The number of complete cycles the rotating mirror goes through before the angular velocity gets to zero is approximately 1166.8 revs
What is angular velocity?Angular velocity is the ratio of the angle turned to the time taken.
The kinematic equation for angular velocity are presented as follows;
ω = ω₀ + α·t
θ = θ₀ + ω₀·t + 0.5·α·t²
Where;
θ₀ = The initial angle turned = 0
ω₀ = The initial angular velocity of the mirrors = 115 rad/s clockwise
α = The angular acceleration = (115 - (-115))rad/s/(85 s) = -46/17 m/s²
t = The duration of the motion;
When the angular velocity, ω is zero, we get;
0 = 115 - 46/17·t
t = 85/2
Which indicates;
θ = 0 + 115× (85/2) + 0.5×(46/17) ×(85/2)² = 7331.25
θ = 7331.25 radians
θ = 7331.25/(2×π) ≈ 1166.8 rev
The mirrors would have turned through approximately 1166.8 revolutions when the angular gets to zero
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URGENTTTT
Referring to the graph in the section header, what was his displacement between 100 and 300 seconds?
Referring to the graph in the section header, what was the runner's velocity during segment D?
The displacement of the runner according to the graph is obtained as 250 m.
What is the displacement?The term displacement has to do with the distance that is covered in a specified direction. The difference between distance and displacement is that displacement is a vector while distance is a scalar quantity.
Thus we bring the direction into play when we are talking about the displacement of the object. Now we have a graph that shows the displacement of the runner in the vertical axis and then shows the time that is taken in the horizontal axis.
Given the graph as we have it, we can be bale to pick out the following from the graph;
1) Displacement of the runner at 100 s = 500 m
2) Displacement of the runner at 300 s = 750 m
Therefore;
Displacement of the runner between 100 and 300 seconds;
750 m - 500 m = 250 m
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Below are three different arrangements of two mirrors near a source of
light. For each arrangement, a light ray is drawn from the source to the
first mirror. In which of these arrangements would the light eventually
travel parallel to, but in the opposite direction to, the original light. [This
type of device is called a retro-reflector.]
A.
B.
C.
In arrangement B) , mirrors are placed mutually perpendicular to each other .
A retroreflector is a device or surface that reflects radiation back to its source with minimum scattering.
When two mirrors are placed perpendicular to each other , and if a light ray that strikes an object consisting of two mutually perpendicular reflective surfaces is reflected back exactly parallel to the direction to the source it came from.
out of all arrangements , it can be observed that in arrangement B) , mirrors are placed mutually perpendicular to each other .
hence , correct option will be
option B
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A student throws a baseball vertically upward and then catches it. What would that graph look like?
A falling object with a mass of 2.55 kg encounters 4.0 N of air resistance. What is the acceleration of the object? (Choose up to be the positive direction, and remember the definition of weight).
Question 9 options:
a)
-21 N
b)
-241.0 m/s2
c)
-21.0 m/s2
d)
-8.2 m/s2
e)
8.2 m/s2
The acceleration of the falling obeject of mass 2.55 kg is -8.2 m/s². And the right option is d) -8.2 m/s².
What is acceleration?This can be defined as the rate of change of velocity.
To calculate the acceleration of the object, we use the formula below.
Formula:
a = (R-mg)/m............. Equation 1Where:
a = Acceleration of the objectm = Mass of the objectR = Air resistanceg = Acceleration due to gravity.Note: Taking forces acting upward to be positve and downward force to be negatove,
From the question,
Given:
R = 4 Nm = 2.55 kgg = 9.8 m/s²Substitute these values into equation 2
a = [4-(2.55×9.8)]/2.55a = -20.99/2.55a = -8.2 m/s²Hence, The acceleration of the object is -8.2 m/s².
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alex is pushing a heavy box.The force he exerts is represented by the white arrow. In order to make his task easier in which direction should an additional force be applied?
Answer:
The other arrow/force should be in the same direction that Alex is pushing the heavy box.
Explanation:
If Alex is pushing the heavy box to the right, then another person helping him that is also pushing the heavy box to the right would lessen the amount that he has to push.
16) What is the acceleration of the ball on its way up?
a) 0m/s
b) 8m/s
c) -9.81m/s^2
d) +9.81m/s
The acceleration of the ball on it way up is -9.81m/s².
The correct option is C)
What is acceleration?
This is the rate of change of velocity with respect to time. The speed and direction of the accelerating object are also very important. It unit is meters per second square, m/s².
What is Gravity?
This is the force that pulls a body toward the center of the earth. This force causes objects to fall freely. This free-falling object has an acceleration of 9.8m/s downward the earth. This is called acceleration gravity.
What is velocity?
This refers to the speed at which an object moves in a given direction. It unit is meters per second, m/s.
Recall that the direction of motion is assumed to be the positive direction. Other parameters depend on the direction of motion. Hence for upward acceleration, the direction of motion is positive but the acceleration due to gravity is negative because the direction is downwards.
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A type of toy catapult consists of a movable plunger which has a spring attached as shown above. The handle was pulled down to fully compress the spring and on release the metal ball of mass 0.1 kg (weight 1 N) was projected 0.75 m vertically. ai What type of energy is stored in a compressed spring? [1 ii What happens to this stored energy when the handle of the plunger is released?
A i. what happens to this stored energy when the handle of plunger is released?
iam for su
r it is A
Explanation:
ertically. ai What type of energy is stored in a compressed spring? [1 ii What happens to this stored energy when the handle of the plunger is released?
A i. what
Honey is a technology company that provides online coupons to its subscribers. Honey's analytics staff has developed a classification method to predict whether a customer who has been sent a coupon will apply the coupon toward a purchase. For a sample of customers, the following table lists the classification model's estimated coupon usage probability for a customer. For this particular campaign, suppose that when a customer uses a coupon, Honey receives $1 in revenue from the product sponsor. To target the customer with the coupon offer, Honey incurs a cost of $0.05. Honey will offer a customer a coupon as long as the expected profit of doing so is positive. Using the equation
Expected Profit of Coupon Offer = P(coupon used) × Profit if coupon used + (1 - P(coupon used)) × Profit if coupon not used
determine which customers should be sent the coupon.
Customer Probability of Using Coupon
1 0.44
2 0.34
3 0.24
4 0.11
5 0.06
Determine the expected profit for each customer. Round your answers to the nearest cent. Enter negative value as negative number, if any.
Customer Expected Profit
1 $
2 $
3 $
4 $
5 $
The expected profit is positive for customers (Select your answer: 2 and 3, 4 and 5, 1, 2, and 33, 4, and 5, 1, 2, 3, and 4, 1, 2, 3, and 5, 2, 3, 4, and 5, 1, 2, 3, 4, and 5) so these customers (Select your answer: should be offered or should not be offered) the coupon.
The expected profit is positive for the customers 1, 2, 3, 4, 5.
What is expected profit?This is the term that is used to refer to the gain that would be expected to be gotten based on the fact that a person has engaged in a business.
We have 1 - 0.05 = 0.95 profit if the coupon is used
-0.05 is the profit if the coupon is not used
for consumer 1
the probability = 0.44
expected profit = 0.44 x 0.95 - 0.05 x 0.56
= 0.418 - 0.028
= 0.39
for consumer 2
the probability = 0.34
expected profit = 0.34 x 0.95 - 0.05 x 0.66
= 0.323 - 0.033
= 0.29
For consumer 3
the probability = 0.24
expected profit = 0.24 x 0.95 - 0.05 x 0.76
= 0.228 - 0.038
= 0.19
For consumer 4
the probability = 0.11
expected profit = 0.11 x 0.95 - 0.05 x 0.89
= 0.1045 - 0.0445
= 0.06
For consumer 5
the probability = 0.06
expected profit = 0.06 x 0.95 - 0.05 x 0.94
= 0.057 - 0.047
= 0.01
The expected profits can be listed as:
0.390.290.190.060.01The expected profits are positive for all of 1, 2, 3, 4, and 5, hence these customers can purchase the coupon.
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Please help me asap with all I’ll mark you brainly
The point that represents maximum potential energy is W.
The point that represents potential energy at 0 joules is Z.
The point that represents potential energy at 50 percent is Y.
The point that represents maximum kinetic energy is X.
Potential energy is the energy held through an object because of its function relative to other items, stresses inside itself, its electric-powered fee, or different elements. potential energy is energy this is saved – or conserved - in an object or substance. This saved energy is based totally on the position, arrangement, or state of the object or substance.
Potential energy refers to the stored energy within an object that exists because of the item's role, country, or arrangement. Potential energy is the strength this is stored in an item because of its function relative to some 0 roles. An item possesses gravitational capability strength if it is located at a top above (or beneath) the zero top.
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Part F
Imagine you were a sportscaster at the Olympics. You'd created a mathematical model similar to the one you just did. Imagine that you had a
computer program that could do an instantaneous analysis of video motion using that model. How could you use it in your sportscast?
A program that could do an instantaneous analysis of video motion will be useful it in a sportscast to analyze events as they occur.
Why will a program be needed?A motion video is defined as the display of video images at a rate (such as thirty frames per second) that causes objects to appear to move smoothly and continuously.
Sports inherently involve fast and accurate motion, which can be difficult for competitors to master but also for coaches and trainers to analyze and audiences to follow. Because of the nature of most sports, monitoring with sensors or other devices attached to players or equipment is generally not possible. This opens up a plethora of opportunities for the use of computer vision techniques to assist competitors, coaches, and the audience
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What is the approximate tangential speed of an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s?
The approximate tangential speed of an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s is 5.34 m/sec.
What is speed?
The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.
Given in the question an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s, tangential speed is ,
v = [tex]2\pi*r[/tex]/t
v = 2*3.14*1.8*108/2.2*104
v = 5.34 m/sec.
The approximate tangential speed of an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s is 5.34 m/sec.
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IF B is added to Ã, under what Condition does the resultant vector have magnitude equal to A + B ?
Answer:
its b and a
Explanation:
Mars had an orbital period of 1.88 years. In two or more complete sentences,explain how to calculate the average distance from mars to the sun, then calculate it
The average distance from mars to the sun if Mars had an orbital period of 1.88 years is 2.27 * [tex]10^{8}[/tex] km
P² = a³
P = Orbital period
a = Average distance
P = 1.88 years
a³ = 1.88²
a³ = 3.53
a = 1.52 AU
a = 1.52 * 1.496 * [tex]10^{8}[/tex] km
a = 2.27 * [tex]10^{8}[/tex] km
The formula used to solve the given problem is derived from Kepler's third law of planetary motion. AU is the abbreviated from of Astronomical unit. 1 AU = 1.496 * [tex]10^{8}[/tex] km
Therefore, the average distance from mars to the sun is 2.27 * [tex]10^{8}[/tex] km
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A car accelerated uniformly from rest and attained a velocity of 8m/s. it then travels with the uniform velocity of for the next 22 seconds and later brought to rest in 5 seconds
(a )draw the velocity time graph
(b.) calculate the total distance covered (c.) calculate the distance covered after 25 seconds.
Answer:
See below
Explanation:
See diagram below
8 seconds to 60 m/s then 60 m/s for 22 seconds then to 0 m/s in 5 seconds
What is the gravitational force acting on a 70.0 kg object standing on the Earth’s surface?
The radius of the earth is 6.371 x 106 m and the mass is 5.972 x 1024 kg.
The gravitational force acting on a 70.0 kg object standing on the Earth’s surface is 687.37N
What is gravitational force ?
A mass attracts a mass; the amount of the gravitational force is directly proportional to the masses of the two items and inversely proportional to the square of the distance between the two objects. Gravitational force is an attractive force that exists between all objects with mass.
The square of the distance between two things has an inverse relationship with the force of gravity, which depends directly on the masses of the two items. Accordingly, the force of gravity increases with mass but decreases as object distance increases.
F = G (M*m) /r2
F = 6.674×10−11 * 5.972*10^24*70/ (6.371*10^6)^2
= 687.37N
F = gravitational force
G = gravitational constant
m = mass of the body
M = mass of the earth
r = distance between them
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Lucy is cruising through space in her new spaceship. As she coasts along, a tiny spacebug drifts into her path and bounces off the window.
Consider several statements concerning this scenario. Evaluate each statement according to the law of momentum conservation and match it to the appropriate category.
TRUE: The total change in momentum for this interaction is zero.
FALSE: The change in the space bug's momentum is greater than the change in the spaceship's momentum.
UNDETERMINED: If the space bug had stuck to the spaceship instead of bouncing off, momentum would not have been conserved for this interaction.
A car is initially moving at 10.5 m/s and accelerates uniformly to reach a speed of 21.7 m/s in 4.34 s. How far did the car move during this
acceleration?
The care travelled a distance of 69.87 m.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. SI unit of acceleration is meter/second² (m/s²).
Given parameters:
Initial velocity of the car; u = 10.5 m/s.
Final velocity of the car; v = 21.7 m/s.
Time; t = 4.34 s.
The acceleration of the moving car; a = (Final velocity of the car - Initial velocity of the car)/time
= ( 21.7 m/s - 10.5 m/s)/4.34 s.
= 2.58 m/s².
Hence, the car move a distance during this acceleration; s = ut +1/2 at²
= 10.5×4.34 + 1/2 × 2.58×4.34² m.
= 69.87 m.
Hence, the car move a distance of 69.87 m during this acceleration.
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a race car is traveling in a uniform circular motion around a race track what happends to the radial aceleration of the car if the velocity is dobled and the radio od the circel is half
A race car is traveling in a uniform circular motion around a race track, the radial acceleration of the car when the velocity is doubled and the radius of the circle is halved will increase by a factor of 8 (Option D)
What is radial acceleration?To arrive at the above conclusion, we must recall that radial acceleration is defined by:
Ac = v²/r; where
Ac - is the magnitude of radial acceleration
v - is the linear or tangential speed
r - is the radius of the circular path
A′c - is the new magnitude of the radial acceleration.
Given that the linear velocity is duplicated and simultaneously the radius is split in two, then the new radial acceleration increases by a factor of 8, according to the following calculation:
A'c = (2v²)/(0.5r)
= 4v²/(0.5r)
= 8 · (v²/r)
= 8 · Ac
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Full Question:
A race car is traveling in a uniform circular motion around a race track what happens to the radial acceleration of the car if the velocity is doubled and the radius of the circle is halfed?
A. It remains the same.
B. It increases by a factor of 2.
C. It increases by a factor of 4.
D. It increases by a factor of 8.
E. It decreases by a factor of 2.
A football player runs due east for 30 yards then cuts up the field due north for a
distance of 35 yards before running into the end zone.
What is the total displacement of the football player?
You may find out an object's total displacement—or how far it is from its point of origin—by using the football player's total displacement, d=46.10yd,definite integral of velocity function of an item.
Is the overall displacement equivalent to the distance?It's common for people to believe that distance & displacement are really just different labels for the same thing. Displacement and distance are different ideas, though. The overall distance traveled by an object during its voyage will be more than the displacement between those two points if it changes direction.
How is displacement volume calculated?In terms of its density and volume, the displaced fluid's mass can be stated as m = V. W = mg, where g is the acceleration due to gravity, is the weight of the fluid that has been displaced. As a result, W = Vg can be used to indicate the weight of the displaced fluid.
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A child throws a piece of candy corn directly up with an initial velocity of 3.8 m/s. If the starting height of the candy was 2.2 meters, what will be the height of the candy after 0.3 seconds? Use a = -9.8m/s/s
A light ray travelling from diamond into air has an angle of refraction of 56. A piece of glass is then placed right next to the diamond. Explain how the angle of refraction will change now that the light is moving from diamond into glass instead of air
The angle of refraction of a light ray travelling from diamond into air has an angle of refraction of 56 will decrease now that the light is moving from diamond into glass instead of air.
When a light ray travels from rarer medium to a denser medium, the refracted ray tends to move towards the normal. So angle of refraction < angle of incidence. When a light ray travels from denser medium to a rarer medium, the refracted ray tends to move away from the normal. So angle of refraction > angle of incidence.
Glass is denser than air. So the angle of refraction will be higher for air than the angle of refraction of glass. So, when the medium is changed from air to glass, the angle of refraction will decrease.
Therefore, the angle of refraction of a light ray travelling from diamond into air has an angle of refraction of 56 will decrease now that the light is moving from diamond into glass instead of air.
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A ball rolls down a hill with a constant acceleration of 2 m/. The ball starts at rest and
travels for 4.0 s before it stops
2.-What was the ball's velocity just before it stopped?
a) 2.0 m/s.
b) 8.0 m/s
c)12 m/s
d) 16 m/s
According to the given statement The ball's velocity just before it stopped was 8.0 m/s.
The correct option is B.
What is acceleration?The rate at which velocity and speed change over time is referred to as acceleration. When anything moves faster or slower, it is said to be accelerating or decelerating in a straight line. Even if the speed remains constant, moving in a circle quickens because the direction is always changing.
Is acceleration a speed?A increase in an object's orientation or speed is referred to as acceleration. Acceleration is the term for the pace at which speed changes. Don't forget that velocity is made up of two components: direction and speed.
Briefing:The definition of acceleration comes first
a = v[tex]_f[/tex] - v[tex]_o[/tex] /t
2 = v[tex]_f[/tex]- 0/4
v[tex]_f[/tex]= 8 m/s
After 4 seconds, the ball will be moving at a speed of 8 m/s.
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A plane is flying to Minnesota with a velocity of 373.52 km/h, N. The plane encounters a crosswind with a velocity of 64.90 km/h, W. What is the magnitude of the resultant velocity of the plane?
Answer:
379.12 km/h N 9.86° W
Explanation:
You want to know the resultant velocity when a plane's velocity of 373.52 km/h N is modified by a crosswind at 64.90 km/h W.
Vector sumIn (N, E) coordinates, the sum of the velocities is ...
(373.52, 0) +(0, -64.90) = (373.52, -64.90)
The magnitude of this vector is ...
|v| = √(373.52² +64.90²) ≈ 379.12 . . . . km/h
The direction will be west of north by the angle ...
θ = arctan(-64.90/373.52) ≈ -9.86° . . . . . . N = 0°, + = clockwise
The resultant velocity is 379.12 km/h N 9.86° W.
The number density of gas atoms at a certain location in the space above our planet is about 1.18 x 10^11 m^-3, and the pressure is 2.50 x 10^-10 N/m² in this space. What is the
temperature there in degrees celsius?
There is a temperature of 153.56K in that area.
In plain English, what is the Boltzmann constant?The Boltzmann constant, often known as Boltzmann's constant and denoted by the letters k or k B, establishes the relationship between absolute temperature and the amount of kinetic energy held within each molecule of an ideal gas.
A gas's temperature is what?A gas's temperature is a representation of its molecules' typical average translational kinetic energy. The molecules in a hot gas move more quickly than those in a cold gas; the mass remains constant, but the kinetic energy—and consequently the temperature—is higher due to the higher velocity of the molecules.
PV=nKT
where,
K=1.380649 × 10-23 m2 kg s-2 K-1
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A soccer coach is working with a device that measures the velocity of a soccer ball after it has
been kicked.
Which units should the coach use for velocity?
Choose 1 answer:
meters per second
kilograms
meters
meters per second
What is Velocity?
The pace at which an object's position changes in relation to a frame of reference and time is what is meant by velocity. Although it may appear sophisticated, velocity is just the act of moving quickly in one direction. Since it is a vector quantity, the definition of velocity requires both magnitude (speed) and direction. Its SI equivalent is the meter per second (ms-1). A body is considered to be accelerating if the magnitude or direction of its velocity changes.
Therefore, it will measured in meters per second.
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Cory is studying the relationship between the temperature (T) of water, and the volume (v) of a certain gas that can dissolve in the water. He comes up with the following equation that describes the relationship: v = 0.036T+0.21. What is the qualitative relationship that describes this quantitative relationship?
The relationship that would be able to describe this is that the gas does not dissolve into the water at a temperature below -5.83 units.
What is a quantitative relationship?This is the term that is used to refer to the data types that includes Numbers such as weight, cost, and measurements
What is qualitative data?The descriptive and conceptual information gathered through surveys, interviews, or observation is referred to as qualitative data.
With a slope of 0.036, the volume v varies linearly with temperature T.
Volume v grows by 0.036 units for every unit increase in temperature as a result.
The volume of the gas dissolved in water is 0.21 units when the water's temperature is zero.
The smallest volume that is feasible is 0 because the volume cannot be negative. At a certain temperature, this occurs. This is the temperature at that time. Let's refer to it as Tc.
we have
Tc = -0.21 / 0.036
= -5.83
This means that the gas does not dissolve into the water below a temperature of -5.83 units.
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True or false: Rocks have different properties such as hardness and texture
True. Rocks have different properties.
What are Rocks?Rocks are naturally formed, consolidated material composed of grains of one or more minerals. Rocks are grouped into three categories depending on their origin:
igneous (formed from solidification of molten material)sedimentary (formed by the accumulation of fragmental material derived from preexisting rocks of any origin as well as the accumulation of organic material or precipitated material)metamorphic (occur as a result of high pressure, high temperature and the chemical activity of fluids changing the texture and (or) mineralogy of preexisting rocks).Physical properties of RocksThere are many physical properties of rocks, they may include; color, crystal form (or shape), hardness, luster (or shine), density, texture and fracture (how the rock disintegrates)
In conclusion, all rocks have different physical properties; texture and hardness are few of the possible properties.
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In an arcade game a 0.097 kg disk is shot
across a frictionless horizontal surface by compressing it against a spring and releasing it.
If the spring has a spring constant of
166 N/m and is compressed from its equilibrium position by 5 cm, find the speed with
which the disk slides across the surface.
Answer:
Explanation:
Mass of disk = 0.14 kgSpring constant = 155 N/mLength = 4 cmWe need to calculate the speed Using energy conservationWhere, k = spring constantx = compressed lengthm = mass of the discPut the value into the formulaHence, The speed with which the disk slides across the surface is 1.33095 m/s.
aball is through horizontal From The top at buiding the ball lands I00m for building and It takes 4 Second For It to hit The ground Find: A, The Inital horizontal componet OF Velocity
A ball is through horizontal From The top at building the ball lands I00m for building and It takes 4 Second For It to hit The ground . The Initial horizontal component of Velocity will be 25 m/s
using kinematic equation
s = u t + 1/2 a [tex]t^{2}[/tex]
since , there is no acceleration in horizontal direction
s = u(x) t + 0
100 = u (x) * 4
u(x) = 100 / 4
= 25 m/s
The Initial horizontal component of Velocity will be 25 m/s
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Three miles of an ideal gas kept at constant temperature 300K are compressed from volume of 4L to 1L. Calculate work done in the process where R = 8.31 J/mol/K
[tex]{ \boxed{ \red{ \sf{W = 10370.652 \: J}}}}[/tex]
Explanation:
Given,
[tex]{ \blue{ \sf{μ = 3}}}[/tex]
[tex]{ \blue{ \sf{ T= 300K}}}[/tex]
[tex]{ \blue{ \sf{ V_{1} = 4L}}}[/tex]
[tex]{ \blue{ \sf{ V_{2} = 1L}}} [/tex]
[tex]{ \blue{ \sf{W = \: ?}}}[/tex]
[tex]{ \blue{ \sf{R = 8.31 \: J/mol/K}}}[/tex]
[tex]{ \purple{ \sf{W = μRT \: l_{n}[ \frac{ V_{2}}{ V_{1} }}]}} [/tex]
[tex]{ \purple{ \sf{W = μRT[ l_{n} V_{2} - l_{n}V _{1}}]}}[/tex]
[tex]{ \purple{ \sf{W = 2.303μRT[ log_{1} - log_{4}]}}}[/tex]
[tex]{ \purple{ \sf{W = 2.303 \times 3 \times 8.31 \times 300(0 - 0.6021)}}}[/tex]
[tex]{ \purple{ \boxed{ \green{ \sf{W = 10370.652 \: J}}}}}[/tex]