Match the following chemical and physical changes and properties, there will be two answers for each.​

Answer:

Ionized molecules will be found in the aqueous layer

Explanation:

The principle of solvent extraction involves the partitioning of a substance between an aqueous layer and an organic layer. The aqueous layer is polar in nature while the organic layer is nonpolar in nature.

All nonpolar substances are found in the organic layer while all polar substances are found in the aqueous layer. Hence, in the aqueous phase, the following species can be found; positive ions, negative ions and neutral polar molecules or ionic substances.

Answer:

a) volume₁ = 444.6 L  

b) Volume₂ = 306 L  and percentage Error = 31.2%

Explanation:      

Given that;

the solution contains 35.0 wt% H₂SO₄

A quantity of the 35% solution is needed that contains 195.5 kg of H₂SO₄

Lets say mass of solution containing 195.5 kg H₂SO₄ is 'A' kg

Now since the question saysm it is a 35% wt solution,

so

(35/ 100) × Akg = 195.5kg

0.35A = 195.5

A = 558.6kg

So A = 558.6 kg

therefore mass of the  solution is 558.6kg

a)

also Specific gravity is 1.2563

since density of water = 1kg/ L

density of solution = SG of H₂SO₄ × density of water

therefore density of solution = 1.2563 ×1kg/ L  = 1.2563 kg/ L

Now to calculate the required volume (L) of the solution

we say;

Volume of solution = mass / density

Volume = 558.6kg / 1.2563kg/L

Volume₁ = 444.6 L  

b)

Now If pure-component specific gravity is to be used,

Specific Gravity = 1.8255

which means Density will be  = 1.8255 kg/ L

Therefore will be

Volume = 558.6kg / 1.8255kg/L

Volume₂ = 306 L

To calculate the error

we say volume₁ - volume₂

Error = 444.6L - 306L = 138.6

So

Percent error = ( 138.6L / 444.6L) × 100

percentage Error = 31.2%

Answer:

[tex]m=1.779x10^{6}kg[/tex]

Explanation:

Hello,

In this case, mass and volume define density as shown below:

[tex]\rho =\frac{m}{V}[/tex]

Whereas the mass is computed by:

[tex]m=\rho *V[/tex]

Thus, knowing the dimensions of the pool, we compute its volume:

[tex]V=41.4m*28.2m*(5.00ft*\frac{1m}{3.281ft} )=1779.15m^3[/tex]

But in cubic centimetres:

[tex]V=1779.15m^3*\frac{1x10^6cm}{1m^3} \\\\V=1.779x10^{9}cm^3[/tex]

Therefore, the mass in kilograms turns out:

[tex]m=1\frac{g}{cm^3} *1.779x10^{9}cm^3*\frac{1kg}{1000g}\\ \\m=1.779x10^{6}kg[/tex]

Regards.

Answer:

Explanation:

First of all it should be noted that number of protons is called atomic number in chemistry. The atom that has the atomic number of 34 in the periodic table is Selenium (Se). Anions are negatively charged atoms; the negative charge means the atoms have lost electron(s) while still having the same number of protons.

From the above, we can deduce that the only atom that can have 34 protons is Se and for it to become negatively charged (anion), it must lose electron(s).

The different chemical symbols thereof will be Se⁻,Se²⁻, Se³⁻ if it loses one, two or three electrons respectively while still having the atomic number of 34

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Answer:

29. Option (b) 32 mL

30. Option (d) 3.9 g/mL

31. Option (d) 13.195 g

Explanation:

29. Determination of the volume of the rock.

Volume of water = 15 mL

Volume of water + Rock = 47 mL

Volume of Rock =.?

Volume of Rock = (Volume of water + Rock) – (Volume of water)

Volume of Rock = 47 – 15

Volume of Rock = 32 mL

30. Determination of the density of the rock.

Density of a substance is simply defined as the mass of the substance per unit volume of the substance. It can be represented mathematically as:

Density (D) = mass (m) /volume (V)

D = m/V

With the above formula, the density of the rock can be obtained as follow:

Mass (m) of Rock = 125 g

Volume (V) of Rock = 32 mL

Density (D) =?

D = m/V

D = 3.9 g/mL

Therefore, the density of the rock is 3.9 g/mL.

31. Determination of the sum of 3.7 g and 9.495 g.

The sum of 3.7 g and 9.495 g can be obtained as follow:

3.7 g + 9.495 g = 13.195 g

Answer:

$96.8

Explanation:

divide 847 by 28 because each gallon gets the car 28 miles and there's 847 miles in total and you get 30.25 and you multiple that by the cost so it be 30.25×3.20=$96.8

Answer:

heated test tube in cold water

Answer:

[tex]pH=3.74[/tex]

Explanation:

Hello,

In this case, by using the Henderson-Hasselbach equation one could compute the pH considering that the pKa of hydrofluoric acid, HF, is 3.14:

[tex]pH=pKa+log(\frac{[base]}{[acid]} )[/tex]

Whereas the concentration of the base and acid are computed by considering the mixing process with a total volume of 300 mL (0.3 L):

[tex]n_{HF}=0.1L*0.05mol/L=0.005molHF\\\\n_{NaF}=0.2L*0.1mol/L=0.02molNaF[/tex]

[tex][HF]=\frac{0.005molHF}{0.3L}=0.017M[/tex]

[tex][NaF]=\frac{0.02molHF}{0.3L}=0.067M[/tex]

Therefore, the pH turns out:

[tex]pH=3.14+log(\frac{0.067M}{0.017M} )\\\\pH=3.74[/tex]

Regards.

Answer:

Explanation:

In the following reaction we have shown an example of aromatic substitution reaction .

C₆H₆ + RCl = C₆H₅R  + HCl

This  reaction takes place in the presence of catalyst like AlCl₃ which is a lewis acid .

First of all formation of carbocation is made as follows .

RCl + AlCl₃ = R⁺ + AlCl₄⁻

This R⁺ is carbocation which is also called electrophile . It attacks the ring to get attached with it .

C₆H₆ + R⁺  =   C₆H₅R⁺H.

The complex formed is unstable , though it is stabilized by resonance effect . In the last step H⁺ is kicked out of the ring . The driving force that does it is the steric hindrance due to presence of two adjacent group of H and R⁺ at the same place . Second driving force is attack by the base  AlCl₄⁻ that had been formed earlier . It acts as base and it extracts proton ( H⁺ ) from the ring .

C₆H₅R⁺H + AlCl₄⁻  = C₆H₆ + AlCl₃ + HCl .

The formation of a stable product C₆H₆ also drives the reaction to form this product .

Answer:

The concentration of [tex]H^{+}[/tex] is 1.48  × [tex]10^{-9}[/tex] M

The absolute uncertainty of [tex][{H^{+}][/tex] is ±0.12 × [tex]10^{-9}[/tex] M

The concentration of [tex]H^{+}[/tex] is written as 1.48(±0.12) × [tex]10^{-9}[/tex] M

Explanation:

The pH of a solution is given by the formula below

pH = [tex]-log_{10}[{H^{+}][/tex]

∴ [tex][H^{+}] = 10^{-pH}[/tex]

where [tex][{H^{+}][/tex] is the [tex]H^{+}[/tex] concentration

From the question,

pH = 8.83±0.04

That is,

pH =8.83 and the uncertainty is ±0.04

First, we will determine [tex][{H^{+}][/tex] from

[tex][H^{+}] = 10^{-pH}[/tex]

[tex][{H^{+}] = 10^{-8.83}[/tex]

[tex][{H^{+}] = 1.4791[/tex] × [tex]10^{-9}[/tex] M

[tex][{H^{+}] = 1.48[/tex] × [tex]10^{-9}[/tex] M

The concentration of [tex]H^{+}[/tex] is 1.48  × [tex]10^{-9}[/tex] M

The uncertainty of [tex][{H^{+}][/tex]  ( [tex]U_{[H^{+}] }[/tex] ) from the equation [tex][H^{+}] = 10^{-pH}[/tex] is

[tex]U_{[H^{+}] } = 2.303 \\[/tex] × [tex]{[H^{+}] }[/tex] × [tex]U_{pH }[/tex]

Where [tex]U_{[H^{+}] }[/tex] is the uncertainty of [tex][{H^{+}][/tex]

[tex]U_{pH }[/tex] is the uncertainty of the pH

Hence,

[tex]U_{[H^{+}] }[/tex] = 2.303 × 1.4791 × [tex]10^{-9}[/tex] × 0.04

[tex]U_{[H^{+}] }[/tex] = 1.36 × [tex]10^{-10}[/tex] M

[tex]U_{[H^{+}] }[/tex] = 0.12 × [tex]10^{-9}[/tex] M

Hence, the absolute uncertainty of [tex][{H^{+}][/tex] is ±0.12 × [tex]10^{-9}[/tex] M

Explanation:

S= 2

P=6

D=10

F= 14

F orbital holds a maximum of 14 electrons

Answer:

14.

Explanation:

The f level consists of 7 orbitals and each can accommodate up to 2 electrons.

Answer:

The volume of a sample is 5 ml.

Answer:

(a) Enantiomers

(b) Diastereomers

Explanation:

In the first pair of molecules, we have an opposite configuration. That is, in the first molecule we have an R and S configuration and in the second an S and R configuration. Therefore we have a mirror image, if this is true, we will have a mirror image and we will have "enantiomers". (See figure 1)

In the second pair of molecules, we do not have a mirror image. Since the first molecule has an R, S configuration (the mirror image would be S, R). In the second molecule, we have an R, R configuration (the mirror image would be S, S). Therefore, the relationship between these molecules is "diastereoisomers". (See figure 2)

Answer:

2-bromo-4 methylheane

Explanation:

Numbering from right to left, the bromine atom falls on the second (2) carbon, while the methyl branch on the 4th.

The systematic naming (IUPAC) of haloalkanes follows the alphabetical rule in naming the substituents, be it alkyl  groups or halogens.

I hope the explanation would suffice.

Answer:145g

Explanation:

The question is incomplete; the complete question is;

What alkene would give the products below after reaction with O3, followed by reduction with (CH3)2S? Write the condensed structural formula (CH3)2C=O and CH3-CH2-CH=O

Answer:

2-methylpent-2-ene (C6H12)

Explanation:

Ozonolysis is a wonderful method for determining the location of double bonds in an alkene since the oxygenated carbons in the carbonyl compounds formed after ozonolysis are the ones that were initially joined by the double bonds in the original alkene.

Hence if an alkene yields (CH3)2C=O and CH3-CH2-CH=O, the original alkene must be C6H12, that is, 2-methylpent-2-ene

Answer:

0.36 g/cm3 I hope this helps

Answer:

0.36 hope it helped

Explanation:

Answer:

E. glycogenolysis

Explanation:

Glycogenolysis is the process whereby excess glucose stored by the body in the form of glycogen is then converted back/broken down into glucose molecules to serve as a source of energy

Glucagon secretion is stimulated when blood glucose concentration decreases and is secreted by the pancreas. The liver then converts the glycogen into glucose for use by the body

Answer:

This is required answer.

Explanation:

Given that,

The neutralization reaction between methylamine and acetic acid

We know that,

According to proton theory of acid and base,

An acid is a substance which denotes the hydrogen as proton.

Base is a substance which accept the proton.

We need to draw curved arrows to indicate the direction of electron flow

According to diagram,

Diagram shows the movement of electrons in this step of the mechanism.

Hence, This is required answer.

Answer:

The options are a, c, d and h

Explanation:

The following ingredients can be found in a packaged food cereal

Monoglycerides are used as emulsifiers and they are also added to cereals to improve there texture and shelf-life.

Folic acid or folate is a vitamin that most cereals are fortified with to act as dietary supplement.

Iron is an essential mineral element, meaning your body needs it (basically for  blood production). Cereals are usually fortified with iron for this reason.

Disodium phosphate is also a food additive used to improve the quality of food and is also found in cereals.

Answer:

2NO(g) + O2(g) ---> 2NO2(g)

Explanation:

The mechanism for this reaction involves two elementary reactions in which both are bimolecular as shown below;

NO(g) +O2(g) ----> NO2(g) + O(g)

NO(g) + O(g) ----> NO2(g)

Hence overall balanced reaction equation;

2NO(g) + O2(g) ---> 2NO2(g)

Answer:

NO(g)+O(g)---->NO_2(g)

Explanation:

Answer:

hydroxide ion

Explanation:

acids produce hydrogen ion when dissolved in water

Answer:

The number of protons in the nucleus of the atom is equal to the atomic number

(Z). The number of electrons in a neutral atom is equal to the number of protons .

The mass number of the atom (M) is equal to the sum of the number of protons

and neutrons in the nucleus.

Answer:

45.069 mL

Explanation:

mass/density=volume.

If we fill in the numbers provided, we would have:

35.6/0.7899=45.069

Don't forget to add your measurements!

45.069 mL

its closer than us than the planets

:)

Answer:

[See Below]

Explanation:

25 ml.

Answer:

SiO2

Explanation:

A covalent network solid is a solid substance held together by a network of covalent bonds. Silicon dioxide forms a three dimensional covalent network solid structure.

Silicon dioxide is comprised of a network in which each silicon atom is at the centre of a tetrahedron of four oxygen atoms. Each of the oxygen atoms is also bonded to another silicon atom, at the centre of its own tetrahedron of oxygen atoms. This gives rise to a crystalline solid structure which is hard, having a high melting point.

Answer:

170 passenger .  ( approx )

Explanation:

Total volume of metal making fuselage = π ( r₂² - r₁² ) l

r₂ is outer radius of cylindrical tube like fuselage

= 6.5 / 2 + .0025 = 3.2525 m

r₁ is inner  radius of cylindrical tube like fuselage

= 6.5 / 2 = 3.25 m

l = 70.7 m

Total volume of fuselage = π ( r₂² - r₁² ) l

= 3.14 x 70.7 x ( 3.2525² - 3.25² )

= 221.998 ( 10.57875 - 10.5625)

= 3.60747 m³

If it is made of aluminium , its mass

= volume x density

= 3.60747 x 2700 kg

= 9740.16 kg

weight of passenger = 81 x 400 = 32400 kg

Total mass =  32400 + 9740.16

= 42140.16 kg

If it is made of iron  , its mass

= volume x density

= 3.60747 x 7870 kg

= 28390.79  kg

If number of passenger required be n

81 n + 28390.79 = 42140.16 ( as per condition given )

n = 170 passenger .  ( approx )

Answer:

Maximum pressure P = 4.9 × 10⁻⁵ Pa

Explanation:

From the information given, the mean free path can be expressed with the formula:

[tex]\lambda = \dfrac{RT}{\sqrt{2} \pi \times d^2 \times N_A \times P}[/tex]

Making Pressure P the subject of the formula because we intend to find the maximum pressure, we have:

[tex]P= \dfrac{RT}{\sqrt{2} \pi \times d^2 \times N_A \times \lambda }[/tex]

At standard conditions

R = gas constant = 8.314 J/mol.K

T = temperature at 25°C = (273 + 25) = 298 K

π = pi = 3.14

d = (364× 10⁻¹²m)²

[tex]N_A[/tex] = avogadro's number = 6.023 × 10²³

λ = mean free path = 1.0 m

[tex]P= \dfrac{RT}{\sqrt{2} \pi \times d^2 \times N_A \times \lambda }[/tex]

[tex]P= \dfrac{8.314 \ J/mol.K \times 298 \ K}{\sqrt{2}\times (3.14) \times (364 \times 10^{-12} \ m) ^2 \times 6.023 \times 10^{23}/mol \times 1.0 \ m }[/tex]

P = 0.007 kg/m.s²

P = 0.007 Pa

[tex]P = 0.007 Pa \times \dfrac{0.007 \ torr}{1 \ Pa}[/tex]

P = 4.9 × 10⁻⁵ Pa