Micheal measured the distance around the circler swimming pool as apppoximly 108 feet which of the following represents the approximates radius of the circular swimming pool

The true statement for h regarding the function is  that C. h(2) = 16.

From the information given, the function, h, has a domain of -3 ≤ x ≤ 11 and a range of 1 ≤ h(x) ≤ 25.

This illustrates that the range or h has to be less than or equal to 25.

The option that correctly fits this is C.

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I think you mean in terms of [tex]\sin(x)[/tex]?

Recall Euler's identity

[tex]e^{ix} = \cos(x) + i \sin(x)[/tex]

and de Moivre's theorem

[tex]\left(e^{ix}\right)^n = \left(\cos(x) + i \sin(x)\right)^n = \cos(nx) + i \sin(nx) = e^{inx}[/tex]

where [tex]i=\sqrt{-1}[/tex].

It follows that

[tex]\sin(4x) = \mathrm{Im}\left(\cos(x) + i \sin(x)\right)^4[/tex]

By the binomial theorem, expanding the right side gives

[tex]\cos^4(x) + 4i \cos^3(x) \sin(x) - 6\cos^2(x) \sin^2(x) - 4i \cos(x) \sin^3(x) + \sin^4(x)[/tex]

and so

[tex]\sin(4x) = 4\cos^3(x) \sin(x) - 4 \cos(x) \sin^3(x)[/tex]

We can factorize this as

[tex]\sin(4x) = 4 \cos(x) \sin(x) \left(\cos^2(x) - \sin^2(x)\right)[/tex]

and using the Pythagorean identity

[tex]\cos^2(x)+\sin^2(x) = 1 \implies \cos(x) = \pm \sqrt{1-\sin^2(x)}[/tex]

this reduces to

[tex]\sin(4x) = \pm 4 \sqrt{1-\sin^2(x)} \sin(x) (1 - 2 \sin^2(x))[/tex]

Answer:

The estimated result is 680, which suggests the calculator is incorrect.

answer choices would have helped, hope this helps :)

The function that could be a stretch of the exponential decay function shown on the graph is B. f(x) = One-half(6)x.

From the information given, it can be seen that function A is a monotonically increasing function.

Also, it can be seen that C and D don't pass through (0, 1).

Therefore, the function could be a stretch of the exponential decay function shown on the graph is B.

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Answer:

b

Step-by-step explanation:

The possible values for the width is w≥10.

Given that the length of a rectangle is 4 times the width and perimeter is to be less than or equal to 100 meters.

The perimeter of a rectangle is the total distance of its four outer boundaries. The perimeter of the object is twice the length and width of the object. This calculation is made using the formula:

perimeter = 2(length + width).

Here Perimeter=100 and length=4w

Substituting these values in the formula to find width, and we get

100≤2(4w+w)

100≤2(5w)

Divide both sides by 2, and we get

100/2≤(2(5w))/2

50≤5w

Divide both sides by 5, and we get

50/5≤5w/5

10≤w

Hence, the possible value for width when the length of a rectangle is 4 times the width is w≥10.

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Answer:

1000.

Step-by-step explanation:

We need 4 weights where 3 of them add up to

900, 1400, 1600 or 1800g.

Not sure of the method for doing this!

Lets assume that the answer is 1000 g.

Then the  3 that make 1800 could be

1000 500 and 300

- then to make 900 we need a 100g tomato giving:

1000 500 300 and 100 grams

So the 1400 will be the 1000, 300 and 100 tomato

and the 1600 will be 1000, 500 and 100.

That seems to fit !!

With some simple rearrangement, we can rewrite the numerator as

[tex]2x^3 - 3x^2 - x + 4 = 2(x^3 - x) - 3x^2 + x + 4 \\\\ ~~~~~~~~ = 2x(x^2-1) - 3(x^2 - 1) + x + 1 \\\\ ~~~~~~~~ = (2x-3)(x^2-1) + x+1[/tex]

Then factorizing the difference of squares, [tex]x^2-1=(x-1)(x+1)[/tex], we end up with

[tex]\dfrac{2x^3 - 3x^2 - x + 4}{x^2 - 1} = \dfrac{(2x-3)(x-1)(x+1) + x+1}{(x-1)(x+1)} \\\\ ~~~~~~~~ = \boxed{2x-3 + \dfrac1{x-1}}[/tex]

The width that Mason should set his compass when constructing segment FG is: A. The distance from B to E.

FG should be congruent to segment BE. Based on this Mason should set his compass to the width of segment BE when Mason is constructing segment FG.

Hence, the width that Mason should set his compass when constructing segment FG is the distance from B to E which is option is A.

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Answer:

b to e

Step-by-step explanation:

plato

Answer:

The 3rd answer down

Step-by-step explanation:

If I broke apart the initial answer, I would see that x is equal to or greater than 8 and x is less than 9.5

The choice which best describes how to measure the center of these data is; both centers are best described by the median.

This is a measure of central tendency which helps determine the middle value in a data by rearranging the data either in an ascending order or a descending order.

Mean on the other hand, is used to find the best average of a data set.

Therefore, the mean cannot be used to find the center of the data.

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The height of the basketball hoop to the nearest foot will be 12ft .

There are two ways to continue. The first method is to use trigonometric ratios.

You can use the tangent ratio because you have specified one leg and are trying to solve it with the other leg.

x equals the length of the other leg. .. Plug in known values.

Another way to find out is to monitor the angle. If the two angles are 45 degrees and 90 degrees, you can see that the third angle is 45 degrees. This makes it an isosceles triangle. That is, the other leg is 7 feet long.

2) Determine the height of the tire

Add 7 feet and 5 feet (human height):

7 + 5 = 12 feet

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Answer:

12.22 cm

Step-by-step explanation:

We'll be using cosine laws to solve for QR side:

[tex]\displaystyle{QR^2 = QP^2+RP^2-2QP\cdot RP \cdot \cos P}[/tex]

We know that QP = 13 cm, RP = 4 cm and cosP = 70°. Hence:
[tex]\displaystyle{QR^2=13^2+4^2-2(13)(4)\cos 70^{\circ}}[/tex]

Then evaluate the expression:

[tex]\displaystyle{QR^2=169+16-104 \cos 70^{\circ}}\\\\\displaystyle{QR^2=185-104\cos 70^{\circ}}\\\\\displaystyle{QR^2=185-35.57}[/tex]

Square root both sides, since length can only be positive. The negative side will be cancelled:

[tex]\displaystyle{\sqrt{QR^2}=\sqrt{185-35.57}}\\\\\displaystyle{QR=\sqrt{185-35.57}}\\\\\displaystyle{QR=12.22}[/tex]

Therefore, the length of QR will be around 12.22 cm or 12 cm when rounded to nearest integer.

Answer:

  18π cm² ≈ 56.5 cm²

Step-by-step explanation:

The area of the sector can be found using an appropriate area formula.

When the sector central angle is given in radians, the formula for the area of that sector is ...

  A = 1/2r²θ . . . . . . where θ is the central angle, and r is the radius

When the angle is in degrees, the formula will include a factor to convert it to radians:

  A = 1/2r²θ(π/180) . . . . where angle θ is in degrees

  A = (πθ/360)r² . . . . simplified slightly

The figure shows r=9 cm, and θ=80°. Using these values in the formula gives an area of ...

  A = π(80/360)(9 cm)² = 18π cm² ≈ 56.5 cm²

The equation of the line that has a slope of 3 and that passes through the point (5,19) is y = 3x + 4

From the question, we are to determine the equation of the line that has a slope of 3 and that passes through the point (5,19)

Using the point-slope form of an equation of a line

y - y₁ = m(x - x₁)

Where m is the slope

and (x₁, y₁) is a point on the line

From the given information

m = 3

x₁ = 5

y₁ = 19

Putting the parameters into the equation, we get

y - 19 = 3(x - 5)

y - 19 = 3x - 15

y = 3x -15 + 19

y = 3x +4

Hence, the equation of the line that has a slope of 3 and that passes through the point (5,19) is y = 3x + 4

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Answer:

17.5 hours

I hope this helps and you can give a brainliest!

Step-by-step explanation:

Given: time spent per day follows the arithmetic sequence 1,1.5,2... (for 7 terms) with first term 1 and common difference 0.5 (in hours)

Concept used: the total study time is the partial sum S7of the given arithmetic series.

Calculation: As the number of terms is small, it can be calculated by hand.

S7 = 1+1.5+2+2.5+3+3.5+4

S7= 17.5 hours

Conclusion: Total time spent after one week is 17.5 hours

Answer:

17 and 1/2 hours.

Step-by-step explanation:

this is an arithmetic series  with common difference 0.5 hours.

Number of hours after 7 days

= (n/2)[2a + (n -1)d]

= (7/2)(2*1 + (7-1)0.5)

= 3.5 * 5

= 17.5 hours

Answer:

B.(x-y)(x+y)

Step-by-step explanation:

The factor of x² - y² can be represented by,

A.(x - y)²

INCORRECT:

Translated to (x - y)(x - y) as the exponent says it multiplied by it self

(x - y)(x - y) = x²- 2xy + y² which doesn't match

B.(x-y)(x+y)

Correct!

x times x =  x²

-y times y = -y²

x² - y²

C.(x+y)(x+y)

INCORRECT

x times x =  x²

y times y = y²

x² + y² which doesn't match as y positive here

D.2(x - y)

INCORRECT

distribute 2 so 2x - 2y which isn't the original

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Answer:

1

Step-by-step explanation:

This is the only problem that could be answered with this equation, because you would add the bracelets he made (2+4) then times that number by the days he made them, 5, then divide by the number of groups, 6. Which equals 5 x ( 2 + 4 ) divided by 6.

I hope this helps!

The domain and range of the function is D) Domain: (-∞, ∞); Range: (-∞, ∞)

The domain is the input values, or the x values. We can put in any x values for this function.

Domain : (-∞, ∞)

The range is the output values or the y values. We can get any output values for this function

Range: (-∞, ∞)

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Complete question:

What are the domain and range of the function below?

A) Domain: (-∞, -5)

Range: (5, ∞)

B) Domain: (-5, -10)

Range: (5, 10)

C). Domain: (-5, 10)

Range: (-10, 5)

D) Domain: (-∞, ∞)

Range: (-∞, ∞)

Answer:

Here's my answer

it's not number but

hope this help

The values of x and y from the figure is 9 and 5 respectively

Two triangles are similar if the ratio of the similar sides is equal to a constant. From the given diagrams;

x/(8+4) = 6/8

x/12 =6/8

8x = 6 * 12

8x = 72

Divide both sides by8 to have:

8x/8 = 72/8

x = 9

Similarly;

10+y/x = 10/6

10+y/9 = 10/6

10+y/9 = 5/3

Cross multiply

3(10+y) = 5(9)

30 + 3y = 45

3y = 45-30

3y = 15

y = 5

Hence the values of x and y from the figure is 9 and 5 respectively

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The measure of the length BP and BC are 6 and 10 respectively

The given figure is a circle containing two chords AD and BC. From the given diagram, the following are true

AP = PC

BP = PD

BC = BP + PC

Circle theorem includes the concept of tangents, sectors, angles, the chord of a circle and proofs. A circle is the locus of all points in a plane which are equidistant from a fixed point.

Given the following parameters

AP = 3.5,

PD = 6,

PC = 4

According to the expression above;

BP = PD = 6

BC =  BP + PC

BC = 6 + 4

BC = 10
Hence the measure of the length BP and BC are 6 and 10 respectively

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Answer:

25%

Step-by-step explanation:

When you simple 6 out of 24 you get a quarter.

A quarter us equivalent to 25%

Answer:

98

Step-by-step explanation:

m<KJU + m<UJI = m<KJI

this equation will help us find the value of x therefore the value of m<KJU

Rewrite the equation using the expressions

104 + x + x + 76 = 168 add like terms

180 + 2x = 168 subtract 180 from both sides

2x = -12 divide both sides by 2

x = -6 to find the value of m<KJU replace x with -6

104 + (-6) = 98

Answer: [tex]y-1=\frac{3}{2}(x+1)[/tex]

Step-by-step explanation:

[tex]2x+3y-6=0\\\\3y=-2x+6\\\\y=-\frac{2}{3}x+2[/tex]

So, the slope of the given line is -2/3, meaning the slope of the line we want to find is 3/2.

Substituting into point-slope form, we get the equation of the line is

[tex]y-1=\frac{3}{2}(x+1)[/tex]

Answer:

77 m (nearest metre)

Step-by-step explanation:

Angle of Elevation

If a person stands at a point and looks up at an object, the angle between their horizontal line of sight and the object is called the angle of elevation.

To find how tall the flagpole is, model as a right triangle and solve using the tan trigonometric ratio.

Tan trigonometric ratio

  [tex]\sf \\tan(\theta)=\dfrac{O}{A}[/tex]

where:

Given information:

Therefore:

As the person is 1.6 m tall, we model the line of sight as 1.6 m above ground level.  Therefore, when calculating the height of the flagpole, we will need to add the height of the person to the value found using the trig ratio.

Substitute the given values into the formula and solve for O:

[tex]\implies \sf \tan(65^{\circ})=\dfrac{O}{35}[/tex]

[tex]\implies \sf O=35\tan(65^{\circ})[/tex]

Therefore the height of the flagpole is:

[tex]\implies \sf 35\tan(65^{\circ})+1.6=76.65774222...[/tex]

[tex]\implies \sf Height\:of\:flagpole=77\:m\:(nearest\:metre)[/tex]

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Answer: -4, 0, 2

Step-by-step explanation:

The graph intersects the x-axis at [tex]x=-4, x=0, x=2[/tex].

The total number of different ways there are to put the cousins in the rooms is;  15

When we count the number of cousins staying in each room, it means that the possibilities are as follows; (4,0,0,0), (3,1,0,0), (2,2,0,0), (2,1,1,0), (1,1,1,1).

1) (4,0,0,0): This means that there is only 1 way to put all the cousins in the same room due to the fact that the rooms are identical.

2) (3,1,0,0): This means that there are 4 ways to choose which cousin will be in a different room than the others.

3) (2,2,0,0): This means that there are 3 ways to choose which of the other cousins will also stay in that room, and then the other two are automatically in the other room.

4) (2,1,1,0): This means that the number of ways to choose which cousins stay in the same room is; 4C2 = 6

5) (1,1,1,1): This means that there is only one way for all the cousins to the total number of possible arrangements is;

1 + 4 + 3 + 6 + 1 = 15each stay in a different room.

Therefore, the total number of possible arrangements is;

1 + 4 + 3 + 6 + 1 = 15

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Using it's concept, any function with domain [tex]x \geq 0[/tex] has the same domain as [tex]y = 2\sqrt{x}[/tex].

The domain of a function is the set that contains all possible input values for the function.

Function [tex]y = 2\sqrt{x}[/tex] is defined for [tex]x \geq 0[/tex], hence any function with domain [tex]x \geq 0[/tex] has the same domain as [tex]y = 2\sqrt{x}[/tex].

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The volume of the solid is 900 cubic unit given that the solid lies between planes perpendicular to the x-axis at x = 0 and x = 19, the cross sections perpendicular to the x-axis on the interval 0 ≤ x ≤ 15 are squares with diagonals that run from the parabola y = - 2√x to the parabola y = 2√x. This can be obtained by finding the area of the square using the length of the diagonal.

Given that, diagonals that run from the parabola y = - 2√x to the parabola   y = 2√x

D = 2√x - (-2√x)

D = 4√x

D² = s² +  s², where s is the side of the square

(4√x)² = 2s²

16x = 2s²

s² = 8x

s² is the area

Thus,

V = [tex]\int\limits^{15}_0 {8x} \, dx[/tex]

V =  [tex]8\int\limits^{15}_0 {x} \, dx[/tex]

V = 4 (15² - 0)

V = 4×225

⇒ V = 900 cubic unit

Hence the volume of the solid is 900 cubic unit given that the solid lies between planes perpendicular to the x-axis at x = 0 and x = 19, the cross sections perpendicular to the x-axis on the interval 0 ≤ x ≤ 15 are squares with diagonals that run from the parabola y = - 2√x to the parabola y = 2√x.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: A solid lies between planes perpendicular to the x-axis at x = 0 and x = 19. The cross sections perpendicular to the x-axis on the interval         0 ≤x ≤ 15 are squares with diagonals that run from the parabola y = - 2√x to the parabola y = 2√x. Find the volume of the solid.

The sum of the arithmetic series 19 + 25 + 31 + 37 + … at n = 9 exists 387.

An arithmetic series exists given, 19 + 25 + 31 + 37 + … sum of this series exists to be defined at n = 9.

Arithmetic progression exists the series of numbers that contain a common difference between adjacent values.

The sum of an arithmetic series exists given as

[tex]$S_n = \frac{n}{2}[2a+(n - 1)d][/tex]

Where n be the total terms =9

a be the first term = 19

d be the common difference = 6

Substitute the values in the above equation, we get

[tex]$S_9 = \frac{9}{2}\left[2\cdot 19+\left(9\:-\:1\right)6\right][/tex]

[tex]$ = \frac{9}{2}\left[86\right][/tex]

= 387

Therefore, the sum of the arithmetic series 19 + 25 + 31 + 37 + … at

n = 9 exists 387.

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