Momentum of 0.5 kg moving ball with the velocity of 5 m / s ​

Answer:

30.25 m/s

46.68 m

Explanation:

Work Energy theorem states that

W = ½mv2² - ½mv1²

W = ½m(v2² - v1²)

Net work done by the force = -mgd

Net work done = -m * 9.8 * 14.8

Net work done = -145m

Using the work energy theorem

-145m = ½m(v2² - v1²)

-145m = ½ * m(25² - v1²)

-290m = 625m - v1²m

v1² = 625 + 290

v1² = 915

v1 = √915 = 30.25 m/s

B

-mgd = ½m(v2² - v1²), where v2 = 0, so

-mgd = ½mv1²

Making d the subject of the formula, we have

d = -½mv1²/mg

d = v1²/2g

d = 915/ 2 * 9.8

d = 915 / 19.6

d = 46.68 m

Answer:

The amplitude of a sound wave is a reflection of how much energy is carried, which contributes to the intensity of the sound. Intensity is measured in decibels and is perceived as sound volume. Thus, the volume is proportional to the amplitude of the sound wave. The frequency of a sound wave is perceived as pitch.

Explanation:

The amount of energy carried by a sound wave is reflected in its amplitude, which affects the sound's intensity. The perception of intensity as sound loudness is expressed in decibels. Hence, the relationship between the volume and the sound wave's amplitude is clear. Pitch is the perceived frequency of a sound wave.

Wave is is a disturbance in a medium that carries energy as well as momentum . wave is characterized by amplitude, wavelength and phase. Amplitude is the greatest distance that the particles are vibrating. especially a sound or radio wave, moves up and down. Amplitude is a measure of loudness of a sound wave. More amplitude means more loud is the sound wave.

Wavelength is the distance between two points on the wave which are in same phase.

Phase is the position of a wave at a point at time t on a waveform.

There are two types of the wave longitudinal wave and transverse wave.

Longitudinal wave : in which, vibration of the medium (particle) is parallel to propagation of the wave. Sound wave is a longitudinal wave.

Transverse wave : in which, vibration of the medium (particle) is perpendicular to propagation of the wave. Light wave is a Transverse wave.

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Answer:

So the answer is yes, we can the back be shaped like a spinning rod

spinal column that is approximated by a long and narrow rod,

Explanation:

The bone system of the body is very well modeled in physics, the back has a spinal column that is approximated by a long and narrow rod, this rod is fixed in the lower part to the coccyx and has a weight in the upper part (head), this rod has longitudinal vertical movement and twisting movement around the lower part of the bar.

So the answer is yes, we can the back be shaped like a spinning rod

Answer:

A. We know that amplitude at x is

Asin (kx)

But k= 2πf/v

k= 2*3.132*235/193= 7.65

So A = 0.35*sin( 7.65x 0.18)= 0.00841m

C

Vmax = Amplitude x angular velocity

= 0.0084 x 2πf

= 0.0084* 2*3.142* 235= 12.4m/s

D. Maximum acceleration = omega² x Amplitude

= (2πf)²* 0.00841= 183.40m/s²

Answer:

116.67 km/h

Explanation:

avarge speed = total distance / total time

Answer: 490 / 4.2 = 116.67 km/h

Answer:

4hr

Explanation:

The total time Timmy spent in the whole journey is 4 hours.

The given parameters;

The total distance of the journey is calculated as follows;

[tex]( 1 - \frac{2}{5} ) \times total = 60 \ miles\\\\\frac{3}{5} \times total = 60\\\\total = \frac{60 \times 5}{3} \\\\total = 100 \ miles[/tex]

The amount of time for the whole journey is calculated as follows;

[tex]average \ speed = \frac{total \ distance}{total \ time} \\\\total \ time = \frac{100 \ miles }{25 \ mph} \\\\total \ time = 4 \ hours[/tex]

Thus, the total time Timmy spent in the whole journey is 4 hours.

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Answer:

Gravity is an attractive force as well as electromagnetic, but electromagnetic attracts and repels.

Explanation:

Answer:

First to find deceleration of the train we use

v²= u²+ 2as

56²= 73²+ 2(0.5)a

a= -2193mi/hr²

Then we find time in which the train does the intersection

Using

S= ut+ 1/2 at²

1= 73t-1/2(1293)t²

t =68.5s

But since the train is to intersect in 3.9s the time will be the difference which is

65.68s

So finding acceleration

S= ut + 1/2at²

1.3mi= 45/3600mi/s(65.58s)+ 1/2a(65.5)²

So a= 1.179ft/s²

To find velocity we use

V= u + at

= 45/3600mi/s + (-2.33E-4mis²)(65.58s)

V= 0.0271mi/s

= 97.6ft/s

Answer:

Shortest distance = 0.1914 m

Explanation:

Given that,

Amplitude of the wave is 0.0957 m

Frequency of the wave is 3.75 Hz

Wavelength of the wave is 1.97 m

We need to find the shortest transverse distance between a maximum and a minimum of the wave.

The distance between maximum point in positive axis and the baseline is equal to amplitude.

Shortest distance = 2 A

D = 2 × 0.0957

D = 0.1914 m

So, the shortest transverse distance between a maximum and a minimum of the wave is 0.1914 m.

Answer:

They oscillates perpendicularly to one another, the oscillation of one field generates the other field.

Explanation:

In a light wave, an oscillating electric field of a light wave produces a magnetic field, and the magnetic field also oscillates to produce an electric field. The magnetic field and the electric field of a light wave both oscillates perpendicularly to one another. The resultant energy and direction of the wave generated as a result of these oscillating fields is propagated perpendicularly to both fields.

Answer:

The bulk modulus of the liquid is 1.229 x 10¹⁰ Pa

Explanation:

Given;

density of liquid, ρ = 1400 kg/m³

frequency of the wave, f = 390 Hz

wavelength, λ = 7.60 m

The speed of the sound is given by;

v = fλ

v = 390 x 7.6

v = 2964 m/s

The bulk modulus of the liquid is given by;

[tex]v = \sqrt{\frac{B}{\rho}}\\\\v^2 = \frac{B}{\rho}\\\\B = \rho v^2[/tex]

where;

B is bulk modulus

B = (1400)(2964)²

B = 1.229 x 10¹⁰ N/m²

B = 1.229 x 10¹⁰ Pa

Therefore, the bulk modulus of the liquid is 1.229 x 10¹⁰ Pa

Answer and Explanation: Heisenberg's Uncertainty Principle states that if the position of the particle is known, its momentum is unknown and vice-versa.

So, it is impossible to determine both the position and the momentum of a particle with arbitrary accuracy.

The statement, " It is impossible to simultaneously determine both the position and the momentum of a particle with arbitrary accuracy" is correct. Hence, option (c) is correct.

The given problem is based on the Heisenberg's uncertainty principle. As per the Heisenberg's uncertainty principle, "It is not possible to obtain both the momentum and position of particles at same time, if one is obtained with full certainty then other comes uncertain". And the expression for the Heisenberg's principle is,

[tex]\Delta x \times \Delta p \geq \dfrac{h}{4\pi}[/tex]

Here,

[tex]\Delta x[/tex] is the uncertainty in position.

[tex]\Delta p[/tex]  is the uncertainty in momentum.

h is the Planck's constant.

So, as per the above definition the statement, " It is impossible to simultaneously determine both the position and the momentum of a particle with arbitrary accuracy" is justified.

Thus, we can conclude that the statement, " It is impossible to simultaneously determine both the position and the momentum of a particle with arbitrary accuracy" is correct. Hence, option (c) is correct.

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Answer:

a set up where current flows without a voltage difference

Explanation:

because a circuit is a set up of different components, and throughout the circuit the voltage is the same, even with more components

Answer:

a set-up where current flows due to a voltage difference

a closed path of conductors

Explanation:

Answer:

3.948m/s

Explanation:

To solve this we need to apply Doppler effect theory

So

To find the frequency received by insect will be gotten when the Source and observer both are moving in same direction which is given by

f1 = f0 x (V - Vo)/(V - Vs)

f0 = 30.0 kHz

V = 344 m/s

Vs will now be the speed of the bat and

Vo will be the speed of the object which is = 0 m/s

So substituting we have

f1 = 30 x 10^3 x (344- 0)/(344- Vs)

Next to find the frequency reflected by wall we use

f2 = f1 x (V + Vs)/(V + Vo)

So substituting the value of f1 calculated above we have

f2 = 30 x 10^3 x (344 + Vs) x (344 - 0)/[(344 - Vs) x (344 + 0)]

f2 = 30 x 10^3 x (344 + Vs)/(344- Vs)

But the beat frequency detected by bat is 700 Hz,

So we say

f2 - f0 = 700 Hz

30 x 10^3 x (344+ Vs)/(344 - Vs) - 30x 10^3 = 700

(344 + Vs)/(344 - Vs) = 1 + 700/30000 = 1.023

344 + Vs = 344 x 1.023 - Vs x 1.0233

Vs = 344 x ( 1.023 - 1)/(1 + 1.023)

So finally

Vs = Speed of source that is the bat is = 3.949m/s

1.085m

Explanation:

Using

a= lambda/sinစ

Sinစ= (587.5*10^-9) x 0.75*10^-3

= 0.000783

Sinစ=0.875*10^-3/d

0.000783= 0.875/d

d= 1.085m

Answer:

Hence, there will be a collision

Explanation:

First we calculate total distance covered by the speedy sue's car before coming to rest:

2as = Vf² - Vi²

where,

a = deceleration = - 1.9 m/s²

s = distance covered = ?

Vf = Final Velocity = 0 m/s (since car finally stops)

Vi = Initial Velocity = 35 m/s

Therefore,

2(-1.9 m/s²)s = (0 m/s)² - (35 m/s)²

s = 322.37 m

Now, we calculate time taken by car to stop:

Vf = Vi + at

0 m/s = 35 m/s + (-1.9 m/s²)t

t =  18.42 s

Now, we calculate distance traveled by van in this time:

s₁ = V₁t

where,

s₁ = distance traveled by van = ?

V₁ = speed of van = 5.2 m/s

Therefore,

s₁ = (5.2 m/s)(18.42 s)

s₁ = 95.78 m

Now, for collision to occur, the following relation must be satisfied:

s ≥ 160 m + s₁

using values:

322.37 m > 160 m + 95.78 m

322.37 m > 255.78 m

Hence, there will be a collision

Answer:

resultant force = 14 N  ( East direction)

Explanation:

A =   √( (4*7)² + (4*7)² )

A = 39.6 N

B = 4 * 7

B = 28 N

C = 2 * 7

C = 14 N

∑ y forces = Ay - B = (4*7) - 28 = 0

∑ x forces = Ax - C = (4*7) - 14 = 14 N

so the resultant force = 14 N  ( East direction)

Explanation:

Density = mass / volume

ρ = 5.7 g / 0.3 mL

ρ = 19 g/mL

Yes, it's pure gold.

Yes, it's pure gold.

According to the question:

Density = mass / volume.

ρ = 5.7 g / 0.3 mL.

ρ = 19 g/mL.

Hence, Yes it's pure gold.

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Answer:

v=10m/s

Explanation:

[tex]a=\frac{vf-vi}{t}\\ 5m/s^{2}=\frac{vf-0}{2}\\ vf=5*2\\vf=10 m/s[/tex]

Answer:

All of a,b, and c hope this helps

This question is incomplete, the complete question is;

Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is

|FI = |QQ'I / d²

where K = 1/4π∈0, and

∈0 = 8.854 × 10⁻¹² C²/(N.m²) is the permittivity of free space.

Consider two point charges located on the x-axis:

one charge, q₁ = -18.5 nC, is located at

x₁ = -1.715m; the charge q₂ = 30.5 nC, is at the origin ( x₂=0 )

What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q₃ = 51.0 nC placed between q₁ and q₂ at x₃ = -1.085 m ?

Answer: (Fnet3)x = -3.3287 × 10⁻⁵ N

Explanation:

Given that;

Q₁ = -18.5 nC       Q₃ = 51 nC        Q₂ = 30.5 nC

x₁ = - 1.715m         x₃ = - 1.085m     x₂ = 0

Now

x - component of Net force on charge Q₃ is

(Fnet3)x = -K|Q₁I|Q₃I / r₁3² - -K|Q₂I|Q₃I / r₂3²

(Fnet3)x = -(9×10⁹)(51×10⁻⁹) [ 18.5 / ((-1.085 + 1.715)²) + (30.5 / (-1.085)² ] × 10⁻⁹

(Fnet3)x = -3.3287 × 10⁻⁵ N

Answer:

The average [tex]x[/tex] component velocity [tex]V_{avg,x}[/tex] is 32.5 m/s

Explanation:

v = u +at bhjklj kj h

x = (u + v / 2 )t

Average velocity is given by

[tex]V_{avg} = \frac{Displacement}{Time} \\V_{avg} = \frac{x_{2} - x_{1} }{t_{2} - t_{1} }[/tex]

From the question,

Initial speed, u = 28 m/s

Final speed, v = 37 m/s

Time, t = 10 secs

From the formula

[tex]x = (\frac{u + v}{2})t\\[/tex]

where [tex]x[/tex] is the displacement

Put the given values into the equation to find the displacement [tex]x[/tex]

[tex]x = (\frac{28 + 37}{2}) 10\\ x = (\frac{65}{2})10\\ x = (\frac{32.5}{10})\\ x = 325 m[/tex]

Now, for the average [tex]x[/tex] component velocity [tex]V_{avg,x}[/tex]

[tex]V_{avg} = \frac{Displacement}{Time} \\V_{avg} = \frac{x_{2} - x_{1} }{t_{2} - t_{1} }[/tex]

[tex]V_{avg,x} = \frac{325 - 0}{10 - 0}\\V_{avg,x} = \frac{325}{10}\\ V_{avg,x} = 32.5 m/s[/tex]

Hence, the average [tex]x[/tex] component velocity [tex]V_{avg,x}[/tex] is 32.5 m/s

The average x component of velocity during the maneuver of the truck is 32.5 m/s.

Velocity:

The term velocity of any object is defined as the ratio of displacement covered by any object to the time taken by the object to displace.

Given data:

The magnitude of initial speed is, u = 28 m/s.

The magnitude of final speed is, v = 37 m/s.

The time interval is, t = 10 s.

The displacement covered by the truck is calculated as,

[tex]d = \dfrac{v+u}{2} \times t\\\\ d = \dfrac{37+28}{2} \times 10\\\\ d = 325 \;\rm m[/tex]

Now, the expression for the x-component of the average velocity is given as,

[tex]v_{x}=\dfrac{d}{t}[/tex]

Solving as,

[tex]v_{x}=\dfrac{325}{10}\\\\ v_{x}=32.5 \;\rm m/s[/tex]

Thus, we can conclude that the average x component of velocity during the maneuver of truck is 32.5 m/s.

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Given :

( Let , take upward direction +ve and downward direction -ve )

Initial speed of stone , u = 4 m/s .

Height , h = 20 m .

To Find : Time taken to reach ground .

Solution :

We know , by equation of motion .

Displacement is given by :

[tex]h=h_o+ut+\dfrac{gt^2}{2}\\\\0=20+4t-2t^2\\\\t^2-2t-10=0[/tex]  ( Here , g = acceleration due to gravity = [tex]-9.8\ m/s^2[/tex] .)

Solving above equation , we get :

t = 4.32 s .

Hence , this is the required solution .

Answer:

Acceleration, [tex]a=45\ m/s^2[/tex]

Explanation:

The velocity of a particle is given by :

[tex]V=5t^2[/tex]

t is time in seconds

The acceleration in terms of velocity is given by :

[tex]a=\dfrac{dv}{dt}\\\\a=\dfrac{d(5t^2)}{dt}\\\\a=5\times \dfrac{t^3}{3}[/tex]

We need to find the acceleration of the particle at t = 3 s. Put t = 3 s in the expression of a.

So,

[tex]a=\dfrac{5\times 3^3}{3}\\\\a=45\ m/s^2[/tex]

So, the acceleration of the particle at t = 3 s is [tex]45\ m/s^2[/tex].

Explanation:

Given:

v₀ = 30 m/s

v = 0 m/s

a = -7.0 m/s²

Find: t and Δx

v = at + v₀

0 m/s = (-7.0 m/s²) t + 30 m/s

t = 4.3 seconds

v² = v₀² + 2aΔx

(0 m/s)² = (30 m/s)² + 2 (-7.0 m/s²) Δx

Δx = 64 meters

Answer: -5 m/s^2

Explanation: a = v - u/t

                         = 32 - 47/3

                         = -15/3

                         = -5 m/s^2

Explanation:

Write in scientific notation.

4000 = 4.0×10³