Planet-X has a mass of 4.74×1024 kg and a radius of 5870 km.
1. What is the First Cosmic Speed i.e. the speed of a satellite on a low lying circular orbit around this planet? (Planet-X doesn't have any atmosphere.)
2. What is the Second Cosmic Speed i.e. the minimum speed required for a satellite in order to break free permanently from the planet?
3. If the period of rotation of the planet is 16.6 hours, then what is the radius of the synchronous orbit of a satellite?

The next time the string will have the same appearance that it did at t=0s is 2.29 s.

v = fλ

f = v/λ

where;

half of the upward pulse is a quarter of wavelength = ¹/₄ x 4 m = 1 m

f = 3.5/1

f = 3.5 Hz

t1 = 4/3.5 = 1.143 s

The next time the string will have the same appearance that it did at t=0s.

d = 4 m x 2 = 8 m

t2 = 8/3.5

t2 = 2.29 s

Thus, the next time the string will have the same appearance that it did at t=0s is 2.29 s.

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Answer:

1.85c

Explanation:

a photon moves at c, the electron is moving at 0.85c, and since they are moving in opposing directions, the relative speed would be 1.85c

The relative velocity of the electron and photon is equal to the speed of light in a vacuum, which is 3 × 10⁸ m/s The negative sign indicates that they are moving in opposite directions.

The formula for adding velocities in special relativity is given by:

V(relative) = (V₁ - V₂) ÷ (1 - (V₁ × V₂ ÷ c²))

where:

V₁ = velocity of the electron

V₂ = velocity of the photon

c = speed of light in a vacuum

The relative velocity is:

V(relative) = (0.85c - c) ÷ (1 - (0.85c × c ÷ c²))

V(relative) = (0.85c - c) ÷ (1 - 0.85)

V(relative) = (-0.15c) ÷ (0.15)

V(relative) = -c

Therefore, The relative velocity of the electron and photon is equal to the speed of light in a vacuum, which is 3 × 10⁸ m/s The negative sign indicates that they are moving in opposite directions.

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Answer:

I think it's force

Explanation:

Mark as brainliest if it is right

Answer: A

Explanation:

Force can cause a stationary object to start moving or a moving object to change its speed or direction or both

The number of half-lives that would go by in 44 h is 7 half-lives

This is the time taken for half a substance to decay

The number of half-lives that will elaspe after 44 h can be obtained as illustrated below:

n = t / t½

n = 44 / 6.01

n = 7

Thus, 7 half-lives will elaspe after 44 h

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(a) The time taken by the ball to reach its greatest height is 2 seconds.

(b) The time taken by the ball to travel from A to B, C is 4.08 m/s.

(c) The speed with which the ball hits the hoarding is 69.3 m/s.

H = u²sin²θ/2g

H = (40² x (sin 30)²) / (2 x 9.8)

H = 20.4 m

h = ut - ¹/₂gt²

20.4 = (40 x sin 30)t - (0.5)(9.8)t²

20.4 = 20t - 4.9t²

4.9t² - 20t + 20.4 = 0

solve the quadratic equation using formula method;

t = 2 seconds

This is the time of motion of the ball;

T = 2usinθ/g

T = (2 x 40 sin 30)/9.8

T = 4.08 s

v = u + gt

vy = 40 sin30  + (9.8 x 4.08)

vy = 59.98 ms

vx = 40 x cos30

vx = 34.64 m/s

vf = √(vy² + vx²)

vf = √(59.98² + 34.64²)

vf = 69.3 m/s

Thus, the time taken by the ball to reach its greatest height is 2 seconds.

The time taken by the ball to travel from A to B, C is 4.08 m/s.

The speed with which the ball hits the hoarding is 69.3 m/s.

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(a) The surface charge density in the sphere of radius 7.4 is 0.0322 C/m³.

(b) The surface density on the 2nd sphere is  3.48  x 10⁻⁴ C/m³.

F = kq₁q₂/r²

Fr² = kq₁q₂

q₁q₂ = Fr²/k

where;

q₁q₂ = (0.62 x 0.38²) / (9 x 10⁹)

q₁q₂ = 9.95 x 10⁻¹² C

q₂ = 9.95 x 10⁻¹² C/q₁

From the question;

q₁ + q₂ = 55 x 10⁻⁶

q₁ + 9.95 x 10⁻¹² /q₁ = 55 x 10⁻⁶

q₁² + 9.95 x 10⁻¹²  =  55 x 10⁻⁶q₁

q₁² - 55 x 10⁻⁶q₁  + 9.95 x 10⁻¹²   = 0

solve the quadratic equation using formula method;

q₁ = 5.48 x 10⁻⁵ C

q₂ = 55 x 10⁻⁶ C - 5.48 x 10⁻⁵ =  1.82 x 10⁻⁷ C

V1 = ⁴/₃πr³

V1 = (⁴/₃ π)(0.074)³ =  1.7 x 10⁻³ m³

Surface charge density = (5.48 x 10⁻⁵ C) / (1.7 x 10⁻³ m³) = 0.0322 C/m³

V2 = (⁴/₃ π)(0.05)³ = 5.236 x 10⁻⁴ m³

Surface charge density = ( 1.82 x 10⁻⁷ C) / (5.236 x 10⁻⁴ m³) = 3.48  x 10⁻⁴ C/m³

Thus, the surface charge density in the sphere of radius 7.4 is 0.0322 C/m³.

The surface density on the 2nd sphere is  3.48  x 10⁻⁴ C/m³.

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The solution for the questions below is mathematically given as

(A)

Generally, the equation for the flux is  mathematically given as

[tex]\Phi _{B}=B.A[/tex]

[tex]\Phi _{B}=B.A\\\\\Phi _{B}=B(40*30*10^{-4}) ,[/tex]

So, the magnetic flux through the coil is constant.

From faradays law,

[tex]\varepsilon =-\frac{\mathrm{d} \Phi _{B}}{\mathrm{d} t}[/tex]

---(1) for the induced emf. Since magnetic flux is constant, LHS. of (1) =0

induced emf=0

(B)

Let x be the length of the coil's magnetic field area.

[tex]then, \Phi _{B}=B.A=B(40*x*10^{-4}) \\\\\frac{\mathrm{d}\Phi _{B} }{\mathrm{d} t}=40\\B*10^{-4}*\frac{\mathrm{d} x}{\mathrm{d} t}[/tex]

induced emf=0.0132V

(C)

In conclusion, Therefore, there is no variation in the magnetic flux across the coil when magnetic flux=0.

induced emf=0

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(a) The magnetic field the line produced at ground level is 3.75 x 10⁻⁶ T.

(b) The lines magnetic field as a percent of the earth's magnetic field is 7.5%.

(c) No, since this field is much smaller than the earth's magnetic field, it would be expected to have less effect than the earth's field.

B = (μ x I) / (2πr)

B = (4π x 10⁻⁷ x  150) / (2π x 8)

B = 3.75 x 10⁻⁶ T

x = 3.75 x 10⁻⁶ /0.5G

x = (3.75 x 10⁻⁶ ) / (0.5 x 10⁻⁴)

x = 0.075

x = 0.075 x 100% = 7.5%

Thus, we can conclude that, since this field is much smaller than the earth's magnetic field, it would be expected to have less effect than the earth's field.

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Both forming images when placed in their respective places best describes  Becquerel’s experiments.

This was conducted by  Henri Becquerel in which he sought to know how uranium salts are affected by light.

He discovered that the salts emits a penetrating radiation and formed an image in the presence of light but didn't form any in darkness.

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The weight of a 100-kg person decreases by 4 N when he goes from sea level to mountain top at an altitude of 5000 m.

The weight of a person is determined by the mass of the body and the acceleration due to gravity.

The acceleration due to gravity, g is dependent on the mass of the earth, M the radius of the earth and the gravitational force constant , G.

Mathematically, the acceleration due to gravity at the mountain top is determined using the formula:

where:

G = 6.67 × 10⁻¹¹ Nm²/kg²

M = 5.9736 x 10²⁴ kg

r = 638000 + 5000 = 6385000

g = (6.67 × 10⁻¹¹  *  5.9736 x 10²⁴ )(6385000)²

g = 9.77 m/s²

His weight at the mountain top will be:

weight = 100 * 9.77

weight = 977 N

Weight at sea level = 100 * 9.81 = 981 N

Decrease in weight = 981 - 977

Decrease in weight = 4 N

In conclusion, the weight of the man varies according to his distance from the earth.

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According to Newton's 3rd law, there will be equal and opposite force on the astronaut which is  -6048 N

The law state that in every action, there will be equal and opposite reaction.

Given that a rocket takes off from Earth's surface, accelerating straight up at 69.2 m/s2. We are to calculate the normal force (in N) acting on an astronaut of mass 87.4 kg, including his space suit.

Let us first calculate the force involved in the acceleration of the rocket by using the formula

F = ma

Where mass m = 87.4 kg, acceleration a = 69.2 m/s2

Substitute the two parameters into the formula

F = 87.4 x 69.2

F = 6048.08 N

According to the Newton's 3rd law, there will be equal and opposite force on the astronaut.

Therefore, the normal force acting on the astronaut is -6048 N approximately

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Answer:

a = 7.5

Explanation:

m = f/a

f = 30

m = 4

Thus;

a = f/m

a = 30/4

a = 7.5

Answer:

It doubles as well.

Explanation:

Assuming that the area on which the force acts remains constant, and knowing that by definition:

P = F/A

We see that if we have a double force:

p = 2 F/A

Then the pressure is doubled.

Answer:

pressure doubles if area is constant

Explanation:

we know,

p=F/A

when force is double by keeping area constant

F=2F

Then,

Change in pressure (p') will be

P'=2F/A

or,p'=2×F/A

or,p'=2p(since, P=F/A)

therefore, when force is double by keeping area constant the pressure will increase by 2 times

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Answer:

No

Explanation:

Plastic bags are not magnetic materials, only magnetic materials (such as iron) can be attracted by the magnet.

Hope this helps.

Answer: The force acting on the proton of charge ​1.5 x10-19 C moving with velocity 1.5 x10-19 C under the influence of a magnetic field of 0.7 T will be 3.15×10^-13 N.

Explanation: To find the answer we need to know more about the Lorentz magnetic force.

                                  F= q (v× B)

                               [tex]F= qvBsin\alpha[/tex]  where, [tex]\alpha[/tex] is the angle between v and B.

                                [tex]B=0.7 T\\q=1.5*10^{-19}C\\v= 3*10^{6}m/s.\\\alpha =90 degree.\\[/tex] because, from the question it is clear that the proton is moving along x axis and the magnetic field is along the y axis.

                      [tex]F=qvBsin\alpha =1.5*10^{-19}C*3*10^6 m/s*0.7T*sin (90)\\F=3.15*10^{-13}N[/tex]

Thus, we can conclude that the Lorentz force acting on the proton will be 3.15×10^-13 N.

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In response to a magnetic field of 0.7 T, a proton with a charge of 1.5 x 10-19 C travelling at a speed of 1.5 x 10-19 C will experience a force of 3.15 x 10^-13 N.

We need to learn more about the Lorentz magnetic force in order to locate the solution.

                                      F= Q (v× B)

                                   [tex]F=QvBsin\alpha[/tex]

[tex]\alpha[/tex] the angle between v and B is, where.

                           [tex]F=3.15*10^{-13}N[/tex]

Thus, we can infer that the proton will be subject to a 3.15 10^-13 N Lorentz force.

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C. Graph representing a linear relationship between mass on the x-axis and kinetic energy on the y-axis.

Kinetic energy is the energy possessed by a body due to its motion.

K.E = ¹/₂mv²

where;

The kinetic energy of a body is directly proportional to the mass of the object.

Thus, the correct relationship between kinetic energy and mass is Graph representing a linear relationship between mass on the x-axis and kinetic energy on the y-axis.

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Answer:

You would weigh the same.

Explanation:

At the moment, since Earth is not a perfect sphere, the Earth "bulges out" at the equator, so you're further from the centre of the Earth. Since gravity acts through a body's center of mass, the further you are from the centre the weaker the gravitational acceleration you will feel, because gravity weakens over distance.

So, you're actually lighter at the equator than you'd be at the poles.

However, if the Earth was a perfect sphere, this "bulge" at the equator would not happen, and so you would weigh the same at the poles and at the equator.

Hope this makes sense.

Answer:

90.3N

Explanation:

⊥mg = (0.170 m)(1.20 kg) 9.81 m/s

τ ball = r⊥Wball = (0.340 m)(1.42 N) = − 0.483 N ⋅m

F − 2.001− 0.483 N ⋅m = 0

F = 2.484 N ⋅m

0.0275 m = 90.3 N

The net torque acting on the forearm and hand is 90.3N

Torque is a measure of the pressure that can motivate an object to rotate about an axis. simply as pressure is what causes an object to accelerate in linear kinematics, torque is what reasons an item to collect angular acceleration. Torque is a vector amount.

⇒mg = (0.170 m)(1.20 kg) 9.81 m/s

⇒torque = r⊥weight of the ball

⇒ (0.340 m)(1.42 N) = − 0.483 N ⋅m

⇒F = − 2.001− 0.483 N ⋅m = 0

⇒F = 2.484 N ⋅m

⇒0.0275 m = 90.3 N

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An example of an offensive action is B. kicking a ball into the goal

Something that is offensive upsets or embarrasses people because it is rude or insulting.

Offensive is an arranged campaign or plan of action, normally created by the military or planned to achieve some specific political aim or goal. A military plan to strike is an example of a military offensive. A plan to fight the war on medications is an instance of an offensive.

The four types of offensive operations are move to contact, attack, exploitation, and pursuit.

Leaders direct these offensive operations sequentially and in combination to generate highest combat power and destroy the enemy.

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Thus, the distance traveled by automobile is [tex]=1.31m[/tex]

The mass of the person is [tex]m=65kg[/tex]

The deceleration of the automobile is [tex]a=30g[/tex]

The acceleration due to gravity is [tex]g=9.81m/s.[/tex]

The initial velocity of the automobile is [tex]v_{i}=100 km/h*\frac{1m/s}{3.6km/h} =27.78m/s[/tex]

Determination of the force exerted on the person:

The force applied to the person can be calculated using Newton's second law as follows:

[tex]F=ma[/tex]

[tex]30g[/tex]Here, m denotes the person's mass, while a denotes the car's acceleration. Because the driver is moving at 30g, the car's acceleration is assumed to be positive.

Substitute the values as 70 kg for [tex]m,(30g)[/tex] for a, and[tex]9.81m/s^{2}[/tex]

for g in the above equation.

[tex]F=70kg*30g[/tex]

   [tex]=70kg*30g*9.81m/s^{2} (\frac{1N}{1kg*m/s^{2} })[/tex]

   [tex]=20,601N[/tex]

Thus, the force acting on the person is [tex]=20,601N[/tex]

Determination of the distance traveled by automobile:

The final velocity of the car can be calculated using Newton's third law and represented as follows:

[tex]v_{f} ^{2}=v_{i} ^{2}+2ad[/tex]

[tex]d=\frac{v_{f} ^{2}=v_{i} ^{2}}{2a}[/tex]

Here [tex]v_{f}[/tex] is the final velocity of the automobile. The final velocity of the automobile becomes 0 m/s as the automobile comes to rest. The acceleration is taken to be negative because the automobile is decelerating at [tex]30g[/tex]

Substitute the values as [tex]0 m/s[/tex] for[tex]v_{f} =27.78m/s[/tex], for[tex]v_{i} ,(-30g)[/tex],  for a, and  [tex]9.81m/s^{2}[/tex]for g in the above equation.

[tex]d=\frac{(0 m/s)^{2} - (27.78m/s)^{2} }{2*(-30)*9.81m/s^{2} }[/tex]

[tex]=1.31m[/tex]

Thus, the distance traveled by automobile is[tex]=1.31m[/tex]

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Based on the weight of the objects in the water, the water level in the given scenario is as follows;

The rise or fall of a fluid when an object is placed in it is determined by the density, mass, and volume of the object.

According to Archimedes' principle, the upthrust or upward force acting on a body fully or partially  immersed in a fluid, is equal to the weight of the fluid displaced.

Considering the given situations:

In conclusion, the rise in water level depends on the weight of the objects.

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DNA sequencing is the technique which allows multiple peoples DNA to be compared to look for similarities and differences in order to solve crime and is denoted as option C.

This is referred to as the deoxyribonucleic acid and contains the genetic components of organisms and is also located in the nucleus. On the other hand, DNA sequencing refers to the process of determining the nucleic acid sequence.

Each organisms has a unique DNA sequence which is why it is used to identify individuals through the use of bodily fluids such as saliva, blood etc.

It is used to compare the similarities and differences in order to solve crime thereby making it the most appropriate choice.

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(a) The coil's self-inductance is 7.26 mH.

(b) The self-induced emf in the coil is 7.26 V

(c) The direction of the induced emf is from b to a.

L = N²μA/I

L = (600² x 4π x 10⁻⁷ x 6.9 x 10⁻⁴)/(0.043)

L = 7.26 x 10⁻³ H

L = 7.26 mH

emf = N(ΔBA)/t

where;

B = μNI/L

B1 = (4π x 10⁻⁷ x 600 x 5)/0.043

B1 = 0.0876 T

B2 =  (4π x 10⁻⁷ x 600 x 2)/0.043

B2 = 0.035 T

emf = NΔBA/t

emf = (600)(0.0876 - 0.035)(6.9 x 10⁻⁴) / (3 x 10⁻³)

emf = 7.26 V

The direction of the induced emf is always opposite to the direction of the applied current.

Thus, the direction of the induced emf is from b to a.

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Answer:

Approximately [tex]25\; {\rm N}[/tex] assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].

Explanation:

This mass is in a circular motion of radius [tex]r[/tex]. Hence, when the velocity of the mass is [tex]v[/tex], the acceleration of this mass should be [tex](v^{2} / r)[/tex]. The net force on this mass should be [tex](\text{net force}) = (m\, v^{2}) / r[/tex] towards the center of the circle.

When this [tex]m = 0.80\; {\rm kg}[/tex] mass is at the top of this circle, both gravitational pull and the force of the string (tension) point downwards. Hence, the net force on this mass would be:

[tex](\text{net force}) = (\text{weight}) + (\text{tension})[/tex].

Thus:

[tex]\begin{aligned} (\text{tension}) &= (\text{net force}) -(\text{weight})\\ &= \frac{m\, v^{2}}{r} - m\, g \\ &= m\, \left(\frac{v^{2}}{r} - g\right) \\ &= 0.80\; {\rm kg}\times \left(\frac{(9.0\; {\rm m\cdot s^{-1}})^{2}}{2.0\; {\rm m}} - 9.81\; {\rm m\cdot s^{-2}}\right) \\ &\approx 25\; {\rm kg \cdot m\cdot s^{-2}} \\ &= 25\; {\rm N}\end{aligned}[/tex].

A wave is a phenomenon that does not cause a permanent displacement in the particles of the medium through which it passes. And it transfers energy from one end of the medium to the other. Examples of waves include light waves, sound waves, water waves, x-rays, radiowaves, etc. Thus the required answers for each part of the question are:

a. The angle that the light wave would have is [tex]7.5^{o}[/tex].

b. The type of mirror that can be used is a plane mirror.

c. The image distance is 146.3 cm.

ii. The image formed by the mirror is a real image.

a. When a ray of light passes from one medium to another, then refraction occurs. The refraction depends on the refractive index of the medium considered.

Thus from Snell's law, we have:

refractive index, n, = [tex]\frac{Sin i}{Sin r}[/tex]

where: i is the angle of incidence, and r is the refracted angle.

Now given that n = 1.5, and i = 15.

Then;

n = [tex]\frac{Sin i}{Sin r}[/tex]

1.5 = [tex]\frac{Sin 15}{Sin r}[/tex]

Sin r = [tex]\frac{0.2588}{1.5}[/tex]

        = 0.17253

r = [tex]Sin^{-1}[/tex] 0.17253

  = 9.936

r ≅ [tex]10^{o}[/tex]

Since the light wave now moves from the glass into water, the determined refracted angle now becomes its angle of incidence in water. So that;

n = [tex]\frac{Sin i}{Sin r}[/tex]

1.33 = [tex]\frac{Sin 10}{Sin r}[/tex]

Sin r = [tex]\frac{0.17365}{1.33}[/tex]

       = 0.1306

r = [tex]Sin^{-1}[/tex] 0.1306

 = 7.504

r = [tex]7.5^{o}[/tex]

Therefore, the angle that the light wave would have is [tex]7.5^{o}[/tex].

b. The image formed would be the same size as that of the object. And also the same distance as that of the object to the pole of the lens.

The type of mirror that can be used is a plane mirror.

The ray diagram is attached to this answer.

c. From the mirror formula;

[tex]\frac{1}{f}[/tex] = [tex]\frac{1}{u}[/tex] + [tex]\frac{1}{v}[/tex]

where; f is the focal length of the mirror, u is the object's distance to the mirror, and v is the image's distance to the mirror.

Given; u = 65 cm, and f = 45 cm, then:

[tex]\frac{1}{45}[/tex] = [tex]\frac{1}{65}[/tex] + [tex]\frac{1}{v}[/tex]

[tex]\frac{1}{v}[/tex] = [tex]\frac{1}{45}[/tex] -  [tex]\frac{1}{65}[/tex]

[tex]\frac{1}{v}[/tex] = [tex]\frac{20}{2925}[/tex]

v = [tex]\frac{2925}{20}[/tex]

v  = 146.25 cm

The image distance is 146.3 cm.

ii. The image formed by the mirror is a real image.

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The resultant force is 8N  

Given that mass is 2kg , v= 40m/s, u =20m/s and we need to calculate resultant force
F=ma

m is given
so for a
v-u/t=a { first equation of motion }

40-20/4= 4
so a=4

F = ma =2*4 = 8N
The difference between the forces that are acting on an object as part of a system is known as the resultant force.
v = u + at is the first equation of motion. Here, v denotes the end speed, u the starting speed, an acceleration, and t the passage of time. The first equation of motion is provided by the velocity-time relation, which may be used to calculate acceleration.

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Answer:

See below

Explanation:

T = period of orbit = sqrt ( 4  pi^2  r^3  /  (G  Me)  )

   G = gravitational constant   6.6743 x 10^-11  m^3 / (kg-s^2)

Me = mass of earth      =  6 x 10^24 kg

 r = radius = 6600 km = 6,600,000 m

plug in the values to find T = 5323.75 seconds

(check my math)

Answer:

 no

Explanation:

The angle subtended by the radius of the target at Emily's distance can be found using the tangent relation.

 tan(α) = opposite/adjacent = (1/4 ft)/(150 ft) = 1/600

The angle is found using the inverse relation -

α = arctan(1/600) ≈ 0.095°

If Emily's aim is off by 0.2°, she will miss the target by several inches.

Emily's projectile will miss her aiming point by ... (150 ft)tan(0.2°) ≈ 0.524 ft ≈ 6.28 in

The altitude or height of the pole vaulter as she crosses the bar is 4.04 m.

The height of the pole vaulter is determined from the change in kinetic energy which is equal to the potential energy at that height.

h = (v - u)²/2g

h = (10 - 1.1)²/2 * 9.8

h = 4.04 m.

In conclusion, the height is determined from the potential energy at that height.

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