Look at the image to receive the answers

Answer:

17900

Step-by-step explanation:

First term a = -19

common difference d = -15-(-19) = 4

number of terms, n = 100

sum of first 100 terms,

n/2(2a+(n-1)d)

= 100/2(2×(-19)+(100-1)4)

= 50×(-38+99×4)

= 50×358

= 17900

Answer:

bag of chips = 2

cookies=1

Step-by-step explanation:

b = bags of chip cost

c = cookie cost

7b+3c = 17

3b +1c = 7

Multiply the second equation by -3

-9b -3c = -21

Add this to the first equation

7b+3c = 17

-9b -3c = -21

------------------------

-2b    = -4

Divide by -2

-2b/-2 = -4/-2

b = 2

Now find c

3b +1c = 7

3(2)+c = 7

6+c =7

c = 7-6

c=1

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

We're not quite sure what the question is.

It appears you may be interested in the names of the groups of 3 digits. Each such group is called a "period." Each period is named for the place value of its right-most digit.

The period just to the left of the decimal point is the "ones" period. To the left of that is the "thousands" period, and to its left is the "millions" period.

When writing the name of a number, the name of the three digits within a period is given, followed by the period name (if it is greater than "ones"). This continues left to right, until you get to the decimal point. For example, the number shown is ...

  eight hundred sixty-two thousand seven hundred ninety-four

You have the correct answer. It is choice A. Nice work.

I prefer using full circles because sometimes the arcs could be too small in measure to not go where you want them to. If you're worried about things getting too cluttered (a legitimate concern), then I recommend drawing everything in pencil and only doing the circles as faint lines you can erase later. Once the construction is complete, you would go over the stuff you want to keep with a darker pencil, pen or marker. You can also use the circle as a way to trace over an arc if needed.

Choice B is false as a full circle can be constructed with a compass. Simply rotate the compass a full 360 degrees. Any arc is a fractional portion of a circle.

Choice C is false for similar reasoning as choice B, and what I mentioned in the paragraph above.

Choice D contradicts choice A, so we can rule it out. Arcs are easier to draw since it takes less time/energy to rotate only a portion of 360 degrees. Also, as mentioned earlier, having many full circles tend to clutter things up.

Answer:

4 sweets

Step-by-step explanation:

we know that there is a total of 48 sweets being handed out, and we can tell that this is an example of inverse proportion:

when one increases the other decreases

So, we multiply 8 * 6 to get 48, and then divide that by 12 to get 4 which is how many each student gets

for some constant k -> xy/z=k

Answer:

time taken for trip 2nd half >  time taken for trip 1st half

Step-by-step explanation:

Let the total distance of Joy's trip be = D

Then, the first half distance travelled = D/2

The rate (speed) at which Joy travels during first half = x

So, time taken to travel first half  = Distance / Speed

= (D/2) / x = D / 2x

Let the rate (speed) at which Joy travels during second half = x'

As given, x' (second half speed) < x (first half speed)

So, time taken to travel first half =  Distance / Speed  

(D/2) / x' =  D / 2x'

As  x' < x : D / 2x'  > D / 2x .

Trip 1st half Time taken trip < 2nd half ; or trip 2nd half time taken > 1st half

Answer:

f(x)=5cos(1/3x) this is an equation

Answer:

9  3  -7  -13

4  -4  11  8

0  9  2  -4

Step-by-step explanation:

9  3  -7  -13

4  -4  11  8

0  9  2  -4

Answer: 9  3  -7  -13

4  -4  11  8

0  9  2  -4

Step-by-step explanation:

Answer:

The probability of randomly selecting a queen or club from a deck of cards = 17/52

Step-by-step explanation:

Here in this question, we are concerned with computing the probability of randomly selecting a queen or club form a deck of cards

Mathematically, the probability is;

Probability of selecting a queen + Probability of selecting a club

Probability of selecting a queen = number of queens/total card number

The number of queens = 4

Probability of selecting a queen = 4/52

Probability of selecting a club card = number of club cards/ total number of cards

Number of club cards = 13

Probability of selecting a club card = 13/52

The probability of selecting a queen or club from a deck of cards = 4/52 + 13/52 = 17/52

Answer:

[tex]\frac{A}{(x-1)} + \frac{B}{(x-9)}[/tex]

Step-by-step explanation:

Given the expression [tex]\dfrac{1}{(x-1)(x-9)}[/tex], we are to write the expression as a partial fraction. Writing as a partial fraction means rewriting the expression a s a sum of two or more expression.

Before we will do this we will need to check the nature of the function at the denominator whether it is linear, quadratic or a repeated function. According to the question, the denominator at the denominator is a linear function and since it is a linear function, we can separate both linear function without restriction as shown;

[tex]\dfrac{1}{(x-1)(x-9)} = \frac{A}{(x-1)} + \frac{B}{(x-9)}[/tex] where A and B are the unknown constant which are numerical values.

Answer:

Hey there!

The slope is -1/3, because the rise over run is -1/3.

Let me know if this helps :)

Answer:

3003 ways

Step-by-step explanation:

(7+8)C5

= 15C5

= 15!/(5!10!)

= 3003

Answer: The value of (f*g)(7) is 66.

Step-by-step explanation:

Given functions: [tex]f(x)= 4x-6\text{ and } g(x)=\sqrt{x+2}[/tex]

Since, product of two functions: [tex](u*v)(x)=u(x)\times v(x)[/tex]

[tex](f*g)(x)=f(x)\times g(x)\\\\=4x-6\times \sqrt{x+2}\\\\\Rightarrow\ (f*g)(x)=(4x-6) \sqrt{x+2}[/tex]

[tex](f*g)(7)=(4(7)-6)\sqrt{7+2}\\\\=(28-6)\sqrt{9}\\\\=22\times 3=66[/tex]

Hence, the value of (f*g)(7) is 66.

Answer:

sec^2(x)

Tell me if I'm correct or wrong. If I'm correct, plz mark me brainliest!

Step-by-step explanation:

Recall that

[tex]\sin (\frac{\pi}{2} - x) = \cos x[/tex]

[tex]\cos (\frac{\pi}{2} - x) = \sin x[/tex]

So we can rewrite the given expression as

[tex]\dfrac{\cos^2 x}{\sin^2 x} + (\sin^2 x + \cos^2 x)[/tex]

[tex]\Rightarrow \dfrac{\cos^2 x}{\sin^2 x} + 1[/tex]

or

[tex]\dfrac{\cos^2 x + \sin^2 x}{\sin^2 x} = \dfrac{1}{\sin^2 x} = \csc^2 x[/tex]

Answer:

y=2x-1

Step-by-step explanation:

Consider two points, (-2,-5) and (-1,-3)

slope = ((-3)-(-5))/((-1)-(-2))=2/1=2

b=-5-(2)×(-2)=-1

putting it into y=mx+c,

y=2x-1

Answer:

[tex]7w^{5}x^{2}[/tex]

Step-by-step explanation:

We can start by looking at each variable and and constant separately. In the first one, the constant part is 14 and in the second its 7. We can notice that the GCF of these two is 7. Next we have the part with w. The first one is w^5 while the second is w^6. We can notice that we can factor w^5 out of both, so it is the GCF. We can notice that only the first one has a y, so we can ignore it since it is not in common with both expressions. Lastly, we have x: the first has x^2 and the second has x^2 as well. They are the same, so the GCF would just be x^2.

Now, we can multiply the results together to get the GCF of the whole expressions:

7 * w^5 * x^2 = [tex]7w^{5}x^{2}[/tex]

Answer:

The probability will 4.32%.

The probability that all four are brown is 35/8,64,501.

Given that, A group of hens lays 69 eggs in a single day. On one particular day, there were 7 brown eggs and 62 white eggs.

Probability without replacement means once we draw an item, then we do not replace it back to the sample space before drawing a second item. In other words, an item cannot be drawn more than once.

If four eggs are selected at random, without replacement, the probability that all four are brown is 7/69 × 6/68 × 5/67 × 4/66

= 7/69 × 3/34 × 5/67 × 2/33

=7/23 × 1/17 × 5/67 × 1/33

=35/8,64,501

Therefore, the probability that all four are brown is 35/8,64,501.

To learn more about the probability visit:

https://brainly.com/question/11234923.

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==================================================

Explanation:

When we reflect any point (x,y) over the line y = x, the x and y coordinates swap. So for instance, we have K = (5, -9) turn into K ' = (-9, 5).

Consider a point like (1,2). We can move it down 1 unit to have it land on the line y = x, then we can move it one unit to the right to move it to (2,1). These two translations effectively move the original point to its reflected location. The distance from (1,2) to y = x, is the same as the distance from (2,1) to y = x. Furthermore, the line connecting (1,2) to (2,1) is perpendicular to y = x.

Answer:

[tex]\frac{98p^{6}}{q}[/tex]

Step-by-step explanation:

Distribute the exponents

[tex](\frac{(7^{-2}p^{-6}q^{-8})}{2q^{-9}} )^{-1}[/tex]

[tex](\frac{q}{98p^{6}} )^{-1}[/tex]

Distribute the -1

[tex]\frac{98p^{6}}{q}[/tex]

9514 1404 393Answer:

  C) Rectangle

Step-by-step explanation:

In general, the vertical cross section of a "right" cylinder will be a rectangle. In some special cases, it may be a square.

Each intersection of the plane with the curved surface is a line, not a curve, so the shape cannot be a circle or ellipse.

Nearest 1000: 5000

Nearest 100: 4600

Nearest 10: 4580

Hope that helped!!! k

------------------------------------------------------------------------------------------

Answer:

(a) 2,162,160

(b) 3,003

Step-by-step explanation:

(a) order matters

You can choose from 14 for the first pick. Then you have 13 left for the second pick. Then you have 12 left for the third pick. Keep going until you have 9 left for the 6th pick. The number when order matters is:

total = 14 * 13 * 12 * 11 * 10 * 9 = 2,162,160

(b) Order does not matter

Start with the same number as above for picking 6 out of 14. Since order does not matter, we divide by the number of ways you can arrange 6 items.

Since there are 6! ways of arranging 6 items,

total = 2,162,160/6! = 3,003

The number of ways when the order matters are 121080960.

The number of ways when order does not matters are 3003.

Given,

Choose 6 colors, without replacement, from 14 distinct colors.

We have to find:

- How many ways can this be done, if the order of the choices matters.

- How many ways can this be done if the order of the choices does not matter.

We use permutation when the order of the arrangements matters.

It is given by:

[tex]^ nP_r[/tex] = n! / r!

We use combination when order does not matter.

It is given by:

[tex]^nC_{r}[/tex] = n! / r! (n-r)!

Find the number of ways when order matters.

We have,

n = 14 and r = 6

[tex]^{14}P_{6}[/tex]

= 14! / 6!

= (14 x 13 x 12 x 11 x 10 x 9 x 8 x 7 x 6!) / 6!

= 4 x 13 x 12 x 11 x 10 x 9 x 8 x 7

= 121080960

Find the number of ways when order does not matter.

We have,

n = 14 and r = 6

[tex]^{14}C_{6}[/tex]

= 14! / 6! 8!

= 14 x 13 x 12 x 11 x 10 x 9 / 6 x 5 x 4 x 3 x 2

= 7 x 13 x 11  x 3  

= 3003

Thus,

The number of ways when the order matters are 121080960.

The number of ways when order does not matters are 3003.

Learn more about combination here:

https://brainly.com/question/28134115

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Answer:

25.0000 + -37.5000 + 66.6667 + -63.5416 + 66.6667

Step-by-step explanation:

The actual formatting of the question has been attached to this response.

From the question,

Let the sequence of terms be [tex]b_{n}[/tex] i.e

[tex]b_{n}[/tex] = [tex]\frac{(-5)^{n+1} }{n!}[/tex]

Let the sequence of partial sums be [tex]S_{n}[/tex] i.e

[tex]S_{n}[/tex] = s₁ + s₂ + s₃ + . . . + sₙ

Therefore the first five terms of the sequence of partial sums will be S₅ i.e

S₅ =  s₁ + s₂ + s₃ + s₄ + s₅

Where;

s₁ = b₁

s₂ = b₁ + b₂ = s₁ + b₂

s₃ = b₁ + b₂ + b₃ = s₂ + b₃

s₄ = b₁ + b₂ + b₃ + b₄ = s₃ + b₄

s₅ = b₁ + b₂ + b₃ + b₄ + b₅ = s₄ + b₅

Where;

b₁ can be found by substituting n = 1 into equation (i) as follows;

[tex]b_{1}[/tex] = [tex]\frac{(-5)^{1+1} }{1!}[/tex]

[tex]b_{1}[/tex] = 25

[tex]b_{1}[/tex] = 25.0000

Recall that

s₁ = b₁

∴ s₁ = 25.0000 to 4 decimal places

--------------------------------------------------------------------------

b₂ can be found by substituting n = 2 into equation (i) as follows;

[tex]b_{2}[/tex] = [tex]\frac{(-5)^{2+1} }{2!}[/tex]

[tex]b_{2}[/tex] = -62.5

[tex]b_{2}[/tex] = -62.5000

Recall that

s₂ = s₁ + b₂

∴ s₂ = 25.000 + -62.5000 = -37.5000

-----------------------------------------------------------------------------------------

b₃ can be found by substituting n = 3 into equation (i) as follows;

[tex]b_{3}[/tex] = [tex]\frac{(-5)^{3+1} }{3!}[/tex]

[tex]b_{3}[/tex] = 104.1667

Recall that

s₃ = s₂ + b₃

∴ s₃ = -37.5000 + 104.1667 = 66.6667

--------------------------------------------------------------------------------

b₄ can be found by substituting n = 4 into equation (i) as follows;

[tex]b_{4}[/tex] = [tex]\frac{(-5)^{4+1} }{4!}[/tex]

[tex]b_{4}[/tex] = -130.2083

Recall that

s₄ =  s₃ + b₄

∴ s₄ = 66.6667 + -130.2083 = -63.5416

-------------------------------------------------------------------------

b₅ can be found by substituting n = 5 into equation (i) as follows;

[tex]b_{5}[/tex] = [tex]\frac{(-5)^{5+1} }{5!}[/tex]

[tex]b_{5}[/tex] = 130.2083

Recall that

s₅ = s₄ + b₅

∴ s₅ = -63.5416 + 130.2083 = 66.6667

------------------------------------------------------------------------------

Therefore, the first five terms of the partial sum is:

25.0000 + -37.5000 + 66.6667 + -63.5416 + 66.6667

Answer:

  35 cm

Step-by-step explanation:

The volume of a cylinder is given by ...

  V = πr²h

We want to find h for the given volume and diameter. First, we must convert the given values to compatible units.

  1 L = 1000 cm³, so 99 L = 99,000 cm³

  60 cm diameter = 2 × 30 cm radius

So, we have ...

  99,000 cm³ = π(30 cm)²h

  99,000/(900π) cm = h ≈ 35.01 cm

The oil is 35 cm deep in the drum.

Answer:

[tex]\displaystyle \left(\frac{-(m^{2}-1)\, x + 2\, m\, y - 2\, m \, c}{m^{2} + 1},\, \frac{(m^{2} - 1)\, y + 2\, m \, x + 2\, c}{m^{2} + 1}\right)[/tex].

Step-by-step explanation:

Consider the line that is perpendicular to [tex]y = m\, x + c[/tex] and goes through [tex](x,\, y)[/tex].

Both [tex](x,\, y)[/tex] and the reflection would be on this new line. Besides, the two points would be equidistant from the intersection of this new line and line [tex]y = m\, x + c[/tex].

Hence, if the vector between [tex](x,\, y)[/tex] and that intersection could be found, adding twice that vector to [tex](x,\, y)\![/tex] would yield the coordinates of the reflection.

Since this new line is perpendicular to line [tex]y = m\, x + c[/tex], the slope of this new line would be [tex](-1/m)[/tex].

Hence, [tex]\langle 1,\, -1/m\rangle[/tex] would be a direction vector of this new line.

[tex]\langle m,\, -1\rangle[/tex] (a constant multiple of [tex]\langle 1,\, -1/m\rangle[/tex] would also be a direction vector of this new line.)

Both [tex](x,\, y)[/tex] and the aforementioned intersection are on this new line. Hence, their position vectors would differ only by a constant multiple of a direction vector of this new line.

In other words, for some constant [tex]\lambda[/tex], [tex]\langle x,\, y \rangle + \lambda\, \langle m,\, -1 \rangle = \langle x + \lambda \, m,\, y - \lambda \rangle[/tex] would be the position vector of the reflection of [tex](x,\, y)[/tex] (the position vector of [tex](x,\, y)\![/tex] is [tex]\langle x,\, y \rangle[/tex].)

[tex]( x + \lambda \, m,\, y - \lambda )[/tex] would be the coordinates of the intersection between the new line and [tex]y = m\, x + c[/tex]. [tex]\lambda\, \langle m,\, -1 \rangle[/tex] would be the vector between [tex](x,\, y)[/tex] and that intersection.

Since that intersection is on the line [tex]y = m\, x + c[/tex], its coordinates should satisfy:

[tex]y - \lambda = m\, (x + \lambda \, m) + c[/tex].

Solve for [tex]\lambda[/tex]:

[tex]y - \lambda = m\, x + m^{2}\, \lambda + c[/tex].

[tex]\displaystyle \lambda = \frac{y - m\, x - c}{m^{2} + 1}[/tex].

Hence, the vector between the position of [tex](x,\, y)[/tex] and that of the intersection would be:

[tex]\begin{aligned} & \lambda\, \langle m,\, -1 \rangle \\= \; & \left\langle \frac{m\, (y - m\, x - c)}{m^{2} + 1},\, \frac{(-1)\, (y - m\, x - c)}{m^{2} + 1}\right\rangle \\ =\; &\left\langle \frac{-m^{2}\, x + m\, y - m\, c }{m^{2} + 1},\, \frac{-y + m\, x + c}{m^{2} + 1}\right\rangle \end{aligned}[/tex].

Add twice the amount of this vector to position of [tex](x,\, y)[/tex] to find the position of the reflection, [tex]\langle x,\, y \rangle + 2\, \lambda \,\langle m,\, -1 \rangle[/tex].

[tex]x[/tex]-coordinate of the reflection:

[tex]\begin{aligned} & x + 2\, \lambda\, m \\ = \; & x + \frac{-2\, m^{2}\, x + 2\, m \, y - 2\, m \, c}{m^{2} + 1} \\ =\; & \frac{-(m^{2} - 1) \, x + 2\, m \, y - 2\, m \, c}{m^{2} + 1}\end{aligned}[/tex].

[tex]y[/tex]-coordinate of the reflection:

[tex]\begin{aligned} & y + (-2\, \lambda)\\ = \; & y + \frac{- 2\, y + 2\, m\, x + 2\, c}{m^{2} + 1} \\ =\; & \frac{(m^{2} - 1) \, y + 2\, m \, x + 2\, m \, c}{m^{2} + 1}\end{aligned}[/tex].

Answer:

-11.2 pounds

Step-by-step explanation:

It is given that,

Shawna finds a study of American men that has an equation to predict weight (in pounds) from  height (in inches):

y = -210 + 5.6x

Height of Shawna's dad is 72 inches

Weight is 182 pounds

We need to find the residual of weight and height for Shawna's dad.

Predicted weight of 72 inches men,

y' = -210 + 5.6(72)

y' = 193.2 pounds

So, residual is :

Y = 182 - 193.2

Y = -11.2 pounds

So, the residual of weight and height for Shawna's dad is -11.2 pounds.

Answer:

-11.2 pounds

Step-by-step explanation:

Got it right on the test.

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Hi my lil bunny!

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80,023 written in scientific notation is [tex]8,0023[/tex] x [tex]10^4[/tex].

Step 1

To find a, take the number and move a decimal place to the right one position.

Original Number: 80,023

New Number: 8.0023

Step 2

New Number: 8 . 0 0 2 3

Decimal Count:   1 2 3 4

Now, to find b, count how many places to the right of the decimal.

There are 4 places to the right of the decimal place.

Step 3

Building upon what we know above, we can now reconstruct the number into scientific notation.

Remember, the notation is: a x 10^b

a = 8.0023

b = 4

Now the whole thing:

8.0023 x 104

Step 4

Check your work:

10^4 = 10,000 x 8.0023 = 80,023

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Have a great day/night!

❀*May*❀