off:____.

Answers

Answer 1

The chief factor that determines what type of electromagnetic radiation that objects give off in the absence of a strong magnetic field is their temperature.

What is the radioactive activity?

The radioactive activity refers to the energy that a atomic nucleus can release in a given period of time due to the emission of different types of radiation.

This activity (radioactive activity) increases as temperature rises due to a higher collision of subatomic particles that form molecules.

In conclusion, the chief factor that determines what type of electromagnetic radiation in the absence of a magnetic field is temperature.

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Related Questions

Astronomers have realized that the surface of ida is older than the surface of gaspra. How do they measure this?

Answers

From counting craters on each asteroids , astronomers have realized that the surface of ida is older than the surface of gaspra.

Ida, and Gaspra are three objects located in the asteroid belt between Mars and Jupiter.

Crater counting is a method for estimating the age of a planet's surface based upon the assumptions that when a piece of planetary surface is new, then it has no impact craters; impact craters accumulate after that at a rate that is assumed known.

Counting how many craters of various sizes there are in a given area allows determining how long they have accumulated and consequently, how long ago the surface has formed. Hence , from counting craters on each asteroids ,astronomers have realized that the surface of ida is older than the surface of gaspra.

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A stone ‘X’ of mass 2 kg is at the height of 20m in two minutes, calculate the power delivered. [g=10 m/s-2]

Answers

400 J power will be delivered by lifting a stone of mass 2 kg at the height of 20m in two minutes.

What is power?

The quantity of energy transferred or transformed per unit of time is known as power. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as an activity in ancient writings. A scalar quantity is a power.

Work completed and time is linked in the power equation. Since forces may move objects and we know that forces perform work, we might anticipate that by understanding the power, we can gain insight into how a body moves through time. This outcome may be especially beneficial.

Given that, a stone ‘X’ of mass 2 kg is lifted to the height of 20m in two minutes, and g=10 m/s-2

Power Delivered = Work done in lifting the stone

Work Done = Potential energy = mgh

Work done = 2 × 10 × 20

Work done = 400 J

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A loop rests in the plane of a page of textbook while a magnetic field is directed into the page. A clockwise current is induced.

Answers

(b) when the magnetic field gets stronger.

correct option :

When a loop rest in the plane of the page and magnetic field is directed into the page then we will apply here right hand thumb rule in which thumb represent the direction of magnetic field and curling fingers represent direction of induced current. So, in this case the direction of magnetic field is into the page and curling fingers shows induced current in clockwise direction.

  Thus, option (b) is correct.

Incorrect options:

   option (A) is incorrect because when magnetic field will change  

     according to flux.

   option (C) is incorrect because field is stronger so it does not matter

     size of loop increases or decreases.

   option (D) is incorrect because it moves any other side the field will be

     stronger.

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[Your question is incomplete, but most probably your full question was-Check all that apply:

A. when the magnetic field is tilted so it is no longer perpendicular to the page

B. when the magnetic field gets stronger

C. when the size of the loop decreases

D. when the loop is moved sideways across the page]

The speed of water flowing through a hose increases from 2.05 m/s to 31.4 m/s as it goes through the nozzle. What is the pressure in the hose, assuming the absolute pressure in the nozzle is atmospheric pressure

Answers

The pressure in the hose as the speed of water changes from 2.05 m/s to 31.4 m/s as it goes through the nozzle is 5.92 × 10⁵ N/m².

Given:

The flow of water through the hose initially, v₁ = 2.05 m/s

The flow of water through the hose initially, v₂ = 31.4 m/s

Calculation:

From Bernoulli's equation we have:

P₁ + 1/2 ρv₁² + ρgh₁ = P₂ + 1/2 ρv₂² + ρgh₂

where P₁ is atmospheric pressure

           P₂ is the pressure in the hose

           ρ is the density of the fluid

           h₁ is the initial height

           h₂ is the final height

           v₁ is the initial velocity of the fluid

           v₂ is the final velocity of the fluid  and

           g is the acceleration due to gravity

Re-arranging the above equation we get:

P₂ = P₁ + 1/2 ρ(v₁²-v₂²) + ρg (h₁-h₂)

Applying values in the above equation we get:

P₂ = P₁ + 1/2 ρ(v₁²-v₂²) + ρg (0)

    = (1.01 × 10⁵ Pa)+ 1/2 (10³ g/m³) [(31.4m/s)²-(2.05 m/s)²]

    = (1.01 × 10⁵ Pa)+ 1/2 (10³ g/m³) [981.7575]

    = (1.01 × 10⁵ Pa)+ (4.91 × 10⁵ Pa)

    = 5.92 × 10⁵ Pa

    = 5.92 × 10⁵ N/m²

Therefore, the pressure in the hose is 5.92 × 10⁵ N/m².

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A proton exits the cyclotron 1. 0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1. 0 ms ?.

Answers

The diameter of the largest orbit just before the protons exit the cyclotron is 39 cm.

The number of orbits completed by the proton during this 1.0 ms is 14000 revolutions.

The kinetic energy for the protons can be computed by using the formula:

   K.E = 1/2mv²

mv² = 2 K.E

v = sqrt( 2*KE / M)

the kinetic energy of the medical isotopes = 6.5 MeV

substituting the values,

v = sqrt( 2* 6.5* 1.6* 10^-13 / 1.67* 10^-27 )

v = 3.53 × 10⁷ m/s

The radius of the orbit can be estimated by using the formula:

mv² / R = qvB

r = q*v / mv²

r = ( 1.67* 10^-27 * 3.53 × 10⁷ ) / ( 1.9* 1.6* 10^-19 )

r = 0.19415 m

Since diameter (D) = 2r,

D= 2(0.19415  m)

D= 0.39 m

D≅ 39 cm

The time period to complete a revolution around the spiral trajectory is:

T = 2πr / v

T = 2*3.14* 0.1941 / 3.53*10^7

T = 0.7 × 10⁻⁷ s

Finally, the number of orbits that the proton does to complete the revolution in 1 ms is:

n = t / T

n = 10^-3 / (0.7*10^-7)

n = 14285.71

n ≅ 14000 revolutions

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Your question is incomplete, but most probably full question was:

A medical cyclotron used in the production of medical isotopes accelerates protons to 6.5 MeV. The magnetic field in the cyclotron is 1.9 T.

(a) What is the diameter of the largest orbit, just before the protons exit the cyclotron? Express your answer with the appropriate units. d = 57 cm Previous

(b) A proton exits the cyclotron 1.0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1.0 ms?

Jan is holding an ice cube. What causes the ice to melt?

Thermal energy from the ice is transferred to the air.
Thermal energy from Jan’s hand is transferred to the ice.
The air absorbs thermal energy from Jan’s hand.
Jan’s hand absorbs thermal energy from the ice.

Answers

The ice melts because Thermal energy from Jan’s hand is transferred to the ice.

What is thermal energy?

Thermal energy is the energy due to temperature difference.

Thermal energy flows from hotter to colder bodies.

The ice Jan is holding melts because heat is transferred from his hands t the ice.

In conclusion, thermal energy flow causes melting.

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Answer:

its b

Explanation:

because the heat from your hand makes the ice melt!

Vega, the brightest star in the constellation lyra, has a parallax angle of approximately 0.13 arcseconds. approximately how far away is vega from the sun?

Answers

Vega, the brightest star in the constellation lyra, has a parallax angle of approximately 0.13 arcseconds,  approximately  Vega will be 25.076 Light year or 7.692 Parsec away from the sun

The parallax angle is the angle between the Earth at one time of year, and the Earth six months later, as measured from a nearby star.

Mathematically it can be understood as that the parallax angle is the angle which is taken from a point at one time on the earth and again after six months later from the same point on the earth. The parallax angle is the semi-angle of inclination between the two lines to sight.

Stellar parallax is the basis for the parsec, which is the distance from the Sun to an astronomical object that has a parallax angle of one arcsecond.

Distance (in parsec) = 1 / (parallax angle ( arcsec))

given

parallax angle = 0.13 arcseconds

Distance (in parsec) = 1/ 0.13 = 7.692 Parsec

if 1 Parsec = 3.26 Light year

So, 7.692 Parsec will be equal to =  3.26 * 7.692 = 25.076 Light year

                                                        ≈ 25.076 Light year

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As the number of protons in an atom’s nucleus increases

a) The overall stability of the atom decreases

b) The number of electrons must increase to maintain the atom’s overall neutral charge

c) The more neutrons are required to stabilize the nucleus

d) All of the above

Answers

As the number of protons in an atom’s nucleus increases, the number of electrons must increase to maintain the atom’s overall neutral charge; option B.

What is atomic number of an element?

Atomic number is the number of protons present in the nucleus of an atom.

The atomic number of atoms of elements increase with increase in atomic number.

In conclusion, atomic number increases the size down a group and decreases atomic size across a period.

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A boy moves down a waterslide from a height of 10 meters. what is his velocity when he hits the water at the bottom of the slide?

Answers

The velocity of the boy when he hits the water at the bottom of the slide is 14 m/s.

Velocity of the boy at the bottom of the slide

The velocity of the boy when he hits the water at the bottom of the slide is calculated from the principle of conservation of energy.

K.E = P.E

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

h is height of the boyg is acceleration due to gravity

v = √(2 x 9.8 x 10)

v = 14 m/s.

Thus, the velocity of the boy when he hits the water at the bottom of the slide is 14 m/s.

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Earth orbits the sun at an average circular radius of about 149.60 million kilometers every 365.26 Earth days.
a) Determine the Earth’s average orbital speed expressed in kilometers per hours.
b) Based on the information given in this question, calculate the approximate mass of the Sun.

Answers

The Earth’s average orbital speed expressed in kilometers per hours is 107225.5 Km/hr and the mass of the sun is 2.58 x [tex]10^{24}[/tex] Kg

Relationship between Linear and angular speed

Linear speed is the product of angular speed and the maximum displacement of the particle. That is,

V = Wr

Where

V = Linear speedW = Angular speedr = Radius

Given that the earth orbits the sun at an average circular radius of about 149.60 million kilometers every 365.26 Earth days.

a) To determine the Earth’s average orbital speed, we will make use of the below formula to calculate angular speed

W = 2[tex]\pi[/tex]/T

W = (2 x 3.143) / (365.26 x 24)

W = 6.283 / 876624

W = 7.2 x [tex]10^{-4}[/tex] Rad/hr

The Earth’s average orbital speed V = Wr

V = 7.2 x  [tex]10^{-4}[/tex] x 149.6 x [tex]10^{6}[/tex]

V = 107225.5 kilometers per hours.

b) Based on the information given in this question, to calculate the approximate mass of the Sun, we will use Kepler's 3rd law

M = (4[tex]\pi ^{2}[/tex][tex]r^{3}[/tex]) / G[tex]T^{2}[/tex]

M = (4 x 9.8696 x 3.35 x [tex]10^{24}[/tex]) / (6.67 x [tex]10^{-11}[/tex] x 7.68 x [tex]10^{11}[/tex])

M = 1.32 x [tex]10^{26}[/tex] / 51.226

M = 2.58 x [tex]10^{24}[/tex] Kg

Therefore, the Earth’s average orbital speed expressed in kilometers per hours is 107225.5 Km/hr and the mass of the sun is 2.58 x [tex]10^{24}[/tex] Kg

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Why stars are shows like twinkling in the sky’s!
Reply please!

Answers

Answer:

As light from a star races through our atmosphere, it bounces and bumps through the different layers, bending the light before you see it. Since the hot and cold layers of air keep moving, the bending of the light changes too, which causes the star's appearance to wobble or twinkle.

What is the tangential speed of a lug nut on a wheel of a car if the lug nut is located 0.114 m from the axis of rotation; and the wheel is rotating at 6.53 rev/sec

Answers

The tangential speed of a lug nut on a wheel of a car will be 4.68 m/s

Given:

Distance of lug nut = 0.114 m

wheel is rotating at speed = 6.53 rev/sec

To Find:

tangential speed of a lug nut

Solution: Tangential velocity is the linear speed of any object moving along a circular path. A point on the outside edge of a turntable moves a greater distance in one complete rotation than a point near to the center

Vr = r.ω

(0114 m)(41.03 rad/s) = Vr

Vr = 4.68 m/s

Hence, tangential speed of lug nut on wheel of car is 4.68 m/s

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A man pushes a box across a floor. as he increases the force he applies horizontally to the box

a) the kinetic friction decreases
b) the kinetic friction may increase or decrease depending on the velocity of the box
c) the kinetic friction remains the same
d) the kinetic friction increases

Answers

When a man pushes a box across a floor, as he increases the force he applies horizontally to the box, then the kinetic friction remains the same.

To find the answer, we need to know about friction.

What is friction?Whenever a body moves, over the surface of another body, a force comes into play which acts parallel to the surface of contact and opposes the relative motion. This opposing force is called friction.There are two frictions acting on a surface.Static friction:  It come into play between two bodies before when it starts moving. Self-adjusting force and the max value of it is called limiting static friction.Kinetic friction:  It come into play between two bodies when it starts moving. It is not a self-adjusting force.As we increase applied force, kinetic friction will remain same.

Thus, we can conclude that, kinetic friction remains the same when we increase the applied force.

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As a guy pushes a box across a floor, the kinetic friction stays constant no matter how much force is applied on the box horizontally.

We must understand friction if we are to find the solution.

Describe friction?A force that works parallel to the surface of contact and opposes the relative motion is always present whenever a body moves over the surface of another body. Friction is the name for this opposing force.On a surface, there are two frictions operating.Static friction: It occurs between two bodies before motion is initiated. Limiting static friction is the term used to describe the maximum amount of self-adjusting force.As soon as two bodies begin to move, kinetic friction is triggered. It is not a force that adjusts itself.The amount of kinetic friction will not change when we apply more force.

We can therefore draw the conclusion that kinetic friction does not change as the applied force is increased.

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Work is being done in "which of these situations? All motions
are at a constant velocity (including velocity = zero).
O Jessica pushes a 25 kilogram cart a distance of 10 meters.
O
A weightlifter holds a 100 k/fogram barbell over his head.
O Bane carries a 20 kilogram box a distance of 50 meters.
O Ali is trying to push a truck away from the parking lot.

Answers

Work is being done when Jessica pushes a 25 kilogram cart a distance of 10 meters and Bane carries a 20 kilogram box a distance of 50 meters.

What is Work ?

Work is the product of force and distance in the direction of the force. And the S.I unit of work is Joule

Looking at the given options one by one;

O Jessica pushes a 25 kilogram cart a distance of 10 meters. Work is done by Jessica. The work done = 25 x 10 x 10 = 2500 Joules

O A weightlifter holds a 100 kilogram barbell over his head. The weightlifter does no work.

O Bane carries a 20 kilogram box a distance of 50 meters. Bane does work. The work done = 20 x 10 x 10 = 2000 Joules

O Ali is trying to push a truck away from the parking lot. Since there is no movement, there is no work done.

Therefore, Work is being done when Jessica pushes a 25 kilogram cart a distance of 10 meters and Bane carries a 20 kilogram box a distance of 50 meters.

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When a 3.0 N weight is attached to a vertical coil spring, it stretches 5.0 cm. What weight would be required to stretch the spring 12.5 cm?
Group of answer choices

a. 7.5 N

b. 15 N

c. 4.5 N

d. 1.2 N

Answers

The weight required to stretch the spring 12.5 cm is 7.5 N (Option A)

Data obtained from the questionInitial weight (W₁) = 3 N Initial Length (L₁) = 5 cmNew length (L₂) = 12.5 cmNew Weight (W₂) =?

How to determine the new weight

The new weight required to stretch the spring can be obtained as follow:

W₁ / L₁ = W₂ / L₂

3 / 5 = W₂ / 12.5

Cross multiply

W₂ × 5 = 3 × 12.5

Divide both sides by 5

W₂ = (3 × 12.5) / 5

W₂ = 7.5 N

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Why are temperatures in the thermosphere not strictly comparable to those experienced near earth's surface?

Answers

Temperatures in the thermosphere are not strictly comparable to those experienced near Earth's surface because the gases of the thermosphere are moving at very high speeds, and the temperature is very high.

The thermosphere lies among the exosphere and the mesosphere. “Thermo” way warmness and the temperature in this layer can reach as much as 4,500 tiers Fahrenheit. in case you have been to hang around inside the thermosphere, though, you'll be very cold because there are not sufficient fuel molecules to transfer the warmth to you.

The thermosphere is the outer layer of the Earth's surroundings, extending from about 53 miles to greater than 370 miles above the surface. The temperature increases rapidly in this layer due to the absorption of huge quantities of incoming excessive electricity sun radiation by using atoms of nitrogen and oxygen.

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Two worlds in the outer solar system that seem remarkably similar to each other are:

Answers

Two worlds in the outer solar system that seem remarkably similar to each other are: Triton and Pluto

The outer solar system comprises the next four planets and everything beyond the planet Neptune but within the gravitational pull of the Sun. The Kuiper Belt and the Oort Cloud are also parts of the outer region.

Triton is only slightly larger than Pluto. Both worlds have similar surface materials, such as nitrogen, methane and carbon monoxide. Their diameters, masses and densities are also similar. Both Triton and Pluto may also have originated within the Kuiper Belt. Triton is thought to be originally a Kuiper Belt Object that was captured by Neptune's gravity.

Because Triton and Charon-Pluto are both from the Kuiper belt they are both made of similar materials such as nitrogen, methane, carbon dioxide and water ice. Both  have large cores that are made primarily of rock with mantles of water ice and crusts made of frozen nitrogen. Neither of them have a magnetic field.

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If you will be rinsing your regulator after removing it from the cylinder, you must make sure that the ______ ______ is firmly in place. Select one: Mouthpiece plug Alternate-air-source retainer Dust cap None of the above

Answers

If you will be rinsing your regulator after removing it from the cylinder, you must make sure that the dust cap is firmly in place.

What is Dust cap?

A dust cap is a gently curved dome mounted either in concave or convex orientation over the central hole of most loudspeaker diaphragms.

Thus, if you will be rinsing your regulator after removing it from the cylinder, you must make sure that the dust cap is firmly in place.

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The hypothetical upper limit to the mass a star can be before it self-destructs due to the massive amount of fusion it would produce. Stars over this limit tend to be surrounded by massive nebulae of material blasted off of their surfaces.

Answers

The hypothetical upper limit to the mass a star can be before it self-destructs due to the massive amount of fusion it would produce is apparently as a result of Eddington luminosity

What are stars?

Stars are a fixed luminous point in the sky which is a large and remote incandescent body

So therefore, the hypothetical upper limit to the mass a star can be before it self-destructs due to the massive amount of fusion it would produce is apparently as a result of Eddington luminosity

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Calculate the net force on particle q1. First, find the direction of the force particle q2 is exerting on particle q1. Is it pushing to the right, or to the left?

Answers

The net force on particle particle q1 is 13.06 N towards the left.

Force on q1 due to q2

F(12) = kq₁q₂/r₂

F(12) = (9 x 10⁹ x 13 x 10⁻⁶ x 7.7 x 10⁻⁶)/(0.25²)

F(12) = -14.41 N  (towards left)

Force on q1 due to q3

F(13) = (9 x 10⁹ x 7.7 x 10⁻⁶ x 5.9 x 10⁻⁶)/(0.55²)

F(13) = 1.352 N (towards right)

Net force on q1

F(net) = 1.352 N - 14.41 N

F(net) = -13.06 N

Thus, the net force on particle particle q1 is 13.06 N towards the left.

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Answer:

its +

Explanation:

A bowling ball accidentally falls out of the cargo bay of an airliner as it flies along in a horizontal direction. As seen from the ground, which path would the bowling ball most closely follow after leaving the airplane?

Answers

The path the bowling ball would most closely follow after leaving the airplane is horizontal direction.

Path of the bowling ball

Based on the law of inertia, which is the reluctance of an object to stop moving once in motion or start moving when it is at rest.

The bowling ball will maintain the path of the airline in the first few seconds of fall, after which it will change its path to vertical direction.

Thus, the path the bowling ball would most closely follow after leaving the airplane is horizontal direction.

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Consider the following forces. (1) frictional (2) gravitational (3) tension (4) strong nuclear (5) normal (6) electroweak which of the forces listed are considered fundamental forces?

Answers

The forces listed are considered fundamental forces (2) gravitational (4) strong nuclear (6) electroweak.

Fundamental force, also called fundamental interaction, in physics, is any of the four primary forces—gravitational, electromagnetic, sturdy, and weak—that govern how gadgets or particles interact and how certain particles decay. All of the regarded forces of nature may be traced to those essential forces.

Now, physicists say they have discovered viable symptoms of a fifth essential force of nature. The findings come from studies performed at a laboratory near Chicago. The four fundamental forces govern how all of the objects and particles inside the Universe engage with each other.

The strong nuclear pressure pulled definitely and negatively charged quarks collectively to form undoubtedly charged protons and neutrally charged neutrons. The strong nuclear force also binds protons and neutrons within the nucleus of atoms. The weak nuclear force enabled complicated atoms to form through nuclear fusion.

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How stars are twinkling in the sky?

Answers

Answer:

As light from a star races through our atmosphere, it bounces and bumps through the different layers, bending the light before you see it. Since the hot and cold layers of air keep moving, the bending of the light changes too, which causes the star's appearance to wobble or twinkle.

When a person is standing upright, the weight of anything being lifted and carried in the hands is first reflected onto the:

Answers

Pelvic girdle

In human anatomy, the pelvis is a complex of bones that connects the trunk and the legs, supports and balances the trunk, and houses and supports the intestines, the urinary bladder, and the internal organ. It is sometimes referred to as the bony pelvis or the pelvic girdle.
One is located on the left side of the body and the other is located on the right. They come together to make the pelvic girdle, a portion of the pelvis. The hip bones are attached to the upper portion of the skeleton at the sacrum.
The pelvic girdle's main function is to support the upper body's weight while seated and transfer that weight to the lower limbs while standing. For the muscles in the trunk and lower limbs, it functions as attachment point.

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The length of a rectangular plot of land is 151.28 m, and its width is 72.35 m. What is the perimeter of this plot?
605.1 m
223.6 m
289.4 m
a.
b. 447.3 m
c.
d.
Please select the best answer from the choices provided
OA
OB
OC
OD

Answers

[tex] \large{ \boxed{ \tt{447.3 \: m}}}[/tex]

-Please see the attached picture for full solution!:)

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7. A battery is used to light a 24 W electric lamp. The battery provides a charge of 120 C in
60 s.
TH
24W
What is the potential difference across the lamp?

Answers

Answer:

power p =24 watt

charge q=120 C

time t = 60s

let V be the potential difference

we know that

work done =qV = pt

qV = Pxt

120V = 24 * 60

V = (24 * 60) / 120

V = 12 volts

The flywheel shown has a radius of 20 in., a weight of 330 lbs, and a radius of gyration of 15 in. A 110-lb block A is attached to a wire that is wrapped around the flywheel, and the system is released from rest. The effect of friction is neglected.

Answers

The acceleration Block A is derived as a= 11.983ft/s². See explanation below.

What is the calculation deriving the above?

Recall that we are given the following:

Radium = 20 inches

Weight = 330lbs

Radius of gyration = 15in

Mass of Block = 110lb

The formula for Moment of Inertia is also given as:

I = mk²

= 330 [ 15/12]²

I = 515.625 lb/ft²

To derive the moment about O, we recourse to

∈M₀ = I∝

TR =  I∝

T [20/12] = 515.625 ∝

T = 309.375∝

Next, to derive the weight of the block A hanging freely,

Wa = MAg

= 110 x 32.2

= 3542 lbf

Acceleration is derived by

A = r∝

= [20/12] ∝

a = 1.667 ∝.........Lets call this equation 1

Value of the acceleration derived by Dalembert Principle


∈Fy = mAa

Wa-T = mAa

3542 - 309.375∝ = 110 x 1.667∝

3542 = 492.745∝

∝ = 7.8188 Rad/s²............Lets call this equation 2

Substituting the value of ∝ in equation 1, we have

a = 1.667∝

= 1.667 x 7.1883

a = 11.983 ft/s²

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A force of 50 n is used to push a wheelchair forward at constant velocity. if the wheelchair is displaced 0.5 m each second, what is the mechanical power expended when transporting the wheelchair?

Answers

The mechanical power expended when transporting the wheelchair is 25 Watts

What is power?

Power is defined as  the amount of energy transferred or converted per unit time. The unit of power is measured in Watts. The higher units are kilowatts, megawatts etc.

The formula for calculating the power expended is expressed as:

Power = Workdone/Time

Since workdone = force * distance, the formula for power will be:

Power = Force*distance/Time

Given the following parameters

Force = 50N

distance = 0.5m

time = 1 second

Substitute to determine the power

Power = 50*0.5/1

Power = 25/1

Power = 25Watts

Hence the mechanical power expended when transporting the wheelchair is 25 Watts

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A velocity-time graph is shown below:

Answers

The average acceleration in the first 10 seconds of the journey is 2 m/s²; option B.

What is acceleration?

Acceleration is the rate of change of velocity with time.

Acceleration = change in velocity/time

From the graph;

Acceleration in first  seconds = 20 - 0/5 = 4 m/s²

Acceleration in second 5 seconds = 0

Average acceleration = 4 + 0/2

Average acceleration = 2 m/s²

In conclusion, average acceleration is the average of the final and initial acceleration.

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Why might the measurements of ""true distances"" be different for different groups even though they are measuring the same distance?

Answers

While measuring , there are a lot of errors which can happen due to which ""true distances"" be different for different groups even though they are measuring the same distance.

While measuring , there are a lot of errors which can happen , to find the most correct value in order to make the result precise and accurate number of measurements needed to be done in order to reduce the error

As nothing can be measured with full precision and accuracy, different measurements for different groups even though they are measuring the same distance.

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