Jeni is using the Label Wizard to solve a problem. What problem was she most likely experiencing?

O The images were not attaching to the labels.
O The spell check feature was not working within the label boundaries. O The text was getting cut off when the labels printed.
O The print preview function was showing only one label at a time.​

Answer:

Option A

Availability

Explanation:

The implementation of too many security protocols will lead to a reduction of the ease at which a piece of information is accessible.  Accessing the piece of information will become hard even for legitimate users.

The security protocols used should not be few, however, they should be just adequate to maintain the necessary level of confidentiality and integrity that the piece of information should have, While ensuring that the legitimate users can still access it without much difficulty.

Answer:

Which sentence best matches the context of the word reticent as it is used in the following example?

We could talk about anything for hours. However, the moment I brought up dating, he was extremely reticent about his personal life.

Explanation:

Which sentence best matches the context of the word reticent as it is used in the following example?

We could talk about anything for hours. However, the moment I brought up dating, he was extremely reticent about his personal life.

Answer:

QWERTY

Explanation:

The QWERTY keyboard arrangement was invented back when typewriters were used, and they needed a keyboard layout that wouldn't jam the letters.

Today, QWERTY is the most commonly used keyboard layout.

Hope this helped!

Answer:

nonrecursive

Explanation:

Answer:

I am writing a Python program:

pi=3.14 #the value of pi is set to 3.14

radius = float(input("Enter the radius of sphere: ")) #prompts user to enter the radius of sphere

surface_area = 4 * pi * radius **2 #computes surface area of sphere

volume = (4.0/3.0) * (pi * radius ** 3) #computes volume of sphere

print("Surface Area of sphere is: ", surface_area) #prints the surface area

print("Volume of sphere is: {:.2f}".format(volume)) #prints the volume        

Explanation:

Please see the attachment for the complete interactive code.

The first three lines of print statement in the attached image give a brief description of the program.

Next the program assigns 3.14 as the value of π (pi). Then the program prompts the user to enter the radius. Then it computes the surface area and volume of sphere using the formulas. Then it prints the resultant values of surface area and volume on output screen.

The psuedocode for this program is given below:

PROGRAM SphereVolume

pi=3.14

NUMBER radius, surface_area, volume  

INPUT radius

COMPUTE volume = (4/3) * pi* radius ^3

COMPUTE surface_area = 4 * pi * radius ^ 2

OUTPUT volume , surface_area

END

Explanation:

the answer is false ........

The fact that the speed of a vehicle is lower than the prescribed limits shall relieve the driver from the duty to decrease speed when approaching and crossing an intersection is not true.

An intersection serves as the point where many lanes cross on the road which is a point where driver is required to follow the traffic rules.

However, the above statement is not true because , a driver can decide not  decrease speed when approaching and crossing an intersection, even though it is a punishable offense in traffic rules.

Read more on traffic rules here: https://brainly.com/question/1071840

#SPJ2

Answer:

we have that it grows more quickly than linear.

Explanation:

It will still work if they are divided into groups of 77, because we will still know that the median of medians is less than at least 44 elements from half of the \lceil n / 7 \rceil⌈n/7⌉ groups, so, it is greater than roughly 4n / 144n/14 of the elements.

Similarly, it is less than roughly 4n / 144n/14 of the elements. So, we are never calling it recursively on more than 10n / 1410n/14 elements. T(n) \le T(n / 7) + T(10n / 14) + O(n)T(n)≤T(n/7)+T(10n/14)+O(n). So, we can show by substitution this is linear.

We guess T(n) < cnT(n)<cn for n < kn<k. Then, for m \ge km≥k,

\begin{aligned} T(m) & \le T(m / 7) + T(10m / 14) + O(m) \\ & \le cm(1 / 7 + 10 / 14) + O(m), \end{aligned}

T(m)

​

≤T(m/7)+T(10m/14)+O(m)

≤cm(1/7+10/14)+O(m),

​

therefore, as long as we have that the constant hidden in the big-Oh notation is less than c / 7c/7, we have the desired result.

Suppose now that we use groups of size 33 instead. So, For similar reasons, we have that the recurrence we are able to get is T(n) = T(\lceil n / 3 \rceil) + T(4n / 6) + O(n) \ge T(n / 3) + T(2n / 3) + O(n)T(n)=T(⌈n/3⌉)+T(4n/6)+O(n)≥T(n/3)+T(2n/3)+O(n) So, we will show it is \ge cn \lg n≥cnlgn.

\begin{aligned} T(m) & \ge c(m / 3)\lg (m / 3) + c(2m / 3) \lg (2m / 3) + O(m) \\ & \ge cm\lg m + O(m), \end{aligned}

T(m)

​

≥c(m/3)lg(m/3)+c(2m/3)lg(2m/3)+O(m)

≥cmlgm+O(m),

​

therefore, we have that it grows more quickly than linear.

Answer:

Explanation:

Answer:

Explanation:

Answer:

a

Explanation:

a. Color Hue Spectrum

Answer:

HELLOOOO

Alr lets start with steps by dividing by 2 again and againn..

265 / 2 = 132 ( rem = 1 )

132 / 2 = 66 ( rem = 0 )

66/2 = 33 ( rem = 0 )

33/2 = 16 ( rem = 1 )

16/2 = 8 ( rem = 0 )

8/2 = 4 ( rem = 0 )

4/2 = 2 ( rem = 0 )

2/2 = 1 ( rem = 0 )

1/2 = 0 ( rem = 1 )

now write all the remainders from bottom to up

100001001

is ur ans :)))

Answer:

Basic Applications of Computer

1 ) Home. Computers are used at homes for several purposes like online bill payment, watching movies or shows at home, home tutoring, social media access, playing games, internet access, etc.

2 ) Medical Field.

3 ) Entertainment.

4 ) Industry.

5 ) Education.

Explanation:

Hope it helps you

Mark my answer as brainlist

have a good day

Answer:

Round trip times required =  log2N

Explanation:

The round-trip times required before TCP can send N segments using a slow start is log2N. we can arrive at this by looking at the mode of operation of TCP which is  at the 1st time of using a TCP it starts the congestion window as 1 then it  sends an initial segment. When the acknowledgement of the initial segment arrives, TCP increases the congestion window to 2 and then sends 2 segments, When the 2 acknowledgements of the segments sent out arrives, they each increase the congestion window by one, thereby increasing the congestion window to 4 . therefore it takes   log2N round trips before TCP can send N segments

Answer:

Charles Babbage, an English mechanical engineer and polymath, originated the concept of a programmable computer. Considered the "father of the computer",he conceptualized and invented the first mechanical computer in the early 19th century.

Answer:

a. The DLP system flagged the message.

Explanation:

Data Leaked Prevention System is the software that detects potential data breaches that may result in the future. It detects the possible data breach, then monitors it and immediately blocks any sensitive data. DLP system is widely used by businesses. The human resource team received a message because sensitive information about the business benefits and tax is shared with a candidate.

Answer:

A computer is an electronic device that accept raw data and instructions and process it to give meaningful results.

Answer:

10010100001001010100101101010100000000000000000010100101010101111010001001010010100101001

Explanation:

Answer:a

What are the activities a Database Designer will do if using the SDLC to design a Database [10]

Q1b

List the five main components of Access Database and state their uses [1

Explanation:

Answer:

The answer is "0 to 4294967295"

Explanation:

Given bit:

32 bits

Calculating smallest and largest bits:

In any processor, it works only on the 0 and 1 bit and it also stores 0 and 1 values. so, the smallest address in bit value is= 0 and the largest bit value can be defined as follows:

largest address value in bits:

[tex]\Longrightarrow 2^{32}-1\\\\\Longrightarrow 4294967296 -1\\\\\Longrightarrow 4294967295\\\\[/tex]

smallest address= 0

largest address = 4294967295

Answer:

false i think.

Explanation:

Gradient Descent is more likely to reach a local minima. because starting at different points and just in general having a different starting point, will lead us to a different local minimum( aka the lowest point closest to the starting point). if alpha(the learning rate) is too large, gradient descent may fail to converge and may even diverge.

Explanation:

In general, when a program runs in text-based environment like command line interface, the program is used for determining the order in which things happen.

As the program runs, the user will not have any choice and he or she can enter the required data.

If the user enters the data in required format then, he/she can get the result or output in desired format.

Answer:

?

Explanation:

these are instructions to a question?

Answer:

I think the above information will help you a lot.

Have a nice day.

Please read the screen shot brainly is not letting me write the whole thing

Answer:

You'll need dual monitor cables and an adapter.

Explanation:

First Step

Position your monitors on your desk or workspace. Make sure the systems are off.

Second Step

Make sure your power strip is close by. Then plug your power strip and connect the first monitor to your PC via your HDMI

Use an adapter to do the same for the second monitor.

Turn the entire system on

Third Step

On your PC, right click on a blank place in your home screen and click on Display Settings.

If you want to have two separate displays showing the same thing, select Duplicate, but if you want to have the two displays independent of each other, select Extend Display.

Apply the settings and select Done.

Answer:

D

Explanation:

The value of i is incremented by one then assigned to d

Answer:

Explanation:

Using Python as our programming language

code:

def partitionArray(A,k):

flag=0

if not A and k == 1:

return "Yes"

if k > len(A) or len(A)%len(A):

return "No"

flag+=1

cnt = {i:A.count(i) for i in A}

if len(A)//k < max(cnt.values()):

return "No"

flag+=1

if(flag==0):

return "Yes"

k=int(input("k= "))

n=int(input("n= "))

print("A= ")

A=list(map(int,input().split()))[:n]

print(partitionArray(A,k))

Code Screenshot:-

Answer:

a)  

int apples [5] = {2, 4, 6, 8, 10};

b)

int *aPtr   //this is the pointer to int

Another way to attach a pointer to a an int variable that already exists:

int * aPtr;

int var;

aPtr = &var;

c)

for (int i = 0; i < size; i++){

       cout << values[i] << endl;    }

d)  

   aPtr = values;

   aPtr = &values[0];    

both  the statements are equivalent

e)

If its referring to the part d) then the address is:

cout<<aPtr;

f)

     for (int i = 0; i < size; ++i) {

            cout<<*(vPtr + i)<<endl;    }

g)

   cout << (aPtr + 3) << endl;  // address referenced by aPtr + 3

   cout << *(aPtr + 3) << endl; // value stored at that location

This value stored at location is 8

h)

    aPtr = &apples[4];

    aPtr -= 4;

    cout<<aPtr<<endl;

    cout<<*aPtr<<endl;  

Explanation:        

a)

int apples [5] = {2, 4, 6, 8, 10};

In this statement the array names is apples, the size of the array is specified in square brackets. so the size is 5. The type of array apples is int this means it can store integer elements. The values or elements of the array apples are even integers from 2 to 10. So the elements of array are:

apples[0] = 2

apples[1] = 4

apples[2] = 6

apples[3] = 8

apples[4] = 10

b)

In this statement int *aPtr  

The int* here is used to make the pointer aPtr points to integer object. Data type the pointer is pointing to is int. The asterisk symbol used with in makes this variable aPtr a pointer.

If there already exists an int type variable i.e. var and we want the pointer to point to that variable then declare an int type pointer aPtr and aPtr = &var; assigns the address of variable var to aPtr.

int * aPtr;

int var;

aPtr = &var;

c)

The complete program is:

int size= 5;

int values[size] = {2,4,6,8,10};

for (int i = 0; i < size; i++){

       cout << values[i] << endl; }

The size of array is 5. The name of array is values. The elements of array are 2,4,6,8,10.

To print each element of the values array using array subscript notation, the variable i is initialized to 0, because array index starts at 0. The cout statement inside body of loop prints the element at 0-th index i.e. the first element of values array at first iteration. Then i is incremented by 1 each time the loop iterates, and this loop continues to execute until the value of i get greater of equal to the size i.e. 5 of values array.

The output is:

2

4

6

8

10

d)

aPtr = values;

This statement assigns the first element in values array to pointer aPtr. Here values is the address of the first element of the array.

aPtr = &values[0];    

In this statement &values[0] is the starting address of the array values to which is assigned to aPtr. Note that the values[0] is the first element of the array values.

e)

Since &values[0] is the starting address of the array values to which is assigned to aPtr. So this address is the physical address of the starting of the array. If referring to the part d) then use this statement to print physical address is aPtr pointing to

cout<<aPtr;

This is basically the starting address of the array values to which is assigned to aPtr.

The output:

0x7fff697e1810                

f)

i variable represents offset and corresponds directly to the array index.

name of the pointer i.e. vPtr references the array

So the statement (vPtr + i) means pointer vPtr that references to array values plus the offset i array index that is to be referenced. This statement gives the address of i-th element of values array. In order to get the value of the i-th element of values array, dereference operator * is used.  It returns an ith value equivalent to the address the vPtr + i is pointing to. So the output is:

2

3

6

8

10

g)

values[0] is stored at 1002500

aPtr + 3 refers to values[3],

An integer is 4 bytes long,

So the address that is referenced by aPtr + 3 is

1002500 + 3 * 4 = 1002512

values[3] is basically the element of values array at 3rd index which is the 4th element of the array so the value stored at that referred location  is 8.

h)

Given that aPtr points to apples[4], so the address stored in aPtr is

1002500 + 4 * 4 = 1002516

aPtr -= 4  is equivalent to aPtr = aPtr - 4

The above statement decrements aPtr by 4 elements of apples array, so the new value is:

1002516 - 4 * 4 = 1002500

This is the address of first element of apples array i.e 2.

Now

cout<<aPtr<<endl; statement prints the address  referenced by aPtr -= 4 which is 1002500  

cout<<*aPtr<<endl;  statement prints the value is stored at that location which is 2.

Answer:

Cloud based LinkedIn automation includes tools and software that run through the cloud-system and are not detectable by LinkedIn. Cloud based LinkedIn automation tools are becoming the favorite among B2B marketers and sales professionals as they are giving the desired outcomes without any effort.

Answer:

no because...

Explanation:

proffesers say you can't copy so why would they copy and also proffesers have degrees they can co.e up with their own questions to help you students to learn more

Explanation:

algorithmic thinking - developing a set of instructions or sequence of steps to solve a problem;

evaluation - ensuring a solution is fit-for-purpose;

decomposition - breaking a problem down into its component parts;

Answer:

Following are the code to this question:

import java.util.*; //import package for user input

class RetailItem//defining class RetailItem  

{

private String desc;//defining String variable

private int unit;//defining integer variable

private double prices;//defining double variable

RetailItem()//defining default Constructor

{

   //Constructor body

}

Output:

The Sub Total value: 199.75

The Sales Tax value: 11.985

The Total value: $211.735

Explanation:

In the above code three class "RetailItem, CashRegister, and Main" is defined, in the class "RetailItem", it defines three variable that is "desc, unit, and prices", inside the class "get and set" method and the constructor is defined, that calculates its value.

In the next step,  class "CashRegister" is defined, and inside the class parameterized constructor is defined, which uses the get and set method to return its value.  

In the next step, the main class is declared, in the main method two-class object is created and calls its method that are "getSubtotal, getTax, and getTotal".  

There is some technical error that's why full code can't be added so, please find the attached file of code.